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01 Solutions 46060 5/6/10 2:43 PM Page 11 © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. 1–18. The bolt shank is subjected to a tension of 80 lb. Determine the resultant internal loadings acting on the cross section at point C. 90 C 6 in. A B Segment AC: : + ©F x = 0; N C + 80 = 0; N C = -80 lb + c ©F y = 0; V C = 0 a+©M C = 0; M C + 80(6) = 0; M C = -480 lb # in. Ans. Ans. Ans. 1–19. Determine the resultant internal loadings acting on the cross section through point C. Assume the reactions at the supports A and B are vertical. 6 kip/ft 6 kip/ft A C D B 3 ft 3 ft 6 ft Referring to the FBD of the entire beam, Fig. a, a+ ©M B = 0; 1 2 (6)(6)(2) + 1 2 (6)(6)(10) - A y(12) = 0 A y = 18.0 kip Referring to the FBD of this segment, Fig. b, : + ©F x = 0; N C = 0 Ans. + c ©F y = 0; 18.0 - 1 2 (3)(3) - (3)(3) - V C = 0 V C = 4.50 kip Ans. a +©M C = 0; M C + (3)(3)(1.5) + 1 (3)(3)(2) - 18.0(3) = 0 2 M C = 31.5 kip # ft Ans. 11

01 Solutions 46060 5/6/10 2:43 PM Page 12 © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. *1–20. Determine the resultant internal loadings acting on the cross section through point D. Assume the reactions at the supports A and B are vertical. 6 kip/ft 6 kip/ft Referring to the FBD of the entire beam, Fig. a, a+©M B = 0; 1 2 (6)(6)(2) + 1 2 (6)(6)(10) - A y(12) = 0 A y = 18.0 kip A C 3 ft 3 ft D 6 ft B Referring to the FBD of this segment, Fig. b, : + ©F x = 0; N D = 0 Ans. + c ©F y = 0; 18.0 - 1 2 (6)(6) - V D = 0 V D = 0 Ans. a+©M A = 0; M D - 18.0 (2) = 0 M D = 36.0 kip # ft Ans. •1–21. The forged steel cl**amp** exerts a force of F = 900 N on the wooden block. Determine the resultant internal loadings acting on section a–a passing through point A. 200 mm F 900 N Internal Loadings: Referring to the free-body diagram of the section of the cl**amp** shown in Fig. a, ©F y¿ = 0; 900 cos 30° - N a - a = 0 N a - a = 779 N ©F x¿ = 0; V a - a - 900 sin 30° = 0 V a - a = 450 N Ans. Ans. 30 A a F 900 N a+©M A = 0; 900(0.2) - M a - a = 0 M a - a = 180 N # m Ans. a 12

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