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[ COMBO ] BỒI DƯỠNG TOÁN 8 NÂNG CAO VÀ PHÁT TRIỂN (VŨ HỮU BÌNH-NXBGD) & TUYỂN TẬP ĐỀ THI HSG TOÁN 8 (NGUYỄN VĂN TÚ-THCS THANH MỸ)

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4<br />

5<br />

a<br />

b<br />

c<br />

Tuyển tập đề thi <strong>HSG</strong> Toán 8<br />

x −1<br />

⇒ =<br />

3 2<br />

y − 1 y + y + 1<br />

y −1<br />

− 1 = ( −1)( − + 1) = − ( − + 1)<br />

⇒ =<br />

3 2<br />

x − 1 x + x + 1<br />

3 2 2<br />

x x x x y x x<br />

x y −1 −1<br />

⇒ + = +<br />

3 3 2 2<br />

y −1 x − 1 y + y + 1 x + x + 1<br />

2<br />

( x + y) − 2xy + ( x + y)<br />

+ 2<br />

2<br />

⎜<br />

⎝ ( ) ( ) ( )<br />

( xy − )<br />

⎛ 2 2<br />

x + x + 1+ y + y + 1 ⎞ ⎛ ⎞<br />

= − = −⎜ ⎜<br />

2 2 2 2<br />

( x x 1)( y y 1)<br />

⎟ x y x y 2xy xy x y xy x y 1⎟<br />

⎝<br />

+ + + +<br />

⎠ + + − + + + + + + ⎠<br />

4 − 2xy x y 2 2<br />

= − ⇒ + − = 0<br />

2 2 3 3 2 2<br />

x y + 3 y −1 x − 1 x y + 3<br />

Ta cã: M = ( x 2 x )( x 2 x )<br />

+ 10 + 16 + 10 + 24 + 16<br />

§Æt a = x 2 + 10x + 16 suy ra M = a( a+8) + 16 = a 2 + 8a + 16 = ( a+ 4) 2<br />

M = ( x 2 + 10x + 20 ) 2 ( ®pcm)<br />

gi¸c AHD vu«ng c©n t¹i H theo gi thiÕt).<br />

+ Hai tam gi¸c ADC vµ BEC cã:<br />

Gãc C chung.<br />

CD CA<br />

= (Hai tam gi¸c vu«ng CDE<br />

CE CB<br />

vµ CAB ®ång d¹ng)<br />

Do ®ã, chóng dång d¹ng (c.g.c).<br />

Suy ra: 0<br />

BEC = ADC = 135 (v× tam<br />

Nªn 0<br />

AEB = 45 do ®ã tam gi¸c ABE vu«ng c©n t¹i A. Suy ra: BE = AB 2 = m 2<br />

BM 1 BE 1 AD<br />

Ta cã: = ⋅ = ⋅ (do ∆BEC ∼ ∆ADC<br />

)<br />

BC 2 BC 2 AC<br />

mµ AD = AH 2 (tam gi¸c AHD vu«ng c©n t¹i H)<br />

BM 1 AD 1 AH 2 BH BH<br />

nªn = ⋅ = ⋅ = = (do ∆ABH ∼ ∆CBA<br />

)<br />

BC 2 AC 2 AC AB 2 BE<br />

Do ®ã ∆BHM ∼ ∆BEC<br />

(c.g.c), suy ra: BHM = BEC = 135 ⇒ AHM = 45<br />

0 0<br />

Tam gi¸c ABE vu«ng c©n t¹i A, nªn tia AM cßn lµ ph©n gi¸c gãc BAC.<br />

Suy ra: GB = AB , mµ AB = ED ( ∆ABC ∼ ∆ DEC ) = AH ( ED // AH ) =<br />

HD<br />

GC AC AC DC HC HC<br />

GB HD GB HD GB HD<br />

Do ®ã: = ⇒ = ⇒ =<br />

GC HC GB + GC HD + HC BC AH + HC<br />

<strong>ĐỀ</strong> SỐ 35<br />

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