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Algebraic Topology Problem Set 2 — Solutions - Strickland, Neil

Algebraic Topology Problem Set 2 — Solutions - Strickland, Neil

2Q5:(a) Just take X =

2Q5:(a) Just take X = (0, ∞) and f(x) = x. Clearly f(x) > 0 for all x ∈ X. However, if ɛ > 0 thenɛ/2 ∈ X and f(ɛ/2) = ɛ/2 < ɛ, so it is not true that f(x) ≥ ɛ for all x ∈ X.(b) Now suppose that X is compact and f : X −→ R is continuous and f(x) > 0 for all x ∈ X.Consider the function g(x) = 1/f(x), which is defined and continuous everywhere on Xbecause f(x) > 0 for all x. We know that a continuous function from a compact space to Ris bounded, so there is some constant C > 0 such that g(x) ≤ C for all x. Now put ɛ = 1/Cand observe that f(x) = 1/g(x) ≥ 1/C = ɛ for all x.

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