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analisis de vigas estaticamente indeterminadas - Ing. Carlos ...

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Por suma <strong>de</strong> momentos en el nodo 1):<br />

400(<br />

4)<br />

2(<br />

4)<br />

<br />

M2 <br />

380(<br />

8)<br />

906.<br />

66 kg.<br />

m<br />

2<br />

<br />

3<br />

<br />

<br />

Verificación con fórmula:<br />

2<br />

17w<br />

L 17(<br />

400)<br />

( 8)<br />

M2 <br />

906.<br />

66<br />

480 480<br />

2<br />

kg.<br />

m<br />

Punto don<strong>de</strong> la fuerza cortante es cero.<br />

V x<br />

400 x x <br />

420 <br />

<br />

4<br />

<br />

2<br />

<br />

<br />

X = 2.898275 m<br />

La ecuación <strong>de</strong> momentos es:<br />

M x<br />

400 x<br />

420 x <br />

0 x 4<br />

24<br />

X = 2.898275 m<br />

M = 811.52 kg.m<br />

X = 4.00 m<br />

M = 613.34 kg.m<br />

Fin <strong>de</strong>l problema.<br />

3<br />

0<br />

400 kg/m<br />

420 380<br />

4.00 4.00<br />

420<br />

811.52<br />

613.34<br />

906.66<br />

Fuerza Cortante<br />

Creado y editado por: <strong>Ing</strong>eniero <strong>Carlos</strong> Remberto Zeledón Lanuza<br />

380<br />

Momento Flexionante<br />

906.66

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