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3-7 Perpendicular Lines in the Coordinate Plane - Nexuslearning.net

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3.7<br />

What you should learn<br />

GOAL 1 Use slope to<br />

identify perpendicular l<strong>in</strong>es <strong>in</strong><br />

a coord<strong>in</strong>ate plane.<br />

GOAL 2 Write equations<br />

of perpendicular l<strong>in</strong>es, as<br />

applied <strong>in</strong> Ex. 46.<br />

Why you should learn it<br />

Equations of perpendicular<br />

l<strong>in</strong>es are used by ray trac<strong>in</strong>g<br />

software to create realistic<br />

reflections, as <strong>in</strong> <strong>the</strong><br />

illustration below and <strong>in</strong><br />

Example 6.<br />

REAL<br />

REAL LIFE<br />

LIFE<br />

<strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong><br />

<strong>in</strong> <strong>the</strong> Coord<strong>in</strong>ate <strong>Plane</strong><br />

GOAL 1<br />

172 Chapter 3 <strong>Perpendicular</strong> and Parallel <strong>L<strong>in</strong>es</strong><br />

SLOPE OF PERPENDICULAR LINES<br />

In <strong>the</strong> activity below, you will trace a piece of paper to draw perpendicular l<strong>in</strong>es<br />

on a coord<strong>in</strong>ate grid. Po<strong>in</strong>ts where grid l<strong>in</strong>es cross are called lattice po<strong>in</strong>ts.<br />

1<br />

2<br />

3<br />

4<br />

ACTIVITY<br />

Develop<strong>in</strong>g<br />

Concepts<br />

LESSON INVESTIGATION<br />

In <strong>the</strong> activity, you may have discovered <strong>the</strong> follow<strong>in</strong>g.<br />

POSTULATE<br />

EXAMPLE 1<br />

F<strong>in</strong>d each slope.<br />

Slope of j 1 = 3<br />

0<br />

Investigat<strong>in</strong>g Slopes of <strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong><br />

Put <strong>the</strong> corner of a piece of paper on a lattice<br />

po<strong>in</strong>t. Rotate <strong>the</strong> corner so each edge passes<br />

through ano<strong>the</strong>r lattice po<strong>in</strong>t but nei<strong>the</strong>r edge<br />

is vertical. Trace <strong>the</strong> edges.<br />

F<strong>in</strong>d <strong>the</strong> slope of each l<strong>in</strong>e.<br />

Multiply <strong>the</strong> slopes.<br />

Repeat Steps 1–3 with <strong>the</strong> paper at a different angle.<br />

POSTULATE<br />

POSTULATE 18 Slopes of <strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong><br />

In a coord<strong>in</strong>ate plane, two nonvertical l<strong>in</strong>es are<br />

perpendicular if and only if <strong>the</strong> product of <strong>the</strong>ir<br />

slopes is º1.<br />

Vertical and horizontal l<strong>in</strong>es are perpendicular.<br />

Decid<strong>in</strong>g Whe<strong>the</strong>r <strong>L<strong>in</strong>es</strong> are <strong>Perpendicular</strong><br />

º 1 2<br />

= º º 3 3<br />

Slope of j2 = = 6<br />

= 3<br />

4 2 <br />

3º(º3)<br />

<br />

0 º (º4)<br />

Multiply <strong>the</strong> slopes.<br />

2<br />

The product is º 3<br />

3<br />

2 = º1, so j1 fi j2 .<br />

product of slopes = 2º} 1 } =º1<br />

2<br />

j 1<br />

(0, 3)<br />

(4, 3)<br />

1<br />

y<br />

1<br />

j 2<br />

(3, 1)<br />

x


Logical<br />

Reason<strong>in</strong>g<br />

xy xy<br />

Us<strong>in</strong>g<br />

Algebra<br />

EXAMPLE 2<br />

Decid<strong>in</strong>g Whe<strong>the</strong>r <strong>L<strong>in</strong>es</strong> are <strong>Perpendicular</strong><br />

Decide whe<strong>the</strong>r AC<br />

¯˘ and DB<br />

¯˘ are perpendicular.<br />

SOLUTION<br />

Slope of AC<br />

¯˘ = = 6<br />

= 2<br />

3<br />

Slope of DB<br />

¯˘ 3<br />

= = = º<br />

º 6<br />

1<br />

2 <br />

2 º(º4)<br />

<br />

4º1<br />

2 º(º1)<br />

<br />

º1 º 5<br />

The product is 2º 1<br />

2 = º1, so AC<br />

¯˘ fi DB<br />

¯˘ .<br />

EXAMPLE 3<br />

Decid<strong>in</strong>g Whe<strong>the</strong>r <strong>L<strong>in</strong>es</strong> are <strong>Perpendicular</strong><br />

Decide whe<strong>the</strong>r <strong>the</strong> l<strong>in</strong>es are perpendicular.<br />

l<strong>in</strong>e h: y = 3<br />

x + 2 l<strong>in</strong>e j: y = º4 x º 3<br />

4 3<br />

SOLUTION<br />

The slope of l<strong>in</strong>e h is 3<br />

. The slope of l<strong>in</strong>e j is º4<br />

4 3 .<br />

The product is 3 4<br />

º 4 3 = º1, so <strong>the</strong> l<strong>in</strong>es are perpendicular.<br />

EXAMPLE 4<br />

Decid<strong>in</strong>g Whe<strong>the</strong>r <strong>L<strong>in</strong>es</strong> are <strong>Perpendicular</strong><br />

Decide whe<strong>the</strong>r <strong>the</strong> l<strong>in</strong>es are perpendicular.<br />

SOLUTION<br />

l<strong>in</strong>e r: 4x + 5y = 2 l<strong>in</strong>e s: 5x + 4y = 3<br />

Rewrite each equation <strong>in</strong> slope-<strong>in</strong>tercept form to f<strong>in</strong>d <strong>the</strong> slope.<br />

l<strong>in</strong>e r: l<strong>in</strong>e s:<br />

4x + 5y = 2 5x +4y = 3<br />

5y = º4x + 2 4y = º5x + 3<br />

y = º 4<br />

x + 2 <br />

5 5<br />

y = º5<br />

4 x + 3<br />

<br />

4<br />

slope = º 4<br />

<br />

5<br />

slope = º5<br />

4 <br />

Multiply <strong>the</strong> slopes to see if <strong>the</strong> l<strong>in</strong>es are perpendicular.<br />

º 4 5<br />

º 5 4 =1<br />

The product of <strong>the</strong> slopes is not º1. So, r and s are not perpendicular.<br />

3.7 <strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong> <strong>in</strong> <strong>the</strong> Coord<strong>in</strong>ate <strong>Plane</strong> 173<br />

y<br />

B(1, 2) C(4, 2)<br />

1<br />

1<br />

A(1, 4)<br />

D(5, 1)<br />

x


GRAPHIC ARTS<br />

Many graphic artists<br />

use computer software to<br />

design images.<br />

CAREER LINK<br />

www.mcdougallittell.com<br />

REAL<br />

REAL LIFE<br />

LIFE<br />

INTERNET<br />

STUDENT HELP<br />

Study Tip<br />

You can check m 2 by<br />

multiply<strong>in</strong>g m 1 • m 2 .<br />

(º2) 1<br />

2 =º1 ✓<br />

FOCUS ON<br />

CAREERS<br />

GOAL 2<br />

EXAMPLE 5<br />

174 Chapter 3 <strong>Perpendicular</strong> and Parallel <strong>L<strong>in</strong>es</strong><br />

WRITING EQUATIONS OF PERPENDICULAR LINES<br />

Writ<strong>in</strong>g <strong>the</strong> Equation of a <strong>Perpendicular</strong> L<strong>in</strong>e<br />

L<strong>in</strong>e l1 has equation y = º2x + 1. F<strong>in</strong>d an equation of <strong>the</strong> l<strong>in</strong>e l2 that passes<br />

through P(4, 0) and is perpendicular to l1 . First you must f<strong>in</strong>d <strong>the</strong> slope, m2 .<br />

m1 • m2 =º1 The product of <strong>the</strong> slopes of fi l<strong>in</strong>es is º1.<br />

º2 • m2 =º1 The slope of l1 is º2.<br />

m2 = 1<br />

<br />

2<br />

Divide both sides by º2.<br />

Then use m = 1<br />

and (x, y) = (4, 0) to f<strong>in</strong>d b.<br />

2<br />

y = mx + b Slope-<strong>in</strong>tercept form<br />

0= 1<br />

(4) + b Substitute 0 for y, }1 } for m, and 4 for x.<br />

2 2<br />

º2 = b Simplify.<br />

So, an equation of l2 is y = 1<br />

2<br />

. . . . . . . . . .<br />

x º2.<br />

RAY TRACING Computer illustrators use ray<br />

trac<strong>in</strong>g to make accurate reflections. To figure<br />

out what to show <strong>in</strong> <strong>the</strong> mirror, <strong>the</strong> computer<br />

traces a ray of light as it reflects off <strong>the</strong> mirror.<br />

This calculation has many steps. One of <strong>the</strong><br />

first steps is to f<strong>in</strong>d <strong>the</strong> equation of a l<strong>in</strong>e<br />

perpendicular to <strong>the</strong> mirror.<br />

EXAMPLE 6<br />

Writ<strong>in</strong>g <strong>the</strong> Equation of a <strong>Perpendicular</strong> L<strong>in</strong>e<br />

The equation y = 3<br />

x + 3 represents a mirror.<br />

2<br />

A ray of light hits <strong>the</strong> mirror at (º2, 0). What<br />

is <strong>the</strong> equation of <strong>the</strong> l<strong>in</strong>e p that is<br />

perpendicular to <strong>the</strong> mirror at this po<strong>in</strong>t?<br />

SOLUTION<br />

The mirror’s slope is 3<br />

, so <strong>the</strong> slope of p is º2<br />

2 3 .<br />

Use m = º 2<br />

and (x, y) = (º2, 0) to f<strong>in</strong>d b.<br />

3<br />

0= º 2<br />

(º2) + b<br />

3<br />

º 4<br />

= b<br />

3<br />

So, an equation for p is y = º 2<br />

x º 4<br />

3 3 .<br />

1<br />

Top view of mirror<br />

y<br />

1<br />

3<br />

y x 3<br />

2<br />

ray of light<br />

p<br />

x


GUIDED PRACTICE<br />

Vocabulary Check ✓<br />

Concept Check ✓<br />

Skill Check ✓<br />

PRACTICE AND APPLICATIONS<br />

STUDENT HELP<br />

Extra Practice<br />

to help you master<br />

skills is on p. 808.<br />

STUDENT HELP<br />

HOMEWORK HELP<br />

Example 1: Exs. 7–20<br />

Example 2: Exs. 21–24,<br />

33–37<br />

Example 3: Exs. 25–28,<br />

47–50<br />

Example 4: Exs. 29–32<br />

Example 5: Exs. 38–41<br />

Example 6: Exs. 42–46<br />

1. Def<strong>in</strong>e slope of a l<strong>in</strong>e.<br />

2. The slope of l<strong>in</strong>e m is º 1<br />

. What is <strong>the</strong> slope of a l<strong>in</strong>e perpendicular to m?<br />

5<br />

3. In <strong>the</strong> coord<strong>in</strong>ate plane shown at <strong>the</strong> right, is<br />

¯˘ ¯˘<br />

AC perpendicular to BD?<br />

Expla<strong>in</strong>.<br />

A(1, 3)<br />

3<br />

y<br />

4. Decide whe<strong>the</strong>r <strong>the</strong> l<strong>in</strong>es with <strong>the</strong> equations<br />

y = 2x º 1 and y = º2x + 1 are perpendicular.<br />

5. Decide whe<strong>the</strong>r <strong>the</strong> l<strong>in</strong>es with <strong>the</strong> equations<br />

5y º x = 15 and y + 5x = 2 are perpendicular.<br />

B(2, 0)<br />

1<br />

D(2, 2)<br />

C(1, 1)<br />

6. The l<strong>in</strong>e l 1 has <strong>the</strong> equation y = 3x. The l<strong>in</strong>e l 2 is perpendicular to l 1 and<br />

passes through <strong>the</strong> po<strong>in</strong>t P(0, 0). Write an equation of l 2 .<br />

SLOPES OF PERPENDICULAR LINES The slopes of two l<strong>in</strong>es are given.<br />

Are <strong>the</strong> l<strong>in</strong>es perpendicular?<br />

7. m1 = 2, m2 =º 1<br />

2 8. m1 = 2<br />

3 , m2 = 3<br />

2 9. m1 = 1<br />

4 , m2 =º4<br />

10. m 1 = 5<br />

7 , m 2 =º7<br />

5 11. m 1 =º 1<br />

2 , m 2 =º1<br />

2 12. m 1 = º1, m 2 =1<br />

SLOPES OF PERPENDICULAR LINES <strong>L<strong>in</strong>es</strong> j and n are perpendicular. The<br />

slope of l<strong>in</strong>e j is given. What is <strong>the</strong> slope of l<strong>in</strong>e n? Check your answer.<br />

13. 2 14. 5 15. º3 16. º7<br />

17. 2<br />

<br />

3<br />

18. 1 <br />

5<br />

19. º1<br />

3 20. º 4<br />

<br />

3<br />

IDENTIFYING PERPENDICULAR LINES F<strong>in</strong>d <strong>the</strong> slope of AC<br />

¯˘ and BD<br />

¯˘ .<br />

Decide whe<strong>the</strong>r AC<br />

¯˘ is perpendicular to BD<br />

¯˘ .<br />

21. y<br />

22.<br />

2<br />

B(3, 2) C(0, 1)<br />

A(1, 2)<br />

23. y<br />

24.<br />

B(2, 3)<br />

A(2, 1)<br />

1<br />

1<br />

1<br />

D(0, 2)<br />

C(4, 1)<br />

D(3, 0)<br />

x<br />

x<br />

A(3, 0)<br />

B(1, 1)<br />

1<br />

C(3, 0)<br />

1<br />

A(1, 3)<br />

B(4, 3)<br />

C(2, 2)<br />

D(2, 0)<br />

3.7 <strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong> <strong>in</strong> <strong>the</strong> Coord<strong>in</strong>ate <strong>Plane</strong> 175<br />

1<br />

y<br />

y<br />

D(1, 2)<br />

5<br />

x<br />

x<br />

x


STUDENT HELP<br />

HOMEWORK HELP<br />

Visit our Web site<br />

www.mcdougallittell.com<br />

for help with Exs. 33–36.<br />

INTERNET<br />

xy xy USING ALGEBRA Decide whe<strong>the</strong>r l<strong>in</strong>es k1 and k2 are perpendicular.<br />

Then graph <strong>the</strong> l<strong>in</strong>es to check your answer.<br />

25. l<strong>in</strong>e k1 : y = 3x 26. l<strong>in</strong>e k1 : y = º 4<br />

x º 2<br />

5<br />

l<strong>in</strong>e k2 : y = º 1<br />

3 x º 2 l<strong>in</strong>e k2 : y = 1 x + 4<br />

5<br />

27. l<strong>in</strong>e k 1 : y = º 3<br />

4 x + 2 28. l<strong>in</strong>e k 1<br />

176 Chapter 3 <strong>Perpendicular</strong> and Parallel <strong>L<strong>in</strong>es</strong><br />

: y = 1 x º 10<br />

3<br />

l<strong>in</strong>e k2 : y = 4<br />

3 x + 5 l<strong>in</strong>e k2 : y = 3x<br />

xy xy USING ALGEBRA Decide whe<strong>the</strong>r l<strong>in</strong>es p1 and p2 are perpendicular.<br />

29. l<strong>in</strong>e p1 : 3y º 4x = 3 30. l<strong>in</strong>e p1 : y º 6x = 2<br />

l<strong>in</strong>e p 2 : 4y + 3x = º12 l<strong>in</strong>e p 2 : 6y º x = 12<br />

31. l<strong>in</strong>e p 1 : 3y + 2x = º36 32. l<strong>in</strong>e p 1 : 5y + 3x = º15<br />

l<strong>in</strong>e p 2 : 4y º 3x = 16 l<strong>in</strong>e p 2 : 3y º 5x = º33<br />

LINE RELATIONSHIPS F<strong>in</strong>d <strong>the</strong> slope of each l<strong>in</strong>e. Identify any parallel or<br />

perpendicular l<strong>in</strong>es.<br />

33. y œ<br />

34.<br />

W<br />

P<br />

35. y<br />

Z 36.<br />

C S<br />

R<br />

A<br />

B<br />

1<br />

V<br />

1<br />

A<br />

1<br />

37. NEEDLEPOINT To check whe<strong>the</strong>r two<br />

stitched l<strong>in</strong>es make a right angle, you can<br />

count <strong>the</strong> squares. For example, <strong>the</strong> l<strong>in</strong>es at<br />

<strong>the</strong> right are perpendicular because one<br />

goes up 8 as it goes over 4, and <strong>the</strong> o<strong>the</strong>r<br />

goes over 8 as it goes down 4. Why does<br />

this mean <strong>the</strong> l<strong>in</strong>es are perpendicular?<br />

D<br />

2<br />

WRITING EQUATIONS L<strong>in</strong>e j is perpendicular to <strong>the</strong> l<strong>in</strong>e with <strong>the</strong> given<br />

equation and l<strong>in</strong>e j passes through P. Write an equation of l<strong>in</strong>e j.<br />

38. y = 1<br />

x º 1, P(0, 3) 39. y = 5 x + 2, P(5, 1)<br />

2 3<br />

40. y = º4x º 3, P(º2, 2) 41. 3y + 4x = 12, P(º3, º4)<br />

x<br />

x<br />

K<br />

8<br />

F<br />

2<br />

S<br />

y<br />

œ<br />

1 L<br />

P<br />

4 8<br />

H<br />

y<br />

2<br />

T<br />

G<br />

O<br />

E<br />

4<br />

2<br />

R<br />

x<br />

x


HELAMAN<br />

FERGUSON’S<br />

stone drill is suspended by<br />

six cables. The computer<br />

uses <strong>the</strong> lengths of <strong>the</strong><br />

cables to calculate <strong>the</strong><br />

coord<strong>in</strong>ates of <strong>the</strong> drill tip.<br />

REAL<br />

REAL LIFE<br />

LIFE<br />

FOCUS ON<br />

PEOPLE<br />

Test<br />

Preparation<br />

★ Challenge<br />

EXTRA CHALLENGE<br />

www.mcdougallittell.com<br />

WRITING EQUATIONS The l<strong>in</strong>e with <strong>the</strong> given equation is perpendicular to<br />

l<strong>in</strong>e j at po<strong>in</strong>t R. Write an equation of l<strong>in</strong>e j.<br />

42. y = º 3<br />

x + 6, R(8, 0)<br />

4<br />

43. y = 1 x º 11, R(7, º10)<br />

7<br />

44. y = 3x + 5, R(º3, º4) 45. y = º 2<br />

x º 3, R(5, º5)<br />

5<br />

46. SCULPTURE Helaman Ferguson designs sculptures on a computer. The<br />

computer is connected to his stone drill and tells how far he should drill at<br />

any given po<strong>in</strong>t. The distance from <strong>the</strong> drill tip to <strong>the</strong> desired surface of <strong>the</strong><br />

sculpture is calculated along a l<strong>in</strong>e perpendicular to <strong>the</strong> sculpture.<br />

Suppose <strong>the</strong> drill tip is at<br />

(º1, º1) and <strong>the</strong> equation<br />

y = 1<br />

x + 3 represents <strong>the</strong><br />

4<br />

surface of <strong>the</strong> sculpture. Write<br />

an equation of <strong>the</strong> l<strong>in</strong>e that<br />

passes through <strong>the</strong> drill tip and<br />

is perpendicular to <strong>the</strong> sculpture.<br />

LINE RELATIONSHIPS Decide whe<strong>the</strong>r <strong>the</strong> l<strong>in</strong>es with <strong>the</strong> given equations<br />

are parallel, perpendicular, or nei<strong>the</strong>r.<br />

47. y = º2x º 1 48. y = º 1<br />

x + 3<br />

2<br />

49. y = º3x + 1 50. y = 4x + 10<br />

y = º2x º 3 y = º 1<br />

x + 5<br />

2<br />

y = 1 x + 1<br />

3<br />

y = º2x + 5<br />

51. MULTI-STEP PROBLEM Use <strong>the</strong> diagram<br />

at <strong>the</strong> right.<br />

a. Is l 1 ∞ l 2 ? How do you know?<br />

b. Is l 2 fi n? How do you know?<br />

c. Writ<strong>in</strong>g Describe two ways to prove<br />

that l 1 fi n.<br />

DISTANCE TO A LINE In Exercises 52–54,<br />

use <strong>the</strong> follow<strong>in</strong>g <strong>in</strong>formation.<br />

The distance from a po<strong>in</strong>t to a l<strong>in</strong>e is<br />

def<strong>in</strong>ed to be <strong>the</strong> length of <strong>the</strong><br />

perpendicular segment from <strong>the</strong> po<strong>in</strong>t to<br />

<strong>the</strong> l<strong>in</strong>e. In <strong>the</strong> diagram at <strong>the</strong> right, <strong>the</strong><br />

distance d between po<strong>in</strong>t P and l<strong>in</strong>e l is<br />

given by QP.<br />

52. F<strong>in</strong>d an equation of QP<br />

¯˘ .<br />

53. Solve a system of equations to f<strong>in</strong>d <strong>the</strong> coord<strong>in</strong>ates of po<strong>in</strong>t Q, <strong>the</strong><br />

<strong>in</strong>tersection of <strong>the</strong> two l<strong>in</strong>es.<br />

54. Use <strong>the</strong> Distance Formula to f<strong>in</strong>d QP.<br />

sculpture<br />

2<br />

y<br />

(1, 1)<br />

1<br />

L y<br />

1 L2 n<br />

3.7 <strong>Perpendicular</strong> <strong>L<strong>in</strong>es</strong> <strong>in</strong> <strong>the</strong> Coord<strong>in</strong>ate <strong>Plane</strong> 177<br />

d<br />

drill<br />

L<br />

P(2, 2)<br />

1<br />

1<br />

y<br />

œ<br />

1<br />

1<br />

y –x 3 4<br />

2<br />

y 2x 12<br />

x<br />

x<br />

x


MIXED REVIEW<br />

ANGLE MEASURES Use <strong>the</strong> diagram to complete <strong>the</strong> statement.<br />

(Review 2.6 for 4.1)<br />

55. If m5 = 38°, <strong>the</strong>n m8 = ?.<br />

56. If m3 = 36°, <strong>the</strong>n m4 = ?.<br />

57. If 8 £ 4 and m2 = 145°,<br />

<strong>the</strong>n m7 = ?.<br />

58. If m1 = 38° and 3 £ 5, <strong>the</strong>n m6 = ?.<br />

IDENTIFYING ANGLES Use <strong>the</strong> diagram to complete <strong>the</strong> statement.<br />

(Review 3.1 for 4.1)<br />

59. 3 and ? are consecutive <strong>in</strong>terior angles.<br />

60. 1 and ? are alternate exterior angles.<br />

61. 4 and ? are alternate <strong>in</strong>terior angles.<br />

62. 1 and ? are correspond<strong>in</strong>g angles.<br />

63. Writ<strong>in</strong>g Describe <strong>the</strong> three types of proofs you have learned so far.<br />

(Review 3.2)<br />

QUIZ 3 Self-Test for Lessons 3.6 and 3.7<br />

F<strong>in</strong>d <strong>the</strong> slope of AB<br />

¯˘ . (Lesson 3.6)<br />

178 Chapter 3 <strong>Perpendicular</strong> and Parallel <strong>L<strong>in</strong>es</strong><br />

1. A(1, 2), B(5, 8) 2. A(2, º3), B(º1, 5)<br />

Write an equation of l<strong>in</strong>e j 2 that passes through po<strong>in</strong>t P and is parallel to<br />

l<strong>in</strong>e j 1. (Lesson 3.6)<br />

3. l<strong>in</strong>e j1 : y = 3x º 2 4. l<strong>in</strong>e j1 : y = 1<br />

x + 1<br />

2<br />

P(0, 2) P(2, º4)<br />

Decide whe<strong>the</strong>r k 1 and k 2 are perpendicular. (Lesson 3.7)<br />

5. l<strong>in</strong>e k 1 : y = 2x º 1 6. l<strong>in</strong>e k 1 : y º 3x = º2<br />

l<strong>in</strong>e k 2: y = º 1<br />

2 x + 2 l<strong>in</strong>e k 2: 3y º x = 12<br />

7. ANGLE OF REPOSE When a<br />

granular substance is poured <strong>in</strong>to a<br />

pile, <strong>the</strong> slope of <strong>the</strong> pile depends<br />

only on <strong>the</strong> substance. For example,<br />

when barley is poured <strong>in</strong>to piles,<br />

every pile has <strong>the</strong> same slope. A pile<br />

of barley that is 5 feet tall would be<br />

about 10 feet wide. What is <strong>the</strong> slope<br />

of a pile of barley? (Lesson 3.6)<br />

4<br />

3 2<br />

1 5 6<br />

Not drawn to scale<br />

8<br />

1 4 5<br />

2 3<br />

10 ft<br />

7<br />

8<br />

6 7<br />

5 ft

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