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(CO)HOMOLOGY AND CRITICAL POINT THEORY - Math - IPM

(CO)HOMOLOGY AND CRITICAL POINT THEORY - Math - IPM

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374 CHAPTER 3. (<strong>CO</strong>)<strong>HOMOLOGY</strong> <strong>AND</strong> <strong>CRITICAL</strong> <strong>POINT</strong> <strong>THEORY</strong><br />

Exercise 3.1.3 Show that the homology of two circles joined at a point (i.e. figure ∞) is Z⊕Z in dimension<br />

1. More generally, show that if X ∨ Y is two simplicial complexes X and Y joined at one vertex, then for<br />

j > 0<br />

Hj(X ∨ Y ; R) = Hj(X; R) ⊕ Hj(Y ; R).<br />

For reasons that will become clear later it is essential to extend the notion of homology to the relative case,<br />

i.e., define Hn(X, A; R) whee X is a simplicial complex and A ⊂ X is a subcomplex. Then by construction<br />

Cn(A; R) ⊆ Cn(X; R), and we define<br />

Cn(X, A; R) = Cn(X; R)<br />

Cn(A; R) .<br />

Since ∂n+1(Cn+1(A; R)) ⊆ Cn(A; R), we have the induced boundary map ∂n+1 : Cn+1(X, A; R) → Cn(X, A; R)<br />

which we are denoting by the same letter ∂n+1 It clearly satisfies (3.1.1). We refer to Cn(X, A; R) as the<br />

R-module of relative chains. Similarly the R-modules relative cycles and boundaries are defined as<br />

We define Hn(X, A; R) as<br />

(3.1.7) as before.<br />

Zn(X, A; R) = ker∂n, Bn(X, A; R) = Im∂n+1.<br />

Hn(X, A; R) = Zn(X, A; R)<br />

Bn(X, A; R) .<br />

Exercise 3.1.4 Let X be the disc B 2 ⊂ R 2 and A = ∂B 2 be its boundary. By realizing B 2 and a simplicial<br />

complex and A as a subcomplex show that<br />

H1(X, A; R) R, Hj(X, A; R) = 0 for j = 1.<br />

Let X and Y be simplicial complexes and f : X → Y be a simplicial map. Therefore it gives R-module<br />

homomorphisms<br />

fn : Cn(X; R) −→ Cn(Y ; R).<br />

Then fn’s commutes with the boundary operators ∂n, i.e., ∂ Y n fn = fn−1∂ X n where the superscripts X or Y<br />

refer to the simplicial complex relative to which the boundary operator is defined. It follows that f induces<br />

a homomorphism<br />

f⋆ = fn⋆ : Hn(X; R) −→ Hn(Y ; R).<br />

Similar considerations apply to simplicial maps of pairs of simplicial complexes f : (X, A) → (Y, B). This<br />

means that A ⊂ X and B ⊂ Y are subcomplexes, f is a simplicial map of X to Y mapping A to B, and we<br />

have induced maps<br />

f⋆ = fn⋆ : Hn(X, A; R) −→ Hn(Y, B; R).

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