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Complex Analysis - Maths KU

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186 Chapter 4 Elementary Functions<br />

Observe that each of the values found in parts (a)–(c) could have also<br />

been found by setting n = 0 in the expressions for ln z from Example 3.<br />

Note: ☞ It isimportant to note that the identitiesfor the complex logarithm in<br />

Theorem 4.3 are not necessarily satisfied by the principal value of the complex<br />

logarithm. For example, it is not true that Ln(z1z2) =Ln z1 +Lnz2 for<br />

all complex numbers z1 and z2 (although it may be true for some complex<br />

numbers). See Problem 55 in Exercises 4.1.<br />

Ln z as an Inverse Function Because Ln z is one of the valuesof<br />

the complex logarithm ln z, it followsfrom (10) that:<br />

e Lnz = z for all z �= 0. (16)<br />

This suggests that the logarithmic function Ln z isan inverse function of<br />

exponential function e z . Because the complex exponential function is not<br />

one-to-one on itsdomain, thisstatement isnot completely accurate. Rather,<br />

the relationship between these functions is similar to the relationship between<br />

the squaring function z 2 and the principal square root function z 1/2 =<br />

� |z|e iArg(z)/2 defined by (7) in Section 2.4. The exponential function must<br />

first be restricted to a domain on which it is one-to-one in order to have a<br />

well-defined inverse function. In Problem 52 in Exercises 4.1, you will be<br />

asked to show that e z isa one-to-one function on the fundamental region<br />

−∞

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