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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 10. Using the Law of Sines: 60 N 80 N sinα = sin10° or α = 7.4832° β = 180° − ( 10° + 7.4832° ) = 162.517° Then: R 80 N = sin162.517° sin10° or R = 138.405 N (a) α = 7.48°! (b) R = 138.4 N ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 11. Using the triangle rule and the Law of Sines Have: β = 180° − ( 35° + 25° ) = 120° Then: P R 80 lb = = sin 35° sin120° sin 25° or (a) (b) P = 108.6 lb ! R = 163.9 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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