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60 5 (2 )− ∂B ϕ∂z∂(rB ϕ )r∂r∂E r∂z= iεµωE r (5.102)= 0 (5.103)= −iωB ϕ (5.104)− ∂E rr∂ϕ = 0 (5.105)3 1 1 3 B ϕ E r ∂ 2 E r∂z 2 = −εµω 2 E r (5.106)∂ 2 B ϕ∂z 2 = −εµω 2 B ϕ (5.107)E r B ϕ exp [iωt ∓ i √ εµωz] (5.108) z B φ E r I √ µ I 1E r =ε 2π r exp [iωt ∓ i√ εµωz] (5.109)B ϕ = µ I 12π r exp [iωt ∓ i√ εµωz] (5.110)E ϕ = 0, E z = 0 (5.111)B r = 0, B z = 0 (5.112)5.2.10 (?) ± ()5.3 ()2
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