Class XI Chapter **11** – Conic Section Maths ______________________________________________________________________________ Exercise **11**.1 Book Name: **NCERT** Solutions Question 1: Find the equation of the circle with centre (0, 2) and radius 2 Solution 1: The equation of a circle with centre (h, k) and radius r is given as (x - h) 2 + (y - k) 2 = r 2 It is given that centre (h, k) = (0, 2) and radius (r) = 2. Therefore, the equation of the circle is x y 2 2 2 0 2 2 2 2 x y y 44 4 2 2 x y y 4 0 Question 2: Find the equation of the circle with centre (-2, 3) and radius 4 Solution 2: The equation of a circle with centre (h, k) and radius r is given as (x - h) 2 + (y - k) 2 = r 2 It is given that centre (h, k) = (-2, 3) and radius (r) = 4. Therefore, the equation of the circle is (x + 2) 2 + (y - 3) 2 = (4) 2 X 2 + 4x + 4 + y 2 - 6y + 9 = 16 X 2 + y 2 + 4x - 6y - 3 = 0 Question 3: 1 1 Find the equation of the circle with centre , 2 4 and radius 1 12 Solution 3: The equation of a circle with centre (h, k) and radius r is given as (x â€“ h) 2 + (y â€“ k) 2 = r 2 It is given that centre (h, k) = 1 1 , 2 4 and radius (r) = 1 12 Printed from Vedantu.com. Register now to book a Free LIVE Online trial session with a Top tutor.

Class XI Chapter **11** – Conic Section Maths ______________________________________________________________________________ Therefore, the equation of the circle is 2 2 2 1 1 1 x 2 y 4 12 2 1 2 y 1 1 x x y 4 2 16 144 2 1 2 y 1 1 x x y 0 4 2 16 144 2 2 144x 144x 36 144 y 72y 91 0 2 2 144x 144x 144 y 72y 44 0 2 2 36x 36x 36y 18y **11** 0 2 2 36x 36y 36x 18y **11** 0 Question 4: Find the equation of the circle with centre (1, 1) and radius 2 Solution 4: The equation of a circle with centre (h, k) and radius r is given as (x â€“ h) 2 + (y â€“ k) 2 = r2 It is given that centre (h, k) = (1, 1) and radius (r) = 2 . Therefore, the equation of the circle is x1 2 y1 2 2 2 2 2 x x y y 2 1 2 1 2 2 2 x y x y 2 2 0 Question 5: Find the equation of the circle with centre (â€“a, â€“b) and radius Solution 5: The equation of a circle with centre (h, k) and radius r is given as (x â€“ h) 2 + (y â€“ k) 2 = r 2 It is given that centre (h, k) = (â€“a, â€“b) and radius (r) = Therefore, the equation of the circle is a 2 2 a b . b 2 2 Printed from Vedantu.com. Register now to book a Free LIVE Online trial session with a Top tutor.

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**Magazine:** CLASS_11_MATHS_SOLUTIONS_NCERT

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