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8 months ago

Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 12. Using the triangle rule and the Law of Sines (a) Have: 80 lb 70 lb sinα = sin 35° sinα = 0.65552 α = 40.959° or α = 41.0°! (b) β = 180 − ( 35° + 40.959° ) = 104.041° Then: R 70 lb = sin104.041° sin 35° or R = 118.4 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 13. We observe that force P is minimum when α = 90 ° . Then: (a) P = ( 80 lb) sin 35° And: (b) R = ( 80 lb) cos35° or P = 45.9 lb ! or R = 65.5 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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