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Structural Design of Pavements PART VI Structural ... - TU Delft

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41<br />

Normally BB measurements are only taken in the wheel tracks. These values are in fact the<br />

Def n values since that pavement area has been subjected to n load repetitions. If we also take<br />

deflection measurements between the wheel tracks, then we get a good estimate <strong>of</strong> the<br />

flexural stiffness <strong>of</strong> that part <strong>of</strong> the pavement that is not subjected to traffic loads. These<br />

deflections can be taken as representative for Def 0 .<br />

Assume that the deflection measured between the wheel tracks is 350 µm and that the<br />

deflection in the wheel tracks is 390 µm. The pavement has an unbound base. Then we arrive<br />

to:<br />

DeltaDef n = 390 – 350 = 40<br />

and<br />

DeltaDef c / Def 0 = 0.4767 – 0.000299 x 350 = 0.372<br />

so<br />

DeltaDef c = 0.372 x 350 = 130<br />

We also calculate:<br />

b = 0.91<br />

so<br />

DeltaDef n / DeltaDef c = (n / N) b<br />

40 / 130 = (n / N) 0.91<br />

n / N = 0.27<br />

Normally road authorities are not interested in a damage ratio or a remaining pavement life<br />

expressed in a number <strong>of</strong> allowable load repetitions but much more in a remaining life in<br />

years. This can be estimated in the following way.<br />

Assume the traffic composition has not changed in time and for reasons <strong>of</strong> simplicity we also<br />

assume that no growth in the number. <strong>of</strong> vehicles per day has taken place. This means that<br />

the area indicated in figure 26 is representative for the cumulative amount <strong>of</strong> traffic n that has<br />

passed the road during time period t.<br />

Traffic intensity<br />

n<br />

N<br />

t<br />

T<br />

Time<br />

Figure 26: Procedure to estimate the remaining life in years from the n/N ratio.<br />

In the same way the allowable number <strong>of</strong> load repetitions N is arrived after T years. From this<br />

simple example it is clear that in this case:<br />

t / T = n / N

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