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Chapter 6 Partial Differential Equations

Chapter 6 Partial Differential Equations

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6.1. INTRODUCTION 5<br />

Solutions to Laplace’s equation ∆u(x) = 0 are said to be harmonic. Suppose f(z) =<br />

f(x + iy) =u(x, y)+iv(x, y) is analytic. The Cauchy-Riemann equations state that<br />

∂u<br />

∂x = ∂v<br />

∂y ,<br />

∂u<br />

∂y = −∂v ∂x<br />

and so<br />

u xx + u yy =0, v xx + v yy =0.<br />

Thus the real and imaginary parts of an analytic function are harmonic. There is a converse<br />

statement of this result known as Weyl’s Theorem that depends on the notion of a weak<br />

solution. Roughly stated, ∆u(x) = 0 in a weak sense if for all smooth functions φ with<br />

compact support in Ω, ∫<br />

u(x)(∆φ)(x) dx =0.<br />

We will not prove this next result.<br />

Ω<br />

Weyl’s Theorem If u is a weak solution of ∆u(x) = 0 on Ω, then u ∈ C ∞ (Ω) and u<br />

satisfies Laplace’s equation in a classical sense.<br />

The so-called Cauchy problem for Laplace’s equation,<br />

u xx + u yy =0, |x| < ∞,y >0<br />

u(x, 0) = f(x),<br />

u y (x, 0) = g(x),<br />

is not well-posed. Indeed, consider the specific problem<br />

u xx + u yy =0, |x| < ∞,y >0<br />

cos nx<br />

u(x, 0) =<br />

n<br />

u y (x, 0)=0<br />

with the solution<br />

u n (x, y) = 1 cosh(ny) cos(nx).<br />

n<br />

For n sufficiently large, the data of this problem can be made uniformly small. However,<br />

lim u n(x, y) =∞.<br />

n→∞<br />

In other words, small changes in the data do not correspond to small changes in a solution.

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