Reasonin Rakesh Yadav

131.(d)
132.(b)
3km.
2km.
3km.
3km.
1km.
Rohan is 1 km. away from the
starting point.
C
13km.
B
90º
12km.
A
Initial
Point
Use Pythagorus Theorem in
right - angle - triangle ABC
CB AC ² – AB ²
CB 13 ² – 12²
CB 169 – 144
CB 25
= 5 km.
CB is required distance
133.(a)
A
134.(b)
50km.
40km.
B
C
D
E
10km.
AC 40² 30²
Starting
Point
= 1600 900
30km.
2500 = 50 km.
A
F
80m.
E B
60m. 30m.
20m. 20m.
D
AF (AE)²+ EF ²
60 ² 80 ²
30m.
C
135.(d)
3600 6400
= 10000 = 100m
8km. 12km. E
C
4km.
3km. 3km.
B
AD
136.(b)
8m.
8km.
AE²+ED²
3 ² 4 ²
A
Starting
Point
9 16 25 = 5 km
4m.
Starting
2m.
2m.
Point
10m. 4m. 6m.
Rakesh Yadav Sir
D
8m.
20m.
Ganesh is 10m. far from the
starting point
137.(b)
Last point 25km. 5km.
of B
5km.
Last point
of A
138.(d)
139.(a)
20km.
5km. B A 5km.
Distance will be 30 km. between
them.
10km.
10km.
10km.
Office
Pran Khan
20km.
Answer = 20 km.
5km.
15km.
10km.
7km.
Starting
Point
8km.
5km. Last
Point
Man is 8km. away from starting point.
140.(b)
4km.
2km.
2km.
2km.
5km.
3km.
2km.
Sumitra is 2km. away from
starting point
141.(d)
15m.
25m.
15m.
Starting
Point
20m.
25m.
Ramesh is 45m. for from the
starting point.
142.(c)
Starting
Point
A 20 m. B
D
143.(b)
Last
Point
E
F
10m.
5m. 10m.
35m.
EA² = (EF)² + (AF)²
EA² = 100 100
EA = 10 2 m.
Answer : 10 2 m.
Uncle’s
house
144.(b)
www.yoursmahboob.wordpress.com
200 m.
John’s
house
100 m.
Uncle’s
office
10m.
C
Kabir’s
house
100 m.
100 m.
100m.
Kabir’s
office
John's Uncle's house is 300
metre far from Kabir's office.
B
4 km.
A
C
6 km.
6 km.
D
E
4 km.
F
4 km.
268 Rakesh Yadav Readers Publication Pvt. Ltd