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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 14. For T BC to be a minimum, R and T BC must be perpendicular. Thus T BC = ( 70 N) sin 4° = 4.8829 N And R = ( 70 N) cos 4° = 69.829 N (a) (b) T = 4.88 N 6.00° ! BC R = 69.8 N ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 15. Using the force triangle and the Laws of Cosines and Sines We have: γ = 180° − ( 15° + 30° ) = 135° 2 2 2 Then: ( ) ( ) ( )( ) R = 15 lb + 25 lb − 2 15 lb 25 lb cos135° or 2 = 1380.33 lb R = 37.153 lb and 25 lb 37.153 lb sin β = sin135° ⎛ 25 lb ⎞ sin β = ⎜ sin135° 37.153 lb ⎟ ⎝ ⎠ = 0.47581 β = 28.412° Then: α + β + 75° = 180° α = 76.588° R = 37.2 lb 76.6° ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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