Views
1 year ago

# Final NB 2016-2017 Turley

## 22 Rule 3: A final zero

22 Rule 3: A final zero or trailing zeros in the decimal portion ONLY are significant. This rule causes the most confusion among students. In the following example the zeros are significant digits and highlighted in blue. 0.07030 0.00800 Here are two more examples where the significant zeros are highlighted in blue. When Zeros are Not Significant Digits 4.7 0 x 10−³ 6.5 0 0 x 10⁴ Zero Type # 1 : Space holding zeros in numbers less than one. In the following example the zeros are NOT significant digits and highlighted in red. 0.09060 0.00400 These zeros serve only as space holders. They are there to put the decimal point in its correct location. They DO NOT involve measurement decisions. Zero Type # 2 : Trailing zeros in a whole number. In the following example the zeros are NOT significant digits and highlighted in red. 200 25000 For addition and subtraction, look at the decimal portion (i.e., to the right of the decimal point) of the numbers ONLY. Here is what to do: 1) Count the number of significant figures in the decimal portion of each number in the problem. (The digits to the left of the decimal place are not used to determine the number of decimal places in the final answer.) 2) Add or subtract in the normal fashion. 3) Round the answer to the LEAST number of places in the decimal portion of any number in the problem The following rule applies for multiplication and division: The LEAST number of significant figures in any number of the problem determines the number of significant figures in the answer. This means you MUST know how to recognize significant figures in order to use this rule.

How Many Significant Digits for Each Number? 1) 2359 = ______ 4 2) 2.445 x 10−⁵= ______ 4 3) 2.93 x 10⁴= ______ 3 4) 1.30 x 10−⁷= ______ 3 5) 2604 = ______ 4 6) 9160 = ______ 4 7) 0.0800 = ______ 3 8) 0.84 = ______ 2 9) 0.0080 = ______ 2 10) 0.00040 = ______ 2 11) 0.0520 = ______ 3 12) 0.060 = ______ 2 13) 6.90 x 10−¹= ______ 3 14) 7.200 x 10⁵= ______ 4 15) 5.566 x 10−²= ______ 4 16) 3.88 x 10⁸= ______ 3 17) 3004 = ______ 4 18) 0.021 = ______ 2 19) 240 = ______ 2 20) 500 = ______ 1 23

Chemistry Notebook - Torres
chap04 - Learning Services Home
Ch 12 Quantum mechanics and atomic theory
I. COMPOUNDS & BONDING