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2. What is the oxidation number of Na in Na2O?<br />

Since O = -2, the two Na must each be +1.<br />

3. What is the oxidation number of Cl in ClO¯?<br />

The O is -2, but since a -1 must be left over, then the Cl is +1.<br />

4. What is the oxidation number for each element in KMnO4?<br />

K = +1 because KCl exists. We know the Cl = -1 because HCl exists.<br />

O = -2 by definition<br />

Mn = +7. There are 4 oxygens for a total of -8, K is +1, so Mn must be the rest.<br />

5. What is the oxidation number of S in SO4 2¯<br />

O = -2. There are four oxygens for -8 total. Since -2 must be left over, the S must = +6.<br />

Please note that, if there is no charge indicated on a formula, the total charge is taken to be zero.<br />

Practice Problems<br />

Find oxidation numbers<br />

1. N in NO3¯<br />

2. C in CO3 2¯<br />

3. Cr in CrO4 2¯<br />

N is 5+ because the charge is -1 so -6+5=-1<br />

C is 4+ because the charge is -2 so -6+4= -2<br />

Cr is +6 because the charge is -2 so -8+6=-2<br />

4. Cr in Cr2O7 2¯<br />

5. Fe in Fe2O3<br />

6. Pb in PbOH +<br />

7. V in VO2 +<br />

8. V in VO 2+<br />

9. Mn in MnO4¯<br />

10. Mn in MnO4 2¯<br />

Cr is -8 because the charge is -2 so -16-14=-2<br />

Fe is 3+ because the charge is 0 so 6-6=0<br />

2+<br />

5+<br />

4+<br />

7+<br />

6+<br />

Notes:<br />

Depending on the charge + or - number of the problem, it can vary what the oxidation number of an element can be.<br />

Oxygen is normally -2 it all depends on the ion charge. The oxidation number of something like Magnesium can change<br />

completely to something its not in charge wise so that it can complete the problem.<br />

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