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Eduardo Kausel-Fundamental solutions in elastodynamics_ a compendium-Cambridge University Press (2006)

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5.3 Half-plane, SV-P source and receiver at surface (Lamb’s problem) 71<br />

g yy (˜r 1 , ˜r 2 ,ω) =−<br />

i [<br />

]<br />

H (2)<br />

0<br />

( ˜ 1 ) + H (2)<br />

0<br />

( ˜ 2 )<br />

4µ x<br />

⎤<br />

⎡<br />

u yy (x, z, t) = 1 ⎣ H (t − ˜t 1)<br />

√<br />

2πµ x<br />

t 2 − ˜t<br />

1<br />

2<br />

+ H (t − ˜t 2)<br />

√<br />

t 2 − ˜t 2<br />

2<br />

(5.10)<br />

⎦ (5.11)<br />

5.3 Half-plane, SV-P source and receiver at surface (Lamb’s problem) 2<br />

An impulsive <strong>in</strong>-plane l<strong>in</strong>e source P is applied on the surface of a lower half-space, and<br />

displacements are observed there. For an upper half-space z > 0, reverse the sign of the<br />

coupl<strong>in</strong>g terms. The source has dimensions [F][T]/[L] = [impulse]/[length <strong>in</strong> y direction].<br />

τ = tβ<br />

|x| , τ R = β , a = β C R α = 1 − 2ν , δ = Dirac delta (5.12)<br />

2(1 − ν)<br />

⎧<br />

0 τ1<br />

⎧<br />

0 τ1<br />

⎧<br />

2τ (2τ 2 − 1) √ τ 2 − a 2√ 1 − τ 2<br />

u xz =<br />

Pβ ⎪⎨<br />

a ≤ τ ≤ 1<br />

(2τ 2 − 1) 4 + 16τ 4 (τ 2 − a 2 )(1 − τ 2 )<br />

πµx π(2τR ⎪⎩<br />

2 − 1)3<br />

4 ( 1 − 4τR 2 + 8τ R 6(1 − a2 ) )δ(τ − τ R) else<br />

u zx =−u xz<br />

u yy =<br />

Pβ 1<br />

√ H (τ − 1)<br />

πµ|x| τ 2<br />

− 1 (5.13e)<br />

(5.13a)<br />

(5.13b)<br />

(5.13c)<br />

(5.13d)<br />

Note: Observe that x <strong>in</strong> u xz has no absolute sign. Also,<br />

(β/x)δ(τ − τ R ) = sgn x δ(t − t R ).<br />

2 Er<strong>in</strong>gen, A. C. and Suhubi, S. S., 1975, Elastodynamics, Academic <strong>Press</strong>, Vol. II, p. 617. Note: eq. 7.16.7 <strong>in</strong> that<br />

book has an error that affects the coefficient of the Dirac delta term <strong>in</strong> u xz. This has been corrected here.

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