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# Sol Cap 02 - Edicion 8

## COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Setting the k coefficient to zero gives: Q − TABz = And using the above result for T AB we have 680 N Q = TABz = z y 0 Then, from the specifications of the problem, y = 300 mm = 0.3 m and z 2 2 ∴ z = ( ) 2 = 0.84 m − 0.3 m 0.866 m (a) or and 680 N T AB = = 2266.7 N 0.30 (b) Q = 2266.7( 0.866) = 1963.2 N or T = 2.27 kN ! AB Q = 1.963 kN ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 128. From the analysis of Problem 2.127, particularly the results: y 2 2 2 + z = 0.84 m T AB Q = = 680 N y 680 N z y With y = 550 mm = 0.55 m, we obtain: and 2 2 ( ) 2 z = 0.84 m − 0.55 m ∴ z = 0.73314 m (a) or and 680 N T AB = = 1236.36 N 0.55 T = 1.236 kN ! AB (b) Q = 1236.36( 0.73314) N = 906 N or Q = 0.906 kN ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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