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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 22. F = 5kips cos40° 5 kips: ( ) x or F x = 3.83 kips ⊳ ( ) F = 5kips sin40° y or F = 3.21 kips ⊳ y F =− 7kips cos70° 7 kips: ( ) x or F =−2.39 kips ⊳ x ( ) F = 7 kips sin 70° y or F = 6.58 kips ⊳ y F =− 9kips cos20° 9 kips: ( ) x ( ) F = 9 kips sin 20° y or F =−8.46 kips ⊳ x or F = 3.08 kips ⊳ y Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 23. Determine the following distances: 680 N Force: d d d OA OB OC F x ( ) ( ) 2 2 = − 160 mm + 300 mm = 340 mm ( ) ( ) 2 2 = 600 mm + 250 mm = 650 mm ( ) ( ) 2 2 = 600 mm + − 110 mm = 610 mm ( −160 mm) = 680 N 340 mm 390 N Force: F y = F x = F y = ( 300 mm) 680 N 340 mm ( 600 mm) 390 N 650 mm ( 250 mm) 390 N 650 mm F =− 320 N ! x F = 600 N ! y F = 360 N ! x 610 N Force: F x = ( 600 mm) 610 N 610 mm F = 150 N ! y F y ( −110 mm) = 610 N 610 mm F = 600 N ! x F =− 110 N ! y Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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