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Dynamics 2<br />

Lecturer: Prof. Dr. G. Lohmann<br />

Due date: 22.04.2011<br />

<strong>Exercise</strong> 1<br />

Summer semester 2013<br />

<strong>Exercise</strong> 1<br />

15.04.2011<br />

April 16, 2013<br />

1. Ekman spiral<br />

Show the Ekman equation and solution which was shown in the lecture. Draw a<br />

figure.<br />

4 points<br />

2. Wind-driven ocean circulation<br />

When the windstress is only zonal, the Sverdrup transport is<br />

ρ 0 βV = curl τ = − ∂ ∂y τ x (1)<br />

and Ekman transports and Ekman pumping velocity of the surface layer are<br />

Assume furthermore<br />

ρ 0 fV E = −τ x (2)<br />

ρ 0 w E = − ∂ ∂y τ x . (3)<br />

τ x = −τ ∗ cos(πy/B) (4)<br />

for an ocean basin 0 < x < L, 0 < y < B. Westerlies are in the northern part and<br />

easterlies are in the equatorward part.<br />

Tasks:<br />

a) Calculate V, V E , w E .<br />

a) At which latitudes are |V | and |V E | at their maximum? Calculate their magnitudes.<br />

Take constant f = 10 −4 s −1 and β = 1.8 · 10 −11 m −1 s −1 and B =<br />

5000 km, τ ∗ /ρ 0 = 10 −4 m 2 s −2 .<br />

b) calculate the maximum of w E for constant f (value see above).<br />

4 points<br />

1


Dynamics 2<br />

Lecturer: Prof. Dr. G. Lohmann<br />

Due date: 22.04.2011<br />

Summer semester 2013<br />

<strong>Exercise</strong> 1<br />

15.04.2011<br />

3. The Stommel model: of the wind-driven circulation in a homogeneous ocean of<br />

constant depth h is described by<br />

R∇ 2 ψ + β∂ x ψ =<br />

1<br />

ρ 0<br />

(∂ x τ y 0 − ∂ y τ x 0 ) (5)<br />

where R is a coefficient of bottom friction, β the derivative of the Coriolis frequency<br />

at a central latitude, and the 2-dimensional τ 0 the windstress vector. The depth<br />

integrated velocity is<br />

(U, V ) =<br />

Finally, ψ is the related streamfunction<br />

∫ 0<br />

−h<br />

(u, v)dz .<br />

U = −∂ y ψ, V = ∂ x ψ .<br />

a) Derive this equation from the conservation of momentum (linearized) and mass<br />

(volume!) assuming w = 0 at the mean surface z = 0 and at the bottom z = −h.<br />

For simplicity take Cartesian coordinates for the horizontal, β = df/dy. Boundary<br />

condition for the flux of momentum are τ(z = 0) = τ 0 and τ(z = −h) = R(−V, U).<br />

b) in the boundary layer the terms on the left hand side of (5) get large. Show by<br />

scaling that the width of the layer is W = R/β.<br />

c) how large must R be to get a width W = 100 km? (β = 2 × 10 −11 m −1 s −1 ).<br />

6 points<br />

Notes on submission form of the exercises: Working in study groups is encouraged,<br />

but each student is responsible for his/her own solution. The answers to the questions<br />

shall be provided at the tutorium at the due date.<br />

2

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