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Momentum - Elastic & Inelastic Collisions PART 1 Elastic Collisions

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LAB# 11<br />

MOMENTUM - ELASTIC & INELASTIC COLLISIONS<br />

Figure 1: Equipment for the "<strong>Elastic</strong> & <strong>Inelastic</strong> <strong>Collisions</strong>" experiment showing the air track, two air<br />

gliders, elastic and inelastic bumpers, two photocells and the glider flags.<br />

Introduction: <strong>Momentum</strong> is one of the important physical variables used in the quantitative<br />

description of dynamics. What makes it important is its usefulness, and what makes it useful is<br />

that in an isolated system it is conserved. The conditions for momentum conservation are: If the<br />

net external force acting on an object, or system of objects, is zero the total momentum of that<br />

object, or system of objects, is constant. The linear momentum of a physical body is defined as<br />

the product of its mass and its velocity,<br />

<br />

P mv.<br />

(1)<br />

It is a vector quantity like velocity, acceleration, and force, and every moving physical body<br />

possesses momentum. When two freely moving bodies collide, momentum is “conserved”. That<br />

is, the momentum of the system before the collision is equal to the momentum of the system<br />

after collision. This Conservation of <strong>Momentum</strong> Law applies to elastic and inelastic collisions,<br />

regardless of the nature of the interaction force between the objects 1 . Thus, using conservation<br />

of momentum even though the details of the forces of collision are complicated and unknown,<br />

you can find the motion of the bodies after a collision if you know their motion before the<br />

collision.<br />

In the first part of this experiment you will analyze only elastic collisions in one dimension.<br />

These are collisions in which the objects rebound from the collision in such a way that kinetic<br />

energy is conserved.<br />

1 Unlike conservation of energy, conservation of momentum is not violated by the actions of internal forces. For<br />

energy, energy is conserved only if the internal forces are conservative.


In the second part of this experiment we will investigate inelastic collisions. These are collisions<br />

where the objects stick together and/or deform so that kinetic energy in not conserved.<br />

Specifically, we will investigate perfectly inelastic collisions. This is a collision where the<br />

objects stick together and move off as one after the collision with the same final velocity.<br />

Equipment: Pasco® air track, the “Lab# 11 <strong>Collisions</strong>” program, two gliders, air track parts kit<br />

which includes the elastic and inelastic bumpers, along with two flags and two photocells. See<br />

Figure 1.<br />

Figure 2 Bumper Plate. One possible choice for bumper in elastic collisions.<br />

NOTE WELL: The computer has only one timer, so it can not time two overlapping intervals. In each<br />

of the following collision experiments, two gliders and two photogates are used. Your time<br />

measurements will be accurate if there is never more than one photogate blocked at any instant. It takes<br />

a little thought and maybe some trial and error to get your data in this experiment. When repeating a<br />

single set of experimental conditions and using the computer to determine the mean velocities: be sure<br />

to cross out any data in which the measured time intervals overlap.<br />

(Hint: Fill in the open circles in front of the procedure steps to help you perform the experiment)<br />

Procedure:<br />

o For all parts of this experiment you will use two gliders of equal mass (m a = m b ).<br />

Attach<br />

counterweights so that the masses of the gliders are equal.<br />

o Find the mass of the gliders after you have attached the bumpers and counterweights. As<br />

shown in Figure 1, attach the rubber band bumper to one glider and a bumper plate to the<br />

other. Note: Some groups find that using two rubber band bumpers, as shown in Figure 1,<br />

and turning one so that they are at 90 angles relative to each other gives better results than<br />

using the bumper plate, see Figure 2. Whichever method you choose is acceptable, just be<br />

sure to be consistent.<br />

o On the opposite ends of the gliders, attach the Velcro bumper for the second part of the<br />

experiment.<br />

o Carefully level the airtrack.


o After you are convinced that the airtrack is level (the gliders don't accelerate in either<br />

direction), and the gliders have equal masses, place two photogates, separated by some<br />

distance from each other, as indicated in Figures 1 and 3.<br />

o In any experiment using two photogates, keep both photogates parallel to each other. And<br />

remember to keep the flag perpendicular to the beam.<br />

<strong>PART</strong> 1 <strong>Elastic</strong> <strong>Collisions</strong>:<br />

Figure 3. <strong>Elastic</strong> collision, mass m a initially at rest. Part 1A<br />

A. Equal masses, one glider at rest.<br />

In the first part of this experiment you setup a collision between the gliders in which one of the<br />

gliders, m a , is initially at rest. See Figure 3.<br />

o Confirm that the airtrack is level.<br />

o Make sure the gliders will collide so that the rubber bumper on one hits the bumper plate, or<br />

the rubber bumper, on the other properly.<br />

o Plug the photogates into the proper ports on the Labpro interface, and open the “Lab# 11<br />

<strong>Collisions</strong>” icon.<br />

o Turn on the air supply to the airtrack and place both gliders on the airtrack.<br />

o Keep glider m a at rest and slightly push m b allowing it to slide freely with a constant velocity<br />

o Be sure that m b passes completely through photogate I before m a enters photogate II.<br />

o Note: Pay special attention to the order of the photogates in the experiment. This information<br />

is necessary to find the correct velocity.<br />

o Repeat this procedure for three (3) trials.<br />

Analysis:<br />

We wish to determine if the momentum of the system was conserved by calculating, and<br />

comparing, the momentum of the system before and after the collision. We will also compare<br />

the kinetic energy of the system before and after the collision to determine if it was conserved.<br />

Since m a was initially at rest the initial and final momentums of the system are given by,<br />

<br />

pi<br />

mbvbi<br />

<br />

(2)<br />

p m v m v<br />

f<br />

The initial and final kinetic energies of the system are given by,<br />

b<br />

bf<br />

a<br />

af


K<br />

f<br />

<br />

K<br />

1<br />

2<br />

<br />

1<br />

i 2 b<br />

2<br />

b bf<br />

m v<br />

m v<br />

<br />

2<br />

bi<br />

1<br />

2<br />

m<br />

a<br />

v<br />

2<br />

af<br />

(3)<br />

Enter the values of your measurements into a table, such as Table 1 below (don’t forget your<br />

units!). Comment on whether momentum was conserved in the collisions. Also comment on<br />

whether kinetic energy was conserved in the collisions. Was there any noticeable relationship<br />

between the initial speed of m b and the final speed of m a ? HINT: What was the apparent speed<br />

of m b after the collision? Looking at Equations (2) and (3) should convince you that for an<br />

initially stationary m a an exchange of velocities between m a and m b is the only possibility.<br />

v bi v af p i p f Ki K f Δp ΔK<br />

Table 1 <strong>Elastic</strong> Collision: One glider at rest.<br />

B. Equal masses, both gliders moving<br />

In this elastic collision both gliders will be in motion towards each other. See Figure 4..<br />

Figure 4. <strong>Elastic</strong> collision, both masses in motion. Part 1B.<br />

In Order to be able to correctly measure the speeds of the gliders when both will be moving<br />

you must adjust the initial positions and velocities such that:<br />

m b passes through photogate I before m aa reaches photogate II.<br />

m a passes through photogate II before m b rebounds back through photogate I.<br />

m b passes back through photogate I before m a rebounds back through photogate II.<br />

Hint: Start m b first with a slow velocity, then, after m b passes photogate I, start m a through<br />

photogate II with a faster velocity. If the collision is performed correctly, the computer will<br />

run through two complete sequences of the collision timing mode, showing all four transit<br />

times.<br />

o Confirm that the airtrack is level.


o Make sure the gliders will collide so that the rubber bumper on one hits the bumper plate, or<br />

the rubber bumper, on the other properly.<br />

o Again, use the “Lab# 11 <strong>Collisions</strong>” Program.<br />

o Turn on the air supply to the airtrack and place both gliders on the airtrack.<br />

o Keep glider m a at rest and slightly push m b allowing it to slide freely with a constant velocity<br />

o Be sure that m b passes completely through photogate I before m a enters photogate II.<br />

o Note: Pay special attention to the order of the photogates in the experiment. This information<br />

is necessary to find the correct velocity.<br />

o Repeat this procedure for three (3) trials.<br />

Analysis:<br />

We again wish to determine if the momentum, as well as the kinetic energy, of the system was<br />

conserved by calculating, and comparing, their respective values before and after the collision.<br />

Since in this part of the experiment both m a and m b were initially moving the initial and final<br />

momentums of the system are given by,<br />

<br />

pi<br />

mbvbimavai<br />

<br />

(4)<br />

p m v m<br />

v<br />

f<br />

b<br />

bf<br />

a<br />

af<br />

The initial and final kinetic energies of the system are given by,<br />

K<br />

K<br />

f<br />

i<br />

<br />

<br />

1<br />

2<br />

1<br />

2<br />

2<br />

b bi<br />

2<br />

b bf<br />

m v<br />

m v<br />

<br />

1<br />

2<br />

<br />

m<br />

1<br />

2<br />

2<br />

abvai<br />

2<br />

avaf<br />

m<br />

(5)<br />

Enter the values of your measurements into a table, such as Table 2 below (don’t forget your<br />

units!). Notice we did use vector notation in equations (4). That is because, even though the<br />

collisions occurred in one dimension, and the full use of vectors is not necessary, momentum is a<br />

vector quantity and you must account for its direction by use of the correct sign. This is the<br />

special case of the use of vectors in one dimension. Typically we take the initial direction of m b<br />

to be the positive direction, so its initial velocity is positive. That makes the initial velocity of m a<br />

negative. In short you must pick a direction to be the positive direction and than account for that<br />

in your calculation of momentum. Comment on whether momentum was conserved in the<br />

collisions. Also comment on whether kinetic energy was conserved in the collisions.<br />

v bi v ai v bf v af p i p f Ki K f Δp ΔK<br />

Table 2 <strong>Elastic</strong> collision: Both gliders moving.<br />

A very useful physical quantity in the study of collisions is that of impulse,<br />

Fdtp.<br />

<br />

I (6)<br />

Impulse gives us a measure of how much an object’s momentum was changed. In a collision<br />

between two objects the impulse delivered to m b by m a must be equal in magnitude and opposite


in direction to the impulse delivered to object m a by object m b (a restatement of Newton’s third<br />

law). Calculate the impulse each mass delivers to the other and comment on whether the<br />

impulses are equal in magnitude and opposite in direction.<br />

p bi p ai p bf p af Δp a Δp b I a I b<br />

Table 3: <strong>Elastic</strong> Collision: Impulse calculation.<br />

Comment on any noticeable relationship between the initial and final speeds speed of m b and m a ?<br />

HINT: This result is only true for elastic collisions between equal mass objects. You may wish<br />

to take a look at your textbook for the final velocities of objects after an elastic collision.<br />

<strong>PART</strong> 2 <strong>Inelastic</strong> <strong>Collisions</strong>: equal masses, one glider initially moving.<br />

We have dealt with the concept of momentum and its conservation for elastic collisions in one<br />

dimension. Now, we can observe the case of an inelastic collision and see whether the law of<br />

conservation of momentum holds under these conditions. When a collision is inelastic, the<br />

kinetic energy is not conserved and is converted to thermal energy and is sometimes used in the<br />

physical deformation of the objects (i.e. automobile accidents). However, it turns out that the<br />

conservation of momentum is still valid. In some situations, such as an explosion, potential<br />

energy is released during the collision and the final kinetic energy may be larger than the initial<br />

kinetic energy! Of course the total kinetic plus potential energy of the system is still conserved 2 .<br />

In the inelastic collision analyzed in this lab, see Figure 5, the two bodies stick together after<br />

collision and have, therefore, a common final velocity. Strictly speaking this type of collision is<br />

termed a perfectly inelastic collision since the objects stick together and move off with the same<br />

final velocity. Again you will be using the “Lab# 11 <strong>Collisions</strong>” program.<br />

o If you have not already done so, attach the Velcro bumpers on the gliders so that, upon<br />

collision, the gliders stick together.<br />

o Be sure to attach matching weights to the opposite end of each glider so the gliders continue<br />

to have equal mass.<br />

o Turn on the air supply to the air track.<br />

o With glider m a at rest between the photogates, push m b allowing it to move completely<br />

through photogate I before colliding with m a .<br />

o After passing photogate I. m b will collide with m a . They will stick together and move along<br />

the track with a common final velocity.<br />

o The computer will record the transit time, and calculate the velocity, of m a (now connected<br />

with m b ) through photogate II.<br />

2 In any event if one adds up all forms of energy, kinetic, potential, thermal, etc. the total energy is always strictly<br />

conserved.


Figure 5. <strong>Inelastic</strong> collision, mass m a initally at rest. Part 2.<br />

Analysis:<br />

As with the previous parts of this experiment we wish to determine if the momentum, as well as<br />

the kinetic energy, of the system was conserved. In this part of the experiment m a was initially at<br />

rest, and m a and m b had the same final velocities. Therefore the initial and final momentums of<br />

the system are give by,<br />

p m v<br />

p<br />

f<br />

i<br />

b<br />

b<br />

bi<br />

( m m<br />

) v<br />

a<br />

f<br />

(7)<br />

The initial and final kinetic energies of the system are given by,<br />

K<br />

f<br />

1 2<br />

i<br />

<br />

2<br />

mbvbi<br />

1<br />

2<br />

2<br />

( mb<br />

ma<br />

) v<br />

f<br />

K<br />

<br />

(8)<br />

Enter the values of your measurements into a table, such Table 4 below. Comment on whether<br />

momentum was conserved in the collisions. Also comment on whether kinetic energy was<br />

conserved in the collisions. If kinetic energy was not conserved, where do you think it went?<br />

What percentage of the systems initial kinetic energy was converted to other forms of energy?<br />

v bi v f p i p f Ki K f Δp ΔK %K i “lost”<br />

Table 4 <strong>Inelastic</strong> collision: One glider at rest.<br />

Questions:<br />

1. The relationship of velocities,<br />

vbf<br />

vaf<br />

,<br />

(9)<br />

vai<br />

vbi<br />

is called the coefficient of restitution. Using one of your trials from part (2) of this experiment<br />

and one of your trials from part (1A) of this experiment calculate the coefficient of restitution for<br />

these two situations. Describe, in your own words, what the coefficient of restitution for a<br />

collision tells us. You may wish to think, for example, in terms of the collision that takes place<br />

between a racket ball and a racket (http://www.racquetresearch.com/coeffici.htm).


2. It is interesting to note the change in momentum of the target object, for us m a , in the two<br />

different types of collisions (m a initially at rest is the elastic and perfectly inelastic collisions).<br />

Pick a trial from part (1A) and part (2) where the initial velocities of m b are as similar as<br />

possible. Calculate the change in momentum of m a for the two cases and comment on the<br />

differences. Specifically for which case is the change in momentum for m a the greatest? Briefly<br />

explain why this makes sense, from the point of view of conservation of momentum.<br />

HINT: momentum is a vector! Lastly, let us say you are a scientist or engineer working for<br />

NASA and you are tasked with the responsibility of diverting an asteroid heading straight for<br />

Earth. You know that you must deflect the asteroid as much as possible (without breaking it into<br />

many Earth destroying pieces). The asteroid is the target. Would you want your projectile to<br />

make an elastic or inelastic collision with the asteroid, in the hopes of changing its momentum<br />

by the greatest amount? Briefly explain. Good luck with that task, no pressure!

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