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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 102. See Problem 2.101 for the figure and the analysis leading to the linear algebraic Equations (1), (2), and (3) below. T T AB AC ⎛5⎞⎛25⎞ = ⎜ T ⎝ ⎟⎜ ⎟ 3⎠⎝43⎠ AD ⎛17⎞⎛18⎞ = ⎜ T ⎝ ⎟⎜ ⎟ 8 ⎠⎝43⎠ AD (1) (2) From Equation (1) From Equation (3) 255 0.8TAB + TAD − W = 0 (3) 172 T AB ⎛5⎞⎛25⎞ = ⎜ ⎝ ⎟⎜ ⎟ 3⎠⎝43⎠ ( 4.3 kN) or T AB = 4.1667 kN 255 0.8( 4.1667 kN) + ( 4.3 kN) − W = 0 172 ∴ W = 9.71 kN ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 103. uuur AB =− ( 4.20 m) i −( 5.60 m) 2 2 ( ) ( ) ( 2.40 m) ( 5.60 m) ( 4.20 m) AB = − 4.20 m + − 5.60 m = 7.00 m uuur AC = i − j + k ( ) ( ) ( ) ( 5.60 m) − ( 3.30 m) j 2 2 2 AC = 2.40 m + − 5.60 m + 4.20 m = 7.40 m uuur AD =− j k ( ) ( ) 2 2 AD = − 5.60 m + − 3.30 m = 6.50 m uuur AB TAB TAB = TABλAB = TAB = ( −4.20i − 5.60j) AB 7.00 m T ⎛ 3 4 ⎞ AB = ⎜− − TAB ⎝ ⎟ 5 i 5 j ⎠ uuur AC TAC TAC = TACλAC = T AC = 2.40i − 5.60j+ 4.20k AC 7.40 m ( ) T ⎛12 28 21 ⎞ AC = ⎜ − + TAC ⎝ ⎟ 37 i 37 j 37 k ⎠ uuur AD TAD TAD = TADλAD = TAD = −5.60j − 3.30k AD 6.50 m T ⎛ 56 33 ⎞ AD = ⎜− − T ⎝ ⎟ 65 j 65 k ⎠ P = P j AD For equilibrium at point A: Σ F = 0 TAB + TAC + TAD + P = ( ) 0 i component: 3 12 − TAB + TAC = 0 5 37 or T AB 20 = TAC (1) 37 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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