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1 - 宇宙線研究室 - 京都大学

1 - 宇宙線研究室 - 京都大学

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1.5VVV RI 250ΩI動 作 点 V07.2. 97 2 ?? (V, I) = (1.0[V], 2.0[mA]) V 0 = RI + V (7.11)I = V 0 − V(7.12)R 7.7: 7.2.4 ?? 1 I B I E I C ?? β 200 I B V CE I C I B ≪ I C , I E (7.13)I C ≃ I E (7.14)I C = βI B , β = 200 (7.15)- I C − V CE V 0 = R C I C + V CE + R E I E = R C I C + V CE + R E I C (7.16)V CE = V 0 − (R C + R E ) I C = 6.0[V] − 500[Ω]I C (7.17)V CE = 0 →V 0I C = =6[V] = 12[mA]R C + R E 500[Ω](7.18)I C = 0 → V CE = V 0 = 6[V] (7.19)??I C − V CE I B ?? I B − V BE

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