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1.2 Syarat Batas di batas dua bahan dielektriknˆDivergensi Gauss:rnr( B•1−rB ) = 0 → B21⊥∫∇= B2⊥r• FdV=∫rF• nˆ dS2 1rn• (rD1−rD ) = 0 →εE211⊥= ε E22⊥nˆTeorema Stokes:rnˆx ( E2−rE1∫) = 0 →r∇xFE• ndS =1 //ˆ=E∫2 //rFr• dl2 1rnˆx ( H2−Hˆ1)=0→B1 //=B2 //5

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