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Eksempel<br />

EI 12 −6L m<br />

L 3 −6L −4L2 − ω2<br />

420<br />

156 −22L<br />

−22L −4L 2 v 2<br />

θ 2<br />

= 0 0<br />

ω 1 = 3,533<br />

ω 2 = 34,81<br />

1/2<br />

EI<br />

mL 3<br />

1/2<br />

EI<br />

mL 3<br />

102

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