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Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 68. Free-Body Diagram of Pulley (a) (b) (c) (d) 2 ( )( ) Σ F = 0: 2T − 280 kg 9.81 m/s = 0 y T = 1 ( 2746.8 N ) 2 2 ( )( ) Σ F = 0: 2T − 280 kg 9.81 m/s = 0 y T = 1 ( 2746.8 N ) 2 2 ( )( ) Σ F = 0: 3T − 280 kg 9.81 m/s = 0 y 1 T = ( 2746.8 N ) 3 2 ( )( ) Σ F = 0: 3T − 280 kg 9.81 m/s = 0 y 1 T = ( 2746.8 N ) 3 T = 1373 N ⊳ T = 1373 N ⊳ T = 916 N ⊳ T = 916 N ⊳ (e) 2 ( )( ) Σ F = 0: 4T − 280 kg 9.81 m/s = 0 y T = 1 ( 2746.8 N ) 4 T = 687 N ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 69. Free-Body Diagram of Pulley and Crate (b) 2 ( )( ) Σ F = 0: 3T − 280 kg 9.81 m/s = 0 y 1 T = ( 2746.8 N ) 3 T = 916 N ⊳ (d) 2 ( )( ) Σ F = 0: 4T − 280 kg 9.81 m/s = 0 y T = 1 ( 2746.8 N ) 4 T = 687 N ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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