陽電子砲でシトを攻撃できるか、を物理的に計算する
陽電子砲でシトを攻撃できるか、を物理的に計算する
陽電子砲でシトを攻撃できるか、を物理的に計算する
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Un Petit Puits No.2 (2007 12 )<br />
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1995 12 <br />
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1: (C)GAINAX<br />
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1 1 enoto@amalthea.phys.s.u-tokyo.ac.jp<br />
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-<br />
eV α <br />
Un Petit Puit <br />
http://ceres.phys.s.u-tokyo.ac.jp/˜enoto/editorial/pdf/<br />
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m e +c 2 = 511 keV <br />
m e −c 2 = 511 keV 511 keV <br />
2 <br />
e + + e − → γ + γ (1)<br />
511 keV <br />
2 511 keV <br />
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511 keV 4 <br />
2: 511 keV (J.Knodlseder, et al., A&A, 2006)<br />
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511 keV <br />
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Positron<br />
emission tomography PET <br />
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FONC <br />
511 keV PET <br />
2 <br />
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4 <br />
2
l = 10 m <br />
d = 10 cm <br />
V = πd 2 × l = 3.14 × (10 cm) 2 × 10 m = 3.14 × 10 5 cm 3 (2)<br />
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H <br />
n = 1 g/cm 3 nV g <br />
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N A <br />
N(e + ) = nVN A = 1.89 × 10 29 (3)<br />
N(e + ) = 1.89 × 10 29 <br />
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(1) (2) <br />
(3) <br />
1. (Ionization) <br />
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2. (Bremssttrahlung) <br />
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3. (Pair Creation) <br />
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1 km () <br />
1 km 3 1 GeV (=10 9 eV) <br />
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3: / (Particle Data Group )<br />
(NIST )<br />
0.511MeV = 5.1×10 −4<br />
GeV 1 GeV <br />
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(3) <br />
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Needed Energy = N(e + ) × E e + = 1.89 × 10 29 × 1 GeV = 1.89 × 10 38 eV (4)<br />
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2015 <br />
10000 kWh 1 kWh = 2.25 × 10 25 eV <br />
eV 2.25 × 10 37 eV <br />
365 ×24 = 8740 <br />
Provided Energy = 2.57 × 10 33 eV (5)<br />
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(4) (5) 5 <br />
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(2) <br />
1 cm 1 m <br />
3 <br />
2 <br />
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5 <br />
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5 <br />
4
e + e − <br />
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4: Geant4 <br />
Geant4 <br />
Geant4<br />
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4() 1 km 10 m<br />
1 GeV <br />
4() <br />
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5
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