الذهبيه - فيزياء

. ᕩ Ύ맨 ᕩ맨 Ύo Ύ 冐 Α 맨 冐 ɖṦ൴ 䁀 Ṧo Ύ o 횠 맨 맨
C1.C2
120 × 30
Ceq
= = = 24μF
C1+C2
120 + 30
Qt
= Ceq
.ΔV = 24 × 20 = 480μC = Q1
= Q2
Ck 2 = C2.k
= 2 × 30 = 60μF
C1.Ck 2 120 × 60
Ceq
= = = 40μF
C1+Ck 2 120 + 60
Qt
= Q2
= Q1
= 480μC
Q 480
Q 480
ΔVt
= = = 12 ν , ΔV1
= = = 4 ν , ΔV
Ceq
40
C1
120
1
2 1
-6 2
-6
PE1=
C1
ΔV = ×120 ×10 × 4 = 9.6 ×10 J
2
2
1
2 1
-6 2
-6
PEk 2=
Ck 2 ΔV = × 60 ×10 × 8 = 192 ×10 J
2
2
k 2
=
Q
C
k 2
=
480
60
= 8 ν
՚ Ϡt 㤷 Ϡ 㤷 R R R R 㤷 R 맨ᕩ
6 v
Ṧ Ṧo 횠 맨 Ṧ똨맨맨൴R맨 ϘΑ 8μF ,C 12μF ,C 24μF 횠Ϝ Ύ똨 Ύ 冐 Α m o 맨 /
C1 2
2
R 맨ϘɖR맨 횠 Ύo Α ᕩ맨 Ύ 冐 맨 o ṦmṦ맨 . ṦΎ o 횠 맨 Ύ R맨 똨똨mΑ 똨 맨 Α R
맨 R맨 Βᕩ 冐 m 맨 RɖϮ맨 Ύ 冐 Α 맨 Βᕩ 冐 m 맨 RɖϮ맨 mΑ Α 맨 Ύ R맨 mΑ 맨맨 -1
맨 맨 Βᕩ 冐 m 맨 RɖϮ맨 Ύ 冐 Α 맨 Βᕩ 冐 m 맨 RɖϮ맨 mΑ Α 맨 Ύ R맨 mΑ 䁀 -2
1 Ceq
=C1+C2+C3
= 8 + 12 + 24 = 48μF
ΔVt
= ΔV1
= ΔV2
= ΔV3
= 6 ν
Q1= ΔV.C1
= 6 × 8 = 48μC
Q2= ΔV.C2
= 6 ×12 = ᕪ2μC
Q3= ΔV.C3
= 6 × 24 = 144μC
Q = ΔV.C = 6 × 48 = 288μC
3
3
2
C
Q
t
1 1 1
= +
Ceq
C1
C2
= 4μF
= ΔV
t
.Ceq
= 6 × 4 = 24μC
eq
+
1
C
3
= Q
1
=
1
8
= Q
2
+
1
12
= Q
3
+
1
24