dilute NaOH solution is added to a pale
dilute NaOH solution is added to a pale
dilute NaOH solution is added to a pale
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A white precipitate of th<strong>is</strong> ion does not red<strong>is</strong>solve<br />
in excess <strong>NaOH</strong>. When <strong>dilute</strong> sulfuric acid <strong>is</strong><br />
<strong>added</strong> <strong>to</strong> the original <strong>solution</strong>, a white precipitate<br />
forms.<br />
Name the ion.<br />
Give the formulae for the first AND the second<br />
precipitates.<br />
A white precipitate of th<strong>is</strong> ion red<strong>is</strong>solves in<br />
excess <strong>NaOH</strong>. When excess <strong>dilute</strong> ammonia<br />
<strong>solution</strong> <strong>is</strong> <strong>added</strong> <strong>to</strong> the original <strong>solution</strong>, a white<br />
precipitate forms and remains. When <strong>dilute</strong><br />
sulfuric acid <strong>is</strong> <strong>added</strong> <strong>to</strong> the original <strong>solution</strong> no<br />
precipitate <strong>is</strong> seen.<br />
Name the ion present.<br />
Give the formula for the first and second precipitate.<br />
A white precipitate of th<strong>is</strong> ion does not red<strong>is</strong>solve<br />
in excess <strong>NaOH</strong>. When <strong>dilute</strong> sulfuric acid <strong>is</strong><br />
<strong>added</strong> <strong>to</strong> the original <strong>solution</strong>, the <strong>solution</strong><br />
remains colourless.<br />
Name the ion present.<br />
Give the formula for the precipitate.<br />
A white precipitate of th<strong>is</strong> ion red<strong>is</strong>solves in<br />
excess <strong>NaOH</strong>. When excess <strong>dilute</strong> ammonia<br />
<strong>solution</strong> <strong>is</strong> <strong>added</strong> <strong>to</strong> the original <strong>solution</strong>, a white<br />
precipitate forms and remains. When <strong>dilute</strong><br />
sulfuric acid <strong>is</strong> <strong>added</strong> <strong>to</strong> the original <strong>solution</strong>, a<br />
white precipitate forms.<br />
Name the ion.<br />
Give the formulae for the first, second AND the<br />
third precipitates.