14.12.2012 Views

Complex Analysis - Maths KU

Complex Analysis - Maths KU

Complex Analysis - Maths KU

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

370 Chapter 6 Series and Residues<br />

EXERCISES 6.6 Answers to selected odd-numbered problems begin on page ANS-20.<br />

6.6.1 Evaluation of Real Trigonometric Integrals<br />

In Problems<br />

�<br />

1–12, evaluate the given trigonometric integral.<br />

2π<br />

� 2π<br />

1<br />

1<br />

1.<br />

dθ 2.<br />

0 1+0.5 sin θ 0 10 − 6 cos θ dθ<br />

� 2π<br />

� 2π<br />

cos θ<br />

1<br />

3.<br />

dθ 4.<br />

3 + sin θ 1+3cos2θ dθ<br />

5.<br />

7.<br />

9.<br />

11.<br />

0<br />

� π<br />

0<br />

� 2π<br />

0<br />

� 2π<br />

0<br />

� 2π<br />

0<br />

1<br />

dθ [Hint: Let t =2π− θ.] 6.<br />

2 − cos θ<br />

sin 2 θ<br />

dθ 8.<br />

5 + 4 cos θ<br />

cos 2θ<br />

dθ 10.<br />

5 − 4 cos θ<br />

cos 2 θ<br />

dθ 12.<br />

2 + sin θ<br />

0<br />

� π<br />

0<br />

� 2π<br />

0<br />

� 2π<br />

0<br />

� 2π<br />

0<br />

1<br />

1 + sin 2 θ dθ<br />

cos 2 θ<br />

3 − sin θ dθ<br />

1<br />

cos θ + 2 sin θ +3 dθ<br />

cos 3θ<br />

5 − 4 cos θ dθ<br />

In Problems 13 and 14, establish the given general result. Use Problem 13 to verify<br />

the answer in Example 1. Use Problem 14 to verify the answer to Problem 7.<br />

� π<br />

dθ<br />

aπ<br />

13.<br />

dθ =<br />

0 (a + cos θ) 2<br />

( √ a2 , a>1<br />

− 1) 3<br />

� 2π<br />

sin<br />

14.<br />

2 θ 2π<br />

dθ =<br />

a + b cos θ b2 � √<br />

a − a2 − b2 � , a>b>0<br />

0<br />

6.6.2Evaluation of Real Improper Integrals<br />

In Problems 15–26, evaluate the Cauchy principal value of the given improper<br />

integral. � ∞<br />

1<br />

15.<br />

−∞ x2 dx<br />

− 2x +2<br />

16.<br />

� ∞<br />

1<br />

−∞ x2 − 6x +25 dx<br />

� ∞<br />

1<br />

17.<br />

−∞ (x2 dx<br />

+4) 2 18.<br />

� ∞<br />

x<br />

−∞<br />

2<br />

(x2 � ∞<br />

1<br />

19.<br />

−∞ (x<br />

dx<br />

+1) 2 2 dx<br />

+1) 3 20.<br />

� ∞<br />

x<br />

−∞ (x2 � ∞<br />

2x<br />

21.<br />

−∞<br />

dx<br />

+4) 3 2 − 1<br />

x4 +5x2 dx<br />

+4<br />

22.<br />

� ∞<br />

1<br />

−∞ (x2 +1) 2 (x2 +9) dx<br />

� ∞<br />

x<br />

23.<br />

0<br />

2 +1<br />

x4 dx<br />

+1<br />

24.<br />

� ∞<br />

1<br />

0 x6 +1 dx<br />

� ∞<br />

x<br />

25.<br />

2<br />

x6 dx<br />

+1<br />

26.<br />

� ∞<br />

x 2<br />

(x2 +2x + 2)(x2 dx<br />

+1) 2<br />

0<br />

In Problems 27–38, evaluate the Cauchy principal value of the given improper<br />

integral. � ∞<br />

cos x<br />

27.<br />

−∞ x2 dx<br />

+1<br />

28.<br />

� ∞<br />

cos 2x<br />

−∞ x2 +1 dx<br />

� ∞<br />

x sin x<br />

29.<br />

x2 dx<br />

+1<br />

30.<br />

� ∞<br />

cos x<br />

(x2 dx<br />

+4) 2<br />

−∞<br />

−∞<br />

0

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!