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Solução
d ( x 2 + 3x 3 − 4x )
2 = 2x + 9x − 4
dx
Passos
d
dx
( x 2 + 3x 3 − 4x )
Aplicar a regra da soma/diferença: ( f ± g )′ = f ′ ± g′
=
d x + dx
( 2 ) d 3x −
d 4x
dx
( 3
) ( ) dx
Symbolab
( 2 )
d x = 2x
dx
d ( 3 3x )
2 = 9x
dx
d 4x = 4
dx
( )
2
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= 2x + 9x − 4
Grá co
2
Plotar o grá co: 2x + 9x − 4
Symbolab
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