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MATHEMATICS

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The circle<br />

The equation of the tangent at P(4, 3) is<br />

y − 3 y 3<br />

4<br />

y= −<br />

4<br />

= − x 4<br />

3 ( − = x− x<br />

3 ( −<br />

3 4) ( − 4) 4)<br />

3y<br />

➝<br />

− 93y= − 16 39y−<br />

= − 416 9x<br />

= −16 4x−<br />

4x<br />

➝ 4x<br />

+ 34yx− + 25 43xy=<br />

+ − 0325 y − = 25 0 = 0<br />

(ii) OQR forms a right-angled triangle.<br />

Find Q:<br />

3 y<br />

− 25 =<br />

0<br />

➝ y =<br />

25<br />

3<br />

Find R:<br />

4 x<br />

− 25 =<br />

0<br />

➝<br />

x<br />

=<br />

25<br />

4<br />

Area of triangle OQR is<br />

1 25<br />

2<br />

× 25 625<br />

4<br />

× 3<br />

= 24<br />

square units.<br />

Area is 1 × base × height.<br />

2<br />

The base is the x coordinate<br />

of R and the height is the<br />

y coordinate of Q.<br />

Substitute x = 0 into the<br />

tangent equation to find Q.<br />

Substitute y = 0 into the<br />

tangent equation to find R.<br />

Exact means leave your answer<br />

as a fraction (or a surd).<br />

Exercise 5.4<br />

1 Find the equations of the following circles.<br />

(i) centre (2, 3), radius 1<br />

(ii) centre (2, −3), radius 2<br />

(iii) centre (−2, 3), radius 3<br />

(iv) centre (−2, −3), radius 4<br />

2 For each of the following circles state<br />

(a) the coordinates of the centre<br />

(b) the radius.<br />

(i) x 2 + y 2 = 1<br />

(ii) x 2 + (y − 2) 2 = 2<br />

(iii) (x – 2) 2 + y 2 = 3<br />

(iv) (x + 2) 2 + (y + 2) 2 = 4<br />

(v) (x − 2 ) 2 + (y +2) 2 = 5<br />

3 The equation of a circle is (x − 3) 2 + (y + 2) 2 = 26.<br />

Complete the table to show whether each point lies inside the circle,<br />

outside the circle or on the circle.<br />

Point Inside Outside On<br />

(3, −2) ¸<br />

(−2, −5)<br />

(6, −6)<br />

(4, 3)<br />

(0, 2)<br />

(−2, −3)<br />

22

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