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8 months ago

Sol Cap 02 - Edicion 8

COSMOS: Complete Online

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 82. 2 2 2 x y z F = F + F + F ( 450 N) ( 600 N) ( 1800 N) 2 2 2 F = + + − Fx 450 N cosθ x = = F 1950 N Fy 600 N cosθ y = = F 1950 N F = 1950 N ! θ = 76.7°! x θ = 72.1°! y Fz cosθ z = = F −1800 N 1950 N θ = 157.4°! z Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS: Complete Online Solutions Manual Organization System Chapter 2, Solution 83. 2 2 2 x y z (a) We have ( θ ) ( θ ) ( θ ) cos + cos + cos = 1 ( cosθy) = 1 − ( cosθx) − ( cosθz) 2 2 2 Since F y < 0 we must have cosθ y < 0 2 2 Thus cosθ =− 1 − ( cos 43.2° ) − cos( 83.8° ) y cosθ y =− 0.67597 θ = 132.5°! y (b) Then: F = F y cosθ y F −50 lb = − 0.67597 73.968 lb F = And F = Fcosθ x x ( ) F = 73.968 lb cos 43.2° x F = 53.9 lb ! x F = Fcosθ z z ( ) F = 73.968 lb cos83.8° z F = 7.99 lb ! z F = 74.0 lb ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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