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Final NB 2016-2017 Turley

6) ___ Mn(NO2)2 + ___

6) ___ Mn(NO2)2 + ___ BeCl2 ___ Be(NO2)2 + ___ MnCl2 Already Balanced Mn 1 Mn 1 N 2 N 2 O 2 O 2 Be 1 Be 1 Cl 2 Cl 2 7) ___ 3 AgBr + ___ GaPO4 ___ Ag3PO4 + ___ GaBr3 3x Ag 1 Br 1 Ga 1 P 1 O 4 Ag 3 Br 3 Ga 1 P 1 O 4 8) ___ 3 H2SO4 + ___ 3 B(OH)3 __ B2(SO4)3 + ___ 6 H2O H 2 B 2 S 1 S 3 3x O 4 O 12 B 1 H 2 O 3 O 1 x6 2x H 3 9) ___ 1 S8 + ___ 8 O2 ___ 8 SO2 8x S 8 o 2 S 1 O 2 x8 10) ___ Fe + ___ 2 AgNO3 ___ Fe(NO3)2 + ___ 2 Ag Fe 1 Ag 1 N 1 O 3 x2 Fe 1 N 2 O 6 Ag 1 x2 94

1) 2 NaNO3 + PbO Pb(NO3)2 + Na2O 2) 6 AgI + Fe2(CO3)3 2 FeI3 + 3 Ag2CO3 3) C2H4O2 + 2 O2 2 CO2 + 2 H2O 4) ZnSO4 + Li2CO3 ZnCO3 + Li2SO4 5) V2O5 + 5 CaS 5 CaO + V2S5 6) Mn(NO2)2 + BeCl2 Be(NO2)2 + MnCl2 7) 3 AgBr + GaPO4 Ag3PO4 + GaBr3 8) 3 H2SO4 + 2 B(OH)3 B2(SO4)3 + 6 H2O 9) S8 + 8 O2 8 SO2 10) Fe + 2 AgNO3 Fe(NO3)2 + 2 Ag Additional Notes: -Focus on the bigger parts of the equation being balanced first -There can be no decimals -Every equation can be balanced -If you use fraction than time it by two to get rid of it. -Leave the parts of the equation with a single element for last. -No matter can be created nor destroyed -6 Easy Steps 1.Determine the correct formulas for all the reactants and products in the reaction. 2.Begin balancing with the most complicated-looking group. A polyatomic ion that appears unchanged on both sides of the equation can be counted as a single unit. 3.Save the elemental (single elements) reactant and products for last, especially if it is hydrogen or oxygen. Keep your eye out for diatomic molecules such as oxygen, hydrogen, and the halogens. 4.If you get stuck, double the most complicated-looking group and try again. 5.Finally, make sure that all coefficients are in the lowest-possible ratio. 6.Know when to quit! None of the reactions you will encounter will be that difficult. If the coefficients are getting wild, double-check what you’ve done since you may have a simple mistake. 95

Chemistry Notebook - Torres
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Ch 12 Quantum mechanics and atomic theory