PointView presentation for Grid-Interop 2010 by Navindra Yadav

gridwiseac.org

PointView presentation for Grid-Interop 2010 by Navindra Yadav

Calculation of Network Availability

• Identify the Serial and Parallel components

1 3 5

2 4

2 4 6

1 3 5 7

6 8

9

• Failure of any node, link disrupts

• Network Availability = A = A 1 * A 2

* A 3 * A 4 * A 5 * A 6 * A 7

• If all A * are 90%.

• A = 0.4782969 = 47%

9 11 13 15

10

12 14

• Assume a simple Active-Active Design

• Network Availability = 1 – (UnAvail_P1

* UnAvail_P2 * UnAvail_P3) =

• = 1 – ((1-Avail_P1) * (1-Avail_P1) * (1-

Avail_P1))

• If all A * are 90%

• A= 1 – ((1-0.59049)* (1-0.729) * (1-

0.4782969))

• = 1 – (0.40951* .271 * . 0.5217031)

• = 0.942102845513649 = 94%

Grid-Interop 2010

© 2010 Cisco Systems, Inc. All rights reserved. 5

More magazines by this user
Similar magazines