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MODUL-MATEMATIKA-EKONOMI-2

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Laboratorium Manajemen DasarJawab :Cara 1Pd = Ps P = 33 + (6)45 – Q = 33 + Q Pe = 39- Q - Q = 33 – 45- 2Q = - 12Qe = 6Ps = Qe . Pe − ∫ f(Q)dQ= 6 . 39 – ∫ [33 + Q] dQ= 234 – [33Q + 0,5Q 2 ] = 234 – [33(6) + 0,5(6) 2 ] – [33(0) + 0,5(0) 2 ]= 234 – 216 – 0= 18Analisis :Jadi produsen memperoleh keuntungan sebesar Rp 18 dikarenakanperusahaan dapat menjual barang dengan harga Rp 39 padahalsebenarnya ia bersedia menjual dengan harga yang lebih rendah dariharga keseimbangan pasar yang bernilai Rp 33.Grafik Surplus Produsen Soal 1Matematika Ekonomi 2 68 Litbang ATA 13/14

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