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Exemplu 1 subnetting (pdf)

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Pasul 3…<br />

• Obtinem 16 subretele posibile si 16<br />

noduri posibile in fiecare subretea<br />

pentru ca:<br />

– Fiecare din cei 4 biti imprumutati poate fi<br />

1 sau 0, deci avem 2 4 =16 combinatii<br />

– Identic pentru cei 4 biti ramasi in host id<br />

• Important: Sunt de fapt numai 14<br />

subretele disponibile si tot atatea<br />

noduri in fiecare dintre ele. . De ce

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