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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 64. At Collar A ... Have F = k( L′ − L ) For stretched length For unstretched length s AB AB ( 12 in. ) ( 16 in. ) L ′ = + AB L′ AB = 20 in. L = 12 2 in. AB 2 2 Then F s = ( − ) 4 lb/in. 20 12 2 in. F s = 12.1177 lb For the collar ... Σ F y = 0 4 − W + ( 12.1177 lb ) = 0 5 W = 9.69 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 65. At Collar A ... Σ F y = 0: h − 9lb+ F 0 2 2 s = 12 + h or hF = 9 144 + h s Now F = k( L′ − L ) Where the stretched length 2 s AB AB ( ) 2 2 12 in. L′ = + h AB L AB = 12 2 in. Then hF = 9 144 + h s Becomes ⎡ ⎢ ( ) 2 h 3 lb/in. 144 + − 12 2 ⎤ = 9 144 + ⎣ h ⎥⎦ h h − 3 144 + h = 12 2 h or ( ) 2 2 2 Solving Numerically ... h = 16.81 in. ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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