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Calculus- Early Transcendentals, 2021a

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382 Differential Equations<br />

Solution. We write the equation in standard form: y ′ + 3y/t = 0. Then<br />

∫<br />

P(t)= − 3 dt = −3lnt<br />

t<br />

and<br />

y = Ae −3lnt = At −3 .<br />

Substituting to find A: 2= A(1) −3 = A, so the solution is y = 2t −3 .<br />

♣<br />

Exercises for 10.2<br />

Find the general solution of each equation in the following exercises.<br />

Exercise 10.2.1 y ′ + 5y = 0<br />

Exercise 10.2.3 y ′ +<br />

y<br />

1 +t 2 = 0<br />

Exercise 10.2.2 y ′ − 2y = 0<br />

Exercise 10.2.4 y ′ +t 2 y = 0<br />

In the following exercises, solve the initial value problem.<br />

Exercise 10.2.5 y ′ + y = 0,y(0)=4<br />

Exercise 10.2.6 y ′ − 3y = 0, y(1)=−2<br />

Exercise 10.2.7 y ′ + ysint = 0, y(π)=1<br />

Exercise 10.2.8 y ′ + ye t = 0, y(0)=e<br />

√<br />

Exercise 10.2.9 y ′ + y 1 +t 4 = 0,y(0)=0<br />

Exercise 10.2.10 y ′ + ycos(e t )=0, y(0)=0<br />

Exercise 10.2.11 ty ′ − 2y = 0,y(1)=4<br />

Exercise 10.2.12 t 2 y ′ + y = 0, y(1)=−2,t> 0<br />

Exercise 10.2.13 t 3 y ′ = 2y, y(1)=1,t> 0<br />

Exercise 10.2.14 t 3 y ′ = 2y, y(1)=0,t> 0<br />

Exercise 10.2.15 A function y(t) is a solution of y ′ + ky = 0. Suppose that y(0)=100 and y(2)=4. Find<br />

k and find y(t).<br />

Exercise 10.2.16 A function y(t) isasolutionofy ′ + t k y = 0. Suppose that y(0) =1 and y(1) =e −13 .<br />

Find k and find y(t).<br />

Exercise 10.2.17 A bacterial culture grows at a rate proportional to its population. If the population is<br />

one million at t = 0 and 1.5 million at t = 1 hour, find the population as a function of time.<br />

Exercise 10.2.18 A radioactive element decays with a half-life of 6 years. If a mass of the element weighs<br />

ten pounds at t = 0, find the amount of the element at time t.

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