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Usporedba heurističkih algoritama na problemima ... - Zemris - FER

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) grafovi ispitnih funkcija<br />

3<br />

f p 0<br />

( x)<br />

= x − 4x<br />

1 4 3 2<br />

f p 1<br />

( x)<br />

= x − x − 2x<br />

+ 1<br />

4<br />

4<br />

fp0<br />

3<br />

2<br />

5<br />

fp1<br />

0<br />

-5<br />

1<br />

-10<br />

0<br />

-1<br />

-2<br />

-3<br />

-4<br />

-2 -1.5 -1 -0.5 0 0.5 1 1.5 2<br />

-15<br />

-20<br />

-25<br />

-30<br />

-35<br />

-2 -1 0 1 2 3 4 5<br />

f p<br />

1 4 2<br />

2<br />

( x)<br />

= (35x<br />

− 30x<br />

+ 3)<br />

8<br />

fp2<br />

1<br />

0.5<br />

0<br />

-0.5<br />

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1<br />

f ( x)<br />

= 1+<br />

xsin(10π<br />

)<br />

0<br />

x<br />

2<br />

sin(10πx<br />

)<br />

f1(<br />

x)<br />

=<br />

x<br />

3<br />

f0<br />

2.5<br />

2<br />

1.5<br />

1<br />

0.5<br />

0<br />

-0.5<br />

-1<br />

-1 -0.5 0 0.5 1 1.5 2<br />

5<br />

f1<br />

4<br />

3<br />

2<br />

1<br />

0<br />

-1<br />

-2<br />

-3<br />

-4<br />

-5<br />

-1 -0.5 0 0.5 1 1.5 2<br />

33

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