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# ch01-03 stress &amp; strain &amp; properties

## 01 Solutions 46060

01 Solutions 46060 5/6/10 2:43 PM Page 54 © 2010 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. •1–81. The tension member is fastened together using two bolts, one on each side of the member as shown. Each bolt has a diameter of 0.3 in. Determine the maximum load P that can be applied to the member if the allowable shear stress for the bolts is t allow = 12 ksi and the allowable average normal stress is s allow = 20 ksi. P 60 P a+©F y = 0; N - P sin 60° = 0 P = 1.1547 N (1) b+ ©F x = 0; V - P cos 60° = 0 P = 2 V (2) Assume failure due to shear: V t allow = 12 = (2) p 4 (0.3)2 V = 1.696 kip From Eq. (2), P = 3.39 kip Assume failure due to normal force: N s allow = 20 = (2) p 4 (0.3)2 N = 2.827 kip From Eq. (1), P = 3.26 kip (controls) Ans. 54

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