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Ivo Gostiša - ZAPS

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IZRAČUN - primer 2<br />

Inženirska metoda - ODMIKI MED OBJEKTI<br />

1. Izračun temperature v prostoru, kjer nastane požar<br />

q = 600 MJ/m 2 spec. pož. obremenitev<br />

A = 4 m x 10 m = 40 m 2<br />

okenska odprtina<br />

Av okno = h = 2 m x š = 3 m = 6 m 2<br />

požarno breme = 600 MJ/m2 x 40 m2 = 24000 MJ<br />

toplotna vrednost = 16 MJ/kg<br />

količina goriva = 24000 MJ : 16 MJ/kg = 1500 kg<br />

m’ = hitrost gorenja = 5,5*Av*(h) 1/2 = 46,7 kg/s<br />

trajanje gorenja: t b (min) = 1500 kg : 46,7 kg/s = 32,1 min<br />

T º = 20 ºC<br />

T e = 345*log(8* t b +1) + T º = 257,95<br />

T e = 851 ºC<br />

9-Dec-11 Načrtovanje požarne varnosti v stavbah 12

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