beamer - Vrije Universiteit Amsterdam
beamer - Vrije Universiteit Amsterdam
beamer - Vrije Universiteit Amsterdam
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Finite Unichain Case<br />
.<br />
Ergodic Theorem Finite Case<br />
.<br />
Suppose that the Markov chain satisfies the unichain condition with a finite<br />
set of transient states (|T| < ∞) and with a finite irreducible set of recurrent<br />
states (|R| < ∞). Then<br />
.<br />
1<br />
lim<br />
n→∞ n<br />
n∑<br />
f (Xk) = ∑<br />
πjf (j) (w.p. 1)<br />
k=1<br />
Proof: let r be an arbitrary initial state<br />
1<br />
n<br />
n∑<br />
k=1<br />
f (Xk) = 1<br />
n<br />
k=1<br />
j∈I<br />
j∈I<br />
n∑ ∑<br />
{Xk = j|X0 = r}f (j) = ∑ (<br />
1<br />
n<br />
j∈I<br />
n∑<br />
k=1<br />
)<br />
{Xk = j|X0 = r} f (j).<br />
Take n → ∞; interchange limit and finite sum allowed; apply empirical state<br />
average property (slide 12).<br />
c⃝ Ad Ridder (VU) SOR– Fall 2012 29 / 36