MATHEMATICS
28Ur3tG
28Ur3tG
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The circle<br />
The equation of the tangent at P(4, 3) is<br />
y − 3 y 3<br />
4<br />
y= −<br />
4<br />
= − x 4<br />
3 ( − = x− x<br />
3 ( −<br />
3 4) ( − 4) 4)<br />
3y<br />
➝<br />
− 93y= − 16 39y−<br />
= − 416 9x<br />
= −16 4x−<br />
4x<br />
➝ 4x<br />
+ 34yx− + 25 43xy=<br />
+ − 0325 y − = 25 0 = 0<br />
(ii) OQR forms a right-angled triangle.<br />
Find Q:<br />
3 y<br />
− 25 =<br />
0<br />
➝ y =<br />
25<br />
3<br />
Find R:<br />
4 x<br />
− 25 =<br />
0<br />
➝<br />
x<br />
=<br />
25<br />
4<br />
Area of triangle OQR is<br />
1 25<br />
2<br />
× 25 625<br />
4<br />
× 3<br />
= 24<br />
square units.<br />
Area is 1 × base × height.<br />
2<br />
The base is the x coordinate<br />
of R and the height is the<br />
y coordinate of Q.<br />
Substitute x = 0 into the<br />
tangent equation to find Q.<br />
Substitute y = 0 into the<br />
tangent equation to find R.<br />
Exact means leave your answer<br />
as a fraction (or a surd).<br />
Exercise 5.4<br />
1 Find the equations of the following circles.<br />
(i) centre (2, 3), radius 1<br />
(ii) centre (2, −3), radius 2<br />
(iii) centre (−2, 3), radius 3<br />
(iv) centre (−2, −3), radius 4<br />
2 For each of the following circles state<br />
(a) the coordinates of the centre<br />
(b) the radius.<br />
(i) x 2 + y 2 = 1<br />
(ii) x 2 + (y − 2) 2 = 2<br />
(iii) (x – 2) 2 + y 2 = 3<br />
(iv) (x + 2) 2 + (y + 2) 2 = 4<br />
(v) (x − 2 ) 2 + (y +2) 2 = 5<br />
3 The equation of a circle is (x − 3) 2 + (y + 2) 2 = 26.<br />
Complete the table to show whether each point lies inside the circle,<br />
outside the circle or on the circle.<br />
Point Inside Outside On<br />
(3, −2) ¸<br />
(−2, −5)<br />
(6, −6)<br />
(4, 3)<br />
(0, 2)<br />
(−2, −3)<br />
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