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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System j component: 2 12 6 FBA − TAC − TAD − 1.6W = 0 (2) 3 29 11 1 16 7 k component: FBA − TAC + TAD = 0 (3) 3 29 11 2 Setting ( )( ) W = 20 kg 9.81 m/s = 196.2 N And Solving Equations (1), (2), and (3) simultaneously: F = 1742 N ⊳ BA T = 1517 N ⊳ AC T = 403 N ⊳ AD Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 117. Σ F x = 0: ( )( ) ( )( ) ( )( ) − T sin30° sin 50° + T sin30° cos 40° + T sin 30° cos60° = 0 AD BD CD Dividing through by sin 30° and evaluating: − 0.76604T + 0.76604T + 0.5T = 0 (1) AD BD CD Σ F y = 0: ( ) ( ) ( ) − T cos30° − T cos30° − T cos30° + 62 lb = 0 AD BD CD or TAD + TBD + T CD = 71.591 lb (2) Σ F z = 0: Solving Equations (1), (2), and (3) simultaneously: T sin 30° cos50° + T sin 30° sin 40° − T sin 30° sin 60° = 0 AD BD CD or 0.64279T + 0.64279T − 0.86603T = 0 (3) AD BD CD T = 30.5 lb ! AD T = 10.59 lb ! BD T = 30.5 lb ! CD Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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