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NONLINEAR INTEGRAL INEQUALITIES INVOLVING ... - Ele-Math

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Then for t0 t t1 , the inequality<br />

holds, where<br />

t1 = sup<br />

<br />

<strong>NONLINEAR</strong> <strong>INTEGRAL</strong> <strong>INEQUALITIES</strong> 813<br />

u(t) ψ −1<br />

<br />

Ψ −1<br />

<br />

W −1<br />

W Ψ(M) <br />

+ A(t)<br />

<br />

r<br />

Ψ(r) =<br />

r0<br />

r<br />

W(r) =<br />

r1<br />

(2.3)<br />

ds<br />

ψ −1 (s) p, 0 < r0 < k, (2.4)<br />

ds<br />

q ψ−1 (Ψ−1 (s)) , 0 < r1<br />

<br />

< Ψ(M), (2.5)<br />

q(t) = max max<br />

1in ωi(t), max<br />

1 jm ˜ω <br />

j(t) , (2.6)<br />

A(t) =<br />

n<br />

∑<br />

i=1<br />

αi(t)<br />

αi(t0)<br />

M = max<br />

fi(s)ds+<br />

<br />

k, ψ<br />

<br />

m β j(t)<br />

∑<br />

j=1 β j(t0)<br />

max<br />

s∈[J−h,t0] φ(s)<br />

τ ∈ [t0,T) : W Ψ(M) + A(t) ∈ Dom W −1 ,<br />

W −1<br />

W Ψ(M) <br />

+ A(t) ∈ Dom Ψ −1 and<br />

Ψ −1<br />

<br />

W −1<br />

W Ψ(M) <br />

+ A(t)<br />

<br />

∈ Dom ψ −1<br />

Proof. Define a function z : [J − h,T) → R+ by<br />

g j(s)ds, (2.7)<br />

, (2.8)<br />

for t ∈ [t0,τ]<br />

⎧<br />

n αi(t)<br />

M + ∑ fi(s)u<br />

⎪⎨ i=1 αi(t0)<br />

z(t) =<br />

⎪⎩<br />

p <br />

(s)ωi u(s) ds<br />

m β j(t)<br />

+ ∑ g j(s)u<br />

j=1 β j(t0)<br />

p t ∈ [t0,T),<br />

(s) ˜ω j max u(ξ) ds,<br />

ξ ∈[s−h,s]<br />

M, t ∈ [J − h,t0].<br />

The function z is nondecreasing. Since ψ(u(t)) ψ(max s∈[J−h,t0] φ(s)) M = z(t)<br />

for t ∈ [J −h,t0] by (2.2) and (2.8) and ψ(u(t)) z(t) for t ∈ [t0,T) by (2.1) and (2.8),<br />

the inequality<br />

u(t) ψ −1 z(t) holds for t ∈ [J − h,T). (2.9)<br />

<br />

.

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