Source Coding
Source Coding
Source Coding
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So, this algorithm guarantees for<br />
prod producing cing instantaneous instantaneo s decodable codes codes.<br />
Ex:<br />
l i<br />
r<br />
=<br />
=<br />
check<br />
S<br />
S<br />
S<br />
S<br />
S<br />
S<br />
S<br />
S<br />
1<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
8<br />
2,<br />
2,<br />
3,<br />
3,<br />
4,<br />
4,<br />
4,<br />
4<br />
2<br />
=<br />
=<br />
=<br />
=<br />
=<br />
=<br />
0<br />
S<br />
S<br />
S<br />
S<br />
S<br />
: 2 × 2<br />
1<br />
= S<br />
= S<br />
2<br />
3<br />
4<br />
5<br />
6<br />
7<br />
+<br />
+<br />
2<br />
+ 2<br />
+<br />
2<br />
+ 2<br />
2<br />
+ 2<br />
+<br />
2<br />
−2<br />
−2<br />
− 2<br />
−3<br />
− 3<br />
−4<br />
−4<br />
−4<br />
+ 2 × 2<br />
=<br />
=<br />
=<br />
=<br />
=<br />
=<br />
=<br />
=<br />
−3<br />
+ 4 × 2<br />
−4<br />
≤ 1<br />
( . 0000 L ) 2 X 1 = 00<br />
( . 0100 L)<br />
2 X 2 = 01<br />
( . 1000 L ) 2 X 3 = 100<br />
( . 1010 L)<br />
2 X 4 = 101<br />
( . 1 100 L ) 2 X 5 = 1100<br />
( . 11010<br />
L)<br />
2 X 6 = 1101<br />
( . 1 110 L ) 2 X 7 = 1110<br />
( . 11110<br />
L)<br />
X = 1111<br />
Remark: (1) instantaneous decodable<br />
(2) this encoding procedure is independent of p i<br />
2<br />
8<br />
16