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2007 4 5 c○ <br />
<br />
1 1<br />
1.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1<br />
1.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 6<br />
1.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7<br />
1.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 11<br />
1.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13<br />
1.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 16<br />
1.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17<br />
2 1 22<br />
2.1 1 . . . . . . . . . . . . . . . . . . . . . . . 22<br />
2.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25<br />
2.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31<br />
2.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . 34<br />
3 1 40<br />
3.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 40<br />
3.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 42<br />
3.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 44<br />
3.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 48<br />
3.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 49<br />
3.6 . . . . . . . . . . . . . . . . . . 52<br />
4 57<br />
4.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 57<br />
4.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 62<br />
4.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64<br />
4.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 68<br />
5 74<br />
5.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 74<br />
5.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 75<br />
5.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 77<br />
5.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 81<br />
5.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 85<br />
5.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 88<br />
5.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 93<br />
5.8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 99<br />
5.9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 107<br />
5.10 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 111
ii<br />
6 116<br />
6.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 116<br />
6.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 116<br />
6.3 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 120<br />
6.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 121<br />
6.5 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 125<br />
6.6 2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 129<br />
6.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 131<br />
7 133<br />
7.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 133<br />
7.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 135<br />
7.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 141<br />
8 WKB () 148<br />
8.1 WKB . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 148<br />
8.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 150<br />
8.3 . . . . . . . . . . . . . . . . . . . . . . . . . 153<br />
8.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 156<br />
8.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 157<br />
9 160<br />
9.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 160<br />
9.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 161<br />
9.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 165<br />
9.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 168<br />
9.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 169<br />
9.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 170<br />
9.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 172<br />
10 175<br />
10.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 175<br />
10.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 178<br />
10.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 183<br />
10.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 187<br />
10.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 189<br />
10.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 195<br />
10.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 199<br />
10.8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 207<br />
11 209<br />
11.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 209<br />
11.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 210<br />
11.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 211
iii<br />
11.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 214<br />
11.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 215<br />
11.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 216<br />
11.7 , . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 217<br />
12 221<br />
12.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 221<br />
12.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 222<br />
12.3 : 0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 224<br />
12.4 : 0 . . . . . . . . . . . . . . . . . . . . . . . . . . . . 227<br />
13 229<br />
13.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 229<br />
13.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 232<br />
14 237<br />
14.1 ( Levi–Civita ) . . . . . . . . . . . . . . . . . . . . . . . . . . . 237<br />
14.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 238<br />
14.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 239<br />
14.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 241<br />
14.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 246<br />
15 248<br />
15.1 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 248<br />
15.2 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 250<br />
15.3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 255<br />
15.4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 259<br />
15.5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 263<br />
15.6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 265<br />
15.7 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 274<br />
15.8 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 277<br />
15.9 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 280<br />
284<br />
<br />
<br />
()<br />
J. J. , ()<br />
<br />
, <br />
<br />
, <br />
1, 2, 3 ()<br />
1, 2 ()<br />
()<br />
I, II ()
1 1<br />
1 <br />
1.1 <br />
m¨r = F 2 <br />
, , <br />
, <br />
, , 1 <br />
r = (x, y, z) , r <br />
, 3 x, y, z f(x, y, z) f(r) <br />
✓ 1<br />
✏<br />
= h/2π ( h ) p , <br />
ˆp = − i∇ <br />
ˆp x = − i ∂<br />
∂x , ˆp y = − i ∂ ∂y , ˆp z = − i ∂ ∂z<br />
, ˆ , <br />
<br />
✒<br />
2 <br />
<br />
ˆp x xf(r) = −i ∂<br />
(<br />
∂x xf(r) = −i f(r) + x ∂f(r) )<br />
, x ˆp x f(r) = −ix ∂f(r)<br />
∂x<br />
∂x<br />
( )<br />
x ˆp x − ˆp x x f(r) = if(r)<br />
✑<br />
f(r) , f(r) , <br />
x ˆp x − ˆp x x = i<br />
, 2 <br />
Â, ˆB [ Â , ˆB ] = Â ˆB − ˆBÂ [ Â , ˆB ] <br />
[ x , ˆp x ] = i x 1 = x, x 2 = y, x 3 = z <br />
[ x i , ˆp j ] = i δ ij , [ x i , x j ] = 0 , [ ˆp i , ˆp j ] = 0 (1.1)<br />
<br />
✓ 2<br />
✏<br />
V (r) m , <br />
i ∂ ψ(r, t) = Ĥψ(r, t) ,<br />
∂t Ĥ<br />
= ˆp2<br />
2<br />
+ V (r) = −<br />
2m 2m ∇2 + V (r) (1.2)<br />
ψ(r, t) V (r) t <br />
, r = (x, y, z) d 3 r = dx dy dz <br />
|ψ(r, t)| 2 d 3 r<br />
(1.2) <br />
✒<br />
✑
1 2<br />
H , <br />
ψ(r, t) (1.2) , , Ĥψ(r, t) , (1.2)<br />
ψ(r, t) = 0 , ψ(r, t) <br />
, <br />
, <br />
ψ(r, t) , ψ(r, t) <br />
, <br />
(1.2) ψ 1 () , C , ψ(r, t) (1.2) ,<br />
C ψ(r, t) (1.2) , ψ(r, t) C ψ(r, t) <br />
, ψ(r, t) C ψ(r, t) , <br />
<br />
, ψ 1 (r, t), ψ 2 (r, t), · · · (1.2) , <br />
ψ(r, t) = ∑ i<br />
C i ψ i (r, t) ,<br />
C i = <br />
(1.2) <br />
ψ(r, t) = C 1 ψ 1 (r, t) + C 2 ψ 2 (r, t)<br />
, <br />
|ψ| 2 = |C 1 ψ 1 | 2 + |C 2 ψ 2 | 2 + 2Re (C ∗ 1 C 2 ψ ∗ 1ψ 2 )<br />
, |C 1 ψ 1 | 2 + |C 2 ψ 2 | 2 3 C 1 ψ 1 C 2 ψ 2 <br />
, <br />
<br />
2 , <br />
∫<br />
P (t) = d 3 r |ψ(r, t)| 2 (1.3)<br />
<br />
2 <br />
∂ψ(r, t)<br />
∂t<br />
V , <br />
∂ψ ∗ (r, t)<br />
∂t<br />
=<br />
(<br />
−<br />
<br />
2im ∇2 + 1 )<br />
i V (r) ψ(r, t)<br />
=<br />
( <br />
2im ∇2 − 1<br />
i V (r) )<br />
ψ ∗ (r, t)<br />
, ρ(r, t) = |ψ(r, t)| 2 <br />
<br />
∂ρ(r, t)<br />
∂t<br />
= ∂ψ∗ ∂ψ<br />
ψ + ψ∗<br />
∂t ∂t = (<br />
)<br />
ψ(r, t)∇ 2 ψ ∗ (r, t) − ψ ∗ (r, t) ∇ 2 ψ(r, t)<br />
2im<br />
∇·(ψ∇ψ ∗ ) = (∇ψ)·∇ψ ∗ + ψ∇ 2 ψ ∗<br />
<br />
∂ρ(r, t)<br />
∂t<br />
= ∇·(<br />
)<br />
ψ(r, t)∇ψ ∗ (r, t) − ψ ∗ (r, t) ∇ψ(r, t)<br />
2im
1 3<br />
<br />
<br />
j(r, t) =<br />
(<br />
)<br />
ψ ∗ (r, t)∇ψ(r, t) − ψ(r, t) ∇ψ ∗ (r, t) = (<br />
)<br />
2im<br />
m Im ψ ∗ (r, t)∇ψ(r, t)<br />
∂ρ(r, t)<br />
∂t<br />
(1.4)<br />
+ ∇·j(r, t) = 0 (1.5)<br />
V <br />
∫<br />
∫<br />
∫<br />
d<br />
d 3 r ρ(r, t) = − d 3 r ∇·j(r, t) = − dS n·j(r, t)<br />
dt<br />
V<br />
V<br />
S V , n S V S <br />
, S ψ(r, t) 0 0 , <br />
∫<br />
d<br />
d 3 r ρ(r, t) = dP<br />
dt<br />
dt = 0<br />
P <br />
P ψ(r, t)/ √ P (1.2) ψ(r, t) <br />
∫<br />
d 3 r |ψ(r, t)| 2 = 1 (1.6)<br />
S<br />
|ψ(r, t)| 2 d 3 r (1.6) <br />
(1.5) , ρ , j <br />
(1.5) , ρ = |ψ| 2 , (1.4) <br />
j () <br />
1.1<br />
V (r) <br />
dP<br />
dt = 2 ∫<br />
d 3 r |ψ(r, t)| 2 Im V (r)<br />
<br />
V <br />
✓ 3<br />
✏<br />
A(r, p) Â = A(r, ˆp) ψ(r, t) , <br />
, 〈A ˆ 〉 <br />
∫<br />
〈A ˆ 〉 = d 3 r ψ ∗ (r, t) A(r, −i∇) ψ(r, t)<br />
, ψ(r, t) , ,<br />
, <br />
✒<br />
 ,  ψ(r, t) <br />
, <br />
∫<br />
〈A ˆ 〉 ̸= d 3 r A(r, −i∇) ψ ∗ (r, t) ψ(r, t)<br />
  = A(r) <br />
∫<br />
∫<br />
〈A ˆ 〉 = d 3 r A(r) ψ ∗ (r, t) ψ(r, t) = d 3 r A(r) |ψ(r, t)| 2<br />
✑
1 4<br />
, 2 |ψ(r, t)| 2 <br />
, <br />
, 1 (Ehrenfest) <br />
<br />
<br />
〈A ˆ 〉 , Â <br />
i d ∫<br />
〈A ˆ 〉 = d 3 r<br />
(i ∂ψ∗ Âψ + ψ ∗ Â i ∂ψ )<br />
dt<br />
∂t<br />
∂t<br />
(1.2) <br />
i d ∫<br />
〈A ˆ 〉 =<br />
dt<br />
<br />
1 2 <br />
∫<br />
∫<br />
d 3 2<br />
r (Ĥψ∗)Âψ = −<br />
2m<br />
∫<br />
)<br />
d 3 r<br />
(− (Ĥψ∗)Âψ + ψ∗ÂĤψ ∫<br />
∫<br />
d 3 2<br />
r (Ĥψ∗)Âψ = − d 3 r (∇ 2 ψ ∗<br />
2m<br />
)Âψ + d 3 r V (r)ψ ∗ Âψ<br />
∫<br />
∫<br />
d 3 r ψ ∗ ∇ 2 Âψ + d 3 r V (r)ψ ∗ Âψ = d 3 r ψ ∗ ĤÂψ<br />
<br />
i d ∫<br />
〈A ˆ 〉 =<br />
dt<br />
) ∫<br />
d 3 r<br />
(− ψ ∗ ĤÂψ + ψ∗ÂĤψ = d 3 r ψ ∗ [ Â , Ĥ ] ψ (1.7)<br />
 Ĥ , 〈A ˆ 〉 <br />
Ĥ , 〈H ˆ 〉 , Â = 1 <br />
∫<br />
〈A ˆ 〉 = d 3 r |ψ(r, t)| 2 = P<br />
, P <br />
(Ehrenfest) <br />
(1.7) Â = r , Â = ˆp <br />
d<br />
dt 〈 r 〉 = 1 ∫<br />
d 3 r ψ ∗ [ r , Ĥ ] ψ ,<br />
i<br />
d<br />
dt 〈 ˆp 〉 = 1 ∫<br />
d 3 r ψ ∗ [ ˆp , Ĥ ] ψ<br />
i<br />
[ x , Ĥ ] , Ĥ x ˆp x <br />
Â, ˆB, Ĉ <br />
[ x , Ĥ ] = 1<br />
2m [ x , ˆp2 x ]<br />
[ Â , ˆBĈ ] = Â ˆBĈ − ˆBĈÂ )<br />
(Â = ˆB − ˆBÂ)<br />
Ĉ + ˆB<br />
(ÂĈ − ĈÂ = [ Â , ˆB ] Ĉ + ˆB [ Â , Ĉ ]<br />
[ x , ˆp x ] = i <br />
[ x , Ĥ ] = 1 (<br />
)<br />
[ x , ˆp x ] ˆp x + ˆp x [ x , ˆp x ] = i 2m<br />
m ˆp x
1 5<br />
y , z <br />
[ r , Ĥ ] = i m<br />
ˆp (1.8)<br />
<br />
<br />
d<br />
dt 〈 r 〉 = 1 ∫<br />
d 3 r ψ ∗ ˆp ψ = 1 m<br />
m 〈 ˆp 〉<br />
(<br />
)<br />
[ ˆp , Ĥ ] = [ ˆp , V (r) ] = − i ∇V (r) − V (r)∇<br />
, ψ , <br />
(<br />
) ( )<br />
[ ˆp , Ĥ ]ψ = − i ∇V (r)ψ − V (r)∇ψ = − i ∇V (r) ψ (1.9)<br />
∇ V (r) F (r) V (r) <br />
F (r) = − ∇V (r)<br />
<br />
∫<br />
d<br />
dt 〈 ˆp 〉 = d 3 r ψ ∗ (F (r)) ψ = 〈F (r)〉<br />
, <br />
d<br />
dt 〈 r 〉 = 1 m 〈 ˆp 〉 ,<br />
d<br />
〈 ˆp 〉 = 〈F (r)〉 (1.10)<br />
dt<br />
<br />
〈F (r)〉 = F ( 〈r〉 ) , , , <br />
〈F (r)〉 ̸= F ( 〈r〉 ) 1 X = 〈 x 〉 <br />
F (x) = F (X + x − X) = F (X) + F ′ (X)(x − X) + F ′′ (X)<br />
(x − X) 2 + · · ·<br />
2<br />
<br />
∫<br />
〈F (x)〉 = dx F (x) |ψ(x, t)| 2<br />
∫<br />
∫<br />
= F (X) dx |ψ| 2 + F ′ (X) dx (x − X)|ψ| 2 + F ′′ ∫<br />
(X)<br />
dx (x − X) 2 |ψ| 2 + · · ·<br />
2<br />
<br />
∫<br />
∫<br />
dx |ψ| 2 = 1 , X = dx x |ψ| 2<br />
<br />
m d2<br />
dt 2 〈 x 〉 = F (〈 x 〉) + F ′′ (〈 x 〉)<br />
(<br />
〈 x 2 〉 − 〈 x 〉 2) + · · · (1.11)<br />
2<br />
2 <br />
V (x) ∝ x n , n = 0, 1, 2 (1.12)<br />
F (x) 2 0 , 〈 x 〉 <br />
, 〈 x 〉 , |ψ(x, t)| 2 x = 〈 x 〉 <br />
|ψ(x, t)| 2 , 〈 x 〉 <br />
(1.12) ,
1 6<br />
( 〈 x 2 〉 ≈ 〈 x 〉 2 ), F (x) ( F ′′ (〈 x 〉) ≈ 0 ), <br />
1, 2, 3 , <br />
, ∆x = √ 〈 x 2 〉 − 〈 x 〉 2 , ∆p = √ 〈 ˆp 2 〉 − 〈 ˆp 〉 2 , 11 , <br />
∆x∆p ≥ /2 <br />
, x , <br />
<br />
<br />
∫<br />
〈 ˆp 〉 = − i d 3 r ψ ∗ (r, t) ∇ψ(r, t)<br />
, <br />
∫<br />
〈 ˆp 〉 ∗ = i d 3 r ψ(r, t) ∇ψ ∗ (r, t)<br />
, <br />
∫<br />
dx ψ(r, t) ∂ψ∗ (r, t)<br />
[<br />
] x=+∞<br />
∫<br />
= ψ(r, t)ψ ∗ (r, t) − dx ψ ∗ ∂ψ(r, t)<br />
(r, t)<br />
∂x<br />
x=−∞<br />
∂x<br />
∫<br />
= − dx ψ ∗ ∂ψ(r, t)<br />
(r, t)<br />
∂x<br />
<br />
∫<br />
〈 ˆp 〉 ∗ = − i d 3 r ψ ∗ (r, t) ∇ψ(r, t) = 〈 ˆp 〉<br />
, <br />
<br />
∫<br />
〈 ˆp 〉 = − i d 3 r ψ(r, t) ∇ψ(r, t) = − i 2<br />
∫<br />
d 3 r ∇ψ 2 (r, t) = i × <br />
〈 ˆp 〉 0 <br />
〈 ˆp x 〉 = − i ∫<br />
d 3 r ∂<br />
2 ∂x ψ2 (r, t) = − i ∫<br />
2<br />
, 〈 ˆp 〉 ̸= 0 <br />
dy dz [ ψ 2 (r, t) ] x=∞<br />
x=−∞ = 0<br />
(1.4) j <br />
j(r, t) = 1 (<br />
)<br />
ψ ∗ (r, t) ˆp ψ(r, t) − ψ(r, t) ˆp ψ ∗ (r, t)<br />
2m<br />
<br />
∫<br />
d 3 r j(r, t) =<br />
〈 ˆp 〉 + 〈 ˆp 〉∗<br />
2m<br />
= 〈 ˆp 〉<br />
m<br />
j(r, t) , v(r, t) j = ρ v <br />
, j v (1.4) j <br />
<br />
1.2 <br />
, ψ α (r, t) , α <br />
, ψ α (r, t)<br />
|ψ α 〉 | α 〉 | 〉
1 7<br />
| α 〉, | β 〉 〈 α | β 〉 <br />
∫<br />
〈 α | β 〉 = d 3 r ψα(r, ∗ t) ψ β (r, t)<br />
<br />
〈 α | β 〉 ∗ = 〈 β | α 〉<br />
, 〈 α | α 〉 , u, v | γ 〉 = u | α 〉 + v | β 〉 <br />
〈 α ′ | γ 〉 = u 〈 α ′ | α 〉 + v 〈 α ′ | β 〉 , 〈 γ | α ′ 〉 = u ∗ 〈 α | α ′ 〉 + v ∗ 〈 β | α ′ 〉<br />
<br />
 ψ α(r, t) Âψ α(r, t)  | α 〉 | β 〉 <br />
<br />
∫<br />
〈 β | Â | α 〉 = d 3 r ψβ(r, ∗ t) Â ψ α(r, t)<br />
<br />
1.3 <br />
ψ α (r, t), ψ β (r, t) <br />
(∫<br />
∗ ∫<br />
d 3 r ψα(r, ∗ t) Â ψ β(r, t))<br />
= d 3 r ψβ(r, ∗ t) ˆB ψ α (r, t) , 〈 α | Â | β 〉∗ = 〈 β | ˆB | α 〉<br />
ˆB  ˆB = † <br />
〈 α |  | β 〉∗ = 〈 β | † | α 〉 (1.13)<br />
 , † =  ,  <br />
A ij A † (A † ) ij = A ∗ ji , <br />
(1.13) <br />
| γ 〉 = Â| β 〉 | µ 〉 <br />
〈 γ | µ 〉 = 〈 µ | γ 〉 ∗ = 〈 µ |  | β 〉∗ = 〈 β | † | µ 〉<br />
| µ 〉 = ˆB † | α 〉 , <br />
〈 γ | ˆB † | α 〉 = 〈 β | † ˆB† | α 〉<br />
<br />
〈 α | ˆB | β 〉∗ = 〈 α | ˆB | γ 〉 ∗ = 〈 γ | ˆB † | α 〉 = 〈 β | † ˆB† | α 〉<br />
〈 α | ˆBÂ | β 〉∗ = 〈 β | ( ˆBÂ)† | α 〉 <br />
( ˆBÂ)† = † ˆB†<br />
n Â1Â2 · · · Ân <br />
(Â1 Â 2 · · · Ân<br />
) †<br />
=  † n · · · † 2† 1 (1.14)
1 8<br />
, <br />
 ˆB <br />
(Â ˆB) † = ˆB † Â † = ˆBÂ<br />
 ˆB ,  ˆB <br />
|ψ〉 Â ˆB|ψ〉 = ˆBÂ|ψ〉 = |ψ〉, Â ˆB = ˆBÂ = 1 , <br />
 Â−1 1  <br />
Ĉ ˆD ˆD −1 Ĉ −1 = ĈĈ−1 = 1 , ∴ (CD) −1 = ˆD −1 Ĉ −1<br />
, †  = † = 1, † = A −1 <br />
  ˆB <br />
(Â ˆB) −1 = ˆB −1 Â −1 = ˆB † Â † = (AB) †<br />
 ˆB  ˆB <br />
<br />
Û | α′ 〉 = Û| α 〉 <br />
〈 α ′ |  | β 〉 = 〈 β | † | α ′ 〉 ∗ = 〈 β | † Û | α 〉 ∗ = 〈 α | († Û) † | β 〉 = 〈 α | Û †  | β 〉 (1.15)<br />
〈 α ′ | 〈 α ′ | = 〈 α |U † | β ′ 〉 = Û| β 〉 <br />
〈 α ′ | β ′ 〉 = 〈 α | Û † Û | β 〉 (1.16)<br />
, Û 〈 α′ | β ′ 〉 = 〈 α | β 〉 <br />
<br />
 ϕ(r)  ϕ(r) , ϕ(r) <br />
, ϕ a (r) <br />
 ϕ a (r) = a ϕ a (r)<br />
a , ϕ a (r) Â <br />
, a a <br />
 ,  , <br />
a 1 , a 2 , · · · a i ϕ i (r) :<br />
 ϕ i (r) = a i ϕ i (r) ,  | i 〉 = a i | i 〉 (1.17)<br />
, 〈 i | i 〉 = 1 ϕ i (r) <br />
1. (1.17) ϕ ∗ i 〈 i |Â| i 〉 = a i〈 i | i 〉 = a i <br />
〈 i |Â| i 〉 a i <br />
2. (1.17) ϕ ∗ j 〈 j |Â| i 〉 = a i〈 j | i 〉 <br />
〈 i |Â| j 〉 = a i〈 i | j 〉
1 9<br />
 | j 〉 = a j | j 〉 | i 〉 <br />
〈 i |Â| j 〉 = a j〈 i | j 〉<br />
<br />
a i ≠ a j <br />
(a i − a j ) 〈 i | j 〉 = 0<br />
∫<br />
〈 i | j 〉 = d 3 r ϕ ∗ i ϕ j = 0<br />
ϕ i ϕ j ϕ i <br />
<br />
〈 i | j 〉 = δ ij (1.18)<br />
3. , ψ(r) ϕ i (r) <br />
<br />
ψ(r) = ∑ c i ϕ i (r) , | ψ 〉 = ∑ c i | i 〉 (1.19)<br />
i<br />
i<br />
c i ϕ ∗ j (r) <br />
<br />
〈 j | ψ 〉 = ∑ i<br />
ψ(r) <br />
c i 〈 j | i 〉 = ∑ i<br />
c i δ ij = c j (1.20)<br />
| ψ 〉 = ∑ i<br />
| i 〉〈 i | ψ 〉 (1.21)<br />
<br />
ψ(r) = ∑ i<br />
∫<br />
∫<br />
ϕ i (r) d 3 r ′ ϕ ∗ i (r ′ ) ψ(r ′ ) = d 3 r ′ ψ(r ′ ) ∑ i<br />
ϕ i (r) ϕ ∗ i (r ′ )<br />
<br />
∑<br />
ϕ i (r) ϕ ∗ i (r ′ ) = δ(r − r ′ ) (1.22)<br />
i<br />
(1.22) <br />
, (1.18), (1.22) <br />
(1.13) <br />
〈ψ|  |ψ〉 = 〈ψ|  |ψ〉∗ = 〈ψ| † |ψ〉<br />
,  = † 3 , , <br />
<br />
✓ 3 ′<br />
✏<br />
 , 1  ϕ i(r) 1 <br />
, ϕ i <br />
∫<br />
|c i (t)| 2 , c i (t) = d 3 r ϕ ∗ i (r) ψ(r, t)<br />
 a i , ψ(r, t) <br />
, c i ψ(r, t) (1.19) <br />
✒<br />
✑
1 10<br />
ψ <br />
∫<br />
1 = d 3 r ψ ∗ (r, t) ψ(r, t) = ∑ ij<br />
∫<br />
c ∗ i c j d 3 r ϕ ∗ i (r) ϕ j (r) = ∑ ij<br />
c ∗ i c j δ ij = ∑ i<br />
|c i | 2<br />
, 1 , <br />
, ∑ |c i | 2 = 1 <br />
 <br />
〈 Â 〉 = ∑ i<br />
a i |c i | 2<br />
<br />
 |ψ〉 = ∑ i<br />
c i  | i 〉 = ∑ i<br />
c i a i | i 〉<br />
<br />
〈 ψ | A | ψ 〉 = ∑ ij<br />
c ∗ j c i a i 〈 j | i 〉 = ∑ i<br />
a i |c i | 2<br />
, 3 ′ 3 <br />
 1 ϕ k(r) <br />
∫<br />
∫<br />
c i = d 3 r ϕ ∗ i (r) ψ(r, t) = d 3 r ϕ ∗ i (r) ϕ k (r) = δ ik<br />
, Â i ≠ k a i 0 , <br />
a k <br />
1.2<br />
<br />
ˆp = − i∇ , 〈 α | ˆp | β 〉 ∗ = 〈 β | ˆp | α 〉 <br />
ˆp † = (− i∇) † = (−i) ∗ ∇ † = i ∇ †<br />
∇ † = − ∇ ∇ <br />
<br />
F (x) <br />
F (Â) <br />
F (x) =<br />
∞∑<br />
f n x n<br />
n=0<br />
∞<br />
F (Â) = ∑<br />
f n  n<br />
n=0<br />
 Â| i 〉 = a i| i 〉  <br />
<br />
∞ F (Â)| i 〉 = ∑<br />
∞∑<br />
f n  n | i 〉 = f n a n i | i 〉 = F (a i )| i 〉 (1.23)<br />
n=0<br />
F (a i ) F (x) <br />
(1.23) F (Â) |ψ〉 <br />
n=0<br />
|ψ〉 = ∑ i<br />
c i | i 〉 ,<br />
c i =
1 11<br />
<br />
F (Â)|ψ〉 = ∑ i<br />
c i F (Â) | i 〉 = ∑ i<br />
c i F (a i ) | i 〉 (1.24)<br />
, <br />
<br />
e =<br />
 ˆB , eÂ+ ˆB = eÂe ˆB <br />
∞∑<br />
n=0<br />
 n<br />
n!<br />
eÂe − = e −Âe = 1 , ∴ ( eÂ) −1<br />
= e<br />
−Â<br />
 ˆB eÂ+ ˆB ≠ eÂe ˆB (4.44) <br />
(<br />
e  ) †<br />
∑<br />
∞<br />
= (Ân ) †<br />
n=0<br />
n!<br />
=<br />
∞∑ († ) n<br />
n=0<br />
n!<br />
= exp ( A †)<br />
 (iÂ)† = − i <br />
(<br />
e  ) †<br />
= e ,<br />
(<br />
e iÂ) †<br />
= e<br />
−i = ( e iÂ) −1<br />
e , e i <br />
1 ψ(x + c) <br />
 = c d<br />
dx <br />
ψ(x + c) = ψ(x) + c dψ<br />
dx + c2 d 2 ψ<br />
2! dx 2 + · · · + cn d n ψ<br />
n! dx n + · · ·<br />
ψ(x + c) =<br />
∞∑<br />
n=0<br />
ˆp = − i d<br />
dx <br />
(<br />
n!Ân 1<br />
ψ(x) = exp(Â) ψ(x) = exp c d )<br />
ψ(x) (1.25)<br />
dx<br />
e icˆp/ ψ(x) = ψ(x + c) (1.26)<br />
e icˆp/ − c x <br />
1.4 <br />
|ψ〉 Â , Â ( <br />
) <br />
√<br />
) 2<br />
∆a = 〈ψ|<br />
(Â − a |ψ〉 , a = 〈ψ| Â |ψ〉<br />
a , 〈ψ| a |ψ〉 = a〈ψ|ψ〉 = a <br />
<br />
√<br />
) √<br />
√<br />
∆a = 〈ψ|<br />
(Â2 − 2a + a2 |ψ〉 = 〈ψ|Â2 |ψ〉 − a 2 = 〈ψ|Â2 |ψ〉 − 〈ψ|  |ψ〉2
1 12<br />
|ψ〉 Â 〈ψ|Â2 |ψ〉 = 〈ψ| Â |ψ〉2 = a 2 , 〈ψ|Â2 |ψ〉 ̸=<br />
〈ψ| Â |ψ〉2 <br />
2 Â ˆB <br />
∆a∆b ≥ 1 2<br />
∣<br />
∣〈ψ|[ Â , ˆB ]|ψ〉<br />
∣ ∣∣ (1.27)<br />
〈ψ|[ Â , ˆB ]|ψ〉 ̸= 0 ,<br />
 ˆB , ,  = x, ˆB = ˆpx <br />
[ x , ˆp x ] = i <br />
∆x∆p x ≥ 2<br />
(1.28)<br />
, <br />
<br />
(1.27) <br />
c ψ(r) = ψ α (r) + c ψ β (r) <br />
∫ (<br />
)(<br />
)<br />
〈ψ|ψ〉 = d 3 r ψα(r) ∗ + c ∗ ψβ(r)<br />
∗ ψ α (r) + c ψ β (r)<br />
= 〈 α | α 〉 + |c | 2 〈 β | β 〉 + c 〈 α | β 〉 + c ∗ 〈 β | α 〉 ≥ 0 (1.29)<br />
c , c = − 〈 β | α 〉/〈 β | β 〉 〈 β | α 〉 = 〈 α | β 〉 ∗ (1.29) <br />
〈ψ|ψ〉 = 〈 α | α 〉 −<br />
|〈 β | α 〉|2<br />
〈 β | β 〉<br />
≥ 0 , 〈 α | α 〉〈 β | β 〉 ≥ |〈 β | α 〉| 2 (1.30)<br />
( ) ψ = 0 , ψ α ∝ ψ β <br />
 ′ =  − a , | ψ a 〉 = Â′ | ψ 〉 (1.16) <br />
) 2<br />
〈 ψ a | ψ a 〉 = 〈 ψ |Â′† Â ′ | ψ 〉 = 〈 ψ |(Â′ ) 2 | ψ 〉 = 〈 ψ |<br />
(Â − a | ψ 〉 = (∆a)<br />
2<br />
1 ˆB <br />
(∆b) 2 = 〈 ψ b | ψ b 〉 , | ψ b 〉 = ˆB ′ | ψ 〉 =<br />
, <br />
(<br />
ˆB − b<br />
)<br />
| ψ 〉 , b = 〈 ψ | ˆB | ψ 〉<br />
(∆a) 2 (∆b) 2 = 〈 ψ a | ψ a 〉〈 ψ b | ψ b 〉 ≥ |〈 ψ a | ψ b 〉| 2 ∣<br />
= ∣〈 ψ | Â′ ˆB′ ∣<br />
| ψ 〉<br />
∣ 2<br />
λ <br />
ψ b (r) = λ ψ a (r) (1.31)<br />
Â′ ˆB′ 2 <br />
 ′ ˆB′ = i Ĉ + ˆD ,<br />
Ĉ = 1 2i<br />
(Â′ ˆB′ − ˆB ′ Â ′) = 1 2i [ Â , ˆB ] , ˆD = Â ′ ˆB′ + ˆB ′ Â ′<br />
2<br />
Â′ ˆB ′ (Â′ ˆB′ ) † = ˆB ′ Â ′ Ĉ ˆD <br />
, <br />
∣<br />
∣〈 ψ |Â′ ˆB′ | ψ 〉 ∣ 2 = ∣ i 〈 ψ | Ĉ | ψ 〉 + 〈 ψ | ˆD | ψ 〉 ∣ 2 = 〈 ψ | Ĉ | ψ 〉2 + 〈 ψ | ˆD | ψ 〉 2
1 13<br />
<br />
(∆a) 2 (∆b) 2 ≥ 〈 ψ | Ĉ | ψ 〉2 + 〈 ψ | ˆD | ψ 〉 2 ≥ 〈 ψ | Ĉ | ψ 〉2 = 1 4<br />
(1.29) <br />
∣<br />
∣〈 ψ |[ Â , ˆB ]| ψ 〉<br />
∣ ∣∣<br />
2<br />
(1.29) (1.31) <br />
〈 ψ | ˆD | ψ 〉 = 1 (<br />
〈 ψ<br />
2<br />
|Â′ ˆB′ | ψ 〉 + 〈 ψ | ˆB<br />
)<br />
′ Â ′ | ψ 〉 = 1 (<br />
〈 ψ a | ψ b 〉 + 〈 ψ a | ψ b 〉 ∗) = 0 (1.32)<br />
2<br />
(1.31) <br />
λ + λ ∗<br />
〈 ψ a | ψ a 〉 = 0<br />
2<br />
(∆a) 2 = 〈ψ a |ψ a 〉 ̸= 0 ν λ = iν <br />
ψ b (r) = iν ψ a (r) ,<br />
<br />
(1.32) <br />
〈 ψ a | ψ b 〉 = 1 2<br />
(1.33) <br />
<br />
i.e.<br />
( )<br />
)<br />
ˆB − b ψ(r) = iν<br />
(Â − a ψ(r) (1.33)<br />
(<br />
)<br />
〈 ψ a | ψ b 〉 − 〈 ψ b | ψ a 〉 = 1 (Â′<br />
2 〈 ψ | ˆB′ − ˆB ′ Â ′) | ψ 〉 = 1 2 〈 ψ |[ Â , ˆB ]| ψ 〉<br />
ν = − i 〈 ψ a | ψ b 〉<br />
〈 ψ a | ψ a 〉 = − i 〈 ψ |[ Â , ˆB ]| ψ 〉<br />
= − i 〈 ψ |[ Â , ˆB ]| ψ 〉<br />
2〈 ψ a | ψ a 〉<br />
2 (∆a) 2 (1.34)<br />
1.3<br />
ψ(x) <br />
1 x ˆp ∆x∆p = /2 <br />
ψ(x) =<br />
(<br />
1<br />
(2π(∆x) 2 ) exp − (x − x 0) 2 )<br />
1/4 4(∆x) 2 + ik 0 x<br />
, x 0 = 〈ψ| x |ψ〉 , k 0 = 〈ψ| ˆp |ψ〉 <br />
(1.35)<br />
1.5 <br />
<br />
∂ψ(r, t)<br />
i = Ĥψ(r, t) (1.36)<br />
∂t<br />
ψ(r, t) = f(t)ϕ(r) <br />
<br />
i df(t)<br />
= 1<br />
f(t) dt ϕ(r)Ĥϕ(r)<br />
t , r , <br />
E f <br />
df(t)<br />
dt<br />
= E i f(t)
1 14<br />
f(t) = f 0 e −iEt/ f 0 ϕ(r) <br />
ψ(r, t) = e −iEt/ ϕ(r) (1.37)<br />
<br />
Ĥϕ(r) = Eϕ(r) (1.38)<br />
ϕ(r) <br />
Ĥ , E <br />
(1.37) , t = 0 Ĥ ϕ , e−iEt/<br />
, t = 0 , (1.37) ψ(r, t) <br />
|ψ(r, t)| 2 = |ϕ(r)| 2 , Â <br />
, 〈Â 〉 <br />
∫ (<br />
∗<br />
∫<br />
〈Â 〉 = d 3 r e ϕ(r)) −iEt/ Âe −iEt/ ϕ(r) = d 3 r ϕ ∗ (r)Âϕ(r)<br />
(1.7) , [ Â , Ĥ ] ≠ 0 <br />
, Â Ĥ Â <br />
(1.38) , ,<br />
<br />
Ĥϕ n (r) = E n ϕ n (r) , Ĥ | n 〉 = E n | n 〉<br />
(1.18) c n c n e −iEnt/ ϕ n (r) (1.36)<br />
, , (1.36) , (1.36) <br />
ψ(r, t) = ∑ n<br />
c n e −iE nt/ ϕ n (r) , |ψ(t)〉 = ∑ n<br />
c n e −iE nt/ | n 〉 (1.39)<br />
c n (1.39) ϕ ∗ j (r) , (1.18)<br />
<br />
〈 j |ψ(t)〉 = ∑ n<br />
c n e −iE nt/ δ nj = c j e −iE jt/<br />
t = 0 <br />
∫<br />
c n = 〈 n |ψ(0)〉 = d 3 r ϕ ∗ n(r) ψ(r, 0) (1.40)<br />
, t = 0 ψ(r, 0) c n , ψ(r, t)<br />
, ψ(r, 0) Ĥ ϕ k c n = 〈 n | k 〉 = δ nk <br />
<br />
ψ(r, t) = e −iEkt/ ϕ k (r)<br />
<br />
(1.39) <br />
|ψ(r, t)| 2 = ∑ c ∗ nc n ′e i(En−E n ′ )t/ ϕ ∗ n(r)ϕ n ′(r)<br />
nn ′<br />
, <br />
ψ(r, t) = c 1 e −E 1t/ ϕ 1 (r) + c 2 e −E 2t/ ϕ 2 (r)
1 15<br />
<br />
(<br />
)<br />
|ψ(r, t)| 2 = |c 1 ϕ 1 (r)| 2 + |c 2 ϕ 2 (r)| 2 + 2Re c ∗ 1c 2 e i(E 1−E 2 )t/ ϕ ∗ 1(r)ϕ 2 (r)<br />
, |E 1 − E 2 |/ , <br />
∫<br />
d 3 r |ψ(r, t)| 2 = ∑ ∫<br />
c ∗ nc n ′e i(En−E n ′ )t/ d 3 r ϕ ∗ n(r)ϕ n ′(r) = ∑ c ∗ nc n ′e i(En−E n ′ )t/ δ nn ′ = ∑<br />
nn ′ nn ′ n<br />
|c n | 2<br />
<br />
 〈ψ(t)|  |ψ(t)〉 = ∑ nn ′ c ∗ nc n ′e i(En−E n ′ )t/ 〈 n |  | n′ 〉 (1.41)<br />
, , c n = δ nk <br />
〈ψ(t)| Â |ψ(t)〉 = 〈 k | Â | k 〉 = 〈ψ(0)| Â |ψ(0)〉<br />
, 〈 n | Ĥ | n′ 〉 = E n 〈 n | n ′ 〉 =<br />
E n δ nn ′ , <br />
〈ψ(t)| Ĥ |ψ(t)〉 = ∑ n<br />
|c n | 2 E n<br />
( ) t E n <br />
|〈 n |ψ(t)〉| 2 = |c n e −iEnt/ | 2 = |c n | 2<br />
<br />
e −iĤt/ e −iĤt/ | n 〉 = e −iEnt/ | n 〉 (1.39) <br />
|ψ(t)〉 = ∑ n<br />
c n e −iĤt/ | n 〉<br />
e −iĤt/ n <br />
|ψ(t)〉 = e −iĤt/ ∑ n<br />
c n | n 〉 = e −iĤt/ |ψ(0)〉 (1.42)<br />
(1.26) , , <br />
(1.42) (1.36) <br />
, (1.15) , (1.41) <br />
〈ψ(t)| Â |ψ(t)〉 = 〈ψ(0)| eiĤt/ Â e −iĤt/ |ψ(0)〉 (1.43)<br />
<br />
1.4<br />
ψ(r, t) Ĥ ϕ n(r) <br />
ψ(r, t) = ∑ n<br />
f n (t) ϕ n (r)<br />
(1.36) f n (t) i df n<br />
dt = E nf n (1.39)
1 16<br />
1.5<br />
Ĥ <br />
〈 n |[ Â , Ĥ ]| n′ 〉 = (E n ′ − E n ) 〈 n |Â | n′ 〉<br />
(1.41) (1.7) , (1.43) (1.7) <br />
1.6<br />
〈 n |[ Â , Ĥ ]| n 〉 = 0 Â = r· ˆp <br />
1<br />
2m 〈 n | ˆp2 | n 〉 = 1 ˆp2<br />
〈 n | r·(∇V ) | n 〉 , Ĥ = + V (r) (1.44)<br />
2 2m<br />
<br />
1.6 <br />
ˆp = − i∇ <br />
∇ exp(ik·r) = ik exp(ik·r) , ˆp exp(ik·r) = k exp(ik·r)<br />
exp(ik·r) k N k <br />
ϕ k (r) = N k exp(ik·r)<br />
, Ĥ = ˆp2 /(2m) <br />
Ĥϕ k (r) = E k ϕ k (r) , E k = 2 k 2<br />
ϕ k (r) Ĥ E k |ϕ k (r)| r <br />
∫<br />
∫<br />
d 3 r |ϕ k (r)| 2 = |N k | 2 d 3 r = <br />
, r V <br />
V → ∞ |N k | 2 V = 1 , <br />
ϕ k (r) = 1 √<br />
V<br />
exp(ik·r)<br />
2m<br />
<br />
N k = (2π) −3/2 <br />
∫ ( )<br />
〈 k | k ′ 〉 = NkN ∗ k ′ d 3 r exp i (k ′ − k)·r = (2π) 3 |N k | 2 δ(k − k ′ ) = δ(k − k ′ )<br />
, <br />
, <br />
∂ψ(r, t)<br />
i = − 2<br />
∂t 2m ∇2 ψ(r, t)<br />
, (1.39), (1.40) ϕ i (r) ϕ k (r) , k i <br />
<br />
∫<br />
∫<br />
ψ(r, t) = d 3 k c(k) ϕ k (r)e −iωkt 1<br />
= d 3 k c(k) exp (ik·r − iω<br />
(2π) 3/2 k t) ,<br />
ω k = E k<br />
= k2<br />
2m
1 17<br />
, , <br />
(1.40) | i 〉 | k 〉 <br />
∫<br />
1<br />
〈 k |ψ(0)〉 = d 3 r exp (− ik·r) ψ(r, 0)<br />
(2π) 3/2<br />
= 1 ∫<br />
∫<br />
(2π) 3 d 3 r exp (− ik·r) d 3 k ′ c(k ′ ) exp (ik ′·r)<br />
∫ ∫ d<br />
= d 3 k ′ c(k ′ 3 r<br />
( ) ∫<br />
)<br />
(2π) 3 exp i (k ′ − k)·r = d 3 k ′ c(k ′ ) δ(k − k ′ ) = c(k)<br />
<br />
1.7<br />
ψ(r, t) ψ(r, t) = N exp(ik·r − iEt/) <br />
1. ρ j j = ρv v <br />
k k/m ρ v <br />
j = ρ v <br />
2. ∆x ∆p x <br />
1.8<br />
<br />
∫<br />
d 3 r<br />
ϕ(k, t) = exp(− ik·r) ψ(r, t)<br />
(2π)<br />
3/2<br />
<br />
∫<br />
1. ψ(r, t) d 3 k |ϕ(k, t)| 2 = 1 <br />
2. ∫<br />
∫<br />
d 3 r ψ ∗ (r, t) ˆp ψ(r, t) = d 3 k k |ϕ(k, t)| 2<br />
3.<br />
k |ϕ(k, t)| 2 <br />
3 ′ <br />
∫<br />
d 3 (<br />
r<br />
(2π) 3/2 xn exp(−ik·r) ψ(r, t) = i ∂ ) n<br />
ϕ(k, t) <br />
∂k x<br />
∫<br />
d 3 r<br />
(2π) 3/2 V (r) exp(−ik·r) ψ(r, t) = V (i∇ k)ϕ(k, t)<br />
∇ k k <br />
4. p = k <br />
∂ϕ(p, t)<br />
i = p2<br />
∂t 2m ϕ(p, t) + V (ˆr) ϕ(p, t) , ˆr = i∇ p (1.45)<br />
r , <br />
(1.1) <br />
1.7 <br />
r t exp (ik·r − iωt) ω > 0 k ω = k 2 /(2m)<br />
t , θ = k·r − ωt 2 r 1 , r 2 <br />
k·r 1 − ωt = k·r 2 − ωt , ∴ k·(r 1 − r 2 ) = 0
1 18<br />
k r 1 − r 2 , t , r k <br />
, exp (ik·r − iωt) <br />
, k k t ∆t , k <br />
∆r <br />
k·r − ωt = k·<br />
(r + k k ∆r )<br />
− ω (t + ∆t) , k = | k |<br />
<br />
v p = ∆r<br />
∆t = ω k<br />
v p = ω/k v p <br />
v p = k/(2m) , k/m <br />
2 <br />
∂ψ(r, t)<br />
(S) i = − 2<br />
∂t 2m ∇2 ψ(r, t) , (M) ∇ 2 ψ(r, t) − 1 ∂ 2 ψ(r, t)<br />
c 2 ∂t 2 = 0 (1.46)<br />
(S) , (M) <br />
ψ(r, t) = exp (ik·r − iωt) <br />
(S) ω = k2 , (M) ω = ck (1.47)<br />
2m<br />
exp (ik·r − iωt) (S) , k/(2m) k <br />
, , (M) , c <br />
(1.47) ω k ω k <br />
(1.46) ψ 1 , a(k) , <br />
<br />
∫<br />
ψ(r, t) =<br />
( )<br />
d 3 k a(k) exp ik·r − iω k t<br />
(1.46) 1 k x = k <br />
ψ(x, t) =<br />
∫ ∞<br />
−∞<br />
( )<br />
dk a(k) exp ikx − iω k t<br />
(1.48)<br />
, <br />
a(k) = a 0 e −α2 (k−k 0 ) 2 , α > 0 (1.49)<br />
α , k k 0 a(k) e −α2 (k−k 0 ) 2<br />
= e −1<br />
k |k − k 0 | = 1/α , (1.48) k 0 − 1/α < k < k 0 + 1/α <br />
α → ∞ <br />
a(k) =<br />
{<br />
a0 , k = k 0<br />
0 , k ≠ k 0<br />
α → 0 a(k) = a 0 (1.46) , θ = kx − ω k t k 2 <br />
<br />
θ(k) = θ(k 0 ) + dθ<br />
dk ∣ (k − k 0 ) + 1<br />
k=k0<br />
2<br />
d 2 θ<br />
dk 2 ∣<br />
∣∣∣k=k0<br />
(k − k 0 ) 2<br />
= k 0 x − ω 0 t + (x − v g t) (k − k 0 ) − γt(k − k 0 ) 2
1 19<br />
<br />
ω 0 = ω k0 ,<br />
v g = dω k<br />
dk<br />
(1.48) k − k 0 k <br />
ψ(x, t) = a 0 e ik 0x−iω 0 t<br />
∫ ∞<br />
−∞<br />
∣ , γ = 1<br />
k=k0<br />
2<br />
(<br />
dk exp − ( α 2 + iγt ) )<br />
k 2 + i (x − v g t) k<br />
= a 0 exp<br />
(ik 0 x − iω 0 t − (x − v gt) 2 ) ∫ (<br />
∞<br />
4(α 2 dk exp<br />
+ iγt) −∞<br />
(14.22) , z 1 , z 2 Re z 1 > 0 <br />
∫ ∞<br />
dx exp ( −z 1 (x − z 2 ) 2) √ π<br />
=<br />
z 1<br />
<br />
|ψ(x, t)| 2 <br />
−∞<br />
d 2 ω k<br />
dk 2 ∣<br />
∣∣∣k=k0<br />
− (α 2 + iγt)<br />
√<br />
( π<br />
ψ(x, t) = a 0<br />
α 2 + iγt exp ik 0 x − iω 0 t − (x − v gt) 2 )<br />
4(α 2 + iγt)<br />
(<br />
|ψ(x, t)| 2 = a2 0 π<br />
αD exp − (x − v gt) 2 )<br />
2D 2 , D(t) =<br />
√<br />
α 2 +<br />
(<br />
k − i(x − v ) ) 2<br />
gt)<br />
2(α 2 + iγt)<br />
(1.50)<br />
( ) 2 γt<br />
(1.51)<br />
α<br />
v g ψ(x, t) k = k 0 , <br />
v g v g <br />
(S)<br />
dω k<br />
dk = k m ≠ ω k<br />
k = k<br />
2m , (M) dω k<br />
dk = c = ω k<br />
k<br />
, (S) , <br />
|ψ(x, t)| x = v g t D , <br />
(M) γ = 0 D(t) = α , <br />
(= ) , (S) γ = /(2m) ≠ 0 <br />
, D(t) , ω k ∝ k , <br />
ω k /k k , <br />
, ω k k <br />
v g = dω k /dk <br />
, (1.51) ψ(x, t) <br />
∫ ∞<br />
∫<br />
dx |ψ(x, t)| 2 = a2 0 π ∞<br />
dx exp<br />
(− (x − v gt) 2 )<br />
αD<br />
2D 2 = a2 0 π √<br />
√ α<br />
2πD2 = 1 , ∴ a 0 =<br />
αD<br />
π √ 2π<br />
−∞<br />
−∞<br />
<br />
√<br />
(<br />
1 α<br />
ψ(x, t) = √<br />
2π α 2 + iγt exp ik 0 x − iω 0 t − (x − v gt) 2 )<br />
4(α 2 + iγt)<br />
|ψ(x, t)| 2 1<br />
= √ exp<br />
(− (x − v gt) 2 )<br />
2π D 2D 2<br />
(1.52)<br />
(1.53)<br />
t = 0 (1.35) x 0 = 0 , ∆x = α <br />
, , v g = k 0 /m
1 20<br />
, , <br />
t 〈 · · · 〉 <br />
〈 x 〉 =<br />
〈 x 2 〉 =<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
−∞<br />
∫<br />
dx x |ψ(x, t)| 2 1 ∞<br />
= √ dx (x + v g t) e −x2 /(2D 2) = v g t<br />
2π D<br />
−∞<br />
∫<br />
dx x 2 |ψ(x, t)| 2 1 ∞<br />
= √ dx (x + v g t) 2 e −x2 /(2D 2 )<br />
2π D<br />
−∞<br />
∫<br />
1 ∞<br />
= √ dx ( x 2 + (v g t) 2) e −x2 /(2D 2) = D 2 + (v g t) 2<br />
2π D<br />
−∞<br />
(∆x) 2 = 〈 x 2 〉 − 〈 x 〉 2 = D 2 , <br />
(<br />
∂<br />
∂x ψ(x, t) = ik 0 −<br />
x − v )<br />
gt<br />
2(α 2 ψ(x, t)<br />
+ iγt)<br />
<br />
〈 ˆp 〉 = <br />
∫ ∞<br />
(<br />
)<br />
x − v g t<br />
dx k 0 + i<br />
2(α 2 |ψ(x, t)| 2 = k 0 +<br />
i ∫ ∞<br />
√ dx x /(2D 2 )<br />
e−x2<br />
+ iγt)<br />
2π D 2(α 2 + iγt)<br />
−∞<br />
= k 0 = mv g<br />
〈 ˆp 〉 = m d〈 x 〉/dt , <br />
∫ ∞<br />
〈 ˆp 2 〉 = − 2 dx ψ ∗ (x, t) ∂2<br />
ψ(x, t)<br />
∂x2 −∞<br />
∫ ∞<br />
= 2 dx ∂ψ∗ (x, t) ∂ψ(x, t)<br />
−∞ ∂x ∂x<br />
∫ ∞<br />
= 2 dx<br />
∣ ik 0 −<br />
x − v 2<br />
gt<br />
−∞ 2(α 2 + iγt) ∣ |ψ(x, t)| 2<br />
∫ ∞<br />
(<br />
= 2 dx k0 2 + k 0(x − v g t)γt<br />
α 2 D 2 + (x − v gt) 2 )<br />
4α 2 D 2 |ψ(x, t)| 2 = 2 k0 2 + 2<br />
4α 2<br />
−∞<br />
, (∆p) 2 = 〈 ˆp 2 〉 − 〈 ˆp 〉 2 = 2 /(4α 2 ) <br />
√<br />
∆x∆p = D <br />
2α = ( ) 2 γt<br />
1 +<br />
2 α 2<br />
t ≠ 0 α ∆p γt<br />
α = ∆p<br />
m t <br />
( ) 2 ∆p<br />
(∆x) 2 = D 2 = α 2 +<br />
m t t = 0<br />
t = t 0<br />
∆x , <br />
∆p/m <br />
(1.53) |ψ(x, t)| 2 t 0 <br />
<br />
, 〈 x 〉 〈 p 〉 , <br />
∆x ∆p , 〈 x 〉 <br />
−∞<br />
t = 2t 0<br />
t = 3t 0<br />
0 v g t 0 2v g t 0 3v g t 0 x<br />
〈 p 〉 ,
1 21<br />
1.9<br />
(1.48) <br />
(1.48) <br />
ψ(x, t) = 1<br />
2π<br />
<br />
∫ ∞<br />
−∞<br />
a(k) = 1<br />
2π<br />
∫ ∞<br />
−∞<br />
dx e −ikx ψ(x, 0)<br />
∫ ∞<br />
dx ′ dk e ik(x−x′ )−iω k t ψ(x ′ , 0) =<br />
−∞<br />
G(x, t) = 1<br />
2π<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
−∞<br />
dk e ikx−iω kt<br />
dx ′ G(x − x ′ , t) ψ(x ′ , 0) (1.54)<br />
(1.55)<br />
G(x, t) 1 (14.21) <br />
√ ( )<br />
m<br />
G(x, t) =<br />
2πit exp i mx2<br />
(1.56)<br />
2t<br />
(1.52) t = 0 <br />
ψ(x, 0) =<br />
(1.54) (1.52) <br />
G(x, t) (1.55) <br />
(1.56) t → 0 <br />
)<br />
1<br />
√√ exp<br />
(ik 0 x − x2<br />
2π α 4α 2<br />
G(x, 0) = 1<br />
2π<br />
lim<br />
t→0<br />
√<br />
∫ ∞<br />
−∞<br />
dk e ikx = δ(x)<br />
( )<br />
m<br />
2πit exp i mx2<br />
2t<br />
= δ(x)<br />
1 <br />
<br />
δ(x) = √ 1 e −x2 /ε<br />
lim √ π ε→0 ε
2 1 22<br />
2 1 <br />
2.1 1 <br />
1 <br />
− 2<br />
d 2<br />
ψ(x) + V (x)ψ(x) = Eψ(x) (2.1)<br />
2m dx2 <br />
ψ i (x) 1 <br />
c 1 ψ 1 (x) + c 2 ψ 2 (x) + · · · + c n ψ n (x) = 0 =⇒ c 1 = c 2 = · · · = c n = 0<br />
1 , <br />
1 (2.1) 2 ψ 1 (x) <br />
ψ 2 (x) :<br />
− 2<br />
d 2<br />
2m dx 2 ψ 1(x) + V (x)ψ 1 (x) = Eψ 1 (x) ,<br />
− 2<br />
d 2<br />
2m dx 2 ψ 2(x) + V (x)ψ 2 (x) = Eψ 2 (x)<br />
ψ 2 ψ 1 <br />
ψ 2 (x) d2<br />
dx 2 ψ 1(x) − ψ 1 (x) d2<br />
dx 2 ψ 2(x) = 0<br />
<br />
ψ 2 (x) d2<br />
dx 2 ψ 1(x) − ψ 1 (x) d2<br />
dx 2 ψ 2(x) = d (<br />
ψ 2 (x) d<br />
dx dx ψ 1(x) − ψ 1 (x) d )<br />
dx ψ 2(x)<br />
<br />
ψ 2 (x) d<br />
dx ψ 1(x) − ψ 1 (x) d<br />
dx ψ 2(x) = (2.2)<br />
x → ± ∞ ψ 1 (x) = ψ 2 (x) = 0 = 0 <br />
<br />
ψ 2 (x) d<br />
dx ψ 1(x) − ψ 1 (x) d<br />
dx ψ 2(x) = 0 , d<br />
dx<br />
ψ 1 (x)<br />
ψ 2 (x) = 0<br />
ψ 1 (x) = × ψ 2 (x) ψ 1 ψ 2 <br />
x → ± ∞ 0 , ( V = 0 ), e ikx<br />
e −ikx E = 2 k 2 /(2m) , <br />
2 1 <br />
(2.1) ψ(x) ψ(x) = ψ R (x) + iψ I (x) V (x) <br />
(<br />
− 2<br />
2m<br />
d 2<br />
)<br />
dx 2 + V (x) − E<br />
ψ R (x) = 0 ,<br />
(− 2<br />
d 2<br />
)<br />
2m dx 2 + V (x) − E ψ I (x) = 0<br />
, C ψ I (x) = C ψ R (x) <br />
ψ(x) = (1 + iC)ψ R (x)<br />
ψ R (x) 1 + iC ψ R (x)
2 1 23<br />
, V (x) = V (−x) ψ(x) <br />
(2.1) x −x <br />
V (x) = V (−x) <br />
− 2<br />
d 2<br />
ψ(−x) + V (−x)ψ(−x) = Eψ(−x)<br />
2m dx2 − 2<br />
d 2<br />
ψ(−x) + V (x)ψ(−x) = Eψ(−x) (2.3)<br />
2m dx2 ψ(−x) ψ(x) E , , c <br />
<br />
ψ(−x) = c ψ(x)<br />
ψ(x) = c ψ(−x) = c 2 ψ(x) c 2 = 1 <br />
, ψ(x) <br />
ψ(−x) = ± ψ(x)<br />
<br />
x = a V (x) , a − ε ≤ x ≤ a + ε <br />
dψ ′ (x)<br />
dx<br />
= 2m ( )<br />
2 V (x) − E ψ(x) ,<br />
ψ ′ (x) = dψ(x)<br />
dx<br />
<br />
ψ ′ (a + ε) − ψ ′ (a − ε) =<br />
∫ a+ε<br />
a−ε<br />
dx F (x) ,<br />
F (x) = 2m ( )<br />
2 V (x) − E ψ(x) (2.4)<br />
V (x) x = a F (x) , a − ε ≤ x ≤ a + ε <br />
F min ≤ F (x) ≤ F max<br />
F min , F max <br />
2εF min ≤ ψ ′ (a + ε) − ψ ′ (a − ε) ≤ 2εF max<br />
ε → + 0 <br />
ψ ′ (a + 0) − ψ ′ (a − 0) = 0<br />
, ψ ′ (x) x = a <br />
∫ a+ε<br />
a−ε<br />
dx ψ ′ (x) = ψ(a + ε) − ψ(a − ε) ,<br />
∫ a+ε<br />
a−ε<br />
dx ψ ′ (x) = 2εψ ′ (a) + · · ·<br />
ε→0<br />
−−−−→ 0<br />
ψ(x) x = a <br />
<br />
V 1 (x) V (x) = v 0 δ(x − a) + V 1 (x) v 0 δ(x − a) <br />
⎧<br />
⎨ v 0<br />
V ε (x) = 2ε , |x − a| < ε<br />
⎩ 0 , |x − a| > ε
2 1 24<br />
ε → + 0 ψ(x) ψ ′ (x) (2.4) <br />
ψ ′ (a + ε) − ψ ′ (a − ε) = 2mv 0<br />
2<br />
2 ε → + 0 0 <br />
ψ(a) + 2m<br />
2<br />
ψ ′ (x) x = a x ≠ a <br />
∫ a+ε<br />
a−ε<br />
dx<br />
( )<br />
V 1 (x) − E ψ(x)<br />
ψ ′ (a + 0) − ψ ′ (a − 0) = 2mv 0<br />
2 ψ(a) (2.5)<br />
− 2 d 2 ψ<br />
2m dx 2 + V 1(x)ψ = E ψ<br />
x > a x < a x = a , (2.5) <br />
<br />
(2.5) ψ x = a , <br />
− 2 d 2 ψ<br />
(<br />
)<br />
2m dx 2 + v 0 δ(x − a) + V 1 (x) ψ = E ψ<br />
ψ(a) ≠ 0 d 2 ψ/dx 2 x = a ( ψ(a) = 0 δ(x − a) <br />
V 1 (x) ) ψ(x) 1 <br />
<br />
ψ(x) =<br />
{<br />
ψ − (x) , x < a<br />
ψ + (x) , x > a , ψ(x) = θ(a − x)ψ −(x) + θ(x − a)ψ + (x)<br />
θ(x) <br />
θ(x) =<br />
{<br />
1 , x > 0<br />
0 , x < 0<br />
dθ(x)/dx = δ(x) ψ + (a) = ψ − (a) <br />
ψ ′ (x) = − δ(x − a)ψ − (x) + θ(a − x)ψ −(x) ′ + δ(x − a)ψ + (x) + θ(x − a)ψ +(x)<br />
′<br />
(<br />
)<br />
= δ(x − a) ψ + (a) − ψ − (a) + θ(a − x)ψ −(x) ′ + θ(x − a)ψ +(x)<br />
′<br />
= θ(a − x)ψ ′ −(x) + θ(x − a)ψ ′ +(x)<br />
<br />
(<br />
ψ ′′ (x) = δ(x − a)<br />
)<br />
ψ +(a) ′ − ψ −(a)<br />
′ + θ(a − x)ψ −(x) ′′ + θ(x − a)ψ +(x)<br />
′′<br />
<br />
(<br />
) )<br />
δ(x − a)<br />
(− 2<br />
ψ +(a) ′ − ψ −(a)<br />
′ + v 0 ψ(a)<br />
2m<br />
+ θ(a − x)<br />
(− 2<br />
2m<br />
d 2<br />
dx 2 + V 1(x) − E<br />
)<br />
ψ − + θ(x − a)<br />
(− 2<br />
2m<br />
x = a δ(x − a) 0<br />
(<br />
)<br />
− 2<br />
ψ ′<br />
2m<br />
+(a) − ψ −(a)<br />
′ + v 0 ψ(a) = 0<br />
d 2<br />
dx 2 + V 1(x) − E<br />
)<br />
ψ + = 0
2 1 25<br />
(2.5) <br />
<br />
(2.1) ψ ∗ (x) <br />
∫<br />
∫<br />
∫<br />
NE = − 2<br />
dx ψ ∗ (x) d2 ψ(x)<br />
2m<br />
dx 2 + dx V (x) |ψ(x)| 2 , N = dx |ψ(x)| 2<br />
1 <br />
∫<br />
− 2<br />
dx ψ ∗ (x) d2 ψ(x)<br />
2m<br />
dx 2<br />
∫<br />
∫<br />
= 2<br />
dx dψ∗ dψ(x)<br />
2m dx dx<br />
= 2<br />
dx<br />
2m<br />
∣<br />
dψ(x)<br />
dx<br />
∣<br />
2<br />
> 0<br />
<br />
E > 1 ∫<br />
dx V (x) |ψ(x)| 2<br />
N<br />
V (x) ≥ V min <br />
E > 1 ∫<br />
N<br />
<br />
dx V (x) |ψ(x)| 2 ≥ V min<br />
N<br />
∫<br />
dx |ψ(x)| 2 = V min<br />
2.2 <br />
−a<br />
O<br />
a<br />
a, V 0 V (x)<br />
{<br />
0 , |x| > a<br />
V (x) =<br />
− V 0 , |x| < a<br />
(2.6)<br />
|x| = a , <br />
|x| = a <br />
, F (x) = − dV/dx x = − a F > 0, x = a <br />
F < 0 , 0 , ,<br />
, <br />
−V 0<br />
• ( , )<br />
• , <br />
<br />
<br />
1 <br />
(− 2<br />
2m<br />
d 2 )<br />
dx 2 + V (x)<br />
ψ(x) = E ψ(x) (2.7)<br />
V (x) (2.6) − V 0 < E < 0 <br />
√<br />
√<br />
α = − 2ma2 E<br />
2ma2 (E + V 0 )<br />
2 , β =<br />
2 (2.8)<br />
, (2.7) <br />
|x| < a <br />
|x| > a <br />
d2 ψ(x)<br />
dx 2<br />
d2 ψ(x)<br />
dx 2<br />
= − β2<br />
a 2 ψ(x)<br />
= α2<br />
a 2 ψ(x) (2.9)
2 1 26<br />
V (x) = V (−x) , (2.9) x ≥ 0 <br />
x ≥ 0 (2.9) <br />
A, B, C, D <br />
⎧<br />
⎨ A sin βx βx<br />
+ B cos<br />
ψ(x) = a a ,<br />
⎩<br />
Ce −αx/a + De αx/a ,<br />
0 ≤ x < a<br />
x > a<br />
x → ∞ ψ(x) D = 0 <br />
<br />
ψ ′ (0) = 0 A = 0 x = a ψ(x), ψ ′ (x) <br />
B cos β = Ce −α ,<br />
βB sin β = αCe −α<br />
2 <br />
, <br />
α = β tan β (2.10)<br />
α 2 = β 2 tan 2 β , tan β > 0<br />
<br />
v 0 =<br />
α 2 + β 2 = v 2 0 cos2 β = β 2 /v 2 0 <br />
√<br />
2ma2 V 0<br />
2 (2.11)<br />
| cos β| = β v 0<br />
, tan β > 0 (2.12)<br />
C = Be α cos β <br />
⎧<br />
⎨ B cos βx<br />
ψ(x) = a ,<br />
⎩<br />
B cos β e −α(x−a)/a ,<br />
0 ≤ x < a<br />
x > a<br />
(2.13)<br />
B ψ(x) <br />
∫ a<br />
(<br />
1 +<br />
0<br />
dx cos 2 βx<br />
a = a 2<br />
cos 2 β<br />
∫ ∞<br />
a<br />
)<br />
sin 2β<br />
= a (<br />
1 + α )<br />
2β 2 v0<br />
2<br />
dx e −2α(x−a)/a = a<br />
2α cos2 β = a 2<br />
β 2<br />
αv 2 0<br />
(2.14)<br />
(2.15)<br />
<br />
∫ ∞<br />
−∞<br />
(<br />
dx |ψ(x)| 2 = a|B| 2 1 + α v0<br />
2<br />
) (<br />
+ β2<br />
αv0<br />
2 = a|B| 2 1 + 1 )<br />
√<br />
1<br />
= 1 , ∴ B =<br />
α<br />
a<br />
α<br />
1 + α<br />
<br />
<br />
ψ(0) = 0 B = 0 x = a <br />
A sin β = Ce −α ,<br />
βA cos β = − αCe −α<br />
<br />
α = − β cot β (2.16)
2 1 27<br />
(2.12) <br />
| sin β | = β v 0<br />
, tan β < 0 (2.17)<br />
<br />
⎧<br />
⎨ A sin βx<br />
ψ(x) = a ,<br />
⎩<br />
A sin β e −α(x−a)/a ,<br />
0 ≤ x < a<br />
x > a<br />
√<br />
1 α<br />
, A =<br />
a 1 + α<br />
(2.18)<br />
<br />
(2.12), (2.17) | cos β | | sin β | β/v 0 β <br />
β/v 0 <br />
v 0 = 5 , (2.12), (2.17) 2 , ◦ <br />
β/v 0 = 1 α 2 = v 2 0 − β 2 = 0 , E = 0 , <br />
<br />
(n − 1)π<br />
2<br />
< v 0 ≤ nπ 2<br />
, n = 1, 2, 3, · · ·<br />
n n β β k ( k = 0, 1, 2, · · · )<br />
, k β k (2.12) , (2.17) <br />
1<br />
β 0 β 1 π β 2 β 3 2π β<br />
(2.12), (2.17) β k <br />
E k = −<br />
( )<br />
2<br />
2ma 2 α2 k =<br />
2<br />
2ma 2 βk 2 − v0<br />
2<br />
, v 0 E 0 < E 1 < · · · , <br />
E 0 , E 1 , E 2 , · · · 1 , 2<br />
, · · · V 0 E k <br />
<br />
− α 2 = 2ma 2 E/ 2<br />
−10<br />
−20<br />
−30<br />
<br />
−40<br />
0 π 5 2π v 0
2 1 28<br />
V 0 → ∞ E k → − ∞ , E k + V 0 <br />
2 , β/v 0 β , (2.12), (2.17) β k = (k + 1)π/2<br />
<br />
E k + V 0 =<br />
2<br />
2ma 2 β2 k = 2<br />
2m<br />
( ) 2 (k + 1)π<br />
, k = 0, 1, 2, · · · (2.19)<br />
, α → ∞ , (2.13), (2.18) |x| > a ψ(x) = 0 ,<br />
|x| < a <br />
<br />
⎧<br />
⎪⎨<br />
ψ(x) =<br />
⎪⎩<br />
v , <br />
E E = mv 2 /2 + V (x) <br />
m<br />
2 v2 = E − V (x) ≥ 0<br />
<br />
(2.6) , −V 0 < E < 0 ,<br />
|x| < a , <br />
, <br />
, <br />
|x| > a ψ(x) 0 <br />
2a<br />
1 (k + 1)πx<br />
√ cos , k = 0, 2, 4, · · ·<br />
a 2a<br />
1 (k + 1)πx<br />
√ sin , k = 1, 3, 5, · · ·<br />
a 2a<br />
a|ψ(x)| 2<br />
0.8<br />
0.6<br />
0.4<br />
0.2<br />
v 0 = 3<br />
v 0 = 1<br />
v 0 = 0.5<br />
(2.20)<br />
0 a x<br />
, <br />
v 0 = 0.5, 1, 3 (2.13) <br />
|x| > a P ψ(x) , (2.15) <br />
P = 2<br />
∫ ∞<br />
a<br />
dx |ψ(x)| 2 = |B| 2 aβ2<br />
αv 2 0<br />
P V 0 <br />
( ) 1 ( ) <br />
1 <br />
v 0<br />
≤ π/2 |x| > a ψ(x) ∝<br />
e −α|x|/a E ≈ 0, ( α ≈ 0 ) <br />
, x <br />
, |x| > a v 0 <br />
E ( α ), P <br />
v 0 → ∞ α → ∞ , β → (k + 1)π/2 <br />
P → 0 , <br />
<br />
= 1 β 2<br />
1 + α v0<br />
2 = 1 E + V 0<br />
1 + α V 0<br />
1.0<br />
0.0<br />
1 2 3 4 v 0<br />
2.1<br />
<br />
V (x) =<br />
{<br />
∞ ,<br />
|x| > a<br />
0 , |x| < a
2 1 29<br />
( ) 2<br />
1. E E > 2 1<br />
<br />
2m 2a<br />
2. (2.19) (2.20) <br />
2.2<br />
v 0 → 0 <br />
1. E k k = 0 1 E 0 = − 2<br />
2ma 2 v4 0<br />
<br />
2. V 0 = u 0 /(2a) a → 0 v 0 = √ mau 0 / 2 → 0 <br />
E 0 = −<br />
2<br />
2ma 2 v4 0 = − mu2 0<br />
2 2 (2.21)<br />
<br />
{ ∫ 0 , |x| > a<br />
∞<br />
V (x) =<br />
− u 0 /(2a) , |x| < a , dx V (x) = − u 0<br />
−∞<br />
a → 0 V (x) = − u 0 δ(x) <br />
(− 2 d 2 )<br />
2m dx 2 − u 0δ(x) ψ(x) = Eψ(x)<br />
, E (2.21) x = 0 <br />
(2.5) <br />
2 <br />
E , 2 <br />
x → − ∞ ψ(x) → 0 , x → + ∞ ψ(x) → 0<br />
ψ(x) , x → ∞ ψ(x) → 0 , <br />
x → − ∞ ψ(x) → 0 , ψ(x) , ,<br />
x → − ∞ ψ(x) → 0 1 x → − ∞ ψ → 0 <br />
, (2.9) A, C, D, F , G <br />
⎧<br />
Ae αx/a ,<br />
⎪⎨<br />
ψ(x) = C sin βx βx<br />
+ D cos<br />
a a ,<br />
⎪⎩<br />
F e αx/a + Ge −αx/a ,<br />
x = − a ψ, dψ/dx <br />
x < − a<br />
x < |a|<br />
x > a<br />
(2.22)<br />
Ae −α = − C sin β + D cos β , αAe −α = β (C cos β + D sin β) (2.23)<br />
<br />
x = a <br />
( )<br />
C α<br />
A = e−α β cos β − sin β ,<br />
( )<br />
D α<br />
A = e−α β sin β + cos β<br />
(2.24)<br />
C sin β + D cos β = F e α + Ge −α , β (C cos β − D sin β) = α ( F e α − Ge −α) (2.25)
2 1 30<br />
<br />
F<br />
((sin<br />
A = e−α<br />
β + β ) ( C<br />
2<br />
α cos β A + cos β − β ) ) D<br />
α sin β A<br />
(<br />
= e −2α sin β + β ) ( )<br />
α<br />
α cos β β cos β − sin β<br />
G<br />
A = eα 2<br />
(2.26)<br />
((sin β − β ) ( C<br />
α cos β A + cos β + β ) ) D<br />
α sin β = α2 + β 2<br />
cos β sin β (2.27)<br />
A αβ<br />
, − V 0 < E < 0 E x → − ∞ ψ(x) → 0 <br />
, E . F ≠ 0 x → ∞<br />
ψ(x) F = 0 (2.26) <br />
(sin β + β α cos β ) ( α<br />
β cos β − sin β )<br />
= 0<br />
(2.10), (2.16) E , <br />
E <br />
(2.10) (2.22) α/β = tan β (2.24) <br />
( )<br />
C α<br />
A = e−α β cos β − sin β = e −α( )<br />
tan β cos β − sin β = 0<br />
α = β tan β (2.27) <br />
, (2.22) <br />
( )<br />
D α<br />
A = e−α β sin β + cos β = e −α( )<br />
tan β sin β + cos β = e−α<br />
cos β<br />
G<br />
A = tan2 β + 1<br />
cos β sin β = 1<br />
tan β<br />
⎧<br />
⎪⎨ Ae −α|x|/a , |x| > a<br />
ψ(x) =<br />
⎪⎩ A e−α βx<br />
cos<br />
cos β a , |x| < a (2.28)<br />
ψ(x) = ψ(−x) x (2.13) x ≥ 0 <br />
, (2.16) , tan β = − β/α <br />
C<br />
)<br />
A = e−α( − cot β cos β − sin β = − e−α<br />
sin β<br />
D<br />
)<br />
A = e−α( − cot β sin β + cos β = 0<br />
G<br />
A = − cot2 β + 1<br />
cos β sin β = − 1<br />
cot β<br />
<br />
⎧<br />
⎪⎨<br />
ψ(x) =<br />
⎪⎩<br />
Ae αx/a ,<br />
− A e−α βx<br />
sin<br />
sin β a ,<br />
− Ae −αx/a ,<br />
x < − a<br />
|x| < a<br />
x > a<br />
(2.29)<br />
x (2.18) x ≥ 0
2 1 31<br />
(2.24), (2.26), (2.27) (2.22) , v 0 = 5<br />
β = β 0 (2.28) β β 0 <br />
(2.22) β/β 0 β β 0 <br />
, x → ∞ , 1 1 <br />
1 , 2 <br />
ψ(x)<br />
0.99 0.9999<br />
ψ(x)<br />
−a<br />
O<br />
a<br />
x<br />
−a<br />
O<br />
a<br />
x<br />
1.01 1.0001<br />
2.3<br />
<br />
V (x) v 0 , a <br />
V (x) = − 2 v<br />
(<br />
)<br />
0<br />
δ(x − a) + δ(x + a)<br />
2m<br />
(2.30)<br />
1. E <br />
<br />
av 0 q = − log |q − 1| , q = 2 v 0<br />
√<br />
− 2mE<br />
2 (2.31)<br />
2. (2.31) q q <br />
av 0 ≤ 1 1 , av 0 > 1 2 , <br />
3. a → 0 a → ∞ (2.21) u 0 = 2 v 0 /(2m) <br />
2.3 <br />
, m mg ( x ) <br />
x = 0 <br />
(− 2 d 2 )<br />
{<br />
2m dx 2 + V (x) ∞ , x < 0<br />
ψ(x) = E ψ(x) , V (x) =<br />
mgx , x > 0<br />
x ≤ 0 ψ(x) = 0, x → ∞ ψ(x) → 0 x > 0 <br />
(− d2<br />
dq 2 + 2m2 g<br />
2 α 3 q )<br />
ψ(q) = 2mE<br />
2 ψ(q) , q = αx<br />
α2 (2.32)
2 1 32<br />
α = ( 2m 2 g/ 2) 1/3<br />
<br />
( d<br />
2<br />
dq 2 − (q − ε) )<br />
ψ(q) = 0 ,<br />
ε = 2mE<br />
2 α 2 = E ( 2<br />
mg 2 2 ) 1/3<br />
(2.33)<br />
x = q − ε (15.100) , (Airy) <br />
ψ(q) = CAi(q − ε) + DBi(q − ε)<br />
(15.103) q → ∞ Bi(q − ε) D = 0 <br />
, q = 0 ψ(0) = CAi(− ε) = 0 , 277 <br />
a n Ai(x) ε = − a n , E <br />
( mg 2 2 ) 1/3 ( mg 2 2 ) 1/3<br />
E n = ε<br />
= − a n (2.34)<br />
2<br />
2<br />
0 > a 1 > a 2 > · · · 0 < E 1 < E 2 < · · · (15.102) a n <br />
<br />
2<br />
3 |a n| 3/2 + π ≈ nπ , n = 1, 2, 3, · · · (2.35)<br />
4<br />
E n ≈<br />
(<br />
9π 2 mg 2 2) 1/3<br />
2<br />
(<br />
n − 1 4) 2/3<br />
(2.36)<br />
ψ n (q) = CAi(q + a n ) Ai(q) − a n > 0 x <br />
<br />
Ai(z) z > l , ( l ∼ 3 ) Ai 2 (z) ≈ 0 ψ(q) = CAi(q + a n ) <br />
, q ≥ 0 , q + a n l <br />
<br />
q = αx =<br />
( 2m 2 ) 1/3 ( ) 1/3<br />
g<br />
2<br />
2 x , a n = −<br />
mg 2 2 E n<br />
0 ≤ x E ( )<br />
n<br />
<br />
2 1/3<br />
mg + ∆ , ∆ = 2m 2 l<br />
g<br />
, E = mv 2 /2 + mgx , mv 2 /2 = E − mgx ≥ 0 <br />
0 ≤ x ≤ E/mg<br />
() , , ∆ <br />
<br />
( )<br />
∆ <br />
2 1/3<br />
E n /mg = l<br />
2m 2 g E n /mg =<br />
, n E n /mg ∆ , n E n /mg ≫ ∆ , <br />
<br />
[ x , x + dx ] P cl (x) dx <br />
dt <br />
<br />
P cl (x) ∝ dt<br />
dx = 1 v = √ m<br />
2<br />
l<br />
− a n<br />
(E − mgx)−1/2<br />
P cl (x) = mg 1<br />
√ ,<br />
2E 1 − mgx/E<br />
<br />
∫ E/mg<br />
0<br />
P cl (x) dx = 1 (2.37)
2 1 33<br />
<br />
277 <br />
z = q + a n =<br />
( 2m 2 ) 1/3 (<br />
g<br />
2 x − E )<br />
n<br />
−1 , x E (<br />
n<br />
1 + 1 )<br />
mg<br />
mg a n<br />
<br />
ψ(q) = CAi(q + a n ) ≈ C sin ( 2<br />
3 |q + a n| 3/2 + π/4 )<br />
√ π |q + an | 1/4<br />
, <br />
C 2<br />
π | q + a n | −1/2 = C2<br />
π<br />
1<br />
√<br />
− an (1 − mgx/E n )<br />
n |ψ n | 2 , 1/ √ 1 − mgx/E n<br />
, n <br />
n = 2 n = 30 |ψ n | 2 P cl <br />
5<br />
|ψn| 2 × En/mg<br />
2<br />
1<br />
n = 2<br />
|ψn| 2 × En/mg<br />
4<br />
3<br />
2<br />
1<br />
n = 30<br />
0 5<br />
q<br />
0 5 10 15 20 25 30<br />
q<br />
mgx , ,<br />
, (2.34) ( Ultra cold neutron ) <br />
<br />
• Nature 415 (2002) 297<br />
http://www.nature.com/nature/journal/v415/n6869/full/415267a.html<br />
http://www.nature.com/nature/journal/v415/n6869/full/415297a.html<br />
• Physical Review D67 (2003) 102002<br />
http://prola.aps.org/abstract/PRD/v67/i10/e102002<br />
(2.36) E 1 ≈ 1.4 × 10 −12 eV ( 0.1 eV<br />
) <br />
, , <br />
(1.52) , <br />
V (x) (2.32) 3.4 <br />
2.4<br />
V (x) = mg|x| , E <br />
( mg 2 2 ) 1/3 [ ( 3π<br />
E ≈<br />
k + 1 2/3<br />
, k = 0, 1, 2, · · ·<br />
2 4 2)]<br />
k = 2n − 1 (2.36)
2 1 34<br />
2.4 <br />
<br />
d 2 ψ<br />
dx 2 + 2m ( )<br />
2 E − V (x) ψ(x) = 0<br />
, E <br />
ψ(x) λ , <br />
<br />
q = x λ ,<br />
, <br />
ε = 2mλ2 E<br />
2 , U(q) = 2mλ2<br />
2 V (x)<br />
d 2 ψ(q)<br />
( )<br />
dq 2 + ε − U(q) ψ(q) = 0 (2.38)<br />
, 2 3 , <br />
(2.38) ( 131 )<br />
q min ≤ q ≤ q max , <br />
0 ε , <br />
ψ(q) , , 1 ε <br />
<br />
, , <br />
1 ( , [] (<br />
) 1992 )ε <br />
ψ − (q, ε) : q = q min q <br />
ψ + (q, ε) : q = q max q <br />
ψ − (q, ε) ψ + (q, ε) <br />
q = q c , ( q min < q c < q max ) ψ − (q c , ε) ≠ ψ + (q c , ε) <br />
q = q c , <br />
φ − (q, ε) = ψ −(q, ε)<br />
ψ − (q c , ε) , φ +(q, ε) = ψ +(q, ε)<br />
ψ + (q c , ε)<br />
φ − (q c , ε) = φ + (q c , ε) = 1 q = q c , ε <br />
, φ ′ (q) q = q c <br />
φ ′ −(q c , ε) − φ ′ +(q c , ε) =<br />
W (ε)<br />
ψ − (q c , ε)ψ + (q c , ε)<br />
<br />
W (ε) = ψ ′ −(q c , ε) ψ + (q c , ε) − ψ − (q c , ε) ψ ′ +(q c , ε)<br />
, W (ε) = 0 , (2.2) W (ε) q c<br />
<br />
<br />
(2.38) Y 1 (q) = ψ(q) , Y 2 (q) = ψ ′ (q) 1 2 <br />
dY 1<br />
dq = Y 2 ,<br />
dY 2<br />
dq = (<br />
U(q) − ε ) Y 1
2 1 35<br />
, ( Runge–Kutta ) , (2.38)<br />
( Numerov ) q min ≤ q ≤ q max N q <br />
q k = q min + ∆q k , k = 0, 1, · · · , N q , ∆q = q max − q min<br />
N q<br />
q = q k f(q) f k = f(q k ) <br />
<br />
f k±1 = f(q k ± ∆q) = f k ± ∆qf k ′ + (∆q)2 f ′′<br />
2<br />
q = q k 2 <br />
(2.38) <br />
k ± (∆q)3<br />
3!<br />
f ′′′<br />
k<br />
+ (∆q)4 f k ′′′′ + · · ·<br />
4!<br />
f k+1 − 2f k + f k−1 = (∆q) 2 f ′′<br />
k + (∆q)4<br />
12 f ′′′′<br />
k + O ( (∆q) 6) (2.39)<br />
ψ ′′′′<br />
k<br />
f ′′<br />
k = f k+1 − 2f k + f k−1<br />
h 2 + O((∆q) 2 ) (2.40)<br />
= d2 F (q)ψ(q)<br />
dq 2 ∣<br />
∣∣∣q=qk<br />
, F (q) = U(q) − ε<br />
, 2 f(q) = F (q)ψ(q) (2.40) <br />
ψ ′′′′<br />
k<br />
= F k+1ψ k+1 − 2F k ψ k + F k−1 ψ k−1<br />
(∆q) 2 + O((∆q) 2 )<br />
ψ ′′<br />
k = F kψ k (2.39) <br />
ψ k+1 − 2ψ k + ψ k−1 = (∆q) 2 ψ ′′<br />
k + (∆q)4<br />
12 ψ′′′′ k + O((∆q) 6 )<br />
= (∆q) 2 F k ψ k + (∆q)2<br />
12<br />
D q = (∆q) 2 /12 <br />
)<br />
)<br />
(1 − D q F k+1 ψ k+1 − 2<br />
(1 + 5D q F k ψ k +<br />
k k − 1 <br />
(F k+1 ψ k+1 − 2F k ψ k + F k−1 ψ k−1<br />
)<br />
+ O((∆q) 6 )<br />
(1 − D q F k−1<br />
)<br />
ψ k−1 = O((∆q) 6 ) (2.41)<br />
ψ k ≈ 2 (1 + 5D qF k−1 ) ψ k−1 − (1 − D q F k−2 ) ψ k−2<br />
1 − D q F k<br />
, k = 2, 3, · · · (2.42)<br />
ψ 0 ψ 1 k = 2, 3, · · · ψ 2 , ψ 3 , · · · ψ − <br />
, ψ Nq , ψ Nq−1 <br />
ψ k ≈ 2 (1 + 5D qF k+1 ) ψ k+1 − (1 − D q F k+2 ) ψ k+2<br />
1 − D q F k<br />
, k = N q − 2, N q − 3, · · · (2.43)<br />
k ψ Nq−2, ψ Nq−3, · · · ψ + <br />
, W (ε) ψ ′ (q) , (2.40) <br />
ψ ′ k = ψ k+1 − ψ k−1<br />
2∆q<br />
+ O((∆q) 2 )<br />
<br />
ψ ′ k = 8(ψ k+1 − ψ k−1 ) − ψ k+2 + ψ k−2<br />
12∆q<br />
+ O((∆q) 4 ) (2.44)
2 1 36<br />
(2.44) <br />
<br />
ψ ± (q) , <br />
ψ 0 = ψ − (q min ) , ψ 1 = ψ − (q min + ∆q) , ψ Nq −1 = ψ + (q max − ∆q) , ψ Nq = ψ + (q max )<br />
<br />
• − ∞ < q < ∞ ψ(q) q→±∞<br />
−−−−−→ 0 <br />
q min , q max ψ(q min ) ≈ 0, ψ(q max ) ≈ 0 ( , <br />
)<br />
ψ 0 = ψ Nq = 0 , ψ 1 = ψ Nq −1 = ≠ 0 (2.45)<br />
, <br />
q → ± ∞ U(q) → 0 ψ ′′ (q) = − ε ψ(q) <br />
ψ(q) → e ±√ −ε q <br />
ψ 0 = e √ −ε q min<br />
,<br />
ψ 1 = e √ −ε (q min+∆q)<br />
(2.46)<br />
ψ Nq = e −√ −ε q max<br />
, ψ Nq −1 = e −√ −ε (q max −∆q)<br />
(2.47)<br />
q c q c = 0 <br />
• 0 ≤ q < ∞ ψ(0) = 0 , ψ(q) q→∞<br />
−−−−→ 0 <br />
q min = 0 (2.45) q = q max (2.47) x ≈ λ , q c ≈ 1<br />
<br />
<br />
<br />
W (ε) , W (ε) = 0 <br />
ε 2 ε min < ε < ε max<br />
, N e <br />
ε i = ε min + i ∆ε , i = 0, 1, · · · , N e , ∆ε = ε max − ε min<br />
N e<br />
W (ε) , W (ε i )W (ε i+1 ) < 0 ε i < ε < ε i+1 W (ε) = 0 <br />
ε ε i ε i+1 ( <br />
)N e , ε min < ε < ε max <br />
, <br />
W (ε) <br />
Y (ε) = φ ′ −q c , ε) − φ ′ +q c , ε) = ψ′ −(q c , ε)<br />
ψ − (q c , ε) − ψ′ +(q c , ε)<br />
ψ + (q c , ε) = 0<br />
, q c ψ + (q c , ε c ) = 0 ψ − (q c , ε c ) = 0 <br />
ε = ε c Y (ε c ) ε ε c , ψ(q c , ε)<br />
ψ ′ (q c , ε) , Y (ε) , <br />
, ,
2 1 37<br />
, q c = 0 Y (ε) = 0<br />
, q c <br />
C <br />
• <br />
<strong>qm</strong>in = q min , <strong>qm</strong>ax = q max , dq = ∆q , nq = N q , nc = q c − q min<br />
∆q<br />
wf[k] = ψ k , pot[k] = U(q k )<br />
main , W (ε) <br />
wf pot N q +1 U(q k ) <br />
, nc<br />
k = nc q k q c <br />
• double wronski( double ee )<br />
ε W (ε) <br />
(2.45) for (2.42)<br />
wf[k] = ψ − k ψ − ′ (2.44) k = nc + 2 <br />
for (2.43) wf[k] = ψ + k for <br />
ψ − ψ + k ≤ nc − 1 wf[k] = ψ − k , k ≥ nc <br />
wf[k] = ψ + k , k ≤ nc − 1 <br />
<br />
wf[k] ⇐ C wf[k] ,<br />
• double get_eigen( double e1, double e2 )<br />
C = ψ + nc<br />
= wf[nc]<br />
ψ − nc wf1<br />
2 ε = e1, e2 , W (ε) = 0 <br />
|1 − e1/e2| < = 10 −6 <br />
#include <br />
#include <br />
double potential( double q );<br />
double wronski( double ee );<br />
double get_eigen( double e1, double e2 );<br />
double wf[ ... ], pot[ ... ], <strong>qm</strong>in, <strong>qm</strong>ax, dq;<br />
int nc, nq;<br />
int main()<br />
{<br />
double emin, emax, de, ee, w1, w2, qc;<br />
int i, ne;<br />
<strong>qm</strong>in = ... ; <strong>qm</strong>ax = ... ; qc = ... ; dq = ... ;<br />
nq=(<strong>qm</strong>ax-<strong>qm</strong>in)/dq;<br />
nc=(qc-<strong>qm</strong>in)/dq;<br />
<strong>qm</strong>ax=<strong>qm</strong>in+nq*dq; qc=<strong>qm</strong>in+nc*dq;<br />
for(i=0; i
2 1 38<br />
}<br />
ee=emin+de*i;<br />
w2=wronski( ee );<br />
if( w1*w2
2 1 39<br />
}<br />
if( w1*w3 > 0 ){<br />
w1=w3; e1=e3;<br />
} else {<br />
w2=w3; e2=e3;<br />
}<br />
}<br />
return e1;<br />
2.5 ( U 0 )<br />
1. U(q) = q 2 2. U(q) = U 0<br />
(<br />
e −2q − 2e −q) 3. U(q) = −<br />
U 0<br />
(cosh q) 2<br />
, ε , q min , q max <br />
q cl , ( U(q cl ) − ε = 0 ) 2 , U 0 ≈ 20 , q max , − q min ≈ 4 ,<br />
∆q ≈ 0.1 ψ k = wf[k] <br />
<br />
S =<br />
∫ <strong>qm</strong>ax<br />
q min<br />
( ψ<br />
2<br />
ψ 2 0 + ψN 2<br />
(q) dq ≈ ∆q<br />
q<br />
2<br />
ψ k / √ S ψ k <br />
N q −1<br />
∑<br />
+ ψk<br />
2<br />
k=1<br />
(2.38) n <br />
1. ε n = 2n + 1 , n = 0, 1, 2, · · ·<br />
(<br />
2. ε n = − n + 1 2 − √ ) 2<br />
U 0 , 0 ≤ n < √ U 0 − 1 2<br />
3. ε n = −<br />
(n + 1 2 − √<br />
U 0 + 1 4<br />
) 2<br />
, 0 ≤ n <<br />
√<br />
)<br />
U 0 + 1 4 − 1 2<br />
1. 2. ( Morse ) <br />
2. , 3. 1 () 87 <br />
<br />
<br />
<br />
<br />
ε<br />
<br />
ε 0 = − 15.7779 , ε 1 = − 8.8336<br />
ε 2 = − 3.8893 , ε 3 = − 0.9450<br />
n = 2 , 3 q max <br />
, <br />
ε = − 14.8, ε = − 13.8 <br />
q c = 0 ψ ′ <br />
, ε ε 0 <br />
<br />
1<br />
0<br />
−15.7779<br />
−8.8336 −3.8839 −0.5924<br />
U 0 = 20<br />
q min = −1.6<br />
q max = 4.0<br />
∆q = 0.05<br />
0 2 4<br />
q
3 1 40<br />
3 1 <br />
3.1 <br />
1 V (x) , <br />
, <br />
, , <br />
<br />
(− 2 d 2 )<br />
2m dx 2 + V (x) ψ(x) = E ψ(x)<br />
, ψ(x) x→±∞<br />
−−−−−→ 0 , <br />
<br />
, (1.4) () <br />
(1.5) 1 <br />
<br />
ρ(x, t) = |ψ(x, t)| 2<br />
j(x, t) =<br />
<br />
2im<br />
∂ρ(x, t)<br />
∂t<br />
+<br />
∂j(x, t)<br />
∂x<br />
= 0 (3.1)<br />
(<br />
)<br />
ψ ∗ ∂ψ(x, t)<br />
(x, t) − ψ(x, t) ∂ψ∗ (x, t)<br />
= (<br />
∂x<br />
∂x m Im ψ ∗ (x, t)<br />
D = [x 1 , x 2 ] <br />
∫<br />
d<br />
x2<br />
dt P 12(t) = j(x 1 , t) − j(x 2 , t) , P 12 (t) = dx ρ(x, t)<br />
x 1<br />
)<br />
∂ψ(x, t)<br />
∂x<br />
D P 12 , D x = x 1 D j(x 1 , t)<br />
x = x 2 D j(x 2 , t) , j(x, t) <br />
x ψ(x, t) = e −iEt/ ψ(x) , ρ(x, t), j(x, t) <br />
<br />
x → − ∞ x x → − ∞<br />
ψ(x) <br />
ψ(x) = + <br />
x → + ∞ <br />
ψ(x) = x <br />
x → ± ∞ V (x) <br />
<br />
V (x) x→−∞<br />
−−−−−→ V − ,<br />
V (x) x→+∞<br />
−−−−→ V +<br />
, E V − = 0 <br />
x → − ∞ , <br />
− 2 d 2 ψ<br />
2m dx 2 = Eψ
3 1 41<br />
E < 0 κ = √ −2mE/ 2 ψ ′′ = κ 2 ψ A, B <br />
ψ(x) = Ae κx + Be −κx<br />
x → − ∞ ψ B = 0 ψ(x) = Ae κx → 0 , <br />
, E > 0 <br />
√<br />
2mE<br />
ψ(x) = Ae ikx + Be −ikx , k =<br />
ψ(x) ψ I (x) ψ R (x)<br />
2<br />
ψ I (x) x→−∞<br />
−−−−−→ Ae ikx ,<br />
ψ R (x) x→−∞<br />
−−−−−→ Be −ikx<br />
, x → − ∞ <br />
J I = (<br />
m Im ψI ∗ (x) dψ )∣<br />
I(x) ∣∣∣x=−∞<br />
, J R = (<br />
dx<br />
m Im ψR(x) ∗ dψ )∣<br />
R(x) ∣∣∣x=−∞<br />
dx<br />
<br />
J I = k m |A|2 ,<br />
J R = − k m |B|2<br />
, ψ I |ψ I (x)| 2<br />
x→−∞<br />
−−−−−→ |A| 2 , ψ I (x) <br />
|A| 2 , k/m x ,<br />
ψ R (x → −∞) k/m x ψ I (x) , ψ R (x)<br />
E > 0 <br />
x → ∞ <br />
− 2 d 2 ψ<br />
2m dx 2 = (E − V +) ψ<br />
E < V + ( E > 0 V + > 0 )<br />
√<br />
ψ(x) = Ce −κ′x , κ ′ 2m(V+ − E)<br />
=<br />
x → ∞ ψ(x) → 0 x → ∞ , E > V +<br />
<br />
ψ(x) = Ce ik′x + De −ik′x , k ′ =<br />
2<br />
√<br />
2m(E − V+ )<br />
x → ∞ x <br />
D = 0 , <br />
⎧<br />
Ae ⎪⎨<br />
ikx + Be −ikx , x → − ∞<br />
ψ(x) → Ce −κ′x , x → ∞ , E < V + , ( V + > 0 )<br />
(3.2)<br />
⎪⎩<br />
Ce ik′x , x → ∞ , E > V +<br />
E , <br />
E > V − = 0 E <br />
(3.2) |ψ(x)| x → − ∞ 0 <br />
∫ ∞<br />
−∞<br />
dx |ψ(x)| 2<br />
2
3 1 42<br />
, , <br />
, <br />
x → ∞ <br />
J T = (<br />
m Im ψ ∗ (x) dψ(x) )∣<br />
∣∣∣x=∞<br />
dx<br />
, R T <br />
∣ R =<br />
J R ∣∣∣<br />
∣ , T =<br />
J I<br />
1 , <br />
∣<br />
∣<br />
J T ∣∣∣<br />
J I<br />
, (3.2) <br />
⎧<br />
⎪⎨ 0 , E < V + , ( V + > 0 )<br />
J T = k ⎪⎩<br />
′<br />
m |C|2 , E > V +<br />
<br />
R =<br />
B<br />
∣ A ∣<br />
2<br />
⎧<br />
⎪⎨ 0 , E < V +<br />
, T =<br />
k ⎪⎩<br />
′ 2<br />
C<br />
k ∣ A ∣ , E > V +<br />
A, B, C , <br />
ψ(x, t) = e −iEt/ ψ(x) , ρ(x, t) j(x, t) , (3.1) <br />
dj(x)/dx = 0 j(x) = x → −∞ <br />
j(x) = m Im [ (Ae ikx + Be −ikx) ∗<br />
d (<br />
Ae ikx + Be −ikx)]<br />
dx<br />
= ( [ik<br />
m Im |A| 2 − |B| 2) − 2k Im ( AB ∗ e 2ikx)] = k m<br />
(<br />
|A| 2 − |B| 2) (3.3)<br />
, x → ∞ j(x) = J T <br />
0 < E < V + |A| 2 − |B| 2 = 0 , ∴ R = 1 , T = 0<br />
(<br />
V + < E k |A| 2 − |B| 2) = k ′ |C| 2 , ∴ R + T = 1<br />
R + T = 1 <br />
<br />
3.2 <br />
V (x) V 0 <br />
⎧<br />
⎨ 0 , x < 0<br />
V (x) =<br />
⎩ V 0 , x > 0<br />
(3.4)<br />
V (x)<br />
V 0<br />
E E > 0 <br />
x < 0 <br />
O<br />
x<br />
ψ(x) = Ae ikx + Be −ikx , k =<br />
√<br />
2mE<br />
2 (3.5)
3 1 43<br />
x > 0 <br />
E V 0 <br />
E > V 0 <br />
(3.6) (3.2) <br />
− 2 d 2 ψ<br />
2m dx 2 = (E − V 0) ψ (3.6)<br />
ψ(x) = Ce ik′x , k ′ =<br />
x = 0 ψ(x) ψ ′ (x) (3.5), (3.7) <br />
√<br />
2m(E − V0 )<br />
2 (3.7)<br />
A + B = C ,<br />
k(A − B) = k ′ C<br />
<br />
R T <br />
R =<br />
B<br />
∣ A ∣<br />
T = k′<br />
k<br />
2<br />
B<br />
A = k − k′<br />
k + k ′ ,<br />
=<br />
C<br />
A = 2k<br />
k + k ′ (3.8)<br />
( ) k − k<br />
′ 2<br />
(√ √ ) 2<br />
E − E − V0<br />
k + k ′ = √ √ (3.9)<br />
E + E − V0<br />
2 C<br />
∣ A ∣ = 4kk′<br />
(k + k ′ ) 2 = 4 √ E(E − V 0 )<br />
( √E √ ) 2<br />
(3.10)<br />
+ E − V0<br />
R + T = 1 <br />
E > V 0 , , <br />
V 0 > 0 z = E/V 0 − 1 > 0 <br />
R =<br />
(√ z + 1 −<br />
√ z<br />
√ z + 1 +<br />
√ z<br />
) 2<br />
= (√ z + 1 − √ z ) 4<br />
=<br />
⎧<br />
⎨<br />
⎩<br />
1 − 4 √ z + · · · , z ≈ 0<br />
1<br />
16z 2 + · · · , z ≫ 1<br />
E ≈ V 0 R ≈ 1 , , E ≫ V 0 R ≈ 0 <br />
<br />
E < V 0 <br />
(3.6) (3.2) <br />
ψ(x) = Ce −κ′x , κ ′ =<br />
x = 0 A + B = C , ik (A − B) = − κ ′ C <br />
√<br />
2m(V0 − E)<br />
2 (3.11)<br />
B<br />
A = k − iκ′<br />
k + iκ ′ ,<br />
C<br />
A = 2k<br />
∣ ∣ ∣∣∣<br />
k + iκ ′ , R = k − iκ ′ ∣∣∣<br />
2<br />
k + iκ ′ = 1 (3.12)<br />
x > 0 j(x) = 0 T = 0 R +T = 1 , x < 0<br />
j(x) |A| = |B| (3.3) j(x) = 0 , (3.11) (3.12) <br />
(3.7), (3.8) <br />
k ′ =<br />
√<br />
− 2m(V 0 − E)<br />
2 = iκ ′
3 1 44<br />
<br />
, , <br />
, E − V (x) ≥ 0 x , E < V 0 x > 0 <br />
, x > 0 <br />
ψ(x) = Ce −κ′x = A<br />
2k<br />
k + iκ ′ e−κ′x ≠ 0 (3.13)<br />
, x > 0 <br />
V 0 < 0 E > 0 > V 0 , R T (3.9), (3.10) <br />
, T = 1, R = 0 T (E) <br />
1.0<br />
0.8<br />
T<br />
0.6<br />
V 0 < 0 <br />
V 0 > 0 <br />
0.4<br />
0.2<br />
0 1 2<br />
E/|V 0 |<br />
3.3 <br />
V 0 , a <br />
⎧<br />
⎨ 0 , |x| > a<br />
V (x) =<br />
⎩ V 0 , |x| < a<br />
V (x)<br />
V 0<br />
|x| > a V = 0 <br />
(3.2) <br />
⎧<br />
⎨ Ae ikx + Be −ikx ,<br />
ψ(x) =<br />
⎩ Ce ikx ,<br />
x < − a<br />
x > a<br />
−a<br />
O<br />
a<br />
x<br />
<br />
E > V 0 <br />
|x| < a <br />
√<br />
d 2 ψ<br />
2m(E −<br />
dx 2 = − k′2 ψ(x) , k ′ V0 )<br />
=<br />
2<br />
F , G <br />
⎧<br />
Ae<br />
⎪⎨<br />
ikx + Be −ikx , x < − a<br />
ψ(x) = F e ik′x + Ge −ik′x , |x| < a<br />
⎪⎩<br />
Ce ikx ,<br />
x > a<br />
(3.14)
3 1 45<br />
x = − a x = a <br />
Ae −ika + Be ika = F e −ik′a + Ge ik′a , k ( Ae −ika − Be ika) ( ) = k ′ F e −ik′a − Ge ik′ a<br />
(3.15)<br />
F e ik′a + Ge −ik′a = Ce ika , ( ) k ′ F e ik′a − Ge −ik′ a<br />
= kCe ika (3.16)<br />
(3.16) <br />
(3.15) <br />
F<br />
A = k′ + k<br />
2k ′ e i(k−k′ )a C A , G<br />
A = k′ − k<br />
2k ′ e i(k+k′ )a C A<br />
(3.17)<br />
<br />
R =<br />
B<br />
∣ A ∣<br />
T =<br />
C<br />
∣ A ∣<br />
R + T = 1 <br />
<br />
2<br />
2<br />
B<br />
A = i ( k ′2 − k 2) sin(2ak ′ )<br />
2kk ′ cos(2ak ′ ) − i (k ′2 + k 2 ) sin(2ak ′ ) e−2iak (3.18)<br />
C<br />
A = 2kk ′<br />
2kk ′ cos(2ak ′ ) − i (k ′2 + k 2 ) sin(2ak ′ ) e−2iak (3.19)<br />
(<br />
k ′2 − k 2) 2<br />
sin 2 (2ak ′ )<br />
=<br />
4k 2 k ′2 cos 2 (2ak ′ ) + (k ′2 + k 2 ) 2 sin 2 (2ak ′ )<br />
(<br />
k ′2 − k 2) 2<br />
sin 2 (2ak ′ )<br />
=<br />
4k 2 k ′2 + (k ′2 − k 2 ) 2 sin 2 (2ak ′ ) = V0 2 sin 2 (2ak ′ )<br />
4E(E − V 0 ) + V0 2 sin2 (2ak ′ )<br />
=<br />
4k 2 k ′2<br />
4k 2 k ′2 + (k ′2 − k 2 ) 2 sin 2 (2ak ′ ) = 4E(E − V 0 )<br />
4E(E − V 0 ) + V0 2 sin2 (2ak ′ )<br />
ε = (2a) 2 2mE<br />
2 , v 0 = (2a) 2 2mV 0<br />
2<br />
R =<br />
v 2 0 sin 2 ( √ ε − v 0 )<br />
4ε(ε − v 0 ) + v 2 0 sin2 ( √ ε − v 0 ) , T = 4ε(ε − v 0 )<br />
4ε(ε − v 0 ) + v 2 0 sin2 ( √ ε − v 0 )<br />
(3.20)<br />
<br />
, E > V 0 E ≈ V 0 , ( ε ≈ v 0 ) <br />
sin 2 ( √ ε − v 0 ) ≈ ε − v 0<br />
<br />
v 2<br />
R ≈<br />
0(ε − v 0 )<br />
4ε(ε − v 0 ) + v0 2(ε − v 0) = v2 0<br />
4ε<br />
, T ≈<br />
+ 4ε v0 2 + 4ε (3.21)<br />
E V 0 T <br />
sin( √ ε − v 0 ) = 0 , √ ε − v 0 = 2ak ′ = nπ , n = 1, 2, 3, · · · (3.22)<br />
E T = 1 ( n = 0 T 0/0 <br />
, (3.21) ε = v 0 ) |x| < a <br />
ψ(x) = F e inπx/2a + Ge −inπx/2a<br />
v 2 0
3 1 46<br />
ψ(a) = (−1) n ψ(− a) , x < − a x > a <br />
(−1) n , <br />
T = 1 ε − v 0 = (nπ) 2 ε − v 0 = (nπ) 2 + x <br />
<br />
T =<br />
v 2 0 sin 2 ( √ ε − v 0 )<br />
4ε(ε − v 0 )<br />
=<br />
v 2 0(x/2nπ) 2<br />
4(v 0 + (nπ) 2 )(nπ) 2 + O(x3 )<br />
(<br />
1 + v2 0 sin 2 ( √ ) −1<br />
ε − v 0 )<br />
1<br />
≈<br />
4ε(ε − v 0 ) 1 + x 2 /Γ 2 , Γ = (2nπ)2 √<br />
v0 + (nπ)<br />
v 2 (3.23)<br />
0<br />
, Γ , v 0 , T x = 0 Γ <br />
<br />
0 ≤ sin 2 ( √ ε − v 0 ) ≤ 1 <br />
T min ≤ T ≤ 1 , T min = 4ε(ε − v 0)<br />
4ε(ε − v 0 ) + v 2 0<br />
( ) 2 v0<br />
= 1 −<br />
2ε − v 0<br />
T 1 T min v 0 T min (ε) <br />
E ≫ V 0 T ≈ 1 <br />
0 < E < V 0 <br />
|x| < a <br />
√<br />
d 2 ψ<br />
dx 2 = κ′2 ψ(x) , κ ′ 2m(V0 − E)<br />
=<br />
2<br />
E > V 0 k ′ iκ ′ − iκ ′ k ′ → iκ ′ <br />
|x| < a <br />
<br />
ψ(x) = F e −κ′x + Ge κ′ x<br />
cos(2ak ′ ) → cos(2iaκ ′ ) = cosh(2aκ ′ ) , sin(2ak ′ ) → sin(2iaκ ′ ) = i sinh(2aκ ′ )<br />
(3.18), (3.19) <br />
(3.17) <br />
(<br />
B<br />
κ ′2<br />
A = + k 2) sinh(2aκ ′ )<br />
2ikκ ′ cosh(2aκ ′ ) − (κ ′2 − k 2 ) sinh(2aκ ′ ) e−2iak<br />
C<br />
A = 2ikκ ′<br />
2ikκ ′ cosh(2aκ ′ ) − (κ ′2 − k 2 ) sinh(2aκ ′ ) e−2iak<br />
(3.24)<br />
<br />
R =<br />
B<br />
∣ A ∣<br />
T =<br />
C<br />
∣ A ∣<br />
2<br />
2<br />
=<br />
=<br />
F<br />
A = κ′ − ik<br />
2κ ′ e (ik+κ′ )a C A , G<br />
A = κ′ + ik<br />
2κ ′ e (ik−κ′ )a C A<br />
(κ ′2 + k 2 ) 2 sinh 2 (2aκ ′ )<br />
4κ ′2 k 2 + (κ ′2 + k 2 ) 2 sinh 2 (2aκ ′ ) = v0 2 sinh 2 ( √ v 0 − ε )<br />
4ε(v 0 − ε) + v0 2 sinh2 ( √ v 0 − ε )<br />
4κ ′2 k 2<br />
4κ ′2 k 2 + (κ ′2 + k 2 ) 2 sinh 2 (2aκ ′ ) = 4ε(v 0 − ε)<br />
4ε(v 0 − ε) + v 2 0 sinh2 ( √ v 0 − ε )<br />
(3.25)<br />
(3.26)<br />
(3.27)
3 1 47<br />
E < V 0 , |x| < a <br />
, x > a , , E <br />
x > a , <br />
ε ≈ v 0 , (3.21) ε = v 0 <br />
T = 4<br />
1<br />
=<br />
4 + v 0 1 + 2ma 2 V 0 / 2<br />
, , x ≫ 1 <br />
sinh x = (e x − e −x )/2 ≈ e x /2 , v 0 − ε ≫ 1 <br />
T ≈<br />
<br />
4ε(v 0 − ε)<br />
4ε(v 0 − ε) + v0 2 exp (2√ v 0 − ε ) /4 ≈ 16 ε(v 0 − ε)<br />
v0<br />
2<br />
exp ( −2 √ v 0 − ε )<br />
v 0 = 20 (3.20), (3.27) T ε <br />
T min <br />
⎧<br />
⎨ 0 , 0 < E < V 0<br />
T =<br />
⎩ 1 , E > V 0<br />
, T = 1 (3.22) ε ε = 29.87, 59.48, 108.83, · · · <br />
1.0<br />
0.8<br />
T<br />
0.6<br />
0.4<br />
0.2<br />
0 20 40 60 80 100<br />
ε<br />
T 1 T min , v 0 ε − v 0 <br />
v 0 = 2000 T (3.23) , ε = v 0 + (nπ) 2 ,<br />
T ε ≈ v 0 + (nπ) 2 , <br />
<br />
1.0<br />
0.8<br />
T<br />
0.6<br />
0.4<br />
0.2<br />
2000 2020 2040 2060 2080 2100<br />
ε
3 1 48<br />
3.1<br />
(3.3) , (3.14) <br />
)<br />
k<br />
(|A|<br />
⎧⎪ 2 − |B| 2 , x < −a<br />
j(x) = ⎨<br />
m × ( )<br />
k ′ |F | 2 − |G| 2 , |x| < a<br />
⎪ ⎩<br />
k|C| 2 ,<br />
x > a<br />
0 < E < V 0 , |x| < a <br />
2<br />
m κ′ Im (F ∗ G)<br />
, j(x) <br />
3.4 <br />
<br />
⎧<br />
⎨ 0 , |x| > a<br />
V (x) =<br />
⎩ − V 0 , |x| < a , a <br />
−a<br />
V (x)<br />
−V 0<br />
a<br />
x<br />
V 0 <br />
, (3.14) ∼ (3.19) <br />
k =<br />
√<br />
2mE<br />
2 , k ′ =<br />
√<br />
2m(E + V0 )<br />
2<br />
k ′ (3.20) v 0 → − v 0<br />
<br />
R =<br />
v0 2 sin 2 ( √ ε + v 0 )<br />
4ε(ε + v 0 ) + v0 2 sin2 ( √ ε + v 0 ) , T = 4ε(ε + v 0 )<br />
4ε(ε + v 0 ) + v0 2 sin2 ( √ ε + v 0 )<br />
(3.28)<br />
n <br />
√ ε + v0 = 2ak ′ = nπ , nπ > √ v 0<br />
ε T = 1 <br />
T min ≤ T ≤ 1 ,<br />
( ) 2 v0<br />
T min = 1 −<br />
2ε + v 0<br />
v 0 = 20 T (ε) T min <br />
1.0<br />
0.8<br />
T<br />
0.6<br />
0.4<br />
0.2<br />
0 20 40 60 80 100<br />
ε
3 1 49<br />
, (3.14) ∼<br />
(3.19) E > 0 , − V 0 < E < 0 k = √ 2mE/ 2 <br />
, E < 0 κ = √ − 2mE/ 2 k iκ <br />
, (3.14) <br />
<br />
B/A, C/A <br />
⎧<br />
Ae ⎪⎨<br />
−κx + Be κx ,<br />
ψ(x) = F e ik′x + Ge −ik′x ,<br />
⎪⎩<br />
Ce −κx ,<br />
x < − a<br />
|x| < a<br />
x > a<br />
(<br />
B<br />
k ′2<br />
A = + κ 2) sin(2ak ′ )<br />
2κk ′ cos(2ak ′ ) − (k ′2 − κ 2 ) sin(2ak ′ ) e2aκ<br />
C<br />
A = 2κk ′<br />
2κk ′ cos(2ak ′ ) − (k ′2 − κ 2 ) sin(2ak ′ ) e2aκ<br />
F<br />
A = k′ + iκ<br />
2k ′ e −(ik′ +κ)a C A , G<br />
A = k′ − iκ<br />
2k ′ e (ik′ −κ)a C ( F<br />
A = A<br />
f = 2κk ′ cos(2ak ′ ) − ( k ′2 − κ 2) sin(2ak ′ )<br />
(2.8) α, β κ = aα , k ′ = aβ <br />
f = 2a 2( αβ ( cos 2 β − sin 2 β ) − ( β 2 − α 2) )<br />
sin β cos β<br />
= 2a 2( )(<br />
)<br />
α cos β − β sin β α sin β + β cos β<br />
) ∗<br />
(3.29)<br />
f = 0 E (2.10), (2.16) <br />
E (3.29) x → ± ∞ ψ(x) → 0<br />
A = 0, B/A → ∞ <br />
, B/A E , <br />
, <br />
3.2<br />
(2.30) , R T <br />
R =<br />
B<br />
∣ A ∣<br />
2<br />
= 1 − T , T =<br />
C<br />
∣ A ∣<br />
2<br />
=<br />
k 2 + v0<br />
2<br />
k 2<br />
(<br />
cos 2ka − v 0<br />
2k sin 2ka ) 2<br />
, B/A, C/A E (2.31) <br />
3.5 <br />
, , <br />
<br />
∂ψ(x, t)<br />
i =<br />
(− 2<br />
∂t 2m<br />
∂ 2 )<br />
∂x 2 + V (x)<br />
ψ(x, t) (3.30)
3 1 50<br />
, , <br />
, <br />
V (x) = 0 <br />
A exp(ikx − iω k t) + B exp(−ikx − iω k t) ,<br />
ω k = k2<br />
2m<br />
(3.31)<br />
(3.30) k > 0 B/A k <br />
, <br />
B<br />
A = √ R k e iθ k<br />
R k , E < V 0 , (3.12) <br />
<br />
−1 κ′<br />
R k = 1 , θ k = − 2 tan<br />
k , κ′ =<br />
(3.31) A (3.30) , <br />
ψ(x, t) = ψ I (x, t) + ψ R (x, t)<br />
(3.30) <br />
ψ I (x, t) =<br />
ψ R (x, t) =<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
dk A(k) exp(ikx − iω k t)<br />
dk B(k) exp(−ikx − iω k t) =<br />
∫ ∞<br />
0<br />
√<br />
2mV0<br />
2 − k 2 (3.32)<br />
dk √ R k A(k) exp(iθ k − ikx − iω k t)<br />
ψ I (x, t) , ψ R (x, t) A(k) k = k 0 , <br />
k = k 0 , A(k) k = k 0 k − k 0 <br />
2 <br />
ω k ≈ ω 0 + (k − k 0 )v 0 , ω 0 = ω k0 , v 0 = dω k<br />
dk<br />
kx − ω k t ≈ k(x − v 0 t) + (k 0 v 0 − ω 0 )t <br />
<br />
<br />
0<br />
∣ = k 0<br />
k=k0<br />
m<br />
(<br />
) ∫ ∞<br />
( )<br />
ψ I (x, t) ≈ exp i(k 0 v 0 − ω 0 )t dk A(k) exp ik(x − v 0 t)<br />
(<br />
)<br />
= exp i(k 0 v 0 − ω 0 )t ϕ(x − v 0 t) (3.33)<br />
ϕ(x) = ψ I (x, 0 ) =<br />
∫ ∞<br />
0<br />
dk A(k) e ikx<br />
θ k ≈ θ 0 + (k − k 0 ) γ , θ 0 = θ k0 , γ = dθ k<br />
dk<br />
∣<br />
∣<br />
k=k0<br />
<br />
(<br />
ψ R (x, t) ≈ exp i(θ 0 − γk 0 ) + i(v 0 k 0 − ω 0 )t) ∫ dk √ (<br />
)<br />
R k A(k) exp ik(−x − v 0 t + γ)<br />
(<br />
√<br />
≈ exp i(θ 0 − γk 0 ) + i(v 0 k 0 − ω 0 )t)<br />
R0 ϕ(− x − v 0 t + γ) (3.34)
3 1 51<br />
√ R k k A(k) R k ≈ R 0 = R k0 <br />
(3.33) v 0 x , (3.34) <br />
x = −v 0 t + γ , γ (3.32) <br />
γ = dθ k<br />
dk ∣ = 2 √<br />
k=k0<br />
κ ′ , κ ′ 2mV0<br />
0 =<br />
0<br />
2 − k0<br />
2<br />
E 0 < V 0 x > 0 (3.13) x > 0<br />
e −κ′x , e −κ′x ∼ e −1 , x r ∼ 1/κ ′ <br />
x ∼ x r γ ∼ 2x r <br />
<br />
|ψ(x, t)| 2 = |ψ I (x, t) + ψ R (x, t)| 2<br />
≈ |ϕ(x − v 0 t)| 2 + R 0 |ϕ(−x − v 0 t + γ)| 2<br />
+ 2 √ R 0 Re<br />
(ϕ )<br />
∗ (x − v 0 t) ϕ(−x − v 0 t + γ) e i(θ 0−γk 0 )<br />
, 3 , <br />
, f(x) ϕ(x) = e ik0x f(x) <br />
(<br />
)<br />
Re ϕ ∗ (x − v 0 t) ϕ(−x − v 0 t + γ) e i(θ 0−γk 0 )<br />
= f(x − v 0 t) f(−x − v 0 t + γ) cos (2k 0 x − θ 0 )<br />
, cos (2k 0 x − θ 0 ) π/k 0 f(x) , <br />
|ψ(x, t)| 2 π/k 0 <br />
, (3.30) , <br />
, |ψ(x, t)| 2 <br />
• , <br />
, <br />
, (3.33), (3.34) |ϕ(x)|<br />
, (1.50) <br />
, (k − k 0 ) 2
3 1 52<br />
3.6 <br />
t = 0 ψ(x, 0) , <br />
t = t max ψ(x, t) ( , ( ) 7.5 )x <br />
x min ≤ x ≤ x max , ψ(x min , t) = ψ(x max , t) = 0 <br />
x min , x max ψ(x, t) 0 λ <br />
<br />
(3.30) <br />
q = x λ , τ = <br />
2mλ 2 t<br />
i ∂ ψ(q, τ) = Hψ(q, τ) ,<br />
∂τ H<br />
= − ∂2<br />
∂q 2 + U(q) ,<br />
2mλ2<br />
U(q) =<br />
2 V (x)<br />
, = 1 , 2m = 1 <br />
∆τ = τ max /N τ , τ = τ n = n∆τ, ( n = 0, 1, · · · , N τ ) <br />
ψ (n) (q) = ψ(q, τ n ) ψ (n−1) , (1.42) τ = τ n <br />
ψ (n) (q) = exp(−iH∆τ ) ψ (n−1) (q)<br />
∆τ exp(−iH∆τ ) ≈ 1 − iH∆τ H<br />
ϕ α (q) <br />
ψ (0) (q) = ∑ α<br />
c α (0) ϕ α (q) ,<br />
Hϕ α (q) = E α ϕ α (q)<br />
(1 − iH∆τ) n ϕ α (q) = (1 − iE α ∆τ) n ϕ α (q) <br />
ψ (n) (q) ≈ (1 − iH∆τ) ψ (n−1) (q) ≈ · · · ≈ (1 − iH∆τ) n ψ (0) (q)<br />
= ∑ α<br />
c α (0) (1 − iE α ∆τ) n ϕ α (q) (3.35)<br />
c α (t) = c α (0) e −iEατ<br />
(3.35) <br />
, <br />
(<br />
| c α (0) (1 − iE α ∆τ) n | = |c α (0)| 1 + (E α ∆τ) 2) n/2<br />
, 1 + (Eα ∆τ) 2 > 1<br />
, n ∆τ <br />
, 1 <br />
exp(−iH∆τ ) ≈ 1 − iH∆τ/2<br />
1 + iH∆τ/2 = 2<br />
1 + iH∆τ/2 − 1 (3.36)<br />
∆τ 2 exp(−iH∆τ) , 1 − iH∆τ <br />
ψ (n) (q) ≈<br />
( ) n 1 − iH∆τ/2<br />
ψ (0) (q) = ∑ 1 + iH∆τ/2<br />
α<br />
c α (0)<br />
( ) n 1 − iEα ∆τ/2<br />
ϕ α (q)<br />
1 + iE α ∆τ/2<br />
<br />
∣ ∣∣∣ 1 − iE α ∆τ/2<br />
1 + iE α ∆τ/2∣ = 1<br />
,
3 1 53<br />
(3.36) <br />
(<br />
)<br />
ψ (n) 2<br />
(q) ≈<br />
1 + iH∆τ/2 − 1 ψ (n−1) (q) = φ(q) − ψ (n−1) (q)<br />
<br />
φ(q) =<br />
2<br />
1 + iH∆τ/2 ψ(n−1) (q) <br />
∆q = (q max − q min )/N q <br />
(<br />
1 + i∆τ<br />
2 H )<br />
φ(q) = 2ψ (n−1) (q) (3.37)<br />
q = q k = q min + k∆q ,<br />
k = 0, 1, · · · , N q<br />
k q = q k <br />
(<br />
)<br />
f k+1 + f k−1 − 2f k = (∆q) 2 f ′′ (q k ) + (∆q)2<br />
12 f (4) (q k ) + · · ·<br />
2 <br />
<br />
f ′′ (q k ) ≈ f k+1 + f k−1 − 2f k<br />
(∆q) 2 , k = 1, 2, · · · , N q − 1<br />
Hφ k = − φ ′′<br />
k + U k φ k ≈ − φ k+1 + φ k−1 − 2φ k<br />
(∆q) 2 + U k φ k<br />
(3.37) k = 1, 2, · · · , N q − 1 <br />
φ k+1 − (a k − ib) φ k + φ k−1 = 2ib ψ (n−1)<br />
k<br />
, a k = 2 + (∆q) 2 U k , b = 2(∆q)2<br />
∆τ<br />
(3.38)<br />
φ 0 , φ 1 φ k , ψ(q min , τ) = ψ(q max , τ) = 0 ,<br />
φ 0 = φ Nx = 0 φ k <br />
φ k+1 = C k φ k + D k (3.39)<br />
(3.38) <br />
1<br />
φ k =<br />
φ k−1 + D k − 2ib ψ (n−1)<br />
k<br />
a k − ib − C k a k − ib − C k<br />
φ k = C k−1 φ k−1 + D k−1 <br />
C k−1 =<br />
1<br />
a k − ib − C k<br />
,<br />
D k−1 = D k − 2ib ψ (n−1) (<br />
)<br />
k<br />
= C k−1 D k − 2ib ψ (n−1)<br />
k<br />
a k − ib − C k<br />
(3.40)<br />
<br />
, τ = τ n−1 ψ (n−1) τ = τ n ψ (n) <br />
1. φ Nq = C Nq−1φ Nq−1 + D Nq−1 = 0 C Nq−1 = D Nq−1 = 0 <br />
(3.40) k = N q − 1 k = 1 k , ψ (n−1)<br />
k<br />
<br />
C k , D k <br />
2. C k , D k , φ 0 = 0 (3.39) k = 0 k = N q − 1 , <br />
k φ k ψ (n) ψ (n)<br />
k<br />
= φ k − ψ (n−1)<br />
k<br />
C
3 1 54<br />
• <br />
<strong>qm</strong>in = q min , <strong>qm</strong>ax = q max , dq = ∆q , dt = ∆τ , nq = N q , nt = N τ<br />
a k k C <br />
, ψ(q k , τ), C k , D k , φ k ... r , ... i <br />
, GCC <br />
<br />
• C k a k , a k<br />
U(q) , U(q) ( pot(q) ) <br />
pot main <br />
• ψ (n−1)<br />
k<br />
ψ (n)<br />
k<br />
, C k <br />
D k D k ψ (n−1)<br />
k<br />
, φ 0 = 0 <br />
(3.39) φ k <br />
int main()<br />
{<br />
/* , */<br />
for( k=0; k=1; k-- ){<br />
cr[k-1] = 1/( aa[k]-i*b-cr[k]-i*ci[k] ) ;<br />
ci[k-1] = 1/( aa[k]-i*b-cr[k]-i*ci[k] ) ;<br />
}<br />
for( n=1; n=1; k-- ){<br />
dr[k-1] = ..... ;<br />
di[k-1] = ..... ;<br />
}<br />
phir[0] = phii[0] = 0; /* φ k */<br />
for( k=0; k
3 1 55<br />
}<br />
return 0;<br />
double pot( double q )<br />
{<br />
return 0; /* */<br />
}<br />
|ψ(q, τ)| 2 q <br />
, , , <br />
q |ψ(q, τ)| 2 , , GNUPLOT <br />
, PostScript TEX tpic <br />
http://physics.s.chiba-u.ac.jp/~kurasawa/index.html<br />
--> <br />
<br />
51 , ψ(q, 0) , <br />
<br />
ψ(q, 0) =<br />
(<br />
1<br />
(2πα 2 ) exp − (q − q 0) 2 )<br />
{<br />
1/4 4α 2 + ik 0 q , U(q) =<br />
0 , q < 0<br />
U 0 , q > 0<br />
(3.41)<br />
<br />
q min = − 110, q max = 100, τ max = 100, N τ = 1000, N q = 1500<br />
q 0 = − 50, α = 8, k 0 = 0.6, U 0 = 0.38<br />
Pentium4 ( 3.4GHz ) 0.1 <br />
3.3<br />
<br />
1. , , U(q) = 0 (1.53) <br />
(1.53) <br />
(<br />
|ψ(q, τ)| 2 1<br />
= √<br />
2πα2 (1 + τ 2 /α 4 ) exp − (q − q 0 − 2k 0 τ) 2 )<br />
2α 2 (1 + τ 2 /α 4 )<br />
<br />
2. 51 <br />
3. () , , () 121 ∼ 124 <br />
3.4<br />
<br />
{<br />
U0 q , q > 0<br />
U(q) =<br />
∞ , q < 0<br />
ψ(q, τ) ψ(0, τ) = 0 q min = 0 <br />
q 0 τ = τ 0 q = 0 , τ 0 = √ q 0 /U 0<br />
q 0 = τ 0 = 50 U 0 = 1/50 U 0 <br />
(3.41) k 0 = 0 q 0 = 50, U 0 = 0.025 <br />
, q = q 0 F = − U 0 q = 0
3 1 56<br />
q cl (t) • × 〈 q 〉<br />
〈 q 〉 =<br />
∫ ∞<br />
0<br />
dq q|ψ(q, t)| 2<br />
(1.11) F = 〈 q 〉 = q cl (t) , <br />
, , <br />
〈 q 〉 ≈ q cl (t) , <br />
〈 q 〉 ,<br />
, |ψ(q, τ)| 2
4 57<br />
4 <br />
x − kx <br />
ω = √ k/m mω 2 x 2 /2 , H<br />
<br />
Ĥ <br />
H = p2<br />
2m + 1 2 mω2 x 2<br />
Ĥ = ˆp2<br />
2m + 1 2 mω2 x 2 ,<br />
ˆp = − i d<br />
dx<br />
, <br />
, , <br />
<br />
<br />
, ˆ q<br />
√ mω<br />
q = α x , α =<br />
<br />
<br />
H = − 2 d 2<br />
2m dx 2 + 1 2 mω2 x 2 = ω 2<br />
, H ϕ(x) = E ϕ(x) <br />
(− d2<br />
dq 2 + q2 )<br />
d 2 ϕ<br />
dq 2 + ( ε − q 2) ϕ(q) = 0 , ε = 2E<br />
ω<br />
(4.1)<br />
<br />
4.1 <br />
(4.1) <br />
<br />
q → ± ∞ ϕ(q) <br />
) (<br />
(− d2<br />
dq 2 + q2 − ε q n e aq2 = 1 − 4a 2 + ε − 2a<br />
)<br />
n(n − 1)<br />
q 2 −<br />
q 4 q n+2 e aq2 ≈ (1 − 4a 2 )q n+2 e aq2<br />
a = ±1/2 q n e ±q2 /2 q → ± ∞ <br />
(4.1) <br />
ϕ(q) = h(q) e −q2 /2<br />
d 2 h dh<br />
− 2q + (ε − 1) h = 0 (4.2)<br />
dq2 dq<br />
x , <br />
h(q) = q l ( a 0 + a 1 q 2 + a 2 q 4 + · · · ) =<br />
∞∑<br />
a k q 2k+l , a 0 ≠ 0 (4.3)<br />
k=0
4 58<br />
l , <br />
q dh<br />
∞ dq = ∑<br />
(2k + l)a k q 2k+l<br />
k=0<br />
d 2 h<br />
∞<br />
dq 2 = ∑<br />
(2k + l)(2k + l − 1)a k q 2k+l−2 =<br />
k=0<br />
∞∑<br />
(2k + l + 2)(2k + l + 1)a k+1 q 2k+l<br />
k=−1<br />
<br />
∞∑<br />
)<br />
l(l − 1)a 0 q l−2 +<br />
((2k + l + 2)(2k + l + 1)a k+1 − (2l + 4k + 1 − ε) a k q 2k+l = 0<br />
k=0<br />
<br />
l(l − 1)a 0 = 0 , a k+1 =<br />
2(2k + l) + 1 − ε<br />
(2k + l + 2)(2k + l + 1) a k (4.4)<br />
a 0 ≠ 0 l = 0 l = 1 2 , k 2l+4k+1−ε ≠ 0<br />
, k <br />
a k 2l + 4k − 3 − ε<br />
=<br />
a k−1 (2k + l)(2k + l − 1) → 1 k<br />
<br />
∞∑<br />
e q2 = b k q 2k ,<br />
k=0<br />
b k (k − 1)!<br />
= = 1 b k−1 k! k<br />
q → ± ∞ h(q) → q l e q2<br />
ϕ(q) = h(q) e −q2 /2 → q l e q2 /2 <br />
ϕ , (4.3) , k = k 0 <br />
2l + 4k 0 + 1 − ε = 0 (4.5)<br />
a k0+1 = a k0+2 = · · · = 0 h(q) 2k 0 + l <br />
q → ± ∞ ϕ(q) → 0 , (4.5) <br />
E = 1 (<br />
2 ωε = ω 2k 0 + l + 1 )<br />
2<br />
l = 0, 1 2k 0 + l n <br />
(<br />
E n = ω n + 1 )<br />
, n = 0, 1, 2, · · · (4.6)<br />
2<br />
<br />
ε = 2n + 1 (4.2) <br />
d 2 h dh<br />
− 2q + 2nh = 0 (4.7)<br />
dq2 dq<br />
n = 0, 1, 2, · · · , (4.4) <br />
h(q) =<br />
∞∑<br />
a k q 2k+l 2(2k + l − n)<br />
, a k+1 =<br />
(2k + 2 + l)(2k + l + 1) a k<br />
k=0<br />
h(q) k 0 = (n − l)/2 k 0 <br />
, n l = 0 , l = 1 k ≥ k 0 + 1 a k = 0
4 59<br />
a k <br />
k 0 − k + 1<br />
a k = − 4<br />
(2k + l)(2k + l − 1) a k−1 = (−4) k k 0 (k 0 − 1) · · · (k 0 − k + 1)<br />
(2k + l)(2k + l − 1) · · · (l + 1) a 0<br />
=<br />
(−4) k k 0 ! l!<br />
(k 0 − k)! (2k + l)! a 0<br />
l = 0, 1 l! = 1 a 0 ≠ 0 , a k0 a k0 = 2 n = 2 2k0+l <br />
a 0 <br />
a 0 = (−1) k 0 2l n!<br />
k 0 !<br />
, ∴ a k = (−1) k 0−k 2 2k+l n!<br />
(k 0 − k)! (2k + l)! = (−1)k′ 2n−2k′ n!<br />
k ′ ! (n − 2k ′ )!<br />
k ′ = k 0 −k [n/2] = n/2 k 0 = [n/2]<br />
<br />
h(q) = H n (q) ≡<br />
[n/2]<br />
∑<br />
H n (q) n (Hermite) <br />
k=0<br />
(−1) k n!<br />
k! (n − 2k)! (2q)n−2k (4.8)<br />
d n<br />
[n/2]<br />
dq n F ∑ n!<br />
(q2 ) =<br />
k! (n − 2k)! (2q)n−2k F (n−k) (q 2 )<br />
k=0<br />
( I 9 ), F (q) = e −q <br />
<br />
d n<br />
[n/2]<br />
∑ n!<br />
dq n = e−q2 k! (n − 2k)! (2q)n−2k (−1) n−k e −q2<br />
k=0<br />
dn<br />
H n (q) = (−1) n e q2<br />
dq n (4.9)<br />
e−q2<br />
248 15.1 <br />
E n = ω(n + 1/2) ϕ n <br />
ϕ n (x) = C n H n (q) e −q2 /2 = C n H n (αx) e −α2 x 2 /2 , α =<br />
√ mω<br />
<br />
(4.10)<br />
C n <br />
(4.7) 2 , H n (q) n <br />
l = 0, n l = 1 k > [n/2] a k = 0 <br />
H n (q) , n l = 1 k a k ≠ 0 , <br />
h(q) H n (q) (4.7) n <br />
, h(q) H n (q) 2 <br />
2 q → ± ∞ e q2 , <br />
4.1<br />
(4.8) (4.9) n = 2, 3 <br />
4.2<br />
<br />
(15.8) C n (4.22)
4 60<br />
<br />
H a <br />
√ ( mω<br />
a = x +<br />
i )<br />
2 mω p = √ 1 (<br />
q + d )<br />
2 dq<br />
p = − i d/dx <br />
√ ( mω<br />
a † = x −<br />
i )<br />
2 mω p = √ 1 (<br />
q − d )<br />
2 dq<br />
(4.11)<br />
(4.12)<br />
<br />
<br />
a a † = 1 2<br />
a † a = 1 2<br />
2 <br />
H q <br />
d<br />
dq qf(q) = f(q) + q d dq f(q) , d dq q = 1 + q d dq<br />
(<br />
q + d ) (<br />
q − d )<br />
= 1 (q 2 + d dq dq 2 dq q − q d )<br />
dq − d2<br />
dq 2 = 1 2<br />
(q 2 − d dq q + q d )<br />
dq − d2<br />
dq 2 = 1 )<br />
(q 2 − 1 − d2<br />
2<br />
dq 2<br />
H = − 2 mω<br />
2m <br />
d 2<br />
(q 2 + 1 − d2<br />
dq 2 )<br />
a a † − a † a = [ a , a † ] = 1 (4.13)<br />
d √ mω<br />
dx = <br />
d<br />
dq <br />
dq 2 + 1 <br />
2 mω2 mω q2 = ω 2<br />
, N = a † a <br />
) (<br />
(− d2<br />
dq 2 + q2 = ω a † a + 1 )<br />
2<br />
(4.14)<br />
*** (4.13) , a a † ***<br />
N ν , | ν 〉 <br />
| φ 〉 = a | ν 〉 (1.16) <br />
N | ν 〉 = ν | ν 〉 , 〈 ν | ν 〉 = 1<br />
N ν , ν = 0 <br />
ν = 〈 ν |N| ν 〉 = 〈 ν | a † a | ν 〉 = 〈 φ | φ 〉 ≥ 0 (4.15)<br />
| φ 〉 = a | ν 〉 = 0<br />
| ν 〉 | 0 〉 (4.13) <br />
Na| ν 〉 = (aa † − 1)a| ν 〉 = aN| ν 〉 − a| ν 〉 = (ν − 1) a| ν 〉<br />
Na † | ν 〉 = a † ( 1 + a † a ) | ν 〉 = (ν + 1) a † | ν 〉<br />
a| ν 〉 N ν − 1 ν = 0 a | 0 〉 = 0 <br />
, a † | ν 〉 N ν + 1 | ν 〉 a , a † N <br />
<br />
· · · a k | ν 〉 · · · a 2 | ν 〉 a| ν 〉 | ν 〉 a † | ν 〉 (a † ) 2 | ν 〉 · · ·<br />
· · · ν − k · · · ν − 2 ν − 1 ν ν + 1 ν + 2 · · ·
4 61<br />
ν , k ν − k ≠ 0 a k | ν 〉 ̸= 0 <br />
, k N ν − k N <br />
, ν a ν | ν 〉 ∝ | 0 〉 <br />
a ν+1 | ν 〉 = a ν+2 | ν 〉 = · · · = 0<br />
, N , N = a † a ν <br />
ν n <br />
a † a | n 〉 = n | n 〉 , n = 0, 1, 2, · · · (4.16)<br />
H = ω (N + 1/2) E n = ω (n + 1/2) <br />
(4.6) <br />
| n 〉 c n <br />
| n 〉 = c n<br />
(<br />
a<br />
† ) n<br />
| 0 〉 , 〈 0 | 0 〉 = 1<br />
(1.16) Û = c n<br />
(<br />
a<br />
† ) n<br />
Û † = c ∗ na n <br />
〈 n | n 〉 = |c n | 2 〈 0 | a n (a † ) n | 0 〉<br />
I n = 〈 0 | a n (a † ) n | 0 〉 , (4.13) <br />
I n = 〈 0 | a n−1 a a † (a † ) n−1 | 0 〉 = 〈 0 | a n−1 (N + 1) (a † ) n−1 | 0 〉<br />
(a † ) n−1 | 0 〉 N n − 1 <br />
I n = n 〈 0 | a n−1 (a † ) n−1 | 0 〉 = n I n−1 = n(n − 1) I n−2 = · · · = n!I 0 = n!<br />
〈 n | n 〉 = |c n | 2 n! = 1 , <br />
| n 〉 = 1 √<br />
n!<br />
(<br />
a<br />
† ) n<br />
| 0 〉 , 〈 0 | 0 〉 = 1 (4.17)<br />
| n 〉 <br />
a † | n 〉 = √ n + 1 | n + 1 〉 , a | n 〉 =<br />
{ √ n | n − 1 〉 , n ≠ 0<br />
0 , n = 0<br />
(4.18)<br />
<br />
a † N n 1 , a 1 <br />
(4.11), (4.12) a, a † , <br />
, (4.16) (4.17) <br />
(4.13) , a, a † <br />
, a † , a a| 0 〉 = 0 <br />
| 0 〉 , (4.17) | n 〉 n <br />
4.3<br />
(4.18)
4 62<br />
(4.11), (4.12) (4.17) ϕ n ϕ 0 <br />
a ϕ 0 = √ 1 (<br />
q + d )<br />
ϕ 0 = 0<br />
2 dq<br />
C 0 ϕ 0 = C 0 e −q2 /2 <br />
∫ ∞<br />
−∞<br />
, ϕ 0 <br />
dx |ϕ 0 (q)| 2 = |C|2<br />
α<br />
∫ ∞<br />
−∞<br />
dq e −q2<br />
= |C|2 √ π = 1<br />
α<br />
ϕ 0 (x) =<br />
√ √ α<br />
α<br />
/2 x<br />
=<br />
2 /2<br />
π 1/2 e−q2 π 1/2 e−α2<br />
(4.19)<br />
(4.17) <br />
√ α (<br />
ϕ n (x) =<br />
a<br />
† ) (<br />
n<br />
e<br />
−q 2 /2 = C<br />
π 1/2 n q − d ) n<br />
e −q2 /2 , C n =<br />
n!<br />
dq<br />
f(q) <br />
e q2 /2 d dq e−q2 /2 f(q) =<br />
( d<br />
dq − q )<br />
f(q) ≡ f 1 (q)<br />
√<br />
α<br />
π 1/2 n! 2 n (4.20)<br />
e q2 /2 d2<br />
dq 2 e−q2 /2 f(q) = e q2 /2 d dq e−q2 /2 e q2 /2 d dq e−q2 /2 f(q)<br />
= e q2 /2 d dq e−q2 /2 f 1 (q) =<br />
( d<br />
dq − q )<br />
f 1 (q) =<br />
( d<br />
dq − q ) 2<br />
f(q)<br />
<br />
( d<br />
dq − q ) n<br />
f(q) = e q2 /2 dn<br />
dq n e−q2 /2 f(q) , n = 0, 1, 2, · · · (4.21)<br />
f(q) = e −q2 /2 (4.20) q = αx = √ mω/ x <br />
√ α<br />
ϕ n (x) =<br />
/2 H<br />
π 1/2 n! 2 n e−q2 n (q) , H n (q) = (−1) n e<br />
q2 dn<br />
dq n e−q2 (4.22)<br />
(4.10) , <br />
4.2 <br />
E = 0 , <br />
, 0 ω/2 <br />
, x p , <br />
( 0 ) , <br />
0 <br />
H ϕ 〈 · · · 〉 <br />
∆x = √ 〈(x − 〈 x 〉) 2 〉 = √ 〈 x 2 〉 − 〈 x 〉 2 , ∆p = √ 〈(p − 〈 p 〉) 2 〉 = √ 〈 p 2 〉 − 〈 p 〉 2<br />
ϕ(x) 〈 x 〉 = 〈 p 〉 = 0 <br />
〈 H 〉 = 1<br />
2m 〈 p2 〉 + mω2<br />
2 〈 x2 〉 = 1<br />
2m (∆p)2 + mω2<br />
2 (∆x)2
4 63<br />
∆x∆p ≥ /2 <br />
〈 H 〉 ≥ 1 ( ) 2 <br />
+ mω2<br />
2m 2∆x 2 (∆x)2 ≥ 2<br />
(<br />
1<br />
2m<br />
( ) ) 2 1/2<br />
mω 2<br />
2∆x 2 (∆x)2 = ω 2<br />
2 ≥ 〈 H 〉 = ω/2 <br />
∆x∆p = ( ) 2<br />
2 , 1 <br />
= mω2<br />
2m 2∆x 2 (∆x)2 , ∆x = <br />
√<br />
<br />
2∆p = 2mω = √ 1<br />
2 α<br />
ω/2 , <br />
, <br />
(4.17) <br />
x = q α = a† + a<br />
√<br />
2 α<br />
,<br />
p = −iα d dq = i α √<br />
2<br />
(<br />
a † − a )<br />
<br />
x | n 〉 = 1 √<br />
2 α<br />
( √n<br />
+ 1 | n + 1 〉 +<br />
√ n | n − 1 〉<br />
)<br />
n ≠ n ′ 〈 n ′ | n 〉 = 0 <br />
〈 n | x | n 〉 = 0 , 〈 n | p | n 〉 = 0 , ϕ n (x) <br />
, (4.13) <br />
(<br />
a † + a ) 2<br />
= (a † ) 2 + a 2 + 2a † a + 1<br />
<br />
<br />
x 2 | n 〉 = 1<br />
2α 2 (√<br />
(n + 1)(n + 2) | n + 2 〉 +<br />
√<br />
n(n − 1) | n − 2 〉 + (2n + 1)| n 〉<br />
)<br />
〈 n | x 2 | n 〉 = 1 (<br />
α 2 n + 1 )<br />
(<br />
, 〈 n | p 2 | n 〉 = (α) 2 n + 1 )<br />
2<br />
2<br />
(4.23)<br />
(4.24)<br />
<br />
(∆x) 2 = 〈 n | x 2 | n 〉 − 〈 n | x | n 〉 2 = 1 (<br />
α 2 n + 1 )<br />
2<br />
(<br />
(∆p) 2 = 〈 n | p 2 | n 〉 − 〈 n | p | n 〉 2 = (α) 2 n + 1 )<br />
2<br />
∆x∆p = (n + 1/2) , ( n = 0 ) α <br />
∆x α 2 = 1/(2(∆x) 2 ) , (4.19) <br />
( )<br />
1<br />
ϕ 0 (x) =<br />
(2π(∆x) 2 ) exp −<br />
x2<br />
1/4 4(∆x) 2<br />
, x 0 = k 0 = 0 (1.35) <br />
α 2 = mω/ (4.24) <br />
mω 2<br />
2 〈 n | x2 | n 〉 = 1<br />
2m 〈 n | p2 | n 〉 = ω 2<br />
(<br />
n + 1 )<br />
= E n<br />
2 2<br />
(1.44) V (x) = mω 2 x 2 /2 x dV/dx = mω 2 x 2 = 2V (x) <br />
(1.44) <br />
<br />
1<br />
2m 〈 n | p2 | n 〉 = 〈 n | V | n 〉 = 1 ( ) p<br />
2<br />
2 〈 n | 2m + V | n 〉 = E n<br />
2
4 64<br />
4.3 <br />
<br />
, E , v mv 2 /2 = E − mω 2 x 2 /2 ≥ 0 <br />
, <br />
x 2 ≤ 2E<br />
mω 2 , q2 = α 2 x 2 ≤ ε , ε = 2E<br />
ω<br />
, x x + dx P cl (x) dx , <br />
dt <br />
<br />
<br />
P cl ∝ dt<br />
dx = 1 v ∝ 1<br />
√ , P C<br />
cl = √<br />
ε − q<br />
2 ε − q<br />
2<br />
∫ √ ε/α<br />
− √ ε/αdx P cl = 2C α<br />
∫ √ ε<br />
0<br />
dq<br />
√ = 2C [sin −1 q ] √ ε<br />
√ = C<br />
ε − q<br />
2 α ε α π = 1<br />
P cl =<br />
0<br />
α<br />
π √ ε − q 2 (4.25)<br />
E = ω(n + 1/2) ε = 2n + 1 <br />
0.6<br />
n=0<br />
0.2<br />
n = 50<br />
|ϕn(q)| 2 /α<br />
0.4<br />
0.2<br />
n=3<br />
0.1<br />
0.0<br />
0 1 2 3 q<br />
0.0<br />
0 1 2 3 4 5 6 7 8 9 10 q<br />
n = 0, 3 (4.22) |ϕ n | 2 q ϕ n n <br />
, q ≥ 0 <br />
P cl (q)/α q , <br />
| q | > √ 2n + 1 , , n |ϕ n | 2 <br />
P cl (q) ( n = 50 )ϕ n q > 0 n/2 , |ϕ n | 2 <br />
, P cl n → ∞ H n (q) <br />
(15.105) WKB ( 154 )E n ∼ ω<br />
, E n ≫ ω <br />
<br />
<br />
t = 0 ψ(x, 0) , ψ(x, t) (1.39), (1.40) <br />
∞∑<br />
ψ(x, t) = c n e −iEnt/ ϕ n (x) , c n =<br />
∫ ∞<br />
n=0<br />
−∞<br />
dx ϕ n (x) ψ(x, 0) (4.26)
4 65<br />
( ϕ ∗ n = ϕ n ) ψ(x, 0) , x 0 p 0 <br />
(1.35)<br />
ψ(x, 0) =<br />
(<br />
1<br />
(2π(∆x) 2 ) exp − (x − x 0) 2<br />
1/4 4(∆x) 2 + i p )<br />
0x<br />
<br />
(4.27)<br />
∆x ∆x (∆x) 2 = 1/(2α 2 ) x q = αx <br />
<br />
ψ(x, 0) =<br />
(15.7) <br />
∞∑<br />
n=0<br />
√ α<br />
π 1/2 e−(q−q0)2 /2+ik 0q , q 0 = αx 0 , k 0 = p 0<br />
α = α p 0<br />
mω<br />
c n<br />
√<br />
n!<br />
s n =<br />
∫ ∞<br />
−∞<br />
dx<br />
∞∑<br />
n=0<br />
ϕ n (x)<br />
√<br />
n!<br />
s n ψ(x, 0)<br />
= √ 1 ∫ ∞<br />
dq exp<br />
(− q2 + s 2<br />
+ √ 2 sq − (q − q 0) 2<br />
π 2<br />
2<br />
−∞<br />
q <br />
∞∑<br />
n=0<br />
(<br />
c<br />
√ n<br />
s n = exp − q2 0 + k0 2 − 2iq 0 k 0<br />
n! 4<br />
(<br />
= exp − q2 0 + k0 2 )<br />
− 2iq 0 k 0<br />
∑ ∞<br />
4<br />
n=0<br />
+ q )<br />
0 + ik<br />
√ 0<br />
s 2<br />
1<br />
n!<br />
)<br />
+ ik 0 q<br />
( ) n q0 + ik<br />
√ 0<br />
s n<br />
2<br />
(4.28)<br />
s n <br />
c n = √ 1 ( ) n (<br />
q0 + ik<br />
√ 0<br />
exp − q2 0 + k 2 )<br />
0 − 2iq 0 k 0<br />
n! 2<br />
4<br />
(4.29)<br />
(4.22) (4.26) (15.6) <br />
√ ( α<br />
ψ(x, t) =<br />
π exp − q2<br />
1/2 2 − q2 0 + k0 2 − 2iq 0 k 0<br />
− iωt )<br />
∑ ∞<br />
(λ/2) n<br />
H n (q)<br />
4<br />
2 n!<br />
n=0<br />
√ ( α<br />
=<br />
π exp − q2<br />
1/2 2 − q2 0 + k0 2 − 2iq 0 k 0<br />
− iωt )<br />
4<br />
2 − λ2<br />
4 + λq<br />
(4.30)<br />
<br />
λ =<br />
(q 0 + ik 0<br />
)<br />
e −iωt<br />
|e z | = exp(Re z) <br />
|ψ(x, t)| 2 = √ α (<br />
exp − q 2 − q2 0 + k0<br />
2 − λ2 R − λ2 I<br />
π 2 2<br />
)<br />
+ 2λ R q , λ R = Re λ , λ I = Im λ<br />
λ |λ| 2 = λ 2 R + λ2 I = q2 0 + k 2 0 <br />
|ψ(x, t)| 2 =<br />
√ α (<br />
exp − (q − λ R ) 2) =<br />
π<br />
α √ π<br />
exp<br />
(<br />
− α 2( ) ) 2<br />
x − X(t)<br />
(4.31)<br />
<br />
X(t) = λ R<br />
α = x 0 cos ωt + p 0<br />
sin ωt<br />
mω<br />
X(t) t = 0 x 0 , p 0 , |ψ(x, t)| 2
4 66<br />
ψ(x, t) 〈 · · · 〉 x x 2 <br />
〈 x 〉 = 1 ∫ ∞<br />
α 2 dq q |ψ(x, t)| 2 = √ 1 ∫ ∞<br />
dq (q + λ R ) e −q2<br />
πα<br />
〈 x 2 〉 = 1 √ πα<br />
2<br />
−∞<br />
∫ ∞<br />
−∞<br />
−∞<br />
dq (q + λ R ) 2 e −q2 = 1 ( 1<br />
α 2 2 + λ2 R<br />
(∆x) 2 = 1/(2α 2 ) ∆x (4.30) <br />
∂<br />
ψ(x, t) = α (λ − αx) ψ(x, t)<br />
∂x<br />
)<br />
= λ R<br />
α<br />
= X(t) (4.32)<br />
= 1<br />
2α 2 + (X(t))2 (4.33)<br />
<br />
( )<br />
)<br />
〈 p 〉 = − i λ − α〈 x 〉 = − iα<br />
(λ − λ R = αλ I = p 0 cos ωt − mωx 0 sin ωt = m dX dt<br />
(4.34)<br />
<br />
∂ 2<br />
∂x 2 ψ(x, t) = − α2 ( 1 − (λ − αx) 2) ψ(x, t) = − α 2( 1 − λ 2 + 2λαx − α 2 x 2) ψ(x, t)<br />
(4.32), (4.33) <br />
〈 p 2 〉 = 2 α 2 (1 − λ 2 + 2λλ R − 1 2 − λ2 R<br />
) (<br />
= 2 α 2 λ 2 I + 1 2<br />
)<br />
= 〈 p 〉 2 + 2 α 2<br />
2<br />
(∆p) 2 = 2 α 2 /2 ∆x∆p = /2 , (4.30) ψ(x, t) <br />
, (∆x) 2 ≠ 1/(2α 2 ) , t = 0 <br />
, t ≠ 0 ψ(x, t) ( 4.4 )<br />
K = p 2 /(2m) V (x) = mω 2 x 2 /2 <br />
〈 K 〉 = 1<br />
2m 〈 p2 〉 = 1<br />
2m 〈 p 〉2 + 2 α 2<br />
4m = 1 (<br />
) 2 ω<br />
p 0 cos ωt − mωx 0 sin ωt +<br />
2m<br />
4<br />
〈 V 〉 = mω2<br />
2 〈 x2 〉 = mω2<br />
2 〈 x 〉2 + mω2<br />
4α 2<br />
= mω2<br />
2<br />
〈 K 〉 〈 V 〉 , H <br />
(<br />
x 0 cos ωt + p ) 2<br />
0<br />
mω sin ωt ω +<br />
4<br />
〈 H 〉 = 〈 K 〉 + 〈 V 〉 = E cl + ω 2 , E cl = p2 0<br />
2m + mω2<br />
2 x2 0<br />
〈 H 〉 E cl <br />
(4.29) <br />
<br />
|c n | 2 = ρn<br />
n! e−ρ , ρ = q2 0 + k0<br />
2<br />
2<br />
∞∑<br />
|c n | 2 = 1 ,<br />
n=0<br />
n=0<br />
n=1<br />
= E cl<br />
ω<br />
∞∑<br />
∑<br />
∞<br />
|c n | 2 n = ρ e −ρ ρ n−1<br />
(n − 1)! = ρ<br />
<br />
<br />
〈 H 〉 = ω<br />
∞∑<br />
n=0<br />
(<br />
|c n | 2 n + 1 ) (<br />
= ω ρ + 1 )<br />
= E cl + ω 2<br />
2<br />
2
4 67<br />
4.4<br />
<br />
i ∂ ψ(x, t) = Hψ(x, t) ,<br />
∂t H<br />
= p2<br />
2m + mω2<br />
2 x2<br />
ψ(x, t) 〈 · · · 〉 <br />
<br />
1. (1.7) <br />
<br />
D x (t) = mω 2( 〈 x 2 〉 − 〈 x 〉 2) , D p (t) = 1 (〈 p 2 〉 − 〈 p 〉 2)<br />
m<br />
D xp (t) = ω 2( )<br />
〈 xp + px 〉 − 2〈 x 〉〈 p 〉<br />
dD x<br />
dt<br />
= D xp ,<br />
dD p<br />
dt<br />
= − D xp ,<br />
dD xp<br />
dt<br />
= − 2ω 2( D x − D p<br />
)<br />
2. 1. D x (t) D p (t) <br />
<br />
D x (0) = D y (0) , D xp (0) = 0<br />
3. ψ(x, 0) (4.27) , 2. (∆x) 2 = 1/(2α 2 ) <br />
4.5<br />
(4.26) <br />
<br />
ψ(x, t) =<br />
∞∑<br />
e −iEnt/ ϕ n (x)<br />
n=0<br />
∫ ∞<br />
−∞<br />
G(x, x ′ , t) =<br />
dx ′ ϕ n (x ′ ) ψ(x ′ , 0) =<br />
∫ ∞<br />
−∞<br />
dx ′ G(x, x ′ , t) ψ(x ′ , 0)<br />
∞∑<br />
e −iEnt/ ϕ n (x)ϕ n (x ′ ) (4.35)<br />
G(x, x ′ , t) 1 (15.10) <br />
√<br />
(<br />
mω<br />
G(x, x ′ , t) =<br />
2πi sin ωt exp i (q2 + q ′2 ) cos ωt − 2qq ′ )<br />
2 sin ωt<br />
q = αx , q ′ = αx ′ , ω → 0 <br />
√ ( m<br />
G(x, x ′ , t) →<br />
2πit exp i m(x − x′ ) 2 )<br />
2t<br />
n=0<br />
, (1.56) <br />
(4.36)<br />
4.6 3.3 pot(x) , <br />
(4.31) , (4.27) ∆x (∆x) 2 = 1/(2α 2 )<br />
∆x , 4.4 D x (t)
4 68<br />
4.4 <br />
( coherent state ) <br />
a | λ 〉<br />
a| λ 〉 = λ| λ 〉 (4.37)<br />
a , λ ,<br />
| n=0 〉 λ = 0 <br />
, [ a , a † ] = 1 a <br />
a † | λ 〉 , | λ 〉 <br />
〈 λ | a | λ 〉 = λ , 〈 λ | a 2 | λ 〉 = λ 2<br />
, <br />
a † a | λ 〉 = λ a † | λ 〉 <br />
〈 λ | a † | λ 〉 = λ ∗ , 〈 λ | (a † ) 2 | λ 〉 = (λ ∗ ) 2<br />
〈 λ | a † a | λ 〉 = λ 〈 λ | a † | λ 〉 = λλ ∗ = |λ| 2 , 〈 λ | aa † | λ 〉 = 〈 λ | a † a + 1 | λ 〉 = |λ| 2 + 1<br />
, <br />
<br />
x = a + a†<br />
√<br />
2 α<br />
, p = − i α a − a†<br />
√<br />
2<br />
, α =<br />
√ mω<br />
<br />
〈 λ | x | λ 〉 = λ + λ∗<br />
√<br />
2 α<br />
=<br />
√<br />
2<br />
α Re λ ,<br />
√<br />
λ − λ∗ 2<br />
〈 λ | p | λ 〉 = − i α √ = mω Im λ (4.38)<br />
2 α<br />
, λ x 2 p 2 <br />
, <br />
〈 λ | x 2 | λ 〉 = 1 (<br />
)<br />
2α 2 〈 λ | a 2 + (a † ) 2 + aa † + a † a | λ 〉 = (λ + λ∗ ) 2 + 1<br />
2α 2<br />
〈 λ | p 2 | λ 〉 = 2 α 2 (1 − (λ − λ ∗ ) 2)<br />
2<br />
(∆x) 2 = 〈 λ | x 2 | λ 〉 − 〈 λ | x | λ 〉 2 = 1<br />
2α 2 , (∆p)2 = 〈 λ | p 2 | λ 〉 − 〈 λ | p | λ 〉 2 = 2 α 2<br />
2<br />
(4.39)<br />
λ , ∆x∆p = /2 <br />
<br />
H = ω(a † a + 1/2) <br />
(<br />
〈E 〉 = 〈 λ | H | λ 〉 = ω |λ| 2 + 1 )<br />
2<br />
(a † a) 2 = a † a a † a = a † (a † a + 1)a = (a † ) 2 a 2 + a † a <br />
〈 λ | (a † a) 2 | λ 〉 = λ 2 〈 λ | (a † ) 2 | λ 〉 + |λ| 2 = |λ| 4 + |λ| 2
4 69<br />
<br />
(<br />
〈 λ | H 2 | λ 〉 = 2 ω 2 〈 λ | (a † a) 2 + a † a + 1 )<br />
( (<br />
| λ 〉 = 2 ω 2 |λ| 2 + 1 ) )<br />
2<br />
+ |λ| 2<br />
4<br />
2<br />
<br />
(∆E) 2 = 〈 λ | H 2 | λ 〉 − 〈 λ | H | λ 〉 2 = 2 ω 2 |λ| 2<br />
<br />
∆E<br />
〈E 〉 = |λ|<br />
|λ| 2 + 1/2<br />
, |λ| ≫ 1, 〈E 〉/ω ≫ 1 <br />
| λ 〉 H | n 〉 <br />
(4.18) <br />
n=0<br />
| λ 〉 =<br />
∞∑<br />
c n (λ) | n 〉 (4.40)<br />
n=0<br />
∞∑<br />
∞∑ √ ∑<br />
∞ √ ∑<br />
∞<br />
a| λ 〉 = c n a| n 〉 = c n n | n − 1 〉 = c n+1 n + 1 | n 〉 = λ c n | n 〉<br />
n=1<br />
ϕ ∗ n ′ 〈 n′ | n 〉 = δ nn ′ √ n + 1 c n+1 = λ c n <br />
c n =<br />
n=0<br />
√ λ<br />
λ 2<br />
c n−1 = √ c n−2 = · · · = √ λn<br />
c 0<br />
n n(n − 1) n!<br />
n=0<br />
c 0 <br />
〈 λ | λ 〉 =<br />
∞∑<br />
∑<br />
∞<br />
|c n | 2 = |c 0 | 2<br />
n=0<br />
n=0<br />
|λ| 2<br />
n!<br />
= |c 0 | 2 e |λ|2 = 1<br />
c 0 = e −|λ|2 /2 <br />
c n (λ) = λn<br />
√<br />
n!<br />
e −|λ|2 /2<br />
(4.41)<br />
(4.18) (4.40) <br />
| λ 〉 = e −|λ|2 /2<br />
( ∞∑<br />
) λa<br />
† n (<br />
)<br />
| 0 〉 = exp λa † − |λ| 2 /2 | 0 〉 (4.42)<br />
n!<br />
n=0<br />
, |c n (λ)| 2 = |λ| 2 e −|λ|2 /n! n, a † a |λ| 2 <br />
<br />
4.7<br />
a † <br />
( Campbell–Hausdorff ) <br />
A, B <br />
<br />
[ A , [ A , B ] ] = [ B , [ A , B ] ] = 0 (4.43)<br />
e A e B = e A+B+[A,B]/2 (4.44)
4 70<br />
( Campbell–Hausdorff ) <br />
<br />
<br />
f(x) = e xA Be −xA <br />
f ′ (x) = dexA<br />
dx Be−xA + e xA B de−xA<br />
= Ae xA Be −xA − e xA Be −xA A = [ A , f(x) ]<br />
dx<br />
f(0) = B <br />
f ′′ (x) = [ A , f ′ (x) ] = [ A , [ A , f(x) ] ]<br />
f (3) (x) = [ A , [ A , f ′ (x) ] ] = [ A , [ A , [ A , f(x) ] ] ]<br />
· · · · · ·<br />
f(x) = e xA Be −xA = f(0) + f ′ (0)x + f ′′ (0)<br />
2<br />
x 2 + f (3) (0)<br />
x 3 + · · ·<br />
3!<br />
= B + x [ A , B ] + x2<br />
2 [ A , [ A , B ] ] + x3<br />
3! [ A , [ A , [ A , B ] ] ] + · · · (4.45)<br />
, (4.43) (4.45) <br />
g(x) = e xA e xB <br />
e xA Be −xA = B + x [ A , B ] (4.46)<br />
dg<br />
(<br />
dx = AexA e xB + e xA Be xB = A + e xA Be −xA) (<br />
)<br />
e xA e xB = A + B + x [ A , B ] g(x)<br />
A+B [ A , B ] , g(0) =<br />
1 <br />
x = 1 (4.44) <br />
<br />
(<br />
)<br />
g(x) = exp (A + B)x + [ A , B ]x 2 /2<br />
A = λ ( a † − a ) , B = λa [ A , B ] = − λ 2 (4.44) <br />
e λa†<br />
= e A+B = e λ2 /2 e λ(a† −a) e<br />
λa<br />
, (4.42) <br />
a| 0 〉 = 0 <br />
( λ 2 − |λ| 2 )<br />
| λ 〉 = exp<br />
e<br />
−a) λ(a† e λa | 0 〉<br />
2<br />
e λa | 0 〉 =<br />
a † − a = − √ 2 d dq | λ 〉 ϕ λ <br />
)<br />
(1 + λa + λ2<br />
2 a2 + · · · | 0 〉 = | 0 〉<br />
( λ 2 − |λ| 2 ) (<br />
ϕ λ (q) = exp<br />
exp − √ 2 λ d )<br />
ϕ 0 (q) = exp<br />
2<br />
dq<br />
( λ 2 − |λ| 2<br />
2<br />
)<br />
ϕ 0 (q − √ 2 λ)
4 71<br />
, (1.25) (4.19) <br />
√ ( α λ 2<br />
ϕ λ (q) =<br />
π exp − |λ| 2<br />
− 1 (<br />
q − √ ) ) 2<br />
2 λ<br />
1/2 2 2<br />
(4.47)<br />
(4.38) <br />
q 0 = α 〈 λ | x | λ 〉 = √ 2 Reλ , k 0 = 1<br />
α 〈 λ | p | λ 〉 = √ 2 Imλ<br />
λ = (q 0 + ik 0 )/ √ 2 (4.47) <br />
√ ( α<br />
ϕ λ (q) =<br />
π exp − (q − q 0) 2<br />
)<br />
+ ik 1/2 0 q − ik 0 q 0 /2<br />
2<br />
, e −ik0q0/2 (4.28) <br />
t = 0 λ = λ 0 t |ψ(t)〉 (4.26) <br />
c n (4.41) <br />
|ψ(t)〉 =<br />
∞∑<br />
n=0<br />
λ n 0<br />
√<br />
n!<br />
e −|λ 0| 2 /2 e −iω(n+1/2)t | n 〉<br />
= e −|λ0|2 /2−iωt/2<br />
( ∞∑ λ0 e −iωt a †) n<br />
| 0 〉 = e −iωt/2 | λ = λ 0 e −iωt 〉<br />
n!<br />
n=0<br />
|ψ(t)〉 |ψ(t)〉 x p (4.38) λ λ 0 e −iωt <br />
<br />
√<br />
2<br />
〈ψ(t)| x |ψ(t)〉 =<br />
α Re ( λ 0 e −iωt) = 〈 λ 0 | x | λ 0 〉 cos ωt + 〈 λ 0 | p | λ 0 〉<br />
sin ωt<br />
mω<br />
√<br />
2<br />
〈ψ(t)| p |ψ(t)〉 = mω<br />
α Im ( λ 0 e −iωt) = 〈 λ 0 | p | λ 0 〉 cos ωt − mω 〈 λ 0 | p | λ 0 〉 sin ωt<br />
(4.32), (4.34) ∆x, ∆p (4.39) ,<br />
<br />
4.8<br />
(4.37) <br />
a ϕ λ = √ 1 (<br />
q + d )<br />
ϕ λ = λϕ λ<br />
2 dq<br />
(4.47) , a † <br />
<br />
4.9 a H (t) = e iHt/ a e −iHt/ , H = ω ( a † a + 1/2 ) <br />
d<br />
1.<br />
dt a H = − iω a H a H (t) = e −iωt a <br />
2. (4.45) a H (t) = e −iωt a <br />
3. t = 0 | λ 0 〉 , t |ψ(t)〉 = e −iHt/ | λ 0 〉 <br />
<br />
a |ψ(t)〉 = λ 0 e −iωt |ψ(t)〉
4 72<br />
<br />
(4.40), (4.41) <br />
〈 λ | λ ′ 〉 = ∑ nn ′ c ∗ n(λ)c n ′(λ ′ )〈 n | n ′ 〉 =<br />
∞∑<br />
c ∗ n(λ)c n (λ ′ ) = exp<br />
(− |λ|2 + |λ ′ | 2 )<br />
∑ ∞<br />
(λ ∗ λ ′ ) n<br />
2<br />
n!<br />
n=0<br />
= exp<br />
(− |λ|2 + |λ ′ | 2 )<br />
+ λ ∗ λ ′<br />
2<br />
n=0<br />
|e z | = e Re z = e (z+z∗)/2 <br />
|〈 λ | λ ′ 〉| = exp<br />
(− |λ|2 + |λ ′ | 2<br />
2<br />
+ λ∗ λ ′ + λλ ′∗ )<br />
= exp<br />
2<br />
(− |λ − λ′ | 2 )<br />
, , λ λ ′ <br />
<br />
<br />
S(x, x ′ ) = 1 ∫<br />
d 2 λ ϕ λ (x) ϕ ∗<br />
π<br />
λ(x ′ )<br />
λ R = Re λ , λ I = Im λ d 2 λ = dλ R dλ I (4.40), (4.41) <br />
S(x, x ′ ) = 1 ∑<br />
∫<br />
√<br />
π n! n′ ! ϕ n(x)ϕ n ′(x ′ ) d 2 λ e −|λ|2 (λ ∗ ) n λ n′<br />
nn ′ 1<br />
λ λ = re iθ <br />
∫<br />
d 2 λ e −|λ|2 (λ ∗ ) n λ n′ =<br />
∫ ∞<br />
0<br />
dr<br />
= 2π δ nn ′<br />
(e −x ) ′ = − e −x <br />
∫ ∞<br />
0<br />
∫ 2π<br />
0<br />
∫ ∞<br />
dx x n e −x = [ − x n e −x] ∫ ∞<br />
∞<br />
+ n dx x n−1 e −x = n<br />
0<br />
<br />
0<br />
S(x, x ′ ) =<br />
0<br />
dθ r n+n′ +1 e −r2 e i(n′ −n)θ<br />
dr r 2n+1 e −r2 = π δ nn ′<br />
∫ ∞<br />
∞∑<br />
ϕ n (x)ϕ n (x ′ ) = δ(x − x ′ )<br />
n=0<br />
0<br />
∫ ∞<br />
0<br />
2<br />
dx x n e −x<br />
dx x n−1 e −x = · · · = n!<br />
, ψ(x) <br />
∫<br />
ψ(x) = dx ′ ψ(x ′ ) δ(x − x ′ ) = 1 ∫ ∫<br />
d 2 λ ϕ λ (x) dx ′ ϕ ∗<br />
π<br />
λ(x ′ )ψ(x ′ )<br />
<br />
| ψ 〉 = 1 ∫<br />
d 2 λ | λ 〉〈 λ | ψ 〉 , 〈 λ | ψ 〉 =<br />
π<br />
∫ ∞<br />
−∞<br />
dx ϕ ∗ λ(x)ψ(x)<br />
∫ ∞<br />
0<br />
dx e −x = n!<br />
| λ 〉 , | λ 〉 <br />
| λ 〉 = 1 ∫<br />
d 2 λ ′ | λ ′ 〉〈 λ ′ | λ 〉 = 1 ∫<br />
d 2 λ ′ | λ ′ 〉 exp<br />
(− |λ|2 + |λ ′ | 2 )<br />
+ λλ ′∗ (4.48)<br />
π<br />
π<br />
2<br />
, | n 〉 <br />
| n 〉 = 1 ∫<br />
d 2 λ | λ 〉〈 λ | n 〉 = 1 ∫<br />
d 2 λ | λ 〉 c ∗<br />
π<br />
π<br />
n(λ) = 1 ∫<br />
π<br />
d 2 λ | λ 〉 (λ∗ ) n<br />
√<br />
n!<br />
e −|λ|2 /2<br />
(4.49)
4 73<br />
4.10<br />
(4.42) <br />
| λ 〉 = D(λ)| 0 〉 , D(λ) = exp ( λa † − λ ∗ a )<br />
, D <br />
D † (λ) = D(−λ) ,<br />
D † (λ)aD(λ) = a + λ<br />
D(−λ) = D −1 (λ) D(λ)D † (λ) = D † (λ)D(λ) = 1 D(λ) <br />
, 2 aD(λ) = D(λ)a + λD(λ) <br />
<br />
a | λ 〉 = aD(λ)| 0 〉 =<br />
(<br />
)<br />
D(λ)a + λD(λ) | 0 〉 = λD(λ)| 0 〉 = λ | λ 〉<br />
4.11<br />
(4.48), (4.49) (4.35) G(x, x ′ , t) <br />
G(x, x ′ , t) = e−iωt/2<br />
π<br />
∫<br />
d 2 λ ϕ λ(t) (x) ϕ ∗ λ(x ′ ) , λ(t) = λe −iωt<br />
(4.36)
5 74<br />
5 <br />
, <br />
, ( Lie algebra ) <br />
( <br />
) <br />
, <br />
5.1 <br />
<br />
, ˆ p p = −i∇ f(r)<br />
( x 1 = x, x 2 = y, x 3 = z )<br />
[ x i , p j ]f(r) ≡<br />
(x i p j − p j x i<br />
)<br />
f(r) = −i<br />
(<br />
x i<br />
∂f<br />
− ∂ x ) (<br />
if<br />
= −i x i<br />
∂x j ∂x j<br />
i = j ∂x i /∂x j = 1 , i ≠ j ∂x i /∂x j = 0 <br />
[ x i , p j ]f(r) = i δ ij f(r)<br />
f(r) f(r) <br />
<br />
∂f<br />
− ∂x )<br />
i ∂f<br />
f − x i<br />
∂x j ∂x j ∂x j<br />
[ x i , p j ] = i δ ij (5.1)<br />
A, B, C, D <br />
[ A , BC ] ≡ ABC − BCA = (AB − BA)C + B(AC − CA)<br />
= [ A , B ] C + B [ A , C ] (5.2)<br />
[ AB , C ] = A [ B , C ] + [ A , C ] B (5.3)<br />
[ A + B , C + D ] = [ A , C ] + [ A , D ] + [ B , C ] + [ B , D ] (5.4)<br />
<br />
<br />
L L = r×p <br />
L <br />
L = r×p ,<br />
p = − i∇<br />
x, y, z 1, 2, 3 <br />
[ L 1 , L 2 ] = [ x 2 p 3 − x 3 p 2 , x 3 p 1 − x 1 p 3 ]<br />
= [ x 2 p 3 , x 3 p 1 ] − [ x 2 p 3 , x 1 p 3 ] − [x 3 p 2 , x 3 p 1 ] + [x 3 p 2 , x 1 p 3 ]<br />
2 3 0 <br />
[ L 1 , L 2 ] = [ x 2 p 3 , x 3 p 1 ] + [ x 3 p 2 , x 1 p 3 ] = x 2 [ p 3 , x 3 ] p 1 + p 2 [ x 3 , p 3 ] x 1<br />
= i (− x 2 p 1 + x 1 p 2 ) = i L 3
5 75<br />
<br />
<br />
[ L 1 , L 2 ] = i L 3 , [ L 2 , L 3 ] = i L 1 , [ L 3 , L 1 ] = i L 2<br />
[ L i , L j ] = i<br />
3∑<br />
ε ijk L k<br />
ε ijk ( Levi–Civita ) ( 237 )<br />
<br />
k=1<br />
⎧<br />
⎪⎨ 0 2 <br />
ε ijk = +1 ijk 123 <br />
⎪⎩<br />
−1 ijk 123 <br />
ε 123 = ε 231 = ε 312 = 1 , ε 132 = ε 213 = ε 321 = −1 , ε ijk = 0<br />
L = r×p <br />
[ L 1 , L 2 ] = iL 3 , [ L 2 , L 3 ] = iL 1 , [ L 3 , L 1 ] = iL 2<br />
<br />
, J <br />
[J x , J y ] = iJ z , [J y , J z ] = iJ x , [J z , J x ] = iJ y (5.5)<br />
<br />
[ J i , J j ] = i ∑ k<br />
ε ijk J k<br />
J ( angular momentum ) J r p <br />
, <br />
, , J <br />
, <br />
5.2 <br />
6 | 〉 2 A, B <br />
| n 〉 , | n 〉 A a n <br />
B b n <br />
A | n 〉 = a n | n 〉 , B | n 〉 = b n | n 〉<br />
|ψ〉 <br />
|ψ〉 = ∑ n<br />
α n | n 〉 ,<br />
α n = 〈 n |ψ〉<br />
a n , b n , α n , A, B <br />
AB |ψ〉 = A ∑ n<br />
α n B | n 〉 = A ∑ n<br />
α n b n | n 〉 = ∑ n<br />
α n b n A | n 〉 = ∑ n<br />
α n b n a n | n 〉
5 76<br />
<br />
BA |ψ〉 = ∑ n<br />
α n a n b n | n 〉<br />
<br />
[ A , B ]|ψ〉 = 0<br />
|ψ〉 [ A , B ] = 0 <br />
, [ A , B ] = 0 A, B | n 〉 a n <br />
A <br />
A | n 〉 = a n | n 〉<br />
AB = BA <br />
AB| n 〉 = BA| n 〉 = a n B| n 〉<br />
B| n 〉 a n A a n , <br />
, a n 1 , B| n 〉 | n 〉 , b<br />
<br />
B| n 〉 = b| n 〉<br />
, | n 〉 B , A B <br />
A a k , a | a, i 〉 , ( i =<br />
1, 2, · · · , k ) <br />
A|a, i 〉 = a |a, i 〉 ,<br />
〈a, i |a, j 〉 = δ ij<br />
AB = BA <br />
AB|a, j 〉 = BA|a, j 〉 = aB|a, j 〉<br />
B|a, j 〉 a A <br />
k∑<br />
B|a, j 〉 = |a, i 〉 b ij , b ij = 〈a, i |B|a, j 〉<br />
i=1<br />
( A, B B|a, j 〉 a A <br />
) (b ij ) {c i }, b :<br />
k∑<br />
b ij c j = b c i , det(b ij − b δ ij ) = 0 (5.6)<br />
j=1<br />
<br />
k∑<br />
|ψ〉 = c j |a, j 〉<br />
, |ψ〉 a A , , (5.6) <br />
k∑<br />
B|ψ〉 = c j B|a, j 〉 =<br />
k∑<br />
c j<br />
j=1<br />
j=1 i=1<br />
j=1<br />
k∑<br />
|a, i 〉 b ij =<br />
k∑ k∑<br />
|a, i 〉 b ij c j = b<br />
i=1 i=1<br />
i=1<br />
k∑<br />
c i |a, i 〉 = b |ψ〉<br />
B , A , <br />
A, B A B
5 77<br />
, , B , <br />
A, B <br />
[ A , B ] = 0 , [ A , C ] = 0 , A A |a〉 <br />
B, C b, c , |a〉 <br />
[ B , C ]|ψ〉 = ∑ a<br />
(BC − CB) |a〉〈a|ψ〉 ∑ a<br />
(bc − cb) |a〉〈a|ψ〉 = 0<br />
[ B , C ] = 0 , A , A <br />
, A, B |ψ ab 〉 A, C |ψ ac 〉 , |ψ ab 〉 <br />
|ψ ac 〉 , |ψ ab 〉 C , |ψ ac 〉 B <br />
[ B , C ] = 0 , [ J 2 , J x ] = 0, [ J 2 , J z ] = 0 J 2 <br />
[ J x , J z ] ≠ 0 <br />
5.3 <br />
(5.2) , <br />
[ J x , J 2 ] = [ J x , Jy 2 + Jz 2 ]<br />
= J y [ J x , J y ] + [ J x , J y ]J y + J z [ J x , J z ] + [ J x , J z ]J z<br />
)<br />
= i<br />
(J y J z + J z J y − J z J y − J y J z = 0<br />
<br />
[J i , ∑ j<br />
J j J j ] = ∑ j<br />
(<br />
)<br />
[J i , J j ] J j + J j [J i , J j ] = i ∑ jk<br />
ε ijk<br />
(<br />
J k J j + J j J k<br />
)<br />
2 j k, k j ε ikj = − ε ijk <br />
[J i , ∑ j<br />
J j J j ] = i ∑ jk<br />
(ε ijk + ε ikj ) J k J j = 0<br />
, J J 2 = J 2 x + J 2 y + J 2 z <br />
2 <br />
J ± = J x ± iJ y ,<br />
J † + = J −<br />
(5.5) <br />
[ J z , J ± ] = [ J z , J x ] ± i [ J z , J y ] = iJ y ± J x = ± J ± (5.7)<br />
[ J + , J − ] = [iJ y , J x ] + [J x , −iJ y ] = −2i [J x , J y ] = 2J z (5.8)<br />
(5.8) J 2 = (J + J − + J − J + )/2 + Jz 2 <br />
J − J + = J 2 − J z (J z + 1) , J + J − = J 2 − J z (J z − 1) (5.9)<br />
<br />
| a 〉 | b 〉 = J k | a 〉 ( k = x, y, z )J k <br />
(1.16) 〈 a |Jk 2| a 〉 = 〈 b | b 〉 ≥ 0
5 78<br />
2 , J 2 J 1 <br />
1 J z J 2 λ <br />
, J z m λ, m |λ m〉 <br />
J 2 |λ m〉 = λ|λ m〉 , J z |λ m〉 = m|λ m〉 , 〈λ m|λ m〉 = 1<br />
J 2 , J z λ, m <br />
〈λ m|J 2 |λ m〉 = λ ≥ 0<br />
| a 〉 = J + |λ m〉 J † + = J − 〈 a | a 〉 = 〈λ m|J − J + |λ m〉 , (5.9)<br />
<br />
〈 a | a 〉 = 〈λ m| ( J 2 − Jz 2 ) )<br />
− J z |λ m〉 = 〈λ m|<br />
(λ − m 2 − m |λ m〉<br />
λ − m 2 − m <br />
〈 a | a 〉 =<br />
(<br />
)<br />
λ − m 2 − m 〈λ m|λ m〉 = λ − m 2 − m ≥ 0 (5.10)<br />
| b 〉 = J − |λ m〉 <br />
〈 b | b 〉 = 〈jm|J + J − |jm〉 = 〈λ m| ( J 2 − J 2 z + J z<br />
)<br />
|λ m〉 = λ − m 2 + m ≥ 0 (5.11)<br />
(5.10), (5.11) <br />
−1 − √ 1 + 4λ<br />
2<br />
≤ m ≤ −1 + √ 1 + 4λ<br />
2<br />
,<br />
1 − √ 1 + 4λ<br />
2<br />
≤ m ≤ 1 + √ 1 + 4λ<br />
2<br />
<br />
− j ≤ m ≤ j , j = −1 + √ 1 + 4λ<br />
2<br />
, λ m m max , m min <br />
− j ≤ m min ≤ m max ≤ j<br />
, m max m min , j λ <br />
λ = (2j + 1)2 − 1<br />
4<br />
= j(j + 1) , j ≥ 0<br />
λ j :<br />
J 2 |jm〉 = j(j + 1)|jm〉 ,<br />
J z |jm〉 = m|jm〉<br />
J ± J 2 <br />
J 2 J ± |jm〉 = J ± J 2 |jm〉 = j(j + 1)J ± |jm〉<br />
(5.7) <br />
J z J ± |jm〉 = (J ± J z ± J ± ) |jm〉 = (m ± 1)J ± |jm〉<br />
J ± |jm〉 J 2 , J z<br />
, j(j + 1), m ± 1 <br />
J + |jm max 〉 ̸= 0 J + |jm max 〉 J z m max + 1 m max
5 79<br />
J + |jm max 〉 = 0 J − |jm min 〉 = 0 <br />
, (5.10), (5.11) <br />
j(j + 1) − m 2 max − m max = 0 , j(j + 1) − m 2 min + m min = 0<br />
m max = j, m min = −j |jm max 〉 J − , J− 2 , · · · , J− n , J z <br />
m max − 1 , m max − 2 , · · · , m max − n , m max − n = m min n <br />
m max = j, m min = −j 2j = n, , 2j <br />
, <br />
J 2 |jm〉 = j(j + 1)|jm〉 , j = 0, 1/2, 1, 3/2, 2, · · · (5.12)<br />
J z |jm〉 = m|jm〉 , m = −j, −j + 1, · · · , j − 1, j (5.13)<br />
(1.18) <br />
〈jm|j ′ m ′ 〉 = δ jj ′ δ mm ′ (5.14)<br />
, √ j(j + 1) , j <br />
j J 2 j(j + 1) <br />
| a 〉 = J + |jm〉 J 2 , J z , j(j + 1), m + 1 , <br />
|j m+1〉 c jm | a 〉 = c jm |j m+1〉 <br />
〈 a | a 〉 = |c jm | 2 〈j m+1|j m+1〉 = |c jm | 2<br />
(5.10) <br />
|c jm | 2 = (j − m)(j + m + 1)<br />
c jm c jm <br />
<br />
J − (5.9) <br />
J + |jm〉 = √ (j − m)(j + m + 1) |j m+1〉 (5.15)<br />
J − |jm〉 = √ (j + m)(j − m + 1) |j m−1〉 (5.16)<br />
J + J z 1 , J − , <br />
<br />
(5.15) (5.16) , 1 |j m 0 〉 2j + 1 <br />
|jm〉 <br />
|j j−1〉 = 1 √ 2j<br />
J − |j j〉<br />
|j j−2〉 =<br />
|j j−3〉 =<br />
1<br />
1<br />
√ J − |j j−1〉 = √ (J − ) 2 |j j〉<br />
(2j − 1)·2 2j(2j − 1)·2<br />
1<br />
1<br />
√ J − |j j−2〉 = √ (J − ) 3 |j j〉<br />
(2j − 2)·3 2j(2j − 1)(2j − 2)·3·2<br />
, <br />
|j j−k〉 =<br />
√<br />
1<br />
√ (J − ) k (2j − k)!<br />
|j j〉 =<br />
(J − ) k |j j〉<br />
2j(2j − 1) · · · (2j − k + 1) k! (2j)! k!
5 80<br />
m = j − k <br />
<br />
<br />
√<br />
(j + m)!<br />
|jm〉 =<br />
(2j)! (j − m)! (J −) j−m | j j 〉 (5.17)<br />
√<br />
(j − m)!<br />
|jm〉 =<br />
(2j)! (j + m)! (J +) j+m | j −j 〉 (5.18)<br />
−i ∇ 3 , ,<br />
, 3 exp(ik·r) , J , J x ,<br />
J y , J z ( j = 0 )<br />
|jm〉 J z , <br />
J x , J y <br />
∆J k =<br />
√<br />
〈 jm |J 2 k | jm 〉 − 〈 jm |J k| jm 〉 2<br />
J x = (J + + J − )/2 (5.15), (5.16) <br />
J x |jm〉 = 1 (<br />
)<br />
c + |j m+1〉 + c − |j m−1〉 , c ± = √ (j ∓ m)(j ± m + 1)<br />
2<br />
〈jm|jm ′ 〉 = δ mm ′ <br />
〈jm|J x |jm〉 = 1 (<br />
)<br />
c + 〈jm|j m+1〉 + c − 〈jm|j m−1〉 = 0 , 〈jm|J y |jm〉 = 0<br />
2<br />
|ψ〉 = J x |jm〉 〈ψ|ψ〉 = 〈jm|Jx|jm〉 2 <br />
〈jm|Jx|jm〉 2 = 1 (<br />
)<br />
c 2<br />
4<br />
+〈j m+1|j m+1〉 + c 2 −〈j m−1|j m−1〉<br />
+ c (<br />
)<br />
+c −<br />
〈j m−1|j m+1〉 + 〈j m+1|j m−1〉<br />
4<br />
= c2 + + c 2 −<br />
4<br />
=<br />
j(j + 1) − m2<br />
2<br />
, 〈jm|J 2 x|jm〉 = 〈jm|J 2 y |jm〉 <br />
〈jm|J 2 x|jm〉 = 〈jm|J 2 y |jm〉 = 1 2 〈jm|(J 2 − J 2 z )|jm〉 =<br />
j(j + 1) − m2<br />
2<br />
<br />
√<br />
j(j + 1) − m<br />
2<br />
∆J x = ∆J y =<br />
2<br />
|m| ≤ j ∆J x = ∆J y = 0 j = m = 0 , , J z J x ,<br />
J y <br />
∆J x ∆J y =<br />
j(j + 1) − m2<br />
2<br />
≥<br />
|m|(|m| + 1) − m2<br />
2<br />
(1.27) <br />
= |m|<br />
2 = 1 ∣<br />
∣〈 jm |[ J x , J y ]| jm 〉 ∣<br />
2<br />
, z J 2 z = J 2 <br />
m 2 = j(j + 1) , , m 2 = j(j + 1) <br />
( j = 0 ), j → ∞ j(j + 1) ≈ j 2 , |j ±j 〉 <br />
z
5 81<br />
5.4 <br />
<br />
z<br />
P(x, y, z)<br />
3 e r , e θ , e φ <br />
e φ xy P r <br />
, <br />
θ , φ <br />
e r = e x sin θ cos φ + e y sin θ sin φ + e z cos θ<br />
e θ = e x cos θ cos φ + e y cos θ sin φ − e z sin θ (5.19)<br />
e φ = − e x sin φ + e y cos φ<br />
x<br />
φ<br />
θ<br />
e θ<br />
e r<br />
e φ<br />
θ<br />
φ<br />
y<br />
x ′<br />
∂ x = ∂<br />
∂x ∇ ≡ e x ∂ x + e y ∂ y + e z ∂ z <br />
f(r) <br />
df = dx ∂ x f + dy ∂ y f + dz ∂ z f =<br />
) (<br />
)<br />
(dx e x + dy e y + dz e z · e x ∂ x f + e y ∂ y f + e z ∂ z f<br />
= dr·∇f (5.20)<br />
, r = re r , e r θ, φ <br />
)<br />
dr = dr e r + r de r = dr e r + r<br />
(dθ ∂ θ e r + dφ ∂ φ e r = dr e r + r dθ e θ + r sin θ dφ e φ<br />
f(r) r, θ, φ <br />
(5.20) <br />
df = dr ∂ r f + dθ ∂ θ f + dφ ∂ φ f<br />
) (<br />
1<br />
=<br />
(dr e r + r dθ e θ + r sin θ dφ e φ · e r ∂ r f + e θ<br />
(<br />
)<br />
1<br />
= dr· e r ∂ r + e θ<br />
r ∂ 1<br />
θ + e φ<br />
r sin θ ∂ φ f<br />
r ∂ θf + e φ<br />
1<br />
)<br />
r sin θ ∂ φf<br />
∇ = e r ∂ r + e θ<br />
1<br />
r ∂ θ + e φ<br />
1<br />
r sin θ ∂ φ (5.21)<br />
e r ×e θ = e φ , e φ ×e r = e θ <br />
(<br />
) (<br />
)<br />
1<br />
L = − i re r × e r ∂ r + e θ<br />
r ∂ 1<br />
θ + e φ<br />
r sin θ ∂ 1<br />
φ = − i e φ ∂ θ − e θ<br />
sin θ ∂ θ<br />
(5.19) <br />
<br />
<br />
L = ie x<br />
(<br />
sin φ ∂ θ + cot θ cos φ ∂ φ<br />
)<br />
− ie y<br />
(<br />
cos φ ∂ θ − cot θ sin φ ∂ φ<br />
)<br />
− ie z ∂ φ (5.22)<br />
(<br />
L ± ≡ L x ± iL y = e ±iφ ± ∂ ∂θ + i cot θ ∂ )<br />
, L z = − i ∂<br />
∂φ<br />
∂φ<br />
L 2 = L +L − + L − L +<br />
2<br />
(5.23)<br />
+ L 2 z = − ∂2<br />
∂θ 2 − cot θ ∂ ∂θ − 1 ∂ 2<br />
sin 2 θ ∂φ 2 (5.24)<br />
, r
5 82<br />
<br />
, j l L = − i r×∇ θ, φ <br />
, θ, φ Y lm (θ, φ)<br />
L 2 Y lm (θ, φ) = l(l + 1) Y lm (θ, φ) , L z Y lm (θ, φ) = m Y lm (θ, φ)<br />
, f(r) ψ(r) = f(r)Y lm (θ, φ) L 2 , L z f(r)<br />
, , ψ(r) <br />
L z = −i∂/∂φ <br />
−i ∂Y lm(θ, φ)<br />
∂φ<br />
= m Y lm (θ, φ) , ∴ Y lm (θ, φ) = F lm (θ) e imφ<br />
r 1 Y lm (θ, φ) = Y lm (θ, φ + 2π), e 2πim = 1 <br />
, m l <br />
, l , 1 , <br />
l <br />
<br />
L 2 F lm (θ) e imφ = l(l + 1) F lm (θ) e imφ<br />
F lm (θ) (5.24) <br />
(− d2<br />
dθ 2 − cot θ d )<br />
dθ +<br />
m2<br />
sin 2 F lm (θ) = l(l + 1) F lm (θ)<br />
θ<br />
(15.25) , <br />
L − Y l −l = L − F l −l (θ) e −ilφ = 0<br />
F l −l (θ) , L + Y l −l (θ, φ) Y lm (θ, φ) ( L + Y l l = 0 )<br />
, L ± Y l ±l = 0, L z Y l ±l = ± l Y l ±l <br />
L 2 Y l ±l = ( L ∓ L ± + L 2 z ± L z<br />
)<br />
Yl ±l = l(l + 1)Y l ±l<br />
, L 2 Y l ±l = l(l + 1)Y l ±l , L − Y l −l = 0 <br />
(5.23) L − F (θ) e −ilφ = 0 ( F l −l (θ) F (θ) )<br />
<br />
∫ ∫<br />
∫<br />
dF<br />
F<br />
= l dθ cot θ = l dθ<br />
<br />
<br />
<br />
∫ π<br />
|C| 2 dθ sin θ<br />
0<br />
∫ 2π<br />
0<br />
(sin θ)′<br />
sin θ<br />
∫<br />
d 3 r · · · =<br />
∫ π<br />
0<br />
dF<br />
dθ − l cot θ F = 0<br />
∫ ∞<br />
0<br />
dθ sin θ<br />
= l log | sin θ | , ∴ F (θ) = C sin l θ , C = <br />
∫ π<br />
dr r 2 dθ sin θ<br />
∫ 2π<br />
dφ sin 2l θ = 2π|C| 2 I l = 1 ,<br />
0<br />
0<br />
∫ 2π<br />
dφ |Y lm (θ, φ)| 2 = 1<br />
I l ≡<br />
0<br />
∫ π<br />
0<br />
dφ · · ·<br />
dθ sin 2l+1 θ =<br />
∫ 1<br />
−1<br />
dt (1 − t 2 ) l
5 83<br />
t = cos θ <br />
I l = [ t(1 − t 2 ) l ] ∫ 1<br />
1<br />
−1 − dt t d dt (1 − t2 ) l = 2l<br />
−1<br />
∫ 1<br />
−1<br />
dt t 2 (1 − t 2 ) l−1 = 2l (− I l + I l−1 )<br />
<br />
I l =<br />
2l<br />
2l + 1 I 2l · 2(l − 1)<br />
l−1 =<br />
(2l + 1)(2l − 1) I l−2<br />
=<br />
2l · 2(l − 1) · 2(l − 2) · · · 2<br />
(2l + 1)(2l − 1)(2l − 3) · · · 3 I 0 = 2<br />
(<br />
2 l l! ) 2<br />
(2l + 1)!<br />
(5.25)<br />
<br />
Y l −l (θ, φ) = F (θ)e −ilφ = 1<br />
√<br />
(2l + 1)!<br />
2 l l! 4π<br />
C , C <br />
(5.18), (5.26) <br />
sin l θ e −ilφ (5.26)<br />
√<br />
Y lm (θ, φ) = 1 2l + 1 (l − m)!<br />
2 l l! 4π (l + m)! (L +) l+m sin l θ e −ilφ (5.27)<br />
L + , (5.23) <br />
( ∂<br />
L + f(θ)e inφ = e iφ ∂θ + i cot θ ∂ )<br />
( )<br />
df(θ)<br />
f(θ)e inφ = e i(n+1)φ − n cot θ f(θ)<br />
∂φ<br />
dθ<br />
( t = cos θ )<br />
d<br />
dt f(θ) sin−n θ =<br />
dθ<br />
d cos θ<br />
( )<br />
d<br />
df(θ)<br />
dθ f(θ) sin−n θ = − sin −n−1 θ − n cot θ f(θ)<br />
dθ<br />
<br />
L + f(θ)e inφ = g(θ)e i(n+1)φ , g(θ) = − sin n+1 θ d dt f(θ) sin−n θ (5.28)<br />
L + , f → g, n → n + 1 <br />
(L + ) 2 f(θ)e inφ = L + g(θ)e i(n+1)φ = − e i(n+2)φ sin n+2 θ d dt sin−n−1 θ g(θ)<br />
<br />
= (−1) 2 e i(n+2)φ sin n+2 θ d2<br />
dt 2 f(θ) sin−n θ<br />
(L + ) k f(θ)e inφ = (−1) k e i(n+k)φ sin n+k θ dk<br />
dt k f(θ) sin−n θ (5.29)<br />
n = − l, f(θ) = sin l θ, k = l + m , (5.27) <br />
√<br />
<br />
Y lm (θ, φ) = (−1)l+m<br />
2 l l!<br />
√<br />
= (−1) m<br />
P m l (x) = 1<br />
2 l l!<br />
( ) l+m<br />
2l + 1 (l − m)!<br />
d<br />
4π (l + m)! eimφ sin m θ<br />
sin 2l θ<br />
d cos θ<br />
2l + 1 (l − m)!<br />
4π (l + m)! eimφ Pl m (cos θ) (5.30)<br />
(<br />
1 − x<br />
2 ) m/2 d l+m<br />
dx l+m (x2 − 1) l , − l ≤ m ≤ l , |x| ≤ 1 (5.31)
5 84<br />
Y lm (θ, φ) , Pl<br />
m(x) ( Legendre ) , P l 0(x)<br />
P l (x) P l (x) l <br />
250 15.2 255 15.3 <br />
Y 00 = √ 1<br />
√ √<br />
3<br />
3<br />
, Y 1 ±1 = ∓<br />
4π 8π sin θ e±iφ , Y 10 =<br />
4π cos θ<br />
Y 2 ±2 =<br />
<br />
√<br />
15<br />
32π sin2 θ e ±2iφ ,<br />
√<br />
15<br />
Y 2 ±1 = ∓<br />
8π sin θ cos θ e± iφ , Y 20 =<br />
√<br />
5 (<br />
3 cos 2 θ − 1 )<br />
16π<br />
|Y lm (θ, φ)| 2 φ z ,<br />
l = 0 |Y 00 | 2 = 1/(4π) <br />
() θ |Y lm (θ, φ)| 2 , l = 2, 3 <br />
( 1 0.5 )<br />
θ<br />
|Y lm | 2<br />
r(t), p(t) , L cl<br />
L cl = r(t)×p(t) L cl , r(t) L cl , <br />
L cl m = ± l , L cl z <br />
xy m = ± l xy (5.26)<br />
|Y l ±l | 2 ∝ sin 2l θ l → ∞ θ ≠ π/2 |Y l ±l | 2 = 0 , , xy <br />
m 0 , L cl z <br />
, |Y lm | 2 xy m = 0 L cl z <br />
, |Y l 0 | 2 z <br />
32π<br />
15 |Y 2 ±2| 2 32π<br />
15 |Y 2 ±1| 2 4π<br />
5 |Y 2 0| 2<br />
64π<br />
35 |Y 3 ±3| 2 72π<br />
35 |Y 3 ±2| 2 45π<br />
28 |Y 3 ±1| 2 4π<br />
7 |Y 3 0| 2<br />
5.1<br />
5.2<br />
x , y , z rY 1m <br />
ψ x (r) = xf(r) , ψ y (r) = yf(r) , ψ z (r) = zf(r)
5 85<br />
(<br />
1. L x ψ x (r) = − i y ∂ ∂z − z ∂ )<br />
ψ x (r) ψ x (r) L x <br />
∂y<br />
ψ y (r) , ψ z (r) L y , L z <br />
2. L y ψ x (r) = − i ψ z (r) , L z ψ x (r) = i ψ y (r) ψ y , ψ z ,<br />
ψ x , ψ y , ψ z L 2 <br />
3. ψ x , ψ y , ψ z Y 1m <br />
5.5 <br />
,<br />
<br />
Hψ(r) = E ψ(r) ,<br />
H = − 2<br />
2m ∇2 + V (r)<br />
{ ϕ n (r) } ψ(r) ϕ n (r) <br />
<br />
|ψ〉 = ∑ n<br />
c n | n 〉<br />
, ϕ ∗ m(r) <br />
∑<br />
〈 m |H| n 〉c n = E ∑ 〈 m | n 〉 c n = E c m<br />
n<br />
n<br />
, 〈 m | n 〉 = δ mn h mn = 〈 m |H| n 〉 , <br />
⎛<br />
⎞ ⎛ ⎞ ⎛ ⎞<br />
h 11 h 12 h 13 · · · c 1<br />
c 1<br />
⎜ h<br />
⎝ 21 h 22 h 23 · · · ⎟ ⎜ c<br />
⎠ ⎝ 2 ⎟<br />
⎠ .<br />
. . . ..<br />
. = E ⎜ c<br />
⎝ 2 ⎟<br />
⎠<br />
. (h mn ) , H <br />
<br />
〈 m |H| n 〉 ∗ = 〈 n |H † | m 〉 = 〈 n |H| m 〉 h ∗ mn = h nm<br />
, (h mn ) <br />
2 ψ α , ψ β A 〈ψ α |A|ψ β 〉 <br />
|ψ α 〉 = ∑ n<br />
α n | n 〉 ,<br />
|ψ β 〉 = ∑ n<br />
β n | n 〉<br />
<br />
∫<br />
〈ψ α |A|ψ β 〉 =<br />
d 3 r ψ ∗ α(r)Aψ β (r) = ∑ mn<br />
α ∗ mβ n<br />
∫<br />
d 3 r ϕ ∗ m(r)Aϕ n (r)<br />
= ∑ mn<br />
α ∗ m〈 m |A| n 〉β n (5.32)<br />
a mn = 〈 m |A| n 〉 <br />
⎛<br />
〈ψ α |A|ψ β 〉 = ∑ αma ∗ mn β n = ( α1 ∗ α2 ∗ · · · ) ⎜<br />
⎝<br />
mn<br />
⎞ ⎛<br />
a 11 a 12 a 13 · · ·<br />
a 21 a 22 a 23 · · · ⎟ ⎜<br />
⎠ ⎝<br />
.<br />
. . . ..<br />
β 1<br />
β 2<br />
.<br />
⎞<br />
⎟<br />
⎠ (5.33)
5 86<br />
, <br />
⎛ ⎞<br />
α =<br />
⎜<br />
⎝<br />
α 1<br />
α 2<br />
.<br />
⎟<br />
⎠ ,<br />
⎛<br />
β = ⎜<br />
⎝<br />
β 1<br />
β 2<br />
.<br />
⎞<br />
⎟<br />
⎠ ,<br />
⎛<br />
A = ⎜<br />
⎝<br />
⎞<br />
a 11 a 12 a 13 · · ·<br />
a 21 a 22 a 23 · · · ⎟<br />
⎠<br />
.<br />
.<br />
.<br />
. ..<br />
<br />
〈ψ α |A|ψ β 〉 = α † A β , 〈ψ α |ψ β 〉 = α † β (5.34)<br />
<br />
→ , → , → (5.35)<br />
, , <br />
{ϕ n } , , <br />
ϕ n :<br />
⎛ ⎞<br />
0<br />
.<br />
ϕ n →<br />
1<br />
⎜<br />
⎝ .<br />
⎟<br />
⎠<br />
0<br />
n <br />
{ϕ n } <br />
, (5.32) <br />
α ∗ m = 〈 m |ψ α 〉 ∗ = 〈ψ α | m 〉 , β n = 〈 n |ψ β 〉<br />
<br />
〈ψ α |A|ψ β 〉 = ∑ mn〈ψ α | m 〉〈 m |A| n 〉〈 n |ψ β 〉<br />
<br />
, <br />
(∑ )<br />
〈ψ α |A|ψ β 〉 = 〈ψ α | | m 〉〈 m | A<br />
m<br />
(∑<br />
n<br />
)<br />
| n 〉〈 n | |ψ β 〉<br />
∑<br />
| n 〉〈 n | = 1 (5.36)<br />
, (5.36) , (5.32) <br />
∑<br />
mn<br />
α ∗ m〈 m |A| n 〉β n = ∑ mn<br />
n<br />
〈ψ α | m 〉〈 m |A| n 〉〈 n |ψ β 〉 = 〈ψ α |A|ψ β 〉 (5.37)<br />
, (5.36) | a 〉 <br />
(∑ )<br />
| a 〉 = | n 〉〈 n | | a 〉 = ∑ n<br />
n<br />
| n 〉〈 n | a 〉<br />
(1.21) (5.36) (1.22)<br />
∑<br />
ϕ n (r) ϕ ∗ n(r ′ ) = δ(r − r ′ ) (5.38)<br />
n
5 87<br />
, { ϕ n (r) } , <br />
, (5.37) <br />
∑<br />
αm〈 ∗ m |A| n 〉β n<br />
mn<br />
= ∑ ∫<br />
∫<br />
∫<br />
d 3 r 1 ψa(r ∗ 1 )ϕ m (r 1 ) d 3 r 2 ϕ ∗ m(r 2 )A(r 2 , p 2 )ϕ n (r 2 ) d 3 r 3 ϕ ∗ n(r 3 )ψ b (r 3 )<br />
mn } {{ } } {{ } } {{ }<br />
αm<br />
∗ 〈 m |A| n 〉<br />
β n<br />
∫<br />
(∑<br />
) (∑<br />
)<br />
= d 3 r 1 d 3 r 2 d 3 r 3 ψa(r ∗ 1 ) ϕ m (r 1 )ϕ ∗ m(r 2 ) A(r 2 , p 2 ) ϕ n (r 2 )ϕ ∗ n(r 3 ) ψ b (r 3 )<br />
m<br />
(5.38) <br />
∑<br />
∫<br />
αm〈 ∗ m |A| n 〉β n = d 3 r 1 d 3 r 2 d 3 r 3 ψa(r ∗ 1 )δ(r 1 − r 2 ) A(r 2 , p 2 ) δ(r 2 − r 3 ) ψ b (r 3 )<br />
mn<br />
<br />
∫ ∫<br />
= d 3 r 2<br />
∫<br />
d 3 r 1 ψa(r ∗ 1 )δ(r 1 − r 2 ) A(r 2 , p 2 ) d 3 r 3 δ(r 2 − r 3 ) ψ b (r 3 )<br />
∫<br />
= d 3 r 2 ψa(r ∗ 2 )A(r 2 , p 2 )ψ b (r 2 ) = 〈ψ α |A|ψ β 〉<br />
J 2 , J z |jm〉 <br />
<br />
| n 〉 = | j , m=j+1−n 〉 , n = 1, 2, · · · , 2j + 1<br />
j J x <br />
J x = (J + + J − )/2 (5.15), (5.16) J x <br />
〈 n | J x | n ′ 〉 = 1 2 〈 m=j+1−n | J + | m=j+1−n ′ 〉 + 1 2 〈 m=j+1−n | J − | m=j+1−n ′ 〉<br />
n<br />
= 1 2√<br />
(n′ − 1)(2j + 2 − n ′ ) 〈 m=j+1−n | m=j+2−n ′ 〉<br />
+ 1 2√<br />
n′ (2j + 1 − n ′ ) 〈 m=j+1−n | m=j−n ′ 〉<br />
<br />
= 1 2<br />
j = 1 <br />
<br />
〈 n | J x | n ′ 〉 = 1 2<br />
〈 n | J x | 1 〉 = 1 2<br />
√<br />
(n′ − 1)(2j + 2 − n ′ ) δ n n′ −1 + 1 2<br />
√<br />
(n′ − 1)(4 − n ′ ) δ n n′ −1 + 1 2<br />
√<br />
n′ (2j + 1 − n ′ ) δ n n′ +1<br />
√<br />
n′ (3 − n ′ ) δ n n′ +1 , n , n ′ = 1, 2, 3<br />
√<br />
2 δn 2 , 〈 n | J x | 2 〉 = 1 2√<br />
2<br />
(δ n 1 + δ n 3<br />
)<br />
, 〈 n | J x | 3 〉 = 1 2√<br />
2 δn 2<br />
J x <br />
⎛<br />
1 ⎜<br />
√ ⎝ 2<br />
0 1 0<br />
1 0 1<br />
0 1 0<br />
⎞<br />
⎟<br />
⎠
5 88<br />
<br />
〈 n | J z | n ′ 〉 = 〈 m=j+1−n | J z | m=j+1−n ′ 〉 =<br />
( )<br />
j + 1 − n δ nn ′<br />
J z <br />
J x m x , | m x 〉 <br />
J x | m x 〉 = m x | m x 〉 , |m x 〉 =<br />
2j+1<br />
∑<br />
n=1<br />
c n |n〉 (5.39)<br />
j = 1 , <br />
⎛<br />
1 ⎜<br />
√ ⎝ 2<br />
0 1 0<br />
1 0 1<br />
0 1 0<br />
⎞ ⎛<br />
⎟ ⎜<br />
⎠ ⎝<br />
c 1<br />
c 2<br />
c 3<br />
⎞ ⎛<br />
⎟ ⎜<br />
⎠ = m x ⎝<br />
c 1<br />
c 2<br />
c 3<br />
⎞<br />
⎟<br />
⎠<br />
<br />
⎛<br />
⎜<br />
⎝<br />
− m x 1/ √ ⎞ ⎛<br />
2 0<br />
1/ √ 2 − m x 1/ √ ⎟ ⎜<br />
2<br />
0 1/ √ ⎠ ⎝<br />
2 − m x<br />
c 1 = c 2 = c 3 = 0 <br />
− m x 1/ √ ∣<br />
2 0 ∣∣∣∣∣∣ 1/ √ 2 − m x 1/ √ 2<br />
∣ 0 1/ √ = −m 3 x + m x = 0<br />
2 − m x<br />
m x = 0 , ±1 J z <br />
5.3 m x = 0, ±1 <br />
|m x =0〉 = √ 1<br />
)<br />
(|m=1〉 − |m=−1〉 , |m x =±1〉 = 1 2 2<br />
c 1<br />
c 2<br />
c 3<br />
⎞<br />
⎟<br />
⎠ = 0 (5.40)<br />
(<br />
|m=1〉 ± √ )<br />
2 |m=0〉 + |m=−1〉<br />
c 1 , <br />
5.6 <br />
l , (5.5) , <br />
j 1/2, 3/2, · · · <br />
, <br />
j = 1/2 , , <br />
, , 1/2 , 1 <br />
<br />
, 3 <br />
, 3 <br />
l , <br />
<br />
J S S (5.5)<br />
[S x , S y ] = iS z , [S y , S z ] = iS x , [S z , S x ] = iS y
5 89<br />
S r ˆp <br />
S s <br />
S 2 |s m s 〉 = s(s + 1)|s m s 〉 , S z |s m s 〉 = m s |s m s 〉 , m s = −s, −s + 1, · · · , s (5.41)<br />
S 2 , S z |s m s 〉 |s m s 〉 ,<br />
|s m s 〉 r (5.41) <br />
, , <br />
∑<br />
m s<br />
ψ ms (r, t) |s m s 〉<br />
ψ ms (r, t) ψ ms (r, t) r , <br />
, ( s = 0 ) , ψ(r, t)<br />
<br />
s = 1/2 m s ±1/2 2 , <br />
<br />
|+〉 = |s= 1 2 , m s = 1 2 〉 , |−〉 = |s= 1 2 , m s =− 1 2 〉<br />
|+〉, |−〉 2 , 2 <br />
<br />
<br />
ψ + (r, t)|+〉 + ψ − (r, t)|−〉 (5.42)<br />
S j = 1/2 S <br />
<br />
S = 1 2 σ<br />
σ S 2 |±〉 = 3 4 |±〉 σ2 |±〉 = 3 |±〉 <br />
, |ψ〉 = ψ + |+〉 + ψ − |−〉 <br />
σ 2 |ψ〉 = ψ + σ 2 |+〉 + ψ − σ 2 |−〉 = 3 |ψ〉<br />
σ 2 = 3 σ 2 z|±〉 = |±〉 σ 2 z = 1 (5.15), (5.16) j = 1/2 <br />
( σ ± = σ x ± i σ y )<br />
σ + |+〉 = 0 , σ + |−〉 = 2|+〉 , σ − |+〉 = 2|−〉 , σ − |−〉 = 0 (5.43)<br />
σ 2 +|±〉 = 0 , σ 2 −|±〉 = 0 <br />
)<br />
σ± 2 = σx 2 − σy 2 ± i<br />
(σ x σ y + σ y σ x = 0 , ∴ σx 2 = σy 2 , σ x σ y + σ y σ x = 0<br />
σ 2 x + σ 2 y = σ 2 − σ 2 z = 2 σ 2 x = σ 2 y = 1 σ x σ y + σ y σ x = 0 <br />
σ x σ y − σ y σ x = 2iσ z <br />
σ x σ y = − σ y σ x = iσ z<br />
σ x σ y = iσ z σ y σ z σ y = − iσ x <br />
σ y σ z = − σ z σ y = iσ x ,<br />
σ z σ x = − σ x σ z = iσ y
5 90<br />
<br />
σ i σ j = δ ij + i ∑ k<br />
ε ijk σ k (5.44)<br />
<br />
<br />
( )<br />
( )<br />
1<br />
0<br />
|+〉 =⇒ , |−〉 =⇒<br />
0<br />
1<br />
(5.45)<br />
(5.42) <br />
ψ(r, t) =<br />
(<br />
ψ + (r, t)<br />
ψ − (r, t)<br />
)<br />
2 ψ(r, t) , <br />
(5.34) <br />
∫<br />
∫<br />
d 3 r ψ † (r, t)ψ(r, t) =<br />
∫<br />
=<br />
d 3 r ( ψ ∗ +(r, t) ψ ∗ −(r, t) ) ( ψ + (r, t)<br />
ψ − (r, t)<br />
(<br />
d 3 r |ψ + (r, t)| 2 + |ψ − (r, t)| 2) = 1<br />
|ψ + (r, t)| 2 d 3 r ( m s = 1/2 ) r d 3 r <br />
|ψ − (r, t)| 2 d 3 r <br />
, , ψ + (r, t) ψ − (r, t) r , <br />
( )<br />
c + (t)<br />
ψ(r, t)<br />
(5.46)<br />
c − (t)<br />
c ± (t) r <br />
(<br />
|c+ (t)| 2 + |c − (t)| 2) ∫ d 3 r |ψ(r, t)| 2 = 1<br />
)<br />
<br />
|c + (t)| 2 + |c − (t)| 2 = 1 ,<br />
∫<br />
d 3 r |ψ(r, t)| 2 = 1<br />
<br />
σ σ (5.45) σ <br />
(<br />
)<br />
〈+|σ|+〉 〈+|σ|−〉<br />
σ =<br />
〈−|σ|+〉 〈−|σ|−〉<br />
(5.43) <br />
σ + =<br />
(<br />
0 2<br />
0 0<br />
)<br />
, σ − =<br />
(<br />
0 0<br />
2 0<br />
)<br />
, σ z =<br />
(<br />
1 0<br />
0 −1<br />
)<br />
σ x = (σ + + σ − )/2, σ y = −i(σ + − σ − )/2 <br />
( ) ( ) (<br />
0 1<br />
0 − i<br />
σ x =<br />
, σ y =<br />
, σ z =<br />
1 0<br />
i 0<br />
1 0<br />
0 −1<br />
)<br />
(5.47)<br />
( Pauli matrix ) (5.44), (5.48) <br />
2 × 2 1 , 2 × 2 I , , σ 2 x = I <br />
, I 1 , σ 2 x = 1
5 91<br />
5.4<br />
(5.44) <br />
σ·A σ·B = A·B + i σ·(A×B) (5.48)<br />
A, B σ <br />
5.5<br />
<br />
n σ n ≡ n·σ σ 2 n = 1 <br />
exp(iθ σ n ) = cos θ + i σ n sin θ (5.49)<br />
, A e A <br />
e A =<br />
∞∑<br />
k=0<br />
A k<br />
k!<br />
(5.50)<br />
<br />
5.6<br />
5.7<br />
2 × 2 σ·A σ·B (5.48) <br />
<br />
σ x σ y σ z = i , Tr σ k = 0 , Tr(σ i σ j ) = 2δ ij , det σ i = − 1<br />
<br />
n σ n = n·σ n <br />
<br />
n = e x sin θ cos φ + e y sin θ sin φ + e z cos θ<br />
σ n = σ x sin θ cos φ + σ y sin θ sin φ + σ z cos θ =<br />
σ n m , χ m =<br />
(<br />
cos θ − m<br />
e iφ sin θ<br />
(<br />
(<br />
cos θ<br />
e iφ sin θ<br />
e −iφ sin θ<br />
− cos θ<br />
)<br />
c +<br />
σ n χ m = m χ m <br />
c −<br />
e −iφ sin θ<br />
− cos θ − m<br />
) (<br />
)<br />
(5.51)<br />
)<br />
c +<br />
= 0 (5.52)<br />
c −<br />
, c + = c − = 0 <br />
cos θ − m e −iφ sin θ<br />
∣ e iφ sin θ − cos θ − m<br />
∣ = m2 − 1 = 0<br />
m = ±1 σ n σ 2 n = 1 , m m 2 = 1 <br />
, (5.52) <br />
iφ m − cos θ<br />
c − = c + e<br />
sin θ<br />
1 − cos θ = 2 sin 2 (θ/2), 1 + cos θ = 2 cos 2 (θ/2) <br />
⎧<br />
⎨ c + e iφ tan(θ/2) , m = 1<br />
c − =<br />
⎩ − c + e iφ cot(θ/2) , m = − 1
5 92<br />
|c + | 2 + |c − | 2 = 1 <br />
⎧<br />
⎨ e iα cos(θ/2) , m = 1<br />
c + =<br />
⎩ e iβ sin(θ/2) , m = − 1<br />
α, β α = β = 0 , n·σ ± 1 χ ± <br />
(<br />
)<br />
(<br />
)<br />
cos(θ/2)<br />
sin(θ/2)<br />
χ + (θ, φ) =<br />
, χ<br />
e iφ − (θ, φ) =<br />
(5.53)<br />
sin(θ/2)<br />
− e iφ cos(θ/2)<br />
, <br />
χ † +χ − = ( cos(θ/2) e −iφ sin(θ/2) ) (<br />
)<br />
sin(θ/2)<br />
= 0 ,<br />
− e iφ cos(θ/2)<br />
∴ χ † mχ m ′ = δ mm ′<br />
χ + χ − , θ , φ r <br />
, n <br />
θ → π − θ , φ → π + φ n → − n <br />
(−n)·σ χ + (π − θ, π + φ) = + χ + (π − θ, π + φ) , ∴ σ n χ + (π − θ, π + φ) = − χ + (π − θ, π + φ)<br />
<br />
χ + (π − θ, π + φ) = e iα χ − (θ, φ) ,<br />
α = <br />
, (5.53) χ + (π − θ, π + φ) = χ − (θ, φ) <br />
θ = 0 σ n = σ z , ± 1 σ z χ ± (z) <br />
( )<br />
( )<br />
1<br />
χ + (z) = , χ − (z) = − e iφ 0<br />
0<br />
1<br />
− e iφ β = π − φ , θ = 0 , φ <br />
n z φ = π <br />
θ = π/2 , φ = 0 σ n = σ x , ± 1 σ x χ ± (x) <br />
( )<br />
χ ± (x) = √ 1 1<br />
|+〉 ± |−〉<br />
, √ (5.54)<br />
2 ± 1<br />
2<br />
(5.47) σ x θ = π/2 , φ = π/2 ± 1<br />
σ y χ ± (y) <br />
<br />
(<br />
χ ± (y) = √ 1<br />
2<br />
1<br />
± i<br />
)<br />
, <br />
|+〉 ± i |−〉<br />
√<br />
2<br />
χ ± (θ, φ) σ 〈σ〉 ± , (5.33) 〈σ x 〉 + = χ † +σ x χ + (5.53) <br />
<br />
〈σ x 〉 + = ( cos(θ/2) e −iφ sin(θ/2) ) ( 0 1<br />
1 0<br />
〈σ y 〉 + = sin θ sin φ , 〈σ z 〉 + = cos θ <br />
) (<br />
cos(θ/2)<br />
e iφ sin(θ/2)<br />
)<br />
= sin θ cos φ<br />
〈σ〉 ± = ± n (5.55)
5 93<br />
χ − − n·σ + 1 , n − n χ ± σ<br />
± n , , σ x , σ y , σ z , 3 <br />
n ′ σ n ′<br />
χ ± (θ, φ) ∆σ ± (σ n ′) 2 = 1 , 〈σ n ′〉 ± = ± n ′·n <br />
√<br />
∆σ ± = 〈(σ n ′) 2 〉 ± − 〈σ n ′〉 2 ± = √ 1 − (n ′·n) 2<br />
∆σ ± = 0 n ′·n = ± 1, , n ′ = ± n <br />
= n ′ ·σ , <br />
, χ + (θ, φ) σ x 9 3 ′ , <br />
σ x +1 −1 9 3 ′ c i (t) ϕ i → χ ± (x) ,<br />
ψ → χ + (θ, φ) (5.34) , ± 1 P ± <br />
∣<br />
P ± = ∣χ † ±(x) χ + (θ, φ) ∣ 2 (5.56)<br />
(5.53), (5.54) <br />
(<br />
P ± = 1 2 ∣ ( 1 ± 1 ) cos(θ/2)<br />
e iφ sin(θ/2)<br />
)∣ ∣∣∣∣<br />
2<br />
=<br />
1 ± sin θ cos φ<br />
2<br />
P + + P − = 1 χ + (θ, φ) σ x 〈σ x 〉 + <br />
〈σ x 〉 + = (+1)×P + + (−1)×P − = sin θ cos φ<br />
, 〈σ x 〉 + σ x 1 <br />
P + = 1 , P − = 0 ( sin θ cos φ = 1 ) P + = 0 , P − = 1 ( sin θ cos φ = − 1 )<br />
n x , x , <br />
χ + (θ, φ) σ x <br />
5.8<br />
χ ± <br />
χ + (θ, φ)χ † +(θ, φ) + χ − (θ, φ)χ † −(θ, φ) = 1 = <br />
, χ <br />
χ = χ + (θ, φ) χ † +(θ, φ)χ + χ − (θ, φ) χ † −(θ, φ)χ = c + χ + (θ, φ) + c − χ − (θ, φ)<br />
c ± = χ † ±(θ, φ)χ <br />
5.7 <br />
A(r) ( = − e ) H , <br />
H 0 = p 2 /2m p P ≡ p + (e/c)A <br />
H = 1 (<br />
p + e ) 2<br />
2m c A , p = − i∇ (5.57)<br />
, H 0 (5.48) ∇×∇ = 0 <br />
(σ·p) 2 = p 2 , H 0 = (σ·p) 2 /2m p → P <br />
H = 1<br />
2m (σ·P )2 = 1<br />
2m P 2 +<br />
i<br />
2m σ·(P ×P ) , P = − i ∇ + e c A (5.58)
5 94<br />
P ∇ A(r) ∇×∇ = 0 , A×A = 0 <br />
P ×P =<br />
(− i ∇ + e )<br />
c A ×<br />
(− i ∇ + e )<br />
c A<br />
= − ie (<br />
)<br />
A×∇ + ∇×A<br />
c<br />
ψ(r) <br />
(<br />
)<br />
A×∇ + ∇×A ψ = A×(∇ψ) + ∇×(Aψ) = A×(∇ψ) + (∇ψ)×A + (∇×A) ψ = B ψ<br />
B(r) = (∇×A) , (5.58) <br />
H = 1<br />
2m P 2 + µ B σ·B(r) , µ B = e = (5.59)<br />
2mc<br />
(σ·p) 2 /2m p → P , <br />
, <br />
B P 2 /2m , µ B σ·B r <br />
, (5.59) , <br />
ϕ(r) r 2 χ <br />
ψ(r) = ϕ(r) χ Hψ = Eψ <br />
χ H r ϕ(r) + ϕ(r)H s χ = E ϕ(r) χ , H r = 1<br />
2m P 2 ,<br />
χ † χ † χ χ † H s χ <br />
H s = µ B σ·B<br />
H r ϕ(r) = E r ϕ(r) , H s χ = E s χ , E = E r + E s<br />
5.10 , , B<br />
r , H s r , , <br />
, B , <br />
( B = ∇×A = 0 ) , A ≠ 0 <br />
<br />
229 <br />
b B , B = |B| , σ b = b·σ H s = µ B B σ b σ b <br />
± 1 <br />
H s χ ± (θ b , φ b ) = ± µ B B χ ± (θ b , φ b )<br />
χ ± (5.53) , θ b , φ b B χ + ,<br />
χ − P 2 /2m ϕ i (r),<br />
E i , (5.59) H <br />
E = E i ± µ B B , ψ(r) = ϕ i (r) χ ± (θ b , φ b )<br />
µ B B<br />
( B = 0 ), 2 <br />
, θ<br />
E i b , φ b , <br />
2 , <br />
µ B B<br />
, 2 E i ± µ B B <br />
( ) B = 0 B ≠ 0<br />
E i B <br />
, B = 0 <br />
, 2
5 95<br />
, H s = µ B σ·B <br />
( )<br />
i d dt χ(t) = H c + (t)<br />
sχ(t) , χ(t) =<br />
c − (t)<br />
(5.60)<br />
3 <br />
1. , ω = µ B B/ (5.51) (5.60) <br />
( ) (<br />
) (<br />
i d c + (t)<br />
cos θ b e −iφ b<br />
sin θ b c + (t)<br />
= ω<br />
dt c − (t) e iφ b<br />
sin θ b − cos θ b c − (t)<br />
)<br />
<br />
)<br />
)<br />
i ċ + = ω<br />
(cos θ b c + + e −iφ b<br />
sin θ b c − , i ċ − = ω<br />
(e iφ b<br />
sin θ b c + − cos θ b c −<br />
1 <br />
c − (t) = eiφ b<br />
sin θ b<br />
( i ċ+<br />
ω − c + cos θ b<br />
)<br />
2 ¨c + = − ω 2 c + H 2 s = (µ B B) 2 <br />
(5.61)<br />
(5.62)<br />
(i) 2 d2<br />
dt 2 χ(t) = i d dt H sχ(t) = H 2 s χ(t) = (µ B B) 2 χ(t) , ∴ ¨c ± = − ω 2 c ±<br />
, c ± a, b <br />
(5.62) <br />
c + (t) = a cos ωt + b sin ωt<br />
c − (t) = eiφ b (<br />
)<br />
(ib − a cos θ b ) cos ωt + (−ia + b cos θ b ) sin ωt<br />
sin θ b<br />
t = 0 a, b c ± (0) <br />
a = c + (0) ,<br />
ib = c + (0) cos θ b + c − (0) sin θ b e −iφ b<br />
<br />
(<br />
c + (t)<br />
c − (t)<br />
)<br />
=<br />
(<br />
) (<br />
cos ωt − i sin ωt cos θ b − i sin ωt sin θ b e −iφ b<br />
c + (0)<br />
− i sin ωt sin θ b e iφ b<br />
cos ωt + i sin ωt cos θ b c − (0)<br />
)<br />
(5.63)<br />
<br />
2. (1.39) χ ± = χ ± (θ b , φ b ) , e ∓iωt χ ± (5.60) <br />
, (5.60) <br />
χ(t) = u e −iωt χ + + v e iωt χ − ,<br />
u, v = <br />
χ ± χ † +χ(0) = u , χ † −χ(0) = v <br />
χ(t) =<br />
(<br />
)<br />
e −iωt χ + χ † + + e iωt χ − χ † − χ(0) (5.64)<br />
2×2 e −iωt χ + χ † + + e iωt χ − χ † − (5.53) (5.63)
5 96<br />
3. , i d | t 〉 = H| t 〉 , H <br />
dt<br />
, (1.42) | t 〉 = e −iHt/ | t = 0 〉 , () <br />
(5.50) H i d dt e−iHt/ = He −iHt/ , | t 〉 = e −iHt/ | t = 0 〉<br />
, <br />
, H = ω σ b (5.49) <br />
| t 〉 = exp (−iωt σ b ) | t = 0 〉 =<br />
(<br />
)<br />
cos ωt − iσ b sin ωt | t = 0 〉<br />
σ b (5.51) (5.63) , e −iH st/ χ ± = e ∓iωt χ ± (5.64) <br />
χ(t) = e −iHst/ ( χ + χ † + + χ − χ † −<br />
, 5.8 <br />
, z ( θ b = 0 ) (5.63) <br />
)<br />
χ(0) = e −iHst/ χ(0)<br />
c + (t) = e −iωt c + (0) , c − (t) = e iωt c − (0)<br />
( (5.61) θ b = 0 , ) (5.53) φ = 0 <br />
c + (0) = cos(θ/2) , c − (0) = sin(θ/2) , θ <br />
<br />
χ(t) =<br />
(<br />
c + (t)<br />
c − (t)<br />
)<br />
=<br />
(<br />
e −iωt cos(θ/2)<br />
e iωt sin(θ/2)<br />
)<br />
(5.65)<br />
(5.53) χ + χ(t) = e −iωt χ + (θ, 2ωt) <br />
, t σ 〈σ〉 (5.55) φ = 2ωt <br />
〈σ〉 = χ † (t)σχ(t) = χ † +(θ, φ)σχ + (θ, φ) = n<br />
<br />
cos θ<br />
B<br />
〈σ〉<br />
〈σ x 〉 = sin θ cos 2ωt , 〈σ y 〉 = sin θ sin 2ωt , 〈σ z 〉 = cos θ<br />
2ωt<br />
〈σ〉 σ ( z ) <br />
2ω ( Larmor precession ) <br />
5.9<br />
χ + , (5.65) t 〈σ〉 <br />
5.10<br />
B B = (0, 0, B) B z <br />
∇×A = B A <br />
A(r) = 1 2 B×r = 1 ( −By, Bx, 0 ) , A(r) = ( −By, 0, 0 )<br />
2<br />
A(r) = ( −By, 0, 0 ) <br />
H = 1 (p + e ) 2<br />
2m c A 2<br />
= −<br />
2m<br />
[ ( ) ]<br />
2 ∂<br />
∂x − ieB c y + ∂2<br />
∂y 2 + ∂2<br />
∂z 2
5 97<br />
H p y p x , p z , H ψ(r) <br />
p x , p z ψ(r) = e i(k xx+k z z) ϕ(y) H E <br />
(<br />
E = ω L n + 1 )<br />
+ 2 kz<br />
2<br />
2 2m , ω L = eB , n = 0, 1, 2, · · ·<br />
mc<br />
xy <br />
<br />
5.11<br />
A(r) = 1 ( −By, Bx, 0 ) , xy 2 <br />
2<br />
130 6.9 , <br />
5.12 B = ∇×A 2 A 1 (r) , A 2 (r) <br />
[ 1<br />
(<br />
p + e ) ]<br />
[ 2 1<br />
(<br />
2m c A 1 + V (r) ψ 1 (r) = E ψ 1 (r) , p + e ) ]<br />
2<br />
2m c A 2 + V (r) ψ 2 (r) = E ψ 2 (r)<br />
∇×(A 2 − A 1 ) = 0 A 2 (r) = A 1 (r) + ∇f(r) <br />
(<br />
ψ 2 (r) = exp − ie )<br />
c f(r) ϕ 2 (r)<br />
ϕ 2 (r) ψ 1 (r) , A <br />
2 , , <br />
( )<br />
<br />
z xy <br />
B(t) = ( B 1 cos ωt , B 1 sin ωt , B 0 )<br />
ω 0 = µ B B 0 / , ω 1 = µ B B 1 / <br />
(<br />
)<br />
)<br />
ω 0 ω 1 e<br />
H(t) = µ B B·σ = ω 1<br />
(σ −iωt<br />
x cos ωt + σ y sin ωt + ω 0 σ z = <br />
ω 1 e iωt − ω 0<br />
(5.66)<br />
H 2., 3. H(t) <br />
(<br />
)<br />
cos θ b sin θ b e −iωt<br />
H(t) = Ω<br />
, cos θ<br />
sin θ b e iωt b = ω 0<br />
− cos θ b Ω , sin θ b = ω 1<br />
Ω ,<br />
Ω = √<br />
ω 2 0 + ω2 1<br />
(5.51) θ = θ b , φ = ωt , H(t) <br />
± Ω , χ ± (θ b , ωt) , 2. e ∓iΩt χ ± (θ b , ωt) <br />
(i d dt − H )<br />
e ∓iΩt χ ± (θ b , ωt) = i e ∓iΩt d dt χ ±(θ b , ωt) ≠ 0<br />
, ( 170 )<br />
<br />
i d dt<br />
(<br />
c + (t)<br />
c − (t)<br />
H (5.66) <br />
)<br />
= H<br />
(<br />
c + (t)<br />
c − (t)<br />
i ċ + = ω 0 c + + ω 1 e −iωt c − , i ċ − = ω 1 e iωt c + − ω 0 c − (5.67)<br />
)
5 98<br />
2 <br />
1 <br />
c + = e−iωt<br />
ω 1<br />
(<br />
i ċ − + ω 0 c −<br />
)<br />
)<br />
¨c − − iωċ − +<br />
(ω0 2 + ω1 2 − ωω 0 c − = 0<br />
(5.68)<br />
√<br />
2 x 2 − iωx + ω0 2 + ω1 2 − ωω 0 = 0 i ω/2 ± i (ω 0 − ω/2) 2 + ω1 2 ,<br />
a , b <br />
(5.68) <br />
c − (t) = e iωt/2( a e iγt + b e −iγt) , γ =<br />
c + (t) = e −iωt/2 (<br />
ω0 − ω/2 − γ<br />
ω 1<br />
√<br />
(ω 0 − ω/2) 2 + ω 2 1<br />
a e iγt + ω 0 − ω/2 + γ<br />
ω 1<br />
b e −iγt )<br />
t = 0 z c + (0) = 1 , c − (0) = 0 <br />
a = − b = − ω 1 /(2γ) <br />
c − (t) = − i ω (<br />
1<br />
γ eiωt/2 sin γt , c + (t) = e −iωt/2 cos γt − i ω )<br />
0 − ω/2<br />
sin γt<br />
γ<br />
z P − (t) , (5.56) <br />
( )∣ P − (t) =<br />
∣ ( 0 1 ) c + (t) ∣∣∣∣<br />
2<br />
= |c − (t)| 2<br />
c − (t)<br />
(5.69)<br />
<br />
P − (t) = A sin 2 (√<br />
(ω 0 − ω/2) 2 + ω 2 1 t )<br />
, A =<br />
ω 2 1<br />
(ω 0 − ω/2) 2 + ω 2 1<br />
(5.70)<br />
( ω 1 = 0 ), P − = 0<br />
1.0<br />
, ω 1 ≠ 0 ω = 2ω 0<br />
P − (t) = sin 2 ω 1 t <br />
A<br />
, 0.5<br />
( ω 1 ≪ ω 0 ) |ω − 2ω 0 | ≤ 2ω 1<br />
0.01 0.2<br />
A ≥ 1/2 , ω 1 ≪ ω 0 , <br />
ω ω ≈ 2ω 0 0.0<br />
<br />
1 2 ω/ω 0<br />
ω 1 /ω 0 = 0.01, 0.2 A(ω) , ω 0 = µ B B 0 / , <br />
µ B <br />
5.13 H (5.66) , <br />
1. D(θ) = exp(−iθσ z /2) (5.49) <br />
D(θ) σ x D † (θ) = σ x cos θ + σ y sin θ<br />
( z θ ) (5.66) <br />
)<br />
H = D(ωt)<br />
(ω 1 σ x + ω 0 σ z D † (ωt)
[ J 1i , J 1j ] = i ∑ k<br />
[ J 2i , J 2j ] = i ∑ k<br />
5 99<br />
2. t | t 〉 i d dt | t 〉 = H| t 〉 | ˜t 〉 = D † (ωt)| t 〉 <br />
d<br />
dt | ˜t 〉 = − iS| ˜t 〉 ,<br />
S = ω 1 σ x + (ω 0 − ω/2) σ z<br />
S | ˜t 〉 = e −itS | t = 0 〉 <br />
3. n<br />
n = ω 1<br />
γ e x + ω √<br />
0 − ω/2<br />
e z , γ = (ω 0 − ω/2) 2 + ω1<br />
2 γ<br />
S = γ n·σ <br />
(<br />
)<br />
| t 〉 = D(ωt) cos γt − i n·σ sin γt | t = 0 〉<br />
c ± (t) (5.69) <br />
5.8 <br />
2 1, 2 J 1 , J 2 <br />
(5.5)<br />
ε ijk J 1k ,<br />
ε ijk J 2k<br />
2 [ J 1i , J 2j ] = 0 , 2 <br />
L 1 L 2 , S , L<br />
S , [ L i , S j ] = 0<br />
, <br />
<br />
J 1 + J 2 , <br />
, , <br />
|j 1 m 1 , j 2 m 2 〉 ≡ |j 1 m 1 〉|j 2 m 2 〉<br />
, |j 1 m 1 〉, |j 2 m 2 〉 J 1 , J 2 <br />
J 2 1 |j 1 m 1 〉 = j 1 (j 1 + 1)|j 1 m 1 〉 , J 1z |j 1 m 1 〉 = m 1 |j 1 m 1 〉<br />
J 2 2 |j 2 m 2 〉 = j 2 (j 2 + 1)|j 2 m 2 〉 , J 2z |j 2 m 2 〉 = m 2 |j 2 m 2 〉<br />
2 , J 1 J 2 |j 2 m 2 〉 , J 2 <br />
J 1 |j 1 m 1 〉 <br />
( )( )<br />
J 1x J 2x |j 1 m 1 , j 2 m 2 〉 = J 1x |j 1 m 1 〉 J 2x |j 2 m 2 〉<br />
(J 1x + J 2x ) |j 1 m 1 , j 2 m 2 〉 =<br />
( )<br />
( )<br />
J 1x |j 1 m 1 〉 |j 2 m 2 〉 + |j 1 m 1 〉 J 2x |j 2 m 2 〉<br />
<br />
J J = J 1 + J 2 J (5.5) <br />
[ J x , J y ] = [ J 1x + J 2x , J 1y + J 2y ] = [ J 1x , J 1y ] + [ J 2x , J 2y ] = i (J 1z + J 2z ) = i J z
5 100<br />
, J = J 1 + J 2 , J 2 J z <br />
|jm〉 :<br />
J 2 |jm〉 = j(j + 1) |jm〉 ,<br />
J z |jm〉 = m |jm〉<br />
J z J z = J 1z + J 2z <br />
J z |j 1 m 1 , j 2 m 2 〉 =<br />
( )<br />
( )<br />
J 1z |j 1 m 1 〉 |j 2 m 2 〉 + |j 1 m 1 〉 J 2z |j 2 m 2 〉 = (m 1 + m 2 ) |j 1 m 1 , j 2 m 2 〉<br />
, J z , J 2 = J 2 1 + J 2 2 + 2J 1·J 2 J 2 1 + J 2 2 <br />
, |j 1 m 1 , j 2 m 2 〉 J 2 <br />
<br />
<br />
|j 1 m 1 , j 2 m 2 〉 = |m 1 , m 2 〉 , |j 1 m 1 〉 = |m 1 〉 , |j 2 m 2 〉 = |m 2 〉<br />
J 2 |m 1 , m 2 〉 = ( J1 2 + 2J 1·J 2 + J2 2 )<br />
|m1 , m 2 〉<br />
(<br />
)<br />
= j 1 (j 1 + 1) + j 2 (j 2 + 1) |m 1 , m 2 〉 + 2J 1·J 2 |m 1 , m 2 〉<br />
J 1x J 2x + J 1y J 2y J 1± = J 1x ± iJ 1y , J 2± = J 2x ± iJ 2y <br />
)<br />
2J 1·J 2 = 2<br />
(J 1x J 2x + J 1y J 2y + J 1z J 2z = J 1+ J 2− + J 1− J 2+ + 2J 1z J 2z<br />
(5.15), (5.16) <br />
2J 1·J 2 |m 1 , m 2 〉 = (J 1+ |m 1 〉) (J 2− |m 2 〉) + (J 1− |m 1 〉)(J 2+ |m 2 〉) + 2 (J 1z |m 1 〉)(J 2z |m 2 〉)<br />
<br />
= c + (j 1 , m 1 )c − (j 2 , m 2 ) |m 1 +1〉|m 2 −1〉 + c − (j 1 , m 1 )c + (j 2 , m 2 ) |m 1 −1〉|m 2 +1〉<br />
+ 2m 1 m 2 |m 1 〉|m 2 〉 , c ± (j, m) = √ (j ∓ m)(j ± m + 1) (5.71)<br />
J 2 |m 1 , m 2 〉 =<br />
(j 1 (j 1 + 1) + j 2 (j 2 + 1) + 2m 1 m 2<br />
)<br />
|m 1 , m 2 〉<br />
+ c + (j 1 , m 1 )c − (j 2 , m 2 ) |m 1 +1〉|m 2 −1〉<br />
+ c − (j 1 , m 1 )c + (j 2 , m 2 ) |m 1 −1〉|m 2 +1〉 (5.72)<br />
1 |m 1 , m 2 〉 J 2 , <br />
<br />
|jm〉 |m 1 , m 2 〉 c(m 1 , m 2 ) <br />
<br />
|jm〉 =<br />
j 1<br />
∑<br />
m 1 =−j 1<br />
, J z <br />
J z |jm〉 =<br />
∑<br />
j 2<br />
∑<br />
m 1,m 2<br />
c(m 1 , m 2 ) (J 1z + J 2z ) |m 1 , m 2 〉 =<br />
m 2 =−j 2<br />
c(m 1 , m 2 ) |m 1 , m 2 〉 (5.73)<br />
∑<br />
m 1,m 2<br />
c(m 1 , m 2 ) (m 1 + m 2 ) |m 1 , m 2 〉
5 101<br />
, m 1 + m 2 = = m |m 1 , m 2 〉 <br />
<br />
∑<br />
m 1 ,m 2<br />
m 1+m 2=m<br />
J z <br />
J 2 |jm〉 =<br />
|jm〉 =<br />
∑<br />
m 1 ,m 2<br />
m 1+m 2=m<br />
c(m 1 , m 2 ) (m 1 + m 2 ) |m 1 , m 2 〉 = m<br />
∑<br />
m 1 ,m 2<br />
m 1+m 2=m<br />
c(m 1 , m 2 )|m 1 , m 2 〉 (5.74)<br />
∑<br />
m 1 ,m 2<br />
m 1+m 2=m<br />
c(m 1 , m 2 ) J 2 |m 1 , m 2 〉 = j(j + 1)<br />
c(m 1 , m 2 )|m 1 , m 2 〉 = m |jm〉<br />
∑<br />
m 1 ,m 2<br />
m 1+m 2=m<br />
c(m 1 , m 2 ) |m 1 , m 2 〉<br />
c(m 1 , m 2 ) (5.72) c(m 1 , m 2 ) <br />
, c(m 1 , m 2 ) <br />
<br />
j 12 = j 1 + j 2<br />
|m 1 | ≤ j 1 , |m 2 | ≤ j 2 , J z m = m 1 + m 2 |m| ≤ j 12 m <br />
j 12 j j 12 m = j 12 m 1 , m 2 m 1 = j 1 ,<br />
m 2 = j 2 , (5.74) 1 <br />
|j =j 12 , m=j 12 〉 = |m 1 =j 1 , m 2 =j 2 〉 (5.75)<br />
m 1 = j 1 , m 2 = j 2 ( m 1 = −j 1 , m 2 = −j 2 ) , 1 J 2 <br />
, (5.72) m 1 = j 1 , m 2 = j 2 , (5.72) 2 3 0 <br />
, |m 1 =j 1 , m 2 =j 2 〉 J 2 <br />
j = j 1 + j 2 <br />
J 2 | m 1 =j 1 , m 2 =j 2 〉 = (j 1 + j 2 ) (j 1 + j 2 + 1) | m 1 =j 1 , m 2 =j 2 〉<br />
j = j 12 |jm〉 |j 1 m 1 , j 2 m 2 〉 , (5.75) (5.75) <br />
J − = J 1− + J 2− <br />
J − |j =j 12 , m=j 12 〉 = (J 1− + J 2− ) | m 1 =j 1 , m 2 =j 2 〉<br />
(5.16) j = m = j 12 <br />
, <br />
(J 1− + J 2− ) | m 1 =j 1 , m 2 =j 2 〉 =<br />
J − |j =j 12 , m=j 12 〉 = √ 2j 12 |j =j 12 , m=j 12 −1〉<br />
(<br />
)<br />
(<br />
)<br />
J 1− | m 1 =j 1 〉 | m 2 =j 2 〉 + | m 1 =j 1 〉 J 2− | m 2 =j 2 〉<br />
= √ 2j 1 | m 1 =j 1 −1 , m 2 =j 2 〉 + √ 2j 2 | m 1 =j 1 , m 2 =j 2 −1〉<br />
<br />
√<br />
√<br />
j 1<br />
j 2<br />
|j =j 12 , m=j 12 −1〉 = |m 1 =j 1 −1 , m 2 =j 2 〉 + |m 1 =j 1 , m 2 =j 2 −1〉 (5.76)<br />
j 12 j 12
5 102<br />
J − = J 1− + J 2− |j =j 12 , m=j 12 −2 〉 <br />
m = j 12 , · · · , − j 12 |j =j 12 , m〉 |m 1 , m 2 〉 <br />
j 1 |j =j 12 −1 , m 〉 m m = j 12 − 1 J z<br />
j 12 − 1 |m 1 , m 2 〉 |m 1 =j 1 , m 2 =j 2 −1〉 |m 1 =j 1 −1 , m 2 =j 2 〉 2 <br />
<br />
|j =j 12 −1 , m=j 12 −1〉 = c 1 |m 1 =j 1 −1 , m 2 =j 2 〉 + c 2 |m 1 =j 1 , m 2 =j 2 −1〉<br />
|j =j 12 , m=j 12 −1〉 J 2 (5.76) <br />
c 1<br />
√<br />
j1 /j 12 + c 2<br />
√<br />
j2 /j 12 = 0 |c 1 | 2 + |c 2 | 2 = 1 <br />
√<br />
√<br />
j 2<br />
j 1<br />
|j =j 12 −1 , m=j 12 −1〉 = − |m 1 =j 1 −1 , m 2 =j 2 〉 + |m 1 =j 1 , m 2 =j 2 −1〉 (5.77)<br />
j 12 j 12<br />
|j = j 12 −1 , m = j 12 −1〉 , J − <br />
|j =j 12 −1 , m〉 |m 1 , m 2 〉 <br />
j = j 12 −n , n = 1, 2, · · · <br />
• |jm〉 <br />
, J − , <br />
m<br />
j 12<br />
j 12 −1<br />
j 12 −2<br />
j 12<br />
j 12 −1<br />
j 12 −2<br />
2 1 j = m = j 12<br />
, (5.75) J − <br />
, j = j 12 1 ,<br />
j = m = j 12 − 1 j = j 12 , m = j 12 − 1 <br />
, J − , j = j 12 − 1 <br />
2 , j = m = j 12 − 2 , <br />
j = j 12 , j = j 12 − 1 m = j 12 −2 2 <br />
−j 12 +2<br />
−j 12 +1<br />
, j = m = j 12 −n j > j 12 − n m = j 12 −n n<br />
<br />
j j j min j |jm〉 2j + 1 <br />
j = j min , j min + 1, · · · , j 1 + j 2 , <br />
N =<br />
j∑<br />
1+j 2<br />
j=j min<br />
(2j + 1)<br />
j 1 + j 2 ( )<br />
N =<br />
∑<br />
(2j + 1) −<br />
j 1 +j 2<br />
j=0<br />
∑<br />
j min −1<br />
j=0<br />
(2j + 1)<br />
−j 12<br />
)<br />
= (j 1 + j 2 )(j 1 + j 2 + 1) + j 1 + j 2 + 1 −<br />
(j min (j min − 1) + j min<br />
= (j 1 + j 2 + 1) 2 − jmin<br />
2<br />
, |jm〉 |j 1 m 1 , j 2 m 2 〉 , <br />
|j 1 m 1 , j 2 m 2 〉 (2j 1 + 1)(2j 2 + 1) <br />
(j 1 + j 2 + 1) 2 − jmin 2 = (2j 1 + 1)(2j 2 + 1) , j min = |j 1 − j 2 |
5 103<br />
j <br />
<br />
j = |j 1 − j 2 |, |j 1 − j 2 | + 1, · · · , j 1 + j 2 (5.78)<br />
5.14<br />
(5.77) J + = J 1+ + J 2+ 0 <br />
c(m 1 , m 2 ) (5.74) , J 2 , J z , J 2 1 ,<br />
J2 2 <br />
J1 2 |jm〉 =<br />
∑<br />
c(m 1 , m 2 ) J1 2 |m 1 , m 2 〉 =<br />
m 1 ,m 2<br />
m 1 +m 2 =m<br />
∑<br />
m 1 ,m 2<br />
m 1 +m 2 =m<br />
c(m 1 , m 2 ) j 1 (j 1 + 1) |m 1 , m 2 〉 = j 1 (j 1 + 1) |jm〉<br />
J 2 2 |jm〉 = j 2 (j 2 + 1) |jm〉 J 2 , J z , J 2 1 , J 2 2 <br />
, J 2 1 J 1 <br />
[ J 2 , J 2 1 ] = [ J 2 1 + 2J 1·J 2 + J 2 2 , J 2 1 ] = 2[J 1·J 2 , J 2 1 ] = 2 ∑ k<br />
[J 1k , J 2 1 ]J 2k = 0<br />
[ J 2 , J 2 2 ] = 0 <br />
J 2 J 1 , J 2 <br />
[ J 2 , J 1z ] = 2 [ J 1·J 2 , J 1z ] = 2 [ J 1x , J 1z ]J 2x + 2 [ J 1y , J 1z ]J 2y = i (J 1x J 2y − J 1y J 2x ) ≠ 0<br />
, J 2 J 1z , J 2z |m 1 , m 2 〉 J 1z , J 2z<br />
J 2 , , |jm〉 J 2 , J 1z , J 2z <br />
( J z = J 1z + J 2z )<br />
|m 1 , m 2 〉 J 2 |jm〉 , (5.76) (5.77) <br />
|m 1 =j 1 −1 , m 2 =j 2 〉<br />
√<br />
√<br />
j 1<br />
j 2<br />
= |j =j 1 +j 2 , m=j 1 +j 2 −1〉 − |j =j 1 +j 2 −1 , m=j 1 +j 2 −1〉<br />
j 1 + j 2 j 1 + j 2<br />
|m 1 , m 2 〉 |jm〉 , <br />
, ( , )<br />
(5.73) c(m 1 , m 2 ) (Clebsch–Gordan) <br />
〈 j 1 m 1 j 2 m 2 | jm 〉 <br />
|jm〉 =<br />
∑<br />
〈 j 1 m 1 j 2 m 2 | jm 〉 |j 1 m 1 , j 2 m 2 〉<br />
m 1,m 2<br />
CG <br />
CG <br />
m = m 1 + m 2 |j 1 − j 2 | ≤ j ≤ j 1 + j 2 〈 j 1 m 1 j 2 m 2 | jm 〉 = 0 CG <br />
|jm〉 |j 1 m 1 , j 2 m 2 〉 <br />
〈jm|j ′ m ′ 〉 =<br />
∑<br />
〈 j 1 m 1 j 2 m 2 | jm 〉〈 j 1 m ′ 1 j 2 m ′ 2 | j ′ m ′ 〉〈j 1 m 1 , j 2 m 2 |j 1 m ′ 1 , j 2 m ′ 2〉<br />
m 1 ,m 2<br />
m ′ 1 ,m′ 2<br />
= ∑<br />
m 1 ,m 2<br />
〈 j 1 m 1 j 2 m 2 | jm 〉〈 j 1 m 1 j 2 m 2 | j ′ m ′ 〉 = δ jj ′ δ mm ′ (5.79)
5 104<br />
<br />
| jm 〉 <br />
<br />
〈 j 1 m 1 j 2 m 2 | j 1 m ′ 1 j 2 m ′ 2 〉 = δ m1 m ′ 1 δ m 2 m ′ 2<br />
∑<br />
〈 j 1 m 1 j 2 m 2 | jm 〉〈 j 1 m ′ 1 j 2 m ′ 2 | jm 〉 = δ m1 m ′ δ 1 m 2 m ′ (5.80)<br />
2<br />
j m<br />
J ± |jm〉 = (J 1± + J 2± ) ∑ 〈 j 1 m 1 j 2 m 2 | jm 〉 |j 1 m 1 , j 2 m 2 〉<br />
= ∑ (( )<br />
( ))<br />
〈 j 1 m 1 j 2 m 2 | jm 〉 J 1± |j 1 m 1 〉 |j 2 m 2 〉 + |j 1 m 1 〉 J 2± |j 2 m 2 〉<br />
(5.15), (5.16) <br />
√<br />
(j ∓ m)(j ± m + 1) 〈 j1 m 1 j 2 m 2 | j m±1 〉<br />
= √ (j 1 ∓ m 1 + 1)(j 1 ± m 1 ) 〈 j 1 m 1 ∓1 j 2 m 2 | jm 〉<br />
+ √ (j 2 ∓ m 2 + 1)(j 2 ± m 2 ) 〈 j 1 m 1 j 2 m 2 ∓1 | jm 〉 (5.81)<br />
, 〈 j 1 j 1 j 2 j 2 | j 1 +j 2 j 1 +j 2 〉 = 1 CG <br />
, CG m = m 1 + m 2 <br />
〈 j 1 m 1 j 2 m 2 | jm 〉<br />
√<br />
(2j 1 + 1)(j 1 + j 2 − j)! (j 1 − j 2 + j)! (−j 1 + j 2 + j)!<br />
=<br />
(j 1 + j 2 + j + 1)!<br />
× √ (j 1 + m 1 )! (j 1 − m 1 )! (j 2 + m 2 )! (j 2 − m 2 )! (j + m)! (j − m)!<br />
× ∑ k<br />
(−1) k<br />
k! (j 1 + j 2 − j − k)! (j 1 − m 1 − k)! (j 2 + m 2 − k)! (j − j 2 + m 1 + k)! (j − j 1 − m 2 + k)!<br />
, k <br />
j 1 = j 2 = 1/2<br />
|j 1 = 1 2 m 1 =± 1 2 〉 = |±〉 1 <br />
|+〉 1 |+〉 2 = | + + 〉 , |+〉 1 |−〉 2 = | + − 〉<br />
j = j 1 + j 2 , · · · , |j 1 − j 2 | j = 1, j = 0 j = 1 <br />
(5.76) j 1 = j 2 = 1/2 <br />
|j =1 m=1 〉 = | + + 〉<br />
|j =1 m=0 〉 = | − + 〉 + | + − 〉 √<br />
2<br />
(5.82)<br />
J − <br />
J − |j =1 m=0 〉 = √ (1 + 0)(1 − 0 + 1) |j =1 m=−1 〉 = √ 2 |j =1 m=−1 〉
5 105<br />
, J 1− |−〉 1 = 0, J 2− |−〉 2 = 0, J 1− |+〉 1 = |−〉 1 , J 2− |+〉 2 = |−〉 2 (5.82) <br />
) )<br />
)<br />
(J 1− + J 2− )<br />
(|−〉 1 |+〉 2 + |+〉 1 |−〉 2 = |−〉 1<br />
(J 2− |+〉 2 +<br />
(J 1− |+〉 1 |−〉 2 = 2 | − − 〉<br />
<br />
|j =1 m=−1 〉 = | − − 〉<br />
m = 0 j = 0 (5.82) <br />
<br />
|j =0 m=0 〉 = | + − 〉 − | − + 〉 √<br />
2<br />
|j 1 m 1 〉|j 2 m 2 〉 2 × 2 = 4 |jm〉 4 , 3 j = 1, <br />
j = 0 <br />
|j =0 m=0 〉 = | + − 〉 − | − + 〉 √<br />
2<br />
, |j =1 m 〉 =<br />
⎧<br />
⎪⎨<br />
| + + 〉 , m = 1<br />
| − + 〉 + | + − 〉<br />
√<br />
2<br />
, m = 0<br />
⎪⎩<br />
| − − 〉 , m = −1<br />
j = 0 1 1 , j = 1 3 3 <br />
<br />
, 2 <br />
H A, B <br />
H = AJ 1·J 2 + B (J 1z + J 2z )<br />
, H , |m 1 , m 2 〉 <br />
| jm 〉 (5.72) , J 1·J 2 |m 1 , m 2 〉 <br />
<br />
<br />
J 2 |jm〉 = j(j + 1) |jm〉 , J 2 1 |jm〉 = j 1 (j 1 + 1) |jm〉 , J 2 2 |jm〉 = j 2 (j 2 + 1) |jm〉<br />
<br />
2J 1·J 2 |jm〉 = ( J 2 − J1 2 − J2<br />
2 ) (<br />
)<br />
|jm〉 = j(j + 1) − j 1 (j 1 + 1) − j 2 (j 2 + 1) |jm〉<br />
H |jm〉 = E jm |jm〉 , E jm = A 2<br />
, |jm〉 H j 1 = j 2 = 1/2 <br />
E jm = A 2<br />
⎧<br />
(<br />
j(j + 1) − 3 ) ⎪⎨<br />
+ Bm =<br />
2<br />
⎪⎩<br />
(<br />
)<br />
j(j + 1) − j 1 (j 1 + 1) − j 2 (j 2 + 1) + Bm<br />
A<br />
4<br />
+ Bm , j = 1 <br />
− 3 4 A , j = 0 (5.83)<br />
B = 0 1 3 , 3 3 B ≠ 0 <br />
3
5 106<br />
j 1 = j 2 = 1/2 , 4 , <br />
H (5.71) <br />
J 1·J 2 | ± ± 〉 = 1 4 | ± ± 〉 , J 1·J 2 | ± ∓ 〉 = 1 2 | ∓ ± 〉 − 1 4 | ± ∓ 〉<br />
<br />
H| ± ± 〉 =<br />
( A<br />
4 ± B )<br />
| ± ± 〉 , H| ± ∓ 〉 = A 2 | ∓ ± 〉 − A 4 | ± ∓ 〉<br />
| ± ± 〉 H A/4 ± B (5.83) j = 1 ,<br />
m = ± 1 , | ± ∓ 〉 H 2 <br />
c 1 , c 2 <br />
<br />
H|ψ〉 = E|ψ〉 , |ψ〉 = c 1 | + − 〉 + c 2 | − + 〉<br />
H|ψ〉 = c 1<br />
( A<br />
2 | − + 〉 − A 4 | + − 〉 )<br />
+ c 2<br />
( A<br />
2 | + − 〉 − A 4 | − + 〉 )<br />
= A 4<br />
(<br />
) (2c 2 − c 1 | + − 〉 + A ) (2c 1 − c 2 | − + 〉<br />
4<br />
A<br />
) (2c 2 − c 1 = Ec 1 ,<br />
4<br />
−A/4 − E A/2<br />
A/2 −A/4 − E<br />
A<br />
) (2c 1 − c 2 = Ec 2 (5.84)<br />
4<br />
) (<br />
)<br />
c 1<br />
= 0<br />
c 2<br />
<br />
−A/4 − E A/2<br />
∣ A/2 −A/4 − E ∣ = (A/4 + E)2 − (A/2) 2 = 0 , ∴ E = − A 4 ± A 2<br />
E = − 3A/4 (5.84) c 2 = − c 1 |c 1 | 2 + |c 2 | 2 = 2|c 1 | 2 = 1 c 1 = 1/ √ 2<br />
<br />
|ψ〉 = | + − 〉 − | − + 〉 √<br />
2<br />
, E = − 3 4 A<br />
(5.83) j = 0 E = A/4 c 2 = c 1 <br />
(5.83) j = 1 , m = 0 <br />
|ψ〉 = | + − 〉 + | − + 〉 √<br />
2<br />
, E = A 4<br />
5.15 j 1 = 1, j 2 = 1 |jm〉 |j 1 m 1 〉|j 2 m 2 〉 |j =0 , m=<br />
0 〉 |j =2 , m=0 〉 , |j =1 , m=0 〉 <br />
5.16 5.15 m 1 , m 2 = 0, ±1 3×3 = 9 |j 1 m 1 〉|j 2 m 2 〉<br />
m = 0 (m 1 , m 2 ) = (1, −1), (−1, 1), (0, 0) 3 <br />
<br />
<br />
| 1 〉 = | m 1 =1 〉| m 2 =−1 〉 , | 2 〉 = | m 1 =−1 〉| m 2 =1 〉 , | 3 〉 = | m 1 =0 〉| m 2 =0 〉
5 107<br />
1. (5.72) J 2 | k 〉 , k = 1, 2, 3 <br />
2. m = 0 c k <br />
3∑<br />
c k | k 〉<br />
k=1<br />
J 2 5.15 m = 0<br />
, <br />
5.17 L 1/2 <br />
J = L + S J 2 J z |jm〉 L 2 , L z | l m l 〉 <br />
| ± 〉 | l m l 〉 Y l ml (θ, φ) 5.8 J − <br />
, | ± 〉 2 <br />
l ≠ 0 <br />
1. J z = L z + S z m | l m− 1 2 〉|+〉 | l m+ 1 2<br />
〉|−〉 2 <br />
(5.72) <br />
J 2 |l m− 1 2 〉|+〉 = (¯l2 + m ) |l m− 1 2<br />
√¯l2 〉|+〉 + − m 2 |l m+ 1 2 〉|−〉<br />
J 2 |l m+ 1 2 〉|−〉 = (¯l2 − m ) |l m+ 1 2<br />
√¯l2 〉|−〉 + − m 2 |l m− 1 2 〉|+〉<br />
¯l = l + 1/2 <br />
2. 1. 2 <br />
|jm〉 = c 1 |l m− 1 2 〉|+〉 + c 2 |l m+ 1 2 〉|−〉<br />
c 1 , c 2 J z , c 1 , c 2<br />
<br />
J 2 |jm〉 = j(j + 1) |jm〉<br />
j = l ± 1/2 , , |jm〉 <br />
| j =l± 1 2 m 〉 = ± √<br />
l ± m + 1/2<br />
2l + 1<br />
|l m− 1 2 〉|+〉 + √<br />
l ∓ m + 1/2<br />
2l + 1<br />
|l m+ 1 2 〉|−〉<br />
c 2 > 0 2 <br />
| j =l± 1 2 m 〉 ⎛<br />
⎜<br />
⎝<br />
<br />
√<br />
l ± m + 1/2<br />
±<br />
Y l m−1/2 (θ, φ)<br />
2l + 1<br />
√<br />
l ∓ m + 1/2<br />
Y l m+1/2 (θ, φ)<br />
2l + 1<br />
⎞<br />
⎟<br />
⎠<br />
5.9 <br />
<br />
1. , <br />
2. ,
5 108<br />
2 , <br />
1. <br />
n θ θ > 0 n<br />
a a ′ , θ = ε <br />
<br />
a ′ = a + ε n×a (5.85)<br />
, z <br />
a ′ x = a x cos ε − a y sin ε = a x − a y ε , a ′ y = a x sin ε + a y cos ε = a x ε + a y , a ′ z = a z<br />
<br />
a ′ = a + ε (−a y , a x , 0) = a + ε n×a , n = (0, 0, 1)<br />
<br />
, <br />
ψ(r), ˜ψ(r)<br />
ψ(r) ˜ψ(r) R<br />
˜ψ(r) = R(n, θ) ψ(r)<br />
r , <br />
r r 1 :<br />
˜ψ(r) = ψ(r 1 )<br />
r<br />
θ<br />
r 1<br />
˜ψ<br />
ψ<br />
r 1 r (5.85) r 1 = r − ε n×r <br />
<br />
˜ψ(r) = ψ(r − ε n×r) = ψ(r) − ε (n×r)·∇ψ(r)<br />
(n×r)·∇ = n·(r×∇) <br />
(<br />
)<br />
˜ψ(r) = 1 − εn·(r×∇) ψ(r) =<br />
( )<br />
1 − iεn·L ψ(r)<br />
L , <br />
R(n, ε) = 1 − iεn·L<br />
, <br />
J , n <br />
R(n, ε) = 1 − iεn·J (5.86)<br />
θ θ N ( N → ∞ ),<br />
θ θ/N N <br />
(<br />
R(n, θ) = lim 1 − iθn·J ) N<br />
= exp (−iθ n·J) (5.87)<br />
N→∞ N<br />
, θ + dθ θ dθ <br />
R(n, θ + dθ) = R(n, dθ)R(n, θ) = (1 − i dθ n·J) R(n, θ)
5 109<br />
<br />
dR(n, θ)<br />
dθ<br />
= −in·JR(n, θ)<br />
, R(n, 0) = 1 (5.87) J <br />
R † (n, θ) = exp (+ iθ n·J) <br />
RR † = R † R = 1 (5.88)<br />
R ( unitary operator ) | α 〉 | α ′ 〉 <br />
| α ′ 〉 = R| α 〉 <br />
<br />
〈 α ′ | α ′ 〉 = 〈 α |R † R| α 〉 = 〈 α | α 〉<br />
<br />
<br />
, S ,<br />
<br />
〈 α |S| α 〉 = 〈 α ′ |S| α ′ 〉 = 〈 α | (1 + iεn·J) S (1 − iεn·J) | α 〉<br />
(<br />
)<br />
= 〈 α | S + iε [n·J , S ] | α 〉<br />
<br />
[ S , J ] = 0 (5.89)<br />
J <br />
V , <br />
(5.85) (5.86) <br />
〈 α ′ |V | α ′ 〉 = 〈 α |V | α 〉 + ε n×〈 α |V | α 〉 , | α ′ 〉 = (1 − iεn·J) | α 〉<br />
<br />
<br />
(1 + iεn·J) V (1 − iεn·J) = V + ε n×V<br />
[ V , n·J ] = i n×V<br />
n j ( n m = δ jm ), <br />
[ V i , J j ] = i (n×V ) i = i ∑ mk<br />
ε imk n m V k = i ∑ k<br />
ε ijk V k (5.90)<br />
V = J , (5.86) <br />
<br />
<br />
H J H, J 2 , J z |n j m〉 , <br />
E njm :<br />
H|n j m〉 = E njm |n j m〉 , J 2 |n j m〉 = j(j + 1)|n j m〉 , J z |n j m〉 = m |n j m〉
5 110<br />
n j, m [ H , J ± ] = 0 <br />
HJ ± |n j m〉 = J ± H|n j m〉 = E njm J ± |n j m〉<br />
J ± |n j m〉 ∝ J ± |n j m±1 〉 <br />
H|n j m±1〉 = E njm |n j m±1〉<br />
E njm±1 = E njm m j <br />
H 2j + 1 <br />
, ψ(r) a ˜ψ(r) <br />
˜ψ(r) = ψ(r − a)<br />
<br />
ψ(r − a) = ψ(x − a x , y − a y , z − a z ) =<br />
p p = − i∇ <br />
=<br />
∞∑<br />
(<br />
) n<br />
1 ∂<br />
− a x<br />
n! ∂x − a ∂<br />
y<br />
∂y − a ∂<br />
z ψ(r)<br />
∂z<br />
n=0<br />
∞∑<br />
n=0<br />
˜ψ(r) = ψ(r − a) = exp (− ia·p/) ψ(r)<br />
1<br />
n! (− a·∇)n ψ(r) = exp (− a·∇) ψ(r)<br />
(5.87) <br />
5.18<br />
(5.90) , A, B A·B <br />
5.19 n = ( sin θ cos φ , sin θ sin φ , cos θ ) z y <br />
θ , z φ , (5.53)<br />
n·σ , σ z |±〉 2 <br />
, |±〉 y θ , (5.87) J = S = σ/2 <br />
exp (−iθσ y /2) |±〉 , z φ <br />
U(θ, φ) |±〉 , U(θ, φ) = exp (−iφσ z /2) exp (−iθσ y /2) (5.91)<br />
(5.49) (5.91) (5.53) , <br />
<br />
U(θ, φ)σ z U † (θ, φ) = σ n<br />
σ z |±〉 = ± |±〉 Uσ z |±〉 = ± U|±〉 <br />
Uσ z U † U|±〉 = ± U|±〉 , σ n U|±〉 = ± U|±〉<br />
<br />
exp (−iθσ y /2) exp (−iφσ z /2) |±〉
5 111<br />
5.20 (S k ) mn = − i ε kmn 3 3 × 3 S 1 , S 2 , S 3 <br />
S , ε kmn (14.1) <br />
1. A(r) n ε , A ′ (r) <br />
r r 1 , r A ′ , r 1 A <br />
<br />
A ′ (r) = A(r 1 ) + ε n×A(r 1 ) , r 1 = r − ε n×r<br />
<br />
A ′ (r) =<br />
, A =<br />
(<br />
)<br />
1 − i ε n·(L + S) A(r) ,<br />
⎛<br />
⎜<br />
⎝<br />
A 1<br />
A 2<br />
⎞<br />
⎟<br />
⎠ <br />
L = − ir×∇<br />
A 3<br />
2. S 1 , S 2 , S 3 , S 2 = 2 , <br />
s = 1 <br />
3. S 1 , S 2 , S 3 3 × 3 S 3 <br />
⎛ ⎞ ⎛ ⎞ ⎛ ⎞<br />
1 0 0<br />
⎜ ⎟ ⎜ ⎟ ⎜ ⎟<br />
⎝ 0 ⎠ , ⎝ 1 ⎠ , ⎝ 0 ⎠<br />
0<br />
S 1 , S 2 , S 3 0 <br />
0<br />
, 0, ± 1 S 3 , <br />
S 1 , S 2 , S 3 0 <br />
1<br />
5.10 <br />
2k + 1 T kq ( q = −k, −k + 1, · · · , k ) J <br />
[ J ± , T kq ] = √ (k ∓ q)(k ± q + 1) T k q±1 , [ J z , T kq ] = q T k q (5.92)<br />
, T kq k ( spherical tensor operator of rank k ) <br />
2 , n <br />
[ n·J , T kq ] = ∑ T kq ′〈 kq ′ |n·J| kq 〉<br />
q ′<br />
| kq 〉 J 2 , J z <br />
<br />
V <br />
J 2 | kq 〉 = k(k + 1)| kq 〉 , J z | kq 〉 = q| kq 〉<br />
V 1 1 = − V 1 + iV 2<br />
√<br />
2<br />
, V 1 0 = V 3 , V 1 −1 = V 1 − iV 2<br />
√<br />
2<br />
(5.93)<br />
, (5.90) V 1 q , (5.92) k = 1, T 1 q = V 1 q <br />
, 1 J <br />
0
5 112<br />
F = F (θ, φ) <br />
<br />
L + Y kq F =<br />
<br />
(L + Y kq<br />
)<br />
F + Y kq L + F = √ (k − q)(k + q + 1) Y k q+1 F + Y kq L + F<br />
[ L + , Y kq ] = √ (k − q)(k + q + 1) Y k q+1<br />
[ L ± , Y kq ] = √ (k ∓ q)(k ± q + 1) Y k q±1 , [ L z , Y kq ] = q Y k q<br />
, Y kq k <br />
, J 2 , J z <br />
|α j m〉 <br />
〈α ′ j ′ m ′ |T kq |α j m〉 = 〈 j m k q | j ′ m ′ 〉 〈α′ j ′ ‖ T k ‖α j 〉<br />
√ 2j + 1<br />
(5.94)<br />
α j, m <br />
, m, m ′ , q CG 〈α ′ j ′ ‖ T k ‖ α j 〉 <br />
( reduced matrix element ) <br />
<br />
(5.92) <br />
J + T kq |jm〉 = [ J + , T kq ] |jm〉 + T kq J + |jm〉<br />
= √ (k − q)(k + q + 1) T k q+1 |jm〉 + √ (j − m)(j + m + 1) T kq |j m+1〉<br />
<br />
|(jk)j ′ m ′ 〉 ≡ ∑ m q<br />
T kq |j m〉〈 j m k q | j ′ m ′ 〉<br />
<br />
J + |(jk)j ′ m ′ 〉<br />
= ∑ (√<br />
〈 j m k q | j ′ m ′ 〉 (k − q)(k + q + 1) Tk q+1 |jm〉 + √ )<br />
(j − m)(j + m + 1) T kq |j m+1〉<br />
m q<br />
= ∑ m q<br />
(<br />
T k q |jm〉 〈 j m k q−1 | j ′ m ′ 〉 √ (k − q + 1)(k + q)<br />
CG (5.81) <br />
+ 〈 j m−1 k q | j ′ m ′ 〉 √ )<br />
(j − m + 1)(j + m)<br />
J + |(jk)j ′ m ′ 〉 = √ (j ′ − m ′ )(j ′ + m ′ + 1) ∑ m q<br />
T k q |jm〉〈 j m k q | j ′ m ′ +1 〉<br />
= √ (j ′ − m ′ )(j ′ + m ′ + 1) |(jk)j ′ m ′ +1〉<br />
<br />
J ± |(jk)j ′ m ′ 〉 = √ (j ′ ∓ m ′ )(j ′ ± m ′ + 1) |(jk)j ′ m ′ ± 1〉 (5.95)<br />
J z |(jk)j ′ m ′ 〉 = m ′ |(jk)j ′ m ′ 〉 (5.96)
5 113<br />
(5.15), (5.16) <br />
CG (5.80) <br />
∑<br />
<br />
〈j ′ m ′ |(jk)j ′′ m ′′ 〉 = δ j′ j ′′δ m ′ m ′′〈j′ m ′ |(jk)j ′ m ′ 〉<br />
∑<br />
|(jk)j ′ m ′ 〉〈j m k q|j ′ m ′ 〉 = ∑ T kq ′′|j m ′′ 〉〈j m ′′ k q ′′ |j ′ m ′ 〉〈j m k q|j ′ m ′ 〉<br />
j ′ m ′ j ′ m ′ m ′′ q ′′<br />
= ∑<br />
T kq ′′|j m ′′ 〉 δ mm ′′δ qq ′′<br />
m ′′ q ′′<br />
〈j ′ m ′ |T kq |j m〉 = ∑<br />
= T kq |j m〉<br />
j ′′ m ′′ 〈j ′ m ′ |(jk)j ′′ m ′′ 〉〈j m k q|j ′′ m ′′ 〉 = 〈j m k q|j ′ m ′ 〉C m ′<br />
C m ′ = 〈j ′ m ′ |(jk)j ′ m ′ 〉 C m ′ m ′ <br />
(<br />
〈j ′ m ′ |J − J + |(jk)j ′ m ′ 〉 = 〈j ′ m ′ |<br />
)<br />
J 2 − J z (J z + 1) |(jk)j ′ m ′ 〉<br />
(<br />
)<br />
= j ′ (j ′ + 1) − m ′ (m ′ + 1) C m ′<br />
, (5.15), (5.95) <br />
〈j ′ m ′ |J − J + |(jk)j ′ m ′ 〉 = (j ′ − m ′ )(j ′ + m ′ + 1)〈j ′ m ′ +1 |(jk)j ′ m ′ +1 〉<br />
= (j ′ − m ′ )(j ′ + m ′ + 1)C m′ +1<br />
, C m ′ +1 = C m ′ , C m ′ m ′ <br />
〈j ′ m ′ |(jk)j ′ m ′ 〉 = 〈j′ ‖ T k ‖j 〉<br />
√ 2j + 1<br />
<br />
〈j ′ m ′ |T kq |j m〉 = 〈 j m k q | j ′ m ′ 〉 〈j′ ‖ T k ‖j 〉<br />
√ 2j + 1<br />
(5.94) <br />
CG 〈 j m k q | j ′ m ′ 〉 CG <br />
, 〈α ′ j ′ m ′ |T kq |α j m〉 0 <br />
m + q = m ′ ,<br />
|j − k| ≤ j ′ ≤ j + k<br />
<br />
, 0 , , T 00 = S <br />
〈α ′ j ′ m ′ | S |α j m〉 = 〈 j m 0 0 | j ′ m ′ 〉 〈α′ j ′ ‖ S ‖α j 〉<br />
〈α<br />
√ = δ jj ′δ ′ j ‖ S ‖α j 〉<br />
mm ′ √ 2j + 1 2j + 1<br />
j m , m <br />
V j ′ = j <br />
〈α ′ j m ′ |V |α j m〉 = 〈α′ j m| J ·V |α j m〉<br />
j(j + 1)<br />
〈j m ′ | J |j m〉 (5.97)
5 114<br />
( projection theorem ) , V J V J<br />
, J e J e J = J/|J| <br />
V J = V ·e J e J = V ·J<br />
J 2 J<br />
, (5.97) V J <br />
<br />
<br />
V ·J (5.93) <br />
J ·V = ∑ q<br />
(−1) q J 1q V 1 −q<br />
, <br />
〈α ′ j m| J ·V |α j m〉 = m 〈α ′ j m| V 1 0 |α j m〉<br />
+ √ (j + m)(j − m + 1)/2 〈α ′ j m−1| V 1 −1 |α j m〉<br />
− √ (j − m)(j + m + 1)/2 〈α ′ j m+1| V 1 1 |α j m〉<br />
= C j<br />
〈α ′ j ‖ V ‖α j 〉<br />
√ 2j + 1<br />
(5.98)<br />
<br />
C j = m 〈 j m 1 0 | j m 〉 + √ (j + m)(j − m + 1)/2 〈 j m 1 −1 | j m−1 〉<br />
− √ (j − m)(j + m + 1)/2 〈 j m 1 1 | j m+1 〉<br />
J ·V m , C j m <br />
(5.98) <br />
V 1q = J 1q <br />
〈α ′ j m ′ |V 1 q |α j m〉 = 〈 j m 1 q | j m ′ 〉 〈α′ j ‖ V ‖α j 〉<br />
√ 2j + 1<br />
= 〈 j m 1 q | j m′ 〉<br />
C j<br />
〈α ′ j m| J ·V |α j m〉 (5.99)<br />
〈j m ′ |J 1q |j m〉 = 〈 j m 1 q | j′ m ′ 〉<br />
C j<br />
〈j m| J 2 |j m〉 = 〈 j m 1 q | j′ m ′ 〉<br />
C j<br />
j(j + 1) (5.100)<br />
, (5.99) (5.100) <br />
<br />
〈α ′ j m ′ |V 1q |α j m〉 = 〈α′ j m| J ·V |α j m〉<br />
j(j + 1)<br />
〈j m ′ |J 1q |j m〉<br />
5.21 2 T k1 q 1<br />
, T k2 q 2<br />
<br />
(T k1 T k2 ) kq<br />
≡ ∑ q 1 q 2<br />
〈k 1 q 1 k 2 q 2 |k q〉 T k1 q 1<br />
T k2 q 2<br />
(T k1 T k2 ) kq<br />
k
5 115<br />
5.22 1/2 µ µ = g l L + g s S <br />
〈 jm | µ z | jm 〉 | jm 〉 5.17 <br />
<br />
J 2 | jm 〉 = j(j + 1)| jm 〉 , L 2 | jm 〉 = l(l + 1)| jm 〉 , j = l ± 1/2
6 116<br />
6 <br />
6.1 <br />
V (r) r V (r) <br />
t r(t) , <br />
m d2 r<br />
dt 2<br />
= − ∇V (r) = − r r<br />
v = dr<br />
dt E = mv2 /2 + V (r) <br />
dE<br />
dt<br />
dv<br />
= mv·<br />
dt + dr<br />
dt<br />
dV<br />
dr<br />
·∇V = v·(<br />
m dv<br />
dt + ∇V )<br />
= 0<br />
L = m r×v <br />
dL<br />
dt<br />
dv<br />
= m v×v + m r×<br />
dt = − r×r 1 dV<br />
r dr = 0<br />
, , L = m r × v = <br />
xy z = 0 x, y 2 <br />
x = r cos θ , y = r sin θ <br />
ẋ = ṙ cos θ − r ˙θ sin θ ,<br />
ẏ = ṙ sin θ + r ˙θ cos θ<br />
<br />
E = m 2<br />
(<br />
ẋ 2 + ẏ 2) + V (r) = m 2<br />
|L| = |mr 2 ˙θ| = <br />
<br />
( ) ( )<br />
ṙ 2 + r 2 ˙θ2 + V (r) , L = m ( 0, 0, xẏ − ẋy ) = 0, 0, mr 2 ˙θ<br />
E = m 2 ṙ2 + V eff (r) , V eff (r) = V (r) + L2<br />
2mr 2<br />
√<br />
dr 2<br />
( )<br />
dt = ± E − V eff (r) , ∴<br />
m<br />
∫<br />
√ ∫<br />
dr<br />
2<br />
√<br />
E − Veff (r) = ± dt<br />
m<br />
V eff (r) 1 L 2 /(2mr 2 ) <br />
<br />
6.2 <br />
V (r) <br />
H ψ(r) = E ψ(r) ,<br />
H = p2<br />
2m + V (r) ,<br />
p = − i∇<br />
r , x, y, z <br />
r, θ, φ (5.21) ∇ 2 <br />
, <br />
(A×B)·(C×D) = A·C B·D − A·D B·C =<br />
3∑<br />
)<br />
(A i C i B j D j − A i D i B j C j<br />
i, j=1
6 117<br />
, , <br />
(A×B)·(C ×D) =<br />
3∑<br />
i=1 j=1<br />
3∑<br />
)<br />
(A i B j C i D j − A i B j C j D i<br />
A = C = r , B = D = ∇ L = − i r×∇ <br />
L 2 = − ∑ )<br />
(x i ∂ j x i ∂ j − x i ∂ j x j ∂ i , ∂ i = ∂<br />
∂x<br />
ij<br />
i<br />
1 ∂ j x i = x i ∂ j + δ ij , 2 x i ∂ j = ∂ j x i − δ ij <br />
L 2 = − ∑ ij<br />
x 2 i ∂ 2 j − 2 ∑ i<br />
x i ∂ i + ∑ ij<br />
∂ j x j x i ∂ i = − r 2 ∇ 2 − 2r·∇ + ∑ ij<br />
(x j ∂ j + 1) x i ∂ i<br />
<br />
∑<br />
x i ∂ i = 3 ∑<br />
ij<br />
i<br />
L 2 = − r 2 ∇ 2 + r·∇ + (r·∇) 2<br />
<br />
∂<br />
∂r = ∂x ∂<br />
∂r ∂x + ∂y<br />
∂r<br />
∂<br />
∂y + ∂z<br />
∂r<br />
x i ∂ i = 3r·∇<br />
<br />
∂<br />
∂z = x r<br />
∂<br />
∂x + y r<br />
∂<br />
∂y + z r<br />
∂<br />
∂z = 1 r r·∇<br />
L 2 = − r 2 ∇ 2 + r ∂ ∂r + r ∂ ∂r r ∂ ∂r = − r2 ∇ 2 + r ∂2<br />
∂r 2 r , ∴ ∇2 = 1 ∂ 2<br />
r ∂r 2 r − 1 r 2 L2 (6.1)<br />
r ≠ 0 L 2 (5.24) , L 2 <br />
L 2 r , <br />
V (r) H r ≠ 0 <br />
<br />
H = − 2<br />
2m ∇2 + V (r) = − 2<br />
2m<br />
1 ∂ 2<br />
r ∂r 2 r + 2 L 2<br />
+ V (r) (6.2)<br />
2mr2 L , (6.2) r <br />
, [ L 2 , L ] = 0 , H, L 2 , L z , <br />
ψ(r) L 2 , L z Y l ml (θ, φ) , H, L 2 , L z <br />
ψ(r) <br />
ψ(r) = R(r) Y l ml (θ, φ) ,<br />
m l = − l, − l + 1, · · · , l − 1, l<br />
( m L z m l ) R(r) R(r) Y lml<br />
L 2 , L z , H R(r) <br />
L 2 Y l ml (θ, φ) = l(l + 1)Y l ml (θ, φ)<br />
H ψ(r) = E ψ(r) <br />
(− 2 1 d 2<br />
2m r dr 2 r + 2 l(l + 1)<br />
2mr 2<br />
)<br />
+ V (r) R l (r) = E R l (r) (6.3)<br />
<br />
(− 2<br />
d 2<br />
2m dr 2 + 2 l(l + 1)<br />
2mr 2<br />
)<br />
+ V (r) χ l (r) = E χ l (r) , χ l (r) = rR l (r) (6.4)
6 118<br />
, <br />
r ≥ 0 r = 0 ψ(r) <br />
<br />
r d 3 r <br />
lim rR l(r) = χ l (0) = 0 (6.5)<br />
r→0<br />
|ψ(r)| 2 d 3 r = |R l (r)| 2 r 2 dr |Y l ml (θ, φ)| 2 dΩ = |χ l (r)| 2 dr |Y l ml (θ, φ)| 2 dΩ<br />
|Y l ml (θ, φ)| 2 1 , r r + dr |χ l (r)| 2 dr<br />
, χ l (r) <br />
∫ ∞<br />
0<br />
dr |χ l (r)| 2 = 1<br />
3 , χ l (0) = 0 <br />
( r ≥ 0 ) <br />
V eff (r) = V (r) + 2 l(l + 1)<br />
2mr 2 (6.6)<br />
1 V eff <br />
, l = 0 V eff (r) = V (r) V (r)<br />
1 , χ(0) = 0 , V (r) = V (− r) <br />
3 <br />
V (r) lim<br />
r→0<br />
r 2 V (r) = 0 χ l V (r) <br />
χ l (0) = 0 r → 0 χ l (r) = c r α , α > 0 <br />
(6.4) <br />
(<br />
− α(α − 1) + l(l + 1) + 2m<br />
2 (<br />
r 2 V (r) − r 2 E) ) r α−2 = 0<br />
lim<br />
r→0 r2 V (r) = 0 − α(α − 1) + l(l + 1) = 0 α = − l , l + 1 , α > 0 <br />
α = l + 1 <br />
r→0<br />
χ l (r) −−−−→ c r l+1 (6.7)<br />
r 2(l+1) , l l <br />
2 l(l + 1)/(2mr 2 ) , <br />
(6.4) 2 , χ l (r) 2 , 2<br />
r l+1 r −l , (6.4) 2 <br />
, (6.5) r −l <br />
1 , E (6.4) χ l (r) 1 <br />
, (6.3) (6.4) l m l , E <br />
l , m l = l, l − 1, · · · , − l 2l + 1 <br />
R l (r) Y l ml (θ, φ) , 2l + 1 H <br />
a m <br />
l∑<br />
m=−l<br />
a m R l (r)Y lm (θ, φ)<br />
1 χ l (r)
6 119<br />
, (6.1) r = 0 ∇ 2 1 = − 4π δ(r) , L r<br />
r<br />
, (6.1) <br />
(<br />
− 1 r<br />
∂ 2<br />
∂r 2 r + L2<br />
r 2 ) 1<br />
r = − 1 r<br />
∂ 2<br />
∂r 2 1 = 0<br />
, 1/r (6.1) r = 0 , (6.5) <br />
, (6.1) r = 0 <br />
∇ 2 ψ(r) = 0 , V (r) = 0 , E = 0 <br />
χ ∝ r l+1 χ ∝ r −l (6.4) ∇ 2 r l Y lml = 0 , ∇ 2 r −l−1 Y lml = 0 <br />
, r l Y lml r −l−1 Y lml <br />
<br />
χ l (r) r r ν <br />
∫<br />
∫ ∞<br />
〈r ν 〉 = d 3 r r ν |ψ(r)| 2 = dr r ν χ l (r) 2<br />
lim<br />
r→0<br />
r 2 V (r) = 0 r → 0 χ l → r l+1 , , r → ∞ <br />
χ l → 0 ν + 2l + 1 > 0 (6.4) <br />
χ ′′<br />
l(l + 1)<br />
l (r) − F (r)χ l (r) = 0 , F (r) =<br />
r 2 + 2m ( )<br />
2 V (r) − E<br />
r ν+1 χ ′ l χ′ l χ′′ l = (χ′ l 2)′<br />
/2 <br />
∫ ∞<br />
0<br />
dr r ν+1 χ ′ l χ ′′<br />
l = 1 2<br />
∫ ∞<br />
0<br />
dr r ν+1 (χ ′ 2<br />
l ) ′ = 1 2<br />
ν + 2l + 1 > 0 r → 0 χ l ∝ r l+1 r ν+1 χ ′ 2<br />
l<br />
∫ ∞<br />
χ ′ l χ l = (χ 2 l )′ /2 <br />
<br />
2<br />
∫ ∞<br />
0<br />
dr r ν+1 χ ′ l<br />
∫ ∞<br />
0<br />
0<br />
dr r ν+1 χ ′ l χ ′′<br />
l = − ν + 1<br />
2<br />
dr r ν+1 F (r)χ ′ l χ l = − 1 2<br />
(<br />
χ ′′<br />
l − F χ l<br />
)<br />
=<br />
∫ ∞<br />
[<br />
0<br />
] ∞<br />
r ν+1 χ ′ l<br />
2 − ν + 1<br />
0 2<br />
∫ ∞<br />
, (6.8) r ν χ l <br />
<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
dr r ν χ l χ ′′<br />
l = −<br />
dr r ν χ l<br />
(<br />
χ ′′<br />
∫ ∞<br />
0<br />
)<br />
l − F χ l =<br />
0<br />
dr χ ′ l (r ν χ l ) ′ = − ν<br />
ν(ν − 1)<br />
2<br />
∫ ∞<br />
0<br />
0<br />
∫ ∞<br />
0<br />
dr r ν χ ′ 2<br />
l<br />
∝ r ν+2l+1 → 0 <br />
∫ ∞<br />
0<br />
dr r ν χ ′ 2<br />
l<br />
dr χ 2 (<br />
l r ν+1 F ) ′<br />
(6.8)<br />
dr χ 2 (<br />
l r ν+1 F ) ∫ ∞<br />
′<br />
− (ν + 1) dr r ν χ ′ l 2 = 0 (6.9)<br />
=<br />
∫ ∞<br />
0<br />
ν(ν − 1)<br />
2<br />
dr r ν−2 χ 2 l −<br />
dr r ν−1 χ ′ l χ l −<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
0<br />
∫ ∞<br />
dr r ν−2 χ 2 l −<br />
dr r ν χ ′ 2<br />
l<br />
−<br />
dr r ν χ ′ 2<br />
l<br />
0<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
dr r ν χ ′ 2<br />
l<br />
dr r ν F χ 2 l = 0
6 120<br />
r ν χ ′ 2<br />
l<br />
2 (6.9) <br />
ν(ν 2 − 1)<br />
〈r ν−2 〉 − 2(ν + 1)〈r ν F 〉 − 〈r ν+1 F ′ 〉 = 0<br />
2<br />
V (r) = V 0 r κ ( κ > − 2 ), F (r) , ν + 2l + 1 > 0 <br />
ν<br />
(<br />
)<br />
ν 2 − 1 − 4l(l + 1) 〈r ν−2 〉 − 2mV ( )<br />
0<br />
2<br />
2 2ν + 2 + κ 〈r ν+κ 〉 + 4mE<br />
2 (ν + 1)〈rν 〉 = 0 (6.10)<br />
( κ = −1 ) <br />
, ν = 0 〈r 0 〉 = 1 <br />
E = 2 + κ 〈V (r)〉 (6.11)<br />
2<br />
(1.44) V (r) = V 0 r κ , r·∇V = r dV/dr = κV , (1.44)<br />
〈p 2 〉/2m = κ 〈V 〉/2 E = 〈p 2 〉/2m + 〈V 〉 = (1 + κ/2)〈V 〉 <br />
6.3 3 <br />
<br />
V (r) =<br />
{<br />
− V 0 , r < a<br />
0 , r > a , V 0 > 0<br />
r < a , (6.3) <br />
( 1<br />
ρ<br />
d 2<br />
)<br />
l(l + 1)<br />
ρ + 1 −<br />
dρ2 ρ 2 R l (r) = 0 , ρ = kr , k =<br />
√<br />
2m(E + V0 )<br />
2 (6.12)<br />
−V 0 < E < 0 k (15.36) <br />
, j l (ρ) n l (ρ) R l (ρ) = A l j l (ρ) + B l n l (ρ)<br />
(15.47) (6.5) B l<br />
r < a R l (r) = A l j l (kr) r > a (6.3) <br />
( 1<br />
z<br />
d 2<br />
)<br />
l(l + 1)<br />
z + 1 −<br />
dz2 z 2 R l (r) = 0 , z = iKr , K =<br />
= 0 <br />
√<br />
− 2mE<br />
z (15.36) , <br />
R l (r) = B l h (1)<br />
l<br />
(iKr) + C l h (2)<br />
l<br />
(iKr) r → ∞ (15.48) <br />
h (1)<br />
l<br />
(iKr) → − i−l<br />
Kr e−Kr h (2)<br />
l<br />
(iKr) → il<br />
Kr eKr<br />
, r → ∞ R l (r) C l = 0 <br />
<br />
⎧<br />
⎨<br />
√ √<br />
A l j l (kr) , r < a<br />
2m(E +<br />
R l (r) =<br />
⎩ B l h (1)<br />
l<br />
(iKr) , r > a , k = V0 )<br />
−2mE<br />
2 , K =<br />
2<br />
r = a R l (r) <br />
A l j l (ka) = B l h (1)<br />
dj l (kr)<br />
l<br />
(iKa) , A l dh (1)<br />
l<br />
(iKr)<br />
dr ∣ = B l (6.13)<br />
r=a<br />
dr ∣<br />
r=a<br />
2
6 121<br />
2 (15.43) <br />
(6.13) <br />
) (<br />
)<br />
A l<br />
(l j l (ka) − ka j l+1 (ka) = B l l h (1)<br />
l<br />
(iKa) − iβa h (1)<br />
l+1 (iKa)<br />
ka j l+1(ka)<br />
j l (ka)<br />
= iKa h(1) l+1 (iKa)<br />
h (1)<br />
l<br />
(iKa) , k2 + K 2 = 2mV 0<br />
2 (6.14)<br />
V 0 K , E = − 2 K 2 /(2m) <br />
(15.42) l = 0 (6.14) <br />
Ka = − ka cot(ka) (6.15)<br />
(2.8) α , β α = − β cot β , 1 <br />
(2.16) , l = 0 χ(0) = 0 1 <br />
<br />
(6.14) , <br />
<br />
√<br />
2mV0<br />
v 0 = a<br />
2 , ε = 2ma2 E<br />
2<br />
v 0 ≤ π/2 <br />
v 0 > π/2 l = 0 <br />
, v 0 > π <br />
l = 1 <br />
2 l(l + 1)/(2mr 2 ) l <br />
ε<br />
0<br />
−10<br />
−20<br />
l = 0<br />
l = 1<br />
l = 2<br />
l = 3<br />
0 π/2 π 3π/2 v 0<br />
, l v 0 v 0 > 3π/2<br />
2 l = 0 <br />
6.1<br />
l E → 0 (6.14)<br />
, l = 0 cos v 0 = 0 , l > 0 j l−1 (v 0 ) = 0 (15.43),<br />
(15.46), (15.47) <br />
6.2<br />
V 0 → + ∞ , a K → ∞ ( E →<br />
− ∞ ) , − V 0 E + V 0 = 2 k 2 /2m <br />
(6.14) k j l (ka) = 0 , V 0 → + ∞ <br />
, <br />
6.4 <br />
, <br />
144 Ze , −e <br />
V (r) <br />
V (r) = − 1 Ze 2<br />
= − Zαc , α = e2<br />
4πε 0 r r<br />
4πε 0 c = 1<br />
137.08
6 122<br />
α (6.4) <br />
(− 2<br />
d 2<br />
2m dr 2 + 2 l(l + 1)<br />
2mr 2<br />
E < 0 <br />
<br />
− Zαc<br />
r<br />
)<br />
− E χ l (r) = 0<br />
ρ = ar , a = 2 √ −2mE/ 2 (6.16)<br />
( d<br />
2<br />
l(l + 1)<br />
−<br />
dρ2 ρ 2 + λ ρ − 1 )<br />
√<br />
mc<br />
2<br />
χ l = 0 , λ = Zα<br />
4<br />
−2E<br />
(6.17)<br />
ρ → ∞ χ ′′<br />
l − χ l/4 = 0 χ l → e ±ρ/2 , <br />
χ l → e −ρ/2 , χ l → ρ l+1 2 <br />
χ l (ρ) = ρ l+1 e −ρ/2 v l (ρ) <br />
(<br />
dχ l<br />
d<br />
dρ = ρl+1 e −ρ/2 dρ + l + 1 − 1 )<br />
v l<br />
ρ 2<br />
(6.17) <br />
d 2 (<br />
χ l<br />
d<br />
dρ 2 = ρl+1 e −ρ/2 dρ + l + 1 − 1 ρ 2<br />
[ d<br />
= ρ l+1 e −ρ/2 2 (<br />
v l 2(l + 1)<br />
dρ 2 + − 1<br />
ρ<br />
) ( d<br />
dρ + l + 1 − 1 ρ 2<br />
) dvl<br />
)<br />
v l<br />
( 1<br />
dρ + 4 − l + 1<br />
ρ<br />
+<br />
) ]<br />
l(l + 1)<br />
ρ 2 v l<br />
ρ d2 v<br />
( )<br />
l<br />
dρ 2 + dvl<br />
( )<br />
2l + 2 − ρ<br />
dρ − l + 1 − λ v l = 0 (6.18)<br />
(15.59) a = l + 1 − λ, b = 2l + 2 , <br />
v l (ρ) = CM(l + 1 − λ, 2l + 2, ρ) (6.19)<br />
l + 1 − λ ≠ − n r , ( n r = 0, 1, 2, · · · ) , ρ → ∞ <br />
M(l + 1 − λ, 2l + 2, ρ) → e ρ , χ l → ρ l+1 e ρ/2<br />
χ l , l + 1 − λ = − n r M(− n r , 2l + 2, ρ) n r χ l <br />
0 λ = n r + l + 1 n (6.17) <br />
E n = − (Zα)2 mc 2<br />
2n 2 , n = n r + l + 1 = 1, 2, · · · (6.20)<br />
0<br />
l = 0 l = 1 l = 2 l = 3<br />
n l n <br />
<br />
, 3 <br />
, l <br />
Z = 1 E n ( n ≤ 5 ,<br />
l ≤ 3 ) (n, l) = (1, 0) <br />
(n, l) = (2, 0), (2, 1) l 2l + 1 <br />
, 4 n = 3 2<br />
(n, l) = (3, 0), (3, 1), (3, 2) 9 E n n 2 <br />
, l = 0, 1, 2, 3, · · · 1 s, p, d, f, g, · · ·<br />
En ( eV )<br />
−5<br />
−10<br />
−15
6 123<br />
, n 1s, 2s, 2p <br />
<br />
<br />
χ nl (r) = Cρ l+1 e −ρ/2 M(− n r , 2l + 2, ρ) , n r = n − l − 1 ≥ 0 (6.21)<br />
(6.20) (6.16) <br />
ρ = 2 r<br />
, a z = a B<br />
n a z Z , a B = <br />
mcα = <br />
ρ n , a B = 0.529 × 10 −10 m χ nl <br />
0<br />
∫ ∞<br />
0<br />
dr χ 2 nl = C 2 na z<br />
2<br />
∫ ∞<br />
0<br />
dρ ρ 2l+2 e −ρ( M(− n r , 2l + 2, ρ)<br />
(15.71) b = 2l + 2 , ν = 1 <br />
∫ ∞<br />
dr χ 2 nl = C 2 na (<br />
z n r ! Γ (2l + 3)<br />
1 + n )<br />
r<br />
= C 2 n 2 [(2l + 1)!] 2 (n − l − 1)!<br />
a z<br />
2 (2l + 2) nr l + 1<br />
(n + l)!<br />
, <br />
√<br />
1 1<br />
χ nl (ρ) =<br />
n(2l + 1)! a z<br />
√<br />
= 1 1<br />
n<br />
a z<br />
) 2<br />
= 1 (6.22)<br />
(n + l)!<br />
(n − l − 1)! ρl+1 e −ρ/2 M(l + 1 − n, 2l + 2, ρ) (6.23)<br />
(n + l)!<br />
(n − l − 1)! ρl+1 e −ρ/2 L 2l+1<br />
n−l−1<br />
(ρ) (6.24)<br />
L k n(ρ) (15.89) ( Laguerre ) <br />
n = 1 l = 0 , n = 2 l = 0, 1 (15.66) <br />
χ 10 (r) = 1 √<br />
az<br />
ρ e −ρ/2 = 2 √<br />
az<br />
χ 21 (r) =<br />
χ 20 (r) = 1 √ 2az<br />
ρ<br />
1<br />
2 √ 6a z<br />
ρ 2 e −ρ/2 =<br />
r<br />
a z<br />
e −r/az (6.25)<br />
1<br />
2 √ r 2<br />
e −r/(2az) (6.26)<br />
6a z<br />
a 2 z<br />
(<br />
1 − ρ )<br />
e −ρ/2 = √ 1<br />
2<br />
2az<br />
(<br />
r<br />
1 − r )<br />
e −r/(2az) (6.27)<br />
a z 2a z<br />
χ 2 nl<br />
(r) <br />
χ 2 21 n <br />
<br />
ρ n <br />
e −ρ/2 = e −r/(na z) <br />
, M(− n r , 2l + 2, ρ) n r <br />
n r ,<br />
n r = n − l − 1 χ nl (r) = 0 r ≠ 0<br />
<br />
0.5<br />
azχ 2 nl<br />
0<br />
(10)<br />
(21) (20)<br />
5 10 r/a z<br />
, L , E <br />
E = m 2 ṙ2 +<br />
L2<br />
2mr 2 − Zαc , m r<br />
2 ṙ2 = E − L2<br />
2mr 2 + Zαc ≥ 0<br />
r
6 124<br />
r L 2 = 2 l(l + 1) E (6.20) <br />
<br />
E −<br />
L2<br />
2mr 2 + Zαc = − (Zα)2 mc 2 (<br />
)<br />
r 2n 2 r 2 r 2 − 2n 2 a z r + n 2 l(l + 1)a 2 z<br />
r − ≤ r ≤ r + , r ± = a z<br />
(n 2 ± n √ )<br />
n 2 − l(l + 1)<br />
r − , r + (2.37), (4.25) <br />
, P cl (r) <br />
<br />
∫ r+<br />
r −<br />
dr<br />
<br />
P cl (r) ∝ 1<br />
dr/dt ∝ r<br />
√<br />
(r+ − r)(r − r − )<br />
[<br />
r<br />
√<br />
(r+ − r)(r − r − ) = − √ (r + − r)(r − r − ) − r + + r −<br />
sin −1 r ] r+<br />
+ + r − − 2r<br />
2<br />
r + − r − r −<br />
= π ) (r + + r − = πa z n 2<br />
2<br />
P cl (r) = 1<br />
r<br />
√<br />
πa z n 2 (r+ − r)(r − r − )<br />
(6.28)<br />
P cl (r) 1 , P cl χ 2 nl ,<br />
r , n r χ 2 nl , P cl ( )<br />
0.005<br />
(n, l) = (20, 0)<br />
(n, l) = (20, 12)<br />
azχ 2 nl<br />
0<br />
200 400 600 800 r/a z<br />
(6.10) <br />
2m<br />
2 V 0 = − 2m<br />
2 Zαc = − 2 ,<br />
a z<br />
4mE<br />
2<br />
= − 4m<br />
2 (Zα) 2 mc 2<br />
2n 2 = − 2<br />
n 2 a 2 z<br />
κ = − 1 (6.10) ν + 2l + 1 > 0 <br />
ν<br />
(<br />
)<br />
ν 2 − 1 − 4l(l + 1) a 2<br />
4<br />
z〈r ν−2 〉 + (2ν + 1) a z 〈r ν−1 〉 − ν + 1<br />
n 2 〈rν 〉 = 0 , 〈r ν 〉 ≡<br />
〈r 0 〉 = 1 ν = 0, 1, 2, · · · <br />
∫ ∞<br />
0<br />
dr r ν χ 2 nl<br />
〈r −1 〉 = 1<br />
n 2 , 〈r〉 = 3n2 − l(l + 1)<br />
a z , 〈r 2 〉 = n 2 5n2 + 1 − 3l(l + 1)<br />
a 2 z , · · · (6.29)<br />
a z 2<br />
2<br />
r −1 , r, r 2 , · · · χ nl , 〈r −2 〉
6 125<br />
( MeV = 10 6 eV , fm = 10 −15 m , m = )<br />
α =<br />
e2<br />
4πε 0 c = 1<br />
137.08 ≈ 1<br />
137 , α2 = 0.5322 × 10 −4 ≈ 1<br />
20000<br />
(6.30)<br />
c = 197.327 MeV fm ≈ 200 MeV fm , mc 2 = 0.511 MeV ≈ 0.5 MeV (6.31)<br />
, e 2 , m , <br />
, ( Z = 1 ) , (6.20) <br />
α 2 mc 2<br />
2<br />
≈ 1 0.5 50<br />
MeV = eV = 12.5 eV , ( 13.60 eV )<br />
20000 2 4<br />
<br />
6.3 a B = <br />
mcα <br />
6.4<br />
(6.20) n 2 , <br />
6.5 (15.71) 〈r −1 〉 (6.29) , 〈r −2 2<br />
〉 =<br />
(2l + 1)n 3 a 2 z<br />
<br />
<br />
6.5 3 <br />
V (r) = mω 2 r 2 /2 , a = √ mω/ (6.4) <br />
( d<br />
2<br />
l(l + 1)<br />
−<br />
dq2 q 2 − q 2 + 2E )<br />
√ mω<br />
χ l (q) = 0 , q = ar =<br />
ω<br />
<br />
r<br />
q → ∞ ( d<br />
2<br />
dq 2 − q2 )<br />
χ l (q) = 0<br />
<br />
d 2<br />
dq 2 e−q2 /2 = ( q 2 − 1 ) e −q2 /2 → q 2 e −q2 /2<br />
( q → ∞ )<br />
q → ∞ χ l → e −q2 /2 χ l (q) = q l+1 e −q2 /2 v l (q) <br />
(<br />
dχ l<br />
dq = ql+1 e −q2 /2 d<br />
dq + l + 1 )<br />
− q v l<br />
q<br />
d 2 (<br />
χ l<br />
dq 2 = ql+1 e −q2 /2 d<br />
dq + l + 1 ) ( d<br />
− q<br />
q dq + l + 1 )<br />
− q v l<br />
q<br />
( ( ) )<br />
= q l+1 e −q2 /2 d<br />
2 l + 1 d<br />
dq 2 + 2 l(l + 1)<br />
− q +<br />
q dq q 2 − 2l − 3 + q 2 v l<br />
<br />
ρ = q 2 <br />
d 2 ( ) (<br />
v l l + 1<br />
dq 2 + 2 dvl<br />
− q<br />
q dq − 2l + 3 − 2E )<br />
v l = 0<br />
ω<br />
d<br />
dq = dρ d<br />
dq dρ = 2√ ρ d dρ , d 2<br />
dq 2 = 4√ ρ d (<br />
√ d ρ<br />
dρ dρ = 4 ρ d2<br />
dρ 2 + 1 2<br />
)<br />
d<br />
dρ
6 126<br />
<br />
(<br />
ρ d2 v l<br />
dρ 2 + l + 3 )<br />
2 − ρ dvl<br />
dρ − a′ v l = 0 , a ′ ≡ 1 (<br />
l + 3 2 2 − E )<br />
ω<br />
(15.59) a = a ′ , b = l + 3/2 (15.65) <br />
(6.32)<br />
<br />
χ l (q) =<br />
v l (ρ) = C M(a ′ , l + 3/2, ρ) + Dρ −l−1/2 M(a ′ − l − 1/2, 1/2 − l, ρ)<br />
(<br />
)<br />
Cq l+1 M(a ′ , l + 3/2, q 2 ) + Dq −l M(a ′ − l − 1/2, 1/2 − l, q 2 ) e −q2 /2<br />
χ l (0) = 0 D = 0 a ′ ≠ − n , ( n = 0, 1, 2, · · · ) q → ∞ <br />
χ l (q) = C q l+1 e −q2 /2 M(a ′ , l + 3/2, q 2 ) → C q l+1 e −q2 /2 e q2 = C q l+1 e q2 /2<br />
a ′ = − n <br />
(<br />
E nl = ω 2n + l + 3 )<br />
2<br />
(6.33)<br />
<br />
ψ nlml (r) = χ nl(r)<br />
r<br />
ρ = q 2 <br />
∫ ∞<br />
0<br />
Y l ml (θ, φ) , χ nl (r) = A nl q l+1 e −q2 /2 M ( −n , l + 3/2 , q 2 ) (6.34)<br />
dr χ nl (r) 2 = A2 nl<br />
2a<br />
∫ ∞<br />
0<br />
dρ ρ l+1/2 e −ρ( M(−n, l + 3/2, ρ)) 2<br />
= 1<br />
(15.71) b = l + 3/2 , ν = 0 <br />
A 2 nl<br />
2a<br />
√<br />
n! Γ (l + 3/2)<br />
Γ (l + n + 3/2)<br />
= 1 , ∴ A nl = 2a<br />
(l + 3/2) n n! Γ 2 (l + 3/2)<br />
(6.35)<br />
n χ nl (r) = 0 r = 0 <br />
(6.33) <br />
N = 2n + l (n, l ) <br />
, <br />
, l <br />
N , l <br />
l = N − 2n , n = 0, 1, 2, · · · , [N/2]<br />
[N/2] n, l <br />
(6.34) 2l + 1 , <br />
ω(N + 3/2) D N <br />
Enl/ω<br />
11/2<br />
9/2<br />
7/2<br />
5/2<br />
3/2<br />
l = 0 l = 1 l = 2 l = 3 l = 4<br />
(2, 0) (1, 2) (0, 4)<br />
(1, 1) (0, 3)<br />
(1, 0) (0, 2)<br />
(0, 1)<br />
(0, 0)<br />
[N/2]<br />
[N/2]<br />
∑<br />
∑ (<br />
D N = (2l + 1) = 2 ( N − 2n ) )<br />
+ 1 =<br />
n=0<br />
n=0<br />
(N + 1)(N + 2)<br />
2<br />
(6.36)
6 127<br />
χ 2 02<br />
N = 2 , χ 2 nl (r) () χ2 10, <br />
(6.34), (6.35) <br />
√ ( 6a<br />
χ 10 =<br />
π q 1 − 2 ) √<br />
16a<br />
1/2 3 q2 e −q2 /2 , χ 02 =<br />
15π 1/2 q3 e −q2 /2<br />
(6.28) , P cl (r) <br />
P cl (r) = 2 r<br />
√<br />
, (ar ± ) 2 = N + 3 √(N<br />
π<br />
(r+ 2 − r 2 )(r 2 − r−)<br />
2 2 ± + 3/2) 2 − l(l + 1) (6.37)<br />
, n P cl χ 2 nl <br />
, r , n χ 2 nl , P cl(r) <br />
( )<br />
1<br />
0.5<br />
(n, l) = (10, 6)<br />
χ 2 nl /a<br />
0.5<br />
χ 2 nl /a<br />
0<br />
1 2 3 ar<br />
0<br />
2 4 6 8 ar<br />
6.6<br />
(6.37) <br />
6.7<br />
l = 0 , , 1 χ(0) = 0 <br />
, 1 , l = 0 <br />
, (6.33) 1 ω(n + 1/2) n 2n + 1 <br />
(6.34) χ n0 1 (4.22)<br />
√<br />
ϕ n (r) = C n e −a2 r 2 a<br />
/2 H n (ar) , C n =<br />
π 1/2 n! 2 n<br />
χ n0 (r) = (−1) n√ 2 ϕ 2n+1 (r) 268 15.12 <br />
6.8 ψ nlml r 2 〈r 2 〉 <br />
〈r 2 〉 =<br />
∫ ∞<br />
0<br />
dr r 2 χ 2 nl = A2 nl<br />
a 3<br />
∫ ∞<br />
0<br />
dq q 2l+4 e −q2( M(−n, l + 3/2, q 2 )<br />
) 2<br />
(15.71) 〈r 2 〉 <br />
〈V (r)〉 = ω 2<br />
(<br />
2n + l + 3 )<br />
= E nl<br />
2 2<br />
1 , (1.44) , (6.11) κ = 2
6 128<br />
<br />
3 , 3 1 ( x 1 = x, x 2 = y, x 3 = z )<br />
H = H 1 + H 2 + H 3 ,<br />
H k = p2 k<br />
2m + 1 2 mω2 x 2 k ( k = 1, 2, 3 )<br />
, ϕ ϕ(r) = X(x) Y (y) Z(z) , Hϕ = Eϕ , <br />
, ϕ −1 Hϕ = E <br />
1<br />
X H 1X + 1 Y H 2Y + 1 Z H 3Z = E<br />
1 , 2 , 3 x, y, z , <br />
, , E 1 , E 2 , E 3 <br />
H 1 X = E 1 X , H 2 Y = E 2 Y , H 3 Z = E 3 Z , E = E 1 + E 2 + E 3<br />
1 , H <br />
(<br />
H ϕ n1 n 2 n 3<br />
(r) = ω n 1 + n 2 + n 3 + 3 )<br />
ϕ n1 n<br />
2<br />
2 n 3<br />
(r) , ϕ n1 n 2 n 3<br />
(r) = ϕ n1 (x) ϕ n2 (y) ϕ n3 (z)<br />
n 1 , n 2 , n 3 , ϕ n (x) 1 (4.22) H <br />
N = n 1 + n 2 + n 3 , N ( N = 0, 1, 2, 3, · · · ) n 1 + n 2 + n 3 = N<br />
ϕ n1 n 2 n 3<br />
, ( N = 0 ) , D N<br />
N ◦ 2 • <br />
1 <br />
◦} ◦ ·{{ · · ◦ ◦}<br />
• ◦} ◦ ·{{ · · ◦ ◦}<br />
• ◦} ◦ ·{{ · · ◦ ◦}<br />
n 1 n 2 n 3<br />
D N = N+2 C 2 =<br />
(6.36) <br />
(N + 1)(N + 2)<br />
2<br />
(6.38)<br />
<br />
(6.34) ψ nlml (r) <br />
ϕ n1 n 2 n 3<br />
(r) = C n1 C n2 C n3 e −a2 r 2 /2 H n1 (x)H n2 (y)H n3 (z)<br />
H ψ nlml (r) L 2 , L z , ϕ n1 n 2 n 3<br />
(r) <br />
H 1 , H 2 , H 3 , ψ nlml<br />
H 1 , H 2 , H 3 <br />
, ϕ n1 n 2 n 3<br />
(r) L 2 , L z ω(N + 3/2) <br />
ψ nlml (r) ϕ n1 n 2 n 3<br />
(r) D N <br />
∑<br />
∑<br />
C n1n 2n 3<br />
ϕ n1n 2n 3<br />
(r) , D nlml ψ nlml (r)<br />
n 1 n 2 n 3<br />
n 1 +n 2 +n 3 =N<br />
n l m l<br />
2n+l=N<br />
H ω(N + 3/2) , , ψ nlml (r) ϕ n1n 2n 3<br />
(r) <br />
N = 0, 1 <br />
N = 0 , n 1 = n 2 = n 3 = 0 , n = l = m l = 0 ψ 000 (r) = ϕ 000 (r) <br />
, M( 0, b, x ) = 1 , Y 00 (θ, φ) = 1/ √ 4π , H 0 (x) = 1 <br />
ψ 000 (r) = A e −a2 r 2 /2 , ϕ 000 (r) = C0 3 e −α2 r 2 /2 , A = aA √<br />
00 a<br />
3<br />
√ = 4π π = 3/2 C3 0
6 129<br />
N = 1 3 <br />
( n 1 , n 2 , n 3 ) = ( 1, 0, 0 ) , ( 0, 1, 0 ) , ( 0, 0, 1 ) n = 0, l = 1, m l = 0, ±1<br />
√<br />
4π<br />
3 rY 10 = r cos θ = z ,<br />
√<br />
4π<br />
3 rY 1 ±1 = ∓<br />
r sin θ e±iφ<br />
√<br />
2<br />
= ∓ x − iy √<br />
2<br />
M( 0, b, x ) = 1 (6.34) <br />
⎧<br />
⎪⎨ z , m l = 0<br />
ψ 01ml = A e −a2 r 2 /2 rY 1 ml = A e −a2 r 2 /2 × ∓ x − iy<br />
⎪⎩ √ , 2<br />
m l = ±1 , √<br />
A = 2a 5<br />
π √ π<br />
, , H 0 (x) = 1 , H 1 (x) = 2x <br />
ϕ 100 = C x e −a2 r 2 /2 , ϕ 010 = C y e −a2 r 2 /2 , ϕ 001 = C z e −a2 r 2 /2 , C = 2aC 2 0C 1 = A<br />
<br />
ψ 010 = ϕ 001 , ψ 01 ±1 = ∓ ϕ 100 − iϕ 010<br />
√<br />
2<br />
<br />
6.6 2 <br />
H <br />
H = − 2<br />
2m<br />
( ∂<br />
2<br />
∂x 2 + ∂2<br />
∂y 2 )<br />
+ V (r) , r = √ x 2 + y 2<br />
2 x = r cos θ , y = r sin θ <br />
<br />
H <br />
∂ 2<br />
∂x 2 + ∂2<br />
∂y 2 = ∂2<br />
∂r 2 + 1 ∂<br />
r ∂r + 1 ∂ 2<br />
r 2 ∂θ 2 = √ 1 ∂ 2 √ 1 r + r ∂r 2 4r 2 + 1 ∂ 2<br />
r 2 ∂θ 2<br />
(<br />
H = − 2 1√r ∂ 2 √ 1 r +<br />
2m ∂r 2 4r 2 + 1 ∂ 2 )<br />
r 2 ∂θ 2 + V (r) (6.39)<br />
(<br />
L z = − i x ∂ ∂y − y ∂ )<br />
= − i ∂ ∂x ∂θ<br />
, H L z L z ϕ(θ), m z <br />
<br />
− i dϕ<br />
dθ = m zϕ , ∴ ϕ = Ne im zθ<br />
r ϕ(θ) = ϕ(θ + 2π) , , e 2πm zi = 1 <br />
m z , H L z ψ(r) <br />
ψ(r) = χ(r) √ r<br />
e imzθ<br />
√<br />
2π<br />
, m z = 0, ±1, ±2, · · ·<br />
(6.39) <br />
H χ(r)<br />
(<br />
√ e imzθ = eim zθ<br />
√ − 2<br />
r r 2m<br />
d 2<br />
dr 2 + 2<br />
2m<br />
m 2 z − 1/4<br />
r 2<br />
)<br />
+ V (r) χ(r)
6 130<br />
Hψ(r) = Eψ(r) <br />
(− 2<br />
2m<br />
<br />
<br />
∫ ∞<br />
0<br />
d 2<br />
dr 2 + 2<br />
2m<br />
dr r<br />
∫ 2π<br />
0<br />
m 2 z − 1/4<br />
r 2<br />
dθ |ψ(r)| 2 =<br />
)<br />
+ V (r) χ(r) = E χ(r) (6.40)<br />
∫ ∞<br />
0<br />
dr |χ(r)| 2 = 1<br />
r → 0 χ(r) → r α <br />
2 (<br />
− α(α − 1) + m 2 z − 1 ) ( )<br />
r α−2 + V (r) − E r α = 0<br />
2m<br />
4<br />
<br />
− α(α − 1) + m 2 z − 1 4 + 2m ( )<br />
2 V (r) − E r 2 = 0<br />
r → 0 r 2 V (r) → 0 <br />
− α(α − 1) + m 2 z − 1 4 = 0 , ∴ α = ± m z + 1 2<br />
α ≥ 0 α = |m z | + 1/2 <br />
2 , , 1 (6.40) <br />
l(l + 1) = (l + 1/2) 2 − 1/4 l = |m z | − 1/2 , (6.40) (6.4) ,<br />
r → 0 r |mz|+1/2 = r l+1 , 3 , 3 <br />
l = |m z | − 1/2 , 2 <br />
, (6.19) l = |m z | − 1/2 <br />
v = CM(|m z | + 1/2 − λ, 2|m z | + 1, ρ)<br />
<br />
|m z | + 1/2 − λ = − n r , n r = 0, 1, 2, · · ·<br />
<br />
E = − (Zα)2 mc 2<br />
2λ 2 = − (Zα)2 mc 2<br />
2(n − 1/2) 2 , n = |m z| + n r + 1 = 1, 2, 3, · · ·<br />
, 3 (6.21) <br />
<br />
χ(r) = C 1 ρ |mz|+1/2 e −ρ/2 M(− n r , 2|m z | + 1, ρ)<br />
6.9 2 <br />
V (r) =<br />
(x mω2 2 + y 2)<br />
2<br />
<br />
(<br />
)<br />
E = ω 2n + |m z | + 1 , ψ(r) = C r |mz| e −a2 r 2 /2 M(−n, |m z | + 1, a 2 r 2 ) e im zθ<br />
( )<br />
E = ω N + 1 , <br />
<br />
(<br />
)<br />
E = ω n 1 + n 2 + 1 , ψ(r) = ϕ n1 (x)ϕ n2 (y)
6 131<br />
6.7 <br />
λ <br />
(6.4) <br />
q = r λ ,<br />
ε = 2mλ2 E<br />
2 , U l (q) = 2mλ2 l(l + 1)<br />
2 V (r) +<br />
q 2<br />
d 2 χ l<br />
dq 2<br />
( )<br />
+ ε − Ul (q) χ l = 0 (6.41)<br />
(2.38) , 2.4 1 <br />
, q ≥ 0 l(l + 1)/q 2 <br />
q min ≤ q ≤ q max , q max q = q max 1<br />
, q min = 0 l ≠ 0 U(0) , q min <br />
, q min = 10 −6 r → 0 r 2 V (r) → 0 (6.7) χ l → r l+1 <br />
, <br />
χ l (q min ) = q l+1<br />
min , χ l(q min + ∆q) = (q min + ∆q) l+1 (6.42)<br />
U l (q) l , 37 <br />
, l main <br />
.....<br />
int nc, nq, l; // l() <br />
int main()<br />
{<br />
.....<br />
<strong>qm</strong>ax=<strong>qm</strong>in+nq*dq; qc=<strong>qm</strong>in+nc*dq;<br />
for( l=0; l
6 132<br />
d = 0.1, 0.5, 1 U(q)/u 0 d → + 0<br />
e (q−1)/d → ∞ ( q − 1 > 0 ) , 0 ( q − 1 < 0 ) <br />
U(q) <br />
0 1 2 3 q<br />
{<br />
0 , q > 1<br />
U(q) →<br />
−0.5<br />
− u<br />
1<br />
0 , q < 1<br />
(6.14) <br />
0.5<br />
l = 0, 1 , d −1.0 0.1<br />
ε (6.14) <br />
<br />
√<br />
2ma2 (E + V 0 )<br />
ka =<br />
2 = √ √<br />
− 2ma2 E<br />
ε + u 0 , Ka =<br />
2<br />
l = 0 (6.14) (6.15) , l = 1 (15.42) <br />
= √ − ε<br />
√<br />
− ε (ε + u0 ) + ε √ ε + u 0 cot √ ε + u 0 + u 0 = 0<br />
<br />
d 1 , U(q) q = 1 <br />
U(q) ≈ U(1) + U ′ (1)(q − 1) = − u (<br />
0<br />
1 + 1 )<br />
+ u 0<br />
2 2d 4d q (6.43)<br />
l = 0 (6.41) q = (4d/u 0 ) 1/3 z <br />
d 2 χ 0<br />
dz 2 + (ε′ − z) χ 0 = 0 , ε ′ =<br />
( ) 2/3 [ 4d<br />
ε + u 0<br />
u 0 2<br />
(<br />
1 + 1 ) ]<br />
2d<br />
(2.33) a n Ai(x) ε ′ = − a n <br />
, a n (2.35) <br />
ε ≈ − u (<br />
0<br />
1 + 1 ) [ 3πu0<br />
+<br />
2 2d 8d<br />
l = 0 ε (6.44) <br />
(<br />
n − 1 4) ] 2/3<br />
, n = 1, 2, 3, · · · (6.44)<br />
l = 0 ε d , ε , <br />
(6.44) n = 1, 2, · · · (6.15) <br />
d = 1 χ 2 0 d = 1 , (6.43) <br />
q 2.5 n = 1, 2 , <br />
, (6.43) , n = 3 <br />
0<br />
ε<br />
−10<br />
χ 2 0<br />
1.0<br />
n = 1<br />
n = 2<br />
n = 3<br />
u 0 = 30.0<br />
l = 0<br />
d = 1.0<br />
−20<br />
u 0 = 30.0<br />
l = 0<br />
0.5<br />
0 1 2<br />
d<br />
0.0<br />
0 1 2 3 4 q
7 133<br />
7 <br />
<br />
, A F (A) a A | a 〉<br />
<br />
A| a 〉 = a | a 〉<br />
| a 〉 F (A) <br />
F (A)| a 〉 = F (a) | a 〉<br />
F (a) F (A) A , <br />
A n | a 〉 = a n | a 〉 |ψ〉 <br />
|ψ〉 <br />
|ψ〉 = ∑ c a | a 〉 , c a = <br />
a<br />
<br />
F (A)|ψ〉 = ∑ a<br />
c a F (A) | a 〉 = ∑ a<br />
c a F (a) | a 〉<br />
F (A) <br />
, 1<br />
z + ∇ 2 , ∇2 e ik·r = − k 2 e ik·r<br />
1<br />
eik·r<br />
z + ∇ 2 = 1<br />
eik·r<br />
z − k 2<br />
<br />
ψ(r) <br />
∫<br />
ψ(r) = d 3 k a(k) e ik·r<br />
<br />
∫<br />
1<br />
z + ∇ 2 ψ(r) = d 3 k a(k)<br />
∫<br />
1<br />
eik·r<br />
z + ∇ 2 = d 3 k<br />
a(k)<br />
z − k 2 eik·r<br />
a(k) , ψ(r) <br />
7.1 <br />
H , <br />
( 34 , 131 ), , <br />
, <br />
H 2 <br />
H = H 0 + H ′<br />
, H 0 H 0 E n , <br />
| n 〉 | n 〉 :<br />
H 0 | n 〉 = E n | n 〉 ,<br />
〈 m | n 〉 = δ mn
7 134<br />
H ′ H 0 , H 0 , H ′ <br />
, H |ψ〉 W<br />
H|ψ〉 = W |ψ〉<br />
<br />
H ′ H <br />
H λ |ψ〉 = W |ψ〉 , H λ = H 0 + λ H ′ (7.1)<br />
, |ψ〉 W λ λ = 0 , |ψ〉 W <br />
, λ = 1 |ψ〉, W<br />
<br />
∞∑<br />
∞∑<br />
|ψ〉 = λ k |ψ k 〉 , W = λ k W k<br />
k=0<br />
k=0<br />
(7.1) <br />
∞∑<br />
∞∑<br />
∞∑<br />
λ k H 0 |ψ k 〉 + λ k H ′ |ψ k−1 〉 =<br />
λ k<br />
k=0<br />
k=1<br />
k=0 k ′ =0<br />
k∑<br />
W k−k ′|ψ k ′〉<br />
λ <br />
k∑<br />
H 0 |ψ 0 〉 = W 0 |ψ 0 〉 , H 0 |ψ k 〉 + H ′ |ψ k−1 〉 = W k−k ′|ψ k ′〉 , ( k ≥ 1 )<br />
<br />
(H 0 − W 0 ) |ψ 0 〉 = 0 (7.2)<br />
(H 0 − W 0 ) |ψ 1 〉 = (W 1 − H ′ ) |ψ 0 〉 (7.3)<br />
(H 0 − W 0 ) |ψ 2 〉 = (W 1 − H ′ ) |ψ 1 〉 + W 2 |ψ 0 〉 (7.4)<br />
<br />
(H 0 − W 0 ) |ψ k 〉 = (W 1 − H ′ ) |ψ k−1 〉 + W 2 |ψ k−2 〉 + · · · + W k |ψ 0 〉 (7.5)<br />
<br />
(7.3) ∼ (7.5) |ψ k 〉 <br />
|ψ k〉 ′ = |ψ k 〉 + α|ψ 0 〉 , α = <br />
k ′ =0<br />
<br />
(H 0 − W 0 ) |ψ ′ k〉 = (H 0 − W 0 ) |ψ k 〉 + α (H 0 − W 0 ) |ψ 0 〉 = (H 0 − W 0 ) |ψ k 〉<br />
, (7.3) ∼ (7.5) , |ψ k 〉 α|ψ 0 〉 <br />
, <br />
〈ψ 0 |ψ k〉 ′ = 〈ψ 0 |ψ k 〉 + α〈ψ 0 |ψ 0 〉 = 0<br />
|ψ<br />
k ′ 〉 |ψ k〉 <br />
〈ψ 0 |ψ k 〉 = 0 , k ≥ 1 (7.6)
7 135<br />
<br />
H 0 (7.2) <br />
〈ψ 0 | (H 0 − W 0 ) |ψ k 〉 ∗ = 〈ψ k | (H 0 − W 0 ) |ψ 0 〉 = 0<br />
(7.5) |ψ 0 〉 (7.6) <br />
0 = − 〈ψ 0 |H ′ |ψ k−1 〉+W 1 〈ψ 0 |ψ k−1 〉+· · ·+W k−1 〈ψ 0 |ψ 1 〉+W k 〈ψ 0 |ψ 0 〉 = − 〈ψ 0 |H ′ |ψ k−1 〉+W k 〈ψ 0 |ψ 0 〉<br />
<br />
<br />
W k = 〈ψ 0|H ′ |ψ k−1 〉<br />
〈ψ 0 |ψ 0 〉<br />
(7.7)<br />
7.2 <br />
1 <br />
(7.2) |ψ 0 〉 H 0 |ψ 0 〉 <br />
|ψ 0 〉 = | i 〉 , W 0 = E i<br />
E i , , E i | i 〉 <br />
, |ψ 0 〉 , |ψ 0 〉 = | i 〉<br />
E i <br />
(7.7) k = 1 <br />
W 1 = 〈ψ 0|H ′ |ψ 0 〉<br />
〈ψ 0 |ψ 0 〉<br />
= 〈 i |H ′ | i 〉<br />
1 , H ′ <br />
, |ψ 1 〉 |ψ 1 〉 H 0 <br />
|ψ 1 〉 = ∑ n<br />
c n | n 〉<br />
(7.3) <br />
∑<br />
c n (H 0 − E i ) | n 〉 = (W 1 − H ′ ) | i 〉<br />
n<br />
H 0 | n 〉 = E n | n 〉 <br />
∑<br />
c n (E n − E i ) | n 〉 = (W 1 − H ′ ) | i 〉<br />
n<br />
| m 〉 <br />
= ∑ n<br />
c n (E n − E i ) 〈 m | n 〉 = ∑ n<br />
c n (E n − E i ) δ mn = c m (E m − E i )<br />
= W 1 〈 m | i 〉 − 〈 m |H ′ | i 〉 = W 1 δ mi − 〈 m |H ′ | i 〉<br />
<br />
c m (E m − E i ) = 〈 i |H ′ | i 〉 δ mi − 〈 m |H ′ | i 〉 (7.8)
7 136<br />
| i 〉 m ≠ i E m ≠ E i <br />
c m = 〈 m |H′ | i 〉<br />
E i − E m<br />
, m ≠ i (7.9)<br />
m = i (7.8) 0 = 0 c i <br />
(7.6) <br />
〈 i |ψ 1 〉 = ∑ n<br />
c n 〈 i | n 〉 = ∑ n<br />
c n δ in = c i = 0<br />
<br />
|ψ 1 〉 = ∑ m≠i<br />
| m 〉 〈 m |H′ | i 〉<br />
E i − E m<br />
(7.10)<br />
, 1 <br />
|ψ〉 = | i 〉 + |ψ 1 〉 = | i 〉 + ∑ m≠i<br />
|ψ〉 = | i 〉 + |ψ 1 〉 〈 i |ψ 1 〉 = 〈ψ 1 | i 〉 ∗ = 0 <br />
| m 〉 〈 m |H′ | i 〉<br />
E i − E m<br />
(7.11)<br />
〈ψ|ψ〉 = 〈 i | i 〉 + 〈 i |ψ 1 〉 + 〈ψ 1 | i 〉 + 〈ψ 1 |ψ 1 〉 = 1 + 〈ψ 1 |ψ 1 〉<br />
〈ψ 1 |ψ 1 〉 H ′ 2 , 1 (7.11) 1 <br />
|ψ〉 m ≠ i | m 〉 , 1 <br />
∣ ∣∣∣ 〈 m |H ′ | i 〉<br />
E i − E m<br />
∣ ∣∣∣<br />
≪ 1<br />
<br />
(7.10) H 0 | m 〉 = E m | m 〉 <br />
1<br />
1<br />
| m 〉 = | m 〉<br />
E i − E m E i − H 0<br />
1/(E i − E m ) , | m 〉 <br />
1<br />
| m 〉 = | m 〉<br />
1<br />
= | m 〉<br />
E i − E m E i − E m E i − E m<br />
, 1/(E i − H 0 ) , 1/(E i − H 0 ) | m 〉 <br />
<br />
(7.10) <br />
|ψ 1 〉 = ∑ m≠i<br />
| m 〉<br />
1<br />
, | m 〉<br />
E i − H 0 E i − H 0<br />
1<br />
E i − H 0<br />
| m 〉 〈 m |H ′ | i 〉 =<br />
1 ∑<br />
| m 〉 〈 m |H ′ | i 〉<br />
E i − H 0<br />
1/(E i − E m ) m , 1/(E i − H 0 ) m <br />
m≠i<br />
, Q i<br />
Q i | m 〉 =<br />
{<br />
0 , m = i <br />
| m 〉 , m ≠ i <br />
Q i <br />
1 ∑<br />
|ψ 1 〉 = Q i | m 〉 〈 m |H ′ | i 〉<br />
E i − H 0<br />
m
7 137<br />
Q i | i 〉 = 0 m m = i , m ≠ i <br />
| m 〉 (5.36)<br />
, <br />
∑<br />
| m 〉〈 m | = 1<br />
n<br />
|ψ 1 〉 =<br />
1 H (7.11) <br />
(<br />
|ψ〉 = 1 +<br />
1<br />
E i − H 0<br />
Q i H ′ | i 〉 (7.12)<br />
)<br />
1<br />
(<br />
Q i H ′ | i 〉 = 1 + G i H ′) | i 〉 , G i =<br />
E i − H 0<br />
(7.11) <br />
2 <br />
(7.7) k = 2 <br />
(7.12) <br />
W 2 = 〈 i |H ′ |ψ 1 〉 = ∑ m≠i<br />
〈 i |H ′ | m 〉 〈 m |H ′ | i 〉<br />
E i − E m<br />
= ∑ m≠i<br />
1<br />
E i − H 0<br />
Q i<br />
|〈 m |H ′ | i 〉| 2<br />
E i − E m<br />
(7.13)<br />
W 2 = 〈 i |H ′ 1<br />
E i − H 0<br />
Q i H ′ | i 〉 (7.14)<br />
H ′ 1/(E i − H 0 ) , <br />
<br />
<br />
|ψ 2 〉 = ∑ n<br />
d n | n 〉 , d i = 0<br />
(7.4) <br />
(7.10) <br />
(E m − E i ) d m = W 1 c m − 〈 m |H ′ |ψ 1 〉 + W 2 〈 m | i 〉<br />
〈 m |H ′ |ψ 1 〉 = ∑ n≠i<br />
〈 m |H ′ | n 〉〈 n |H ′ | i 〉<br />
E i − E n<br />
, m ≠ i <br />
<br />
|ψ 2 〉 = ∑ m≠i<br />
d m = −<br />
G i <br />
⎛<br />
1<br />
⎝ 〈 m |H′ | i 〉〈 i |H ′ | i 〉<br />
− ∑ E i − E m E i − E m<br />
n≠i<br />
d m | m 〉 = ∑ m≠i<br />
∑<br />
n≠i<br />
⎞<br />
〈 m |H ′ | n 〉〈 n |H ′ | i 〉<br />
⎠<br />
E i − E n<br />
| m 〉 〈 m |H′ | n 〉〈 n |H ′ | i 〉<br />
(E i − E m )(E i − E n ) − ∑ | m 〉 〈 m |H′ | i 〉〈 i |H ′ | i 〉<br />
(E i − E m ) 2<br />
m≠i<br />
1<br />
|ψ 2 〉 = Q i H ′ 1<br />
Q i H ′ 1<br />
| i 〉 −<br />
E i − H 0 E i − H 0 (E i − H 0 ) 2 Q iH ′ | i 〉〈 i |H ′ | i 〉<br />
(<br />
)<br />
= G i H ′ G i H ′ − G 2 i H ′ 〈 i |H ′ | i 〉 | i 〉
7 138<br />
<br />
|ψ〉 <br />
|ψ〉 = | i 〉 + |ψ 1 〉 + |ψ 2 〉<br />
〈 i |ψ 1 〉 = 〈 i |ψ 2 〉 = 0 <br />
〈ψ|ψ〉 = 〈 i | i 〉 + 〈ψ 1 |ψ 1 〉 + 〈ψ 1 |ψ 2 〉 + 〈ψ 2 |ψ 1 〉 + 〈ψ 2 |ψ 2 〉<br />
H ′ 2 , H ′ 2 <br />
|ψ 1 〉, |ψ 2 〉 H ′ 1 , 2 , 3, 4 H ′ 3 , 5 4<br />
<br />
<br />
〈ψ|ψ〉 = 1 + ∑ n≠i<br />
⎛<br />
N |ψ〉 , N = ⎝1 + ∑ n≠i<br />
|c n | 2 = 1 + ∑ n≠i<br />
|〈 n |H ′ | i 〉| 2<br />
(E i − E n ) 2<br />
⎞−1/2<br />
|〈 n |H ′ | i 〉| 2<br />
⎠<br />
(E i − E n ) 2 ≈ 1 − 1 ∑ |〈 n |H ′ | i 〉| 2<br />
2 (E i − E n ) 2<br />
n≠i<br />
, N H ′ 2 , <br />
⎛<br />
⎞<br />
⎝1 − 1 ∑ |〈 n |H ′ | i 〉| 2<br />
⎠<br />
2 (E i − E n ) 2 | i 〉 + |ψ 1 〉 + |ψ 2 〉<br />
<br />
<br />
n≠i<br />
1 <br />
d 2<br />
H 0 = − 2<br />
2m dx 2 + 1 2 kx2<br />
n = 0, 1, 2, · · · <br />
H 0 | n 〉 = E n | n 〉 ,<br />
(<br />
E n = ω n + 1 ) √<br />
k<br />
, ω =<br />
2<br />
m<br />
<br />
<br />
a † = √ 1 (<br />
q − d )<br />
, a = 1 (<br />
√ q + d ) √ mω<br />
, q =<br />
2 dq<br />
2 dq<br />
<br />
x<br />
a † | n 〉 = √ n + 1 | n + 1 〉 , a | n 〉 = √ n | n − 1 〉 (7.15)<br />
<br />
<br />
H ′ = b 2 x2 =<br />
b (<br />
a † + a ) 2 b (<br />
= (a † ) 2 + a 2 + 2a † a + 1 )<br />
4mω<br />
4mω<br />
<br />
H ′ | n 〉 =<br />
b (√ √ )<br />
(n + 1)(n + 2) | n + 2 〉 + n(n − 1) | n − 2 〉 + (2n + 1) | n 〉<br />
4mω
7 139<br />
<br />
<br />
W 1 = 〈 n |H ′ | n 〉 =<br />
b (<br />
n + 1 )<br />
2mω 2<br />
W 2 = ∑ n ′ ≠n<br />
|〈 n ′ |H ′ | n 〉| 2<br />
E n − E n ′<br />
= |〈 n + 2 |H′ | n 〉| 2<br />
E n − E n+2<br />
+ |〈 n − 2 |H′ | n 〉| 2<br />
E n − E n−2<br />
( ) 2 ( b (n + 1)(n + 2)<br />
=<br />
− +<br />
4mω<br />
2ω<br />
= − 1 ( ) 2 ( b<br />
8 mω 2 ω n + 1 )<br />
2<br />
)<br />
n(n − 1)<br />
2ω<br />
2 <br />
(<br />
W = ω n + 1 )<br />
(<br />
+ W 1 + W 2 = ω n + 1 ) ( 1 + b<br />
2<br />
2 2mω 2 − 1 ( ) ) 2 b<br />
8 mω 2<br />
(<br />
= ω n + 1 ) ( 1 + b<br />
2 2k − 1 ( ) ) 2 b<br />
8 k<br />
(7.16)<br />
2 1 <br />
(7.15) <br />
|ψ 1 〉 = ∑ n ′ ≠n<br />
| n ′ 〉 〈 n′ |H ′ | n 〉<br />
E n − E n ′<br />
= | n + 2 〉 〈 n + 2 |H′ | n 〉<br />
E n − E n+2<br />
+ | n − 2 〉 〈 n − 2 |H′ | n 〉<br />
E n − E n−2<br />
= b (<br />
8mω 2 − √ (n + 1)(n + 2) | n + 2 〉 + √ )<br />
n(n − 1) | n − 2 〉<br />
√<br />
(n + 1)(n + 2) | n + 2 〉 = (a † ) 2 | n 〉 ,<br />
√<br />
n(n − 1) | n − 2 〉 = a 2 | n 〉<br />
<br />
|ψ 1 〉 = b (<br />
8mω 2 − (a † ) 2 + a 2) | n 〉 = b (2q d )<br />
8k dq + 1 | n 〉 (7.17)<br />
<br />
H = H 0 + H ′<br />
d 2<br />
H = − 2<br />
2m dx 2 + k + b<br />
2<br />
H 0 k k + b , E n ′ <br />
(<br />
E n ′ = ω ′ n + 1 )<br />
√<br />
k + b<br />
, ω ′ =<br />
√1<br />
2<br />
m = ω + b k<br />
ω ′ b <br />
x 2<br />
(<br />
ω ′ = ω 1 + b<br />
)<br />
2k − b2<br />
8k 2 +<br />
b3<br />
16k 3 + · · ·<br />
, (7.16) E ′ n b 2 <br />
H 0 u n <br />
( mω<br />
) 1/4<br />
u n (q) = fn (q) , f n (q) = √ 1 /2 H<br />
π<br />
n!2<br />
n e−q2 n (q)
7 140<br />
H <br />
( ) mω<br />
′ 1/4<br />
√<br />
mω<br />
ϕ n (q) =<br />
f n (q ′ ) , q ′ ′<br />
=<br />
π<br />
<br />
x<br />
<br />
<br />
(<br />
q ′ = q 1 + b )<br />
4k + · · · ,<br />
( mω<br />
ϕ n (q) =<br />
π<br />
=<br />
( ) mω<br />
′ 1/4<br />
=<br />
π<br />
( mω<br />
) ( 1/4<br />
1 + b )<br />
π 8k + · · ·<br />
) 1/4<br />
(<br />
1 + b<br />
8k + · · · ) (<br />
f n (q) + b<br />
4k q df n<br />
dq + · · · )<br />
(<br />
1 + b<br />
8k + b<br />
4k q d dq + · · · )<br />
u n<br />
(7.17) b 1 <br />
7.1<br />
H ′ = bx 2 <br />
W 1 = 0 ,<br />
W 2 = − b2<br />
2k<br />
<br />
<br />
)<br />
d<br />
( )<br />
|ψ 1 〉 = q 0<br />
dq u n(q) , |ψ 2 〉 = q2 0<br />
(q 2 + d2<br />
4 dq 2 u n (q) , N = 1 − q2 0<br />
2n + 1<br />
4<br />
q 0 =<br />
b<br />
√<br />
<br />
ω mω = b √ mω<br />
k <br />
<br />
7.2<br />
H ′ = v 0 x 4 <br />
W 1 = ω 3u 0<br />
8<br />
(<br />
2n 2 + 2n + 1 ) , W 2 = − ω u2 0<br />
32 (2n + 1) ( 17n 2 + 17n + 21 )<br />
<br />
u 0 = 2v ( ) 2<br />
0 <br />
ω mω<br />
q = √ mω/ x <br />
<br />
<br />
d 2 ψ<br />
( )<br />
dq 2 + ε − U(q) ψ = 0<br />
ε = 2E<br />
ω , U(q) = q2 + u 0 q 4<br />
1.2<br />
ε<br />
1.1<br />
1.0<br />
0.9<br />
37 <br />
0.0 0.2 u 0<br />
<br />
n = 0 , 1 , 2 <br />
u 0 < 0
7 141<br />
7.3 <br />
|ψ 0 〉 = | i 〉 , H 0 g <br />
| i, α 〉 , ( α = 1, 2 · · · , g ) <br />
H 0 | i, α 〉 = E i | i, α 〉 , 〈 i, α | i, α ′ 〉 = δ αα ′<br />
<br />
| i, α 〉 <br />
g∑<br />
a α | i, α 〉<br />
α=1<br />
H 0 E i (7.2) , <br />
(7.2) <br />
g∑<br />
|ψ 0 〉 = a α | i, α 〉 ,<br />
α=1<br />
W 0 = E i<br />
, (7.3) <br />
g∑<br />
(H 0 − E i ) |ψ 1 〉 = W 1 a α ′| i, α ′ 〉 −<br />
α ′ =1<br />
g∑<br />
a α ′H ′ | i, α ′ 〉<br />
| i, α 〉 H 0 | i, α 〉 = E i | i, α 〉 0 <br />
g∑<br />
α ′ =1<br />
α ′ =1<br />
(<br />
)<br />
W 1 δ αα ′ − h αα ′ a α ′ = 0 , h αα ′ ≡ 〈 i, α |H ′ | i, α ′ 〉 (7.18)<br />
(7.18) a α = 0 , <br />
(<br />
)<br />
det W 1 δ αα ′ − h αα ′ = 0 (7.19)<br />
g W 1 , W 1 (7.18) a α (7.19) <br />
<br />
|ψ 0 〉 <br />
|ψ 1 〉 = ∑ n<br />
c n | n 〉<br />
(7.3) <br />
| m 〉 <br />
∑<br />
c n (E n − E i ) | n 〉 = (W 1 − H ′ ) |ψ 0 〉<br />
n<br />
(E m − E i ) c m = W 1 〈 m |ψ 0 〉 − 〈 m |H ′ |ψ 0 〉<br />
E m ≠ E i 〈 m |ψ 0 〉 = 0 <br />
c i, α = 0 (7.6) 〈ψ 0 |ψ 1 〉 = 0 <br />
|ψ 1 〉 = ∑<br />
m≠{i,α}<br />
| m 〉 〈 m |H′ |ψ 0 〉<br />
=<br />
E i − E m<br />
c m = 〈 m |H′ |ψ 0 〉<br />
E i − E m<br />
(7.20)<br />
1<br />
E i − H 0<br />
Q i H ′ |ψ 0 〉 , Q i | n 〉 =<br />
⎧<br />
⎨<br />
⎩<br />
| n 〉 , E n ≠ E i<br />
(7.21)<br />
0 , E n = E i
7 142<br />
〈 m |H ′ |ψ 0 〉 = 〈 m |H ′ | i 〉 , <br />
〈 m |H ′ |ψ 0 〉 = ∑ α<br />
a α 〈 m |H ′ | i, α 〉<br />
<br />
2 W 2 〈ψ 0 |ψ 0 〉 = 1 <br />
<br />
<br />
W 2 = 〈ψ 0 |H ′ |ψ 1 〉 = 〈ψ 0 |H ′ 1<br />
E i − H 0<br />
Q i H ′ |ψ 0 〉 =<br />
∑<br />
m≠{i,α}<br />
|〈 m |H ′ |ψ 0 〉| 2<br />
E i − E m<br />
7.3 2 ( g = 2 )<br />
√<br />
W 1 = h (<br />
11 + h 22 ± ∆h<br />
1<br />
, a 1 = 1 ± h )<br />
√<br />
11 − h 22<br />
, a 2 = ∓ |h 12| 1<br />
2<br />
2 ∆h<br />
h 12 2<br />
(<br />
1 ∓ h )<br />
11 − h 22<br />
∆h<br />
<br />
∆h =<br />
√<br />
(h 11 − h 22 ) 2 + 4|h 12 | 2<br />
<br />
, H 0 H ′ <br />
F , H 0 F , | i, α 〉 F <br />
F f iα <br />
F | i, α 〉 = f iα | i, α 〉 ,<br />
α = 1, 2 · · · , g<br />
H ′ F − F H ′ = 0 <br />
0 = 〈 i, α | (H ′ F − F H ′ ) | i, α ′ 〉 = (f iα ′ − f iα ) 〈 i, α |H ′ | i, α ′ 〉<br />
f iα ≠ f iα ′<br />
<br />
h αα ′ = 〈 i, α |H ′ | i, α ′ 〉 = 0<br />
g f iα h αα ′ = δ αα ′h αα , (7.18) <br />
)<br />
(W 1 − h αα a α = 0 , ∴ W 1 = 〈 i, α |H ′ | i, α 〉 , |ψ 0 〉 = | i, α 〉 (7.22)<br />
, H 0 F | i, α 〉 <br />
<br />
f iα , (7.18) , <br />
f 1 f 2 2 , g 1 g 2 = g − g 1 <br />
1 ≤ α ≤ g 1 F | i, α 〉 = f 1 | i, α 〉 , g 1 + 1 ≤ α ≤ g F | i, α 〉 = f 2 | i, α 〉<br />
α ≤ g 1 , α ′ > g 1 h αα ′ = 0 (7.18) <br />
∑g 1<br />
α ′ =1<br />
(<br />
W 1 δ αα ′ − h αα ′<br />
)<br />
a α ′ = 0
7 143<br />
α ≥ g 1 + 1 <br />
g∑<br />
α ′ =g 1 +1<br />
(<br />
)<br />
W 1 δ αα ′ − h αα ′ a α ′ = 0<br />
, g 1 ×g 1 g 2 ×g 2 H 0 F <br />
g 1<br />
∑<br />
α=1<br />
a α | i, α 〉 ,<br />
<br />
g∑<br />
α=g 1+1<br />
a α | i, α 〉 (7.23)<br />
H = H 0 + H ′ F , <br />
(7.23) |ψ 0 〉 , F | i, α 〉 <br />
, , f iα | i, α 〉 1 , <br />
<br />
<br />
z E , <br />
H 0 = − 2<br />
2m ∇2 − Zαc , α = <br />
r<br />
<br />
H ′ = eEz = eEr cos θ<br />
H 0 <br />
, <br />
E n = − (Zα)2 mc 2<br />
2n 2 , n = 1, 2, 3, · · ·<br />
u nlml (r) = χ nl(r)<br />
Y l ml (θ, φ) (7.24)<br />
r<br />
χ nl (r) (6.21) E n n 2 , <br />
( n = 2 ) n = 2 (n, l, m l ) =<br />
(2, 0, 0), (2, 1, 1), (2, 1, 0), (2, 1, −1) 4 <br />
H 0 L , H 0 , L 2 , L z , <br />
u nlml <br />
[ z , L x ] = [ z , yp z − zp y ] = iy , [ z , L y ] = − ix , [ z , L z ] = 0<br />
, H ′ L x , L y L z , L z m l <br />
n = 2 4 m l <br />
m l = 0 : (2, 0, 0) (2, 1, 0) , m l = 1 : (2, 1, 1) , m l = −1 : (2, 1, −1)<br />
<br />
m l = 0 <br />
|ψ 0 〉 = a 1 | 2, 0, 0 〉 + a 2 | 2, 1, 0 〉<br />
(7.18) <br />
⎛<br />
⎝ W 1 − 〈 2, 0, 0 |H ′ | 2, 0, 0 〉 − 〈 2, 0, 0 |H ′ | 2, 1, 0 〉<br />
− 〈 2, 0, 0 |H ′ | 2, 1, 0 〉 W 1 − 〈 2, 1, 0 |H ′ | 2, 1, 0 〉<br />
⎞ ⎛<br />
⎠ ⎝ a 1<br />
⎠ = 0<br />
a 2<br />
⎞
7 144<br />
<br />
〈 n, l, m l |H ′ | n ′ , l ′ , m l 〉 = eE<br />
∫ ∞<br />
0<br />
∫<br />
dr r χ 2l (r) χ 2l ′(r) d cos θ dφ cos θ (Y lml ) ∗ Y l′ m l<br />
Y l ml (θ, φ) (5.30) Y l ml (θ, φ) = f lml (cos θ) e im lφ , ( f lml<br />
<br />
〈 n, l, m l |H ′ | n ′ , l ′ , m l 〉 = 2πeE<br />
∫ ∞<br />
0<br />
dr r χ 2l (r) χ 2l ′(r)<br />
∫ 1<br />
−1<br />
) <br />
dt t f lml (t) f l ′ m l<br />
(t)<br />
f lml (t) t , l = l ′ t f lml (t) f l′ m l<br />
(t) = t f lml (t) 2 t <br />
<br />
<br />
<br />
(6.26), (6.27) <br />
〈 2, 0, 0 |H ′ | 2, 1, 0 〉 = eE<br />
24<br />
(<br />
〈 n, l, m l |H ′ | n ′ , l, m l 〉 = 0 (7.25)<br />
f 00 (t) = √ 1<br />
√<br />
3<br />
, f 10 (t) =<br />
4π 4π t<br />
〈 2, 0, 0 |H ′ | 2, 1, 0 〉 = √ eE ∫ ∞<br />
dr r χ 20 (r) χ 21 (r)<br />
3<br />
( ) 4 ∫ Z ∞<br />
dr r<br />
(2 4 − Z )<br />
r<br />
a B a B<br />
) (<br />
W 1 3eEa B /Z<br />
W 1 <br />
<br />
W 1 = ± 3eEa B<br />
Z<br />
0<br />
, |ψ 0 〉 =<br />
0<br />
e −Zr/aB<br />
= − 3eEa B<br />
Z<br />
)<br />
a 1<br />
= 0 (7.26)<br />
a 2<br />
| 2, 0, 0 〉 ∓ | 2, 1, 0 〉<br />
√<br />
2<br />
m l = ± 1 1 , ,<br />
(7.25) <br />
W 1 = 〈 2, 1, ±1 |H ′ | 2, 1, ±1 〉 = 0<br />
m l = 1 m l = −1 <br />
7.4<br />
n = 2 4 , (7.18) 4×4 <br />
<br />
<br />
10 −14 m , 10 −10 m ,<br />
, Ze , <br />
Ze R <br />
, V (r) <br />
⎧<br />
⎪⎨ − Zαc ) (3 − r2<br />
2R R<br />
V (r) =<br />
2 , r < R<br />
⎪⎩ − Zαc<br />
, α = e2<br />
4πε 0 c = ≈ 1<br />
137<br />
, r > R<br />
r<br />
(7.27)
7 145<br />
<br />
⎧<br />
H = H 0 + H ′ (r) , H 0 = − 2<br />
2m ∇2 − Zαc<br />
⎪⎨<br />
, H ′ (r) =<br />
r<br />
⎪⎩<br />
− Zαc<br />
2R<br />
(3 − r2<br />
R 2 − 2R r<br />
)<br />
, r < R<br />
0 , r > R<br />
H ′ H 0 | n, l, m l 〉 n 2 , <br />
(7.19) (7.24) <br />
∫ R<br />
∫<br />
〈 n, l, m l |H ′ | n, l ′ , m ′ l 〉 = dr H ′ (r)χ nl (r)χ nl ′(r)<br />
0<br />
= δ ll ′ δ ml m ′ l<br />
∫ R<br />
0<br />
dr H ′ (r)χ 2 nl(r)<br />
dΩ Ylm ∗<br />
l<br />
(θ, φ)Y l′ m ′ (θ, φ)<br />
l<br />
, (7.19) h αα ′ , 1 <br />
W 1 = 〈 n, l, m l |H ′ | n, l, m l 〉 =<br />
∫ R<br />
0<br />
dr H ′ (r) χ 2 nl(r)<br />
, H ′ [ H ′ , L ] = 0 ,<br />
H 0 L 2 L z L 2 L z <br />
, <br />
W 1 l l (6.23) <br />
W 1 = |E n | C ∫ ρmax<br />
(<br />
nl<br />
ρ<br />
2<br />
dρ + 2ρ )<br />
max<br />
− 3 ρ 2l+2 F nl (ρ) (7.28)<br />
ρ max ρ<br />
<br />
0<br />
ρ 2 max<br />
E n = − (Zα)2 mc 2<br />
2n 2 , ρ max = 2R<br />
na z<br />
= 2ZR<br />
na B<br />
, a B = <br />
mcα<br />
C nl =<br />
(n + l)!<br />
[(2l + 1)!] 2 (n − l − 1)! , F nl(ρ) = e −ρ( M(l + 1 − n, 2l + 2, ρ)<br />
0 ≤ ρ ≤ ρ max ≪ 1 F nl (ρ) ≈ 1 <br />
l = 0 <br />
3C nl<br />
W 1 ≈ |E n |<br />
(l + 1)(2l + 3)(2l + 5) ρ2l+2 max<br />
W 1 ≈ 4 ( ) 2 ZR<br />
|E n | (7.29)<br />
5n a B<br />
a B a B = 0.53 × 10 −10 m R ∼ 10 −14 m <br />
R/a B ∼ 10 −4 W 1 /|E n | , <br />
<br />
207 <br />
µ <br />
a B = 0.53 × 10 −10 /207 = 2.6 × 10 −13 m<br />
, Z , a B /Z R R ≈<br />
7 × 10 −15 m , Z = 82 R/(a B /Z) = 0.45 , µ <br />
, <br />
) 2
7 146<br />
7.5<br />
(7.27) , 131 <br />
λ λ = a z = a B /Z <br />
⎧<br />
ε = 2mλ2 E 2E<br />
2 =<br />
mc 2 (Zα) 2 , 2mλ<br />
⎪⎨<br />
2<br />
2 V (r) =<br />
⎪⎩ − 2 q ,<br />
− 1 ( )<br />
3 − q2<br />
R z Rz<br />
2 , q < R z<br />
q > R z<br />
R z = ZR/a B q max 123 <br />
n = 1, 2, 3 ε R z R z = 0 <br />
E = − (Zα)2 mc 2<br />
2n 2 , ∴ ε = − 1 n 2<br />
(n, l ) = (1, 0 ) R z 123 , <br />
q = r/a z = 1 , r <br />
1 (7.28) R z , 1 <br />
, l > 0 R z 1 <br />
l = 0 1 (7.29) <br />
µ , <br />
, Z , , <br />
<br />
0.0<br />
ε<br />
−0.2<br />
−0.1<br />
ε<br />
(3, 0)<br />
(2, 1)<br />
(1, 2)<br />
R z<br />
−0.4<br />
(1, 0)<br />
0 1 2 3<br />
0 1<br />
R z<br />
2 3<br />
(2, 0)<br />
−0.6<br />
−0.2<br />
−0.8<br />
(1, 1)<br />
−1.0<br />
2 <br />
1 <br />
g∑<br />
|ψ 0 〉 = a α | i, α 〉<br />
, (7.21) (7.4) | i, α 〉 <br />
0 = W 1 〈 i, α |ψ 1 〉 − 〈 i, α |H ′ |ψ 1 〉 + W 2 〈 i, α |ψ 0 〉<br />
α=1
7 147<br />
〈 i, α |ψ 1 〉 = 0 , 〈 i, α |ψ 0 〉 = a α , (7.21) <br />
W 2 a α − 〈 i, α |H ′ |ψ 1 〉 = W 2 a α − 〈 i, α |H ′ 1<br />
E i − H 0<br />
Q i H ′ |ψ 0 〉 = 0<br />
|ψ 0 〉 <br />
<br />
W 2 a α −<br />
g∑<br />
α ′ =1<br />
h (2)<br />
αα ′ = 〈 i, α |H′ 1<br />
E i − H 0<br />
Q i H ′ | i, α ′ 〉 =<br />
h (2)<br />
αα ′a α ′ = 0 (7.30)<br />
∑<br />
m≠{i,α}<br />
〈 i, α |H ′ | m 〉〈 m |H ′ | i, α ′ 〉<br />
E i − E m<br />
(7.30) (7.18) , (7.18) <br />
, (7.30) W 2 = h (2)<br />
αα , (7.13) (7.14)
8 WKB () 148<br />
8 WKB ()<br />
8.1 WKB <br />
ψ(r, t) = C exp (iW (r, t)/) <br />
i ∂ψ<br />
∂t = − ∂W ∂t ψ , ∇2 ψ = − 1 (<br />
)<br />
2 (∇W ) 2 − i∇ 2 W ψ<br />
<br />
− ∂W ∂t<br />
= 1 (<br />
)<br />
(∇W ) 2 − i∇ 2 W + V (r)<br />
2m<br />
→ 0 , <br />
− ∂W ∂t<br />
= 1<br />
2m (∇W )2 + V (r)<br />
ψ(r, t) = e −iEt/ ψ(r) <br />
W (r, t) = S(r) − Et , ψ(r) = C exp (iS(r)/)<br />
<br />
<br />
1 <br />
1<br />
(<br />
)<br />
(∇S) 2 − i∇ 2 S + V (r) − E = 0<br />
2m<br />
( )<br />
(S ′ ) 2 + 2m V (x) − E − iS ′′ = 0 , S ′ = dS<br />
dx ,<br />
S′′ = d2 S<br />
dx 2 (8.1)<br />
S <br />
S = S 0 + S 1 + 2 S 2 + · · ·<br />
S 0 S 1 WKB( Wentzel–Kramers–Brillouin ) <br />
1 <br />
(S ′ ) 2 = ( S ′ 0 + S ′ 1 + 2 S ′ 2 + · · · )2<br />
= (S<br />
′<br />
0 ) 2 + 2S ′ 0S ′ 1 + 2 ( 2S ′ 0S ′ 2 + (S ′ 1) 2) + · · ·<br />
<br />
<br />
( )<br />
(S 0) ′ 2 + 2m V (x) − E = 0 , 2S 0S ′ 1 ′ − iS 0 ′′ = 0 , 2S 0S ′ 2 ′ + (S 1) ′ 2 − iS 1 ′′ = 0 , · · ·<br />
k(x) =<br />
√<br />
2m ∣ ∣V (x) − E ∣ ∣<br />
, E > V (x) <br />
dS 0<br />
dx = ± k(x) , ∴ ∫<br />
S 0(x) = ± <br />
2<br />
dx k(x)<br />
<br />
S ′ 1 = i 2<br />
S ′′<br />
0<br />
S ′ 0<br />
= i k ′ (x)<br />
2 k(x) , ∴ S 1(x) = i log k(x) + <br />
2
8 WKB () 149<br />
<br />
( ∫<br />
exp (iS/) ≈ exp (iS 0 / + iS 1 ) = exp ± i dx k(x) − 1 )<br />
2 log k(x)<br />
=<br />
( ∫ )<br />
1<br />
√ exp ± i dx k(x)<br />
k(x)<br />
, E > V (x) C ± <br />
ψ(x) = ψ 1 (x) = C ( ∫ )<br />
+<br />
√ exp i dx k(x)<br />
k(x)<br />
+ C −<br />
√ exp<br />
k(x)<br />
( ∫ )<br />
− i dx k(x)<br />
(8.2)<br />
, E < V (x) , <br />
ψ(x) = ψ 2 (x) = D (∫ )<br />
+<br />
√ exp dx k(x) + D ( ∫ )<br />
−<br />
√ exp − dx k(x)<br />
k(x) k(x)<br />
(8.3)<br />
<br />
WKB , (8.1) 3 iS ′′ 1 (S ′ ) 2 <br />
<br />
∣ S ′′ ∣∣∣ ∣(S ′ ) 2 =<br />
∣ d ∣ 1 ∣∣∣ dx S ′ ≈<br />
∣ d<br />
∣ ∣<br />
1<br />
∣∣∣ dx ∣ = d 1<br />
∣∣∣ dx k(x) ∣ = 1<br />
2π<br />
S ′ 0<br />
dλ(x)<br />
dx<br />
∣ ≪ 1<br />
λ(x) = 2π/k(x) WKB <br />
<br />
d 1<br />
∣dx<br />
k(x) ∣ = 1 √<br />
<br />
2<br />
|V ′ (x)|<br />
≪ 1 (8.4)<br />
2 2m |V (x) − E|<br />
3/2<br />
V (x) , V (x) − E = 0, , <br />
WKB k(x) ≈ 0 (8.2), (8.3) <br />
E = V (a) V (x) , x = a <br />
V (x) ≈ V (a) + V ′ (a)(x − a) = E + V ′ (a)(x − a) (8.5)<br />
(8.4) <br />
|v 1/3 (x − a)| ≫ 1<br />
2m<br />
∼ 1 , v =<br />
22/3 2 V ′ (a) (8.6)<br />
x WKB <br />
√<br />
E > V (x) p(x) = k(x) = 2m ( E − V (x) ) <br />
(8.2) 2 <br />
ψ 1 = ψ + + ψ − , ψ ± (x) = C ( ∫ )<br />
±<br />
√ exp ± i dx k(x)<br />
k(x)<br />
<br />
|ψ ± (x)| 2 = |C ±| 2<br />
k(x) = |C ±| 2<br />
p(x)<br />
p(x) [x, x + dx] P cl dx , <br />
dt p = m dx/dt <br />
P cl dx ∝ dt = m p dx , ∴ P cl ∝ 1 p
8 WKB () 150<br />
, WKB ψ ± (x) <br />
J ± (x) = (<br />
m Im ψ±(x) ∗ dψ )<br />
±(x)<br />
dx<br />
<br />
<br />
dψ ± (x)<br />
dx<br />
=<br />
(<br />
) ( ∫ )<br />
− k′ (x)<br />
2k(x) ± ik(x) C±<br />
√ exp ± i dx k(x)<br />
k(x)<br />
J ± (x) = ± m |C ±| 2 = (8.7)<br />
<br />
= × = ± p(x)<br />
m × |C ±| 2<br />
p(x)<br />
, ψ 1 = ψ + + ψ − 2 <br />
Re(ψ + ψ−) ∗ ∝ 1 ( ∫ )<br />
p(x) cos 2 dx k(x)<br />
, <br />
8.2 <br />
E = V (x) x = a <br />
η(x) =<br />
∫ x<br />
a<br />
dx ′ k(x ′ ) , κ(x) =<br />
1<br />
√<br />
k(x)<br />
, (8.2), (8.3) <br />
(<br />
ψ 1 (x) = κ(x) C + e iη(x) + C − e −iη(x)) ,<br />
(<br />
ψ 2 (x) = κ(x) D + e η(x) + D − e −η(x)) (8.8)<br />
WKB , ψ 1 (x) ψ 2 (x)<br />
ψ 1 (x) ψ 2 (x) x a ,<br />
x = a x = a , ψ 1 (x) ψ 2 (x) <br />
, x = a <br />
, ψ 1 (x) ψ 2 (x) <br />
WKB , V (x) <br />
, x = a (8.5) , <br />
(− 2 d 2 )<br />
( )<br />
d<br />
2<br />
2m dx 2 + V (x) ψ(x) = E ψ(x) , <br />
dx 2 − v(x − a) ψ(x) = 0<br />
z = v 1/3 (x − a) <br />
d 2 ψ<br />
dz 2 − zψ = 0<br />
(15.100) , ψ = F Ai(z) + GBi(z) <br />
F G (15.102), (15.103) z → ∞ <br />
[<br />
1<br />
ψ(x) →<br />
2 √ F exp<br />
(− 2 ) ( )] 2<br />
π z 1/4 3 z3/2 + 2G exp<br />
3 z3/2<br />
(8.9)
8 WKB () 151<br />
z → − ∞ <br />
ψ(x) →<br />
=<br />
1<br />
√ π |z|<br />
1/4<br />
[ ( 2<br />
F sin<br />
3 |z|3/2 + π ) ( 2<br />
+ G cos<br />
4 3 |z|3/2 + π )]<br />
4<br />
[<br />
(<br />
1<br />
2i<br />
2 √ (G − iF ) exp<br />
π |z| 1/4 3 |z|3/2 + iπ )<br />
(<br />
+ (G + iF ) exp − 2i<br />
4<br />
3 |z|3/2 − iπ )]<br />
4<br />
(8.10)<br />
277 z → ± ∞ |z| 2<br />
, <br />
WKB , <br />
, WKB <br />
(8.6) z |z| ≫ 1/2 2/3 <br />
x < a <br />
2<br />
3 |z|3/2 = 2 ∫ x<br />
3 |v|1/2 (a − x) 3/2 = − |v| 1/2 dx ′ (a − x ′ ) 1/2<br />
(8.5) <br />
<br />
x > a <br />
<br />
v > 0 <br />
v(x − a) ≈ 2m ( )<br />
2 V (x) − E<br />
2<br />
3 |z|3/2 ≈ −<br />
a<br />
∫ x<br />
a<br />
⎧<br />
2<br />
⎨<br />
3 |z|3/2 ≈<br />
⎩<br />
E<br />
dx ′ √<br />
2m<br />
2 ∣ ∣∣V (x) − E<br />
∣ ∣∣ = − η(x)<br />
− η(x) ,<br />
η(x) ,<br />
x < a<br />
x > a<br />
V (x)<br />
a<br />
WKB ψ 1 WKB ψ 2<br />
<br />
(8.11)<br />
x − a z , x > a (8.9), x < a (8.10) <br />
(8.11) <br />
⎧<br />
v 1/6 (<br />
⎪⎨ 2 √ F e −η(x) + 2Ge η(x)) ,<br />
x > a<br />
πk(x)<br />
ψ(x) =<br />
v 1/6 [<br />
⎪⎩<br />
2 √ (G − iF ) e −iη(x)+iπ/4 + (G + iF ) e iη(x)−iπ/4] , x < a<br />
πk(x)<br />
(8.8) <br />
D + = v1/6<br />
√ G , D − = v1/6<br />
π 2 √ π F , C + = v1/6<br />
2 √ π (G + iF ) e−iπ/4 , C − = v1/6<br />
2 √ (G − iF ) eiπ/4<br />
π<br />
<br />
C + =<br />
( )<br />
( )<br />
1 1<br />
2 D + + iD − e −iπ/4 , C − =<br />
2 D + − iD − e iπ/4 (8.12)<br />
(8.8) <br />
⎧ (<br />
⎪⎨ κ(x) D + e η(x) + D − e −η(x)) ,<br />
ψ(x) = [ (<br />
⎪⎩ κ(x) D + sin η(x) + π 4<br />
)<br />
+ 2D − cos<br />
x > a<br />
(<br />
η(x) + π ) ]<br />
, x < a<br />
4
8 WKB () 152<br />
<br />
D + D + ≠ 0 , x > a e η(x) WKB<br />
η(x) ≫ 1 e η(x) ≫ e −η(x) e −η(x) ,<br />
D + ≠ 0 <br />
⎧<br />
⎪⎨ D + κ(x)e η(x) ,<br />
ψ(x) = [<br />
⎪⎩ κ(x) D + sin<br />
(<br />
η(x) + π 4<br />
x > a<br />
) (<br />
+ 2D − cos η(x) + π ) ]<br />
, x < a<br />
4<br />
<br />
x > a D + = 0 <br />
⎧<br />
⎨ D − κ(x) e −η(x) ,<br />
x > a<br />
ψ(x) =<br />
(<br />
⎩ 2D − κ(x) cos η(x) + π )<br />
, x < a<br />
4<br />
(8.13)<br />
<br />
8.1<br />
x < a ψ(x) = Cκ(x)cos<br />
(η(x) + π )<br />
4 − θ<br />
, sin θ ≠ 0 x > a <br />
ψ(x) = Cκ(x) e η(x) sin θ <br />
v < 0 <br />
x − a z , x > a <br />
(8.10), x < a (8.9) <br />
⎧<br />
|v| 1/6 [<br />
2 √ (G − iF ) e iη(x)+iπ/4<br />
πk(x)<br />
⎪⎨<br />
ψ(x) =<br />
+ (G + iF ) e −iη(x)−iπ/4] , x > a<br />
⎪⎩<br />
(8.8) <br />
|v| 1/6<br />
2 √ πk(x)<br />
C + =<br />
(<br />
F e η(x) + 2Ge −η(x)) ,<br />
x < a<br />
E<br />
a<br />
V (x)<br />
( )<br />
( )<br />
1 1<br />
2 D − − iD + e iπ/4 , C − =<br />
2 D − + iD + e −iπ/4 (8.14)<br />
, (8.8) <br />
⎧ (<br />
⎪⎨ κ(x) D + e η(x) + D − e −η(x)) ,<br />
ψ(x) = [ (<br />
⎪⎩ κ(x) 2D + cos η(x) − π 4<br />
D ± C ± <br />
⎧<br />
⎪⎨ e −iπ/4 κ(x)<br />
ψ(x) =<br />
⎪⎩<br />
<br />
)<br />
− D − sin<br />
x < a<br />
(<br />
η(x) − π ) ]<br />
, x > a<br />
4<br />
[<br />
(C + + iC − ) e −η(x) + iC ]<br />
+ + C −<br />
e η(x) , x < a<br />
2<br />
(<br />
κ(x) C + e iη(x) + C − e −iη(x)) ,<br />
x > a<br />
η(x) x < a η(x) < 0 , x e −η(x) <br />
, D − = 0 x <br />
<br />
⎧<br />
⎨ D + κ(x) e η(x) ,<br />
ψ(x) =<br />
⎩ 2D + κ(x) cos<br />
(<br />
η(x) − π 4<br />
x < a<br />
)<br />
, x > a<br />
(8.15)
8 WKB () 153<br />
D − ≠ 0 , <br />
x > a x C − = 0 <br />
⎧<br />
⎪⎨ e −iπ/4 C + κ(x)<br />
(e −η(x) + i )<br />
ψ(x) =<br />
2 eη(x) , x < a<br />
⎪⎩<br />
C + κ(x) e iη(x) ,<br />
x > a<br />
(8.16)<br />
WKB e −η(x) ≫ e η(x) e η(x) <br />
8.3 <br />
1 WKB <br />
x = a x = b V (x) = E <br />
x = a v < 0 , x = b v > 0 <br />
x → − ∞ ψ(x) → 0 <br />
WKB (8.15) <br />
⎧<br />
⎨ D + κ(x) e ηa(x) ,<br />
x < a<br />
ψ(x) =<br />
(<br />
⎩ 2D + κ(x) cos η a (x) − π )<br />
, x > a<br />
4<br />
E<br />
a<br />
η a (x) =<br />
, x → ∞ ψ(x) → 0 (8.13) <br />
⎧<br />
(<br />
⎨ 2D − κ(x) cos η b (x) + π )<br />
, x < b<br />
ψ(x) =<br />
4<br />
η<br />
⎩<br />
b (x) =<br />
D − κ(x) e −ηb(x) ,<br />
x > b<br />
∫ x<br />
a<br />
∫ x<br />
b<br />
b<br />
V (x)<br />
dx ′ k(x ′ ) (8.17)<br />
dx ′ k(x ′ ) (8.18)<br />
a < x < b 2 , <br />
η a (x) =<br />
∫ x<br />
a<br />
dx ′ k(x ′ ) =<br />
∫ b<br />
a<br />
dx ′ k(x ′ ) +<br />
∫ x<br />
b<br />
dx ′ k(x ′ ) =<br />
∫ b<br />
a<br />
dx ′ k(x ′ ) + η b (x) (8.19)<br />
<br />
(<br />
cos η a (x) − π )<br />
= cos<br />
(η b (x) + π )<br />
∫ b<br />
4<br />
4 + θ , θ = dx k(x) − π<br />
a 2<br />
, 2 , n θ = nπ , D − = (−1) n D + <br />
<br />
∫ b<br />
a<br />
dx k(x) =<br />
∫ b<br />
a<br />
√ ( )<br />
dx 2m E − V (x)<br />
(<br />
= π n + 1 )<br />
, n = 0, 1, 2, · · · (8.20)<br />
2<br />
n + 1/2 n WKB <br />
<br />
<br />
⎧<br />
e<br />
ψ(x) = √ D ⎪⎨<br />
ηa(x) ,<br />
x < a<br />
(<br />
× 2 cos η a (x) − π )<br />
, a < x < b<br />
k(x) 4<br />
⎪⎩<br />
(−1) n e −ηb(x) , x > b<br />
(8.21)
8 WKB () 154<br />
(8.20) η a (b) = π (n + 1/2) dη a /dx = k(x) > 0 η a (x) η a (a) = 0 <br />
η a (b) = π (n + 1/2) , a ≤ x ≤ b 0 ,<br />
cos (η a (x) − π/4) = 0 x<br />
(<br />
η a (x) = π n ′ − 1 )<br />
, n ′ = 1, 2, 3, · · ·<br />
4<br />
n , n WKB η a (x) ≫ 1 <br />
, (8.20) n ≫ 1 , <br />
a ≤ x ≤ b , , |ψ| 2 ,<br />
cos 2 (· · · ) 1/2 <br />
(<br />
|ψ| 2 = 4|D|2<br />
k(x) cos2 η a (x) − π )<br />
=⇒ 2|D|2<br />
4 k(x) = 2|D|2<br />
p(x)<br />
(8.22)<br />
p(x) 1 <br />
WKB <br />
<br />
V (x) V (x) = V (−x) , k(x) a = − b , b > 0 <br />
η a (x) =<br />
∫ x<br />
dx ′ k(x ′ ) = −<br />
∫ −x<br />
dx ′ k(−x ′ ) = −<br />
∫ −x<br />
−b<br />
b<br />
b<br />
dx ′ k(x ′ ) = − η b (−x)<br />
<br />
<br />
η a (−x) =<br />
∫ −x<br />
−b<br />
dx ′ k(x ′ ) =<br />
∫ b<br />
−b<br />
dx ′ k(x ′ ) +<br />
∫ −x<br />
b<br />
dx ′ k(x ′ ) = π<br />
η a (−x) − π (<br />
4 = − η a (x) − π )<br />
+ nπ<br />
4<br />
(<br />
n + 1 )<br />
− η a (x)<br />
2<br />
, (8.21) n , <br />
, WKB <br />
<br />
1 <br />
, V (x) = mω 2 x 2 /2 , (8.20) <br />
∫ x0 √<br />
(<br />
mω dx x 2 0 − x2 = π n + 1 )<br />
√<br />
2E<br />
, x 0 =<br />
−x 0<br />
2<br />
mω 2<br />
x = x 0 sin θ <br />
∫ x0<br />
−x 0<br />
dx<br />
√<br />
x 2 0 − x2 = 2<br />
∫ x0<br />
0<br />
dx<br />
√<br />
x 2 0 − x2 = 2x 2 0<br />
∫ π/2<br />
0<br />
dθ cos 2 θ = π 2 x2 0 = πE<br />
mω 2<br />
E = ω (n + 1/2) , <br />
<br />
V (x) = V (−x) ψ(x) n , x ≥ 0 <br />
ψ(x) 1 α = √ mω/ , q = αx <br />
z =<br />
q αx<br />
√ = √ 2n + 1 2n + 1
8 WKB () 155<br />
x 0 = √ 2n + 1/α , WKB <br />
⎧<br />
ψ(z) = √ D ⎨ e −η +(z) , z > 1<br />
× (<br />
k(z) ⎩ 2 cos η + (z) + π )<br />
, 0 ≤ z < 1<br />
4<br />
<br />
<br />
<br />
⎧<br />
⎪⎨<br />
ψ(z) =<br />
⎪⎩<br />
√<br />
2m<br />
k(z) =<br />
2 |V (x) − E| = α√ (2n + 1)|z 2 − 1|<br />
η ± (z) =<br />
∫ x<br />
±x 0<br />
dx ′ k(x ′ ) = (2n + 1)<br />
∫ z<br />
±1<br />
dz ′√ |z ′2 − 1|<br />
∫<br />
dx √ x 2 − 1 = 1 (<br />
x √ x<br />
2<br />
2 ∣<br />
− 1 − log ∣x + √ )<br />
x 2 − 1∣<br />
∫<br />
dx √ 1 − x 2 = 1 (<br />
x √ )<br />
1 − x<br />
2<br />
2 + sin −1 x<br />
2D ′ ( 2n + 1<br />
(<br />
(1 − z 2 ) cos z √ )<br />
1 − z 1/4 2<br />
2 + sin −1 z − nπ 2<br />
D ′ (<br />
z + √ z 2 − 1<br />
(z 2 − 1) 1/4<br />
)<br />
, 0 < z < 1<br />
) (<br />
n+1/2<br />
exp − 2n + 1 z √ )<br />
z<br />
2<br />
2 − 1 , z > 1<br />
n → ∞ H n (q) (15.105) <br />
ψ(q)/ √ α (4.22) <br />
ϕ n (q) 1<br />
√ = √ H α π<br />
1/2<br />
n! 2 n e−q2 n (q)<br />
WKB ψ(q) z 2 = 1 , ( q 2 = 2n + 1 ) <br />
|1 − z 2 | −1/4 |ψ| 2 D ′ <br />
, ε q = ε ψ(q) = ϕ n (q) D ′ <br />
, WKB n , n ,<br />
, , <br />
| q | < √ 2n + 1 |ψ(q)| 2 , (8.22) <br />
, <br />
1.0<br />
n = 0<br />
n = 3<br />
n = 50<br />
0.6<br />
0.4<br />
0.2<br />
−0.2<br />
1 2 3 4 q<br />
0.2<br />
0.0<br />
−0.2<br />
2 4 6 8 10 q<br />
−0.6<br />
−0.4
8 WKB () 156<br />
8.2 V (a) = ∞ , x = b (8.18) , x = a <br />
(8.17) (8.17) ψ(a) = 0 <br />
V (x)<br />
E<br />
a<br />
b<br />
1. <br />
∫ b<br />
<br />
a<br />
dx √ 2m (E − V (x)) = π<br />
(<br />
n + 3 )<br />
, n = 0, 1, 2, · · · (8.23)<br />
4<br />
2. u(x) x V (x) = u(x) (8.20) n <br />
, (8.23) <br />
{<br />
u(x) , x > 0<br />
V (x) =<br />
∞ , x ≤ 0<br />
3. (2.32) (8.23) E , (2.36) <br />
8.4 <br />
x < a <br />
, x > b <br />
x < a <br />
x > b , <br />
, x > b <br />
( )<br />
x > b x <br />
a<br />
WKB (8.16) <br />
⎧<br />
(<br />
⎪⎨ e −iπ/4 C + κ(x) e −ηb(x) + i )<br />
ψ(x) =<br />
2 eη b(x)<br />
, x < b<br />
⎪⎩<br />
C + κ(x) e iηb(x) ,<br />
x > b<br />
E<br />
b<br />
V (x)<br />
e ηb(x) (8.19) <br />
∫ b<br />
η b (x) = η a (x) − P , P = dx k(x) = 1 ∫ b<br />
√ ( )<br />
dx 2m V (x) − E<br />
a <br />
x < b <br />
(<br />
ψ(x) = κ(x) D + e ηa(x) + D − e −η a(x)<br />
, D − = e −iπ/4+P C + , D + = i 2 e−iπ/4−P C +<br />
x = a x > a (8.12) x < a <br />
a<br />
(8.24)<br />
ψ(x) = ψ + (x) + ψ − (x) ,<br />
ψ ± = C ′ ±κ(x)e ±iηa(x)
8 WKB () 157<br />
<br />
C ′ + =<br />
C ′ − =<br />
( )<br />
1<br />
2 D + + iD − e −iπ/4 =<br />
(e P + e−P<br />
4<br />
( 1<br />
2 D + − iD −<br />
)<br />
e iπ/4 = i<br />
(e P − e−P<br />
4<br />
)<br />
C +<br />
)<br />
C +<br />
ψ + , ψ − (8.7) J I J R<br />
<br />
J I = (<br />
m Im ψ+(x) ∗ dψ )<br />
+(x)<br />
dx<br />
J R = (<br />
m Im ψ−(x) ∗ dψ )<br />
−(x)<br />
dx<br />
= m |C′ +| 2 = m<br />
= − m |C′ −| 2 = − m<br />
, x > a J T <br />
J T = (<br />
m Im ψ ∗ (x) dψ(x) )<br />
dx<br />
) 2 (e P + e−P<br />
|C + | 2<br />
= m |C +| 2<br />
4<br />
) 2 (e P − e−P<br />
|C + | 2<br />
, T R <br />
T = |J T|<br />
|J I | = e −2P<br />
(1 + e −2P /4) 2 , R = |J (<br />
R| 1 − e −2P ) 2<br />
|J I | = /4<br />
1 + e −2P /4<br />
R + T = 1 WKB P = η a (b) ≫ 1 <br />
<br />
T ≈ e −2P = exp<br />
(<br />
− 2 <br />
T ≈ e −2P <br />
∫ b<br />
a<br />
√ (<br />
dx 2m V (x) − E) ) , R ≈ 1<br />
4<br />
8.5 <br />
, α A ( Z <br />
N ) A > 200 , α ( 2, 2 ,<br />
4 He ) (, ) = (Z − 2, N − 2) α <br />
, 1 fm = 1×10 −15 m <br />
, , α <br />
V (r) <br />
⎧<br />
⎪⎨ − V 0 , r < R<br />
V (r) = Z α Z D c α<br />
⎪⎩<br />
,<br />
r<br />
r > R<br />
− V 0 < 0 <br />
, Z α = 2 α , Z D = Z − 2 α<br />
, α <br />
r , R α <br />
V C<br />
V C = Z αZ D c α<br />
R<br />
V C<br />
E α<br />
O<br />
− V 0<br />
R<br />
b<br />
r
8 WKB () 158<br />
r 0 A 1/3 , ( r 0 ≈ 1.2 fm ) , α <br />
R = r 0 A 1/3 + ∆R , ∆R ≈ 1.6 fm ( U ) <br />
A ≈ 230 R ≈ 9 fm Z D = 90 (6.30), (6.31) <br />
V C ≈<br />
2 × 90 × 200<br />
9 × 137<br />
MeV ≈ 29 MeV<br />
α E α 4 ∼ 9 MeV , V C <br />
, r < R α , r > R <br />
, <br />
1 (8.24) P 3 ,<br />
V (x) (6.6) V eff (r) , , α l = 0 <br />
(8.24) <br />
Z α Z D c α<br />
b<br />
− E α = 0 , b = Z αZ D c α<br />
E α<br />
= V C<br />
E α<br />
R<br />
<br />
P = 1 <br />
∫ b<br />
R<br />
√ ( ) √<br />
Zα Z D c α<br />
2mEα<br />
dr 2m<br />
− E α =<br />
r<br />
<br />
∫ b<br />
R<br />
dr<br />
√<br />
b<br />
r − 1<br />
, m α R/b ≤ r/b ≤ 1 <br />
r = b cos 2 θ , 0 ≤ θ ≤ θ 0 = cos −1 ( √<br />
R/b<br />
)<br />
<br />
√ 2mEα<br />
P = 2b<br />
<br />
∫ θ0<br />
0<br />
√<br />
dθ sin 2 2mEα<br />
θ =<br />
<br />
√ (<br />
2mEα<br />
= b<br />
<br />
[<br />
b θ −<br />
] θ0<br />
sin 2θ<br />
2<br />
0<br />
cos −1 √<br />
R<br />
b − √<br />
R<br />
b − R2<br />
b 2 )<br />
E α ≪ V C √ R/b ≪ 1 cos −1 x = π/2 − x − x 3 /6 + · · · <br />
√ ( √<br />
2mEα π R<br />
P ≈ b<br />
2 − 2 b + 1 ( ) ) 3/2 R<br />
= 1 ( )<br />
C1<br />
√ − C 2 + C 3 E α<br />
3 b 2 Eα<br />
(8.25)<br />
(8.26)<br />
<br />
√ √<br />
√ 2αZα Z D mc<br />
C 1 = παZ α Z D 2mc2 , C 2 = 4<br />
2 R<br />
, C 3 = 2 2mc 2 R 3<br />
c<br />
3 αZ α Z D (c) 3<br />
<br />
α R <br />
α v in , v in /(2R) <br />
e −2P<br />
, <br />
α λ λ = e −2P v in /(2R) t K(t)<br />
, dt α K(t)λ dt <br />
K(t + dt) = K(t) − K(t)λ dt , dK dt = − λK , ∴ K(t) = K 0 e −λt
8 WKB () 159<br />
, T 1/2 ( K(t) K 0 K(T 1/2 ) = K 0 /2 ) <br />
(<br />
T 1/2 = log 2<br />
λ = C 0 2 √ 2mE<br />
√ α<br />
exp<br />
b<br />
Eα <br />
(<br />
cos −1 √<br />
R<br />
b − √<br />
R<br />
b − R2<br />
b 2 ))<br />
(8.27)<br />
≈ C ( )<br />
0 C1<br />
√ exp √ − C 2 + C 3 E α , C 0 = R √ 2m log 2 (8.28)<br />
Eα Eα<br />
v in √ 2E α /m , C 3 = 0 (8.28) <br />
( Geiger-Nuttall ) <br />
( Po, Z = 84 ), ( U, Z = 92 ), ( Fm, Z = 100 ) <br />
, T 1/2 α m mc 2 = 3727 MeV , <br />
<br />
Z D<br />
R C 0 C 1<br />
C 2<br />
C 3<br />
fm sec MeV 1/2 MeV 1/2 MeV −1<br />
Po 82 8.78 1.75×10 −21 325 79.7 0.494<br />
U 90 8.95 1.79×10 −21 356 84.3 0.485<br />
Fm 98 9.16 1.83×10 −21 388 89.0 0.481<br />
(8.27) , (8.28) •<br />
( http://www.nndc.bnl.gov/ensdf/ ), • A <br />
(8.27) , , T 1/2 <br />
E α 2 T 1/2 20 , T 1/2<br />
e C1/√ E α<br />
, ( C 1 ≫ √ E α ) <br />
238<br />
100 <br />
10 15<br />
236<br />
1 <br />
T 1/2 ( sec )<br />
10 12<br />
10 9<br />
10 6<br />
10 3<br />
10 0<br />
234<br />
Po<br />
U<br />
232<br />
208<br />
210<br />
206<br />
Fm<br />
230<br />
218<br />
10 18 4 5 6 7 8 9<br />
252<br />
254<br />
250<br />
228<br />
216<br />
226<br />
248<br />
246<br />
1 <br />
1 <br />
1 <br />
1 <br />
10 −3<br />
214<br />
224<br />
10 −6<br />
212<br />
222<br />
E α ( MeV )
9 160<br />
9 <br />
9.1 <br />
H H 0 H ′ (t) <br />
<br />
H = H 0 + H ′ (t)<br />
H 0 E n | n 〉 <br />
H 0 | n 〉 = E n | n 〉 ,<br />
〈 m | n 〉 = δ mn<br />
H H , E n<br />
, <br />
<br />
t | t 〉 , <br />
i ∂ | t 〉 = H| t 〉 (9.1)<br />
∂t<br />
H 0 , e −iE nt/ | n 〉<br />
, | t 〉 <br />
<br />
| t 〉 = ∑ n<br />
c n (t) e −iE nt/ | n 〉 (9.2)<br />
(9.1) <br />
i ∂ ∂t | t 〉 = ∑ (<br />
i dc )<br />
n<br />
dt + E nc n e −iEnt/ | n 〉<br />
n<br />
H| t 〉 = ∑ ( )<br />
c n (t) e −iE nt/<br />
H 0 + H ′ (t) | n 〉 = ∑<br />
n<br />
n<br />
( )<br />
c n e −iE nt/<br />
E n + H ′ (t) | n 〉<br />
<br />
∑<br />
| m 〉 <br />
n<br />
i dc n<br />
dt e−iE nt/ | n 〉 = ∑ n<br />
c n e −iE nt/ H ′ (t)| n 〉<br />
i dc m<br />
dt e−iEmt/ = ∑ n<br />
c n e −iEnt/ 〈 m |H ′ (t)| n 〉<br />
<br />
H ′ mn(t) = 〈 m |H ′ (t)| n 〉 e i(Em−En)t/ = 〈 m |H ′ I(t)| n 〉 , H ′ I(t) = e iH0t/ H ′ (t)e −iH0t/ (9.3)<br />
<br />
dc m<br />
dt<br />
= 1<br />
i<br />
∑<br />
H mn(t) ′ c n (t) (9.4)<br />
(9.1) <br />
c m (t) = c m (t 0 ) + 1<br />
i<br />
n<br />
∑<br />
n 1<br />
∫ t<br />
t 0<br />
dt 1 H ′ mn 1<br />
(t 1 ) c n1 (t 1 )
9 161<br />
t = t 0 c m (t 0 ) c n1 (t 1 ) <br />
c n1 (t 1 ) = c n1 (t 0 ) + 1<br />
i<br />
∑<br />
n 2<br />
∫ t1<br />
t 0<br />
dt 2 H ′ n 1n 2<br />
(t 2 ) c n2 (t 2 )<br />
<br />
c m (t) = c m (t 0 ) + 1<br />
i<br />
∑<br />
n 1<br />
∫ t<br />
t 0<br />
dt 1 H ′ mn 1<br />
(t 1 ) c n1 (t 0 )<br />
+ 1 ∑<br />
∫ t ∫ t1<br />
(i) 2 dt 1<br />
n 1n 2<br />
t 0<br />
t 0<br />
dt 2 H ′ mn 1<br />
(t 1 )H ′ n 1 n 2<br />
(t 2 ) c n2 (t 2 )<br />
<br />
<br />
c (1)<br />
m (t) = 1<br />
i<br />
∑<br />
n 1<br />
∫ t<br />
c m (t) = c m (t 0 ) + c (1)<br />
m (t) + c (2)<br />
m (t) + · · · + c (k)<br />
m (t) + · · · (9.5)<br />
t 0<br />
dt 1 H ′ mn 1<br />
(t 1 ) c n1 (t 0 )<br />
c (2)<br />
m (t) = 1<br />
(i) 2 ∑<br />
n 1 n 2<br />
∫ t<br />
t 0<br />
dt 1<br />
∫ t1<br />
c (k)<br />
m (t) = 1 ∑<br />
∫ t<br />
(i) k<br />
n 1···n k<br />
t 0<br />
dt 1<br />
∫ t1<br />
t 0<br />
dt 2 H ′ mn 1<br />
(t 1 )H ′ n 1n 2<br />
(t 2 ) c n2 (t 0 )<br />
∫ tk−1<br />
t 0 t 0<br />
dt 2 · · · dt k H mn ′ 1<br />
(t 1 )H n ′ 1 n 2<br />
(t 2 ) · · · H n ′ k−1 n k<br />
(t k ) c nk (t 0 )<br />
t = t 0 , , n c n (t 0 ) , t <br />
c n (t) , c (k)<br />
n (t, t 0 ) , (9.5)<br />
H ′ , H ′ mn(t) <br />
c m (t) ≈ c m (t 0 ) + c (1)<br />
m (t)<br />
t = t 0 H 0 | i 〉 c m (t 0 ) = δ mi <br />
, m ≠ i <br />
<br />
c m (t) ≈ c (1)<br />
m (t) = 1<br />
i<br />
∫ t<br />
t 0<br />
dt 1 H ′ mi(t 1 ) = 1<br />
i<br />
∫ t<br />
t 0<br />
dt 1 e i(E m−E i )t 1 / 〈 m |H ′ (t 1 )| i 〉 (9.6)<br />
9.2 <br />
, (9.5) <br />
(9.2) 〈 n | t 〉 = c n (t)e −iEnt/ <br />
c n (t) = e iEnt/ 〈 n | t 〉 = 〈 n |e iH0t/ | t 〉<br />
(9.3) , <br />
∑<br />
H mn ′ 1<br />
(t 1 )H n ′ 1 n 2<br />
(t 2 ) c n2 (t 0 ) = ∑ 〈 m |H I(t ′ 1 )| n 1 〉〈 n 1 |H I(t ′ 2 )| n 2 〉〈 n 2 |e iH 0t 0 / | t 0 〉<br />
n 1 n 2 n 1 n 2<br />
= 〈 m |H I(t ′ 1 )H I(t ′ 2 )e iH0t0/ | t 0 〉
9 162<br />
<br />
<br />
<br />
U(t, t 0 ) = 1 + 1 ∫ t<br />
i<br />
+ 1<br />
(i) k ∫ t<br />
c m (t) = 〈 m |U(t, t 0 ) e iH 0t 0 / | t 0 〉<br />
t 0<br />
dt 1 H ′ I(t 1 ) + 1<br />
(i) 2 ∫ t<br />
t 0<br />
dt 1<br />
∫ t1<br />
t 0<br />
dt 1<br />
∫ t1<br />
t 0<br />
dt 2 H ′ I(t 1 )H ′ I(t 2 ) + · · ·<br />
∫ tk−1<br />
t 0 t 0<br />
dt 2 · · · dt k H I(t ′ 1 )H I(t ′ 2 ) · · · H I(t ′ k ) + · · · (9.7)<br />
| t 〉 = ∑ n<br />
c n (t) e −iE nt/ | n 〉 = e −iH 0t/ ∑ n<br />
| n 〉 c n (t)<br />
= e −iH 0t/ ∑ n<br />
| n 〉〈 n |U(t, t 0 ) e iH 0t 0 / | t 0 〉<br />
= e −iH 0t/ U(t, t 0 ) e iH 0t 0 / | t 0 〉 (9.8)<br />
<br />
U(t, t 0 ) 2 <br />
U (2) (t, t 0 ) =<br />
∫ t<br />
∫ t1<br />
dt 1 dt 2 H I(t ′ 1 )H I(t ′ 2 )<br />
t 0 t 0<br />
<br />
t 2<br />
t<br />
t 0 ≤ t 2 ≤ t ,<br />
t 2 ≤ t 1 ≤ t<br />
<br />
U (2) (t, t 0 ) =<br />
∫ t<br />
∫ t<br />
dt 2 dt 1 H I(t ′ 1 )H I(t ′ 2 )<br />
t 0 t 2<br />
t 0<br />
t 0<br />
t<br />
t 1<br />
<br />
<br />
<br />
U (2) (t, t 0 ) = 1 2<br />
∫ t<br />
U (2) (t, t 0 ) =<br />
t 0<br />
dt 1<br />
∫ t<br />
t 0<br />
dt 2<br />
(<br />
∫ t<br />
t 0<br />
dt 1<br />
∫ t<br />
t 1<br />
dt 2 H ′ I(t 2 )H ′ I(t 1 )<br />
)<br />
θ(t 1 − t 2 )H I(t ′ 1 )H I(t ′ 2 ) + θ(t 2 − t 1 )H I(t ′ 2 )H I(t ′ 1 )<br />
θ(t) =<br />
H ′ I (t 1) H ′ I (t 2) <br />
U (2) (t, t 0 ) = 1 2<br />
∫ t<br />
t 0<br />
dt 1<br />
∫ t<br />
{<br />
1 , t > 0<br />
0 , t < 0<br />
t 0<br />
dt 2 H ′ I(t 1 )H ′ I(t 2 ) = 1 2<br />
(∫ t<br />
t 0<br />
dt 1 H ′ I(t 1 )<br />
, t 1 ≠ t 2 H ′ I (t 1) H ′ I (t 2) T <br />
T[F (t 1 )G(t 2 )] = θ(t 1 − t 2 )F (t 1 )G(t 2 ) + θ(t 2 − t 1 )G(t 2 )F (t 1 )<br />
) 2
9 163<br />
<br />
U (2) (t, t 0 ) = 1 2!<br />
∫ t<br />
t 0<br />
dt 1<br />
∫ t<br />
t 0<br />
dt 2 T[H ′ I(t 1 )H ′ I(t 2 )]<br />
3 , T , <br />
∫ t<br />
t 0<br />
dt 1 · · ·<br />
<br />
U(t, t 0 ) =<br />
k=0<br />
∫ tk−1<br />
t 0<br />
dt k H ′ I(t 1 ) · · · H ′ I(t k ) = 1 k!<br />
∫ t<br />
t 0<br />
dt 1 · · ·<br />
∫ t<br />
t 0<br />
dt k T[H ′ I(t 1 ) · · · H ′ I(t k )]<br />
∞∑<br />
∫<br />
1 1 t ∫ t<br />
( ∫ 1 t<br />
)<br />
k! (i) k dt 1 · · · dt k T[H I(t ′ 1 ) · · · H I(t ′ k )] = T exp dt ′ H I (t ′ )<br />
t 0 t 0<br />
i t 0<br />
<br />
(9.8) <br />
<br />
| t 〉 = V (t, t 0 )| t 0 〉 , V (t, t 0 ) = e −iH 0t/ U(t, t 0 ) e iH 0t 0 /<br />
(9.9)<br />
i ∂ ∂t V (t, t 0) = i ∂e−iH0t/<br />
U(t, t 0 ) e iH0t0/ + e −iH0t/ i ∂U(t, t 0)<br />
e iH0t0/<br />
∂t<br />
∂t<br />
= H 0 e −iH 0t/ U(t, t 0 ) e iH 0t 0 / + e −iH 0t/ i ∂U(t, t 0)<br />
∂t<br />
e iH 0t 0 /<br />
(9.7) <br />
i ∂U(t, t 0)<br />
∂t<br />
= H I(t) ′ + 1 ∫ t<br />
dt 2 H<br />
i<br />
I(t)H ′ I(t ′ 2 ) + · · ·<br />
t 0<br />
+<br />
∫<br />
1 t<br />
(i) k−1<br />
t 0<br />
dt 2 · · ·<br />
∫ tk−1<br />
t 0<br />
dt k H ′ I(t)H ′ I(t 2 ) · · · H ′ I(t k ) + · · ·<br />
= H ′ I(t)U(t, t 0 ) = e iH0t/ H ′ (t)e −iH0t/ U(t, t 0 ) (9.10)<br />
<br />
i ∂ ∂t V (t, t 0) = H 0 V (t, t 0 ) + H ′ (t)V (t, t 0 ) = H(t)V (t, t 0 )<br />
, , | t 〉 = V (t, t 0 )| t 0 〉 <br />
(9.1) H , V (t 0 , t 0 ) = 1 <br />
V (t, t 0 ) = e −i(t−t 0)H/<br />
<br />
<br />
t 2 <br />
| α(t) 〉 = V (t, t 0 )| α 0 〉 , | β(t) 〉 = V (t, t 0 )| β 0 〉<br />
F f αβ (t) = 〈 α(t) | F | β(t) 〉 <br />
<br />
<br />
(9.9) <br />
f αβ (t) = 〈 α 0 | F H (t) | β 0 〉 , F H (t) = V † (t, t 0 )F V (t, t 0 )
9 164<br />
t 0 f αβ (t) F H (t)<br />
F H (t) <br />
( , F )<br />
i ∂F H<br />
∂t<br />
F H 1 = V V † <br />
i ∂F H<br />
∂t<br />
= i ∂V † (t, t 0 )<br />
F V (t, t 0 ) + V † (t, t 0 )F i ∂V (t, t 0)<br />
∂t<br />
∂t<br />
= − V † (t, t 0 )HF V (t, t 0 ) + V † (t, t 0 )F HV (t, t 0 )<br />
= [ F H (t) , H H (t) ] , H H (t) ≡ V † (t, t 0 )H(t)V (t, t 0 ) (9.11)<br />
, (9.1) (9.11) <br />
<br />
H H H (t) (9.11) <br />
i ∂H H<br />
∂t<br />
= [ H H (t) , H H (t) ] = 0 , H H (t) = = H<br />
V (t, t 0 ) = e −i(t−t0)H/ <br />
<br />
H H (t) = e i(t−t0)H/ He −i(t−t0)H/ = H<br />
( )<br />
(9.8) <br />
<br />
| α(t) 〉 = e −iH 0t/ | α(t) 〉 I , | α(t) 〉 I = U(t, t 0 ) e iH 0t 0 / | α 0 〉<br />
f αβ (t) = I 〈 α(t) | F I (t) | β(t) 〉 I ,<br />
F I (t) = e iH 0t 0 / F e −iH 0t/<br />
(9.10) <br />
i ∂ ∂t | α(t) 〉 I = i ∂U(t, t 0)<br />
∂t<br />
(9.10) <br />
e iH0t0/ | α 0 〉 = H ′ I(t)U(t, t 0 ) e iH0t0/ | α 0 〉 = H ′ I(t)| α(t) 〉 I<br />
i ∂ ∂t | α(t) 〉 I = i ∂ ∂t eiH0t/ | α(t) 〉 = i ∂eiH 0t/<br />
| α(t) 〉 + e iH0t/ i ∂ ∂t<br />
∂t | α(t) 〉<br />
( )<br />
= − H 0 e iH0t/ | α(t) 〉 + e iH0t/ H 0 + H ′ (t) | α(t) 〉<br />
= e iH 0t/ H ′ (t)e −iH 0t/ e iH 0t/ | α(t) 〉<br />
, F I (t) <br />
= H ′ I(t)| α(t) 〉 I<br />
i ∂ ∂t F I(t) = e iH0t/( − H 0 F + F H 0<br />
)e −iH0t/ = [ F I (t) , H 0 ]<br />
H H ′ I (t) H 0 <br />
( ) <br />
<br />
H I ′(t) , H′ I (t)
9 165<br />
<br />
H H I ′ (t) <br />
H 0 H <br />
| α(t) 〉 I H 0 | n 〉 <br />
| α(t) 〉 I = ∑ n<br />
c n (t)| n 〉<br />
<br />
i ∂ ∂t | α(t) 〉 I = i ∑ n<br />
dc n<br />
dt | n 〉 = ∑ n<br />
c n H ′ I(t)| n 〉<br />
| m 〉 <br />
i ∑ n<br />
dc m<br />
dt<br />
= ∑ n<br />
H ′ mn(t)c n (t) , H ′ mn(t) = 〈 m |H ′ I(t)| n 〉<br />
(9.4) <br />
9.1<br />
i d dt | t 〉 I = H ′ I(t) | t 〉 I (9.8) <br />
9.3 <br />
H ′ (t) <br />
H ′ (t) =<br />
{<br />
V , t > 0<br />
0 , t < 0<br />
V ω mn ≡ (E m − E n )/ (9.6) <br />
c (1)<br />
m (t) = 1 ∫ t<br />
i 〈 m |V | i 〉 dt 1 e iωmit1 = 1<br />
i 〈 m |V | i 〉sin(ω mit/2)<br />
ω mi /2<br />
0<br />
e iωmit/2 (9.12)<br />
, | i 〉 t > 0 | m 〉 , 1 <br />
|c (1)<br />
m (t)| 2 = 1 ( ) 2<br />
2 |〈 m |V | i sin(ωmi t/2)<br />
〉|2 = π t<br />
ω mi /2 2 |〈 m |V | i 〉|2 f(ω mi /2, t) (9.13)<br />
<br />
ω mi ≠ 0 |c (1)<br />
m (t)| 2 <br />
f(x, t) = sin2 tx<br />
πtx 2<br />
0 ≤ |c (1)<br />
m (t)| 2 4|〈 m |V | i 〉|2<br />
≤<br />
(ω mi ) 2<br />
2π/ω mi , ω mi → 0 <br />
|c (1)<br />
m (t)| 2 = t2<br />
|〈 m |V | i 〉|2<br />
2 t 2 , |〈 m |V | i 〉| 2 |c (1)<br />
m (t)| 2 > 1 <br />
, 1 , ω mi ≈ 0 t <br />
t <br />
t 2<br />
2 |〈 m |V | i 〉|2 ≪ 1
9 166<br />
f(x, t) x <br />
t , f(x, t) x =<br />
0 t/π , 2π/t <br />
, t ( <br />
|c (1)<br />
m (t)| 2 ≪ 1 )<br />
|ω mi | =<br />
E m − E i<br />
∣ ∣ < 2π (9.14)<br />
t<br />
t/π<br />
| m 〉 |c (1)<br />
m (t)| 2 <br />
<br />
−π/t<br />
, | m 〉 , E m ≈<br />
E i | m 〉 <br />
E i − ∆E ≤ E m ≤ E i + ∆E<br />
| m 〉 , <br />
E E +dE ρ(E) dE ρ(E) <br />
ρ(E) ρ(E) , P <br />
P =<br />
∫ Ei +∆E<br />
E i −∆E<br />
t <br />
dE m ρ(E m ) |c (1)<br />
m (t)| 2 = πt ∫ Ei +∆E<br />
2 dE m ρ(E m ) |〈 m |V | i 〉| 2 f(ω mi /2, t)<br />
∆E<br />
<br />
E i −∆E<br />
≫ 2π<br />
t<br />
π/t<br />
(9.15)<br />
, (9.14) , |〈 m |V | i 〉| 2 <br />
ρ(E m ) E m , (9.14) , <br />
E m = E i <br />
P = πt (<br />
)<br />
2 |〈 m |H ′ | i 〉| 2 ρ(E m ) I , I =<br />
E m =E i<br />
x = t ω mi /2 = t (E m − E i )/2 <br />
∫ Ei +∆E<br />
E i−∆E<br />
dE m f(ω mi /2, t)<br />
I = 2 π<br />
∫ t∆E/2<br />
−t∆E/2<br />
dx sin2 x<br />
x 2<br />
(9.15) t∆E/2 ≫ π −∞ ∞ <br />
I = 2 π<br />
∫ ∞<br />
−∞<br />
dx sin2 x<br />
= 2<br />
x 2<br />
<br />
P = t 2π <br />
<br />
w = P t = 2π <br />
(<br />
)<br />
|〈 m |H ′ | i 〉| 2 ρ(E m )<br />
E m=E i<br />
(<br />
)<br />
|〈 m |H ′ | i 〉| 2 ρ(E m )<br />
(9.16)<br />
E m=E i<br />
<br />
<br />
f(x, t → ∞) = δ(x) (9.17)
9 167<br />
(9.13) t → ∞ <br />
|c (1)<br />
m (t)| 2 = t π 2 |〈 m |V | i 〉|2 δ(ω mi /2) = t 2π |〈 m |V | i 〉|2 δ(E m − E i )<br />
δ(ax) = δ(x)/|a| 1 | m 〉 w i→m <br />
w i→m = |c(1) m (t)| 2<br />
= 2π t |〈 m |V | i 〉|2 δ(E m − E i ) (9.18)<br />
<br />
∫<br />
w =<br />
dE m ρ(E m ) w i→m = 2π <br />
= 2π <br />
∫<br />
dE m ρ(E m ) |〈 m |V | i 〉| 2 δ(E m − E i )<br />
(<br />
)<br />
|〈 m |V | i 〉| 2 ρ(E m )<br />
E m =E i<br />
(9.16) <br />
t = 0 V , t = − ∞ <br />
H ′ (t) = V e −ε|t| , ε → + 0<br />
ε e −ε|t| t H ′ (t) = V <br />
, t → ± ∞ e −ε|t| → 0 H ′ (t) → 0 , ( t 0 → − ∞ ) <br />
( t → + ∞ ) H 0 t 0 → − ∞ , t → + ∞ <br />
c (1)<br />
m (∞) = 1 ∫ ∞<br />
i 〈 m |V | i 〉 dt e iωmit−ε|t| = 2π<br />
i 〈 m |V | i 〉 δ(ω mi)<br />
(14.10) <br />
−∞<br />
)<br />
|c (1)<br />
m (∞)| 2 = 4π2<br />
2<br />
2 |〈 m |V | i 〉|2( δ(ω mi )<br />
2 , t 0 → − ∞ , t → + ∞ <br />
<br />
<br />
<br />
w i→m <br />
(9.18) <br />
δ(ω) = 1 ∫ t<br />
dt e iωt<br />
2π t 0<br />
δ(0) = 1 ∫ t<br />
dt = t − t 0<br />
2π t 0<br />
2π<br />
( ) 2 t − t 0<br />
δ(ω) = δ(0) δ(ω) =<br />
2π<br />
δ(ω)<br />
w i→m = |c(1) m (∞)| 2<br />
= 2π<br />
t − t 0 2 |〈 m |V | i 〉|2 δ(ω mi ) = 2π |〈 m |V | i 〉|2 δ(E m − E i )<br />
9.2<br />
(9.17)
9 168<br />
9.4 <br />
H 0 = − 2 ∇ 2 /2m , exp(ik·r) <br />
, <br />
1. 1 <br />
2. <br />
<br />
<br />
1 L 1 , <br />
u(x, y, z) = u(x + L, y, z) = u(x, y + L, z) = u(x, y, z + L) ,<br />
u(r) = C exp(ik·r)<br />
<br />
exp(ik x L) = exp(ik y L) = exp(ik z L) = 1<br />
, n x , n y , n z <br />
k x = 2π L n x , k y = 2π L n y , k z = 2π L n z (9.19)<br />
, k L → ∞ k 1 <br />
u k (r) = 1 √<br />
V<br />
exp(ik·r) , V = L 3 (9.20)<br />
V = L 3 <br />
u k 2 k 2 /2m , <br />
E 0 <br />
F (k x )<br />
N = ∑ k<br />
1 ,<br />
, <br />
|k| ≤ k 0 , k 0 =<br />
√<br />
2mE0<br />
k k <br />
k x ∆k x = 2π/L <br />
2<br />
∑<br />
F (k x ) = L ∑<br />
∆k x F (k x )<br />
2π<br />
k x<br />
k x<br />
∆k x<br />
k x<br />
, ∆k x L → ∞ ∆k x → 0 <br />
, <br />
∑<br />
F (k x ) −−−−→ L→∞ L ∫<br />
dk x F (k x ) , 3 ∑ <br />
2π<br />
k<br />
k x<br />
F (k) −−−−→<br />
L→∞ V ∫<br />
(2π) 3 d 3 k F (k)<br />
<br />
N =<br />
V ∫<br />
(2π) 3 d 3 k =<br />
V ∫ k0<br />
∫<br />
|k|≤k 0<br />
(2π) 3 dk k 2 dΩ<br />
0
9 169<br />
k E = 2 k 2 /2m <br />
N =<br />
∫ E0<br />
0<br />
∫<br />
dE dΩ<br />
V<br />
√<br />
m 2mE<br />
(2π) 3 2 2<br />
E E + dE , k Ω Ω + dΩ <br />
ρ box (E) dE dΩ <br />
ρ box (E) =<br />
V<br />
√<br />
m 2mE<br />
(2π) 3 2 2 (9.21)<br />
(9.21) ( ρ box (E) <br />
4π ) , <br />
, <br />
<br />
<br />
<br />
k <br />
∫<br />
∫<br />
d 3 x u ∗ k(r) u k ′(r) = Ck ∗ C k ′<br />
u k (r) = C k exp(ik·r)<br />
d 3 x exp(i(k ′ − k)·r) = (2π) 3 C ∗ k C k ′δ(k − k ′ ) = δ(k − k ′ )<br />
C k C k = 1/(2π) 3/2 , <br />
<br />
u k (r) =<br />
1<br />
exp(ik·r)<br />
(2π)<br />
3/2<br />
(9.20) V = (2π) 3 <br />
ρ(E) = m 2 √<br />
2mE<br />
2<br />
, , <br />
<br />
9.5 <br />
<br />
H ′ (t) = V e −iωt + V † e iωt<br />
V t = 0 | i 〉 <br />
t <br />
c (1)<br />
m (t) = 1<br />
i<br />
∫ t0<br />
0<br />
dt 1 〈 m | ( V e −iωt 1<br />
+ V † e iωt 1 ) | i 〉<br />
(9.12) ω mi → ω mi ± ω <br />
c (1)<br />
m (t) = − i 〈 m |V | i 〉 sin((ω mi − ω)t/2)<br />
e i(ω mi−ω)t/2<br />
(ω mi − ω)/2<br />
− i 〈 m |V † | i 〉 sin((ω mi + ω)t/2)<br />
(ω mi + ω)/2<br />
e i(ωmi+ω)t/2 (9.22)
9 170<br />
9.2 , c (1)<br />
m (t) ≈ 0 <br />
1 E m ≈ E i + ω , 2 <br />
ω | i 〉 | m 〉 2 <br />
E m ≈ E i − ω , 1 ω<br />
| i 〉 | m 〉 <br />
E m ≈ E i + ω <br />
|c (1)<br />
m (t)| 2 = |〈 m |V | i 〉| 2 πt<br />
2 f((ω mi − ω)/2, t)<br />
<br />
E i + ω − ∆E ≤ E m ≤ E i + ω + ∆E<br />
| m 〉 w (9.16)<br />
E m = E i E m = E i + ω <br />
<br />
w = 2π <br />
(<br />
)<br />
|〈 m |H ′ | i 〉| 2 ρ(E m )<br />
E m=E i+ω<br />
9.3<br />
(5.66) H <br />
)<br />
H = H 0 + H ′ (t) , H 0 = ω 0 σ z , H ′ (t) = ω 1<br />
(σ x cos ωt + σ y sin ωt<br />
σ ± = σ x ± i σ y <br />
H ′ (t) = ω (<br />
1<br />
σ + e −iωt + σ − e iωt) , σ − = (σ + ) †<br />
2<br />
ω 0 ≫ ω 1 H ′ (t) (9.22) <br />
P − (t) (5.70) <br />
9.6 <br />
H ′ (t) , H ′ (t) <br />
<br />
t , H(t) | n(t) 〉 E n (t) <br />
<br />
H(t) | n(t) 〉 = E n (t) | n(t) 〉 (9.23)<br />
t = 0 | n(0) 〉 , H(t) , t <br />
| n(t) 〉 , <br />
t | t 〉 | n(t) 〉 <br />
| t 〉 = ∑ n<br />
c n (t) e −iθn(t) | n(t) 〉 ,<br />
θ n (t) = 1 <br />
∫ t<br />
0<br />
dt ′ E n (t ′ )<br />
<br />
| ṅ(t) 〉 = ∂ ∂H<br />
| n(t) 〉 , Ḣ =<br />
∂t ∂t
9 171<br />
<br />
i ∂ ∂t | t 〉 = ∑ n<br />
(<br />
i dc )<br />
n<br />
dt | n(t) 〉 + ic n(t)| ṅ(t) 〉 + E n (t)c n (t)| n(t) 〉 e −iθn(t)<br />
, <br />
i ∂ ∂t | t 〉 = H(t)| t 〉<br />
<br />
∑<br />
n<br />
( )<br />
dcn<br />
dt | n(t) 〉 + c n(t)| ṅ(t) 〉 e −iθn(t) = 0<br />
| m(t) 〉 〈 m(t) | n(t) 〉 = δ mn <br />
dc m<br />
dt<br />
= − ∑ n<br />
c n (t)〈 m(t) | ṅ(t) 〉 e iθ m(t)−iθ n (t)<br />
(9.24)<br />
(9.23) t <br />
Ḣ| n(t) 〉 + H| ṅ(t) 〉 = Ėn| n(t) 〉 + E n | ṅ(t) 〉<br />
| m(t) 〉 <br />
〈 m(t) |Ḣ| n(t) 〉 + E m(t)〈 m(t) | ṅ(t) 〉 = δ mn Ė n + E n (t)〈 m(t) | ṅ(t) 〉<br />
m ≠ n <br />
〈 m(t) | ṅ(t) 〉 = −<br />
〈 m(t) |Ḣ| n(t) 〉<br />
E m (t) − E n (t)<br />
(9.25)<br />
m = n , 〈 n(t) | n(t) 〉 = 1 t <br />
〈 ṅ(t) | n(t) 〉 + 〈 n(t) | ṅ(t) 〉 = 〈 n(t) | ṅ(t) 〉 ∗ + 〈 n(t) | ṅ(t) 〉 = 0<br />
〈 n(t) | ṅ(t) 〉 , γ n (t) <br />
〈 n(t) | ṅ(t) 〉 = − i dγ n(t)<br />
dt<br />
(9.25), (9.26) (9.24) <br />
dc m<br />
dt<br />
= i dγ m(t)<br />
dt<br />
c m (t) + ∑ n≠m<br />
c n (t)<br />
〈 m(t) |Ḣ| n(t) 〉<br />
ω mn (t)<br />
(<br />
exp i<br />
∫ t<br />
0<br />
)<br />
dt ′ ω mn (t ′ )<br />
(9.26)<br />
(9.27)<br />
<br />
ω mn (t) = E m (t) − E n (t)<br />
<br />
c n (t), Ḣ, ω mn (t) , (9.27) <br />
, t = 0 | i(0) 〉 c n (t) = δ ni m ≠ i <br />
dc m<br />
dt<br />
≈<br />
〈 m(t) |Ḣ| i(t) 〉<br />
ω mi (t)<br />
e iω mi(t)t<br />
<br />
c m (t) ≈<br />
〈 m(t) |Ḣ| i(t) 〉<br />
ω mi (t)<br />
∫ t<br />
0<br />
dt ′ e iωmi(t)t′ ≈<br />
〈 m(t) |Ḣ| i(t) 〉<br />
(<br />
)<br />
iω mi (t) 2 e iωmi(t)t − 1<br />
(9.28)
9 172<br />
<br />
<br />
H ′ (t) = V e −iωt + V † e iωt<br />
H ′ (t) H 0 | n(t) 〉<br />
E n (t) H 0 <br />
H 0 | n 〉 = E n | n 〉<br />
(9.27) m ≠ i <br />
dc m<br />
dt<br />
≈ 〈 m |Ḣ| i 〉<br />
ω mi<br />
e iω mit = −iω<br />
ω mi<br />
〈 m | ( V e −iωt − V † e iωt) | i 〉 e iω mit<br />
<br />
c m = −<br />
ω (<br />
〈 m |V | i 〉 ei(ωmi−ω)t − 1<br />
− 〈 m |V † | i 〉 ei(ωmi+ω)t )<br />
− 1<br />
ω mi ω mi − ω<br />
ω mi + ω<br />
(9.29)<br />
H ′ (t) , , ω , |ω mi | ≫ ω<br />
(9.29) <br />
c m ≈ −<br />
ω (<br />
)<br />
〈 m |V | i 〉 ei(ωmi−ω)t − 1<br />
− 〈 m |V † | i 〉 ei(ωmi+ω)t − 1<br />
≈ (9.28)<br />
ω mi ω mi ω mi<br />
, ω mi ≈ ω ( ) (9.28) <br />
9.7 <br />
H(t) Ḣ ≈ 0 , , (9.27) 2 <br />
<br />
dc m<br />
dt<br />
= i dγ m(t)<br />
dt<br />
c m (t)<br />
c m (t) = c m (0) e iγm(t) <br />
| t 〉 = ∑ m<br />
c m (0) e iγ m(t)−iθ m (t) | m(t) 〉<br />
<br />
(<br />
e −iθm(t) = exp − i <br />
∫ t<br />
0<br />
)<br />
dt ′ E m (t ′ )<br />
e −iEt/ <br />
, γ m (t) t<br />
| m(t) 〉 <br />
|〈 m(t) | t 〉| 2 = |c m (0) e iγm(t)−iθm(t) | 2 = |c m (0)| 2<br />
, , <br />
<br />
B(t) ω (5.66) <br />
<br />
H = µ B B(t)·σ , B x = B 1 cos ωt , B y = B 1 sin ωt , B z = B 0
9 173<br />
B 0 B 1 B = |B(t)| = √ B 2 0 + B2 1 <br />
E m (t) = mµ B B <br />
H(t) | m(t) 〉 = mµ B B | m(t) 〉 , m = ± 1<br />
θ m (t) = 1 <br />
∫ t<br />
0<br />
dt ′ E m (t ′ ) = mµ BB<br />
<br />
σ | m(t) 〉 2 χ m (5.53) <br />
⎛<br />
⎞<br />
√ 1<br />
B + mB0 ⎜<br />
χ m (t) =<br />
⎝<br />
2B m B ⎟<br />
x + iB y<br />
⎠ (9.30)<br />
B + mB 0<br />
t<br />
<br />
(9.26) γ m <br />
⎛<br />
√<br />
d B +<br />
dt χ mB0 ⎜<br />
m =<br />
⎝<br />
2B<br />
0<br />
mω −B y + iB x<br />
B + mB 0<br />
⎞<br />
⎟<br />
⎠<br />
dγ m<br />
dt<br />
= i χ † d<br />
m<br />
dt χ ωB1<br />
2<br />
m = −<br />
2B(B + mB 0 ) = mB 0 − B<br />
ω<br />
2B<br />
<br />
<br />
, t ψ(t) <br />
ψ(t) = ∑<br />
γ m (t) = mB 0 − B<br />
ωt (9.31)<br />
2B<br />
γ m − θ m = − ωt<br />
2 + mϕ(t) , ϕ(t) = − µ BB<br />
t + B 0<br />
2B ωt<br />
m=±1<br />
c m (0) e i(γm−θm) χ m (t) = e −iωt/2<br />
∑<br />
m=±1<br />
t = 0 σ z +1 <br />
( ) √<br />
c m (0) = χ † 1 B + mB0<br />
m(0) =<br />
0<br />
2B<br />
c m (0) e imϕ(t) χ m (t)<br />
<br />
ψ(t) = e−iωt/2<br />
2B<br />
∑<br />
m=±1<br />
e imϕ ⎛<br />
⎝ B + mB 0<br />
m(B x + iB y )<br />
⎞<br />
⎠ = e−iωt/2<br />
B<br />
⎛<br />
⎝ B cos ϕ + iB 0 sin ϕ<br />
i (B x + iB y ) sin ϕ<br />
⎞<br />
⎠<br />
, t σ z −1 P − <br />
P − (t) = | ( 0 1 )ψ(t) | 2 =<br />
(B x + iB y ) sin ϕ<br />
∣ B ∣<br />
2<br />
= B2 1<br />
B 2 sin2 (<br />
µB B<br />
t − B 0<br />
2B ωt )<br />
(9.32)<br />
2 , z <br />
B(t) , t σ z ±1 N ± <br />
P − = N − /(N + + N − ) (9.32) ,
9 174<br />
(5.70) <br />
ω 2 1<br />
P − =<br />
(ω 0 − ω/2) 2 + ω1<br />
2<br />
sin 2 (√<br />
(ω 0 − ω/2) 2 + ω 2 1 t )<br />
ω 0 = µ B B 0 / , ω 1 = µ B B 1 / ω ≪ ω 0 , ω 1 <br />
√ (<br />
)<br />
√(ω 0 − ω/2) 2 + ω1 2 ≈ ω0 2 + ω 0 ω<br />
ω2 1 1 −<br />
2(ω0 2 + ω2 1 ) = µ BB<br />
− B 0<br />
2B ω<br />
, (9.32) <br />
H B(t) , ( ) B(t) <br />
, (9.30) | n(t) 〉 B | n(B) 〉 <br />
(<br />
∂<br />
∂t | n(B) 〉 = dBx ∂<br />
+ dB y ∂<br />
+ dB )<br />
z ∂<br />
| n(B) 〉 = dB dt ∂B x dt ∂B y dt ∂B z dt ·∇ B| n(B) 〉<br />
(9.26) <br />
dγ n<br />
dt<br />
γ n B <br />
γ n (t) = i<br />
= i 〈 n(B) |∇ B | n(B) 〉· dB dt<br />
∫ B(t)<br />
B(0)<br />
〈 n(B) |∇ B | n(B) 〉·dB<br />
B(t) T , B(T ) = B(0) t = 0 t = T <br />
B C <br />
∮<br />
γ n (T ) = i 〈 n(B) |∇ B | n(B) 〉·dB (9.33)<br />
<br />
∫<br />
γ n (T ) = dS·V (B) , V (B) = i ∇ B ×〈 n(B) |∇ B | n(B) 〉<br />
S<br />
C<br />
S C , dS <br />
<br />
9.4<br />
B <br />
B = B( sin θ cos φ , sin θ sin φ , cos θ )<br />
| m(B) 〉 (5.53) , ∇ B <br />
∂<br />
∇ B = e r<br />
∂B + e 1 ∂<br />
θ<br />
B ∂θ + e 1 ∂<br />
φ<br />
B sin θ ∂φ ,<br />
dB = dB e r + B dθ e θ + B sin θ dφ e φ<br />
<br />
i 〈 m(B) |∇ B | m(B) 〉 = m cos θ − 1<br />
2B sin θ<br />
(9.33) γ m (T ) , B z = B cos θ 1 <br />
(9.31) t = 2π/ω <br />
e φ
10 175<br />
10 <br />
10.1 <br />
<br />
N in , dΩ dN N in dΩ<br />
<br />
dσ<br />
dN = N in dΩ (10.1)<br />
dΩ<br />
σ , dσ/dΩ dN <br />
[] −1 , N in [] −1 [] −1 , σ <br />
, σ <br />
1 <br />
(<br />
)<br />
− 2<br />
2m ∇2 + V (r) ψ(r) = E ψ(r)<br />
, <br />
z r , ψ(r) <br />
:<br />
(<br />
ψ(r) −−−−→ r→∞<br />
A e ikz + f(θ, φ) χ(r) )<br />
, k > 0<br />
r<br />
1 , 2 z k > 0 r → ∞<br />
V (r) → 0 , <br />
2 k 2<br />
2m eikz − 2<br />
2m ∇2 f(θ, φ) χ(r) (<br />
= E e ikz + f(θ, φ) χ(r) )<br />
r<br />
r<br />
(6.1) <br />
− 2<br />
2m ∇2 f(θ, φ) χ(r) (<br />
= − 2 d 2 χ<br />
r 2mr dr 2 − χ )<br />
r 2 L2 f(θ, φ)<br />
r → ∞ 2 1 <br />
( 2 k 2 )<br />
(<br />
2m − E e ikz f(θ, φ) <br />
2<br />
d 2 )<br />
χ<br />
−<br />
r 2m dr 2 + Eχ = 0<br />
<br />
E = 2 k 2<br />
2m ,<br />
d 2 χ<br />
dr 2 + k2 χ = 0<br />
2 χ(r) e ikr e −ikr <br />
, , <br />
, χ(r) ∝ e ikr <br />
) √<br />
ψ(r) −−−−→ r→∞<br />
A<br />
(e ikz + f(θ, φ) eikr<br />
2mE<br />
, k =<br />
r<br />
2 (10.2)<br />
ϕ in , ϕ out <br />
ϕ in (r) = A e ikz ,<br />
ϕ out (r) = A f(θ, φ) eikr<br />
r
10 176<br />
f(θ, φ) E > 0 , (10.2) <br />
1 E < 0 <br />
, ψ(r) r→∞<br />
−−−−→ 0 , E < 0 <br />
1 , ∇<br />
<br />
<br />
∇ϕ out (r) = A<br />
∂<br />
∇ = e r<br />
∂r + 1 u(θ, φ) ,<br />
r u(θ,<br />
φ) = e ∂<br />
θ<br />
∂θ + e φ ∂<br />
sin θ ∂φ<br />
) (ikf eikr<br />
r e r + eikr<br />
r 2 (u − e r) f ≈ ikAf eikr<br />
r e r = ik ϕ out (r) e r (10.3)<br />
, J = )<br />
(ψ<br />
m Im ∗ (r)∇ψ(r) r → ∞ <br />
J → m Im [(ϕ ∗ in + ϕ ∗ out<br />
= k m<br />
)<br />
)]<br />
ik<br />
(ϕ in e z + ϕ out e r<br />
(<br />
)<br />
|ϕ in | 2 e z + |ϕ out | 2 e r + Re (ϕ ∗ inϕ out ) (e r + e z )<br />
(10.4)<br />
1 k/m z , <br />
, , N in <br />
N in = k m |ϕ in| 2 = k m |A|2<br />
2 k/m r <br />
dΩ r 2 dΩ , <br />
k<br />
m |ϕ out| 2 r 2 dΩ = k m |A|2 |f(θ, φ)| 2 dΩ<br />
dΩ dN , (10.1) <br />
2 , <br />
dσ<br />
dΩ = |f(θ, φ)|2 (10.5)<br />
r → ∞ f(θ, φ) , <br />
(10.4) 3 , <br />
e −ik·r kr→∞<br />
−−−−−→ 2πi (<br />
δ(Ω r − Ω k )e −ikr − δ(Ω r + Ω k )e ikr) + O(1/(kr) 2 ) (10.6)<br />
kr<br />
Ω r , Ω k r , k <br />
δ(Ω − Ω ′ ) = δ(θ − θ′ ) δ(φ − φ ′ )<br />
sin θ<br />
, Ω F (Ω) = F (θ, φ) <br />
∫<br />
∫ π ∫ 2π<br />
dΩ ′ δ(Ω − Ω ′ )F (Ω ′ ) = dθ ′ dφ ′ δ(θ − θ ′ ) δ(φ − φ ′ )F (θ ′ , φ ′ ) = F (Ω)<br />
k z <br />
∫<br />
I = dΩ r e −ik·r F (Ω r ) =<br />
0<br />
=<br />
0<br />
∫ 2π<br />
0<br />
∫ 2π<br />
0<br />
∫ π<br />
dφ r dθ r sin θ r e −ikr cos θ r<br />
F (θ r , φ r )<br />
0<br />
∫ 1<br />
dφ r dt e −ikrt F (θ r , φ r )<br />
−1
10 177<br />
t = cos θ r t <br />
I =<br />
∫ 2π<br />
0<br />
dφ r<br />
( i<br />
kr<br />
[<br />
e −ikrt F (θ r , φ r ) ] t=1<br />
t=−1 − i<br />
kr<br />
∫ 1<br />
−1<br />
dt e −ikrt ∂ )<br />
∂t F (θ r, φ r )<br />
t = 1 , θ r = 0 r k , t = −1 r k <br />
<br />
I = i<br />
kr<br />
= 2πi<br />
kr<br />
∫ 2π<br />
, <br />
0<br />
)<br />
dφ r<br />
(e −ikr F (Ω k ) − e ikr F (−Ω k )<br />
(<br />
e −ikr F (Ω k ) − e ikr F (−Ω k )<br />
)<br />
− i<br />
kr<br />
I = 2πi (<br />
)<br />
e −ikr F (Ω k ) − e ikr F (−Ω k )<br />
kr<br />
+ 1 ∫ 2π<br />
(kr) 2 dφ r<br />
[e −ikrt ∂ ] t=1<br />
∂t F (θ r, φ r )<br />
0<br />
t=−1<br />
− i<br />
kr<br />
∫ 2π<br />
0<br />
∫ 2π<br />
0<br />
∫ 1<br />
dφ r dt e −ikrt ∂ ∂t F (θ r, φ r )<br />
−1<br />
∫ 1<br />
dφ r dt e −ikrt ∂ ∂t F (θ r, φ r )<br />
−1<br />
− 1 ∫ 2π ∫ 1<br />
−ikrt ∂2<br />
(kr) 2 dφ r dt e<br />
∂t 2 F (θ r, φ r )<br />
kr → ∞ 2, 3 1 1/r <br />
∫<br />
I = dΩ r e −ik·r F (Ω r ) = 2πi (<br />
)<br />
e −ikr F (Ω k ) − e ikr F (−Ω k ) + O(1/(kr) 2 )<br />
kr<br />
(10.6) <br />
(10.4) 3 <br />
J inter (r) = k m Re (ϕ∗ inϕ out ) (e r + e z ) = k (<br />
)<br />
mr |A|2 Re e ikr−ikz f(θ, φ) (e r + e z )<br />
k z kz = k·r (10.6) <br />
e −ikz r→∞<br />
−−−−→ 2πi<br />
kr<br />
0<br />
−1<br />
(<br />
)<br />
e −ikr δ(Ω − Ω z ) − e ikr δ(Ω + Ω z )<br />
, Ω r , Ω z k , , z ( Re(if) = − Imf )<br />
J inter (r) = − 2π [ (<br />
) ]<br />
mr 2 Im f(θ, φ) δ(Ω − Ω z ) − e 2ikr δ(Ω + Ω z ) (e r + e z )<br />
Ω = − Ω z r z e r = − e z δ(Ω + Ω z ) 0 <br />
Ω = Ω z r z θ = φ = 0 , e r = e z <br />
J inter (r) = − 4π<br />
mr 2 Imf(0) δ(Ω − Ω z) e z<br />
( θ = 0 ) θ = π <br />
, <br />
J inter <br />
, ∂ρ/∂t + ∇·J = 0 ∇·J = 0 , r <br />
, <br />
∫<br />
4πr 2 dΩ J ·e r = 0
10 178<br />
r → ∞ J (10.4) <br />
∫<br />
k<br />
dΩ |ϕ in | 2 e z ·e r = k ∫<br />
m<br />
m |A|2 dΩ cos θ = 0<br />
∫<br />
k<br />
dΩ |ϕ out | 2 e r ·e r = k |A| 2 ∫<br />
m<br />
m r 2 dΩ |f(θ, φ)| 2 = k m<br />
∫<br />
dΩ J inter (r)·e r = − 4π<br />
mr 2 |A|2 Imf(0)<br />
<br />
∫<br />
∫<br />
σ tot = dΩ |f(θ, φ)| 2 =<br />
dΩ dσ<br />
dΩ<br />
<br />
∫<br />
dΩ J ·e r = k |A| 2 (<br />
m r 2 σ tot − 4π )<br />
k Im f(0) = 0<br />
|A| 2<br />
r 2<br />
σ tot<br />
<br />
σ tot = 4π k<br />
Im f(0) (10.7)<br />
<br />
10.2 <br />
V (r) 1 , f(θ, φ) <br />
<br />
<br />
k =<br />
√<br />
2mE<br />
2 , U(r) = 2m<br />
2 V (r)<br />
(<br />
∇ 2 + k 2) ψ(r) = U(r)ψ(r) (10.8)<br />
<br />
(<br />
∇ 2 + k 2) G(r) = δ(r) (10.9)<br />
G(r) (10.8) <br />
∫<br />
ψ(r) = ϕ(r) + d 3 r ′ G(r − r ′ )U(r ′ )ψ(r ′ ) , ( ∇ 2 + k 2) ϕ(r) = 0 (10.10)<br />
<br />
(<br />
∇ 2 + k 2) ψ(r) = ( ∇ 2 + k 2) ∫<br />
ϕ(r) + d 3 r ′ ( ∇ 2 + k 2) G(r − r ′ )U(r ′ )ψ(r ′ )<br />
∫<br />
= d 3 r ′ δ(r − r ′ ) U(r ′ )ψ(r ′ ) = U(r)ψ(r)<br />
(10.10) (10.8) (10.10) ϕ(r) G(r) , (10.2) <br />
, (10.8) (10.10) <br />
<br />
∇ 2 e±ikr<br />
r<br />
= e ±ikr ∇ 2 1 (<br />
r + 2 ∇ 1 )<br />
·∇e ±ikr + 1 r<br />
r ∇2 e ±ikr
10 179<br />
<br />
∇ 2 1 r = − 4π δ(r) , ∇1 r = − r r 3 , ∇e±ikr = ± ikr<br />
(<br />
r e±ikr , ∇ 2 e ±ikr = − k 2 ± 2ik )<br />
e ±ikr<br />
r<br />
<br />
<br />
∇ 2 e±ikr<br />
r<br />
= − 4π δ(r) − k 2 e±ikr<br />
r<br />
G (±) (r) = − 1 e ±ikr<br />
4π r<br />
(10.9) (10.10) <br />
ψ(r) = ϕ(r) − 1 ∫<br />
d 3 r ′ exp (± ik|r − r′ |)<br />
4π<br />
|r − r ′ |<br />
r r ′ α <br />
√<br />
|r − r ′ | = r<br />
1 + r′2<br />
r 2 − 2r′<br />
r→∞<br />
cos α −−−−→ r<br />
r<br />
U(r ′ )ψ(r ′ ) (10.11)<br />
(1 − r′<br />
r cos α + · · · )<br />
= r − e r ·r ′ + O (r ′ /r)<br />
<br />
exp (± ik|r − r ′ |)<br />
|r − r ′ |<br />
= exp (± ikr ∓ ik f ·r ′ )<br />
r<br />
+ O (r ′ /r) , k f = ke r<br />
<br />
ψ(r) −−−−→ r→∞<br />
ϕ(r) − 1 e ±ikr ∫<br />
d 3 r ′ e ∓ik f ·r ′ U(r ′ )ψ(r ′ )<br />
4π r<br />
G(r) G (+) (r) , ( ∇ 2 + k 2) ϕ(r) = 0 ϕ(r) ϕ(r) = e ikz <br />
(10.2) , <br />
f(θ, φ) = − 1 ∫<br />
d 3 r ′ e −ik f ·r ′ U(r ′ )ψ(r ′ ) (10.12)<br />
4π<br />
k f = ke r (θ, φ) , , <br />
<br />
(10.12) , ψ(r) f(θ, φ) <br />
(10.11) <br />
∫<br />
ψ(r) = ϕ(r) + d 3 r ′ G (+) (r − r ′ )U(r ′ )ψ(r ′ )<br />
∫<br />
( ∫<br />
)<br />
= ϕ(r) + d 3 r ′ G (+) (r − r ′ )U(r ′ ) ϕ(r ′ ) + d 3 r ′′ G (+) (r ′ − r ′′ )U(r ′′ )ψ(r ′′ )<br />
∫<br />
= ϕ(r) + d 3 r ′ G (+) (r − r ′ )U(r ′ )ϕ(r ′ )<br />
∫<br />
+ d 3 r ′ d 3 r ′′ G (+) (r − r ′ )U(r ′ )G (+) (r ′ − r ′′ )U(r ′′ )ϕ(r ′′ ) + · · · (10.13)<br />
U , <br />
(10.12) <br />
f(θ, φ) = − 1 ∫<br />
d 3 r ′ e −ik f ·r ′ U(r ′ )ϕ(r ′ )<br />
4π<br />
− 1 ∫<br />
d 3 r ′ d 3 r ′′ e −ik f ·r ′ U(r ′ )G (+) (r ′ − r ′′ )U(r ′′ )ϕ(r ′′ ) + · · · (10.14)<br />
4π
10 180<br />
2 <br />
f(θ, φ) ≈ − 1 ∫<br />
d 3 r ′ e −ik f ·r ′ U(r ′ )ϕ(r ′ ) = −<br />
m ∫<br />
4π<br />
2π 2 d 3 r ′ e −ik f ·r ′ V (r ′ )ϕ(r ′ ) (10.15)<br />
k i = ke z k i ϕ(r) = e ikz =<br />
e ik i·r <br />
f(θ, φ) ≈ −<br />
m<br />
∫<br />
2π 2 V(q) , V(q) = d 3 r e −iq·r V (r) , q = k f − k i (10.16)<br />
, V(q) <br />
<br />
dσ<br />
( m<br />
) 2<br />
dΩ = |f(θ, φ)|2 = |V(q)|<br />
2<br />
2π 2<br />
q , <br />
<br />
q<br />
k i =ke z<br />
k f =ke r<br />
θ<br />
<br />
q = 2k sin θ 2<br />
( k ≈ 0 ) q ≈ 0 <br />
∫<br />
V(q) ≈ V(0) = d 3 r V (r)<br />
f(θ, φ) , ( k → ∞ ) θ ≠ 0 q<br />
e −iq·r r V(q) ≈ 0 f(θ, φ)<br />
θ ≈ 0 , V(0) f(0) , <br />
(10.7) , f(θ, φ) V 1 , |f(θ, φ)| 2 <br />
V 2 , (10.14) 2 Imf(0) <br />
<br />
<br />
V(q) = 2π<br />
∫ ∞<br />
0<br />
dr r 2 V (r)<br />
∫ 1<br />
−1dt e −iqrt = 4π q<br />
∫ ∞<br />
0<br />
dr rV (r) sin(qr) (10.17)<br />
q , φ , <br />
q E = 2 k 2 /(2m) θ , E, θ <br />
q σ tot <br />
∫<br />
( m<br />
) 2<br />
∫ π<br />
σ tot = dΩ |f(θ, φ)| 2 = 2π<br />
2π 2 dθ sin θ |V(q)| 2<br />
q = 2k sin(θ/2) 0 ≤ q ≤ 2k , qdq = k 2 sin θ dθ <br />
( k → ∞ ) <br />
E <br />
0<br />
∫ 2k<br />
σ tot =<br />
m2<br />
2π 4 k 2 dq q |V(q)| 2 (10.18)<br />
∫ ∞<br />
σ tot →<br />
m2<br />
2π 4 k 2 dq q |V(q)| 2 =<br />
m<br />
4π 2 E<br />
0<br />
0<br />
∫ ∞<br />
0<br />
dq q |V(q)| 2
10 181<br />
(10.12) ψ(r) ϕ(r) (10.13)<br />
<br />
∫<br />
|ϕ(r)| = 1 ≫<br />
∣ d 3 r ′ G (+) (r − r ′ )U(r ′ )ϕ(r ′ )<br />
∣<br />
r = 0 <br />
∫<br />
∣ d 3 r G (+) (r)U(r)ϕ(r)<br />
∣ = m ∣∫<br />
∣∣∣<br />
2π 2 d 3 r eik(r+z)<br />
V (r)<br />
r ∣ ≪ 1 (10.19)<br />
(10.6) k → ∞ <br />
, <br />
m<br />
2 k ∣<br />
e ik(r+z) ≈ 2πi (<br />
)<br />
δ(Ω + Ω z ) − e 2ikr δ(Ω − Ω z )<br />
kr<br />
∫ ∞<br />
0<br />
∫<br />
dr<br />
(<br />
)<br />
dΩ δ(Ω + Ω z ) − e 2ikr δ(Ω − Ω z )<br />
, <br />
V (r)<br />
∣ ≪ 1<br />
<br />
V (r) <br />
(10.17) <br />
V (r) =<br />
{<br />
V0 , r < a<br />
0 , r > a<br />
(10.20)<br />
V(q) = 4πV 0<br />
q<br />
∫ a<br />
0<br />
dr r sin(qr) = 4πV 0 a 3 v(aq) ,<br />
v(x) ≡<br />
sin x − x cos x<br />
x 3 (10.21)<br />
, <br />
(<br />
dσ<br />
dΩ = 2mV0 a 2 ) 2 a2<br />
2 v(aq) 2<br />
0.1<br />
v(x) 2 x 4 <br />
v(x) 2 ≈ 0 , <br />
v(x) 2<br />
aq = 2ak sin θ 2 4 , sin θ 2 2<br />
ak<br />
, k <br />
v(x) = 1 )<br />
(1 − x2<br />
3 10 + · · ·<br />
0 2 4 6<br />
<br />
( )<br />
dσ dσ<br />
(1<br />
dΩ = − 4 dΩ<br />
0<br />
5 a2 k 2 sin 2 θ )<br />
2 + · · · ,<br />
( ) ( dσ<br />
= a 2 2mV0 a 2 ) 2<br />
dΩ<br />
0<br />
3 2 (10.22)<br />
( θ = 0 ) , k → 0 <br />
θ k , θ ≠ 0
10 182<br />
(10.18) (10.21) <br />
σ tot = 8π ( mV0 a 2 ) 2 ∫ 2k<br />
k 2 2 a 2 dq q v(aq) 2 = 8π ( mV0 a 2 ) 2<br />
0<br />
k 2 2 S(2ak) (10.23)<br />
<br />
S(x) =<br />
∫ x<br />
0<br />
dy y v(y) 2 =<br />
∫ x<br />
0<br />
dy<br />
(sin y − y cos y)2<br />
y 5 = 1 [<br />
− 1 sin 2y<br />
+<br />
4 y2 y 3<br />
= 1 4<br />
− sin2 y<br />
y 4 ] x<br />
0<br />
(<br />
1 − 1 )<br />
sin 2x<br />
+<br />
x2 x 3 − sin2 x<br />
x 4<br />
S ′ (x) = xv(x) 2 , S ′′ (x) = v(x) 2 + 2xv(x)v ′ (x) <br />
S(x) = S(0) + S ′ (0)x + S′′ (0)<br />
x 2 + · · · = x2<br />
2<br />
18 + · · ·<br />
ak ≪ 1 <br />
σ tot = 4πa 2 ( 2mV0 a 2<br />
3 2<br />
) 2 ( ) dσ<br />
= 4π<br />
dΩ<br />
0<br />
(10.24)<br />
, ak ≫ 1 <br />
<br />
σ tot = 2π<br />
k 2 ( mV0 a 2<br />
2 ) 2<br />
(10.19) <br />
<br />
∫<br />
d 3 r eik(r+z)<br />
r<br />
∫ a ∫ 1<br />
V (r) = 2πV 0 dr re ikr dt e ikrt = πV (<br />
0<br />
k 2 1 + 2iak − e 2iak)<br />
e 2iak = 1 + 2iak − 2a 2 k 2 + · · · <br />
0<br />
−1<br />
m<br />
∣ ( ∣∣V0<br />
2 2 k 2 1 + 2iak − e 2iak)∣ ∣ ≪ 1 (10.25)<br />
ma 2 |V 0 |<br />
2 ≪ 1<br />
3 , 121 <br />
<br />
√<br />
2m|V0 |<br />
a<br />
2 > π 2 , ∴ ma 2 |V 0 |<br />
2<br />
> π2<br />
8<br />
, , <br />
(10.25) <br />
ma|V 0 |<br />
2 k<br />
≪ 1<br />
, k → ∞
10 183<br />
10.3 <br />
, <br />
, , <br />
, (10.2) <br />
V (r) , H, L 2 , L z ψ(r) <br />
Y l ml (θ, φ) <br />
ψ(r) = R l (r) Y l ml (θ, φ)<br />
<br />
)<br />
(− 2<br />
2m ∇2 + V (r) ψ(r) = E ψ(r) (10.26)<br />
(6.3)<br />
<br />
<br />
( 1<br />
r<br />
d 2<br />
)<br />
l(l + 1)<br />
r −<br />
dr2 r 2 − U(r) + k 2 R l (r) = 0 (10.27)<br />
U(r) = 2m<br />
2 V (r) ,<br />
R l (r) = χ l(r)<br />
r<br />
k = √<br />
2mE<br />
2<br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − U(r) + k 2 χ l (r) = 0 (10.28)<br />
<br />
V (r) = 0 <br />
( 1<br />
r<br />
d 2<br />
)<br />
l(l + 1)<br />
r −<br />
dr2 r 2 + k 2 R l (r) = 0<br />
15.4 ( 259 ) , j l (kr) <br />
j l (kr) Y l ml (θ, φ) , l = 0, 1, 2, · · · , m l = −l, − l + 1, · · · , l<br />
<br />
(<br />
∇ 2 + k 2) ψ(r) = 0 (10.29)<br />
, A lml<br />
<br />
∞∑ l∑<br />
ψ(r) = A lml j l (kr) Y l ml (θ, φ)<br />
l=0 m l =−l<br />
(10.29) , , (10.29) e ikz<br />
<br />
∞∑<br />
∞∑<br />
e ikz = e ikr cos θ = A l j l (kr) Y l0 (θ, φ) = C l j l (kr) P l (cos θ)<br />
l=0<br />
l=0
10 184<br />
e ikz φ m l = 0 C l <br />
<br />
(15.46) <br />
∞∑<br />
n=0<br />
i n<br />
n! (kr cos θ)n =<br />
j l (ρ) =<br />
∞∑<br />
C l j l (kr) P l (cos θ) (10.30)<br />
l=0<br />
ρ l (<br />
ρ 2 )<br />
1 −<br />
(2l + 1)!! 2(2l + 3) + · · ·<br />
, j l (kr) (kr) n l ≤ n , (5.31) <br />
d l<br />
P l (x) = 1<br />
2 l l! dx l (x2 − 1) l =<br />
(2l)! (<br />
2 l (l!) 2 x l −<br />
)<br />
l(l − 1)<br />
2(2l − 1) xl−2 + · · ·<br />
, P l (cos θ) (cos θ) n l ≥ n , (kr cos θ) n <br />
l = n , (10.30) <br />
(2n + 1)!! <br />
n! = C 1 (2n)!<br />
n<br />
(2n + 1)!! 2 n (n!) 2<br />
(2n + 1)!! = (2n + 1)(2n − 1)(2n − 3) · · · 5 · 3 =<br />
C n = i n (2n + 1) <br />
i n<br />
e ikz =<br />
(2n + 1)! (2n + 1)!<br />
=<br />
2n(2n − 2) · · · 4 · 2 2 n n!<br />
∞∑<br />
i l (2l + 1) j l (kr) P l (cos θ) (10.31)<br />
l=0<br />
( 263 (15.50) )r → ∞ (15.49) <br />
<br />
e ikz<br />
r→∞<br />
−−−−→ 1<br />
2ikr<br />
∞∑ (<br />
(2l + 1) e ikr + (−1) l+1 e −ikr) P l (cos θ) (10.32)<br />
l=0<br />
(10.2) (10.27) r = 0 (6.7) <br />
R l (r) = χ l(r)<br />
r<br />
= C l r l , C l = <br />
r → ∞ (10.27) R l (r) C l <br />
U(r) 1/r 2 0 ( , U ∝ 1/r <br />
), r , <br />
( 1 d 2<br />
)<br />
l(l + 1)<br />
r −<br />
r dr2 r 2 + k 2 R l (r) = 0<br />
R l (r) <br />
)<br />
R l (r) = C l<br />
(a l j l (kr) + b l n l (kr)<br />
a l , b l <br />
)<br />
R l (r) = A l<br />
(cos δ l j l (kr) − sin δ l n l (kr)<br />
(10.33)
10 185<br />
A l δ l R l r <br />
, n l (kr) , δ l <br />
k (15.49) r → ∞ <br />
R l (r) = A (<br />
l<br />
kr sin kr − lπ )<br />
2 + δ l<br />
(10.34)<br />
, (10.33) δ l = 0 , r → ∞ <br />
δ l δ l l ( phase shift ) <br />
R l (r)Y l ml (θ, φ) l, m l , <br />
(10.26) z , <br />
z φ , m l = 0 <br />
<br />
ψ(r) =<br />
∞∑<br />
R l (r)P l (cos θ) (10.35)<br />
l=0<br />
, R l (r)P l (cos θ) , <br />
(10.35) (10.2) r → ∞ <br />
∞∑<br />
(<br />
A l<br />
ψ(r) =<br />
kr sin kr − lπ )<br />
2 + δ l P l (cos θ)<br />
l=0<br />
= eikr<br />
2ikr<br />
∞∑<br />
l=0<br />
A l (−i) l e iδ l<br />
P l (cos θ) − e−ikr<br />
2ikr<br />
∞∑<br />
A l i l e −iδ l<br />
P l (cos θ) (10.36)<br />
, (10.2) (10.32) <br />
) ( ∞<br />
)<br />
A<br />
(e ikz + f(θ) eikr<br />
= eikr<br />
r 2ikr A ∑<br />
(2l + 1)P l (cos θ) + 2ikf(θ)<br />
+ e−ikr<br />
l=0<br />
l=0<br />
∞<br />
2ikr A ∑<br />
(2l + 1)(−1) l+1 P l (cos θ) (10.37)<br />
(10.36) (10.37) , e ikr e −ikr <br />
<br />
l=0<br />
l=0<br />
∞∑<br />
∞∑<br />
A l (−i) l e iδ l<br />
P l (cos θ) = A (2l + 1)P l (cos θ) + 2ikf(θ)A<br />
l=0<br />
l=0<br />
∞∑<br />
∞∑<br />
A l i l e −iδ l<br />
P l (cos θ) = A (2l + 1)(−1) l P l (cos θ)<br />
l=0<br />
P l (cos θ) 2 <br />
l=0<br />
A l = i l e iδ l<br />
(2l + 1)A (10.38)<br />
1 <br />
f(θ) = 1 ∞∑ ( )<br />
(2l + 1) e 2iδ l<br />
− 1 P l (cos θ) = 1 ∞∑<br />
(2l + 1) e iδ l<br />
sin δ l P l (cos θ) (10.39)<br />
2ik<br />
k<br />
δ l , f(θ) <br />
l=0<br />
f l (k) = e2iδ l(k) − 1<br />
2ik<br />
= eiδ l<br />
sin δ l<br />
k<br />
= 1 k<br />
1<br />
cot δ l − i<br />
(10.40)
10 186<br />
<br />
S l (k) = e 2iδl(k) = cot δ l + i<br />
(10.41)<br />
cot δ l − i<br />
S l S ( ) <br />
<br />
dσ<br />
dΩ = |f(θ)|2 = 1 ∑<br />
k 2<br />
l,l ′ (2l + 1)(2l ′ + 1) e iδ l−iδ l′<br />
sin δ l sin δ l ′ P l (cos θ)P l ′(cos θ)<br />
, , σ tot t = cos θ <br />
σ tot = 2π<br />
k 2 ∑<br />
l,l ′ (2l + 1)(2l ′ + 1) e iδ l−iδ l′<br />
sin δ l sin δ l ′<br />
∫ 1<br />
−1<br />
dt P l (t)P l ′(t)<br />
= 2π ∑<br />
k 2 (2l + 1)(2l ′ + 1) e iδ l−iδ l′<br />
2 δ ll ′<br />
sin δ l sin δ l ′<br />
2l + 1 = 4π<br />
k 2<br />
l,l ′<br />
l σ l <br />
∞ ∑<br />
l=0<br />
(2l + 1) sin 2 δ l<br />
σ l = 4π<br />
k 2 (2l + 1) sin2 δ l ≤ 4π (2l + 1) (10.42)<br />
k2 σ l , δ l n δ l = (n + 1/2)π <br />
P l (cos 0) = P l (1) = 1 <br />
f(0) = 1 ∞∑<br />
(2l + 1) e iδ l<br />
sin δ l , ∴ Imf(0) = 1 ∞∑<br />
(2l + 1) sin 2 δ l = k<br />
k<br />
k<br />
4π σ tot<br />
l=0<br />
<br />
(10.38) (10.36) <br />
ψ(r) −−−−→<br />
r→∞ A<br />
2ikr<br />
l=0<br />
∞∑ (<br />
(2l + 1) e 2iδ l<br />
e ikr + (−1) l+1 e −ikr) P l (cos θ)<br />
l=0<br />
e ikz (10.32) , <br />
, <br />
<br />
( )<br />
e 2iδ l<br />
e ikr = e ikr + e 2iδ l<br />
− 1 e ikr<br />
, (10.32) e ikr , <br />
, (10.39) e 2iδ l<br />
− 1 <br />
(10.34) l r → ∞ <br />
R l (r) = − il A l e −iδ l<br />
2ikr<br />
(<br />
e −ikr − (−1) l S l (k) e ikr) (10.43)<br />
<br />
R l (r) = (−i)l e iδ l<br />
A<br />
(<br />
l<br />
e ikr − (−1) l S −1<br />
l<br />
(k)e −ikr)<br />
2ikr<br />
E κ = √ − 2mE/ 2 k = iκ <br />
R l (r) = (−i)l e iδ l<br />
A<br />
(<br />
l<br />
e −κr − (−1) l S −1<br />
l<br />
(iκ)e κr)<br />
2ikr<br />
, r → ∞ S −1<br />
l<br />
(iκ) = 0 <br />
, E l 1 <br />
, E
10 187<br />
10.4 <br />
V (r) χ l (r) = rR l (r) (10.28)<br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − U(r) + k 2 χ l (r) = 0 (10.44)<br />
, r = 0 r → ∞ (10.34)<br />
χ l (r) r→0<br />
−−−−→ C l r l+1 ,<br />
(<br />
χ l (r) −−−−→ r→∞<br />
sin kr − lπ )<br />
2 + δ l<br />
, sin 1 <br />
, Ṽ (r) ˜χ l(r) :<br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − Ũ(r) + k2 ˜χ l (r) = 0 (10.45)<br />
<br />
˜χ l (r) r→0<br />
−−−−→ ˜C l r l+1 ,<br />
χ l × (10.45) − ˜χ l × (10.44) <br />
<br />
<br />
<br />
˜χ l (r) −−−−→ r→∞<br />
sin<br />
(kr − lπ )<br />
2 + ˜δ l<br />
dW<br />
dr = (Ũ(r) − U(r)<br />
)<br />
˜χ l χ l , W (r) = χ l<br />
d˜χ l<br />
dr − dχ l<br />
dr ˜χ l<br />
W (∞) − W (0) =<br />
W (0) = 0 ,<br />
sin<br />
(δ l − ˜δ<br />
)<br />
l = 2m<br />
2 k<br />
∫ ∞<br />
0<br />
)<br />
dr<br />
(Ũ(r) − U(r) ˜χ l χ l<br />
W (∞) = k sin<br />
(δ l − ˜δ<br />
)<br />
l<br />
∫ ∞<br />
, Ṽ (r) = 0 ˜δ l = 0 , ˜χ l (r) = kr j l (kr) <br />
sin δ l = − 2m<br />
2<br />
0<br />
∫ ∞<br />
(10.44) χ l (r) , δ l <br />
∆V (r) = V (r) − Ṽ (r) (10.46) <br />
δ l − ˜δ l ≈ − 2m<br />
2 k<br />
0<br />
)<br />
dr<br />
(Ṽ (r) − V (r) ˜χ l χ l (10.46)<br />
dr rV (r) j l (kr) χ l (r) (10.47)<br />
∫ ∞<br />
0<br />
dr ∆V (r) (˜χ l (r)) 2<br />
, , V (r) = 0 <br />
V (r) , V (r) < 0 δ l > 0 , <br />
V (r) > 0 δ l < 0 , V (r) = 0<br />
r → ∞ χ l (r)<br />
(<br />
χ l (r) = sin kr − lπ )<br />
2 + δ l<br />
δ l > 0 , δ l < 0 <br />
, δ l ×π , V (r) = 0 δ l = 0 , δ l
10 188<br />
δ l<br />
sin(kr − lπ/2 + δ l )<br />
sin(kr − lπ/2)<br />
kr<br />
<br />
V (r) <br />
∣ |V (r)| ≪<br />
∣ E − 2 l(l + 1) ∣∣∣<br />
2mr 2 (10.48)<br />
, (10.44) χ l χ l , , kr j l (kr) δ l ≈ 0 <br />
, (10.47) χ l kr j l (kr) <br />
l=0<br />
sin δ l ≈ − 2mk<br />
2<br />
∫ ∞<br />
0<br />
l=0<br />
dr r 2 V (r) j 2 l (kr)<br />
, (10.39) δ l ≈ 0 <br />
f(θ) ≈ 1 ∞∑<br />
(2l + 1) sin δ l P l (cos θ) ≈ − 2m ∑<br />
∞<br />
k<br />
2 (2l + 1)P l (cos θ)<br />
∫ ∞<br />
0<br />
dr r 2 V (r)j 2 l (kr) (10.49)<br />
(10.16) (10.48) , E <br />
l , V (r) <br />
(10.20) <br />
sin δ l ≈ − 2mV 0k<br />
2<br />
ak ≪ 1 <br />
<br />
<br />
j l (x) x→0<br />
−−−−→<br />
f(θ) ≈ − 2mV 0a 3<br />
2<br />
ak ≪ 1 l = 0 <br />
<br />
∫ a<br />
0<br />
dr r 2 j 2 l (kr) = − 2mV 0<br />
2 k 2<br />
(<br />
xl<br />
1 −<br />
(2l + 1)!!<br />
∫ ak<br />
0<br />
x 2 )<br />
2(2l + 3) + · · ·<br />
sin δ l ≈ − 2mV 0a 2<br />
2 (ak) 2l+1<br />
[(2l + 1)!!] 2 (2l + 3)<br />
∞ ∑<br />
l=0<br />
2l + 1<br />
[(2l + 1)!!] 2 (2l + 3) (ak)2l P l (cos θ)<br />
f(θ) ≈ − 2mV 0a 3<br />
3 2<br />
(<br />
dσ<br />
dΩ = 2mV0 a 2 ) 2 ∫<br />
(<br />
3 2 , σ tot = dΩ |f(θ)| 2 ≈ 4πa 2 2mV0 a 2 ) 2<br />
3 2<br />
(10.24) l = 0 <br />
10.1 (15.50)<br />
e ik·r = 4π<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
(10.16) (10.49) <br />
i l j l (kr)Y ∗<br />
lm(Ω k )Y lm (Ω r )<br />
dx x 2 j 2 l (x) (10.50)<br />
10.2<br />
(10.50) (ak) 2 (10.22)
10 189<br />
10.5 <br />
V (r) <br />
V (r) =<br />
{<br />
− V0 , r < a<br />
0 , r > a , V 0 > 0<br />
r < a (10.27) <br />
( 1<br />
r<br />
d 2<br />
)<br />
l(l + 1)<br />
r −<br />
dr2 r 2 + ρ2 1<br />
a 2 R l (r) = 0 ,<br />
ρ 1 ≡ a<br />
√<br />
k 2 + 2m<br />
2 V 0<br />
, <br />
R l (r) = C l j l (ρ 1 r/a) (10.51)<br />
, r > a <br />
)<br />
R l (r) = A l<br />
(cos δ l j l (ρr/a) − sin δ l n l (ρr/a) , ρ ≡ ak (10.52)<br />
r = a <br />
)<br />
(<br />
)<br />
C l j l (ρ 1 ) = A l<br />
(cos δ l j l (ρ) − sin δ l n l (ρ) , C l ρ 1 j l(ρ ′ 1 ) = A l ρ cos δ l j l(ρ) ′ − sin δ l n ′ l(ρ)<br />
<br />
tan δ l = (γ l − l − 1) j l (ρ) − ρ j<br />
l ′(ρ)<br />
(γ l − l − 1) n l (ρ) − ρ n ′ l (ρ) , γ l(ρ 1 ) = ρ 1j<br />
l ′(ρ 1)<br />
+ l + 1 (10.53)<br />
j l (ρ 1 )<br />
<br />
<br />
j ′ l(x) = l x j l(x) − j l+1 (x) ,<br />
n ′ l(x) = l x n l(x) − n l+1 (x)<br />
tan δ l = (γ l − 2l − 1)j l (ρ) + ρ j l+1 (ρ)<br />
(γ l − 2l − 1)n l (ρ) + ρ n l+1 (ρ) , γ l = 2l + 1 − ρ 1j l+1 (ρ 1 )<br />
= ρ 1j l−1 (ρ 1 )<br />
j l (ρ 1 ) j l (ρ 1 )<br />
(10.54)<br />
<br />
<br />
j −1 (x) ≡ − n 0 (x) = cos x<br />
x<br />
<br />
( ρ = ak ≪ 1 ) (15.46), (15.47) <br />
j l (ρ) =<br />
ρ l (<br />
1 −<br />
(2l + 1)!!<br />
ρ 2 )<br />
2(2l + 3) + · · · , n l (ρ) = −<br />
(2l + 1)!!<br />
2l + 1<br />
(<br />
1<br />
ρ l+1 1 +<br />
ρ 2 )<br />
2(2l − 1) + · · ·<br />
<br />
ρ j l+1 (ρ)<br />
j l (ρ)<br />
ρ n l+1 (ρ)<br />
n l (ρ)<br />
(<br />
= ρ2<br />
ρ 2<br />
)<br />
1 +<br />
2l + 3 (2l + 3)(2l + 5) + · · ·<br />
= 2l + 1 − ρ2<br />
2l − 1 + · · ·<br />
j l (ρ)<br />
n l (ρ) = − 2l + 1<br />
[(2l + 1)!!] 2 ρ2l+1 (<br />
1 −<br />
)<br />
2l + 1<br />
(2l + 3)(2l − 1) ρ2 + · · ·
10 190<br />
<br />
tan δ l ≈ 2l + 1 − γ l(ρ 1 ) − d l ρ 2<br />
γ l (ρ 1 ) − ρ 2 /(2l − 1)<br />
2l + 1<br />
[(2l + 1)!!] 2 ρ2l+1 (10.55)<br />
<br />
<br />
<br />
<br />
ρ 1 =<br />
d l = 1 (<br />
2l + 3<br />
1 + 2l + 1<br />
2l − 1<br />
(<br />
) )<br />
2l + 1 − γ l (ρ 1 )<br />
√ √v 0 2 + ρ2 = v 0 + ρ2<br />
2mV0<br />
+ · · · , v 0 = a<br />
2v 0 2<br />
γ l (ρ 1 ) = γ l (v 0 ) + γ′ l (v 0)<br />
2v 0<br />
ρ 2 + · · ·<br />
tan δ l ≈ 2l + 1 − γ l(v 0 ) + O(ρ 2 )<br />
γ l (v 0 ) − c l ρ 2 2l + 1<br />
[(2l + 1)!!] 2 ρ2l+1 , c l = 1<br />
2l − 1 − γ′ l (v 0)<br />
2v 0<br />
(10.56)<br />
<br />
γ l (v 0 ) ≈ 0 2l + 1 − γ l (v 0 ) ≈ 0<br />
<br />
tan δ l ≈ 2l + 1 − γ l(v 0 )<br />
γ l (v 0 )<br />
<br />
f l = 1 k<br />
2l + 1<br />
[(2l + 1)!!] 2 ρ2l+1 =<br />
2l + 1 j l+1 (v 0 )<br />
[ (2l + 1)!! ] 2 j l−1 (v 0 ) (ka)2l+1<br />
k→0<br />
−−−−→ 0<br />
1<br />
cot δ l − i ≈ tan δ l 2l + 1 j l+1 (v 0 )<br />
≈<br />
k [ (2l + 1)!! ] 2 j l−1 (v 0 ) (ka)2l a (10.57)<br />
l ≠ 0 f l ≈ 0 , l = 0 s <br />
f 0 ≈ a j (<br />
1(v 0 )<br />
j −1 (v 0 ) = − a 1 − tan v )<br />
0<br />
v 0<br />
<br />
(<br />
dσ<br />
dΩ ≈ |f 0| 2 = a 2 1 − tan v ) 2 (<br />
0<br />
, σ tot ≈ 4πa 2 1 − tan v ) 2<br />
0<br />
(10.58)<br />
v 0 v 0<br />
, , <br />
l = 0 , <br />
<br />
l = 0 <br />
dσ/dΩ ≈ 0 <br />
2l + 1 − γ l (v 0 ) = v 0j l+1 (v 0 )<br />
j l (v 0 )<br />
≈ 0<br />
tan δ 0 ≈ d 0 (ka) 3 , ∴ f 0 ≈ d 0 a 3 k 2<br />
10.3<br />
(10.58) k → 0 (10.24)
10 191<br />
<br />
(10.55) ρ → 0 ρ ≪ l l <br />
γ l (ρ 1 ) = ρ (<br />
1j l−1 (ρ 1 )<br />
ρ 2 )<br />
1<br />
≈ (2l + 1) 1 −<br />
j l (ρ 1 )<br />
(2l + 1)(2l + 3)<br />
<br />
, l <br />
, <br />
2l + 1 − γ l (ρ 1 ) − d l ρ 2 ≈ ρ2 1 − ρ 2<br />
2l + 3 = v2 0<br />
2l + 3<br />
ρ 2l+1<br />
(<br />
tan δ l ≈ v2 0<br />
2l + 3 [(2l + 1)!!] 2 ∼ v2 0 eρ<br />
8e l 2 2l<br />
(2l + 1)!! =<br />
(2l + 1)!<br />
2 l l!<br />
∼ √ 2 e −l (2l) l+1<br />
) 2l+1<br />
tan δ l l 0 , <br />
l , , <br />
l , l tan δ l <br />
<br />
<br />
, <br />
γ l (v 0 ) = v 0j l−1 (v 0 )<br />
j l (v 0 )<br />
≈ 0 , j l−1 (v 0 ) ≈ 0<br />
6.1 j l−1 (v 0 ) = 0 l 0 <br />
(10.56) <br />
tan δ l ≈<br />
(2l + 1)2 ρ 2l+1<br />
[(2l + 1)!!] 2 γ l (v 0 ) − c l ρ 2<br />
γ l (v 0 ) c l ρ 2 <br />
( ) ′<br />
γ l(v ′ v0<br />
0 ) = j l−1 (v 0 ) + j ′ v 0<br />
j l (v 0 )<br />
l−1(v 0 )<br />
j l (v 0 )<br />
( ) ′ v0<br />
= j l−1 (v 0 ) + (l − 1)j l−1(v 0 ) − v 0 j l (v 0 )<br />
j l (v 0 )<br />
j l (v 0 )<br />
j l−1 (v 0 ) ≈ 0 γ ′ l (v 0) ≈ − v 0 <br />
γ l (v 0 )/c l > 0 <br />
c l = 1 2 + 1<br />
2l − 1 = 2l + 1<br />
2(2l − 1)<br />
ρ = ρ r ≡<br />
√<br />
γ l (v 0 )<br />
c l<br />
tan δ l , (10.42) σ l k (σ l ) max =<br />
4π(2l + 1)/k 2 ρ = ρ r <br />
cot δ l ≈ d cot δ l(ρ r )<br />
[(2l + 1)!!]2<br />
(ρ − ρ r ) = −<br />
dρ r<br />
(2l + 1) 2 2c lρ −2l<br />
r<br />
(ρ − ρ r ) = − ρ − ρ r<br />
ρ i<br />
(10.59)
10 192<br />
<br />
<br />
<br />
(2l + 1)2 ρ 2l<br />
r<br />
ρ i =<br />
[(2l + 1)!!] 2 (10.60)<br />
2c l<br />
f l = 1 1<br />
k cot δ l − i ≈ − a ρ i<br />
ρ r ρ − ρ r + iρ i<br />
σ l = 4π(2l + 1)|f l | 2 ≈ 4πa2<br />
ρ 2 r<br />
ρ 2 i<br />
(ρ − ρ r ) 2 + ρ 2 i<br />
l ≠ 0 c l > 0 ρ i ∝ (γ l (v 0 )) l γ l (v 0 ) ≈ 0 ρ i <br />
, σ l ρ = ρ l ρ i <br />
c l > 0 γ l (v 0 ) > 0 γ l (v 00 ) = 0, j l−1 (v 00 ) = 0 <br />
γ l (v 0 ) = γ ′ l(v 00 )(v 0 − v 00 ) + · · · = − v 00 (v 0 − v 00 ) + · · ·<br />
γ l (v 0 ) > 0 v 0 < v 00 , σ l <br />
ρ ρ r , ρ i <br />
l = 1 <br />
σ l = 4πa 2 (2l + 1) sin2 δ l<br />
(2l + 1)2 ρ 2l+1<br />
ρ 2 , tan δ l ≈<br />
[(2l + 1)!!] 2 γ l (v 0 ) − c l ρ 2<br />
ρ = ak j l−1 (x) = j 0 (x) = sin x/x <br />
v 0 = π, 2π, · · · ( 121 ) v 0 = π σ 1 <br />
σ 1 (σ l ) max <br />
6<br />
100<br />
σ1/(4πa 2 )<br />
4<br />
2<br />
v 0 = π<br />
v 0 = 0.995π<br />
σ1/(4πa 2 )<br />
v 0 = 0.995π<br />
v 0 = 1.005π<br />
0.0 0.5<br />
ρ = ak<br />
0.15 0.20<br />
ρ = ak<br />
(10.59) , <br />
(<br />
δ l = n + 1 )<br />
π + ρ − ρ r<br />
2 ρ i<br />
ρ i , ρ = ak δ l (n + 1/2)π <br />
(10.52) A l = k r > a <br />
(<br />
) (<br />
r→∞<br />
rR l (r) = kr cos δ l j l (ρr/a) − sin δ l n l (ρr/a) −−−−→ sin kr − lπ )<br />
2 + δ l<br />
r < a q = r/a <br />
rR l (r) = rC l j l (ρ 1 q) = ρ<br />
(<br />
cos δ l j l (ρ) − sin δ l n l (ρ)<br />
) q jl (ρ 1 q)<br />
j l (ρ 1 )
10 193<br />
<br />
sin δ l =<br />
1<br />
√<br />
cot 2 δ l + 1 ≈ ρ<br />
√ i<br />
(ρ − ρr ) 2 + ρ 2 i<br />
, cos δ l = sin δ l cot δ l ≈ −<br />
ρ − ρ r<br />
√<br />
(ρ − ρr ) 2 + ρ 2 i<br />
<br />
<br />
j l (ρ) =<br />
ρ l<br />
(2l + 1)!! , n l(ρ) = −<br />
(2l + 1)!!<br />
2l + 1<br />
1<br />
ρ l+1<br />
rR l (r) ≈<br />
1<br />
√<br />
(ρ − ρr ) 2 + ρ 2 i<br />
ρ l ( [(2l + 1)!!]<br />
2<br />
(2l + 1)!! 2l + 1<br />
)<br />
ρ i<br />
q<br />
ρ 2l − ρ(ρ − ρ jl (ρ 1 q)<br />
r)<br />
j l (ρ 1 )<br />
√<br />
(ρ − ρr ) 2 + ρ 2 i<br />
ρ ρ r (10.60) <br />
rR l (r) ≈<br />
ρ 2 i<br />
√<br />
(ρ − ρr ) 2 + ρ 2 i<br />
1<br />
√ 2cl ρ i<br />
q j l (ρ 1 q)<br />
j l (ρ 1 )<br />
ρ = ρ r r < a r ≫ a , <br />
<br />
l = 1, v 0 = 0.995π, ρ = ρ r krj 1 (kr) <br />
5<br />
rRl(r)<br />
0<br />
0 1 10 20 30<br />
r/a<br />
, r > a r → ∞ <br />
, <br />
, , <br />
ρ = ρ r <br />
<br />
V eff (r) = V (r) + 2 l(l + 1)<br />
2mr 2<br />
, l ≠ 0 <br />
, E > 0 <br />
V (r) <br />
E ≈ 0 E <br />
2 l(l + 1)/(2ma 2 ) <br />
0<br />
V eff (r)<br />
1 2 r/a<br />
E , r = 0 R(r) <br />
E < 0 , R(r) r → ∞ , E r → ∞ R(r) → 0<br />
E > 0 , r → ∞ R(r) ,
10 194<br />
, E R(r)<br />
<br />
k = k r cot δ l (k) = 0 k r ≈ 0 (10.59) <br />
<br />
f l = 1 1<br />
k cot δ l − i ≈ 1 k r<br />
cot δ l ≈ k − k r<br />
k i<br />
,<br />
1<br />
= d cot δ l(k r )<br />
k i dk r<br />
k i<br />
k − k r − ik i<br />
, ∴ σ l ≈<br />
4π(2l + 1)<br />
k 2 r<br />
k 2 i<br />
(k − k r ) 2 + k 2 i<br />
k 2 i σ l k = k r (10.41)<br />
S l (k) = e 2iδ l<br />
<br />
S l (k) = cot δ l + i<br />
cot δ l − i ≈ k − k r + ik i<br />
k − k r − ik i<br />
= k − k∗ res<br />
k − k res<br />
,<br />
k res = k r + ik i<br />
, k S −1<br />
l<br />
(k) = 0, , S l (k) k r , k i <br />
(k) = 0 , Re k Im k , ,<br />
S −1<br />
l<br />
(10.43) k , k 2 /(2m) < 0 S l (k)<br />
<br />
(10.54) η(ρ 1 ) = ρ 1 j l+1 (ρ 1 )/j l (ρ 1 ) <br />
(<br />
) (<br />
)<br />
ρ n l+1 (ρ) − ij l+1 (ρ) − η(ρ 1 ) n l (ρ) − ij l (ρ)<br />
cot δ l − i =<br />
ρ j l+1 (ρ) − η(ρ 1 )j l (ρ)<br />
S −1<br />
l<br />
(k) = 0 <br />
= − i ρ h(1) l+1 (ρ) − η(ρ 1)h (1)<br />
l<br />
(ρ)<br />
ρ j l+1 (ρ) − η(ρ 1 )j l (ρ)<br />
ρ h (1)<br />
l+1 (ρ) − η(ρ 1)h (1)<br />
l<br />
(ρ) = 0 , ρ 1j l+1 (ρ 1 )<br />
j l (ρ 1 )<br />
ρ = ak ρ = iaβ <br />
ρ 1 j l+1 (ρ 1 )<br />
j l (ρ 1 )<br />
=<br />
iaβ h(1)<br />
l+1 (iaβ)<br />
h (1)<br />
l<br />
(iaβ)<br />
, ρ 1 = a<br />
(6.14) <br />
√<br />
k 2 + 2mV 0<br />
2<br />
= ρ h(1) l+1 (ρ)<br />
(ρ)<br />
h (1)<br />
l<br />
√<br />
2mV0<br />
= a<br />
2 − β 2<br />
v 0 , (10.54) δ l (k) σ l <br />
σ tot Born (10.23) <br />
• v 0 = 2.7 l = 1 , v 0 → π , <br />
<br />
• v 0 = 4, 5 l = 2, 3 <br />
• k l = 0 <br />
• v 0 k , , <br />
• (10.54) k → ∞ tan δ l (k) → 0 δ l (∞) = 0 (10.56) l = 0<br />
γ 0 (v 0 ) = 0 tan δ l (0) = 0 , n l δ l (0) = n l π<br />
, n l l ( ),<br />
l = 0 v 0 = 2.7 v 0 = 4 1 , v 0 = 5 2 121
10 195<br />
2π<br />
v 0 = 2.7 = 0.859π<br />
l = 0<br />
δ l<br />
π<br />
l = 1<br />
l = 2<br />
l = 3<br />
σl/(4πa 2 )<br />
2<br />
Born<br />
0 2 4 6 8<br />
ak<br />
0 2 4 6 8<br />
ak<br />
2π<br />
v 0 = 4.0 = 1.273π<br />
δ l<br />
π<br />
σl/(4πa 2 )<br />
2<br />
Born<br />
0 2 4 6 8<br />
ak<br />
0 2 4 6 8<br />
ak<br />
2π<br />
v 0 = 5.0 = 1.592π<br />
δ l<br />
π<br />
σl/(4πa 2 )<br />
2<br />
Born<br />
0 2 4 6 8<br />
ak<br />
0 2 4 6 8<br />
ak<br />
10.6 <br />
(10.28)<br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − U(r) + k 2 χ l (r) = 0 (10.61)<br />
k 2 , r → 0 r 2 U(r) → 0 <br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 χ l (r) = 0<br />
α r l+1 + β r −l , (10.61) 2 Φ l (k, r) ,<br />
Φ (1)<br />
l<br />
(k, r) <br />
Φ l , Φ (1)<br />
l<br />
Φ l (k, r)<br />
r→0<br />
−−−−→ r l+1 , Φ (1) r→0<br />
l<br />
(k, r) −−−−→ r −l (10.62)<br />
r → ∞ , r → ∞ (10.61) <br />
( ) d<br />
2<br />
dr 2 + k2 χ l (r) = 0
10 196<br />
, α e ikr + β e −ikr (10.61) <br />
lim<br />
r→∞ e±ikr F l (± k, r) = 1 (10.63)<br />
F l (k, r) , F l (−k, r) r → 0 <br />
(10.61) ϕ 1 , ϕ 2 W (ϕ 1 , ϕ 2 ) = ϕ 1<br />
dϕ 2<br />
dr − dϕ 1<br />
dr ϕ 2 <br />
dW<br />
dr = ϕ d 2 ϕ 2<br />
1<br />
dr 2 − d2 ϕ 1<br />
dr 2 ϕ 2<br />
( ) ( )<br />
l(l + 1)<br />
l(l + 1)<br />
= ϕ 1<br />
r 2 + U(r) − k 2 ϕ 2 −<br />
r 2 + U(r) − k 2 ϕ 1 ϕ 2 = 0<br />
(<br />
)<br />
r W F l (k, r), F l (−k, r) r → ∞ <br />
(<br />
) (<br />
W F l (k, r), F l (−k, r) = W e −ikr , e ikr) = 2ik<br />
(10.61) F l (k, r) F l (−k, r) <br />
W (ϕ, ϕ) = 0 <br />
Φ l (k, r) = AF l (k, r) + BF l (−k, r)<br />
(<br />
) (<br />
)<br />
W F l (k, r), Φ l (k, r) = B W F l (k, r), F l (−k, r) = 2ik B<br />
(<br />
) (<br />
)<br />
W F l (−k, r), Φ l (k, r) = A W F l (−k, r), F l (k, r) = −2ik A<br />
<br />
(<br />
)<br />
F l (k) = W F l (k, r), Φ l (k, r)<br />
F l (k) (Jost) Φ l (−k, r) = Φ l (k, r) <br />
A = − F l(−k)<br />
2ik<br />
, B = F l(k)<br />
2ik<br />
<br />
r → ∞ <br />
Φ l (k, r) = − 1 (<br />
)<br />
F l (−k) F l (k, r) − F l (k) F l (−k, r)<br />
2ik<br />
Φ l (k, r) → − 1 (F l (−k) e −ikr − F l (k) e ikr)<br />
2ik<br />
r → ∞ (10.43) <br />
S l (k) = (−1) l F l(k)<br />
F l (−k)<br />
(10.64)<br />
(10.65)<br />
<br />
(10.61) (10.63) k k ∗ <br />
( )<br />
d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − U(r) + k 2 Fl ∗ (k ∗ , r) = 0 ,<br />
lim<br />
r→∞ e−ikr Fl ∗ (k ∗ , r) = 1<br />
<br />
F ∗ l (−k ∗ , r) = F l (k, r) (10.66)
10 197<br />
Φ l (k, r) k Φ ∗ l (k∗ , r) = Φ l (k, r) <br />
(<br />
) (<br />
)<br />
Fl ∗ (k ∗ ) = W Fl ∗ (k ∗ , r), Φ ∗ l (k ∗ , r) = W F l (−k, r), Φ l (k, r) = F l (−k)<br />
(10.65) <br />
S l (−k) = S −1<br />
l<br />
(k) , S ∗ l (k ∗ ) = S l (−k) (10.67)<br />
k , , 1 S l (k) , S l (k) <br />
• k , k = − k ∗ S l (−k ∗ ) = S ∗ l (k) S l(k) = S ∗ l (k)<br />
, S l (k) <br />
• k Sl ∗(k) = S l(−k) = S −1<br />
l<br />
(k) |S l (k)| = 1 , δ l<br />
S l (k) = e 2iδl(k) , δ l (k) <br />
• (10.67) S l (k) = 0 <br />
S ∗ l (−k ∗ ) = S l (k) = 0 ,<br />
S l (−k) = Sl ∗ (k ∗ ) = S −1<br />
l<br />
(k) = ∞<br />
k −k ∗ S l , − k <br />
k ∗ S l , , <br />
<br />
<br />
k = k n F l (k n ) = 0 (10.64) <br />
r → ∞ <br />
Φ l (k n , r) = a n F l (k n , r) , a n = − F l(−k n )<br />
2ik n<br />
Φ l (k n , r) → a n e −ik nr = a n e −ik Rr e k Ir , k R = Re k n , k I = Im k n (10.68)<br />
, k I < 0 r → ∞ Φ l (k n , r) → 0 , Φ l (k n , r) 0 <br />
, Φ l (k n , r) , F l (k n ) = 0 k I < 0 k R = 0 <br />
, E = − kI 2 /2m <br />
(10.61) <br />
<br />
d 2<br />
( )<br />
l(l + 1)<br />
dr 2 Φ l(k, r) =<br />
r 2 + U(r) − k 2 Φ l (k, r)<br />
d 2<br />
dr 2 Φ∗ l (k, r) =<br />
( l(l + 1)<br />
r 2 + U(r) − k ∗ 2 )<br />
Φ ∗ l (k, r)<br />
d<br />
(<br />
)<br />
dr W Φ l (k, r), Φ ∗ l (k, r) = Φ l (k, r) d2<br />
dr 2 Φ∗ l (k, r) − Φ ∗ l (k, r) d2<br />
dr 2 Φ l(k, r) = 2i Im(k 2 ) |Φ l (k, r)| 2<br />
<br />
2iIm(k 2 )<br />
∫ ∞<br />
0<br />
dr |Φ l (k, r)| 2 = W<br />
(<br />
(<br />
)∣<br />
Φ l (k, r), Φ ∗ ∣∣r=∞<br />
l (k, r))∣<br />
− W Φ l (k, r), Φ ∗ ∣∣r=0<br />
l (k, r)<br />
(<br />
)∣<br />
= W Φ l (k, r), Φ ∗ ∣∣r=∞<br />
l (k, r)
10 198<br />
(10.68) <br />
(<br />
W Φ l (k n , r), Φ ∗ ∣∣r=∞<br />
l (k n , r))∣<br />
= 2i|a n | 2 k R e ∣ 2k Ir r=∞<br />
<br />
( ∫ ∞<br />
k R 2k I dr |Φ l (k n , r)| 2 − |a n | 2 e ∣ ) 2k Ir r=∞<br />
= 0<br />
0<br />
k R = 0 F l (k) = 0 k R = 0, k I < 0<br />
, k R ≠ 0 , k I < 0 <br />
∫ ∞<br />
0<br />
dr |Φ l (k n , r)| 2 = 0<br />
Φ l (k n , r) = 0 , k R ≠ 0 , k I < 0 F l (k) = 0 ,<br />
k R ≠ 0, k I > 0 Φ l (k n , r) , F l (k) = 0 k <br />
, S l (k) , S l (k) = S −1 (−k) <br />
, S l (k) <br />
<br />
k = k n S l (k) F l (−k n ) = 0 <br />
k R = 0 , k I > 0 k R ≠ 0 , k I < 0<br />
|k I | ≪ |k R | , <br />
E = 2 k 2 n<br />
2m = E R − i 2 Γ ,<br />
E R = 2 (<br />
k<br />
2<br />
2m R − kI 2 ) 2 2<br />
, Γ = −<br />
m k Rk I<br />
, ψ <br />
|ψ(r, t)| 2 ∝ |e −iEt/ | 2 −Γ t/<br />
= e<br />
Γ > 0 ( k R > 0 ) τ e −1 <br />
τ = /Γ Γ <br />
F l (−k n ) = 0 k = k n <br />
F l (−k) = a (k − k n ) , a = dF l(−k n )<br />
dk n<br />
= dF ∗ l (k∗ n)<br />
dk n<br />
=<br />
F l (k ∗ n) = F ∗ l (−k n) = 0 k = k ∗ n <br />
F l (k) = b (k − k ∗ n) , b = dF l(k ∗ n)<br />
dk ∗ n<br />
= a ∗<br />
, k I k n ≈ k ∗ n k = k R <br />
( dFl (k ∗ n)<br />
dk ∗ n<br />
) ∗<br />
S l (k) = (−1) l F l(k)<br />
F l (−k) = k − k∗ n<br />
, e2iθ0 e 2iθ0 = (−1) l a∗<br />
k − k n a<br />
(10.69)<br />
<br />
<br />
S l (k) = e 2iθ0 k R(k − k ∗ n)<br />
k R (k − k n )<br />
k R (k − k n ) = k R (k − k R ) − ik R k I ≈ k2 − k 2 R<br />
2<br />
− ik R k I = m )<br />
(E<br />
2 − E R + iΓ/2
10 199<br />
<br />
S l (k) = e 2iθ E − E (<br />
)<br />
0 R − iΓ/2<br />
E − E R + iΓ/2 = iΓ<br />
e2iθ 0<br />
1 −<br />
E − E R + iΓ/2<br />
σ l <br />
(<br />
π(2l + 1)<br />
σ l =<br />
k 2 |1 − S l | 2 4π(2l + 1) Γ e<br />
iθ 0<br />
)<br />
sin θ 0<br />
= σ l, pot + σ l, res −<br />
k 2 Re<br />
E − E R + iΓ/2<br />
(10.70)<br />
(10.71)<br />
<br />
σ l, pot =<br />
4π(2l + 1)<br />
k 2 sin 2 θ 0 , σ l, res =<br />
4π(2l + 1)<br />
k 2 (Γ /2) 2<br />
(E − E R ) 2 + (Γ/2) 2<br />
Γ σ l, res E = E R , σ l, pot <br />
<br />
E , (10.70) <br />
S l = e 2iδ l<br />
, δ l = θ 0 + θ res , tan θ res = − Γ/2<br />
E − E R<br />
θ res E <br />
π<br />
, θ res nπ , E ≪ E R<br />
θ res = 0, E ≫ E R θ res = π <br />
E ≈ E R <br />
θ res ≈ π 2 + E − E R<br />
Γ/2<br />
π/2<br />
0<br />
E R<br />
Γ , E R θ res <br />
10.7 <br />
V (r) r → ∞ 1/r 2 0 <br />
<br />
m, Ze m ′ , Z ′ e m ′ ≫ m ,<br />
, m <br />
)<br />
(− 2<br />
2m ∇2 + ZZ′ αc<br />
ψ c (r) = Eψ c (r)<br />
r<br />
(<br />
∇ 2 + k 2 − 2kη )<br />
ψ c (r) = 0 , E = 2 k 2<br />
r<br />
2m ,<br />
<br />
<br />
∂ψ c<br />
∂x<br />
ψ c (r) = e ikz f(q) ,<br />
= eikz<br />
∂q<br />
∂x f ′ (q) = e ikz x r f ′ (q) ,<br />
∂ψ c<br />
∂z = eikz (<br />
ikf + ∂q<br />
∂z f ′ (q)<br />
∂ 2 ψ c<br />
∂z 2 = eikz [<br />
−k 2 f(q) +<br />
)<br />
( x 2 + y 2<br />
r 3<br />
q = r − z = 2r sin 2 (θ/2)<br />
∂ 2 ψ c<br />
∂x 2<br />
(<br />
= e ikz ikf(q) − q )<br />
r f ′ (q)<br />
η = ZZ′ αmc<br />
k<br />
[( )<br />
]<br />
1 = eikz r − x2<br />
r 3 f ′ (q) + x2<br />
r 2 f ′′ (q)<br />
− 2ikq ) ]<br />
f ′ (q) + q2<br />
r<br />
r 2 f ′′ (q)
10 200<br />
<br />
∇ 2 ψ c (r) = e ikz ( 2q<br />
r f ′′ (q) +<br />
)<br />
2(1 − ikq)<br />
f ′ (q) − k 2 f(q)<br />
r<br />
(<br />
q d2<br />
dq 2 + (1 − ikq) d dq − kη )<br />
f(q) = 0<br />
ρ = ikq = ik(r − z) <br />
(ρ d2<br />
dρ 2 + (1 − ρ) d dρ + iη )<br />
f(q) = 0<br />
(15.59) a = − iη, b = 1 , q = 0<br />
A c <br />
(15.80) |r − z| → ∞ <br />
ψ c (r) = A c e ikz M(−iη, 1, ikq) (10.72)<br />
)<br />
M(−iη, 1, ikq) =<br />
(1 (−ikq)iη + η2<br />
+ eikq (ikq) −iη−1<br />
Γ (1 + iη) ikq Γ (−iη)<br />
= eπη/2<br />
Γ (1 + iη) eiη log kq (<br />
1 + η2<br />
ikq<br />
(1 +<br />
)<br />
(1 + iη)2<br />
ikq<br />
)<br />
+ eπη/2 ikq−iη log kq<br />
e<br />
Γ (−iη) ikq<br />
<br />
(−ikq) iη = e iη log(−ikq) = e iη(−iπ/2+log(kq))<br />
|r − z| −2 A c = Γ (1 + iη) e −πη/2 q = r − z = 2r sin 2 (θ/2) <br />
<br />
<br />
ψ c (r) −→ ψ in (r) + ψ out (r)<br />
(<br />
)(<br />
)<br />
ψ in (r) = exp ikz + iη log k(r − z) 1 + O(|r − z| −1 )<br />
ψ out (r) = f c (θ)<br />
f c (θ) = 1<br />
2ik<br />
= − η<br />
2k<br />
exp (ikr − iη log 2kr)<br />
(<br />
)<br />
1 + O(|r − z| −1 )<br />
r<br />
Γ (1 + iη) exp ( − iη log sin 2 (θ/2) )<br />
Γ (−iη) sin 2 (θ/2)<br />
Γ (1 + iη) exp ( − iη log sin 2 (θ/2) )<br />
Γ (1 − iη) sin 2 (θ/2)<br />
(10.73)<br />
(10.74)<br />
(10.75)<br />
, Γ (15.52) iΓ (−iη) = − Γ (1 − iη)/η <br />
(Γ (1 + iη)) ∗ = Γ (1 − iη) <br />
<br />
f c (θ) = −<br />
Γ (1 + iη) = |Γ (1 + iη)| e iσ0<br />
η<br />
2k sin 2 (θ/2) eiδ = −<br />
ZZ′ αc<br />
4E sin 2 (θ/2) eiδ , δ = 2σ 0 − η log sin 2 (θ/2) (10.76)
10 201<br />
, (10.73), (10.74) (10.2) <br />
, ψ in exp(iη log k(r − z)) ψ in <br />
ψ in J <br />
J x = )<br />
(ψ<br />
m Im in<br />
∗ ∂<br />
∂x ψ in<br />
J z = k m<br />
= η<br />
m<br />
(<br />
1 − η kr + O((r − z)−1 )<br />
x<br />
r(r − z)<br />
)<br />
(<br />
)<br />
1 + O((r − z) −1 )<br />
z → −∞ J x , J y → 0 , J z → k/m , ψ in <br />
ψ out e ikr /r , exp (−iη log 2kr) (10.3) <br />
ψ out J <br />
|f c | 2 d<br />
(<br />
)<br />
J = e r<br />
m r 2 kr − η log 2kr + Im (fc ∗ uf c ) k |f c | 2 ( )<br />
dr<br />
m r 3 = e r<br />
m r 2 1 + O(r −1 )<br />
, f c (θ) , <br />
(<br />
dσ<br />
ZZ<br />
dΩ = |f c(θ)| 2 ′ ) 2<br />
αc<br />
=<br />
4E sin 2 (10.77)<br />
(θ/2)<br />
( ? ),<br />
, z = r (10.73), (10.74) <br />
θ = 0 <br />
1 (10.75) η <br />
, η 1 , , (10.76) δ = 0 f c (θ) <br />
f born (θ) = −<br />
, (10.16) <br />
∫<br />
V(q) = d 3 r e −iq·r V (r) = 2πZZ ′ αc<br />
= 2πZZ′ αc<br />
iq<br />
ZZ′ αc<br />
4E sin 2 (θ/2)<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
dr r 2 ∫ π<br />
0<br />
cos θ<br />
e−iqr<br />
dθ sin θ<br />
r<br />
dr<br />
(e iqr − e −iqr)<br />
(10.78)<br />
µ e −µr , <br />
µ → + 0 <br />
V(q) = 2πZZ′ αc<br />
iq<br />
[ ] e<br />
(−µ+iq)r<br />
∞<br />
−µ + iq + e(−µ−iq)r<br />
µ + iq<br />
0<br />
= 4πZZ′ αc<br />
q 2 + µ 2<br />
µ→+0<br />
−−−−→ 4πZZ′ αc<br />
q 2<br />
, <br />
f born (θ) = −<br />
m<br />
2π 2 V(q) = − ZZ′ αc<br />
4E sin 2 (θ/2)<br />
(10.78) f born (10.76) , <br />
(10.77) <br />
<br />
(10.35) <br />
ψ c (r) = 1<br />
kr<br />
∞∑<br />
χ l (r) P l (cos θ) (10.79)<br />
l=0
10 202<br />
( d<br />
2<br />
l(l + 1)<br />
−<br />
dρ2 ρ 2 − 2η )<br />
ρ + 1 χ l (r) = 0 , ρ = kr (10.80)<br />
<br />
χ l (ρ) = ρ l+1 e iρ v l (ρ)<br />
(<br />
z d2<br />
dz 2 + (2l + 2 − z) d dz − (l + 1 + iη) )<br />
v l = 0 , z = −2iρ (10.81)<br />
(15.59) a = l + 1 + iη , b = 2l + 2 , <br />
B l <br />
v l (ρ) = B l M(l + 1 + iη, 2l + 2, −2iρ)<br />
(15.77), (15.78) W 1 , W 2 <br />
)<br />
v l (ρ) = B l<br />
(W 1 (l + 1 + iη, 2l + 2, −2iρ) + W 2 (l + 1 + iη, 2l + 2, −2iρ)<br />
= B l e −iρ( )<br />
e iρ W 1 (l + 1 + iη, 2l + 2, −2iρ) + e −iρ W 1 (l + 1 − iη, 2l + 2, 2iρ)<br />
(<br />
)<br />
= 2B l e −iρ Re e iρ W 1 (l + 1 + iη, 2l + 2, −2iρ)<br />
(15.77), (15.79) <br />
<br />
W 1 (l + 1 + iη, 2l + 2, −2iρ) =<br />
=<br />
Γ (2l + 2)<br />
Γ (l + 1 − iη) (2iρ)−l−1−iη g l (η, ρ)<br />
(2l + 1)! eπη/2 e −iη log(2ρ)−i(l+1)π/2+iσ l<br />
|Γ (l + 1 + iη)| (2ρ) l+1 g l (η, ρ) (10.82)<br />
g l (η, ρ) = g(l + 1 + iη, −l + iη, 2iρ) = 1 + η + i ( l(l + 1) + η 2)<br />
+ O(ρ −2 )<br />
2ρ<br />
, σ l Γ (l + 1 + iη) <br />
Γ (l + 1 + iη) = |Γ (l + 1 + iη)| e iσ l<br />
, e 2iσ l<br />
=<br />
Γ (l + 1 + iη)<br />
Γ (l + 1 − iη)<br />
(10.83)<br />
<br />
<br />
B l = 2l |Γ (l + 1 + iη)|<br />
e −πη/2<br />
(2l + 1)!<br />
χ l (ρ) = F l (η, ρ) ≡ B l ρ l+1 e iρ M(l + 1 + iη, 2l + 2, −2iρ)<br />
(<br />
)<br />
= 2B l ρ l+1 Re e iρ W 1 (l + 1 + iη, 2l + 2, −2iρ)<br />
[ (<br />
)) ]<br />
= Im g l (η, ρ) exp i<br />
(ρ − η log(2ρ) − πl/2 + σ l<br />
(10.84)<br />
ρ → ∞ <br />
(<br />
F l (η, ρ) −→ sin ρ − η log(2ρ) − πl )<br />
2 + σ l , ρ = kr
10 203<br />
(10.34) (10.83) σ l <br />
F l (η, ρ) ρ → 0 F l (η, ρ) −→ B l ρ l+1 <br />
, η = 0 (15.85) <br />
<br />
F l (0, ρ) = 2l |Γ (l + 1)|<br />
(2l + 1)!! ρj l (ρ) = ρj l (ρ)<br />
(2l + 1)!<br />
(10.72) (10.79)<br />
A c e ikz M(−iη, 1, ik(r − z)) = 1 ρ<br />
∞∑<br />
C l F l (η, ρ)P l (cos θ) ,<br />
l=0<br />
A c = Γ (1 + iη) e −πη/2<br />
C l x = cos θ (15.27) <br />
C l<br />
F l (η, ρ)<br />
ρ<br />
= A 2l + 1<br />
2 l+1 l!<br />
∫ 1<br />
−1<br />
dx (1 − x 2 ) l dl<br />
dx l eiρx M(−iη, 1, iρ(1 − x))<br />
(15.74) <br />
∫ (<br />
)<br />
e iρx M(−iη, 1, iρ(1 − x)) = v 0 (−iη, 1) dt exp iρx + iρ(1 − x)t t −iη−1 (1 − t) iη<br />
= v 0 (−iη, 1)<br />
C<br />
∞∑ (iρ) n ∫<br />
n=0<br />
n!<br />
C<br />
(<br />
) nt<br />
dt t + (1 − t)x<br />
−iη−1 (1 − t) iη<br />
<br />
C l<br />
F l (η, ρ)<br />
ρ<br />
= A c<br />
2l + 1<br />
2 l+1 l! v 0(−iη, 1)<br />
∞∑ (iρ) n ∫<br />
n=0<br />
n!<br />
C<br />
dt t −iη−1 (1 − t) iη f n (t)<br />
<br />
f n (t) =<br />
∫ 1<br />
−1<br />
(<br />
)<br />
dx (1 − x 2 ) l dl<br />
n<br />
dx l t + (1 − t)x<br />
ρ → 0 F l (η, ρ) → B l ρ l+1 , n = l (5.25) <br />
f l (t) = (1 − t) l l!<br />
∫ 1<br />
−1<br />
dx (1 − x 2 ) l = (1 − t) l l! 22l+1 (l!) 2<br />
(2l + 1)!<br />
<br />
(15.27) <br />
<br />
C l = A c (2i) l ∫<br />
l!<br />
v 0 (−iη, 1) dt t −iη−1 (1 − t) l+iη<br />
B l (2l)!<br />
C<br />
∫<br />
M(−iη, l + 1, 0) = 1 = v 0 (−iη, l + 1) dt t −iη−1 (1 − t) l+iη<br />
C<br />
C l = A c (2i) l l! v 0 (−iη, 1)<br />
B l (2l)! v 0 (−iη, l + 1) = A c (2i) l<br />
B l (2l)!<br />
Γ (l + 1 + iη)<br />
Γ (1 + iη)<br />
= (2l + 1)i l e iσ l<br />
<br />
ψ c (r) = A c e ikz M(−iη, 1, ik(r − z)) = 1 ∞∑<br />
(2l + 1) i l e iσ l<br />
F l (η, ρ)P l (cos θ) (10.85)<br />
ρ<br />
l=0
10 204<br />
η = 0 <br />
(10.31) <br />
∞∑<br />
e ikz = (2l + 1) i l j l (kr)P l (cos θ)<br />
l=0<br />
2 (10.80) , F l (η, ρ) G l (η, ρ) F l<br />
W 1 + W 2 , W 1 − W 2 <br />
(<br />
)<br />
G l (η, ρ) = B l ρ l+1 e iρ i W 1 (l + 1 + iη, 2l + 2, −2iρ) − W 2 (l + 1 + iη, 2l + 2, −2iρ)<br />
(<br />
)<br />
= − 2B l ρ l+1 Im e iρ W 1 (l + 1 + iη, 2l + 2, −2iρ)<br />
[ (<br />
)) ]<br />
= Re g l (η, ρ) exp i<br />
(ρ − η log(2ρ) − πl/2 + σ l<br />
(10.82) ρ → ∞ <br />
G l (η, ρ) → cos<br />
, (15.86) G l (0, ρ) = − ρ n l (ρ) <br />
(<br />
ρ − η log(2ρ) − πl )<br />
2 + σ l<br />
F l G l <br />
(<br />
)<br />
u (+)<br />
l<br />
(η, ρ) = e −iσ l<br />
G l (η, ρ) + i F l (η, ρ)<br />
= 2B l ρ l+1 e iρ−iσl+iπ/2 W 1 (l + 1 + iη, 2l + 2, −2iρ)<br />
( ) ∗<br />
u (−)<br />
l<br />
(η, ρ) = u (+)<br />
l<br />
(η, ρ)<br />
(10.86)<br />
, ρ → ∞ <br />
u (±)<br />
±i(ρ−η log(2ρ)−πl/2)<br />
l<br />
(η, ρ) −→ e<br />
u (+) (η, ρ) , u (−) (η, ρ) <br />
, (10.85) <br />
<br />
ψ c (r) = 1<br />
2ikr<br />
F l (η, ρ) = e−iσ l (<br />
2i<br />
e 2iσ l<br />
u (+)<br />
l<br />
∞∑ ( (2l + 1) i l e 2iσ l<br />
u (+)<br />
l=0<br />
l<br />
)<br />
(η, ρ) − u (−)<br />
l<br />
(η, ρ)<br />
)<br />
(η, kr) − u (−)<br />
l<br />
(η, kr) P l (cos θ) (10.87)<br />
10.4<br />
x = cos θ <br />
(15.27) <br />
, (15.21) <br />
l=0<br />
f c (θ) = 1 Γ (1 + iη)<br />
2ik Γ (−iη)<br />
f c (θ) = 1<br />
2ik<br />
( 1 − x<br />
2<br />
) −1−iη<br />
∞∑<br />
(2l + 1)e 2iσ l<br />
P l (x) (10.88)<br />
l=0<br />
∞∑<br />
∞∑<br />
)<br />
(1 − x) (2l + 1)P l (x) =<br />
((2l + 1)P l − (l + 1)P l+1 − lP l−1 = 0<br />
l=0
10 205<br />
<br />
{<br />
∞∑<br />
0 , x ≠ 1<br />
(2l + 1)P l (x) =<br />
∞ , x = 1<br />
l=0<br />
(15.28) x ′ = 1 , x ≠ 1 , ( θ ≠ 0 ) <br />
f c (θ) = 1<br />
2ik<br />
(10.39) <br />
∞∑<br />
(2l + 1) ( e 2iσ l<br />
− 1 ) P l (cos θ)<br />
l=0<br />
10.5<br />
Γ (15.52) σ l = σ l−1 + tan −1 (η/l) <br />
1<br />
Γ (z) = z eγz<br />
∞<br />
∏<br />
n=1<br />
[(1 + z/n) e −z/n]<br />
<br />
γ = = lim<br />
(1 + 1<br />
n→∞ 2 + 1 3 + · · · + 1 )<br />
n − log n = 0.57721 56649 01532 · · ·<br />
<br />
<br />
∞∑ ( η<br />
σ 0 = − γη +<br />
n n)<br />
− η tan−1<br />
n=1<br />
(10.89)<br />
S l = e 2iσ l<br />
E Γ (z) n ′ = 0, 1, 2, · · · <br />
z = −n ′ , (10.83) , E <br />
<br />
l + 1 + iη = − n ′ , ik = ZZ′ αmc 2<br />
c<br />
1<br />
l + 1 + n ′<br />
E = 2 k 2<br />
2m = − (ZZ′ α) 2 mc 2<br />
2n 2 , n = l + 1 + n ′<br />
(6.20) F l , χ l (r)<br />
<br />
r → ∞ <br />
χ l (r) = D l<br />
(<br />
u (+)<br />
l<br />
(η, kr) − S −1<br />
l<br />
(<br />
χ l (r) = D l e i(kr−η log(2kr)−πl/2) − S −1<br />
2 1 <br />
l<br />
)<br />
u (−)<br />
l<br />
(η, kr)<br />
i(kr−η log(2kr)−πl/2)<br />
F l (η, ρ) = D l e<br />
−i(kr−η<br />
e<br />
log(2kr)−πl/2))<br />
r → ∞ χ l (r) → 0 ik < 0 ZZ ′ < 0 , <br />
, r → 0 u (+)<br />
l<br />
<br />
<br />
S −1<br />
l<br />
u (−)<br />
l<br />
u (−)<br />
l<br />
,
10 206<br />
, , <br />
σ l ≠ 0 l , , <br />
, <br />
V (r) = V 0 (r) + ZZ′ αc<br />
r<br />
V 0 (r) V (r) σ l + δ l , δ l l<br />
0 , σ l l ,<br />
f c (θ) <br />
<br />
ψ(r) = 1<br />
kr<br />
∞∑<br />
χ l (r)P l (cos θ)<br />
l=0<br />
( d<br />
2<br />
l(l + 1)<br />
−<br />
dr2 r 2 − 2m<br />
2 V 0(r) − 2kη )<br />
+ k 2 χ l (r) = 0 (10.90)<br />
r<br />
r V 0 (r) (10.80) <br />
χ l (r) = a l<br />
(<br />
F l (η, kr) cos δ l + G l (η, kr) sin δ l<br />
)<br />
(<br />
r→∞<br />
−−−−→ a l sin kr − η log(2kr) − πl )<br />
2 + σ l + δ l<br />
σ l + δ l V (r) , <br />
G l , r G l<br />
χ l (r) V 0 (r) , <br />
<br />
<br />
F l = i 2<br />
(<br />
e −iσ l<br />
u (−) − e iσ l<br />
u (+)) , G l = 1 (e −iσ l<br />
u (−) + e iσ l<br />
u (+))<br />
2<br />
(<br />
χ l (r) = c l e 2iδ l+2iσ l<br />
u (+)<br />
l<br />
)<br />
(η, kr) − u (−) (η, kr)<br />
, c l = e−iδ l−iσ l<br />
a l<br />
2i<br />
, r → ∞ (10.2) , <br />
r → ∞ , (10.73), (10.74) <br />
r → ∞ <br />
(<br />
)<br />
exp (ikr − iη log 2kr)<br />
ψ(r) = exp ikz + iη log k(r − z) + f(θ)<br />
r<br />
1 U(r) <br />
, 2 f c (θ) f(θ) V 0 (r) <br />
f(θ) <br />
f(θ) = f c (θ) + f 0 (θ)<br />
<br />
ψ(r) = e ikz+iη log k(r−z) + f c (θ)<br />
eikr−iη<br />
log 2kr<br />
r<br />
+ f 0 (θ)<br />
eikr−iη<br />
log 2kr<br />
r
10 207<br />
1 2 ψ c (r) <br />
= 1<br />
2ikr<br />
eikr−iη<br />
log 2kr<br />
ψ(r) = ψ c (r) + f u (θ)<br />
r<br />
∞∑ ( (2l + 1) i l e 2iσ l<br />
u (+)<br />
l=0<br />
+ f 0 (θ)<br />
eikr−iη<br />
log 2kr<br />
, χ l r → ∞ <br />
ψ ( r) = 1<br />
kr<br />
= 1<br />
kr<br />
r<br />
∞∑ (<br />
c l e 2iδ l+2iσ l<br />
u (+)<br />
l=0<br />
∞∑ (<br />
c l e 2iσ l<br />
u (+)<br />
l=0<br />
+ 1<br />
kr<br />
∞∑<br />
c l e 2iσ l<br />
l=0<br />
l<br />
l<br />
l<br />
)<br />
(η, kr) − u (−)<br />
l<br />
(η, kr) P l (cos θ) (10.91)<br />
)<br />
(η, kr) − u (−)<br />
l<br />
(η, kr) P l (cos θ)<br />
(10.92)<br />
)<br />
(η, kr) − u (−)<br />
l<br />
(η, kr) P l (cos θ) (10.93)<br />
(<br />
e<br />
2iδ l<br />
− 1 ) u (+)<br />
l<br />
(η, kr)P l (cos θ) (10.94)<br />
(10.91) (10.93) c l = (2l + 1)i l /(2i) u (+)<br />
l<br />
(η, kr) <br />
(10.94) (10.92) <br />
f 0 (θ) = 1<br />
2ik<br />
∞∑<br />
(2l + 1) e 2iσ (<br />
l e<br />
2iδ l<br />
− 1 ) P l (cos θ) (10.95)<br />
l=0<br />
<br />
dσ<br />
dΩ = |f c(θ) + f 0 (θ)| 2 = |f c (θ)| 2 + |f 0 (θ)| 2 + 2Re(fc ∗ f 0 )<br />
V 0 (r) δ l l 0 , (10.95)<br />
<br />
10.8 <br />
(10.90) , δ l (10.90) <br />
6.7 , r = 0 r , <br />
<br />
λ <br />
q = r λ ,<br />
ε = 2mλ2 E<br />
2 , U 0 (q) = 2mλ2<br />
2 V 0 (r)<br />
( d<br />
2<br />
l(l + 1)<br />
−<br />
dq2 q 2 − U 0 (q) − 2√ )<br />
ε η<br />
+ ε χ l (q) = 0 (10.96)<br />
q<br />
<br />
η = ZZ′ αmcλ<br />
√ ε<br />
= ZZ′ αmc<br />
k<br />
q → 0 q 2 U 0 (q) → 0 χ l (q) (6.42) (10.96) q <br />
<br />
χ max = χ l (q max ) ,<br />
χ max−1 = χ l (q max − ∆q)
10 208<br />
q = q max U 0 (q) <br />
χ max = a l<br />
(<br />
F max cos δ l + G max sin δ l<br />
)<br />
, χ max−1 = a l<br />
(<br />
F max−1 cos δ l + G max−1 sin δ l<br />
)<br />
<br />
<br />
F max = F l<br />
(<br />
η,<br />
√<br />
ε<strong>qm</strong>ax<br />
)<br />
, Fmax−1 = F l<br />
(<br />
η,<br />
√<br />
ε(<strong>qm</strong>ax − ∆q) )<br />
G max = G l<br />
(<br />
η,<br />
√<br />
ε<strong>qm</strong>ax<br />
)<br />
, Gmax−1 = G l<br />
(<br />
η,<br />
√<br />
ε(<strong>qm</strong>ax − ∆q) ) (10.97)<br />
tan δ l = − F maxχ max−1 − F max−1 χ max<br />
G max χ max−1 − G max−1 χ max<br />
(10.98)<br />
χ max χ max−1 , F l G l , δ l <br />
δ l nπ , (10.95) <br />
σ l , F l (η, ρ), G l (η, ρ) σ l<br />
10.5 <br />
(10.89) (10.84), (10.86) F l (η, ρ) G l (η, ρ) (15.79) <br />
g l (η, ρ) = g(l + 1 + iη, −l + iη, 2iρ) =<br />
(a) k <br />
D k+1 =<br />
∞∑<br />
D k ,<br />
k=0<br />
(l + k + 1 + iη)(k − l + iη)<br />
D k<br />
(k + 1) 2iρ<br />
D k = (l + 1 + iη) k (−l + iη) k<br />
k!<br />
1<br />
(2iρ) k<br />
D 0 = 1 g l (η, ρ) , <br />
Re D k+1 =<br />
Im D k+1 =<br />
(2k + 1)η<br />
2(k + 1)ρ Re D k − η2 + l(l + 1) − k(k + 1)<br />
Im D k<br />
2(k + 1)ρ<br />
(2k + 1)η<br />
2(k + 1)ρ Im D k + η2 + l(l + 1) − k(k + 1)<br />
Re D k<br />
2(k + 1)ρ<br />
η = 0 D k = 0 , ( k > l ) g l (η, ρ) , η ≠ 0 <br />
, g l (η, ρ) , ρ <br />
g l (η, ρ) ( 271 ), ρ , , |D k | < 10 −6<br />
k ρ , <br />
, <br />
{<br />
− u0 , q < 1<br />
U 0 (q) =<br />
0 , q > 1<br />
η = 0 , δ l (10.54) <br />
, <br />
u 0<br />
ρ = √ ε , ρ 1 = √ ε + u 0<br />
= 50 , ε = 20 , (10.54) (10.98) <br />
δ l q min = 10 −3 , q max =<br />
3 , ∆q = 0.01, 0.001 <br />
l<br />
(10.98)<br />
0.01 0.001<br />
(10.54)<br />
0 1.0295 1.0488 1.0514<br />
1 0.3748 0.3797 0.3804<br />
2 0.7494 0.7562 0.7571<br />
3 −0.3499 −0.3219 −0.3178<br />
4 −0.4628 −0.4626 −0.4626<br />
5 −0.3969 −0.3885 −0.3873<br />
6 0.0638 0.0694 0.0702<br />
7 0.0027 0.0029 0.0029<br />
∆q ≈ 0.1 ∼ 0.01 , <br />
0 , (10.98) δ l ,<br />
∆q
11 209<br />
11 <br />
11.1 <br />
<br />
3 α, −→ α , ,<br />
, <br />
| α 〉 , α <br />
( ket vector ) <br />
<br />
, , | α 〉 <br />
<br />
<br />
1. 1 <br />
, 1 <br />
, <br />
2. , <br />
| α 〉 , <br />
c 1 | α 〉 + c 2 | α 〉 = (c 1 + c 2 )| α 〉 , ( c 1 , c 2 )<br />
, <br />
, <br />
<br />
<br />
( bra vector ) | α 〉 〈 α | 1 <br />
c c | α 〉 c 〈 α | c ∗ 〈 α | <br />
<br />
⎛ ⎞<br />
A ≡<br />
⎜<br />
⎝<br />
a 1<br />
a 2<br />
a 3<br />
.<br />
⎟<br />
⎠ ⇐⇒ A† = ( a ∗ 1 a ∗ 2 a ∗ 3 · · · )<br />
, | α 〉 + 〈 β | <br />
<br />
〈 α |, | β 〉 , 〈 α | β 〉 <br />
⎛<br />
b 1<br />
( a ∗ 1 a ∗ 2 a ∗ 3 · · · )<br />
⎜<br />
⎝<br />
b 3<br />
. b 2<br />
⎞<br />
⎟<br />
⎠ = a∗ 1b 1 + a ∗ 2b 2 + a ∗ 3b 3 + · · ·<br />
<br />
(<br />
)<br />
(<br />
)<br />
1. 〈 α | c | β 〉 + c ′ | β ′ 〉 = c 〈 α | β 〉 + c ′ 〈 α | β ′ 〉 , c 〈 β | + c ′ 〈 β ′ | | α 〉 = c 〈 β | α 〉 + c ′ 〈 β ′ | α 〉
11 210<br />
2. 〈 α | α 〉 <br />
〈 α | α 〉 ≥ 0 ( | α 〉 )<br />
√ 〈 α | α 〉 | α 〉 <br />
3. | β 〉 = c | α 〉 〈 β | = c ∗ 〈 α | 〈 β | α 〉 = c ∗ 〈 α | α 〉 〈 α | α 〉 <br />
<br />
〈 β | α 〉 ∗ = c 〈 α | α 〉 = 〈 α | β 〉<br />
, <br />
〈 α | β 〉 = 〈 β | α 〉 ∗ (11.1)<br />
a·b = b·a <br />
| α 〉 ,<br />
| α ′ 〉 =<br />
1<br />
√<br />
〈 α | α 〉<br />
| α 〉<br />
〈 α ′ | α ′ 〉 = 1 1 ( normalization ) <br />
, <br />
〈 α | β 〉 = 0 , 2 <br />
11.2 <br />
, , <br />
( operator ) X , <br />
| α 〉 , X<br />
, | α 〉X, X〈 α | <br />
• , , c α c β <br />
(<br />
)<br />
(<br />
)<br />
X c α | α 〉 + c β | β 〉 = c α X| α 〉 + c β X| β 〉 , c α 〈 α | + c β 〈 β | X = c α 〈 α |X + c β 〈 β |X<br />
<br />
• XY = Y X , X Y <br />
( commute ) <br />
• 〈 α | X| β 〉 , 〈 α |X <br />
| β 〉 :<br />
〈 α | (X| β 〉) = (〈 α |X) | β 〉<br />
, 〈 α |X| β 〉 <br />
X ( Hermitian conjugate ) X † <br />
| γ 〉 = X| β 〉 <br />
〈 β |X † | α 〉 = 〈 α |X| β 〉 ∗ (11.2)<br />
〈 β |X † | α 〉 = 〈 α | γ 〉 ∗ = 〈 γ | α 〉 , 〈 γ | = 〈 β |X †<br />
X| β 〉 〈 β |X † 〈 β |X X = X † , X <br />
( Hermitian )
11 211<br />
1. <br />
〈 α |XY | β 〉 = 〈 β |(XY ) † | α 〉 ∗<br />
| γ 〉 = Y | β 〉 〈 γ | = 〈 β |Y † <br />
〈 α |XY | β 〉 = 〈 α |X| γ 〉 = 〈 γ |X † | α 〉 ∗ = 〈 β |Y † X † | α 〉 ∗<br />
<br />
(XY ) † = Y † X † (11.3)<br />
n <br />
2. (11.2) <br />
〈 β | ( X †) †<br />
| α 〉 = 〈 α |X † | β 〉 ∗ = 〈 β |X| α 〉<br />
( X †) †<br />
= X <br />
3. | α 〉〈 β | <br />
( )<br />
( )<br />
| α 〉〈 β | | γ 〉 = | α 〉〈 β | γ 〉 , 〈 γ | | α 〉〈 β | = 〈 γ | α 〉〈 β |<br />
| α 〉〈 β | | γ 〉 | α 〉 〈 β | γ 〉 <br />
, | α 〉〈 β | X = | α 〉〈 β | <br />
〈 α ′ |X| β ′ 〉 ∗ = 〈 β ′ |X † | α ′ 〉<br />
<br />
( )<br />
〈 α ′ |X| β ′ 〉 ∗ = (〈 α ′ | α 〉〈 β | β ′ 〉) ∗ = 〈 α | α ′ 〉〈 β ′ | β 〉 = 〈 β ′ | | β 〉〈 α | | α ′ 〉<br />
X † = | β 〉〈 α |, <br />
(<br />
| α 〉〈 β |) †<br />
= | β 〉〈 α |<br />
<br />
11.3 <br />
A :<br />
A| a 〉 = a| a 〉 (11.4)<br />
a | α 〉 A| α 〉 | α 〉 <br />
(11.4) | a 〉 a A <br />
( eigenvalue ) , | a 〉 , | a 〉 a <br />
(11.4) a | a 〉 <br />
, , ( A † = A ) , <br />
2
11 212<br />
1. <br />
(11.4) 〈 a | 〈 a |A| a 〉 = a〈 a | a 〉 ,<br />
(11.1) 〈 a | a 〉 <br />
a ∗ 〈 a | a 〉 = 〈 a |A| a 〉 ∗ = 〈 a |A † | a 〉 = 〈 a |A| a 〉 = a〈 a | a 〉<br />
, a = a ∗ a <br />
2. <br />
A 2 a, a ′ :<br />
A † = A a ′ , 2 <br />
A| a 〉 = a| a 〉 (11.5)<br />
A| a ′ 〉 = a ′ | a ′ 〉 (11.6)<br />
〈 a ′ |A = a ′ 〈 a ′ | (11.7)<br />
(11.5) 〈 a ′ | 〈 a ′ |A| a 〉 = a〈 a ′ | a 〉 , (11.7) | a 〉 〈 a ′ |A| a 〉 =<br />
a ′ 〈 a ′ | a 〉 2 <br />
(a − a ′ )〈 a ′ | a 〉 = 0<br />
, a ≠ a ′ 〈 a ′ | a 〉 = 0 , | a 〉 | a ′ 〉 <br />
<br />
⎧<br />
⎨ 1 , a ′ = a <br />
δ a′ a =<br />
⎩<br />
0 , a ′ ≠ a <br />
, <br />
〈 a ′ | a 〉 = δ a ′ a〈 a | a 〉<br />
〈 a | a 〉 = 1 <br />
〈 a ′ | a 〉 = δ a′ a (11.8)<br />
<br />
, <br />
, , <br />
:<br />
1. A , A 1 <br />
, A <br />
, a <br />
|〈 a | α 〉| 2<br />
, | α 〉 , | a 〉, | α 〉 <br />
<br />
2. , , <br />
,
11 213<br />
3. ( complete system ) , , | α 〉<br />
<br />
| α 〉 = ∑ a<br />
c a | a 〉 (11.9)<br />
(11.8) <br />
〈 a | α 〉 = ∑ a ′ c a ′〈 a | a ′ 〉 = ∑ a ′ c a ′δ a a ′ = c a (11.10)<br />
, a |c a | 2 <br />
, (11.9) , <br />
<br />
2. 3. ( observable ) <br />
(11.10) (11.9) <br />
| α 〉 = ∑ a<br />
| a 〉〈 a | α 〉 =<br />
( ∑<br />
a<br />
| a 〉〈 a |<br />
)<br />
| α 〉<br />
| α 〉 ∑ a<br />
| a 〉〈 a | <br />
∑<br />
| a 〉〈 a | = 1 (11.11)<br />
a<br />
( completeness ) , A <br />
, <br />
∑<br />
|〈 a | α 〉| 2 = ∑ ( )<br />
∑<br />
〈 α | a 〉〈 a | α 〉 = 〈 α | | a 〉〈 a | | α 〉 = 〈 α | α 〉 = 1<br />
a<br />
a<br />
a<br />
, | α 〉 A () 〈A〉 α <br />
〈A〉 α = ∑ a<br />
a|〈 a | α 〉| 2 = ∑ a<br />
a〈 α | a 〉〈 a | α 〉 = ∑ a<br />
〈 α |A| a 〉〈 a | α 〉 = 〈 α |A| α 〉 (11.12)<br />
<br />
(11.8) (11.11) <br />
, 3 3 e i <br />
(11.8) , e i e i·e j = δ ij <br />
A i A i A i = e i·A <br />
A =<br />
3∑<br />
i=1<br />
A i e i = ∑ i<br />
e i (e i·A)<br />
<br />
| α 〉 = ∑ a<br />
| a 〉〈 a | α 〉<br />
,
11 214<br />
11.1<br />
<br />
<br />
2 | 1 〉 , | 2 〉 E 0 , λ <br />
(<br />
)<br />
H = E 0 | 1 〉〈 1 | − E 0 | 2 〉〈 2 | + λ | 1 〉〈 2 | + | 2 〉〈 1 |<br />
1. H <br />
2. | 1 〉 , | 2 〉 , H c 1 , c 2 <br />
c 1 | 1 〉 + c 2 | 2 〉<br />
H <br />
11.4 <br />
, 1,2,· · · <br />
<br />
α i = 〈 i | α 〉 , X ij = 〈 i |X| j 〉 , i, j = 1, 2, 3, · · ·<br />
| i 〉 <br />
<br />
⎛ ⎞<br />
α ≡<br />
⎜<br />
⎝<br />
α 1<br />
α 2<br />
.<br />
⎟<br />
⎠ , α† = (α1 ∗ α2 ∗ · · · ) , X ≡ ⎜<br />
⎝<br />
⎛<br />
⎞<br />
X 11 X 12 · · ·<br />
X 21 X 22 · · · ⎟<br />
⎠<br />
.<br />
. . ..<br />
, <br />
〈 α |X| β 〉 = ∑ ij<br />
〈 α | i 〉〈 i |X| j 〉〈 j | β 〉 = α † Xβ<br />
, | β 〉 = X| α 〉 〈 i | β 〉 = 〈 i |X| α 〉 = ∑ j<br />
〈 i |X| j 〉〈 j | α 〉 <br />
β i = ∑ j<br />
X ij α j = (Xα) i β = Xα<br />
<br />
→ , → , → <br />
, | i 〉 <br />
, <br />
⎛ ⎞<br />
1<br />
0<br />
| 1 〉 ⇒<br />
⎜<br />
⎝<br />
0 ⎟<br />
⎠ ,<br />
.<br />
A | a 〉 a<br />
⎛ ⎞<br />
0<br />
| 2 〉 ⇒ 1<br />
⎜<br />
⎝<br />
0 ⎟<br />
⎠ , · · ·<br />
.<br />
A| a 〉 = a| a 〉
11 215<br />
| a 〉 a <br />
A <br />
Aa = a a , A ij = 〈 i|A| j〉 (11.13)<br />
A ∗ ij = 〈 i |A| j 〉 ∗ = 〈 j |A † | i 〉 = 〈 j |A| i 〉 = A ji<br />
, A (11.13) <br />
, a <br />
det (A ij − a δ ij ) = 0<br />
<br />
11.2 11.1 <br />
( ) ( )<br />
1<br />
0<br />
| 1 〉 ⇒ , | 2 〉 ⇒<br />
0<br />
1<br />
, H , H <br />
<br />
11.5 <br />
2 A, B AB − BA = 0 <br />
〈 a ′ | (AB − BA) | a 〉 = (a ′ − a)〈 a ′ |B| a 〉 = 0<br />
,<br />
〈 a ′ |B| a 〉 = δ a′ a〈 a |B| a 〉<br />
| a ′ 〉 a ′ <br />
∑<br />
a ′ | a ′ 〉〈 a ′ |B| a 〉 = ∑ a ′ | a ′ 〉δ a′ a〈 a |B| a 〉 = | a 〉〈 a |B| a 〉<br />
(11.11) <br />
B| a 〉 = | a 〉〈 a |B| a 〉<br />
, | a 〉 A , b = 〈 a |B| a 〉 B <br />
A B | a, b 〉 <br />
<br />
A|a, b〉 = a| a, b 〉 , B| a, b 〉 = b| a, b 〉<br />
<br />
a 1 , | a 〉 <br />
, | a, b 〉 b , 1 2 a <br />
( ( degeneracy ) ), b , b <br />
a b | a, b 〉 , <br />
<br />
∑<br />
〈 a, b | a ′ , b ′ 〉 = δ a a ′δ b b ′ , | a, b 〉〈 a, b | = 1<br />
a,b
11 216<br />
, 3 <br />
A, B, C,· · · <br />
, 1 a, b, c, · · · , A, B, C,· · · | a, b, c, · · · 〉 <br />
1 , <br />
∑<br />
〈 a, b, c, · · · | a ′ , b ′ , c ′ , · · · 〉 = δ a a ′δ b b ′δ c c ′ · · · , | a, b, c, · · · 〉〈a, b, c, · · · | = 1<br />
<br />
a,b,c,···<br />
11.6 <br />
, , <br />
, <br />
Q, q (11.4) <br />
Q| q 〉 = q| q 〉<br />
f(q) g(q) <br />
∫<br />
∫<br />
| α 〉 = dq f(q)| q 〉 , | β 〉 =<br />
dq g(q)| q 〉 (11.14)<br />
q <br />
∫ ∫<br />
∫<br />
∫<br />
〈 α | β 〉 = dq f ∗ (q) dq ′ g(q ′ )〈 q | q ′ 〉 = dq f ∗ (q)G(q) , G(q) =<br />
dq ′ g(q ′ )〈 q | q ′ 〉<br />
, q ′ ≠ q 〈 q | q ′ 〉 = 0 , 〈 q | q 〉 <br />
G(q) = 0 , 〈 α | β 〉 = 0 〈 α | β 〉 <br />
, 〈 q | q 〉 G(q) <br />
, , (11.8) <br />
<br />
〈 q | q ′ 〉 = δ(q − q ′ ) (11.15)<br />
G(q) = g(q) <br />
∫<br />
〈 α | β 〉 =<br />
dq f ∗ (q) g(q)<br />
, <br />
| q 〉 , | α 〉 (11.14) <br />
∫<br />
∫<br />
〈q| α 〉 = dq ′ f(q ′ )〈 q | q ′ 〉 = dq ′ f(q ′ )δ(q − q ′ ) = f(q)<br />
<br />
∫<br />
| α 〉 =<br />
∫<br />
dq | q 〉f(q) =<br />
dq | q 〉〈 q | α 〉<br />
<br />
∫<br />
dq | q 〉〈 q | = 1 (11.16)
11 217<br />
| α 〉 , A , a <br />
|〈 a | α 〉| 2 , Q q q + dq <br />
<br />
|〈q| α 〉| 2 dq<br />
(11.16) <br />
∫<br />
∫<br />
(∫<br />
dq |〈 q | α 〉| 2 = dq 〈 α | q 〉〈 q | α 〉 = 〈 α |<br />
)<br />
dq | q 〉〈 q | | α 〉 = 〈 α | α 〉 = 1<br />
| α 〉 Q 〈Q〉 α <br />
∫<br />
∫<br />
〈Q〉 α = dq q|〈 q | α 〉| 2 = dq q〈 α | q 〉〈 q | α 〉<br />
∫<br />
(∫ )<br />
= dq 〈 α |Q| q 〉〈 q | α 〉 = 〈 α |Q dq | q 〉〈 q | | α 〉<br />
= 〈 α |Q| α 〉<br />
, (11.12) <br />
11.7 , <br />
1 ˆx , ˆp <br />
, ˆˆx ˆp <br />
[ ˆx , ˆp ] ≡ ˆxˆp − ˆpˆx = i (11.17)<br />
ˆx | x 〉<br />
ˆx| x 〉 = x| x 〉 , 〈 x |x ′ 〉 = δ(x − x ′ )<br />
ˆx , x <br />
(11.17) <br />
[ ˆx , ˆp 2 ] = ˆp [ ˆx , ˆp ] + [ ˆx , ˆp ]ˆp = 2i ˆp , [ ˆx , ˆp 3 ] = ˆp [ ˆx , ˆp 2 ] + [ ˆx , ˆp ]ˆp 2 = 3i ˆp 2<br />
[ ˆx , ˆp n ] = n i ˆp n−1 , <br />
[ ˆx , F (ˆp) ] = iF ′ (ˆp) (11.18)<br />
F ′ (x) F (x) , S(x) = e −iαx/ <br />
[ ˆx , S(ˆp) ] = αS(ˆp)<br />
<br />
<br />
(<br />
)<br />
ˆxS(ˆp) − S(ˆp)ˆx | x 〉 = ˆxS(ˆp)| x 〉 − xS(ˆp)| x 〉 = αS(ˆp)| x 〉<br />
ˆxS(ˆp)| x 〉 = (x + α) S(ˆp)| x 〉<br />
S(ˆp)| x 〉 ˆx x + α <br />
S(ˆp)| x 〉 = | x + α 〉
11 218<br />
α → 0 S(ˆp) = 1 − iαˆp/ <br />
<br />
| x + α 〉 − | x 〉<br />
ˆp | x 〉 = i lim<br />
= i ∂<br />
α→0 α<br />
∂x | x 〉<br />
〈 x | ˆp | x ′ 〉 = i ∂<br />
∂x ′ 〈 x | x′ 〉 = i ∂<br />
∂x ′ δ(x − x′ ) = − i ∂<br />
∂x δ(x − x′ ) (11.19)<br />
∂ x = ∂<br />
∂x <br />
∫<br />
∫ ( )<br />
〈 x | ˆp 2 | x ′ 〉 = dy 〈 x | ˆp | y 〉〈 y | ˆp | x ′ 〉 = (−i) 2 dy ∂ x δ(x − y) ∂ y δ(y − x ′ )<br />
∫<br />
= (−i) 2 ∂ x dy δ(x − y)∂ y δ(y − x ′ )<br />
= (−i∂ x ) 2 δ(x − x ′ )<br />
<br />
〈 x | ˆp n | x ′ 〉 = (−i∂ x ) n δ(x − x ′ )<br />
F (ˆp) <br />
〈 x |F (ˆp)| x ′ 〉 = F (−i∂ x ) δ(x − x ′ ) (11.20)<br />
〈 x | x ′ 〉 = δ(x − x ′ ) <br />
〈 x |F (ˆp)| x ′ 〉 = F (−i∂ x ) 〈 x | x ′ 〉<br />
〈 x ′ | x ′ (11.20) <br />
〈 x |F (ˆp) = F (−i∂ x ) 〈 x | (11.21)<br />
, | α 〉 <br />
〈 x |F (ˆp)| α 〉 = F (−i∂ x ) 〈 x | α 〉 (11.22)<br />
, ˆx F (ˆx) 〈 x |F (ˆx) = 〈 x |F (x) <br />
〈 x |F (ˆx)| x ′ 〉 = F (x)〈 x | x ′ 〉 = F (x)δ(x − x ′ ) , 〈 x |F (ˆx)| α 〉 = F (x)〈 x | α 〉 (11.23)<br />
F (ˆx) , F (x) <br />
, | x 〉 1 <br />
, ˆp −i∂ x <br />
1. ψ α (x) = 〈 x | α 〉 <br />
∫<br />
| α 〉 = dx | x 〉 ψ α (x)<br />
x x + dx <br />
|〈 x | α 〉| 2 dx = |ψ α (x)| 2 dx<br />
<br />
∫<br />
〈 α | α 〉 =<br />
∫<br />
dx 〈 α | x 〉〈 x | α 〉 =<br />
dx |ψ α (x)| 2 = 1<br />
ψ α (x) | α 〉 <br />
| x 〉
11 219<br />
2. 〈 β |A| α 〉 <br />
∫<br />
〈 β |A| α 〉 =<br />
∫<br />
∫ ∫<br />
dx dx ′ 〈 β | x 〉〈 x |A| x ′ 〉〈 x ′ | α 〉 = dx dx ′ ψβ(x)〈 ∗ x |A| x ′ 〉ψ α (x ′ )<br />
〈 β |A| α 〉 , 2 x x ′<br />
<br />
〈 x |A| x ′ 〉 , A ˆx ˆp , (11.22) (11.23) <br />
∫<br />
∫<br />
〈 β |F (ˆx)| α 〉 = dx〈 β | x 〉〈 x |F (ˆx)| α 〉 = dx ψβ(x)F ∗ (x)ψ α (x)<br />
<br />
∫<br />
∫<br />
〈 β |F (ˆp)| α 〉 = dx〈 β | x 〉〈 x |F (ˆp)| α 〉 = dx ψβ(x)F ∗ (−i∂ x ) ψ α (x) (11.24)<br />
3. t | t 〉 , | t 〉 <br />
( )<br />
ˆp<br />
2<br />
2m + V (ˆx) | t 〉 = i d dt | t 〉 (11.25)<br />
, m , V 〈 x | <br />
, (11.22) (11.23) <br />
(− 2<br />
∂ 2 )<br />
2m ∂x 2 + V (x) ψ(x, t) = i ∂ ψ(x, t) , ψ(x, t) = 〈 x | t 〉 (11.26)<br />
∂t<br />
(11.24), (11.26) <br />
, , ˆp −i∂ x <br />
4. ˆp | p 〉<br />
ˆp | p 〉 = p | p 〉 (11.27)<br />
u p (x) = 〈 x | p 〉 (11.22) 〈 x | ˆp | p 〉 = −i ∂<br />
∂x 〈 x | p 〉 ,<br />
u p (x) <br />
−i ∂<br />
∂x u p(x) = p u p (x)<br />
<br />
u p (x) = N p exp (ipx/)<br />
N p 〈 p | p ′ 〉 = δ(p − p ′ ) <br />
∫<br />
∫<br />
〈 p | p ′ 〉 = dx 〈 p | x 〉〈 x | p ′ 〉 = Np ∗ N p ′ dx exp (i(p ′ − p)x/) = |N p | 2 2π δ(p − p ′ )<br />
, N p = 1/ √ 2π <br />
u p (x) = 1 √<br />
2π<br />
exp (ipx/) (11.28)<br />
| α 〉 | p 〉 ψ α (p) = 〈p| α 〉 <br />
∫<br />
∫<br />
ψ α (p) = dx 〈 p | x 〉〈 x | α 〉 = dx u p (x) ∗ ψ α (x) = √ 1 ∫<br />
dx exp (−ipx/) ψ α (x)<br />
2π<br />
<br />
∫<br />
ψ α (x) =<br />
dp 〈 x | p 〉〈 p | α 〉 = √ 1 ∫<br />
dp exp (ipx/) ψ α (p)<br />
2π
11 220<br />
5. A | a 〉 <br />
| α 〉 = ∑ a<br />
| a 〉〈 a | α 〉<br />
<br />
ψ α (x) = 〈 x | α 〉 = ∑ a<br />
〈 x | a 〉〈 a | α 〉 = ∑ a<br />
c a u a (x)<br />
<br />
c a = 〈 a | α 〉 , u a (x) = 〈 x | a 〉<br />
u a (x) A | a 〉 , ( eigenfunction ) <br />
<br />
<br />
∑<br />
| a 〉〈 a | = 1<br />
a<br />
∑<br />
〈 x | a 〉〈 a | x ′ 〉 = 〈 x | x ′ 〉 = δ(x − x ′ )<br />
a<br />
<br />
∑<br />
u a (x) u ∗ a(x ′ ) = δ(x − x ′ )<br />
a<br />
<br />
3 ˆx | x 〉<br />
ˆx| x 〉 = x| x 〉 , ˆx = (ˆx, ŷ, ẑ) , x = (x, y, z)<br />
<br />
〈 x | x ′ 〉 = δ(x − x ′ ) ,<br />
∫<br />
d 3 x | x 〉〈 x | = 1<br />
ˆp | x 〉 − i∇ <br />
11.3<br />
ˆp | p 〉 | α 〉 <br />
〈 p | ˆx | α 〉 = i ∂〈 p | α 〉<br />
∂p<br />
(11.28) , (11.25) <br />
( p<br />
2<br />
(i<br />
2m + V ∂ ))<br />
ψ(p, t) = i ∂ ψ(p, t) , ψ(p, t) = 〈 p | t 〉<br />
∂p<br />
∂t
12 221<br />
12 <br />
12.1 <br />
c 1 , c 2 <br />
T <br />
| a 〉 = c 1 |a 1 〉 + c 2 |a 2 〉 <br />
<br />
(<br />
) ( ) ( )<br />
T c 1 |a 1 〉 + c 2 |a 2 〉 = c ∗ 1 T |a 1 〉 + c ∗ 2 T |a 2 〉<br />
[ ( )] ∗ [ ( )] ∗ [ ( )] ∗<br />
〈 b | T | a 〉 = c1 〈 b | T | a 1 〉 + c2 〈 b | T | a 2 〉<br />
[ ( ∗<br />
〈 b | T | a 〉)]<br />
| a 〉 <br />
[ ( ] ∗<br />
〈 b | T | a 〉)<br />
= 〈 b ′ | a 〉<br />
〈 b ′ | <br />
〈 b ′ | = 〈 b |T<br />
<br />
(<br />
F 〈 b |<br />
( )<br />
〈 b |<br />
T | a 〉<br />
≠<br />
(<br />
〈 b |T<br />
<br />
[ ( ) ] ∗ ( )<br />
〈 b | T | a 〉 = 〈 b |T | a 〉 (12.1)<br />
) ( )<br />
F | a 〉 = 〈 b |F | a 〉 , <br />
)<br />
| a 〉 , T <br />
[(<br />
) ] [(<br />
)( )] ∗<br />
c 1 〈 a 1 | + c 2 〈 a 2 | T | b 〉 = c 1 〈 a 1 | + c 2 〈 a 2 | T | b 〉<br />
= c ∗ 1<br />
= c ∗ 1<br />
[ ( )] ∗ [ ( )] ∗<br />
〈 a 1 | T | b 〉 + c<br />
∗<br />
2 〈 a 2 | T | b 〉<br />
( ) ( )<br />
〈 a 1 |T | b 〉 + c ∗ 2 〈 a 2 |T | b 〉<br />
<br />
(<br />
) ( ) ( )<br />
c 1 〈 a 1 | + c 2 〈 a 2 | T = c ∗ 1 〈 a 1 |T + c ∗ 2 〈 a 2 |T<br />
, T <br />
2 T 1 , T 2 T 1 T 2 <br />
| b 2 〉 = T 2 | b 〉 <br />
〈 a |(T 1 T 2 )| b 〉 = 〈 a | (T 1 | b 2 〉) =<br />
〈 a |(T 1 T 2 )| b 〉 = 〈 a | (T 1 T 2 | b 〉) = (〈 a |T 1 T 2 ) | b 〉<br />
〈 a |(T 1 T 2 )| b 〉 <br />
[<br />
] ∗ [<br />
∗<br />
(〈 a |T 1 ) | b 2 〉 = (〈a|T 1 )(T 2 | b 〉)]<br />
≠ (〈a|T1 )(T 2 | b 〉)<br />
<br />
| b 〉 = T | a 〉 <br />
〈 b | = 〈 a |T †
12 222<br />
T † T † <br />
( )<br />
(<br />
〈 c | T | a 〉 = 〈 c | b 〉 = 〈 b | c 〉 ∗ = 〈 a |T †) ( )<br />
| c 〉 ∗ = 〈 a | T † | c 〉<br />
(12.2)<br />
F 〈 c |F | a 〉 = 〈 a |F † | c 〉 ∗ <br />
<br />
T <br />
T T † = T † T = 1<br />
, T T , 1 <br />
| a 〉 = T |a〉 , 〈 a | = 〈a|T † , F = T F T †<br />
, F <br />
T 〈 a 1 | F | a 2 〉 = 〈 a 1 |F | a 2 〉 , , <br />
T F T † <br />
〈 a 1 | F | a 2 〉 =<br />
(<br />
〈 a 1 |T †)( T F T †)( ) (<br />
T | a 2 〉 = 〈 a 1 |T †)( ) (<br />
T F T † T | a 2 〉 = 〈 a 1 |T †)( )<br />
T F | a 2 〉<br />
(12.1) <br />
〈 a 1 | F | a 2 〉 =<br />
[( )(<br />
∗<br />
〈 a 1 |T † T F | a 2 〉)]<br />
= 〈 a1 |F | a 2 〉 ∗ (12.3)<br />
<br />
[ x , p ] <br />
[ x , p ] = T xT † T pT † − T pT † T xT † = T (xp − px) T † = T i T † = − i T T † = − i<br />
c T c T † = c ∗ , <br />
<br />
12.2 <br />
{ | a 〉 } K A <br />
K A | a 〉 = | a 〉 (12.4)<br />
K A | α 〉 <br />
∑<br />
K A | α 〉 = K A | a 〉〈 a | α 〉 = ∑ 〈 a | α 〉 ∗ K A | a 〉 = ∑ 〈 a | α 〉 ∗ | a 〉 (12.5)<br />
a<br />
a<br />
a<br />
〈 a | α 〉 K A | α 〉 = | α 〉 , 〈 a | α 〉 <br />
| α 〉 K A | α 〉 = | α 〉 K A ≠ 1 , K A <br />
(12.4) K A 1 <br />
KA 2 <br />
∑<br />
KA| 2 α 〉 = K A 〈 a | α 〉 ∗ | a 〉 = ∑ 〈 a | α 〉 | a 〉 = | α 〉<br />
a<br />
a
12 223<br />
<br />
<br />
K † A | α 〉 = ∑ a<br />
<br />
)<br />
| a 〉〈 a |<br />
(K † A | α 〉 = ∑ a<br />
K 2 A = 1 (12.6)<br />
[( ) ] ∗ ∑<br />
| a 〉 〈 a |K † A<br />
| α 〉 = | a 〉〈 a | α 〉 ∗ = K A | α 〉<br />
a<br />
K † A = K A (12.7)<br />
(12.6) (12.7) K † A K A = K A K † A = K2 A = 1, K A <br />
{| a 〉} | α 〉 ψ α (a) = 〈 a | α 〉 , | α 〉 = K A | α 〉 <br />
(12.5) <br />
( )<br />
ψ α (a) ≡ 〈 a | K A | α 〉 = 〈 a | α 〉 ∗ = ψα(a)<br />
∗<br />
K A {| a 〉} <br />
, F = K A F K † A | a 〉 = K A| a 〉 = | a 〉 (12.3) <br />
〈 a | F | a ′ 〉 = 〈 a | F | a ′ 〉 = 〈 a | F | a ′ 〉 ∗<br />
a, a ′ 〈 a | F | a ′ 〉 , F <br />
<br />
<br />
K A F K † A = ⎧<br />
⎨<br />
⎩<br />
F ,<br />
− F ,<br />
〈 a | F | a ′ 〉 <br />
〈 a | F | a ′ 〉 <br />
{ | a 〉 } { | b 〉 } K A K B <br />
K B | b 〉 = | b 〉<br />
(12.8)<br />
|α〉 <br />
∑<br />
K B | α 〉 = K B | b 〉〈 b | α 〉 = ∑ | b 〉〈 b | α 〉 ∗ = ∑<br />
b<br />
b<br />
ba<br />
| b 〉〈 b | a 〉 ∗ 〈 a | α 〉 ∗<br />
〈 a | b 〉 a, b <br />
K B | α 〉 = ∑ ba<br />
| b 〉〈 b | a 〉〈 a | α 〉 ∗ = ∑ a<br />
| a 〉〈 a | α 〉 ∗ = K A | α 〉<br />
K B = K A , 〈 a | b 〉 K B ≠ K A <br />
K B | a 〉 = | a 〉 K <br />
T <br />
T = T K 2 = F K ,<br />
F = T K<br />
T K F , <br />
K
12 224<br />
12.3 : 0 <br />
<br />
<br />
dp(t)<br />
dt<br />
= F (r(t)) , p(t) = m dr(t)<br />
dt<br />
r(t) = r(−t) (12.9)<br />
( s = −t )<br />
p(t) = m dr(t)<br />
dt<br />
dp(t)<br />
dt<br />
= − dp(s)<br />
dt<br />
= m ds dr(s)<br />
= −p(s) = −p(−t) (12.10)<br />
dt ds<br />
= dp(s)<br />
ds<br />
= F (r(s)) = F (r(t))<br />
, , r(t) <br />
<br />
<br />
∂ψ(r, t)<br />
i =<br />
∂t<br />
(− 2<br />
2m ∇2 + V (r)<br />
)<br />
ψ(r, t)<br />
<br />
ψ(r, t) ≡ ψ ∗ (r, −t)<br />
<br />
<br />
∂ψ(r, t)<br />
i<br />
∂t<br />
= i ds ∂ψ ∗ [<br />
(r, s)<br />
= −i ∂ψ∗ (r, s)<br />
= i<br />
dt ∂s<br />
∂s<br />
] ∗<br />
∂ψ(r, s)<br />
∂s<br />
)<br />
∗ )<br />
∂ψ(r, t)<br />
i =<br />
[(− 2<br />
∂t 2m ∇2 + V (r) ψ(r, s)]<br />
=<br />
(− 2<br />
2m ∇2 + V (r) ψ(r, t)<br />
ψ(r, t) = ψ ∗ (r, −t) t − t ψ(r, −t) <br />
<br />
<br />
∫<br />
∫<br />
r av (t) = d 3 r rψ ∗ (r, t)ψ(r, t) , r av (t) = d 3 r rψ ∗ (r, t)ψ(r, t)<br />
∫<br />
p av (t) = −i d 3 r ψ ∗ (r, t)∇ψ(r, t) ,<br />
∫<br />
p av (t) = −i d 3 r ψ ∗ (r, t)∇ψ(r, t)<br />
ψ(r, t) <br />
r av (t) = r av (−t) (12.11)<br />
, <br />
∫<br />
p av (t) = i d 3 r ψ ∗ (r, −t)∇ψ(r, −t) = − p av (−t) (12.12)<br />
(12.11) (12.12) (12.9) (12.10) <br />
, ψ(r, t) ψ ∗ (r, −t) <br />
ˆx ˆp , T <br />
T ˆxT † = ˆx , T ˆpT † = − ˆp , T T † = T † T = 1 (12.13)
12 225<br />
T <br />
ˆx | r 〉<br />
ˆx| r 〉 = r| r 〉<br />
<br />
K| r 〉 = | r 〉 , KK † = K † K = 1 (12.14)<br />
ˆx, ˆp <br />
〈 r | ˆx | r ′ 〉 = rδ(r − r ′ ) = , 〈 r | ˆp | r ′ 〉 = − i ∂δ(r − r′ )<br />
∂r<br />
= <br />
, (12.8) <br />
K ˆxK † = ˆx ,<br />
K ˆpK † = − ˆp<br />
T = K <br />
H <br />
, (12.13) <br />
H = ˆp2<br />
2m + V (ˆx)<br />
T HT † = H , [ H , T ] = 0<br />
H <br />
i ∂ ∂t | t 〉 = H| t 〉<br />
T , T i = −iT , T H = HT <br />
−i ∂ ∂t T | t 〉 = HT | t 〉<br />
<br />
i ∂ ∂t T | − t 〉 = HT | − t 〉<br />
| t 〉 | t 〉 ≡ T | − t 〉 <br />
( ) [( ) ∗<br />
ψ(r, t) ≡ 〈 r | T | − t 〉 = 〈 r |T | − t 〉]<br />
= 〈 r | − t 〉 ∗ = ψ ∗ (r, −t)<br />
ˆx, ˆp (12.13) <br />
〈 t | ˆx | t 〉 =<br />
[ (<br />
∗<br />
〈− t | T † ˆxT | − t 〉)]<br />
= 〈− t | ˆx | − t 〉 ∗ = 〈− t | ˆx | − t 〉<br />
〈 t | ˆp | t 〉 = − 〈− t | ˆp | − t 〉 (12.11), (12.12) <br />
| α 〉 | α 〉 = T | α 〉 , <br />
, ψ α (r) = ψ ∗ α(r) , | p 〉 <br />
ˆpT = − T ˆp <br />
ˆp | p 〉 = − p | p 〉 , | p 〉 ≡ T | p 〉<br />
, | p 〉 = | − p 〉 | p 〉 <br />
ψ p (r) <br />
ψ p (r) =<br />
1<br />
exp (ip·r/)<br />
(2π)<br />
3/2
12 226<br />
<br />
<br />
ψ p (r) = ψ ∗ p(r) =<br />
1<br />
(2π) 3/2 exp (−ip·r/) = ψ −p(r)<br />
L = ˆx× ˆp T LT † = − L , L 2 T L z <br />
, L 2 , L z | l, m 〉<br />
L 2 | l, m 〉 = 2 l(l + 1)| l, m 〉 , L z | l, m 〉 = m| l, m 〉<br />
| l, m 〉 , | l, −m 〉 | l, m 〉 <br />
Y lm (θ, φ) | l, m 〉 Ylm ∗ (θ, φ) <br />
Y ∗<br />
lm(θ, φ) = (−1) m Y lm (θ, φ)<br />
, | l, m 〉 = (−1) m | l, −m 〉 , L z ≠ 0 <br />
, z , L z <br />
| α 〉 H :<br />
H| α 〉 = E α | α 〉<br />
T , E α <br />
T H| α 〉 = E α T | α 〉<br />
H , H T <br />
HT | α 〉 = E α T | α 〉 (12.15)<br />
, T | α 〉 H | α 〉 E α <br />
T | α 〉 = e iθ | α 〉<br />
<br />
ψ α (r) = ψ ∗ α(r) = e iθ ψ α (r)<br />
e iθ/2 ψ α (r) ψ α (r) ψα(r) ∗ = ψ α (r) , <br />
, <br />
12.1 | α 〉 H T<br />
F 〈 α | F | α 〉 0 <br />
12.2 | p 〉 <br />
K p | p 〉 = | p 〉<br />
T T = P K p P <br />
P ˆxP † = − ˆx , P ˆpP † = − ˆp , P † = P<br />
ψ α (p) = 〈 p | α 〉 <br />
ψ α (p) = ψα(− ∗ p)<br />
| p 〉 ,
12 227<br />
12.4 : 0 <br />
S ˆx× ˆp <br />
T ˆx× ˆpT † = − ˆx× ˆp<br />
<br />
<br />
T ˆxT † = ˆx , T ˆpT † = − ˆp , T ST † = − S (12.16)<br />
T <br />
ˆx, S 2 , S z | r, m 〉 :<br />
ˆx| r, m 〉 = r| r, m 〉 , S 2 | r, m 〉 = s(s + 1)| r, m 〉 , S z | r, m 〉 = m| r, m 〉<br />
(12.14) K <br />
K| r, m 〉 = | r, m 〉 (12.17)<br />
S ± ≡ S x ± iS y <br />
〈m|S + |m ′ 〉 = δ m m′ +1√<br />
s(s + 1) − m′ (m ′ + 1) , 〈m|S − |m ′ 〉 = δ m m′ −1√<br />
s(s + 1) − m′ (m ′ − 1)<br />
, 〈 m |S| m ′ 〉 S z S x = (S + + S − )/2 , S y = (S + − S − )/(2i)<br />
(12.8) <br />
K ˆxK † = ˆx , K ˆpK † = − ˆp<br />
KS x K † = S x , KS y K † = − S y , KS z K † = S z<br />
K (12.16) <br />
, , T F T = F K , (12.16) <br />
F K 2 = 1 F = T K, F † = K † T † , K <br />
(12.16) <br />
F ˆxF † = ˆx , F ˆpF † = ˆp<br />
F S x F † = − S x , F S y F † = S y , F S z F † = − S z<br />
F S x S z , y π <br />
<br />
F = η e −iπSy/ , |η| 2 = 1<br />
η , <br />
T <br />
T = η e −iπSy/ K (12.18)<br />
, K (12.17) Kis y K = is y K <br />
K 2 = 1 KiS y = iS y K K iS y <br />
T = η e −iπSy/ K = Kη ∗ e −iπSy/ ,<br />
T 2 = e −2πiSy/ = (−1) 2s<br />
T 2 = (−1) 2s , S 2 , S y
12 228<br />
1/2 <br />
e −iπS y<br />
= e −iπσ y/2 = cos(π/2) − iσ y sin(π/2) = −iσ y<br />
<br />
T = − iσ y K = −Kiσ y , T 2 = cos π − iσ y sin π = − 1<br />
T † T = T T † = 1 T † = − T , (12.2) <br />
, | α 〉 <br />
( ) ( ) ( )<br />
〈 α | T | α 〉 = 〈 α | T † | α 〉 = − 〈 α | T | α 〉 = 0<br />
| α 〉 T | α 〉 <br />
| α 〉 H , H , (12.15)<br />
T | α 〉 H 1/2 | α 〉 T | α 〉 ,<br />
H 2 , <br />
n 1/2 , k S (k)<br />
, (12.18) S y y <br />
<br />
T 2 =<br />
n∏<br />
k=1<br />
n∑<br />
k=1<br />
S (k)<br />
y<br />
e −2πiS(k) y / = (−1) n<br />
, 1/2 <br />
<br />
( ) [( ) ] ∗<br />
〈 r, m | α 〉 = − 〈 r, m | Kiσ y | α 〉 = − 〈 r, m |K iσ y | α 〉<br />
= i 〈 r, m | σ y | α 〉 ∗ = i ∑ m ′ 〈 m | σ y | m ′ 〉 ∗ 〈 r, m ′ | α 〉 ∗<br />
<br />
ψ α (r) =<br />
(<br />
0 −1<br />
1 0<br />
)<br />
ψ ∗ α(r)<br />
ψ 2 <br />
12.3<br />
ψ α (5.53) n·σ ± 1 <br />
ψ α n·σ ∓ 1
13 229<br />
13 <br />
13.1 <br />
B , <br />
( B = ∇×A = 0 ) ,<br />
A ≠ 0 <br />
<br />
<br />
AB q <br />
( ρ , θ , z ) B <br />
{<br />
B ez , ρ ≤ a<br />
B =<br />
0 , ρ > a<br />
B = 0 D<br />
y<br />
a<br />
B ≠0 a<br />
Dρ 1 ρ 2<br />
x<br />
D = {( ρ , θ , z ) | ρ 1 ≤ ρ ≤ ρ 2 , − d ≤ z ≤ d } ,<br />
ρ 1 > a<br />
x = ρ cos θ , y = ρ sin θ <br />
∂<br />
∇ = e ρ<br />
∂ρ + e θ<br />
ρ<br />
∂<br />
∂θ + e ∂<br />
z<br />
∂z , e ρ = e x cos θ + e y sin θ , e θ = − e x sin θ + e y cos θ (13.1)<br />
, A = A(ρ) e θ , xy ρ C <br />
∮<br />
dr·A(r) = 2πρA(ρ)<br />
C<br />
<br />
∮<br />
∫<br />
∫ {<br />
πρ 2 B , ρ ≤ a<br />
dr·A(r) = dS·(∇×A) = dS·B =<br />
C<br />
S<br />
S<br />
πa 2 B , ρ > a<br />
<br />
ρ > a D <br />
A =<br />
⎧<br />
⎪⎨<br />
A(ρ) =<br />
⎪⎩<br />
Bρ<br />
2 , ρ ≤ a<br />
πa 2 B<br />
2πρ ,<br />
ρ > a<br />
Φ<br />
2πρ e θ , Φ = πa 2 B = (13.2)<br />
de ρ /dθ = e θ , de θ /dθ = − e ρ <br />
H = −<br />
(∇ 2<br />
− i q ) 2<br />
2m c A 2 [<br />
∂<br />
= − e ρ<br />
2m ∂ρ + e θ<br />
ρ<br />
[<br />
= − 2 ∂ 2<br />
2m ∂ρ 2 + 1 ∂<br />
ρ<br />
( ) ] 2<br />
∂<br />
∂θ − iα ∂<br />
+ e z<br />
∂z<br />
∂ρ + 1 ( ) ]<br />
2 ∂<br />
ρ 2 ∂θ − iα + ∂2<br />
∂z 2<br />
<br />
α =<br />
q Φ<br />
2πc = Φ Φ 0<br />
,<br />
Φ 0 = 2πc<br />
q
13 230<br />
ψ(r) = ϕ(ρ, θ) Z(z) Hψ = Eψ <br />
[<br />
− 2 ∂ 2<br />
2m ∂ρ 2 + 1 ∂<br />
ρ ∂ρ + 1 ( ) ] 2 ∂<br />
ρ 2 ∂θ − iα ϕ(ρ, θ) = E ′ ϕ(ρ, θ) ,<br />
dZ<br />
2m dz 2 = E zZ(z)<br />
− 2<br />
E = E ′ + E z <br />
k z = √ 2mE z / 2 d 2 Z/dz 2 = − k 2 zZ Z(−d) = 0 <br />
Z = C z sin k z (z + d) ,<br />
C z = <br />
Z(d) = 0 sin 2dk z = 0 <br />
k z = nπ<br />
(<br />
2d , E z = k2 z<br />
2m = 2 nπ<br />
) 2<br />
, n = 1, 2, 3, · · ·<br />
2m 2d<br />
Z <br />
ϕ <br />
<br />
e iαθ ∂ ∂θ e−iαθ ϕ(ρ, θ) =<br />
( ∂<br />
∂θ − iα )<br />
ϕ(ρ, θ)<br />
iαθ ∂2<br />
e<br />
∂θ 2 e−iαθ ϕ(ρ, θ) = e iαθ ∂ ∂θ e−iαθ e iαθ ∂ ∂θ e−iαθ ϕ(ρ, θ) = e iαθ ∂ ( ) ∂<br />
∂θ e−iαθ ∂θ − iα ϕ(ρ, θ)<br />
=<br />
( ∂<br />
∂θ − iα ) 2<br />
ϕ(ρ, θ)<br />
<br />
ϕ α (ρ, θ) = e −iαθ ϕ(ρ, θ)<br />
ϕ(ρ, θ) <br />
[<br />
− 2 ∂<br />
2<br />
2m ∂ρ 2 + 1 ∂<br />
ρ ∂ρ + 1 ∂ 2 ]<br />
ρ 2 ∂θ 2 ϕ α (ρ, θ) = E ′ ϕ α (ρ, θ)<br />
<br />
<br />
[<br />
− 2 d<br />
2<br />
2m dρ 2 + 1 ρ<br />
ϕ α (ρ, θ) = e iνθ R(ρ)<br />
]<br />
d<br />
dρ − ν2<br />
ρ 2 R(ρ) = E ′ R(ρ) (13.3)<br />
, <br />
ψ<br />
ψ(ρ, θ, z) = e iαθ ϕ α (ρ, θ)Z(z) = e i(α+ν)θ R(ρ)Z(z)<br />
r 1 ψ(ρ, θ, z) = ψ(ρ, θ + 2π, z) <br />
ν = m z − α = m z − Φ Φ 0<br />
,<br />
m z = <br />
E ′ R(ρ) ν , Φ , <br />
, Φ/Φ 0 = <br />
E ′ R(ρ) B = 0 , Φ , <br />
Φ 0 <br />
ψ(ρ, θ, z) = e im zθ R(ρ)Z(z) ,<br />
L z = − i ∂ ∂θ<br />
ψ L z m z
13 231<br />
(13.3) J ν , N ν <br />
, , ρ 2 → ρ 1 <br />
ρ 1 , R(ρ) = <br />
(13.3) <br />
E ′ = 2 ν 2<br />
2mρ 2 =<br />
(m 2<br />
1 2mρ 2 z − Φ ) 2<br />
1 Φ 0<br />
E ′ Φ/Φ 0 <br />
E ′ Φ 0 <br />
ρ = ρ 1 > a ,<br />
ρ ≤ a <br />
2mρ 2 1 E ′ / 2<br />
4<br />
1<br />
0<br />
0 1 2 3<br />
Φ/Φ 0<br />
Φ 0 D <br />
, B ≠ 0 B = 0 D D B = ∇× A = 0 <br />
A = ∇χ D P C <br />
C B ≠ 0 <br />
∮ ∮<br />
∫<br />
dr·A = dr·∇χ = dχ = χ(P ′ ) − χ(P)<br />
C<br />
C<br />
χ(P ′ ) 1 P χ <br />
∮ ∫<br />
∫<br />
dr·A = dS·(∇×A) = dS·B = Φ<br />
C<br />
S<br />
S<br />
<br />
χ(P ′ ) − χ(P) = Φ<br />
Φ ≠ 0 χ(r) r 1 <br />
(<br />
ψ χ (r) = exp − i qχ(r) )<br />
ψ(r)<br />
c<br />
<br />
∇ψ χ (r) = exp<br />
(<br />
− i qχ(r) ) (<br />
∇ − i q )<br />
(<br />
c<br />
c ∇χ ψ(r) = exp − i qχ(r) ) (<br />
∇ − i q )<br />
c<br />
c A ψ(r)<br />
<br />
[<br />
−<br />
(∇ 2<br />
− i q ) ]<br />
2<br />
2m c A(r) + V (r) ψ(r) = E ψ(r)<br />
(<br />
)<br />
− 2<br />
2m ∇2 + V (r) ψ χ (r) = E ψ χ (r) (13.4)<br />
, A , ψ(r) r 1<br />
ψ(P ′ ) = ψ(P) , ψ χ (r) <br />
( )<br />
(<br />
ψ χ (P ′ ) = exp − i qχ(P′ )<br />
ψ(P ′ ) = exp − i qΦ<br />
c<br />
c<br />
) (<br />
exp − i qχ(P)<br />
c<br />
)<br />
= exp<br />
(− 2πi Φ/Φ 0 ψ χ (P) ,<br />
)<br />
ψ(P)<br />
Φ 0 = 2πc<br />
q<br />
(13.5)
13 232<br />
(13.4) (13.5) , E Φ <br />
AB (13.5) Φ Φ 0 <br />
, E Φ 0 Φ <br />
<br />
χ(θ) = Φ 2π θ<br />
, (13.1) <br />
(13.2) <br />
∇χ = e θ<br />
ρ<br />
dχ<br />
dθ =<br />
Φ<br />
2πρ e θ<br />
<br />
∇×∇ χ = Φ 2π<br />
χ(P ′ ) − χ(P) = χ(θ + 2π) − χ(θ) = Φ<br />
( dρ<br />
−1<br />
dρ e ρ×e θ + 1 ρ 2 e θ × de θ<br />
dθ<br />
)<br />
= Φ 2π<br />
(<br />
− e ρ×e θ<br />
+ e ρ×e θ<br />
)<br />
ρ 2 ρ 2<br />
ρ ≠ 0 ∇×∇χ = 0 ρ = 0 ∇χ ∇×∇χ <br />
<br />
∮<br />
∫<br />
dr·∇χ = dS·(∇×∇ χ)<br />
C<br />
S z ( ρ = 0 ) 0 , 0 <br />
S<br />
13.2 <br />
ˆρ(r) ĵ(r) <br />
ˆρ(r) = δ(r − ˆx) , ĵ(r) = 1 (<br />
)<br />
ˆp δ(r − ˆx) + δ(r − ˆx) ˆp<br />
2m<br />
r 3 x, y, z , ˆx , ˆp <br />
, <br />
[ ˆx i , ˆp j ] = i δ ij , i, j = x, y, z<br />
r 3 ˆp <br />
ˆx | r 〉<br />
ˆx| r 〉 = r| r 〉<br />
ˆp (11.21) <br />
〈 r | ˆp = −i ∂〈 r |<br />
(<br />
∂r , ∂<br />
∂<br />
∂r ≡ ∇ = ∂x , ∂ ∂y , ∂ )<br />
∂z<br />
r <br />
<br />
| α 〉 ˆρ <br />
∫<br />
〈 α |ˆρ(r)| α 〉 = d 3 x 〈 α | x 〉〈 x |ˆρ(r)| α 〉<br />
δ(r − ˆx) 〈 x | , δ(r − x) <br />
<br />
〈 x |δ(r − ˆx) = δ(r − x)〈 x |
13 233<br />
<br />
∫<br />
〈 α |ˆρ(r)| α 〉 = d 3 x 〈 α | x 〉δ(r − x)〈 x | α 〉 = 〈 α | r 〉〈 r | α 〉 = |ψ α (r)| 2<br />
ψ α (r) ≡ 〈r|α〉 , <br />
<br />
<br />
〈 α |ĵ(r)| α 〉 = 1 ∫<br />
2m<br />
= 1<br />
2m<br />
(<br />
)<br />
d 3 x 〈 α | ˆp | x 〉〈 x |δ(r − ˆx)| α 〉 + 〈 α |δ(r − ˆx)| x 〉〈 x | ˆp | α 〉<br />
(<br />
)<br />
〈 α | ˆp | r 〉〈 r | α 〉 + 〈 α | r 〉〈 r | ˆp | α 〉<br />
<br />
<br />
〈 r | ˆp = − i ∂〈 r |<br />
∂r<br />
<br />
〈 r | ˆp | α 〉 = − i ∂〈 r | α 〉<br />
∂r<br />
i<br />
〈 α |ĵ(r)| α 〉 =<br />
2m<br />
= − i ∂ψ α(r)<br />
∂r<br />
, 〈 α | ˆp | r 〉 = 〈 r | ˆp | α 〉 ∗ = i ∂ψ∗ α(r)<br />
∂r<br />
(<br />
ψ α (r) ∂ψ∗ α(r)<br />
− ψ ∗<br />
∂r<br />
α(r) ∂ψ )<br />
α(r)<br />
= [<br />
∂r m Im ψα(r) ∗ ∂ψ ]<br />
α(r)<br />
∂r<br />
(1.4) φ(r) ψ α (r) = e iθ φ(r)<br />
, 0 <br />
<br />
(11.18) <br />
∂F (ˆx)<br />
[ F (ˆx) , ˆp ] = i<br />
∂ ˆx<br />
(13.6)<br />
, ∂F (ˆx)/∂ˆx “F (r) x ∂F (r)/∂x r ˆx <br />
” F (ˆx) = δ(r − ˆx) <br />
∂δ(r − ˆx) ∂δ(r − ˆx)<br />
[ δ(r − ˆx) , ˆp ] = i = − i<br />
∂ ˆx<br />
∂r<br />
(13.7)<br />
ˆρ ĵ <br />
[ ˆρ(x) , ĵ(y) ] = 1 (<br />
)<br />
[ δ(x − ˆx) , ˆp ]δ(y − ˆx) + δ(y − ˆx) [ δ(x − ˆx) , ˆp ]<br />
2m<br />
( ∂δ(x − ˆx)<br />
= − i<br />
2m<br />
∂x<br />
δ(y − ˆx) + δ(y − ˆx)<br />
)<br />
∂δ(x − ˆx)<br />
∂x<br />
= − i ∂δ(x − ˆx)<br />
δ(y − ˆx) (13.8)<br />
m ∂x<br />
= − i ∂δ(x − y)<br />
δ(y − ˆx) (13.9)<br />
m ∂x<br />
= − i ∂δ(x − ˆx)<br />
δ(y − x) (13.10)<br />
m ∂x<br />
(13.8) , ˆx
13 234<br />
(13.7) <br />
[ ˆρ(r) , ˆp 2 ] = ˆp · [ ˆρ(r) , ˆp ] + [ ˆρ(r) , ˆp ] · ˆp<br />
, H <br />
, V (ˆx) ˆρ <br />
∂δ(r − ˆx) ∂δ(r − ˆx)<br />
= − i ˆp · − i · ˆp<br />
∂r<br />
∂r<br />
= − i ∂ (<br />
)<br />
∂r · ˆp δ(r − ˆx) + δ(r − ˆx) ˆp = − i 2m∇·ĵ(r)<br />
H = ˆp2<br />
2m + V (ˆx)<br />
1<br />
[ ˆρ(r) , H ] = − ∇·ĵ(r) (13.11)<br />
i<br />
t | t 〉 <br />
i ∂ ∂t | t 〉 = H| t 〉 , −i ∂ ∂t 〈 t | = 〈 t |H<br />
t ρ(r, t) = 〈 t |ˆρ(r)| t 〉 <br />
∂ρ(r, t)<br />
∂t<br />
= 1 〈 t |[ˆρ(r) , H ]| t 〉 = − ∇·〈 t |ĵ(r)| t 〉 = − ∇·j(r, t) , j(r, t) = 〈 t |ĵ(r)| t 〉<br />
i<br />
<br />
F (ˆx) <br />
∫<br />
∫<br />
F (ˆx) = d 3 x F (x) δ(x − ˆx) = d 3 x F (x) ˆρ(x)<br />
F (ˆx) ĵ(y) , F (x) <br />
ĵ(y) , (13.9) <br />
∫<br />
[ F (ˆx) , ĵ(y) ] = d 3 x F (x) [ ˆρ(x) , ĵ(y) ] = − i ∫<br />
m δ(y − ˆx) d 3 ∂δ(x − y)<br />
x F (x)<br />
∂x<br />
<br />
[ F (ˆx) , ĵ(y) ] = i m δ(y − ˆx) ∫<br />
d 3 ∂F (x)<br />
x δ(x − y)<br />
∂x<br />
= i (y)<br />
δ(y − ˆx)∂F<br />
m ∂y<br />
(13.12)<br />
(13.12) y (13.6) <br />
<br />
ˆρ(r) ĵ(r) <br />
ˆρ(r) = ∑ i<br />
δ(r − r i ) , ĵ(r) = 1<br />
2m<br />
∑<br />
)<br />
(p i δ(r − r i ) + δ(r − r i )p i<br />
i<br />
(13.13)<br />
, r i i , p i ˆ <br />
<br />
[ ˆρ(x) , ĵ(y) ] = 1<br />
2m<br />
= − i m<br />
∑(<br />
)<br />
[ δ(x − r i ) , p i ]δ(y − r i ) + δ(y − r i ) [ δ(x − r i ) , p i ]<br />
i<br />
∑<br />
i<br />
∂δ(x − y)<br />
∂x<br />
δ(y − r i ) = − i ∂δ(x − y)<br />
ˆρ(y) (13.14)<br />
m ∂x
13 235<br />
ˆF = ∑ i<br />
F (r i ) <br />
ˆF = ∑ i<br />
∫<br />
∫<br />
d 3 x F (x) δ(x − r i ) = d 3 x F (x) ˆρ(x) (13.15)<br />
, (13.12) <br />
∫<br />
[ ˆF , ĵ(y) ] = d 3 x F (x) [ ˆρ(x) , ĵ(y) ] = − i ∫<br />
d 3 ∂δ(x − y)<br />
x F (x) ˆρ(y)<br />
m<br />
∂x<br />
<br />
<br />
= i m<br />
ˆρ(y)∂F<br />
(y)<br />
∂y<br />
[ ˆF † , ĵ(y) ] = i m ˆρ(y)∂F ∗ (y)<br />
∂y<br />
|α〉 :<br />
(13.16)<br />
(13.17)<br />
T |α〉 = e iθ |α〉<br />
T O <br />
(<br />
〈α|O ĵ(r)|α〉 = 〈α|T †) ) [<br />
)] ∗<br />
O<br />
(T ĵ(r) |α〉 = 〈α|<br />
(T † O ĵ(r)T |α〉<br />
T † r i T = r i , T † p i T = − p i , (13.13) <br />
T † ĵ(r)T = − ĵ(r)<br />
, <br />
(<br />
T † OT ) †<br />
= O (13.18)<br />
O <br />
T † Oĵ(r)T = (T † OT ) (T † ĵ(r)T ) = − (T † OT ) ĵ(r) = − O† ĵ(r)<br />
<br />
〈 α |Oĵ(r)| α 〉 = − 〈 α |O† ĵ(r)| α 〉 ∗ = − 〈α| ĵ(r)O|α〉 = 1 〈 α |[ O , ĵ(r) ]| α 〉 (13.19)<br />
2<br />
O = 1 (13.18) <br />
〈 α | ĵ(r)| α 〉 = 1 〈 α |[ 1 , ĵ(r) ]| α 〉 = 0<br />
2<br />
0 1 K|α〉 = e iθ |α〉 <br />
φ ψ(r) = e −iθ/2 φ(r) <br />
0 <br />
Energy–weighted sum rule<br />
(<br />
T † F (r)ˆρ(r)T ) †<br />
= (F ∗ (r)ˆρ(r)) † = F (r)ˆρ(r)<br />
(13.15) ˆF ˆF † (13.18) , (13.17) <br />
〈 α | ˆF † ĵ(r)| α 〉 = 1 2 〈 α |[ ˆF † ,<br />
i<br />
ĵ(r) ]| α 〉 =<br />
2m ρ α(r) ∂F ∗ (r)<br />
∂r
13 236<br />
<br />
ρ α (r) ≡ 〈 α |ˆρ(r)| α 〉<br />
H , 1 <br />
<br />
<br />
<br />
1<br />
[ H , ˆρ(r) ] = ∇·ĵ(r)<br />
i<br />
〈 α | ˆF † [ H , ˆρ(r) ]| α 〉 = i 〈 α | ˆF † ∂<br />
∂<br />
· ĵ(r)| α 〉 = i<br />
∂r ∂r · 〈 α | ˆF † ĵ(r)| α 〉<br />
〈 α | ˆF † [ H , ˆρ(r) ]| α 〉 = − 2<br />
2m<br />
∂<br />
∂r ·ρ α(r) ∂F ∗ (r)<br />
∂r<br />
∫<br />
〈 α | ˆF † [ H , ˆF ]| α 〉 = d 3 r F (r) 〈 α | ˆF † [ H , ˆρ(r) ]| α 〉<br />
∫<br />
= − 2<br />
2m<br />
∫<br />
= 2<br />
2m<br />
d 3 r F (r) ∂<br />
∂r ·ρ α(r) ∂F ∗ (r)<br />
∂r<br />
d 3 r ρ α (r) ∂F ∗ (r) ∂F (r)<br />
·<br />
∂r ∂r<br />
r → ∞ ρ α (r) → 0 <br />
| α 〉 H :<br />
H| α 〉 = E α | α 〉<br />
(13.20)<br />
(13.20) <br />
<br />
〈 α | ˆF † [ H , ˆF ]| α 〉 =<br />
∑<br />
α ′ 〈 α | ˆF † | α ′ 〉〈 α ′ |[ H , ˆF ]| α 〉<br />
〈 α ′ |[ H , ˆF ]| α 〉 = 〈 α ′ |(H ˆF − ˆF H)| α 〉 = (E α ′ − E α )〈 α ′ | ˆF | α 〉<br />
<br />
〈 α | ˆF<br />
∑<br />
† [ H , ˆF ]| α 〉 = (E α ′ − E α )〈 α | ˆF † | α ′ 〉〈 α ′ | ˆF | α 〉 = ∑ ∣<br />
(E α ′ − E α ) ∣〈 α ′ | ˆF ∣<br />
| α 〉<br />
α ′ α ′<br />
<br />
∑<br />
∣<br />
(E α ′ − E α ) ∣〈 α ′ | ˆF ∫<br />
| α 〉 ∣ 2 = 2<br />
2m<br />
α ′<br />
d 3 r ρ α (r) ∂F ∗ (r)<br />
∂r<br />
·<br />
∂F (r)<br />
∂r<br />
Energy–weighted sum rule H <br />
,<br />
ρ α (r) | α 〉 <br />
( - ) <br />
, F (r) = z <br />
<br />
∂F ∗ (r)<br />
∂r<br />
N <br />
·<br />
∂F (r)<br />
∂r<br />
= (0, 0, 1) · (0, 0, 1) = 1<br />
∑<br />
∣<br />
N∑<br />
∫<br />
(E α ′ − E α ) ∣〈 α ′ | z i | α 〉 ∣ 2 = 2<br />
2m<br />
α ′ i=1<br />
d 3 r ρ α (r) = 2<br />
2m N<br />
∣ 2
14 237<br />
14 <br />
14.1 ( Levi–Civita ) <br />
i, j, k 1, 2, 3 i, j, k 3 ijk 2<br />
, ijk i ′ j ′ k ′ <br />
ijk i ′ j ′ k ′ , , <br />
123 213 123 → 213 ,<br />
123 → 321 → 231 → 213 , <br />
, () ijk → i ′ j ′ k ′ <br />
() 3 ε ijk <br />
⎧<br />
⎪⎨ 0 2 <br />
ε ijk = +1 ijk 123 <br />
⎪⎩<br />
−1 ijk 123 <br />
<br />
ε 123 = ε 231 = ε 312 = 1 , ε 132 = ε 213 = ε 321 = −1 , ε ijk = 0<br />
ε ijk ( Levi–Civita ) <br />
(14.1)<br />
• ikj ijk 1 , ijk () ikj <br />
() ε ijk = − ε ikj ε ijk = ε kij ijk <br />
<br />
• <br />
∑<br />
ε kij ε kmn = δ im δ jn − δ in δ jm (14.2)<br />
k<br />
, i = 1, j = 2 ε kij ≠ 0 k k = 3 <br />
∑<br />
ε k12 ε kmn = ε 312 ε 3mn<br />
k<br />
ε 3mn ≠ 0 m = 1, n = 2 m = 2, n = 1 <br />
⎧<br />
∑<br />
⎪⎨<br />
(ε 312 ) 2 = 1 , m = 1, n = 2<br />
ε k12 ε kmn = ε 312 ε 321 = −1 , m = 2, n = 1<br />
k<br />
⎪⎩<br />
0 , <br />
<br />
∑<br />
ε k12 ε kmn = δ m1 δ n2 − δ n1 δ m2<br />
k<br />
, (14.2) i = 1, j = 2 <br />
• A x, y, z A 1 , A 2 , A 3 A×B k <br />
(A×B) k<br />
= ∑ ij<br />
ε kij A i B j (14.3)<br />
<br />
<br />
(A×B) 1<br />
= ε 123 A 2 B 3 + ε 132 A 3 B 2 = ε 123 A 2 B 3 − ε 123 A 3 B 2 = A 2 B 3 − A 3 B 2
14 238<br />
14.1 (14.2), (14.3) <br />
A×(B×C) = B(C ·A) − C(A·B) , <br />
(A×B)·(C ×D) = (A·C)(B·D) − (B·C)(A·D)<br />
(<br />
)<br />
A×(B×C) = B iA·C − C i A·B<br />
i<br />
<br />
14.2 <br />
“” δ(x) :<br />
⎧<br />
⎨ ∞ , x = 0<br />
∫ ∞<br />
δ(x) =<br />
, δ(x) dx = 1<br />
⎩ 0 , x ≠ 0<br />
−∞<br />
<br />
⎧<br />
⎨<br />
δ(x) = lim δ ε (x) , δ ε (x) =<br />
ε→0 ⎩<br />
f(x) <br />
∫ ∞<br />
−∞<br />
dx f(x) δ(x − a) = f(a)<br />
∫ ∞<br />
−∞<br />
1/(2ε) ,<br />
|x| ≤ ε<br />
0 , |x| > ε<br />
dx δ(x − a) = f(a)<br />
x ≠ a δ(x − a) = 0 , x ≠ a f(a) <br />
, − ∞ ∞ , <br />
, <br />
<br />
δ(x) = δ(−x) (14.4)<br />
x δ(x) = 0 (14.5)<br />
x δ ′ (x) = − δ(x) (14.6)<br />
δ(cx) = 1 δ(x) ,<br />
|c|<br />
( c ≠ 0 ) (14.7)<br />
δ(x 2 − c 2 ) = 1 (<br />
)<br />
δ(x − c) + δ(x + c) ,<br />
2|c|<br />
( c ≠ 0 ) (14.8)<br />
δ(g(x)) = ∑ n<br />
1<br />
|g ′ (x n )| δ(x − x n) , ( g(x n ) = 0 , g ′ (x n ) ≠ 0 ) (14.9)<br />
, <br />
, δ ′ (x) δ(x) 1 , (14.9) , g(x) <br />
(14.6) <br />
∫ ∞<br />
−∞<br />
dx f(x) x δ ′ (x) =<br />
= −<br />
= −<br />
[ ] ∞<br />
f(x)xδ(x) −<br />
−∞<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
−∞<br />
( ′δ(x)<br />
dx f(x)x)<br />
(<br />
)<br />
dx f ′ (x)x + f(x) δ(x)<br />
dx f(x) δ(x)
14 239<br />
<br />
ε > 0 <br />
δ ε (x) = 1 ∫ (<br />
∞<br />
[exp(ikx<br />
dk exp(ikx − ε|k| ) = 1<br />
− εk)<br />
2π<br />
2π ix − ε<br />
−∞<br />
= 1 π<br />
ε<br />
x 2 + ε 2<br />
] ∞<br />
0<br />
[ exp(ikx + εk)<br />
+<br />
ix + ε<br />
] 0<br />
−∞)<br />
, x ≠ 0 δ ε (x)<br />
∫ b<br />
−adx δ ε (x) = 1 π<br />
ε→0<br />
−−−−→ 0 , a, b <br />
[<br />
tan −1 x ] b<br />
ε→+0<br />
−−−−→ 1 (<br />
tan −1 (∞) − tan −1 (−∞) ) = 1<br />
ε −a π<br />
, ε → +0 δ ε (x) δ(x) :<br />
1<br />
δ(x) = lim<br />
ε→+0 2π<br />
∫ ∞<br />
−∞<br />
dk exp(ikx − ε|k| ) = 1<br />
2π<br />
∫ ∞<br />
−∞<br />
dk e ikx (14.10)<br />
1 , 3<br />
, r = ( x, y, z ) , <br />
δ(r) ≡ δ(x) δ(y) δ(z)<br />
( d 3 r = dx dy dz )<br />
∫<br />
∫ ∫ ∫<br />
d 3 r δ(r) = dx δ(x) dy δ(y) dz δ(z) = 1<br />
F (x, y, z) F (r) <br />
∫<br />
d 3 r F (r) δ(r − r 0 ) = F (r 0 )<br />
(14.10) <br />
<br />
δ(r) = 1 ∫ ∞<br />
(2π) 3 d 3 k exp (ik·r) (14.11)<br />
−∞<br />
k·r = k x x + k y y + k z z , d 3 k = dk x dk y dk z<br />
14.3 <br />
F (x) <br />
<br />
<br />
F (x) = 1<br />
2π<br />
∫ ∞<br />
F (x) =<br />
∫ ∞<br />
δ(x − y) = 1<br />
2π<br />
−∞<br />
−∞<br />
dy δ(x − y) F (y)<br />
∫ ∞<br />
−∞<br />
dk exp (ik(x − y))<br />
∫ ∞<br />
dk e ikx dy e −iky F (y) = √ 1 ∫ ∞<br />
dk e ikx ˜F (k) (14.12)<br />
2π<br />
−∞<br />
−∞
14 240<br />
<br />
˜F (k) = √ 1 ∫ ∞<br />
dx e −ikx F (x) (14.13)<br />
2π<br />
−∞<br />
˜F (k) F (x) , F (x) ˜F (k) , F (x) ˜F (k) <br />
<br />
∫ ∞<br />
˜F (k) = dx e −ikx F (x) , F (x) = 1 dk e ikx ˜F (k) (14.14)<br />
−∞<br />
2π −∞<br />
<br />
3 <br />
∫<br />
1 ∞<br />
∫<br />
˜F (k) =<br />
d 3 1 ∞<br />
r exp(−ik·r) F (r) , F (r) =<br />
d 3 k exp(ik·r)<br />
(2π) 3/2 (2π) ˜F (k)<br />
3/2<br />
−∞<br />
, exp(ik·r) <br />
<br />
∫ ∞<br />
−∞<br />
<br />
<br />
(<br />
∇ 2 − m 2) F (r) = − g δ(r) (14.15)<br />
, m, g ( m > 0 )<br />
∇ 2 = ∇·∇ = ∂2<br />
∂x 2 + ∂2<br />
∂y 2 + ∂2<br />
∂z 2<br />
F (r) <br />
∫ d 3 k<br />
F (r) =<br />
(2π) 3 exp(ik·r) ˜F (k) (14.16)<br />
x exp(ik x x) <br />
∂ 2 ∫ d 3 ∫<br />
∂x 2 F (r) = k<br />
(2π) ˜F 3 (k) ∂2<br />
d 3<br />
∂x 2 exp(ik·r) = − k<br />
(2π) ˜F 3 (k) kx 2 exp(ik·r)<br />
y, z <br />
∫ d<br />
∇ 2 3 k<br />
F (r) = −<br />
(2π) ˜F 3 (k) k 2 exp(ik·r) , k 2 = k·k = kx 2 + ky 2 + kz<br />
2<br />
(14.11) , (14.15) <br />
∫ d 3 k<br />
(2π) ˜F 3 (k) ( k 2 + m 2) ∫ d 3 k<br />
exp(ik·r) = g<br />
(2π) 3 exp(ik·r)<br />
(k 2 + m 2 ) ˜F (k) = g , <br />
, <br />
F (r) =<br />
g ∫<br />
(2π) 3 d 3 k exp(ik·r)<br />
k 2 + m 2<br />
3 r k θ k ( k, θ, φ ) <br />
, k·r = k r cos θ <br />
F (r) =<br />
g ∫ ∞ ∫ π<br />
(2π) 3 dk k 2 dθ sin θ<br />
g<br />
=<br />
(2π) 2 ir<br />
= g<br />
4iπ 2 r<br />
0<br />
∫ ∞<br />
0<br />
∫ ∞<br />
−∞<br />
dk k<br />
0<br />
dk exp(ikr)<br />
∫ 2π<br />
0<br />
dφ<br />
exp(ikr) − exp(−ikr)<br />
k 2 + m 2<br />
exp(ikr cos θ)<br />
k 2 + m 2<br />
k<br />
k 2 + m 2 = g e −mr<br />
4π r<br />
(14.17)
14 241<br />
(14.17) (14.15) <br />
(14.17) (14.15) <br />
(<br />
∇ 2 − m 2) e −mr<br />
r<br />
= − 4π δ(r) , m = 0 ∇ 2 1 r<br />
= − 4π δ(r)<br />
<br />
14.4 <br />
<br />
z f(z) <br />
f(z) − f(z 0 )<br />
lim<br />
z→z 0 z − z 0<br />
, f(z) z = z 0 <br />
z 0 , , <br />
f(z) = u(x, y) + iv(x, y) ,<br />
z = x + iy<br />
<br />
<br />
f ′ f(z + ∆z) − f(z)<br />
(z) = lim<br />
∆z→0 ∆z<br />
= lim<br />
∆z→0<br />
( u(x + ∆x, y + ∆y) − u(x, y)<br />
+ i<br />
∆x + i∆y<br />
)<br />
v(x + ∆x, y + ∆y) − v(x, y)<br />
∆x + i∆y<br />
∆y = 0 f ′ (z) = ∂u<br />
∂x + i ∂v<br />
∂x ,<br />
∆x = 0 f ′ (z) = ∂v<br />
∂y − i ∂u<br />
∂y<br />
<br />
∂u<br />
∂x = ∂v<br />
∂y ,<br />
∂v<br />
∂x = − ∂u<br />
∂y<br />
, u, v <br />
f(z) <br />
D , f(z) D f(z)<br />
z = z 0 , f(z) <br />
() 2 z a , z b 2 C z , <br />
t z = z(t) , ( z a z b ) C <br />
f(z) <br />
∫<br />
C<br />
dz f(z) ≡<br />
∫ tb<br />
t a<br />
dt dz<br />
dt f(z(t)) , z a = z(t a ) , z b = z(t b )<br />
, C R z =<br />
R e iθ , ( 0 ≤ θ ≤ π ) <br />
∫<br />
∫ π<br />
dz f(z) = i R dθ e iθ f(Re iθ )<br />
<br />
C<br />
0<br />
O
14 242<br />
✓<br />
✏<br />
D f(z) , C <br />
D <br />
<br />
✒<br />
C<br />
C<br />
∫<br />
C<br />
dz f(z) = 0<br />
<br />
∫ ∫ (<br />
)<br />
dz f(z) = u(x, y) + iv(x, y) (dx + idy)<br />
∫ (<br />
)<br />
= u(x, y)dx − v(x, y)dy<br />
C<br />
∫ (<br />
)<br />
+ i v(x, y)dx + u(x, y)dy<br />
C<br />
C R , , <br />
∫ (<br />
) ∫ ( ∂Q<br />
P (x, y)dx + Q(x, y)dy =<br />
∂x − ∂P )<br />
dxdy<br />
∂y<br />
<br />
∫<br />
C<br />
C<br />
∫<br />
dz f(z) = −<br />
C<br />
R<br />
( ∂v<br />
∂x + ∂u ) ∫ ( ∂u<br />
dxdy + i<br />
∂y<br />
C ∂x − ∂v )<br />
dxdy<br />
∂y<br />
u, v , 0 ,<br />
<br />
(14.17) <br />
f(z) =<br />
z<br />
z 2 + m 2 eirz<br />
f(z) z = ±im , <br />
f(z) , C <br />
C [−R, R ], <br />
R C R , z = im<br />
ε C ε , C 1 ,<br />
−R<br />
O<br />
iR<br />
C 2<br />
C 1<br />
R<br />
− im<br />
C 2 C 1 C 2 , ,<br />
C 1 C 2 , 2 f(z) 2<br />
C , f(z) C 1 0 <br />
∫ ∫ R ∫<br />
∫<br />
dz f(z) = dx f(x) + dz f(z) + dz f(z) = 0 (14.18)<br />
C<br />
−R<br />
C R C ε<br />
C R z = Re iθ = R cos θ + iR sin θ <br />
|e irz | = | exp(−rR sin θ + irR cos θ)| = exp(−rR sin θ)<br />
✑<br />
<br />
<br />
|f(z)| =<br />
sin θ<br />
sin θ<br />
Re−rR Re−rR<br />
|R 2 e i2θ + m 2 ≤<br />
| R 2 − m 2<br />
∣∫<br />
∫ ∣∣∣ π<br />
dz f(z)<br />
∣ ≤ R dθ ∣ ∣e iRθ f(Re iθ ) ∣ R 2 ∫ π<br />
−rR sin θ<br />
≤<br />
C R 0<br />
R 2 − m 2 dθ e<br />
0
14 243<br />
0 ≤ θ ≤ π/2 sin θ ≥ 2θ/π <br />
<br />
∫ π<br />
0<br />
dθ e −rR sin θ = 2<br />
∫ π/2<br />
0<br />
dθ e −rR sin θ ≤ 2<br />
∫ π/2<br />
0<br />
dθ e −2rR θ/π = π<br />
rR<br />
∣∫<br />
∣∣∣ dz f(z)<br />
∣ ≤ π R 2 (<br />
1 − e<br />
−rR )<br />
C R<br />
rR R 2 − m 2 −→ 0 ( R −→ ∞ )<br />
, (14.18) R −→ ∞ <br />
∫ ∞<br />
∫<br />
dx f(x) = − dz f(z) = i<br />
−∞<br />
C ε<br />
∫ 2π<br />
0<br />
dθ α f(im + α) =<br />
α = εe iθ ε −→ + 0 <br />
(14.17) <br />
∫ ∞<br />
−∞<br />
∫ 2π<br />
dx f(x) = i ∫ 2π<br />
2 e−mr dθ = iπe −mr<br />
0<br />
0<br />
(<br />
1 − e<br />
−rR )<br />
dθ im + α<br />
2m − iα e−mr+irα<br />
z = α f(z) , f(z) <br />
f(z) =<br />
∞∑<br />
k=−∞<br />
a k (z − α) k<br />
z = α ε C , C<br />
<br />
z = α + ε e iθ ,<br />
0 ≤ θ ≤ 2π<br />
<br />
∫<br />
(z − α) k dz =<br />
∫ 2π<br />
(<br />
ε e<br />
iθ ) ∫ {<br />
2π<br />
k<br />
iε e iθ dθ = i ε k+1 e i(k+1)θ dθ =<br />
C<br />
0<br />
0<br />
0 , k ≠ −1<br />
2πi ,<br />
k = −1<br />
<br />
∫<br />
f(z) dz = 2πi a −1 (14.19)<br />
C<br />
a −1 f(z) α <br />
a −1 = Res(α)<br />
(14.19) z = α D ,<br />
, D α 1 , α 2 , · · · , α m <br />
<br />
∫<br />
m∑<br />
f(z) dz = 2πi Res(α m ) (14.20)<br />
D<br />
k=1<br />
<br />
f(z) l <br />
∞∑<br />
f(z) = a k (z − α) k , a −l ≠ 0<br />
k=−l<br />
<br />
(z − α) l f(z) = a −l + a −l+1 (z − α) + a −l+2 (z − α) 2 + · · · + a −1 (z − α) l−1 + · · ·
14 244<br />
<br />
<br />
<br />
d l−1<br />
dz l−1 (z − α)l f(z) = (l − 1)! a −1 + l! a 0 (z − α) + · · ·<br />
Res(α) = a −1 =<br />
1<br />
(l − 1)! lim d l−1<br />
z→α dz l−1 (z − α)l f(z)<br />
f(z) = e irz /(z 2 + m 2 ) , z = im l = 1 <br />
<br />
<br />
r <br />
∫ ∞<br />
−∞<br />
(14.17) <br />
<br />
e−mr<br />
Res(im) = lim (z − im)f(z) =<br />
z→im 2im<br />
dx f(x) = − dz f(z) = 2πi<br />
∫C e−mr<br />
ε<br />
2im = πe−mr<br />
m<br />
F (r) =<br />
∫ ∞<br />
∫ ∞<br />
−∞<br />
i<br />
4π 2 r<br />
−∞<br />
dx<br />
dx<br />
∫ ∞<br />
e irx<br />
x 2 + m 2 = πe−mr<br />
m<br />
x<br />
x 2 + m 2 eirx = iπe −mr<br />
−∞<br />
dk<br />
k<br />
k 2 + m 2 eikr = − 1 e −mr<br />
4π r<br />
<br />
a <br />
∫ ∞<br />
−∞<br />
√ π<br />
dx e −ax2 = , Re a ≥ 0 (14.21)<br />
a<br />
a a = re iφ Re a ≥ 0<br />
|φ| ≤ π/2 z = e iφ/2 x <br />
∫ ∞<br />
∫<br />
I = dx e −ax2 = e −iφ/2 dz e −rz2<br />
−∞<br />
C 1<br />
C 1 C 2<br />
−R φ/2<br />
C 4<br />
C 3<br />
R<br />
C 1 tan(φ/2) C 1 + C 2 +<br />
C 3 + C 4 ( R → ∞ ), e −rz2 <br />
∫<br />
∫<br />
dz e −rz2 + dz e −rz2 +<br />
C 1 C 2<br />
∫ −R<br />
R<br />
∫<br />
dz e −rz2 + dz e −rz2 = 0<br />
C 4<br />
C 2 z = Re iθ/2 , θ φ 0 <br />
∫<br />
J 2 = dz e −rz2 = iR<br />
C 2<br />
2<br />
∫ 0<br />
φ<br />
dθ exp ( −rR 2 e iθ)<br />
<br />
|J 2 | ≤ R 2<br />
∫ |φ|<br />
0<br />
dθ ∣ ∣exp ( −rR 2 e iθ)∣ ∣ = R 2<br />
∫ |φ|<br />
0<br />
dθ exp ( −rR 2 cos θ )
14 245<br />
cos θ 1 − 2θ/π 0 < θ < |φ| ≤ π/2 cos θ > 1 − 2θ/π <br />
<br />
|J 2 | ≤ R 2<br />
∫ |φ|<br />
0<br />
dθ exp<br />
( (−rR 2 1 − 2θ ))<br />
= π [ ( (<br />
exp − 1 − 2|φ| ) )<br />
rR 2 − exp ( −rR 2)]<br />
π 4R<br />
π<br />
1 − 2|φ|/π ≥ 0 R → ∞ J 2 → 0 <br />
∫<br />
C 4<br />
dz e −rz2 → 0<br />
<br />
<br />
<br />
∫<br />
dz e −rz2 = −<br />
C 1<br />
∫ −R<br />
R<br />
∫ ∞<br />
−∞<br />
dz e −rz2 =<br />
∫ R<br />
−R<br />
√ √ π π<br />
dx e −ax2 =<br />
r e−iφ/2 =<br />
a<br />
dz e −rz2 →<br />
√ π<br />
r , R → ∞<br />
Re a = 0 a = ik k > 0 φ = π/2 <br />
∫ ∞<br />
−∞<br />
<br />
<br />
∫ ∞<br />
−∞<br />
, a, b <br />
∫ ∞<br />
dx e −ikx2 =<br />
√ π<br />
k e−iπ/4 =<br />
√ π<br />
2k (1 − i )<br />
dx cos ( kx 2) =<br />
∫ ∞<br />
−∞<br />
dx sin ( √<br />
kx 2) π<br />
=<br />
2k<br />
C 4<br />
dx e −a(x+b)2<br />
−∞<br />
−R<br />
, ( R → ∞ )<br />
∫ ∞<br />
∫<br />
∫<br />
∫<br />
∫<br />
dx e −a(x+b)2 = dz e −az2 = − dz e −az2 − dz e −az2 − dz e −az2<br />
−∞<br />
C 1 C 2 C 3 C 4<br />
C 2 z = R + iy y b i = Im b 0 <br />
I 2 =<br />
∫<br />
dz e −az2 = i<br />
C 2<br />
∫ 0<br />
dy e −a(R+iy)2<br />
b i<br />
C 1 b<br />
C 2<br />
C 3<br />
<br />
a(R + iy) 2 (<br />
= a r R 2 − y 2) ( (<br />
− 2a i Ry + i a i R 2 − y 2) )<br />
+ 2a r Ry , a r = Re a , a i = Im a i<br />
a r > 0 R → ∞ I 2 → 0 C 4 <br />
∫ ∞<br />
∫<br />
∫ ∞<br />
√ π<br />
dx e −a(x+b)2 = − dz e −az2 = dx e −ax2 = , Re a > 0 (14.22)<br />
−∞<br />
C 2 −∞<br />
a<br />
a r = 0 b i = 0 <br />
∫ ∞<br />
−∞<br />
√ π<br />
dx e −a(x+b)2 =<br />
a<br />
, b i ≠ 0 e −a(x+b)2 x → ∞ x → − ∞ <br />
R
14 246<br />
14.5 <br />
f(z) = u(z) + iv(z) z 0 f(z) <br />
f(z) = f(z 0 ) + f ′ (z 0 )(z − z 0 ) + · · ·<br />
, f ′ (z 0 ) = |f ′ (z 0 )|e iα , z − z 0 = re iθ <br />
f(z) = f(z 0 ) + |f ′ (z 0 )|re i(α+θ) + · · ·<br />
<br />
u(z) = u(z 0 ) + |f ′ (z 0 )|r cos(θ + α) + · · · , v(z) = v(z 0 ) + |f ′ (z 0 )|r sin(θ + α) + · · ·<br />
, v sin(θ + α) = 0 z u <br />
v(z) = u <br />
f(z) z = z 0 = x 0 + iy 0 df/dz = 0 <br />
f(z) = f(z 0 ) + f ′′ (z 0 )<br />
2<br />
(z − z 0 ) 2 + · · · = f(z 0 ) + |f ′′ (z 0 )|<br />
2<br />
, f ′′ (z 0 ) = |f ′′ (z 0 )|e iβ , z − z 0 = re iθ <br />
u(z) = u(z 0 ) + |f ′′ (z 0 )|<br />
2<br />
r 2 cos (2θ + β) + · · · , v(z) = v(z 0 ) + |f ′′ (z 0 )|<br />
2<br />
θ cos (2θ + β) > 0 u(z 0 ) <br />
, cos (2θ + β) < 0 ,<br />
z = z 0 u(z) = = u(z 0 ) 2 ,<br />
u = u(z) u(z) <br />
z = z 0 <br />
u = u(z) , z = z 0 <br />
z 0 ( saddle point ) <br />
v(z) = u(z) <br />
, z = z 0 <br />
2 z = z 0 , <br />
A<br />
r 2 e i(2θ+β) + · · ·<br />
r 2 sin (2θ + β) + · · ·<br />
2θ + β = π , 2θ + β = 0 u(z) <br />
<br />
z 0<br />
B<br />
, <br />
∫<br />
F (t) = dz e tf(z) g(z)<br />
C 0<br />
|t| → ∞ tf(z) = u(z) + iv(z) <br />
e tf(z) = e u(z)( )<br />
cos v(z) + i sin v(z)<br />
C 0 u(z) C |t| → ∞ <br />
e u(z) , z = z 0 <br />
, |t| → ∞ cos v(z) sin v(z)
14 247<br />
, v(z) , <br />
z = z 0 <br />
tf(z) = tf(z 0 ) + tf ′′ (z 0 )<br />
2<br />
(z − z 0 ) 2 + · · ·<br />
<br />
tf ′′ (z 0 ) = |tf ′′ (z 0 )|e iβ ,<br />
z − z 0 = re iθ<br />
, θ z = z 0 C , r > 0 <br />
θ , A → B B → A θ π <br />
C e i(2θ+β) = − 1 <br />
tf(z) = tf(z 0 ) + |tf ′′ (z 0 )|<br />
2<br />
r 2 e i(2θ+β) + · · · = tf(z 0 ) − |tf ′′ (z 0 )|<br />
2<br />
r 2 + · · ·<br />
|t| → ∞ r − ε ≤ r ≤ ε tf(z)<br />
2 g(z) ≈ g(z 0 ) <br />
∫<br />
F (t) = dz e tf(z) g(z) ≈ e tf(z0) g(z 0 )<br />
x = √ |t| r <br />
C<br />
∫ ε<br />
−ε<br />
dr e iθ e −|tf ′′ (z 0 )|r 2 /2<br />
∫<br />
F (t) ≈ e tf(z0)+iθ 1 X<br />
g(z 0 ) √ dx e −|f ′′ (z 0 )|x 2 /2 , X = √ |t| ε<br />
|t|<br />
−X<br />
|t| → ∞ X → ∞ <br />
∫<br />
√<br />
F (t) = dz e tf(z) g(z) ≈ e tf(z0)+iθ 2π<br />
g(z 0 )<br />
C 0<br />
|tf ′′ (z 0 )|<br />
(14.23)<br />
2θ + β = π + 2nπ <br />
√<br />
F (t) ≈ ± i e tf(z0) 2π<br />
g(z 0 )<br />
tf ′′ (z 0 )<br />
C 0 C
15 248<br />
15 <br />
15.1 <br />
<br />
2 59 <br />
dn<br />
H n (q) = (−1) n e q2<br />
dq n = e−q2<br />
[n/2]<br />
∑<br />
k=0<br />
(−1) k n!<br />
k! (n − 2k)! (2q)n−2k (15.1)<br />
<br />
<br />
d n<br />
dq n qf(q) = q dn f<br />
dq n + f<br />
ndn−1<br />
dq n−1<br />
<br />
(−1) n+1 e q2<br />
d n+1<br />
)<br />
e−q2 = − 2 dn<br />
dqn+1 dq n = − 2<br />
(q dn<br />
qe−q2 dq n + n dn−1<br />
e−q2 dq n−1 e−q2<br />
<br />
H n <br />
<br />
H n+1 (q) = 2qH n (q) − 2nH n−1 (q) (15.2)<br />
dH n<br />
dq = d (<br />
(−1)n<br />
dn<br />
eq2<br />
dq dq n = (−1) n 2q e e−q2 q2<br />
)<br />
dn<br />
dq n + e e−q2 q2 dn+1<br />
dq n+1 e−q2<br />
= 2qH n (q) − H n+1 (q) = 2nH n−1 (q) (15.3)<br />
<br />
d 2 H n<br />
dq 2<br />
(15.3) <br />
= d dq<br />
(2qH n − H n+1<br />
)<br />
= 2H n + 2q dH n<br />
dq − dH n+1<br />
= 2H n + 2q dH n<br />
dq<br />
dq<br />
− 2(n + 1)H n<br />
( d<br />
2<br />
dq 2 − 2q d dq + 2n )<br />
H n = 0 (15.4)<br />
( d<br />
dq e−q2 d dq + 2ne−q2 )<br />
H n = 0 (15.5)<br />
<br />
f(q) = e −q2 <br />
H n (q) = (−1) n e q2<br />
dn<br />
dq n e−q2<br />
= (−1) n e q2 f (n) (q)<br />
, <br />
<br />
∞∑<br />
n=0<br />
H n (q)<br />
n!<br />
t n = e q2<br />
f(q + t) =<br />
∞ ∑<br />
n=0<br />
∞∑<br />
n=0<br />
f (n) (q)<br />
n!<br />
t n<br />
f (n) (q)<br />
(−t) n = e q2 f(q − t) = e −t2 +2tq<br />
n!<br />
(15.6)
15 249<br />
(4.22) <br />
∞∑<br />
n=0<br />
√<br />
ϕ n (q) α<br />
√ t n /2<br />
=<br />
n! π 1/2 e−q2<br />
∞∑<br />
n=0<br />
H n (q)<br />
n!<br />
( ) n √ t α +t<br />
√ =<br />
2 )/2+ √ 2 tq<br />
2 π 1/2 e−(q2<br />
(15.7)<br />
<br />
<br />
I(n, n ′ ) =<br />
∫ ∞<br />
−∞<br />
dq e −q2 H n (q)H n ′(q)<br />
n ≥ n ′ H n <br />
∫ ∞<br />
I(n, n ′ ) = (−1) n dq dn e<br />
[d −q2<br />
dq n H n ′(q) n−1 ∫<br />
e −q2<br />
∞<br />
=<br />
dq n−1 H n ′ − (−1) n dq dn−1 e −q2 dH n ′<br />
dq n−1 dq<br />
−∞<br />
, <br />
] ∞<br />
−∞<br />
∫ ∞<br />
= (−1) n+1 dq dn−1 e −q2 dH n ′<br />
dq n−1 dq<br />
−∞<br />
d k e −q2<br />
dq k = q × e −q2 → 0 , q → ± ∞<br />
H n ′ (15.1) <br />
I(n, n ′ ) =<br />
<br />
∫ ∞<br />
−∞<br />
dq e −q2 dn H n ′<br />
dq n =<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
−∞<br />
(4.22) <br />
−∞<br />
(<br />
)<br />
dq e −q2 dn<br />
dq n (2q) n′ − n ′ (n ′ − 1)(2q) n′ −2 + · · ·<br />
⎧<br />
⎪⎨ 0 , n > n ′<br />
=<br />
∫ ∞<br />
⎪⎩ 2 n n! dq e −q2 = 2 n n! √ π , n ′ = n<br />
−∞<br />
dq e −q2 H n (q) H n ′(q) = √ π n! 2 n δ nn ′ (15.8)<br />
∫ ∞<br />
−∞<br />
, (15.6) <br />
∞∑<br />
∞∑<br />
n=0 m=0<br />
e −q2 <br />
∞∑<br />
∞∑<br />
n=0 m=0<br />
t n s m<br />
n! m!<br />
∫ ∞<br />
−∞<br />
e 2ts <br />
∞∑<br />
dq e −q2 H n (q)H m (q) =<br />
∞∑<br />
n=0 m=0<br />
t n s m<br />
n! m!<br />
dx ϕ n (x)ϕ n ′(x) = δ nn ′<br />
H n (q) H m (q)<br />
t n s m = e −t2 +2tq−s 2 +2sq<br />
n! m!<br />
∫ ∞<br />
−∞<br />
∫ ∞<br />
t n s m (15.8) <br />
−∞<br />
dq exp ( 2ts − (q − s − t) 2) = √ π e 2ts (15.9)<br />
dq e −q2 H n (q)H m (q) = √ π<br />
∞∑ 2 n t n s n<br />
n=0<br />
n!
15 250<br />
<br />
(4.22) (15.2) H n (q) <br />
H 0 (q) = 1 , H 1 (q) = 2q , H 2 (q) = 4q 2 − 2 , H 3 (q) = 8q 3 − 12q<br />
<br />
15.1 (15.5) H n ′(x) n n ′ n ≠ n ′<br />
I(n, n ′ ) = 0 <br />
15.2<br />
(15.6) <br />
∫ ∞<br />
−∞<br />
dq q 2 e −q2 H n (q) H n ′(q)<br />
〈 n ′ | x 2 | n 〉 (4.23) <br />
15.3<br />
1. − d dq e−ikq = ik e −ikq H n (15.1) <br />
∫<br />
1 ∞<br />
√ dk (ik) n e −ikq−k2 /4 = e −q2 H n (q)<br />
4π<br />
−∞<br />
e −q2 H n (q) <br />
∞∑<br />
2. (4.22) ϕ n (x)ϕ n (x ′ ) = δ(x − x ′ ) <br />
3. ( Mehler ) <br />
∞∑<br />
n=0<br />
n=0<br />
z n<br />
(<br />
n! 2 n H n(q)H n (q ′ 1 2qq ′<br />
) = √ exp z − (q 2 + q ′2 )z 2 )<br />
1 − z<br />
2 1 − z 2<br />
(15.10)<br />
z → 1 ϕ n (x) <br />
15.2 <br />
<br />
( Legendre ) <br />
P m l<br />
Pl m (x) = 1<br />
2 l l! (1 − x2 m/2 dl+m<br />
)<br />
dx l+m (x2 − 1) l , − l ≤ m ≤ l , |x| ≤ 1 (15.11)<br />
(x) (1 − x2 ) m/2 l − m m = 0 P l (x) P l (x) <br />
l m ≥ 0 <br />
<br />
P m l<br />
(x) = (1 − x 2 m/2 dm<br />
)<br />
dx m P l(x)<br />
P m l (−x) = (−1) l+m P m l (x) (15.12)<br />
<br />
P l l (x) = (2l)!<br />
2 l l! (1 − x2 ) l/2 = (2l − 1)!! (1 − x 2 ) l/2 , P l l+1(x) = (2l + 1) x P l l (x) (15.13)
15 251<br />
<br />
<br />
P −m<br />
l<br />
(x) <br />
P 0 (x) = 1 , P 1 (x) = x , P 2 (x) = 3x2 − 1<br />
2<br />
, P 3 (x) = 5x3 − 3x<br />
2<br />
P −m<br />
l<br />
(x) = (−1)m<br />
2 l l!<br />
(1 − x 2 ) m/2 F (x) , F (x) = (x 2 −m dl−m<br />
− 1)<br />
dx l−m (x2 − 1) l<br />
u = x − 1 , v = x + 1 , <br />
l−m<br />
F (x) = u −m −m dl−m<br />
∑<br />
v<br />
dx l−m ul v l = u −m v −m (l − m)! d k u l d l−m−k v l<br />
k! (l − m − k)! dx k dx l−m−k<br />
= ∑ k<br />
k=0<br />
(l − m)! l! l!<br />
k! (l − m − k)! (l − k)! (k + m)! ul−k−m v k<br />
k n = k + m <br />
F (x) = ∑ n<br />
(l − m)! l! l!<br />
(n − m)! (l − n)! (l + m − n)! n! ul−n v n−m<br />
, <br />
d l+m<br />
dx l+m ul v l = ∑ k<br />
(l + m)! l! l!<br />
k! (l + m − k)! (l − k)! (k − m)! ul−k v k−m (l + m)!<br />
=<br />
(l − m)! F (x)<br />
<br />
P −m<br />
m (l − m)!<br />
l<br />
(x) = (−1)<br />
(l + m)!<br />
1<br />
2 l l! (1 − x2 )<br />
m/2 dl+m<br />
dx l+m ul v l<br />
m (l − m)!<br />
= (−1)<br />
(l + m)! P l m (x) (15.14)<br />
<br />
( x 2 − 1 ) l<br />
<br />
d l+m<br />
1<br />
2 l l! dx l+m (x2 − 1) l = 1<br />
2 l l!<br />
= ∑ k<br />
l∑ (−1) k l!<br />
k! (l − k)!<br />
k=0<br />
d l+m<br />
x2l−2k<br />
dxl+m (−1) k (2l − 2k)!<br />
2 l k! (l − k)! (l − m − 2k)! xl−m−2k<br />
k m = 0 <br />
P l (x) =<br />
[l/2]<br />
∑<br />
k=0<br />
(−1) k (2l − 2k)!<br />
2 l k! (l − k)! (l − 2k)! xl−2k (15.15)<br />
x = 0 <br />
⎧<br />
⎪⎨<br />
Pl m (0) =<br />
⎪⎩<br />
(−1) (l−m)/2 (l + m)!<br />
2 l( (l − m)/2 ) ! ( (l + m)/2 ) !<br />
l − m <br />
0 l − m
15 252<br />
x = 1 − 2u <br />
1 d l+m<br />
2 l l! dx l+m (x2 − 1) l = (−1)l+m d l+m<br />
2 m l! du l+m ul (u − 1) l = 1 l∑<br />
2 m<br />
m ≥ 0 k ≥ m , m ≤ 0 k ≥ 0 <br />
⎧<br />
⎪⎨ u m/2 (1 − u) m/2 (l + m)!<br />
Pl m m! (l − m)!<br />
(x) =<br />
⎪⎩ u −m/2 m/2<br />
(−1)m<br />
(1 − u)<br />
(−m)!<br />
x = 1 ( u = 0 ) <br />
k=0<br />
(−1) k+m<br />
k! (l − k)!<br />
d l+m<br />
ul+k<br />
dul+m = 1 ∑ (−1) k+m (l + k)!<br />
2 m k! (k − m)! (l − k)! uk−m (15.16)<br />
k<br />
(<br />
(l + 1 + m)(l − m)<br />
1 − u + · · ·<br />
m + 1<br />
)<br />
, m ≥ 0<br />
(<br />
)<br />
l(l + 1)<br />
1 +<br />
m − 1 u + · · · , m ≤ 0<br />
P l (1) = 1 , P l (−1) = (−1) l , P m l (± 1) = 0 ( m ≠ 0 ) , P ′ l(1) =<br />
l(l + 1)<br />
2<br />
(15.17)<br />
<br />
1/ √ 1 − x <br />
(<br />
2xt − t<br />
2 ) n<br />
<br />
1<br />
√ = ∑<br />
∞ (2n)! (<br />
2xt − t<br />
2 ) n<br />
1 − 2xt + t<br />
2 (2 n n!) 2<br />
n=0<br />
1<br />
√ = ∑<br />
∞<br />
1 − 2xt + t<br />
2<br />
=<br />
n=0<br />
∞∑<br />
n=0 k=0<br />
l = n + k l k <br />
[l/2]<br />
1<br />
√ = ∑<br />
∞ ∑<br />
1 − 2xt + t<br />
2<br />
l=0 k=0<br />
x m <br />
(2n)! ∑<br />
n<br />
(2 n n!) 2<br />
n∑<br />
(2m − 1)!! (1 − x 2 ) m/2<br />
(1 − 2xt + t 2 ) m+1/2 =<br />
k=0<br />
n!<br />
k! (n − k)! (2xt)n−k (−t 2 ) k<br />
(−1) k (2n)!<br />
2 n+k n! k! (n − k)! xn−k t n+k<br />
(−1) k (2l − 2k)!<br />
2 l (l − k)! k! (l − 2k)! xl−2k t l =<br />
∞∑<br />
P l (x) t l (15.18)<br />
l=0<br />
∞∑<br />
t l−m Pl m (x) , m ≥ 0 (15.19)<br />
l=m<br />
(15.18), (15.19) , x, t | t | < min ∣ ∣x ± √ x 2 − 1 ∣ ∣ <br />
x |x| ≤ 1 | t | < 1 <br />
<br />
(15.19) t <br />
(2m − 1)!! (1 − x 2 ) m/2 (2m + 1)(x − t)<br />
(1 − 2xt + t 2 ) = ∑<br />
∞ (l − m)t l−m−1 P m m+3/2 l (x) (15.20)<br />
1 − 2xt + t 2 (15.19) <br />
∞∑<br />
l=m<br />
l=m<br />
(<br />
)<br />
(2m + 1)(x − t)t l−m Pl m (x) − (l − m)t l−m−1 (1 − 2xt + t 2 )Pl m (x) = 0
15 253<br />
<br />
<br />
∞∑<br />
l=m<br />
(<br />
)<br />
(l + m)Pl−1 m − (2l + 1)xPl m + (l + 1 − m)Pl+1<br />
m t l−m = 0<br />
(l + 1 − m)P m l+1 − (2l + 1)xP m l + (l + m)P m l−1 = 0 (15.21)<br />
(15.14) m < 0 , (15.13) Pm−1 m = 0 l = m <br />
m ≥ 0 Pm−1 m = 0 (15.13) , l ≥ m Pl<br />
m(x)<br />
<br />
(15.19) x <br />
∞∑<br />
(1 − x 2 ) dP l<br />
m<br />
dx tl−m = (2m − 1)!!(1 − x2 ) m/2 (<br />
− mx + t(2m + 1)(1 − )<br />
x2 )<br />
(1 − 2xt + t 2 ) m+1/2 1 − 2xt + t 2<br />
l=m<br />
(15.22)<br />
<br />
<br />
∞∑<br />
(1 − x 2 ) dP l<br />
m<br />
dx tl−m =<br />
l=m<br />
1 − x 2<br />
(x − t)2<br />
= 1 −<br />
1 − 2xt + t2 1 − 2xt + t 2<br />
(<br />
) (2m − 1)!!(1 − x 2 ) m/2<br />
(2m + 1)t − mx<br />
(1 − 2xt + t 2 ) m+1/2<br />
− t(x − t) (2m − 1)!!(1 − x2 ) m/2 (2m + 1)(x − t)<br />
(1 − 2xt + t 2 ) m+3/2<br />
(15.19), (15.20) <br />
∞∑<br />
(1 − x 2 ) dP l<br />
m<br />
dx tl−m =<br />
l=m<br />
<br />
=<br />
∞∑<br />
l=m<br />
∞∑<br />
l=m<br />
((<br />
)<br />
(2m + 1)t − mx t l−m − (x − t)(l − m)t l−m) Pl<br />
m<br />
(<br />
(l + m)P m l−1 − lxP m l<br />
)<br />
t l−m<br />
(1 − x 2 ) dP m l<br />
dx = (l + m)P m l−1 − lxP m l = (l + 1)xP m l − (l + 1 − m)P m l+1 (15.23)<br />
(15.21) m < 0 <br />
<br />
(15.22) <br />
∞∑<br />
(x − t) dP l<br />
m<br />
dx tl−m = (2m − 1)!!(1 − x2 ) m/2 (<br />
−<br />
(1 − 2xt + t 2 ) m+1/2<br />
l=m<br />
(15.19), (15.20) <br />
∞∑<br />
(x − t) dP l<br />
m<br />
dx tl−m = −<br />
l=m<br />
mx(x − t)<br />
1 − x 2 ∞ ∑<br />
l=m<br />
t l−m P m l (x) +<br />
)<br />
mx(x − t) (2m + 1)(x − t)<br />
1 − x 2 + t<br />
1 − 2xt + t 2<br />
∞∑<br />
(l − m)t l−m Pl m (x)<br />
l=m<br />
t <br />
x dP m l<br />
dx<br />
− dP l−1<br />
m (<br />
dx = l −<br />
m )<br />
1 − x 2 Pl m + mx<br />
1 − x 2 P l−1<br />
m
15 254<br />
(15.23) P m l−1 <br />
(l + m) dP m l−1<br />
dx<br />
= lxdP m l<br />
dx + ( m<br />
2<br />
1 − x 2 − l2 )<br />
P m l<br />
(15.23) x <br />
( d<br />
dx (1 − x2 ) d<br />
)<br />
dx −<br />
m2<br />
1 − x 2 + l(l + 1) Pl m (x) = 0 (15.24)<br />
x = cos θ <br />
( 1<br />
sin θ<br />
<br />
d<br />
dθ sin θ d dθ −<br />
)<br />
m2<br />
sin 2 θ + l(l + 1) Pl m (cos θ) = 0 (15.25)<br />
<br />
P m l<br />
(15.24) <br />
d<br />
dx<br />
(<br />
(1 − x 2 ) dP m k<br />
dx<br />
)<br />
− P m k<br />
(<br />
d<br />
(1 − x 2 ) dP l<br />
m<br />
dx<br />
dx<br />
) (<br />
)<br />
+ k(k + 1) − l(l + 1) Pl m Pk m = 0<br />
<br />
=<br />
=<br />
(<br />
) ∫ 1<br />
l(l + 1) − k(k + 1) dx Pl<br />
m<br />
∫ 1<br />
−1<br />
[<br />
P m l<br />
(<br />
dx<br />
P m l<br />
−1<br />
(<br />
d<br />
(1 − x 2 ) dP k<br />
m<br />
dx<br />
dx<br />
(x) (1 − x 2 ) dP m k<br />
dx<br />
P m k<br />
)<br />
− P m k<br />
− P m<br />
k (x) (1 − x 2 ) dP m l<br />
dx<br />
(<br />
d<br />
(1 − x 2 ) dP l<br />
m<br />
dx<br />
dx<br />
] 1<br />
−1<br />
= 0<br />
))<br />
l ≠ k <br />
F (x) = x 2 − 1 <br />
∫ 1<br />
−1<br />
dx P m l (x) P m k (x) = 0<br />
∫ 1<br />
dx (P m l (x)) 2 =<br />
∫ 1<br />
−1<br />
−1<br />
dx dl+m F l<br />
H(x) ,<br />
dxl+m (−1)m<br />
H(x) ≡<br />
(2 l l!) 2 F m dl+m F l<br />
dx l+m<br />
<br />
∫ 1<br />
−1<br />
[<br />
dx (Pl m (x)) 2 d l+m−1 F l ] 1<br />
=<br />
dx l+m−1 H −<br />
−1<br />
∫ 1<br />
−1<br />
dx dl+m−1 F l<br />
dx l+m−1<br />
[· · · ] 2l + 1 1 0 <br />
<br />
∫ 1<br />
−1<br />
∫ 1<br />
−1<br />
dx (P m l<br />
(x)) 2 = −<br />
∫ 1<br />
−1<br />
dx dl+m−1 F l<br />
dx l+m−1<br />
∫ 1<br />
∫<br />
dx (Pl m (x)) 2 = (−1) l+m dx F l dl+m H<br />
1<br />
(<br />
−1 dx l+m = (−1)l<br />
(2 l l!) 2 dx F l dl+m<br />
−1 dx l+m F m dl+m F l )<br />
dx l+m<br />
F l = x 2l − lx 2l−2 + · · · <br />
d l+m F l<br />
dx l+m = 2l(2l − 1) · · · (l − m + 1)xl−m + · · · = (2l)!<br />
(l − m)! xl−m + · · ·<br />
dH<br />
dx<br />
dH<br />
dx
15 255<br />
<br />
d l+m (<br />
dx l+m F m dl+m F l ) (<br />
)<br />
dx l+m = dl+m (2l)!<br />
dx l+m (l − m)! xl+m + · · ·<br />
(l + m)!<br />
= (2l)!<br />
(l − m)!<br />
<br />
∫ 1<br />
−1<br />
dx (Pl m (x)) 2 = (2l)! (l + m)!<br />
(2 l l!) 2 (l − m)!<br />
(5.25) <br />
<br />
15.4<br />
∫ 1<br />
−1<br />
∫ 1<br />
−1<br />
dx F (x)P l (x) = 1<br />
2 l l!<br />
∫ 1<br />
−1<br />
dx (1 − x 2 ) l = 2 (l + m)!<br />
2l + 1 (l − m)!<br />
dx Pl m (x) Pk m (x) = 2 (l + m)!<br />
2l + 1 (l − m)! δ lk (15.26)<br />
∫ 1<br />
−1<br />
l > n 0 <br />
15.5<br />
∫ 1<br />
−1<br />
( 2<br />
dx P l(x)) ′ = l(l + 1) <br />
dx dl F<br />
dx l (1 − x2 ) l , F (x) n <br />
15.6<br />
|x| ≤ 1 F (x) <br />
<br />
<br />
<br />
∞∑<br />
l=0<br />
2l + 1<br />
2<br />
a l = 2l + 1<br />
2<br />
∫ 1<br />
−1<br />
P l (x)P l (x ′ ) = δ(x − x ′ ) ,<br />
F (x) =<br />
∞∑<br />
a l P l (x) (15.27)<br />
l=0<br />
dx F (x)P l (x) = 2l + 1<br />
2 l+1 l!<br />
∞∑<br />
n=0<br />
∫ 1<br />
−1<br />
dx dl F<br />
dx l (1 − x2 ) l<br />
(−1) n (4n + 1)(2n)!<br />
2 2n+1 (n!) 2 P 2n (x) = δ(x) (15.28)<br />
15.3 <br />
<br />
Y lm (θ, φ) <br />
Y lm (θ, φ) = (−1) m √<br />
2l + 1 (l − m)!<br />
4π (l + m)! eimφ Pl m (cos θ) , − l ≤ m ≤ l (15.29)<br />
(15.13) (15.17) <br />
Y ll (θ, φ) = (−1)l<br />
2 l l!<br />
√<br />
2l + 1<br />
4π (2l)! sinl θ e ilφ , Y lm (0, φ) =<br />
√<br />
2l + 1<br />
4π δ m0 (15.30)<br />
<br />
C lm ≡ (−1) m √<br />
2l + 1 (l − m)!<br />
4π (l + m)!
15 256<br />
(15.12), (15.14) <br />
Y lm (π − θ, φ + π) = C lm (−1) m e imφ P m l (− cos θ) = (−1) l Y lm (θ, φ) (15.31)<br />
Ylm(θ, ∗ φ) = C lm e −imφ m (l + m)!<br />
(−1)<br />
(l − m)! P −m<br />
l<br />
(cos θ) = (−1) m Y l −m (θ, φ) (15.32)<br />
<br />
(15.25) <br />
<br />
L 2 Y lm = l(l + 1)Y lm , L 2 = (−ir×∇) 2 = − 1<br />
sin θ<br />
x = cos θ <br />
P m l<br />
(x) (15.11) <br />
<br />
<br />
(1 − x 2 ) dP m l<br />
dx = 1<br />
2 l l!<br />
(<br />
L ± = e ±iφ ± ∂ ∂θ + i cot θ ∂ )<br />
∂φ<br />
L ± Y lm (θ, φ) = C lm<br />
e i(m±1)φ<br />
√<br />
1 − x<br />
2<br />
(<br />
∓ (1 − x 2 ) d<br />
dx − mx )<br />
P m l<br />
∂<br />
∂θ sin θ ∂ ∂θ − 1<br />
sin 2 θ<br />
(x)<br />
∂ 2<br />
∂φ 2<br />
)<br />
(− mx(1 − x 2 m/2 dl+m<br />
)<br />
dx l+m + (1 − x2 m/2+1 dl+m+1<br />
)<br />
dx l+m+1 (x 2 − 1) l<br />
= − mxP m l + √ 1 − x 2 P m+1<br />
l<br />
L + Y lm (θ, φ) = − C lm e i(m+1)φ P m+1<br />
l<br />
= √ (l − m)(l + m + 1) Y l m+1<br />
L − Y lm (θ, φ) = C lm<br />
e i(m−1)φ<br />
√<br />
1 − x<br />
2<br />
<br />
(15.24) <br />
(<br />
(1 − x 2 ) d<br />
dx − mx )<br />
F (x) =<br />
( F (x)<br />
dF<br />
√ = C lme i(m−1)φ<br />
1 − x<br />
2 dx − m − 1 )<br />
1 − x 2 xF<br />
(<br />
(1 − x 2 ) d<br />
)<br />
dx + (m − 1)x P m−1<br />
l<br />
( )<br />
dF (m − 1)<br />
2<br />
dx = 1 − x 2 − l(l + 1) + m − 1 P m−1<br />
m−1<br />
dPl<br />
l<br />
+ (m − 1)x<br />
dx<br />
<br />
L − Y lm (θ, φ) = − C lm e i(m−1)φ( )<br />
l(l + 1) − m(m − 1)<br />
P m−1<br />
l<br />
= √ (l + m)(l − m + 1) Y l m−1<br />
L ± Y lm (θ, φ) , Y lm <br />
(15.26) <br />
∫<br />
∫<br />
dΩ Y lm (θ, φ) Yl ∗ ′ m ′(θ, φ) = δ ll ′ δ mm ′ , dΩ · · · =<br />
<br />
θ , φ F (θ, φ) Y lm (θ, φ) <br />
F (θ, φ) =<br />
∞∑<br />
l=0 m=−l<br />
l∑<br />
a lm Y lm (θ, φ)<br />
∫ π<br />
0<br />
dθ sin θ<br />
∫ 2π<br />
0<br />
dφ · · · (15.33)
15 257<br />
(15.33) <br />
∫<br />
dΩ F (θ, φ) Y ∗<br />
lm(θ, φ) =<br />
∞∑<br />
l ′ =0<br />
∑l ′ ∫<br />
a l′ m ′<br />
m ′ =−l ′<br />
dΩ Y ∗<br />
lmY ∗<br />
l ′ m ′ = a lm<br />
<br />
F (θ, φ) =<br />
=<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
∫ π<br />
0<br />
∫<br />
Y lm (θ, φ) dΩ ′ F (θ ′ , φ ′ ) Ylm(θ ∗ ′ , φ ′ )<br />
∫ 2π<br />
dθ ′ dφ ′ F (θ ′ , φ ′ ) sin θ ′<br />
0<br />
∞ ∑<br />
l∑<br />
l=0 m=−l<br />
Y lm (θ, φ)Y ∗<br />
lm(θ ′ , φ ′ )<br />
<br />
<br />
sin θ ′<br />
∞ ∑<br />
l∑<br />
l=0 m=−l<br />
Y lm (θ, φ)Y ∗<br />
lm(θ ′ , φ ′ ) = δ(θ − θ ′ ) δ(φ − φ ′ )<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
Y lm (θ, φ)Y ∗<br />
lm(θ ′ , φ ′ ) = δ(Ω − Ω ′ ) , δ(Ω − Ω ′ ) ≡ δ(θ − θ′ ) δ(φ − φ ′ )<br />
sin θ<br />
, δ(Ω − Ω ′ ) <br />
<br />
∫<br />
dΩ F (θ, φ) δ(Ω − Ω 0 ) =<br />
∫ π<br />
0<br />
dθ<br />
∫ 2π<br />
0<br />
dφ F (θ, φ) δ(θ − θ 0 ) δ(φ − φ 0 ) = F (θ 0 , φ 0 )<br />
<br />
2 r 1 r 2 <br />
r 1 = r 1 ( sin θ 1 cos φ 1 , sin θ 1 sin φ 1 , cos θ 1 ) , r 2 = r 2 ( sin θ 2 cos φ 2 , sin θ 2 sin φ 2 , cos θ 2 )<br />
r 1 r 2 α <br />
cos α = r 1·r 2<br />
r 1 r 2<br />
= sin θ 1 sin θ 2 cos(φ 1 − φ 2 ) + cos θ 1 cos θ 2<br />
c 1 = cos θ 1 , s 1 = sin θ 1 , u = cos α F (u) <br />
1<br />
s 1<br />
(<br />
∂<br />
∂θ 1<br />
s 1<br />
∂<br />
∂u dF<br />
( ) dF<br />
F (u) = s 1<br />
∂θ 1 ∂θ 1 du = c 1 u − c 2<br />
du<br />
) ( ) (<br />
∂<br />
u − c1 c 2 dF (u −<br />
F (u) =<br />
∂θ 1 s 2 − 2u<br />
1 du + c1 c 2 ) 2 ) d<br />
s 2 + c 2 2 − u 2 2 F<br />
1<br />
du 2<br />
s 1<br />
<br />
∂F<br />
= − s 1 s 2 sin(φ 1 − φ 2 ) dF<br />
∂φ 1 du ,<br />
∂ 2 F<br />
∂φ 2 1<br />
= − (u − c 1 c 2 ) dF (<br />
du + s 2 1s 2 2 − (u − c 1 c 2 ) 2) d 2 F<br />
du 2<br />
L 1 = − i r 1 ×∇ 1 <br />
( 1<br />
L 2 ∂ ∂<br />
1F (u) = − s 1 + 1 s 1 ∂θ 1 ∂θ 1 s 2 1<br />
∂ 2<br />
∂φ 2 1<br />
)<br />
F (u) = ( u 2 − 1 ) d 2 F<br />
du 2 + 2udF du<br />
(15.34)
15 258<br />
L 2 2F (u) , L 2 = − i r 2 ×∇ 2 <br />
(<br />
(L 1 ) ± F (u) = e ±iφ 1<br />
± ∂<br />
)<br />
∂<br />
(<br />
)<br />
+ i cot θ 1 F = ± c 1 s 2 e ±iφ 2<br />
− s 1 c 2 e ±iφ 1 dF<br />
∂θ 1 ∂φ 1 du<br />
<br />
<br />
( ∂<br />
(L 1 + L 2 ) ± F (u) = 0 , (L 1 + L 2 ) z F (u) = − i +<br />
∂ )<br />
F (u) = 0<br />
∂φ 1 ∂φ 2<br />
F (u) = P l (u) , (15.24) L 2 1P l (u) = l(l + 1)P l (u) <br />
P l (u) =<br />
l∑<br />
m=−l<br />
a m (θ 2 , φ 2 ) Y lm (θ 1 , φ 1 )<br />
L 2 2P l (u) = l(l + 1)P l (u) (L 2 ) z P l (u) = − (L 1 ) z P l (u) <br />
L 2 2a m (θ 2 , φ 2 ) = l(l + 1) a m (θ 2 , φ 2 ) , (L 2 ) z a m (θ 2 , φ 2 ) = − m a m (θ 2 , φ 2 )<br />
a m (θ 2 , φ 2 ) = c m Y l −m (θ 2 , φ 2 ) <br />
(L 1 ) + P l (u) = ∑ m<br />
c m<br />
√<br />
(l − m)(l + m + 1) Yl m+1 (θ 1 , φ 1 )Y l −m (θ 2 , φ 2 )<br />
(L 2 ) + P l (u) = ∑ m<br />
= ∑ m<br />
c m<br />
√<br />
(l + m)(l − m + 1) Ylm (θ 1 , φ 1 )Y l −m+1 (θ 2 , φ 2 )<br />
c m+1<br />
√<br />
(l + m + 1)(l − m) Yl m+1 (θ 1 , φ 1 )Y l −m (θ 2 , φ 2 )<br />
(L 1 + L 2 ) + P l (u) = 0 c m + c m+1 = 0 c m = (−1) m c 0 <br />
∑<br />
∑<br />
P l (u) = c 0 (−1) m Y lm (θ 1 , φ 1 )Y l −m (θ 2 , φ 2 ) = c 0 Y lm (θ 1 , φ 1 )Ylm(θ ∗<br />
2 , φ 2 )<br />
m<br />
θ 2 = 0 (15.30) <br />
√<br />
∑<br />
2l + 1<br />
P l (cos θ 1 ) = c 0 Y lm (θ 1 , φ 1 )<br />
4π δ 2l + 1<br />
m0 = c 0<br />
4π P l(cos θ 1 )<br />
, <br />
m<br />
P l (cos α) =<br />
4π<br />
2l + 1<br />
l∑<br />
m=−l<br />
θ 1 = θ 2 = θ, φ 1 = φ 2 = φ P l (1) = 1 <br />
<br />
15.7<br />
1. (15.18) <br />
l∑<br />
m=−l<br />
1<br />
∞<br />
|r 1 − r 2 | = ∑ r<<br />
l<br />
r><br />
l+1 P l (cos α) =<br />
l=0<br />
m<br />
Y lm (θ 1 , φ 1 )Y ∗<br />
lm(θ 2 , φ 2 ) (15.35)<br />
|Y lm (θ, φ)| 2 = 2l + 1<br />
4π<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
4π<br />
2l + 1<br />
r<<br />
l<br />
r><br />
l+1<br />
Y lm (ˆr 1 )Y ∗<br />
lm(ˆr 2 )<br />
, |r 1 |, |r 2 | r > , r < , α r 1 r 2
15 259<br />
2. 1. F (r 1 , r 2 ) <br />
F (r 1 , r 2 ) =<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
4π<br />
2l + 1 F l(r 1 , r 2 ) Y lm (ˆr 1 )Y ∗<br />
lm(ˆr 2 )<br />
<br />
F l (r 1 , r 2 ) = θ(r 1 − r 2 ) rl 2<br />
r l+1<br />
1<br />
+ θ(r 2 − r 1 ) rl 1<br />
r2<br />
l+1 , θ(x) =<br />
{<br />
1 , x > 0<br />
0 , x < 0<br />
<br />
∇ 2 1F (r 1 , r 2 ) = ∇ 2 2F (r 1 , r 2 ) = − 4πδ(r 1 − r 2 )<br />
∇ 2 1 r<br />
= − 4πδ(r) <br />
15.4 <br />
<br />
( 1 d 2<br />
) (<br />
l(l + 1)<br />
d<br />
2<br />
ρ + 1 −<br />
ρ dρ2 ρ 2 R l (ρ) =<br />
dρ 2 + 2 d<br />
ρ dρ<br />
)<br />
l(l + 1)<br />
+ 1 −<br />
ρ 2 R l (ρ) = 0 (15.36)<br />
15.10 , <br />
R l (ρ) = ρ l χ l (ρ) <br />
1 d 2<br />
ρ dρ 2 ρR l = 1 d 2<br />
( d<br />
ρ dρ 2 ρl+1 χ l = ρ l 2<br />
2(l + 1) d<br />
+<br />
dρ2 ρ dρ<br />
)<br />
l(l + 1)<br />
+<br />
ρ 2 χ l<br />
( )<br />
d<br />
2<br />
2(l + 1) d<br />
+<br />
dρ2 ρ dρ + 1 χ l = 0 (15.37)<br />
<br />
( ) d<br />
2<br />
2(l + 2) d χ<br />
′<br />
+<br />
dρ2 ρ dρ + 1 l<br />
ρ = 1 (<br />
)<br />
χ ′′′ 2(l + 1)<br />
l + χ ′′ 2(l + 1)<br />
l −<br />
ρ<br />
ρ<br />
ρ 2 χ ′ l + χ ′ l<br />
= 1 ( )<br />
d d<br />
2<br />
2(l + 1) d<br />
+<br />
ρ dρ dρ2 ρ dρ + 1 χ l = 0<br />
χ ′ l /ρ (15.37) l l + 1 C l <br />
χ l+1 (ρ) = C l<br />
ρ<br />
( 2 ( ) l+1<br />
dχ l<br />
1<br />
dρ = C d<br />
1 d<br />
l C l−1 χ l−1 = · · · = N l+1 χ 0<br />
ρ dρ)<br />
ρ dρ<br />
N l+1 N l = (−1) l <br />
(<br />
R l (ρ) = ρ l − 1 ) l<br />
d<br />
R 0<br />
ρ dρ<br />
(15.36) l = 0 (ρR 0 ) ′′ + ρR 0 = 0 ρR 0 sin ρ cos ρ <br />
, ρR 0 = sin ρ ρR 0 = − cos ρ <br />
(<br />
j l (ρ) = ρ l − 1 ) l<br />
d sin ρ<br />
ρ dρ ρ , n l(ρ) = − ρ<br />
(− l 1 ) l<br />
d cos ρ<br />
ρ dρ ρ<br />
(15.38)
15 260<br />
j l , n l <br />
l<br />
(ρ) = j l (ρ) + in l (ρ) = − i ρ<br />
(− l 1 ) l<br />
d e iρ<br />
ρ dρ ρ<br />
l<br />
(ρ) = j l (ρ) − in l (ρ) = i ρ<br />
(− l 1 ) l<br />
d e −iρ<br />
ρ dρ ρ<br />
h (1)<br />
h (2)<br />
(15.39)<br />
(15.40)<br />
, h (1)<br />
l<br />
(ρ) 1 , h (2)<br />
l<br />
(ρ) 2 <br />
(15.36) j l (ρ), n l (ρ), h (1)<br />
l<br />
(ρ), h (2)<br />
l<br />
(ρ) 2 <br />
( ∇ 2 + k 2) ψ(r) = 0 , Y lml <br />
(6.1) <br />
ψ(r) =<br />
( 1<br />
r<br />
∞∑<br />
l∑<br />
l=0 m l =−l<br />
F lml (r) Y lml (θ, φ)<br />
d 2<br />
)<br />
l(l + 1)<br />
r −<br />
dr2 r 2 + k 2 F lml (r) = 0<br />
ρ = kr (15.36) A lml , B lml <br />
F lml (r) = A lml j l (kr) + B lml n l (kr)<br />
h (1)<br />
l<br />
(kr), h (2)<br />
l<br />
(kr) , <br />
ψ(r) =<br />
∞∑<br />
l∑<br />
l=0 m l =−l<br />
(<br />
)<br />
A lml j l (kr) + B lml n l (kr) Y lml (θ, φ) (15.41)<br />
, j l , n l , h (1)<br />
l<br />
, h (2)<br />
l<br />
f l ( ∇ 2 + k 2) f l (kr) Y lml = 0 ,<br />
f l (kr) Y lml k → 0 (15.46), (15.47) ,<br />
(15.41) ∇ 2 ψ = 0 , e ik·r ( ∇ 2 + k 2) ψ(r) = 0 <br />
(15.41) ( (15.50) )<br />
<br />
l (15.38) <br />
j 0 (ρ) = sin ρ<br />
ρ , j sin ρ − ρ cos ρ<br />
1(ρ) =<br />
ρ 2 , j 2 (ρ) = (3 − ρ2 ) sin ρ − 3ρ cos ρ<br />
ρ 3<br />
n 0 (ρ) = − cos ρ<br />
ρ<br />
h (1)<br />
0 (ρ) = − ieiρ<br />
ρ ,<br />
, n 1 (ρ) = −<br />
cos ρ + ρ sin ρ<br />
ρ 2 , n 2 (ρ) = − (3 − ρ2 ) cos ρ + 3ρ sin ρ<br />
ρ 3<br />
(ρ + h(1)<br />
i)eiρ<br />
1 (ρ) = −<br />
ρ 2 , h (1)<br />
2 (ρ) = − (3ρ + i(3 − ρ2 ))e iρ<br />
ρ 3 (15.42)<br />
j l , n l , h (1)<br />
l<br />
, h (2)<br />
l<br />
f l <br />
(<br />
f l (ρ) = ρ l − 1 ρ<br />
<br />
) l<br />
d<br />
f 0 (ρ)<br />
dρ<br />
df l<br />
(−<br />
dρ = 1 l<br />
d<br />
lρl−1 f 0 + ρ<br />
ρ dρ) l d (<br />
− 1 ) l<br />
d<br />
f 0 = l dρ ρ dρ ρ f l − f l+1
15 261<br />
<br />
df l+1<br />
dρ<br />
= d dρ<br />
(15.36) d 2 f l /dρ 2 <br />
df l+1<br />
<br />
dρ = l + 2<br />
ρ<br />
( l<br />
ρ f l − df )<br />
l<br />
= − l<br />
dρ ρ 2 f l + l df l<br />
ρ dρ − d2 f l<br />
dρ 2<br />
(<br />
)<br />
df l<br />
dρ + l(l + 2)<br />
1 −<br />
ρ 2 f l = l + 2<br />
ρ<br />
= f l − l + 2<br />
ρ<br />
( ) (<br />
)<br />
l<br />
ρ f l(l + 2)<br />
l − f l+1 + 1 −<br />
ρ 2 f l<br />
f l+1<br />
df l<br />
dρ = f l−1 − l + 1 f l = l ρ ρ f l − f l+1 , f l−1 + f l+1 = 2l + 1 f l (15.43)<br />
ρ<br />
, j −1 = − n 0 , n −1 = j 0 l = 0 <br />
<br />
<br />
1 d<br />
ρ dρ<br />
<br />
sin ρ<br />
ρ<br />
=<br />
∞∑<br />
n=1<br />
sin ρ<br />
ρ<br />
(−1) n<br />
(2n + 1)! 2n ρ2(n−1) ,<br />
=<br />
∞∑<br />
n=0<br />
( 1<br />
ρ<br />
(−1) n<br />
(2n + 1)! ρ2n<br />
) 2<br />
d sin ρ<br />
dρ ρ<br />
=<br />
∞∑<br />
n=2<br />
(−1) n<br />
(2n + 1)! 22 n(n − 1) ρ 2(n−2)<br />
<br />
(<br />
− 1 ) l<br />
d sin ρ ∑<br />
∞<br />
= (−1) l (−1) n<br />
ρ dρ ρ<br />
(2n + 1)! 2l n(n − 1) · · · (n − l + 1) ρ 2(n−l)<br />
=<br />
∞∑<br />
k=0<br />
n=l<br />
(−1) k 2 l (k + l)!<br />
(2k + 2l + 1)! k! ρ2k =<br />
∞∑<br />
k=0<br />
(−1) k<br />
2 k (2k + 2l + 1)!! k! ρ2k<br />
<br />
<br />
<br />
<br />
1 d<br />
ρ dρ<br />
cos ρ<br />
ρ<br />
=<br />
l <br />
∞∑<br />
n=0<br />
(2n + 1)!! = (2n + 1)(2n − 1) · · · 3 · 1 =<br />
j l (ρ) = ρ l<br />
cos ρ<br />
ρ<br />
(−1) n<br />
(2n)! (2n − 1) ρ2n−3 ,<br />
∞ ∑<br />
k=0<br />
=<br />
(2n + 1)!<br />
2 n n!<br />
(−1) k<br />
2 k (2k + 2l + 1)!! k! ρ2k (15.44)<br />
∞∑<br />
n=0<br />
( 1<br />
ρ<br />
n l (ρ) = − 1<br />
ρ l+1<br />
(−1) n<br />
(2n)! ρ2n−1<br />
) 2<br />
d cos ρ<br />
dρ ρ<br />
∞ ∑<br />
n=0<br />
=<br />
(−1) n+l C nl<br />
(2n)!<br />
∞∑<br />
n=0<br />
(−1) n<br />
(2n)!<br />
(2n − 1)(2n − 3) ρ2n−5<br />
ρ 2n (15.45)<br />
, C n0 = 1, l ≥ 1 C nl = (2n − 1)(2n − 3) · · · (2n + 1 − 2l) , <br />
⎧<br />
⎪⎨<br />
1<br />
C nl = (2n − 1)!! × (2n − 2l − 1)!! , n ≥ l<br />
⎪⎩ (−1) l−n (2l − 2n − 1)!! , n ≤ l
15 262<br />
(−1)!! = 1 n = 0 n = l <br />
<br />
ρ → 0 (15.44), (15.45) <br />
j l (ρ) =<br />
n l (ρ) = −<br />
ρ l (<br />
1 −<br />
(2l + 1)!!<br />
ρ 2 )<br />
2(2l + 3) + · · ·<br />
(<br />
(2l − 1)!! ρ 2 )<br />
ρ l+1 1 +<br />
2(2l − 1) + · · ·<br />
(15.46)<br />
(15.47)<br />
n l (ρ) ρ → ∞ <br />
( 1<br />
ρ<br />
) l<br />
d f(ρ)<br />
dρ ρ<br />
= 1 ( d l f l(l + 1)<br />
ρ l+1 −<br />
dρl 2ρ<br />
d l−1 f<br />
dρ l−1 + O( ρ −2))<br />
( l = 1, 2, 3 ), (15.39), (15.40) <br />
(<br />
h (1)<br />
l(l + 1)<br />
l<br />
(ρ) = − i 1 + i<br />
2ρ<br />
(<br />
h (2)<br />
l(l + 1)<br />
l<br />
(ρ) = i 1 − i + · · ·<br />
2ρ<br />
) e<br />
i(ρ−lπ/2)<br />
+ · · ·<br />
ρ<br />
) e<br />
−i(ρ−lπ/2)<br />
ρ<br />
(15.48)<br />
<br />
j l (ρ) = 1 ρ<br />
n l (ρ) = 1 ρ<br />
(<br />
l(l + 1)<br />
sin(ρ − lπ/2) +<br />
2ρ<br />
(15.87), (15.88) <br />
)<br />
cos(ρ − lπ/2) + · · ·<br />
(<br />
l(l + 1)<br />
− cos(ρ − lπ/2) + sin(ρ − lπ/2) + · · ·<br />
2ρ<br />
) (15.49)<br />
<br />
(15.43) <br />
dn l<br />
j l<br />
dρ − n dj l<br />
l<br />
dρ = j l n l−1 − n l j l−1 = j l+1 n l − n l+1 j l<br />
l <br />
(<br />
)<br />
ρ 2 dn l<br />
j l<br />
dρ − n dj l<br />
l = ρ 2( )<br />
j 1 n 0 − n 1 j 0 = 1<br />
dρ<br />
<br />
15.8 (15.43) d dρ ρl+1 f l (ρ) = ρ l+1 f l−1 (ρ) ,<br />
d<br />
dρ ρ−l f l (ρ) = − ρ −l f l+1 (ρ) <br />
15.9<br />
(15.36) <br />
(<br />
)<br />
d<br />
ρj l<br />
dρ ρn d<br />
l − ρn l<br />
dρ ρj l = ρ 2 dn l<br />
j l<br />
dρ − n dj l<br />
l<br />
dρ<br />
<br />
15.10<br />
(15.36) R l (ρ) <br />
R l (ρ) = ρ α<br />
∞ ∑<br />
n=0<br />
a n ρ n , a 0 ≠ 0
15 263<br />
1. (15.36) α = l, − l − 1 , a 1 = 0 <br />
(<br />
)<br />
(α + 2 + n) (α + 3 + n) − l(l + 1) a n+2 + a n = 0<br />
<br />
2. n a n = 0 , n n = 2k b k = a 2k <br />
b k = −<br />
α = l , <br />
b k−1<br />
(α + 2k) (α + 1 + 2k) − l(l + 1)<br />
b k = (−1)k (2l + 1)!!<br />
2 k k! (2l + 2k + 1)!! b 0<br />
b 0 = 1/(2l + 1)!! (15.44) α = − l − 1 <br />
b 0 = − (2l − 1)!! (15.45) <br />
15.11<br />
|x| ≤ 1 , 15.6 <br />
e iqx =<br />
∞∑<br />
l=0<br />
a l (q)P l (x) , a l (q) = 2l + 1<br />
2 l+1 l!<br />
∫ 1<br />
−1<br />
dx dl e iqx<br />
dx l (1 − x 2 ) l<br />
<br />
1. a l (q) = i l (2l + 1)I l (q) <br />
2. I l (q) = j l (q) <br />
3. (15.35) <br />
I l (q) = 1<br />
2 l l! ql (<br />
1 + d2<br />
dq 2 ) l<br />
j 0 (q)<br />
exp(ik·r) = 4π<br />
∞∑<br />
l∑<br />
l=0 m=−l<br />
â a <br />
i l j l (kr)Y lm (ˆr)Y ∗<br />
lm(ˆk) (15.50)<br />
15.5 <br />
<br />
Γ (x) =<br />
∫ ∞<br />
0<br />
dt e −t t x−1 (15.51)<br />
, x − 1 > −1 <br />
Γ (x + 1) = − [ e −t t x ] ∫ ∞<br />
t=∞<br />
t=0 + x dt e −t t x−1 = xΓ (x) (15.52)<br />
x < 0 <br />
0<br />
Γ (x) =<br />
Γ (x + 1)<br />
x<br />
=<br />
Γ (x + 2)<br />
x(x + 1) = · · · = Γ (x + n)<br />
x(x + 1) · · · (x + n − 1)<br />
(15.53)<br />
x = 1 <br />
Γ (n + 1) = n! Γ (1) = n! (15.54)
15 264<br />
x = 1/2 <br />
<br />
u = √ t <br />
<br />
<br />
Γ (n + 1/2) = 1 2 · 3<br />
2 · · · 2n − 1 Γ (1/2) =<br />
2<br />
(2n − 1)!!<br />
2 n Γ (1/2)<br />
(2n − 1)!! = 1·3 · · · (2n − 3)·(2n − 1) = (2n)!<br />
2 n n!<br />
Γ (1/2) =<br />
∫ ∞<br />
0<br />
Γ (n + 1/2) =<br />
dt e −t t −1/2 = 2<br />
∫ ∞<br />
0<br />
du e −u2 = √ π<br />
(2n − 1)!! √ (2n)! √ π = π (15.55)<br />
2 n 2 2n n!<br />
k x = − k + δ , (15.53) n = k + 1 <br />
Γ (−k + δ) =<br />
Γ (1 + δ)<br />
(−k + δ)(−k + 1 + δ) · · · (−1 + δ) δ<br />
δ→0<br />
−−−−→<br />
, Γ (x) x 0 <br />
(15.53) y = 1 − x − n <br />
Γ (1 − x) = Γ (y + n) = y(y + 1) · · · (y + n − 2)(y + n − 1)Γ (y)<br />
Γ (1)<br />
(−k)(−k + 1) · · · (−1) δ = (−1)k 1<br />
k! δ<br />
<br />
= (−1) n (x + n − 1)(x + n − 2) · · · (x + 1)x Γ (1 − x − n)<br />
n Γ (x + n)<br />
= (−1) Γ (1 − x − n)<br />
Γ (x)<br />
Γ (x)Γ (1 − x) = (−1) n Γ (x + n)Γ (1 − x − n) (15.56)<br />
, Γ (x)Γ (1 − x) = π/ sin(πx) <br />
<br />
B(p, q) =<br />
∫ 1<br />
2 t = x/(1 − x) <br />
0<br />
dx x p−1 (1 − x) q−1 =<br />
∫ ∞<br />
Γ t = (1 + u)s , ( 1 + u > 0 ) x = p + q <br />
∫ ∞<br />
u p−1 u <br />
<br />
∫ ∞<br />
0<br />
t = us <br />
<br />
<br />
0<br />
ds e −(1+u)s s p+q−1 =<br />
∫ ∞<br />
du u p−1 ds e −(1+u)s s p+q−1 = Γ (p + q)<br />
0<br />
=<br />
=<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
∫ ∞<br />
0<br />
0<br />
dt<br />
Γ (p + q)<br />
(1 + u) p+q<br />
du<br />
∫ ∞<br />
ds e −s s p+q−1 du u p−1 e −us<br />
0<br />
t p−1<br />
(1 + t) p+q (15.57)<br />
u p−1<br />
= Γ (p + q) B(p, q)<br />
(1 + u)<br />
p+q<br />
ds e −s s p+q−1 1 ∫ ∞<br />
s p dt t p−1 e −t = Γ (q)Γ (p)<br />
B(p, q) =<br />
0<br />
Γ (p)Γ (q)<br />
Γ (p + q)<br />
(15.58)
15 265<br />
15.6 <br />
a , b 0 , <br />
)<br />
(x d2<br />
d<br />
+ (b − x)<br />
dx2 dx − a w(x) = 0 (15.59)<br />
w(x) <br />
(15.59) <br />
k=0<br />
w(x) = x α<br />
∞ ∑<br />
k=0<br />
c k x k , c 0 ≠ 0<br />
∞∑<br />
∞∑<br />
c k (α + k) (α + k − 1 + b) x α+k−1 − c k (α + k + a) x α+k = 0<br />
1 2 1 k ′ = k − 1 k ′ k <br />
∞∑<br />
c k (α + k) (α + k − 1 + b) x α+k−1 =<br />
k=0<br />
k = −1 k ≥ 0 <br />
c 0 α (α − 1 + b) x α−1 +<br />
∞∑<br />
k=−1<br />
k=0<br />
c k+1 (α + k + 1) (α + k + b) x α+k<br />
∞∑ (<br />
)<br />
c k+1 (α + k + 1) (α + k + b) − c k (α + k + a) x α+k = 0<br />
k=0<br />
x <br />
c 0 α (α − 1 + b) = 0 , c k+1 (α + k + 1) (α + k + b) − c k (α + k + a) = 0 (15.60)<br />
c 0 ≠ 0 1 α = 0 α = 1 − b <br />
α = 0 (15.60) 2 <br />
<br />
c k+1 = 1 a + k<br />
k + 1 b + k c k (15.61)<br />
c 1 = a b c 0 , c 2 = 1 a + 1<br />
2 b + 1 c 1 = 1 a(a + 1)<br />
2 b(b + 1) c 0 , c 3 = 1 a + 2<br />
3 b + 2 c 2 = 1 a(a + 1)(a + 2)<br />
3! b(b + 1)(b + 2) c 0<br />
<br />
c k = 1 (a) k<br />
c 0 ,<br />
k! (b) k<br />
(a) k ≡<br />
{<br />
1 , k = 0<br />
a(a + 1) · · · (a + k − 1) , k > 0<br />
(15.62)<br />
<br />
w(x) = c 0 M(a, b, x) , M(a, b, x) ≡<br />
∞∑<br />
k=0<br />
(a) k x k<br />
(b) k k!<br />
(15.63)<br />
M(a, b, x) (15.62) (15.53) n = 0, 1, 2, · · · <br />
⎧<br />
⎪⎨ (−1) k n!<br />
a = − n (−n) k = (n − k)! , k ≤ n<br />
Γ (a + k)<br />
, a ≠ − n (a) k = (15.64)<br />
⎪⎩<br />
Γ (a)<br />
0 , k > n
15 266<br />
α = 1 − b , (15.60) 2 <br />
c k+1 = 1 a − b + 1 + k<br />
c k<br />
k + 1 2 − b + k<br />
(15.61) a , b a − b + 1 , 2 − b <br />
w(x) = c 0 x 1−b M(a − b + 1, 2 − b, x)<br />
, C , D <br />
w(x) = C M(a, b, x) + D x 1−b M(a − b + 1, 2 − b, x) (15.65)<br />
b M(a − b + 1, 2 − b, x) , <br />
w(x) = C M(a, b, x) <br />
a = − n, ( n = 0, 1, 2, · · · ) (15.64) k > n (a) k = 0 M(−n, b, x)<br />
x n <br />
M(0, b, x) = 1 , M(−1, b, x) = 1 − x b , M(−2, b, x) = 1 − 2 b x + x2<br />
b(b + 1)<br />
(15.66)<br />
, a ≠ −n M(a, b, x) (15.59) x → ∞ <br />
(x d2<br />
dx 2 − x d )<br />
dx − a M(a, b, x) = 0<br />
|x dM/dx| ≫ |aM| <br />
( d<br />
2<br />
x<br />
dx 2 − d )<br />
M(a, b, x) = 0 ,<br />
dx<br />
∴ M(a, b, x) = Ce x + D<br />
M(a, b, x) Re x → ∞ e x (15.80) <br />
b ≠ − n , ( n = 0, 1, 2, · · · ) , b = − n k ≥ n + 1 (b) k = 0 <br />
M(a, b, x) a = − m, ( m = 0, 1, 2, · · · ) <br />
m < n M(−m, −n, x) =<br />
m∑<br />
k=0<br />
(−m) k x k<br />
(−n) k k! = m!<br />
n!<br />
m∑<br />
k=0<br />
(n − k)!<br />
(m − k)! k! xk (15.67)<br />
, b = − n M(−m, −n, x) <br />
n M(−n, b, x)<br />
M(−n, b, x) =<br />
<br />
<br />
d n<br />
dx n xb+n−1 e −x =<br />
n∑<br />
k=0<br />
n∑<br />
k=0<br />
(−1) k n!<br />
k! (n − k)! (b) k<br />
x k (15.68)<br />
n! d k e −x d n−k x b+n−1 ∑<br />
n<br />
k! (n − k)! dx k dx n−k = e −x (−1) k n! d n−k x b+n−1<br />
k! (n − k)! dx n−k<br />
k=0<br />
d n−k x b+n−1<br />
dx n−k<br />
= (b + n − 1)(b + n − 2) · · · (b + n − 1 − (n − k) + 1)x b−1+k<br />
=<br />
b(b + 1) · · · (b + n − 1)<br />
b(b + 1) · · · (b + k − 1) zb−1+k = (b) n<br />
(b) k<br />
z b−1+k
15 267<br />
<br />
<br />
<br />
d n<br />
dx n xb+n−1 e −x = e −x x b−1<br />
ν + b > 0 , <br />
I ν (n, b) =<br />
∫ ∞<br />
0<br />
n ∑<br />
k=0<br />
M(−n, b, x) = ex x −b+1<br />
(−1) k n! (b) n<br />
x k = e −x x b−1 (b) n M(− n, b, x)<br />
k! (n − k)! (b) k<br />
(b) n<br />
d n<br />
dx n xb+n−1 e −x (15.69)<br />
dx e −x x b+ν−1 M 2 (−n, b, x) = 1 ∫ ∞<br />
dx x ν M(−n, b, x) dn f<br />
(b) n dx n<br />
f(x) = x b+n−1 e −x <br />
I ν (n, b) = 1<br />
(b) n<br />
[<br />
x ν M(−n, b, x) dn−1 f<br />
dx n−1 ] ∞<br />
0<br />
0<br />
− 1 ∫ ∞ (<br />
) ′ d<br />
dx x ν n−1 f<br />
M(−n, b, x)<br />
(b) n dx n−1<br />
x → ∞ [· · · ] 0 x → 0 x ν+b ν + b > 0 0 <br />
, <br />
I ν (n, b) = (−1)n<br />
(b) n<br />
∫ ∞<br />
0<br />
dx x b+n−1 e<br />
0<br />
−x dn<br />
dx n xν M(−n, b, x) (15.70)<br />
ν I ν ν = 0, ± 1 (15.68) <br />
(<br />
)<br />
x ν M(−n, b, x) = (−1)n x n+ν − n(b + n − 1)x n+ν−1 + · · ·<br />
(b) n<br />
<br />
d n<br />
(−1)n<br />
M(−n, b, x) = n! ,<br />
dxn (b) n<br />
d n<br />
(<br />
)<br />
(−1)n<br />
xM(−n, b, x) = n! n + 1)x − n(b + n − 1)<br />
dxn (b) n<br />
<br />
I 0 (n, b) = n! ∫ ∞<br />
[(b) n ] 2 dx x b+n−1 e −x = n!<br />
n! Γ (b)<br />
Γ (b + n) =<br />
0<br />
[(b) n ]<br />
2<br />
(b) n<br />
I 1 (n, b) = n! ∫ ∞<br />
[(b) n ] 2 dx x b+n e −x( )<br />
n! Γ (b)<br />
( )<br />
(n + 1)x − n(b + n − 1) = b + 2n<br />
(b) n<br />
0<br />
ν = −1 <br />
d n<br />
( )<br />
dx n x−1 M(−n, b, x) = dn 1<br />
dx n x + (n − 1) = (−1)n n!<br />
x n+1<br />
<br />
I −1 (n, b) = n! ∫ ∞<br />
dx x b−2 e −x =<br />
(b) n<br />
ν + b > 0 ν = 0, ± 1 <br />
∫ ∞<br />
0<br />
dx e −x x b+ν−1 M 2 (−n, b, x) =<br />
0<br />
n! Γ (b − 1)<br />
(b) n<br />
(<br />
n! Γ (b + ν)<br />
1 +<br />
(b) n<br />
)<br />
ν(ν + 1)n<br />
b<br />
(15.71)
15 268<br />
15.12<br />
(4.7) ρ = q 2 , h <br />
h = CM(−n/2, 1/2, ρ) + Dρ 1/2 M(−n/2 + 1/2, 3/2, ρ)<br />
, n = 2k h = CM(−k, 1/2, q 2 ), <br />
n = 2k + 1 h = CqM(−k, 3/2, q 2 ) H n (x) <br />
H 2n (x) = (−1) n (2n)!<br />
n!<br />
<br />
<br />
M(−n, 1/2, x 2 n (2n + 1)!<br />
) , H 2n+1 (x) = (−1) 2x M(−n, 3/2, x 2 )<br />
n!<br />
(15.59) M(a, b, x) <br />
∫<br />
M(a, b, x) = dz e xz v(z) (15.72)<br />
C z , <br />
)<br />
∫<br />
)<br />
(x d2<br />
d<br />
+ (b − x)<br />
dx2 dx − a M(a, b, x) = dz v(z)<br />
(x d2<br />
d<br />
+ (b − x)<br />
C dx2 dx − a<br />
∫ (<br />
)<br />
= dz v(z) xz 2 + (b − x)z − a e xz<br />
∫<br />
=<br />
C<br />
C<br />
C<br />
e xz<br />
( (z<br />
dz v(z)<br />
2 − z ) )<br />
d<br />
dz + bz − a e xz<br />
1 <br />
) (x d2<br />
d<br />
+ (b − x)<br />
dx2 dx − a M(a, b, x) = [( z 2 − z ) e xz v(z) ] C<br />
∫ ( ( )<br />
+ dz e xz (b − 2)z − a + 1 v(z) − ( z 2 − z ) )<br />
dv<br />
dz<br />
C<br />
, [ f(z) ] C f(z) , <br />
<br />
[ (<br />
z 2 − z ) e xz v(z) ] (<br />
)<br />
C = 0 , (b − 2)z − a + 1 v(z) − ( z 2 − z ) dv<br />
dz = 0<br />
(15.72) (15.59) v 0 v(z) = v 0 z a−1 (1−z) b−a−1<br />
<br />
M(a, b, x) = v 0<br />
∫<br />
C<br />
dz e xz z a−1 (1 − z) b−a−1 ,<br />
[<br />
e xz z a (1 − z) b−a ] C = 0 (15.73)<br />
, a, b z z a , (1 − z) b−a <br />
Re(b) > Re(a) > 0 , C z = 0 z = 1 , <br />
z = 0, 1 e xz z a (1 − z) b−a = 0 (15.73) <br />
M(a, b, 0) = 1 (15.57) <br />
1 = v 0<br />
∫ 1<br />
0<br />
∫ 1<br />
M(a, b, x) = v 0 dz e xz z a−1 (1 − z) b−a−1<br />
0<br />
dz z a−1 (1 − z) b−a−1 = v 0 B(a, b − a) = v 0<br />
Γ (a)Γ (b − a)<br />
Γ (b)
15 269<br />
<br />
M(a, b, x) =<br />
Γ (b)<br />
Γ (a)Γ (b − a)<br />
∫ 1<br />
0<br />
dz e xz z a−1 (1 − z) b−a−1 , Re(b) > Re(a) > 0<br />
(15.57), (15.58) <br />
Γ (b)<br />
∞∑ x k ∫ 1<br />
M(a, b, x) =<br />
dz z a+k−1 (1 − z) b−a−1 =<br />
Γ (a)Γ (b − a) k!<br />
k=0<br />
M(a, b, x) (15.63) <br />
, a b <br />
b z =<br />
0 z = 1 C <br />
C 0 <br />
z = re iθ0 ,<br />
1 − z = r ′ e iθ1<br />
0<br />
∞∑<br />
k=0<br />
(a) k x k<br />
(b) k k!<br />
C<br />
C 0<br />
0 1<br />
z<br />
, z 0 1 θ 0 =<br />
θ 1 = 0 z = 1 θ 0 θ 1 2π (1−z) b−a<br />
e 2πi(b−a) = e −2πia , z = 0 θ 0 2π z a e 2πia<br />
e −2πia × e 2πia = 1 C 0 e xz z a (1 − z) b−a <br />
(15.73) <br />
M(a, b, x) = v 0<br />
∫<br />
C 0<br />
dz e xz z a−1 (1 − z) b−a−1<br />
ε , z = 0 z = εe iθ , ( θ : −2π → 0 ) <br />
iε a ∫ 0<br />
−2π<br />
dθ e xz e iaθ (1 − z) b−a−1 = iε a ∫ 0<br />
z = 1 z = 1 − εe iθ , ( θ : 0 → 2π ) <br />
0<br />
0<br />
−2π<br />
dθ e iaθ = ε a 1 − e−2πia<br />
a<br />
∫ 2π<br />
∫ 2π<br />
− iε b−a dθ e xz z a−1 e i(b−a)θ = − iε b−a e x dθ e i(b−a)θ = ε b−a e x 1 − e−2πia<br />
b − a<br />
, z = re −2πi 1 − z = r ′ e 2πi , <br />
(∫ 1−ε ∫ ε<br />
)<br />
M(a, b, x) = v 0 + e −2πia dz e xz z a−1 (1 − z) b−a−1<br />
ε<br />
1−ε<br />
(<br />
+ v 0 1 − e<br />
−2πia ) ( ε a a + εb−a e x )<br />
b − a<br />
(<br />
= v 0 1 − e<br />
−2πia ) (∫ 1−ε<br />
dz e xz z a−1 (1 − z) b−a−1 + εa a + εb−a e x )<br />
v 0 b > Re(a) > 0 ε → 0 <br />
x = 0 <br />
ε<br />
(<br />
M(a, b, x) = v 0 1 − e<br />
−2πia ) ∫ 1<br />
dz e xz z a−1 (1 − z) b−a−1<br />
1 = v 0<br />
(<br />
1 − e<br />
−2πia ) ∫ 1<br />
<br />
∫<br />
M(a, b, x) = v 0 (a, b)<br />
C<br />
0<br />
0<br />
b − a<br />
dz z a−1 (1 − z) b−a−1 = v 0<br />
(<br />
1 − e<br />
−2πia ) Γ (a)Γ (b − a)<br />
Γ (b)<br />
dz e xz z a−1 (1 − z) b−a−1 , v 0 (a, b) =<br />
1 Γ (b)<br />
1 − e −2πia Γ (a)Γ (b − a)<br />
(15.74)
15 270<br />
C C <br />
, , (15.74) <br />
a <br />
C , x = |x|e iφ <br />
Z R = − Re −iφ , ( R > 0 ) z <br />
y > 0 z = (−R+iy)e −iφ e xz = e −|x|(R+iy)<br />
, R → ∞ , <br />
<br />
M(a, b, x) = W 1 (a, b, x) + W 2 (a, b, x) ,<br />
W k (a, b, x) = v 0<br />
∫<br />
Z R C 1<br />
C 2<br />
z<br />
0 1<br />
C k<br />
dz e xz z a−1 (1 − z) b−a−1<br />
2 <br />
) (x d2<br />
d<br />
+ (b − x)<br />
dx2 dx − a [<br />
W k (a, b, x) = v 0 e xz z a (1 − z) b−a ] C k<br />
, C 1 e xz = e −|x|R<br />
W 2 (15.59) 2 <br />
C 0 C 1 <br />
Z R z = − |z|e −iφ = − r x , r : 0 → ∞<br />
<br />
( Re(a) > 0 )<br />
W 1 = − v 0<br />
x<br />
<br />
∫ ∞<br />
0<br />
dr e −r ( − r x<br />
R→∞<br />
−−−−→ 0 C 2 , W 1<br />
z = − |z|e −iφ−2πi = − re−2πi<br />
x<br />
) a−1 (<br />
1 + r ) b−a−1 v 0 −<br />
x x<br />
= Γ (b)<br />
Γ (b − a) (−x)−a g(a, a + 1 − b, − x)<br />
g(a, b, x) = 1<br />
Γ (a)<br />
∫ ∞<br />
0<br />
∫ 0<br />
∞<br />
, r : ∞ → 0<br />
( ) a−1 (<br />
dr e −r − re−2πi<br />
1 + r ) b−a−1<br />
x<br />
x<br />
dr e −r r a−1 ( 1 − r x) − b<br />
(15.75)<br />
C 2 1 z = 1−r/x , ( r : ∞ → 0 ), z = 1−re 2πi /x ,<br />
( r : 0 → ∞ ) ( b > Re(a) )<br />
W 2 = − v 0<br />
x<br />
<br />
∫ 0<br />
∞dr e x−r ( 1 − r x) a−1 ( r<br />
x<br />
= Γ (b)<br />
Γ (a) ex x a−b g(b − a, 1 − a, x)<br />
) b−a−1<br />
−<br />
v 0<br />
x<br />
∫ ∞<br />
0<br />
dr e x−r ( 1 − r x<br />
) a−1<br />
( re<br />
2πi<br />
x<br />
) b−a−1<br />
M(a, b, x) = W 1 (a, b, x) + W 2 (a, b, x) (15.76)<br />
W 1 (a, b, x) =<br />
Γ (b)<br />
Γ (b − a) (−x)−a g(a, a + 1 − b, − x) (15.77)<br />
W 2 (a, b, x) = Γ (b)<br />
Γ (a) ex x a−b g(b − a, 1 − a, x) = e x W 1 (b − a, b, −x) (15.78)
15 271<br />
b > Re(a) > 0 , a W 1 W 2 <br />
2 <br />
f(x) = (1 − x) −b <br />
<br />
(1 − x) −b =<br />
∞∑<br />
k=0<br />
f (k) (0)<br />
k!<br />
g(a, b, x) = 1<br />
Γ (a)<br />
=<br />
∞∑<br />
k=0<br />
∞∑<br />
k=0<br />
(b) k<br />
k!<br />
x k =<br />
(b) k<br />
k!<br />
∞∑<br />
k=0<br />
Γ (a + k)<br />
Γ (a)<br />
b(b + 1) · · · (b + k − 1)<br />
k!<br />
∫<br />
1 ∞<br />
x k dr e −r r a+k−1<br />
0<br />
1<br />
∞<br />
x k = ∑<br />
k=0<br />
(a) k (b) k<br />
k!<br />
x k =<br />
∞∑<br />
k=0<br />
(b) k<br />
k! xk<br />
1<br />
x k = 1 + ab<br />
x + · · · (15.79)<br />
, |x| → ∞ <br />
M(a, b, x) =<br />
Γ (b) (<br />
)<br />
a(a + 1 − b)<br />
Γ (b − a) (−x)−a 1 − + · · ·<br />
x<br />
+ Γ (b) (<br />
)<br />
Γ (a) ex x a−b (1 − a)(b − a)<br />
1 + + · · ·<br />
x<br />
(15.80)<br />
(15.79) , k = ∞ , x <br />
, g(a, b, x) <br />
b , z a (1 − z) b−a 269 <br />
e 2πi(b−a) e 2πia = e 2πib ≠ 1 , <br />
(15.73) , C <br />
z = 1 <br />
e 2πi(b−a) e −2πi(b−a) = 1 z = 0 <br />
z a (1 − z) b−a b <br />
0 1<br />
, (15.76) ∼ (15.78) <br />
15.13 C <br />
∫<br />
1<br />
Γ (b)<br />
M(a, b, x) =<br />
(1 − e −2πia )(1 − e 2πi(b−a) ) Γ (a)Γ (b − a)<br />
C<br />
dz e xz z a−1 (1 − z) b−a−1<br />
, z = 0 z = 1 , <br />
269 (15.76) <br />
<br />
<br />
f n (x) =<br />
n∑<br />
k=0<br />
c<br />
)<br />
k<br />
, lim<br />
xk xn( f(x) − f n (x) = 0 (15.81)<br />
|x|→∞<br />
f n (x) f(x) lim<br />
n→∞ f n(x) <br />
f(x) = f n (x) + O(|x| −n ) , f n (x) |x| <br />
g(a, b, x) <br />
z<br />
∞∑<br />
g(a, b, x) = D k ,<br />
k=0<br />
D k = (a) k(b) k<br />
k!<br />
1 (a + k − 1)(b + k − 1)<br />
= D<br />
xk k−1<br />
kx
15 272<br />
a , b , <br />
, k |D k | ≈ |kD k−1 /x| > |D k−1 | k = n <br />
g n (a, b, x) <br />
x n( )<br />
g(a, b, x) − g n (a, b, x) =<br />
∞∑<br />
k=n+1<br />
(a) k (b) k<br />
k!<br />
1<br />
x k−n<br />
x→∞<br />
−−−−→ 0<br />
g n (a, b, x) <br />
lim<br />
n→∞ f n(x) , x n , <br />
, , |x| , <br />
g(a, b, x) (15.75) <br />
g( 1, b, −x) =<br />
∫ ∞<br />
0<br />
( ) b ∫ x<br />
∞<br />
dr e −r = x b e x dr e−r<br />
r + x<br />
r b<br />
b = 1 g n ( 1, b, −x) |1 − g n /g| x n <br />
n ≈ x , <br />
n = 1 , n = 15 g n (1, b, −x) , <br />
x<br />
1.0<br />
10 −1<br />
10 −2<br />
x = 5<br />
0.9<br />
10 −3<br />
10 −4<br />
10 −5<br />
10 −6<br />
10 0 x = 10<br />
x = 15<br />
0 5 10 15 20<br />
n<br />
0.8<br />
0.7<br />
0.6<br />
n = 1<br />
n = 15<br />
0 5 10 15<br />
x<br />
<br />
(15.36) <br />
R l (ρ) = ρ l e iρ S(z) ,<br />
z = −2iρ<br />
<br />
<br />
z d2 S<br />
dS<br />
+ (2l + 2 − z) − (l + 1)S = 0 (15.82)<br />
dz2 dz<br />
H (1)<br />
l<br />
(ρ) = 2l+1 l!<br />
(2l + 1)! ρl e iρ W 1 (l + 1, 2l + 2, −2iρ) = (−i)<br />
H (2)<br />
l<br />
(ρ) = 2l+1 l!<br />
(2l + 1)! ρl e iρ W 2 (l + 1, 2l + 2, −2iρ) = i<br />
(15.36) 2 (15.64), (15.79) <br />
H (1)<br />
l+1 eiρ<br />
l<br />
(ρ) = (−i)<br />
ρ<br />
∞∑<br />
k=0<br />
(l + 1) k (−l) k<br />
k!<br />
l+1 eiρ<br />
l+1 e−iρ<br />
ρ<br />
1<br />
eiρ<br />
= (−i)l+1<br />
(2iρ)<br />
k<br />
ρ<br />
ρ<br />
g(l + 1, −l, 2iρ)<br />
g(l + 1, −l, −2iρ)<br />
l∑<br />
k=0<br />
(l + k)!<br />
( ) k i<br />
(l − k)! k! 2ρ
15 273<br />
<br />
<br />
H (1)<br />
l+1 + H(1)<br />
eiρ<br />
l−1<br />
= (−i)l+2<br />
ρ<br />
∑l−1<br />
F =<br />
<br />
k=0<br />
(<br />
F +<br />
(<br />
= 2l + 1 l+1 eiρ<br />
(−i)<br />
ρ ρ<br />
(2l + 1)!<br />
l!<br />
( ( (l + 1 + k)! (l − 1 + 1 i<br />
−<br />
(l + 1 − k)! (l − 1 − k)!)<br />
k! 2ρ<br />
H (1)<br />
l+1 + H(1) l−1 = 2l + 1 l+1 eiρ<br />
(−i)<br />
ρ<br />
ρ<br />
( ) l ( ) ) l+1 i (2l + 2)! i<br />
+<br />
2ρ (l + 1)! 2ρ<br />
ρ (2l − 1)!<br />
F +<br />
(2l + 1) i (l − 1)!<br />
) k ∑l−1<br />
= 2(2l + 1)<br />
= i 2l + 1<br />
ρ<br />
l∑ (l + k)! 1<br />
(l − k)! k!<br />
k=0<br />
( ) l−1 i<br />
+ (2l)! ( ) ) l i<br />
2ρ l! 2ρ<br />
k=1<br />
∑l−2<br />
k=0<br />
(l − 1 + k)! 1<br />
(l + 1 − k)! (k − 1)!<br />
(l + k)! 1<br />
(l − k)! k!<br />
( ) k i<br />
2ρ<br />
( ) k i<br />
= 2l + 1 H (1)<br />
l<br />
2ρ ρ<br />
(15.43) , l = 0, 1 (15.42) <br />
(<br />
H (1)<br />
0 (ρ) = − ieiρ<br />
ρ = h(1) 0 (ρ) , H(1) 1 (ρ) = − 1 + i ) e<br />
iρ<br />
ρ ρ = h(1) 1 (ρ)<br />
( ) k i<br />
2ρ<br />
, l h (1)<br />
l<br />
(ρ) = H (1)<br />
l<br />
(ρ) h (1) (ρ) <br />
h (1)<br />
l<br />
(ρ) = 2l+1 l!<br />
(2l + 1)! ρl e iρ l+1 eiρ<br />
l∑<br />
( ) k<br />
(l + k)! i<br />
W 1 (l + 1, 2l + 2, −2iρ) = (−i) (15.83)<br />
ρ (l − k)! k! 2ρ<br />
<br />
h (2)<br />
l<br />
(ρ) = 2l+1 l!<br />
(2l + 1)! ρl e iρ l+1 e−iρ<br />
W 2 (l + 1, 2l + 2, −2iρ) = i<br />
ρ<br />
j l (ρ) , n l (ρ) <br />
j l (ρ) = h(1) l<br />
(ρ) + h (2)<br />
l<br />
(ρ)<br />
2<br />
k=0<br />
l∑<br />
k=0<br />
(<br />
(l + k)!<br />
− i ) k<br />
(15.84)<br />
(l − k)! k! 2ρ<br />
= 2l l!<br />
(2l + 1)! ρl e iρ( W 1 (l + 1, 2l + 2, −2iρ) + W 2 (l + 1, 2l + 2, −2iρ)<br />
= 2l l!<br />
(2l + 1)! ρl e iρ M(l + 1, 2l + 2, −2iρ) (15.85)<br />
)<br />
n l (ρ) = h(1) l<br />
(ρ) − h (2)<br />
l<br />
(ρ)<br />
2i<br />
2 l l!<br />
= − i<br />
(2l + 1)! ρl e iρ( )<br />
W 1 (l + 1, 2l + 2, −2iρ) − W 2 (l + 1, 2l + 2, −2iρ)<br />
(15.83), (15.84) <br />
(15.86)<br />
j l (ρ) =<br />
sin(ρ − lπ/2)<br />
ρ<br />
+<br />
cos(ρ − lπ/2)<br />
ρ 2<br />
[l/2]<br />
∑<br />
k=0<br />
(l + 2k)! (−1) k<br />
(l − 2k)! (2k)! (2ρ) 2k<br />
[(l−1)/2]<br />
∑<br />
k=0<br />
(l + 2k + 1)! (−1) k<br />
(l − 2k − 1)! (2k + 1)! (2ρ) 2k (15.87)
15 274<br />
<br />
n l (ρ) = −<br />
+<br />
cos(ρ − lπ/2)<br />
ρ<br />
sin(ρ − lπ/2)<br />
ρ 2<br />
[l/2]<br />
∑<br />
k=0<br />
[(l−1)/2]<br />
∑<br />
k=0<br />
(l + 2k)! (−1) k<br />
(l − 2k)! (2k)! (2ρ) 2k<br />
(l + 2k + 1)! (−1) k<br />
(l − 2k − 1)! (2k + 1)! (2ρ) 2k (15.88)<br />
15.14<br />
(15.82) 2 M(a, b, z) z 1−b M(a − b + 1, 2 − b, z) <br />
a = l + 1 , b = 2l + 2 = 2a M(a, b, z) j l (ρ) z 1−b M(a − b + 1, 2 − b, z) <br />
h (1)<br />
l<br />
<br />
15.7 <br />
<br />
L α n(x) ≡ ex x −α d n<br />
n! dx n e−x x n+α = (α + 1) n<br />
M(−n, α + 1, x) (15.89)<br />
n!<br />
( Laguerre ) , α = 0 , L n (x) <br />
III , <br />
<br />
(L k n) Schiff = n! (−1) k L k n−k , (L k n) Messiah = (n + k)! L k n<br />
(15.89) , (15.68) <br />
L α n(x) =<br />
n∑<br />
m=0<br />
(−1) m C nm (α)<br />
x m (15.90)<br />
m! (n − m)!<br />
<br />
C nm (α) = (α + 1) n<br />
(α + 1) m<br />
=<br />
{<br />
1 , m = n<br />
(α + n)(α + n − 1) · · · (α + m + 1) , 0 ≤ m ≤ n − 1<br />
<br />
k = 0, 1, 2, · · · C nm (k) = (n + k)!/(m + k)! <br />
<br />
L k n(x) =<br />
n∑<br />
m=0<br />
m − k m <br />
<br />
(−1) m n+k<br />
(n + k)!<br />
∑ (−1) m (n + k)!<br />
m! (n − m)! (m + k)! xm , L n+k (x) =<br />
m! (n + k − m)! m! xm<br />
d k<br />
n+k<br />
dx k L ∑<br />
n+k(x) =<br />
m=k<br />
d k<br />
dx k L n+k(x) = (−1) k<br />
n ∑<br />
m=0<br />
m=0<br />
(−1) m (n + k)! m!<br />
m! (n + k − m)! m! (m − k)! xm−k<br />
(−1) m (n + k)!<br />
m! (n − m)! (m + k)! xm = (−1) k L k n(x) (15.91)
15 275<br />
<br />
| t | < 1 <br />
f(x, t) =<br />
1<br />
(<br />
(1 − t) α+1 exp −<br />
xt )<br />
=<br />
1 − t<br />
∞∑ (−x) m<br />
t m (1 − t) −m−α−1<br />
m!<br />
m=0<br />
(1 − t) −m−α−1 <br />
(1 − t) −m−α−1 = 1 +<br />
<br />
f(x, t) =<br />
∞∑<br />
∞∑<br />
m=0 k=0<br />
∞∑<br />
k=1<br />
1<br />
k! (α + m + 1)(α + m + 2) · · · (α + m + k) tk =<br />
(−x) m C m+k,m (α)<br />
m! k!<br />
k = n − m <br />
<br />
<br />
L α n+1 <br />
(n + 1)L α n+1 = ex x −α<br />
t m+k =<br />
1<br />
(<br />
(1 − t) α+1 exp −<br />
xt )<br />
=<br />
1 − t<br />
n!<br />
∞∑<br />
n∑<br />
n=0 m=0<br />
(−x) m C nm (α)<br />
m! (n − m)!<br />
∞∑<br />
k=0<br />
t n =<br />
C m+k,m (α)<br />
k!<br />
∞∑<br />
L α n(x) t n<br />
n=0<br />
∞∑<br />
L α n(x) t n , | t | < 1 (15.92)<br />
n=0<br />
d n+1<br />
dx n+1 e−x x n+1+α = ex x −α d n (<br />
n! dx n (n + 1 + α)e −x x n+α − e −x x n+1+α)<br />
f(x) = e −x x n+α <br />
<br />
<br />
n − 1 <br />
= (n + 1 + α)L α n − ex x −α<br />
d n<br />
dx n e−x x n+1+α = dn xf(x)<br />
dx n = x dn f(x)<br />
dx n + n dn−1 f(x)<br />
dx n−1<br />
(n + 1)L α n+1 = (n + 1 + α − x)L α n − ex x −α<br />
n!<br />
d n−1<br />
d n<br />
dx n e−x x n+1+α<br />
(n − 1)! dx n−1 e−x x n+α<br />
d<br />
dx e−x x n+α = (n + α)x n+α−1 e −x − e −x x n+α<br />
d n−1<br />
dx n−1 e−x x n+α = (n + α) dn−1<br />
dx n−1 e−x x n+α−1 − dn<br />
dx n e−x x n+α<br />
t k<br />
<br />
<br />
e x x −α d n−1<br />
(n − 1)! dx n−1 e−x x n+α = (n + α)L α n−1 − nL α n (15.93)<br />
(n + 1)L α n+1 = (2n + α + 1 − x)L α n − (n + α)L α n−1 (15.94)<br />
<br />
, <br />
xL α+1<br />
n<br />
= ex x −α<br />
n!<br />
d n<br />
dx n e−x x n+α+1 = ex x −α<br />
n!<br />
(x dn<br />
dx n e−x x n+α + n dn−1<br />
dx n−1 e−x x n+α )
15 276<br />
(15.93) <br />
xL α+1<br />
n = (x − n)L α n + (n + α)L α n−1 = (n + α + 1)L α n − (n + 1)L α n+1 (15.95)<br />
<br />
L α n <br />
<br />
<br />
<br />
dL α n<br />
dx = Lα n − α x Lα n + ex x −α d n+1<br />
n! dx n+1 e−x x n+α<br />
d n+1<br />
dx n+1 e−x x n+1+α = x dn+1<br />
dx n+1 e−x x n+α + (n + 1) dn<br />
dx n e−x x n+α<br />
L α n+1 = ex x −α<br />
(n + 1)! x dn+1<br />
dx n+1 e−x x n+α + L α n<br />
x dLα n<br />
dx = (x − α)Lα n + (n + 1)(L α n+1 − L α n) (15.96)<br />
= n L α n − (n + α)L α n−1 (15.97)<br />
<br />
(15.97) <br />
x(L α n) ′′ + (L α n) ′ = n(L α n) ′ − (n + α)(L α n−1) ′<br />
(15.96) <br />
x(L α n−1) ′ = nL α n + (x − α − n)L α n−1 = nL α n + x − α − n (nL α n − x(L α<br />
n + α<br />
n) ′)<br />
(<br />
<br />
)<br />
x d2<br />
d<br />
+ (α + 1 − x)<br />
dx2 dx + n L α n(x) = 0 (15.98)<br />
( d<br />
dx e−x x α+1 d<br />
dx + n e−x x α )<br />
L α n(x) = 0 (15.99)<br />
(15.98) a = −n, b = α + 1 <br />
<br />
α + 1 > 0 <br />
I nm ≡<br />
∫ ∞<br />
<br />
0<br />
dx e −x x α L α n(x)L α m(x) = 1 n!<br />
I nm = (−1)n<br />
n!<br />
∫ ∞<br />
0<br />
dx e −x x<br />
∫ ∞<br />
0<br />
n+α dn<br />
dx L α m(x) dn<br />
dx n e−x x n+α<br />
dx n Lα m(x)<br />
n ≥ m L α m(x) m , n > m n <br />
0 (15.90) <br />
<br />
L α n(x) = (−1)n x n + (n − 1) , ∴ I nn = 1 n!<br />
n!<br />
(15.99) L α m<br />
I nm = 0 <br />
∫ ∞<br />
0<br />
dx e −x x α L α n(x)L α m(x) =<br />
∫ ∞<br />
0<br />
dx e −x x n+α =<br />
Γ (n + α + 1)<br />
n!<br />
δ nm<br />
Γ (n + α + 1)<br />
n!<br />
n, m n ≠ m
15 277<br />
15.8 <br />
<br />
w(q) <br />
<br />
d 2 w<br />
dq 2<br />
d 2 w<br />
− qw(q) = 0 (15.100)<br />
dq2 w(q) =<br />
∫ ∞<br />
∫ ∞<br />
= − dk e ikq k 2 ϕ(k) , qw(q) =<br />
−∞<br />
−∞<br />
dk e ikq ϕ(k)<br />
∫ ∞<br />
−∞<br />
dk ϕ(k)(− i) ∂<br />
∂k eikq = i<br />
k → ± ∞ ϕ(k) → 0 (15.100) <br />
∫ ∞<br />
(<br />
dk e ikq k 2 + i d )<br />
dϕ<br />
ϕ(k) = 0 , ∴<br />
dk<br />
dk = ik2 ϕ<br />
−∞<br />
∫ ∞<br />
−∞<br />
ikq dϕ(k)<br />
dk e<br />
dk<br />
ϕ(k) ∝ e ik3 /3 C <br />
w(q) = CAi(q) , Ai(q) ≡ 1<br />
2π<br />
∫ ∞<br />
−∞<br />
( ) ik<br />
3<br />
dk exp<br />
3 + ikq<br />
Ai(q) (Airy) z = aq <br />
( )<br />
( d<br />
2<br />
d<br />
dq 2 − q Ai(aq) = a 2 2<br />
dz 2 − z )<br />
a 3 Ai(z)<br />
(15.101)<br />
a = e ±2πi/3 a 3 = 1 Ai(e ±2πi/3 q) (15.100) <br />
(<br />
)<br />
Bi(q) = e iπ/6 Ai(e 2πi/3 q) + e −iπ/6 Ai(e −2πi/3 q) = 2Re e iπ/6 Ai(e 2πi/3 q)<br />
, (15.100) C, D w(q) = CAi(q) + DBi(q) <br />
Ai(q) Bi(q) q → ∞ Ai(q) , Bi(q) <br />
, q → − ∞ |q| −1/4 a n Ai(a n ) = 0 <br />
(15.102) (15.103) , |q| 2 <br />
, q → − ∞ (15.102) , a n <br />
2<br />
3 |a n| 3/2 + π [ 3π<br />
4 ≈ nπ , ∴ a n ≈ −<br />
2<br />
(<br />
n − 1 4)] 2/3<br />
, n = 1, 2, 3, · · ·<br />
<br />
1.0<br />
Bi(q)<br />
0.5<br />
a 5<br />
a 4<br />
a 3<br />
−5<br />
a 2<br />
a 1<br />
−1<br />
O<br />
Ai(q)<br />
1 2<br />
q<br />
−0.5
15 278<br />
<br />
(15.101) k = √ |q| z <br />
Ai(q) =<br />
√<br />
|q|<br />
2π<br />
∫ ∞<br />
−∞<br />
dz e λf ±(z) , λ = |q| 3/2 , f ± (z) = iz3<br />
3 ± iz<br />
q > 0 f + (z), q < 0 f − (z) z <br />
z = Re iθ <br />
Re f ± (z) = −<br />
(sin R3<br />
3θ ± 3 )<br />
3<br />
R 2 sin θ<br />
sin 3θ > 0, <br />
0 < θ < π 3 , 2π<br />
3 < θ < π , 4π<br />
3 < θ < 5π 3<br />
R → ∞ e λf±(z) → 0 0 < θ < π/3 <br />
2π/3 < θ < π 2 , <br />
C C D 1 , D 2 <br />
( ∫ R ∫ ∫ )<br />
− + + dz e<br />
−R C D 1<br />
∫D λf ±(z) = 0<br />
2<br />
−R<br />
D 2<br />
C<br />
D 1<br />
R<br />
R → ∞ D 1 D 2 0 <br />
∫ ∞<br />
∫<br />
dz e λf ±(z) = dz e λf ±(z)<br />
−∞<br />
C<br />
, (15.101) f ± (z) <br />
, (14.23) |q| → ∞ Ai(q) <br />
q > 0 <br />
f +(z ′ 0 ) = i ( z0 2 + 1 ) = 0<br />
z 0 z 0 = ± i z = x + iy <br />
i<br />
C 1<br />
z 0 = i <br />
( )<br />
x<br />
2<br />
Imf + (z) = x<br />
3 − y2 + 1 = = Imf + (z 0 ) = 0<br />
C −<br />
C ′<br />
−1<br />
1<br />
C +<br />
z 0 = i <br />
√<br />
x<br />
2<br />
x = 0 y =<br />
3 + 1<br />
f + (z) z = z 0 ( z = z 0 + re iθ )<br />
f + (z) = f + (z 0 ) + f +(z ′′ 0 )<br />
(z − z 0 ) 2 + · · · = f + (z 0 ) + iz 0 (z − z 0 ) 2 + · · · = − 2 2<br />
3 − r2 e 2iθ + · · ·<br />
e 2iθ = 1 θ = 0, π x = 0 θ = ± π/2 x = 0 <br />
, y = √ x 2 /3 + 1 z = i x θ = 0, π <br />
C 1 C 1 <br />
<br />
Ai(q) =<br />
√ q<br />
2π<br />
∫<br />
C 1<br />
dz e λf+(z)
15 279<br />
λ → ∞ r = 0 − ε ≤ r ≤ ε <br />
√ ∫ q ε<br />
Ai(q) ≈ dr dz √ ∫ q ε<br />
(<br />
2π dr eλf +(z) = dr exp − 2 )<br />
2π<br />
3 λ − λr2 + · · ·<br />
−ε<br />
, θ = 0 dz/dr = e iθ = 1 <br />
√ ∫ q<br />
ε<br />
Ai(q) ≈<br />
2π e−2λ/3 dr e −λr2 =<br />
λ → ∞ ε √ λ → ∞ <br />
<br />
Ai(q) ≈<br />
−ε<br />
−ε<br />
√ q<br />
2π e−2λ/3 1<br />
(<br />
1<br />
2 √ π q exp − 2 )<br />
1/4 3 q3/2<br />
√<br />
∫ ε λ<br />
√ ds e −s2<br />
λ<br />
−ε √ λ<br />
q < 0 f −(z ′ 0 ) = 0 z 0 z 0 = ± 1 <br />
( )<br />
x<br />
2<br />
z 0 = ± 1 x<br />
3 − y2 − 1 = = Im f − (z 0 ) = ∓ 2 3<br />
C ± C + + C − <br />
√ ∫ |q|<br />
Ai(q) = I + + I − , I ± = dz e λf−(z)<br />
2π C ±<br />
f − (z) z 0 = ± 1 ( z − z 0 = re iθ± )<br />
f − (z) = f − (z 0 ) + f −(z ′′ 0 )<br />
(z − z 0 ) 2 + · · · = ∓ 2i<br />
2<br />
3 − r2 e 2iθ±∓iπ/2 + · · ·<br />
e 2iθ±∓iπ/2 = 1 , θ ± = ± π/4 dz = dre iθ±<br />
q > 0 <br />
( (<br />
1<br />
2<br />
I ± ≈<br />
2 √ π |q| exp ∓ i<br />
1/4 3 |q|3/2 − π ))<br />
4<br />
<br />
<br />
Ai(q) ≈<br />
(<br />
1 2<br />
√ cos π |q|<br />
1/4 3 |q|3/2 − π )<br />
(<br />
1 2<br />
= √<br />
4<br />
sin π |q|<br />
1/4 3 |q|3/2 + π )<br />
4<br />
<br />
⎧<br />
⎪⎨<br />
Ai(q) →<br />
⎪⎩<br />
(<br />
1<br />
2 √ π q exp − 2 )<br />
1/4 3 q3/2 , q → ∞<br />
1<br />
√ π |q|<br />
1/4 sin ( 2<br />
3 |q|3/2 + π 4<br />
)<br />
, q → − ∞<br />
(15.102)<br />
<br />
Bi(q) <br />
Ai(e 2πi/3 q) = 1<br />
2π<br />
∫ ∞<br />
( ) ik<br />
3<br />
∫ ( )<br />
dk exp<br />
3 + iqe2πi/3 k = e−2πi/3<br />
ik<br />
3<br />
dk exp<br />
2π C 3 + iqk ′<br />
√ ∫ |q|<br />
= e −2πi/3 dz e λf±(z)<br />
2π C ′<br />
−∞<br />
, k ′ = e 2πi/3 k k ′ k 2π/3 <br />
C ′ q < 0 , C − <br />
Ai(e 2πi/3 q) = − e −2πi/3 I − ≈<br />
(i e−iπ/6<br />
2 √ π |q| exp 2 1/4 3 |q|3/2 + iπ )<br />
4
15 280<br />
q > 0 , C ′ C 1 −π/3 < θ < 0 0 <br />
q > 0 z 0 = − i <br />
√<br />
x<br />
2<br />
x = 0 y = −<br />
3 + 1<br />
z = z 0 <br />
f + (z) = f + (z 0 ) + f +(z ′′ 0 )<br />
(z − z 0 ) 2 + · · · = 2 2<br />
3 + r2 e 2iθ + · · ·<br />
x = 0 θ = ± π/2 f + (z) = 2/3 − r 2 + · · · x = 0, , <br />
C ′ Re z < 0 C ′ Im z < 0 <br />
Ai(e 2πi/3 q) ≈ e −2πi/3 √ q<br />
2π<br />
∫ ε<br />
−ε<br />
( )<br />
dr e iπ/2 e 2λ/3−λr2 ≈ e−πi/6 2<br />
2 √ π q exp 1/4 3 q3/2<br />
<br />
(<br />
)<br />
Bi(q) = 2Re e iπ/6 Ai(e 2πi/3 q) →<br />
⎧<br />
⎪⎨<br />
⎪⎩<br />
( )<br />
1 2<br />
√ exp π q<br />
1/4 3 q3/2 , q → ∞<br />
(<br />
1 2<br />
√ cos π |q|<br />
1/4 3 |q|3/2 + π )<br />
, q → − ∞<br />
4<br />
(15.103)<br />
<br />
15.9 <br />
<br />
z <br />
∞∑<br />
k=0<br />
H k (q)<br />
k!<br />
∞∑<br />
k=0<br />
C<br />
H k (q)<br />
z k = e −z2 +2qz<br />
k!<br />
∫<br />
∫<br />
dz z k−n−1 = dz e −z2 +2qz 1<br />
C 1 <br />
∫<br />
{<br />
2πi , n = k<br />
dz z k−n−1 =<br />
C<br />
0 , n ≠ k<br />
<br />
H n (q) = n!<br />
2πi<br />
∫<br />
C<br />
∫<br />
dz e −z2 +2qz 1 n!<br />
=<br />
zn+1 2πi<br />
n → ∞ H n (q) <br />
C<br />
C<br />
z n+1<br />
(<br />
dz exp −z 2 + 2qz − (n + 1) log z<br />
ω(n + 1/2) , q 2 =<br />
2n + 1 q = √ 2n + 1 q ′ , z = √ 2n + 1 z ′ <br />
H n ( √ 2n + 1 q ) = 1 n!<br />
dz exp<br />
((2n + 1)f(z) −<br />
2πi (2n + 1)<br />
∫C<br />
1 )<br />
n/2 2 log z<br />
)<br />
<br />
f(z) = −z 2 + 2qz − 1 2 log z
15 281<br />
, q ′ , z ′ q, z n → ∞ <br />
z = Re iθ <br />
Re f(z) = −R 2 cos 2θ + 2qR cos θ − 1 2 log r<br />
cos 2θ > 0 R → ∞ e (2n+1)f(z)<br />
→ 0 , <br />
− π/4 < θ < π/4 , 3π/4 < θ < 5π/4 <br />
f(z) z f ′ (z) = −2z + 2q − 1/(2z) = 0 <br />
z 2 ± = qz ± − 1/4 <br />
4z + z − = 1 <br />
z = z ± = q ± √ q 2 − 1<br />
2<br />
f(z ± ) = 1 4 + qz ± − 1 2 log z ±<br />
f ′′ (z ± ) = 1 − 4z2 ±<br />
2z 2 ±<br />
= 2 z ∓ − z ±<br />
z ±<br />
= 8z ∓ (z ∓ − z ± )<br />
<br />
|q| < 1 <br />
q = sin φ ,<br />
√<br />
1 − q2 = cos φ , |φ| < π 2<br />
<br />
z ± = 1 2<br />
(<br />
)<br />
sin φ ± i cos φ = 1 2 e∓i(π/2−φ) , f ′′ (z ± ) = − 4 cos φ e ±iφ<br />
, z = z ± z − z ± = re iθ ±<br />
<br />
f(z) = f ± + f ′′ (z ± )<br />
(z − z ± ) 2 = f ± − 2r 2 cos φ e i(2θ±±φ) , f ± = f(z ± )<br />
2<br />
z = z ± r 2 e i(2θ ±±φ) = 1 , <br />
θ ± = ∓ φ 2 , π ∓ φ 2<br />
<br />
Im f(z) = − 2xy + 2qy − 1 2 tan−1 y x = = Im f(z ±)<br />
C ± , 2 <br />
C R → ∞<br />
C +<br />
z +<br />
0 <br />
<br />
H n ( √ 2n + 1 q ) = 1 n!<br />
2πi (2n + 1) (I n/2 − + I + )<br />
∫<br />
I ± = dz e (2n+1)f(z)− 1 2 log z<br />
C ±<br />
−R<br />
C −<br />
z −<br />
R
15 282<br />
θ − = φ 2 , θ + = π − φ 2 n → ∞ z = z ± <br />
I ± ≈<br />
∫ ε<br />
(<br />
dr e iθ± exp (2n + 1)f ± − 2(2n + 1)r 2 cos φ − 1 )<br />
2 log z ±<br />
−ε<br />
(<br />
≈ exp iθ ± + (2n + 1)f ± − 1 ) ∫ ∞ (<br />
)<br />
2 log z ± dr exp −2(2n + 1)r 2 cos φ<br />
(<br />
= exp iθ ± + (2n + 1)f ± − 1 2 log z ±<br />
)√<br />
−∞<br />
π<br />
2(2n + 1) cos φ<br />
<br />
iθ + − 1 2 log z + = iπ − i 2 φ − 1 ( )<br />
1<br />
2 log 2 e−i(φ−π/2) = iπ + log √ 2 − iπ 4<br />
iθ − − 1 2 log z − = log √ 2 + iπ 4<br />
<br />
, f ± <br />
<br />
(<br />
exp iθ ± − 1 )<br />
2 log z ± = √ 2 i e ±iπ/4<br />
f ± = f(z ± ) = 1 4 ± i 2 e∓iφ sin φ + 1 2 log 2 ± i 2<br />
(<br />
φ − π )<br />
= f 1 ± i f 2<br />
2 2<br />
<br />
<br />
f 1 = 1 2 + log 2 + sin2 φ , f 2 = sin φ cos φ + φ − π 2<br />
(<br />
(<br />
I ± ≈ i exp (n + 1/2)f 1 ± i (n + 1/2)f 2 + π )) √<br />
π<br />
4 (2n + 1) cos φ<br />
H n ( √ 2n + 1 q ) ≈ √ 1 n! e<br />
(<br />
(n+1/2)f1<br />
√ cos (n + 1/2)f π (2n + 1) (n+1)/2 2 + π )<br />
cos φ<br />
4<br />
= D n<br />
e (n+1/2) sin2 φ<br />
√ cos φ<br />
( (<br />
)<br />
cos (n + 1/2) sin φ cos φ + φ − nπ 2<br />
(<br />
e (n+1/2)q2 2n + 1<br />
(<br />
= D n<br />
(1 − q 2 ) cos q √ )<br />
1 − q 1/4 2<br />
2 + sin −1 q − nπ 2<br />
)<br />
)<br />
<br />
n ≫ 1 <br />
√<br />
2<br />
D n =<br />
n (n!) 2<br />
π(n + 1/2) n+1 e −(n+1/2)<br />
(<br />
(n + 1) log n + 1 ) (<br />
≈ (n + 1) log n + 1 )<br />
≈ (n + 1) log n + 1 2<br />
2n<br />
2<br />
(n + 1/2) n+1 ≈ n n+1 e 1/2 n n e −n ≈ n!/ √ 2πn <br />
D n ≈<br />
( 2 n+1/2 n!<br />
√ nπ<br />
) 1/2<br />
(15.104)
15 283<br />
q > 1 , <br />
, z − C − <br />
H n ( √ 2n + 1 q ) = 1<br />
∫<br />
n!<br />
dz e (2n+1)f(z)− 1<br />
2πi (2n + 1) n/2 2 log z<br />
C −<br />
C −<br />
z − z +<br />
z = z − <br />
f(z) = f(z − ) + µr 2 e 2iθ ,<br />
z − z − = re iθ<br />
<br />
µ = 1 (<br />
2 f ′′ (z − ) = 4z + (z + − z − ) = 2 q + √ √<br />
q 2 − 1)<br />
q2 − 1<br />
e 2iθ = −1 θ = π/2 <br />
H n ( √ 2n + 1 q ) ≈ 1<br />
(<br />
n!<br />
2πi (2n + 1) exp (2n + 1)f(z n/2 − ) − 1 ) ∫ ∞<br />
2 log z − i dr e −(2n+1)µr2<br />
−∞<br />
= 1<br />
√<br />
n!<br />
π<br />
2π (2n + 1) n/2 e(2n+1)f(z −)<br />
(2n + 1)µz −<br />
µz − = √ q 2 − 1 <br />
f(z − ) = 1 4 + qz − − 1 2 log z − = 1 4 + qz − + 1 2 log z + + log 2<br />
<br />
H n ( √ 2n + 1 q ) ≈ D n<br />
2<br />
= D n<br />
2<br />
(2z + ) n+1/2 (<br />
)<br />
(q 2 − 1) exp (2n + 1)qz 1/4 −<br />
(<br />
q + √ ) n+1/2<br />
q 2 − 1<br />
( 2n + 1<br />
exp<br />
(q 2 − 1) 1/4 2<br />
(<br />
q 2 − q √ ) )<br />
q 2 − 1<br />
, D n (15.104) <br />
√ 2n + 1 q q z = q/<br />
√ 2n + 1 <br />
( 2n + 1<br />
⎧⎪<br />
exp(q 2 /2) ⎨ cos<br />
H n (q) = D n<br />
|1 − z 2 | × 2<br />
1/4 ⎪ ⎩<br />
1<br />
2<br />
(<br />
z + √ z 2 − 1<br />
(<br />
z √ )<br />
1 − z 2 + sin −1 z − nπ 2<br />
)<br />
, |z| < 1<br />
) (<br />
n+1/2exp<br />
− 2n + 1 z √ )<br />
z<br />
2<br />
2 − 1 , z > 1<br />
(15.105)
284<br />
<br />
<br />
94, 229<br />
α 157<br />
246<br />
247<br />
18<br />
185<br />
(1 ) 25<br />
(3 ) 120<br />
112<br />
1, 6, 16, 217<br />
32, 277<br />
141<br />
4<br />
S 186<br />
7<br />
7, 210<br />
59, 248, 280<br />
<br />
159<br />
107<br />
74<br />
99<br />
3, 6<br />
2<br />
79<br />
2<br />
() 258<br />
157<br />
9, 72, 213, 250<br />
213<br />
263<br />
174<br />
3<br />
9<br />
81, 117<br />
() 8<br />
69<br />
260<br />
260<br />
120, 260, 272<br />
84, 255<br />
111<br />
85, 214<br />
81<br />
121, 144, 199<br />
120, 124<br />
228<br />
21, 67<br />
103<br />
19<br />
209<br />
178<br />
1, 4, 12, 60, 74<br />
1<br />
265<br />
242<br />
241<br />
68<br />
8<br />
8, 211<br />
<br />
246<br />
176<br />
1<br />
162<br />
224<br />
97<br />
115<br />
114<br />
112<br />
22, 76, 110, 118, 122, 126<br />
143<br />
122<br />
163<br />
12<br />
148
285<br />
79<br />
79<br />
168<br />
61<br />
34, 131, 140, 146, 207<br />
109<br />
90<br />
88<br />
1 105<br />
3 105<br />
61<br />
241<br />
94<br />
23<br />
134<br />
62<br />
165<br />
271<br />
164<br />
<br />
WKB 148<br />
170<br />
175<br />
(1 ) 57<br />
(3 ) 125<br />
9, 72, 249, 254<br />
14<br />
6, 86<br />
164<br />
238<br />
42<br />
118<br />
75<br />
47, 156<br />
<br />
34<br />
<br />
163<br />
90<br />
19, 49, 64<br />
2, 218<br />
159<br />
42<br />
221<br />
222<br />
175<br />
16, 63, 120, 127<br />
239<br />
166<br />
12, 20, 62, 65, 80<br />
223<br />
185<br />
186<br />
185<br />
209<br />
19<br />
18<br />
264<br />
109<br />
172<br />
260<br />
153<br />
248, 252, 275<br />
4<br />
180<br />
<br />
250<br />
<br />
8<br />
196<br />
<br />
96<br />
() 123, 274<br />
201<br />
97<br />
243<br />
243<br />
84, 250<br />
84, 250<br />
237
286<br />
216