- Text
- Determine,
- Shear,
- Portion,
- Solutions,
- Pearson,
- Saddle,
- Copyright,
- Currently,
- Reproduced,
- Diameter,
- Strain,
- Properties

01 Solutions 46060 5/6/10 2:43 PM Page 41 © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. •1–57. The specimen failed in a tension test at an angle of 52° when the axial load was 19.80 kip. If the diameter of the specimen is 0.5 in., determine the average normal and average shear **stress** acting on the area of the inclined failure plane. Also, what is the average normal **stress** acting on the cross section when failure occurs? 52 0.5 in. + b © F x = 0; V - 19.80 cos 52° = 0 V = 12.19 kip +a © F y = 0; N - 19.80 sin 52° = 0 N = 15.6**03** kip Inclined plane: s¿ = P A t œ avg = V A ; tœ avg = 12.19 p(0.25) 2 Cross section: ; s¿ =15.6**03** p(0.25) 2 sin 52° s = P A ; s = 19.80 = 101 ksi 2 p(0.25) t avg = V A ; t avg = 0 sin 52° = 62.6 ksi = 48.9 ksi Ans. Ans. Ans. Ans. 1–58. The anchor bolt was pulled out of the concrete wall and the failure surface formed part of a frustum and cylinder. This indicates a shear failure occurred along the cylinder BC and tension failure along the frustum AB. If the shear and normal **stress**es along these surfaces have the magnitudes shown, determine the force P that must have been applied to the bolt. A 45 P 45 Average Normal Stress: For the frustum, A = 2pxL = 2p(0.025 + 0.025)A 2 0.05 2 + 0.05 2 B = 0.02221 m 2 50 mm 3 MPa 3 MPa B 30 mm 4.5 MPa s = P A ; 3A106 B = F 1 = 66.64 kN F 1 0.02221 C 25 mm 25 mm Average Shear Stress: For the cylinder, A = p(0.05)(0.**03**) = 0.004712 m 2 t avg = V A ; F 2 4.5A106 B = 0.004712 Equation of Equilibrium: F 2 = 21.21 kN + c ©F y = 0; P - 21.21 - 66.64 sin 45° = 0 P = 68.3 kN Ans. 41

01 Solutions 46060 5/6/10 2:43 PM Page 42 © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. 1–59. The open square butt joint is used to transmit a force of 50 kip from one plate to the other. Determine the average normal and average shear **stress** components that this loading creates on the face of the weld, section AB. 50 kip 30 30 Equations of Equilibrium: a + © F y = 0; N - 50 cos 30° = 0 N = 43.30 kip + Q© F x = 0; -V + 50 sin 30° = 0 V = 25.0 kip A B 6 in. 2 in. 50 kip Average Normal and Shear Stress: 2 A¿ =a b(6) = 13.86 in2 sin 60° s = N = 43.30 = 3.125 ksi A¿ 13.86 t avg = V = 25.0 = 1.80 ksi A¿ 13.86 Ans. Ans. *1–60. If P = 20 kN, determine the average shear **stress** developed in the pins at A and C. The pins are subjected to double shear as shown, and each has a diameter of 18 mm. C Referring to the FBD of member AB,Fig.a a+©M A = 0; F BC sin 30° (6) - 20(2) - 20(4) = 0 F BC = 40 kN : + ©F x = 0; A x - 40 cos 30° = 0 A x = 34.64 kN A 2 m 2 m 30 2 m B + c ©F y = 0; A y - 20 - 20 + 40 sin 30° A y = 20 kN Thus, the force acting on pin A is F A = 2 A x 2 + A y 2 = 2 34.64 2 + 20 2 = 40 kN Pins A and C are subjected to double shear. Referring to their FBDs in Figs. b and c, V A = F A 2 = 40 2 = 20 kN V C = F BC = 40 = 20 kN 2 2 = 81(10 - 6 )p m 2 . Thus The cross-sectional area of Pins A and C are A A = A C = p 4 (0.0182 ) t A = V A A A = 20(1**03** ) 81(10 - 6 )p = 78.59(106 ) Pa = 78.6 MPa t C = V C A C = 20(1**03** ) 81(10 - 6 )p = 78.59(106 ) Pa = 78.6 MPa Ans. Ans. P P 42

- Page 1 and 2: FM_TOC 46060 6/22/10 11:26 AM Page
- Page 3 and 4: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 5 and 6: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 7 and 8: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 9 and 10: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 11 and 12: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 13 and 14: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 15 and 16: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 17 and 18: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 19 and 20: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 21 and 22: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 23 and 24: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 25 and 26: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 27 and 28: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 29 and 30: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 31 and 32: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 33 and 34: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 35 and 36: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 37 and 38: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 39 and 40: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 41: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 45 and 46: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 47 and 48: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 49 and 50: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 51 and 52: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 53 and 54: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 55 and 56: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 57 and 58: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 59 and 60: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 61 and 62: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 63 and 64: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 65 and 66: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 67 and 68: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 69 and 70: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 71 and 72: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 73 and 74: 01 Solutions 46060 5/6/10 2:43 PM P
- Page 75 and 76: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 77 and 78: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 79 and 80: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 81 and 82: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 83 and 84: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 85 and 86: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 87 and 88: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 89 and 90: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 91 and 92: 02 Solutions 46060 5/6/10 1:45 PM P
- Page 93 and 94:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 95 and 96:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 97 and 98:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 99 and 100:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 101 and 102:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 103 and 104:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 105 and 106:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 107 and 108:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 109 and 110:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 111 and 112:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 113 and 114:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 115 and 116:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 117 and 118:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 119 and 120:
03 Solutions 46060 5/7/10 8:45 AM P

- Page 121 and 122:
03 Solutions 46060 5/7/10 8:45 AM P