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# Sol Cap 02 - Edicion 8

## COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 70. Free-Body Diagram: Pulley C (a) F T ( ) ( ) Σ = 0: cos30° − cos50° − 800 N cos50° = 0 x ACB Hence T ACB = 2303.5 N (b) ( ) ( ) Σ F = 0: T sin 30°+ sin 50° + 800 N sin 50°− Q = 0 y ACB TACB = 2.30 kN ⊳ ( )( ) ( ) 2303.5 N sin 30°+ sin 50° + 800 N sin 50°− Q = 0 or Q = 3529.2 N Q = 3.53 kN ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 71. Free-Body Diagram: Pulley C ( ) Σ F = 0: T cos30° − cos50° − Pcos50° = 0 x ACB or P = 0.34730T ACB (1) ( ) Σ F = 0: T sin30° + sin50° + Psin50° − 2000 N = 0 y ACB or 1.26604T + 0.76604P = 2000 N (2) (a) Substitute Equation (1) into Equation (2): ACB ( ) 1.26604T + 0.76604 0.34730T = 2000 N ACB ACB Hence: T ACB = 1305.41 N TACB = 1305 N ⊳ (b) Using (1) P = 0.34730( 1305.41 N) = 453.37 N P = 453 N ⊳ Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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